Answer:
Mark brainliest please
Explanation:
If the data points make a straight line going from the origin out to high x- and y-values, then the variables are said to have a positive correlation .When there is no clear relationship between the two variables, we say there is no correlation between the two variables.
Find the electric field at a point midway between two charges of +40.0x10^-9C and +60.0x10^-9C separated by a distance of 30.0cm
The total electric field produced by the charges at the midpoint is
8 x 10³ N/C.
Amount of charge on the first particle, q₁ = 40 x 10⁻⁹C
Amount of charge on the second particle, q₂ = 60 x 10⁻⁹C
Distance between the charges, r = 30 cm = 0.3 m
The expression for the electric field due to the charges is given by,
E = 1/4πε₀ x q/r²
At the midpoint between the two charges, d = 0.15 m
So, the electric field produced by the charge q₁ at the midpoint is,
E₁ = 1/4πε₀ x q₁/d²
E₁ = 9 x 10⁹ x 40 x 10⁻⁹/(0.15)²
E₁ = 1.6 x 10⁴ N/C
So, the electric field produced by the charge q₂ at the midpoint is,
E₂ = 1/4πε₀ x q₂/d²
E₂ = 9 x 10⁹ x 60 x 10⁻⁹C/(0.15)²
E₂ = 2.4 x 10⁴ N/C
Therefore, the total electric field produced by the charges at the midpoint is,
E = E₂ - E₁
E = 2.4 x 10⁴- 1.6 x 10⁴
E = 8 x 10³ N/C
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Find the surface of each pyramid round to nearest tenth if necessary
12.2m
16m
10.6m
12.2m
12.2m
Surface area of pyramid 1 539.2 \(m^{2}\) Pyramid 2: 370.9 \(m^{2}\) Pyramid 3: 446.4 \(m^{2}\)
To find the surface area of a pyramid, we need to know the dimensions of its base and its slant height. Assuming the base of each pyramid is a square, we can calculate the surface area using the formula:
Surface Area = Base Area + (0.5 × Perimeter of Base × Slant Height)
Let's calculate the surface area for each pyramid using the given dimensions:
1. Pyramid 1: Base = 12.2 m Slant Height = 16 m Base Area = (12.2 \(m^2\)= 148.84 \(m^2\)Perimeter of Base = 4 × 12.2 m = 48.8 m
Surface Area = 148.84 \(m^2\)+ (0.5 × 48.8 m × 16 m) = 148.84 m^2 + 390.4 \(m^2\) = 539.24 \(m^2\) (rounded to nearest tenth)
2. Pyramid 2: Base = 10.6 m Slant Height = 12.2 m Base Area = (10.6 \(m^2\))= 112.36\(m^2\) Perimeter of Base = 4 × 10.6 m = 42.4 m
Surface Area = 112.36\(m^2\)+ (0.5 × 42.4 m × 12.2 m) = 112.36 \(m^2\)+ 258.56 \(m^2\) = 370.92 \(m^2\)(rounded to nearest tenth)
3. Pyramid 3: Base = 12.2 m Slant Height = 12.2 m Base Area = (12.2 \(m^2\)= 148.84 \(m^2\)Perimeter of Base = 4 × 12.2 m = 48.8 m
Surface Area = 148.84 m^2 + (0.5 × 48.8 m × 12.2 m) = 148.84 \(m^2\)+ 297.52 \(m^2\) = 446.36 \(m^2\) (rounded to nearest tenth)
Therefore, the surface areas of the given pyramids are approximately: Pyramid 1: 539.2 \(m^2\)Pyramid 2: 370.9 \(m^2\) Pyramid 3: 446.4 \(m^2\).
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Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Answer:
Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Explanation:
Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.
ight with a frequency of 5.9 x1014 hz travels in a block of glass that has an index of refraction of 1.51. A) What is the wavelength of the light in vacuum ? | B) What is the wavelength of the light in the glass?
