The calories she burns per minute is 17 cal
We are given that the total calories that are burnt in 15 minutes and 20 minutes are 255 and 340 respectively.
We can use the equation
total calorie burnt = time (in minutes) * calorie burnt in one minute
here we know the total calorie that is burnt and the time, we can substitute the calorie that is burnt in a single minute with 'n'.
we can say that :
255 = 15 * x
x=255/15
x= 17.
The total calorie burn per minute is 17.
now for the verification, we know that if the total calorie burn per minute is 17 it should satisfy both the equation.
So, 340 = 20*x
340=20* 17
340 = 340
Thus it satisfies both equations.
Hence the calorie burnt per minute = 17
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a ball is dropped form a height of 30 feet and rebounds 2/3 of the distance it falls on each bounce. how far has the ball traveled vertically when it stops?
When the ball stops bouncing, it will have traveled a total vertical distance of 90 feet.
To determine how far the ball has traveled vertically when it stops, we can calculate the sum of the geometric series formed by the distances of each bounce.
Given that the ball rebounds 2/3 of the distance it falls, the distances covered by each bounce form a geometric sequence with a common ratio of 2/3.
The distance the ball initially falls is 30 feet. The subsequent distances covered by each bounce can be calculated as follows:
First bounce: 30 * (2/3) = 20 feet
Second bounce: 20 * (2/3) = 40/3 feet
Third bounce: (40/3) * (2/3) = 80/9 feet
Fourth bounce: (80/9) * (2/3) = 160/27 feet
Fifth bounce: (160/27) * (2/3) = 320/81 feet
And so on...
To calculate the total distance covered, we sum up the infinite geometric series:
Sum = a / (1 - r)
where "a" is the initial term (30 feet) and "r" is the common ratio (2/3).
Sum = (30) / (1 - 2/3)
Sum = (30) / (1/3)
Sum = 90 feet
Therefore, when the ball stops bouncing, it will have traveled a total vertical distance of 90 feet.
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To practice for a competition, Kate swam 710 meters in the pool each day for 3 weeks. How many kilometers did Kate swim in those 3 weeks?
Answer:
14910 meters
Step-by-step explanation:
3 weeks= 21 days
each day= 710 m
21 days= 710*21
21 days= 14910 m
A circle has a radius of 11 meters. What is the area of the circle?
Answer:
A≈380.13 m²
Step-by-step explanation:
looked it up
Answer:
A= 380.13 m²
Step-by-step explanation:
A=\(\pi r^{2}\)
A= \(\pi\)x\(11^{2}\)
A= 380.13
The 66-mm-diameter solid shaft is made of 2014-t6 aluminum and is subjected to the distributed and concentrated torsional loadings shown where t=1. 7 kn⋅m.
Answer:
bbc
Step-by-step explanation:
In right triangle DOG with the right angle O
find OG if DG = 4√5 and DO = 4.
The calclated length of segment OG is 8 units
Calculating the length OGFrom the question, we have the following parameters that can be used in our computation:
DG = 4√5
DO = 4.
The length OG is calculated as
OG^2 = DG^2 - DO^2
substitute the known values in the above equation, so, we have the following representation
OG^2 = (4√5)^2 - 4^2
Evaluate
OG^2 = 64
So, we have
OG = 8
Hence, the solution is 8
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More info a. Theoretical capacity-based on three shifts, completion of five motorcycles per shift, and a 360 -day year-3 −3×360=5,400. b. Practical capacity-theoretical capacity adjusted for unavoidable interruptions, breakdowns, and so forth-3 −4×320=3,840. c. Normal capacity utilization-estimated at 3,240 units. d. Master-budget capacity utilization-the strengthening stock market and the growing popularity of motorcycles have prompted the marketing department to issue an estimate for 2020 of 3,600 units. Requirement 2. What are the benefits to Zippy, Inc., of using either theoretical capacity or practical capacity? to managers. As a general rule, however, it is important on the production-volume variance as a measure of the economic costs of unused capacity. Requirement 3. Under a cost-based pricing system, what are the negative aspects of a master-budget denominator level? What are the positive aspects? What are the negative aspects of a master-budget denominator level? referred to as the demand spiral. What are the positive aspects? The positive aspects of the master-budget denominator level are that is based on for the product and indicates the price at which would be recovered to enable the company to make a profit.