The wavelength in a vacuum is 5.08 x 10-7 m and the wavelength of the light in the glass is 3.367 x 10-7 m
As we know that
Velocity = wavelength x frequency
So, wavelength = Velocity / frequency
If the light travels in a vacuum,
Then, wavelength = speed of light/frequency
Here the frequency is 5.9 x1014 Hz
And the speed of light = 3 x 10 8 m/s
So, wavelength in vacuum = 3 x 10 8 / 5.9 x1014
= 5.08 x 10-7 m
Again, the wavelength of the light in the glass
λ=c/μn where μ is a block of glass that has an index of refraction
Then λ=(3 x 10 8 )/(1.51x5.9 x1014 )
= 3.367 x 10-7 m
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Analyze Data and Draw Conclusions
Question 7
In Part 1, one plate feels colder than the other plate. Why does it feel colder? Is it actually colder, or are the two
plates the same temperature? Explain.
The plate that feels colder is likely a better conductor of heat compared to the other plate.
Why the difference in temperature?Compared to the other plate, the one that feels cooler is probably a greater heat conductor. The capacity of a material to transfer heat is known as conductivity. A colder feeling will result from the plate's ability to more efficiently absorb heat from our skin if its thermal conductivity is higher.
The two plates may truly be at the same temperature, but our perception of that temperature is affected by the rate of heat transmission, it is crucial to note.
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The social model was created by
A fan blade Spins at 3,000 revolutions per minute.
How
many degrees does it rotate in one second?
18,000 degrees in one second i believe
A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Why backward curve fan has a non overloading characteristic?
Backward curve fan has a non overloading characteristic simply because the pressing changes in static pressure do not overload the motor.
What is centrifugal fan?A centrifugal fan means a kind of a mechanical device for moving air or other gases in a direction at an angle to the incoming fluid
A centrifugal fan has some key characteristics such as low noise level and small air flow with a high increase in static pressure
So therefore, backward curve fan has a non overloading characteristic simply because the pressing changes in static pressure do not overload the motor.
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Moving current has electrical energy.
A flat coil of wire has an area of 0.020 m2 and contains 50 turns. Initially the coil is oriented so that the normal to its surface is parallel to and in the same direction as a constant magnetic field of 0.18 T. The coil is then rotated through an angle of 30o in a time of 0.10 s. What is the average induced emf? -0.44 V +0.44 V +0.24 V
ANSWER:
3rd option: +0.24 V
STEP-BY-STEP EXPLANATION:
Given:
N = 50
Area = 0.020 m^2
B = 0.18 T
θf = 30°
time = 0.10 s
We can calculate the average induced emf by the following formula
\(\epsilon=N\cdot B\cdot A\cdot\left(\frac{\cos\theta_i-\cos\theta_f}{t}\right)\)We replacing:
\(\begin{gathered} \epsilon=\left(50\right)\left(0.18\right)\left(0.02\right)\left(\frac{\cos\:0\degree\:-\cos\:30\degree}{\:0.1}\right) \\ \epsilon=0.241\cong0.24\text{ V} \end{gathered}\)The correct answer is 0.24V
Engineers are designing a system by which a falling mass m
imparts kinetic energy to a rotating uniform drum to which it is attached by thin, very light wire wrapped around the rim of the drum (Figure 1). There is no appreciable friction in the axle of the drum, and everything starts from rest. This system is being tested on earth, but it is to be used on Mars, where the acceleration due to gravity is 3.71 m/s2
. In the earth tests, when m
is set to 15.0 kg
and allowed to fall through 5.00 m
, it gives 350.0 J
of kinetic energy to the drum.
If the system is operated on Mars, through what distance would the 15.0 kg
mass have to fall to give the same amount of kinetic energy to the drum? answer=13.2m
How fast would the 15.0 kg
mass be moving on Mars just as the drum gained 350.0 J
of kinetic energy?
According to the given data in the question, the 15.0 kg mass would be moving at a speed of 6.66 m/s just as the drum gained 350.0 J of kinetic energy on Mars.
What is kinetic energy?Kinetic energy is the energy that a moving physical object has due to its movement. It is defined as the energy an object possesses by virtue of its motion, and is dependent on its mass and velocity.