The benefits of using the theoretical capacity for Zippy, Inc. include providing a maximum production potential based on ideal conditions, aiding in long-term planning, and setting performance benchmarks. Practical capacity considers unavoidable interruptions and breakdowns, providing a more realistic estimate. The negative aspect of a master-budget denominator level is the potential for unused capacity costs, while the positive aspect is using a predetermined cost base for pricing decisions.
Theoretical capacity, based on three shifts and completion of five motorcycles per shift, gives Zippy, Inc. a maximum production potential of 5,400 units per year. This capacity measure helps in long-term planning, resource allocation, and setting performance benchmarks. On the other hand, practical capacity takes into account unavoidable interruptions, breakdowns, and other factors that can impact production. It provides a more realistic estimate of 3,840 units.
Regarding cost-based pricing, the negative aspect of a master-budget denominator level is that it may lead to unused capacity costs. If the estimated demand falls below the master-budget level, there could be underutilized resources, resulting in economic costs for the company. However, the positive aspect of using a master-budget denominator level is that it provides a predetermined cost base for pricing decisions. It helps in setting prices that ensure the company's costs are covered and profitability is achieved.
In summary, theoretical capacity aids in long-term planning and setting benchmarks, while practical capacity considers interruptions. The negative aspect of a master-budget denominator level is unused capacity costs, but it provides a predetermined cost base for pricing decisions, ensuring cost recovery and profitability.
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QUESTION 2, Saturday, October 10th, 2020
I have some geometry questions today. Please include your thoughts or reasoning with your answer. Please ignore the answer I selected for it was not an purpose. Thanks!
Answer:
SSA
Step-by-step explanation:
Answer:
Not congruentStep-by-step explanation:
3 angles are congruent but no evidence of any of sides being congruent, the triangles can still be different
So the answer is Not congruent
For a certain relationship, y varies inversely with x. When x is 4, y is equal to 30. What is the value of y when x is equal to 10?
Step-by-step explanation:
inversely means
y = k/x
therefore
30 = k/4
120 = k
y = 120/10 = 12
FYI :
directly would mean
y = kx
The value of y will be 12 when x is equal to 10.
What is inverse variation?The relationship between two variables known as "inverse variation" occurs when the value of one variable increases while the value of the other variable decreases.
Given that, y varies inversely with x.
Here, y∝1/x
y=k/x
xy=k
When x is 4, y is equal to 30, we get
k=4×30
k=120
When x=10, we get
10y=120
y=12
Therefore, the value of y will be 12 when x is equal to 10.
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To install the right size heating and cooling syster, you must know how many cubic feet an office building contains. The building is 120 feet wide. 20 feet lugh, and 48 feet long. Find the volume.
Answer:
Mizuki is here to help!
115200 \(ft^3\) is the volume of the building.
Step-by-step explanation:
120 x 20 x 48 =
2400 x 48 =
115200
The table below represents the metric volume measure of a liter with each amount represented as a power of 10. a 2-column table with 5 rows. column 1 is labeled unit with entries centiliter, liter, hectoliter, kiloliter, megaliter. column 2 is labeled power of 10 with entries 10 superscript negative 2, 10 superscript 0, 10 squared, 10 cubed, 10 superscript 6. the work shows that a megaliter is 10,000 times larger than a hectoliter. 106 102 = 104 = 10,000 the of the original exponent is the exponent in the power of quotient. the kiloliter is 103 times greater than a . the hectoliter is times greater than centiliter.
A megaliter is 10,000 times larger than a hectoliter.
The kiloliter is 10^3 times greater than a liter while the hectoliter is 10^4 times greater than the centiliter.
What is an equation?An equation is an expression that shows the relationship between two or more variables.
1 mega liter = 10^6 Liter
1 hectoliter = 10^2 Liter.
Hence, a megaliter is 10,000 (10^6/10^2) times larger than a hectoliter
The kiloliter is 10^3 times greater than a liter while the hectoliter is 10^4 times greater than the centiliter.
Uncle Reynald's age is given by the expression 3(12 + 5) - 4.
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Answer:
the first one is diffrence
2nd one is liter
3rd one 10,000
Step-by-step explanation:
Use the elimination method to find a general solution for the given linear system, where differentiation is with respect to t. 2x' y'-4x-4y=e^-t x' y' 2x y=e^4t
It looks like the system of ODEs is
\(\begin{cases} 2x' + y' - 4x - 4y = e^{-t} \\ x' + y' + 2x + y = e^{4t} \end{cases}\)
Differentiate both sides of both equations with respect to \(t\).
\(\begin{cases} 2x'' + y'' - 4x' - 4y' = -e^{-t} \\ x'' + y'' + 2x' + y' = 4e^{4t} \end{cases}\)
Eliminating the exponential terms, we have
\((2x' + y' - 4x - 4y) + (2x'' + y'' - 4x' - 4y') = e^{-t} + (-e^{-t}) \\\\ \implies (2x'' - 2x' - 4x) + (y'' - 3y' - 4y) = 0\)
\((x'' + y'' + 2x' + y') - 4 (x' + y' + 2x + y) = 4e^{4t} - 4\cdot e^{4t} \\\\ \implies (x'' - 2x' - 8x) + (y'' - 3y' - 4y) = 0\)
Now we can eliminate \(y\) and it derivatives.
\(\bigg((2x'' - 2x' - 4x) + (y'' - 3y' - 4y)\bigg) - \bigg((x'' - 2x' - 8x) + (y'' - 3y' - 4y)\bigg) = 0 - 0 \\\\ \implies x'' + 4x = 0\)
Solve for \(x\). The characteristic equation is \(r^2 + 4 = 0\) with roots at \(r=\pm2i\), hence the characteristic solution is
\(\boxed{x(t) = C_1 \cos(2t) + C_2 \sin(2t)}\)
Solve for \(y\). Substituting \(x\) into the second ODE gives
\(x' + y' + 2x + y = e^{4t} \\\\ \implies y' + y = e^{4t} + C_1 \cos(2t) + C_2 \sin(2t)\)
The characteristic equation this time is \(r + 1 = 0\) with a root at \(r=-1\), hence the characteristic solution is
\(y(t) = C_3 e^{-t}\)
Assume a particular solution with unknown coefficients \(a,b,c\) of the form
\(y_p = ae^{4t} + b \cos(2t) + c \sin(2t) \\\\ \implies {y_p}' = 4ae^{4t} - 2b\sin(2t) + 2c\cos(2t)\)
Substituting into the ODE gives
\(5ae^{4t} + (b+2c) \cos(2t) + (-2b+c) \sin(2t) = e^{4t} + C_1 \cos(2t) + C_2 \sin(2t) \\\\ \implies \begin{cases}5a = 1 \\ b+2c = C_1 \\ -2b+c = C_2\end{cases} \\\\ \implies a=\dfrac15, b=\dfrac{C_1-2C_2}5, c=\dfrac{2C_1+C_2}5\)
so that the general solution is
\(\boxed{y(t) = \dfrac15 e^{4t} + \dfrac{C_1-2C_2}5 \cos(2t) + \dfrac{2C_1+C_2}5 \sin(2t) + C_3 e^{-t}}\)
What is the arc length the car traveled to the nearest hundredth?
a. 7.91
b. 8.32
c. 10.99
d. 11.89
To find the arc length, we can use the formula:
\(\[ L = \frac{\theta}{360} \times 2\pi r \]\\Given:\( r = \frac{d}{2} = \frac{30}{2} = 15 \) ft\( \theta = 42 \) degrees\( \pi = 3.14 \)\\Substituting the given values into the formula:\[ L = \frac{42}{360} \times 2 \times 3.14 \times 15 \]\[ L = \frac{42}{360} \times 94.2 \]\[ L = \frac{3956.4}{360} \]\[ L \approx 10.99 \] ftTherefore, the arc length traveled by the car, to the nearest hundredth, is 10.99 feet. The correct option is c.\)
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Given ΔPQR with coordinates P(–4, –1), Q(–4, –5) and R(–1, –5).
The ordered pair (2, y) is on line PR. Enter the value of y for this ordered pair.
Answer:
Answer
Step-by-step explanation:
Step-by-step explanation
Halla la ecuación de la circunferencia con r=10 y cuyo centro es el punto medio que une los puntos del segmanto A=(-7,-6) B(3,14). Escribe la ecuación en la forma ordinaria.