The kinetic energy gained by the drum is equal to the work done by the falling mass. On earth, the work done is given by:
W = mgh = (15.0 kg)(9.81 m/s²)(5.00 m) = 735.75 J
Since the drum gains 350.0 J of kinetic energy, the efficiency of the system is:
efficiency = 350.0 J / 735.75 J = 0.475
On Mars, the work done by the falling mass must also be equal to 350.0 J, but with a different value of h:
350.0 J = (15.0 kg)(3.71 m/s²)h
h = 26.0 m
Therefore, the 15.0 kg mass must fall through 26.0 m on Mars to give the same amount of kinetic energy to the drum.
The final speed of the mass just as the drum gains 350.0 J of kinetic energy can be found using the formula:
K = (1/2)mv²
where K is the kinetic energy of the mass and v is its final speed. Solving for v:
v = \(\sqrt{(2K/m)}\)
On Mars, with the same efficiency as on earth, the kinetic energy of the mass is also 350.0 J. Therefore:
v = \(\sqrt{(2(350.0 J) / 15.0 kg) }\)= 6.66 m/s
So the 15.0 kg mass would be moving at a speed of 6.66 m/s just as the drum gained 350.0 J of kinetic energy on Mars.
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True or False. When energy changes form, some energy is lost to heat.
True
False
Answer:
True
Explanation:
Energy decreases as it moves up trophic levels because energy is lost as metabolic heat when the organisms from one trophic level are consumed by organisms from the next level.
Question 10 (1 point)
A water wave in a 17 m long pool takes 3 seconds to travel to one end of the pool.
What is the speed of the wave?
Answer:
5.67 m/s
Explanation:
The speed of a wave can be calculated as the distance traveled by the wave divided by the time taken:
Speed = Distance/Time
In this case, the distance traveled by the wave is the length of the pool, which is 17 m. The time taken by the wave to travel this distance is 3 seconds.
So, the speed of the wave can be calculated as:
Speed = 17 m/3 s
Speed = 5.67 m/s
Therefore, the speed of the water wave in the 17 m long pool is 5.67 m/s.
identify and explain the importance of any five sources of radiation used in the health sector
We have that Radiations in there own different ways affect the health sector, the identified sources of radiation are
X-ray gamma raySunUraniumStrontium-90Radioactive potassium-40Generally the sources of radiation selected to be discussed are
X-ray gamma raySunUraniumStrontium-90Radioactive potassium-40Potassium-40
This is an internal Radio active element that is found in the human body.It is found in the food we eat because of a Natural Radioactivity that acts on every food as Potassium-40 gives rise to some activity in the food we eat.
X-ray (gamma ray)
X ray is use diversely in the health sector but I will focus its use in the Radioactive scan of the body with the aim to discover what is wrong with a patient or to know if the is anything wrong with a patient
Uranium
This is a source of radiation but one to be abstained from as its possess kidney damaging properties and should be wary of for health purposes
Sun
The Sun is a major source of Radiation and its Health benefits of uses are numerous as exposure to it helps to provide vitamin D for deficient patients strengthens bones and many more
Strontium-90
This is a particle produce beta particles,these particles are use in the Health sector to cure cancer related to the Bones and Eyes
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nice, hey could u look at my recent question
You stand at the base of a 3.90-m long frictionless ramp that is inclined at an angle of 8.60∘. You want to slide a 1.95-kg object up the ramp so that it stops just as it reaches the top. What initial velocity 0 must you give the object?
One stands at the base of a 3.90-m long frictionless ramp that is inclined at an angle of 8.60∘, so one must give the object an initial velocity of 2.29 m/s up the ramp to slide a 1.95-kg object up the ramp.
What is the calculation of the initial velocity?The potential energy of the object at the top of the ramp = the initial kinetic energy of the object, as the final velocity is zero.
m × g ×h = 1/2 × m × \(v_0^2\)
(m= mass of the object, g = acceleration due to gravity, h = height of the ramp, and \(v_0\) = initial velocity of the object)
\(v_0\) =√2× g ×h
\(v_0\) =√2× 9.81 m/\(s^2\) ×3.90 m× sin(8.60°)
\(v_0\) =2.29 m/s
Hence, one stands at the base of a 3.90-m long frictionless ramp that is inclined at an angle of 8.60∘, so one must give the object an initial velocity of 2.29 m/s up the ramp.