Responder:
(x + 2) ² + (y-4) ² = 100
Explicación paso a paso:
La ecuación de un círculo se expresa como (x-x0) ² + (y-y0) ² = r²
r es el radio
(x0, y0) es el centro
Dado que el centro representa el punto medio de (-7, -6) y (3,14)
x0 = -7 + 3/2
x0 = -4/2
x0 = -2
y0 = -6 + 14/2
y0 = 8/2
y0 = 4
Sustituir en la expresión
(x - (- 2)) ² + (y-4) ² = 10²
(x + 2) ² + (y-4) ² = 100
Por lo tanto, la ecuación requerida del círculo es (x + 2) ² + (y-4) ² = 100
HELPPPP ILL MARK YOU BRAINLIST SHOW WORK SHOW WORK
Answer:(−5x3−6x2−5)(−5x2−2x) = 25x5+40x4+12x3+25x2+10x
Step-by-step explanation:
The regular price of an item at a store is p dollars. The item is on sale for 20% off the regular price. Write an expression you can use to find the sale price. Show all work.
Answer: P×0.8
Step-by-step explanation:
1-0.2=0.8
if the mean of a group of samples is 135 with a standard deviation of 45, what is the probability that a number would be less than 170?
Answer: C / .33
Step-by-step explanation:
State the probability that justifies each statement.
11. If 2x+19=27, then 2x=8
Answer:
100% true....
subtracting 19 from both sides brings you to 2x=8, so x=4
Step-by-step explanation:
Hey there!
2x + 19 = 27
SUBTRACT by 19 to BOTH SIDES
2x + 19 – 19 = 27 – 19
Cancel out: 19 – 19 because that gives you 0
KEEP: 27 – 19 because that gives you the value of 8
New EQUATION: 2x = 8
DIVIDE by 2 to BOTH SIDES
2x/2 = 8/2
CANCEL out: 2/2 because that gives you 1
KEEP: 8/2 because that gives you the value of x
“8/2 = x”
Answer: x = 4 ☑️
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
Simplify the expression.
Answer:
\(16 {( \frac{1}{2} x)}^{4} \\ = 16 \times {( \frac{1}{2}) }^{4} {x}^{4} \\ = 16 \times \frac{1}{16} {x}^{4} \\ = {x}^{4} \\ thank \: you\)
Solution:
\(16 \times \bigg ( \frac{x}{2} \bigg)^{4} \\ \\ = 16 \times \bigg( \frac{x^{4} }{2^{4} } \bigg) \\ \\ = 16 \times \frac{ {x}^{4} }{16} \\ \\ = {x}^{4} \\ \\ \)
Therefore answer is x⁴
Hope it helps you :)
A line contains L(-4, -4) and M(2, 3). Line q is in the same coordinate plane but does not intersect IM. Line q contains point N. (Can someone please look at the picture and help me)
The line q passes through (2, 0) and (-7, -4)
How to find line LM?If line Q does not intersect the line LM, then these lines are parallel, thus, have the same slope.
The slope of line LM is given by:
s = (3 + 4)/(2 + 4) = 7/6
Now we know that the line Q contains point N (2, 0) ( i will assume is this because in the image the points don't have the correspondent names).
Then the line also passes through another point (a, b) such that:
s = (0 - b)/(2 - a) = 7/6
Then:
b = -7
a = -4
The line q passes through (2, 0) and (-7, -4)
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THE THREE SIDES OF A TRIANGULAR LOT
ARE MEASURED TO BE APPROXIMATELY 100.52
FT, 15.321 FT AND 143.250 FT LONG. FIND THE
APPROXIMATE PERIMETER OF THE LOT
Answer:
259.09 feet
Step-by-step explanation:
Given that,
The three sides of a triangular lot are measured to be 100.52 ft, 15.321 ft and 143.250 ft.
We need to find the perimeter of the lot.
We know that,
Perimeter = sum of all sides
P = 100.52 + 15.321 + 143.250
P = 259.09 feet
So, the required perimeter of the lot is 259.09 feet.
work out the missing numbers:
a) 2.6 x ? = 2.86
b) ? x 1.2 = 1.8
Will make brainliest
Answer:
a) \(\sf x = 1.1\) b) \(\sf x = 1.5\)
solving steps:
a)
\(\sf 2.6 * x = 2.86\)
\(\sf x = \frac{2.86}{2.6}\)
\(\sf x = 1.1\)
b)
\(\sf x * 1.2 = 1.8\)
\(\sf x = \frac{1.8}{1.2}\)
\(\sf x = 1.5\)
Explain the statement. "All functions are relation but some relations are not functions?"