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The question is incomplete, the complete question is below
You stand at the base of a 3.90-m long frictionless ramp that is inclined at an angle of 8.60∘. You want to slide a 1.95-kg object up the ramp so that it stops just as it reaches the top. What initial velocity must you give the object?
. A driver in a car travelling at a speed of 26.82m/s sees a deer in the middle of the road 100m
away. What is the minimum constant acceleration that is necessary for the car to stop?
5:04 PM
10/28/2020
Answer:
-3.60 m/s^2
Explanation:
List different type of thermometer in terms of their thermometer properties
Answer:
Look below.
Thermometric Property ThermometerVolume expansion of a gas Gas thermometer
Volume expansion of a liquid Laboratory or clinical thermometer
Volume expansion of a solid Bi-metallic strip thermometer
Pressure change of a fixed mass of gas Constant – volume gas thermometer
A baseball (m = 140 g) traveling at 30. m/s moves a fielder's glove backward 35 cm when the ball is caught.
What was the average force exerted by the ball on the glove?
Answer:
180
Explanation:
1) E=F*L, where E - energy of the baseball, F - the required force, L - backward moving (0.35m);
2) E=mV²/2, where E - energy of the baseball, m - the mass of the baseball (0.14kg), V - the velocity of the baseball (30m/s).
3) if E=F*L and E=mV²/2, then F*L=mV²/2, from which
\(F=\frac{mV^2}{2L};\)
4) according to the last formula
\(F=\frac{0.14*900}{2*0.35}=\frac{126}{0.7}=180(N).\)
The force exerted by the ball on the glove is 180 Newtons.
In mechanics, a force is any action that has the potential to change, maintain, or deform a body's motion. The three principles of motion outlined by Isaac Newton in his Principia Mathematica are frequently used to illustrate the concept of force (1687).
Newton's first law states that a body at rest or moving uniformly in a straight line will stay in that state until a force is applied to it. According to the second law, a body will accelerate (change in velocity) in the direction of any external force acting on it.
Given:
A baseball (m = 140 g) traveling at 30 m/s moves a fielder's glove backward 35 cm when the ball is caught,
Calculate the value of force as shown below,
Force = m × V² / 2L
Force = 0.140 × 30² / 2 × 0.35
Force = 0.140 × 900 / 0.70
Force = 126 / 0.7
Force = 180 N
Thus, the force exerted by the ball is 180 Newtons.
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The above photo shows Plates A and B at an mid ocean ridge. If you were to draw arrows on the plates showing plate movement, which way would you draw arrows?
A . The arrows on plates A and B would show the plates moving in the same direction
B . The arrows on plates A and B would show the plates moving towards eachother
C . The arrows on plates A and B would show the plates moving in random directions
D . The arrows on plates A and B would show the plated moving away from each other
Answer:
D . The arrows on plates A and B would show the plated moving away from each other
Explanation:
The correct arrow in this instance will show that the plates A and B would be moving away from each other.
At the mid-ocean ridge, two plates are moving apart and pulling away from one another.
In short, at the mid-oceanic ridge, we have a divergent margin. At a divergent margin, the plates are spreading or moving apart.1. What is the function of a lightning rod?
2. How is charge build-up reduced on airplanes?
3. Why is a ground strap a necessary safety feature when transferring fuel?
4. What are three different methods for reducing charge build-up in clothes dryers?
5. What are four different methods for reducing charge build-up in a computer room with a carpet?
Answer: 1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.
2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.
3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.
4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.
5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.
Explanation:
I hope this helps!
In your business plan, the target market section should clearly identify_____market(s).
A. Both your primary and secondary
B. primary
C. demographic
D. secondary
In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.
4) A force is applied to an object and causes and acceleration of 2.4 m/s2. The same force is
applied to a second object with half the mass of the first. What will the acceleration of the
second object be?
1.2 m/s2
2.4 m/s2
4.8 m/s2
Explanation:
Newton's second law of motion is F = ma, or force is equal to mass times acceleration
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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1:
Forces and Motion:Question 2
A car is travelling east, when suddenly a more massive car travelling
north hits it with a greater force. What is likely to happen to the car
that was originally travelling east?
Explanation:
the car will be brought back
Please help me Thanks!
l will help and if you get it correctly I will say you are welcome
You are lowering two boxes, one on top of the other,
down a ramp by pulling on a rope parallel to the surface of the
ramp (Fig. E5.33). Both boxes move together at a constant speed
of 15.0 cm>s. The coefficient of kinetic friction between the ramp
and the lower box is 0.444, and the coefficient of static friction
between the two boxes is 0.800. (a) What force do you need to
exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?
To solve this problem, we need to use Newton's second law to find the net force acting on the two boxes. The net force is equal to the mass of the two boxes times the acceleration. Since the boxes are moving at a constant speed, the acceleration is zero, and the net force is also zero. This means that the sum of all the forces acting on the two boxes must be zero.The force you exert on the boxes is the force of tension in the rope, and this force is equal in magnitude and opposite in direction to the force of friction on the lower box. The magnitude of the friction force on the lower box is equal to the coefficient of kinetic friction times the normal force acting on the lower box.The normal force is the force exerted by the ramp on the lower box, and it is equal in magnitude to the weight of the lower box. The weight of the lower box is equal to the mass of the lower box times the acceleration due to gravity.The magnitude of the friction force on the upper box is equal to the coefficient of static friction times the normal force acting on the upper box. The normal force acting on the upper box is equal in magnitude to the weight of the upper box.Now that we have all the forces, we can use Newton's second law to solve for the force you need to exert. The equation is:F_tension - F_friction_lower = 0
F_tension = F_friction_lowerF_friction_lower = u_k * N_lower
F_tension = u_k * m_lower * gWhere:F_tension is the force you need to exertF_friction_lower is the force of friction on the lower boxu_k is the coefficient of kinetic friction between the ramp and the lower boxN_lower is the normal force acting on the lower boxm_lower is the mass of the lower boxg is the acceleration due to gravitySubstituting the given values, we get:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The force you need to exert is therefore:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The magnitude of the friction force on the upper box is:F_friction_upper = u_s * N_upperWhere:F_friction_upper is the force of friction on the upper boxu_s is the coefficient of static friction between the two boxesN_upper is the normal force acting on the upper boxSubstituting the given values, we get:F_friction_upper = (0.800) * (m_upper) * (9.8 m/s^2)The direction of the friction force on the upper box is opposite to the direction of motion of the upper box.
Timed plz hurry
Enlarged brain ventricles are presumed to signify
A. an excess of dopamine activity
B. frontal lobe abnormalities
C. development of brain tissue
D. a deterioration of brain tissue
Answer:
D. a deterioration of brain tissue
A deterioration of brain tissue cause enlargement of brain ventricles
When an injury or illness alters the circulation of CSF, one or more of the ventricles becomes enlarged as CSF accumulates. In an adult, the skull is rigid and cannot expand, so the pressure in the brain may increase profoundly. Hydrocephalus is a chronic condition in which is the buildup of fluid in the cavities (ventricles) deep within the brain. It can be controlled, but usually not cured.What is CSF?Cerebrospinal fluid (CSF) is a clear, colorless liquid found in your brain and spinal cord. They combinedly form central nervous system.Central nervous system controls and coordinates everything you do including muscle movement, organ function, and even complex thinking and planningHence, D) is the correct option.
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Five ramps lead from the ground to the second floor of a workshop, as sketched below. All five ramps have the same height; ramps B, C, D and E have the same length; ramp A is longer than the other four. You need to push a heavy cart up to the second floor and you may choose any one of the five ramps.Assuming no frictional forces on the cart, which ramp would require you to do the least work?
The mechanical advantage of ramp A is greater than others and it will require the least force to move the load to greater distance.
Let the height of the ramp = hLet the length of ramp B, C, D and E = LLet the length of the ramp A = 2LThe mechanical advantage of the ramp is calculated as follows;
\(M.A = \frac{L}{h}\)
The mechanical advantage of the ramp B, C, D and E is calculated as;
\(M.A = \frac{L}{h} \\\\\)
The mechanical advantage of the ramp A is calculated as follows;
\(M.A = \frac{2L}{h} \\\\M.A = 2(\frac{L}{h} )\)
Since the length of the ramp A is greater than other ramps, the mechanical advantage will be greater and it will require the least force to move the load to greater distance.
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