Answer:
This is because, a relation could be any set of ordered pairs where as a function is a set of ordered pairs where there is only ONE value of y for every value of x.
Another way of explaining it is:
In fact, every function is a relation. However, not every relation is a function. In a function, there cannot be two lists that disagree on only the last element. This would be tantamount to the function having two values for one combination of arguments. By contrast, in a relation, there can be any number of lists that agree on all but the last element.
The statement "All functions are relations but some relations are not functions" highlights the relationship between functions and relations and the distinction between the two concepts.
In mathematics, a relation is a set of ordered pairs that establishes a connection between elements of two sets. It can be thought of as a collection of inputs and outputs.
On the other hand, a function is a specific type of relation in which each input value (x-coordinate) is associated with exactly one output value (y-coordinate).
So, when we say "all functions are relations," we are acknowledging that functions are a subset of relations. This is because functions satisfy the property of assigning a unique output for each input, making them a special kind of relation.
However, the statement also recognizes that there are relations that do not meet the criteria of a function. This occurs when an input value is associated with multiple output values or when an input value has no corresponding output value.
In other words, some relations may have more than one output value for a given input, or they may lack a well-defined output for certain inputs. Such relations are not considered functions.
Therefore, while all functions can be classified as relations, not all relations can be classified as functions due to the specific requirement of having a unique output for each input.
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how to determine if a linear transformation is an isomorphism
Therefore, to determine if a linear transformation is an isomorphism, we can check if the determinant is non-zero or if the kernel is only the zero vector.
An isomorphism is a bijective linear transformation, that is both one-to-one and onto. The determinant of a linear transformation can help determine if it is an isomorphism. If the determinant is non-zero, the linear transformation is invertible, and therefore an isomorphism. A linear transformation is an isomorphism if and only if its determinant is nonzero.
Additionally, another way to check if a linear transformation is an isomorphism is to check if the kernel, which is the set of all vectors that get mapped to zero, is equal to only the zero vector. If the kernel is only the zero vector, then the linear transformation is one-to-one and therefore an isomorphism.
Therefore, to determine if a linear transformation is an isomorphism, we can check if the determinant is non-zero or if the kernel is only the zero vector.
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Determine the discriminant for the quadratic equation -3=x^2+4x+1. Based on the discriminant value, how many real number solutions does the equation have ? Discriminant value = b^2-4ac
Answer:
One real root (multiplicity 2).
Step-by-step explanation:
-3=x^2+4x+1
x^2 + 4x + 4 = 0
Discriminant = 4^2 - 4*1*4 = 0
There is one real root (multiplicity 2).
The equation has 1 real solution.
The quadratic function is given as:
\(-3=x^2+4x+1\)
Add 3 to both sides of the equation
\(3-3=x^2+4x+1 + 3\)
This gives
\(0=x^2+4x+4\)
Rewrite the equation as:
\(x^2+4x+4 = 0\)
A quadratic equation is represented as:
\(ax^2+bx+c = 0\)
By comparison, we have:
\(a =1\)
\(b =4\)
\(c = 4\)
The discriminant (d) is calculated as:
\(d =b^2 - 4ac\)
So, we have:
\(d =4^2 - 4 \times 1 \times 4\)
\(d =16 - 16\)
Evaluate like terms
\(d = 0\)
Given that the discriminant value is 0, it means that the equation has 1 real solution.
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What is 2/5 divided by 4/7 equal too
I dont know what to do please help
Answer:
V = π(8^2)(31) = 6,232.9 m^3
a1=1 and An+1 = -3An-3 find a5
Answer:
a₅ = 141
Step-by-step explanation:
using the recursive rule \(a_{n+1}\) = - 3\(a_{n}\) - 3 and a₁ = 1
the recursive rule allows a term in the sequence to be found by multiplying the previous term by - 3 and then subtracting 3 , that ia
a₁ = 1
a₂ = - 3a₁ - 3 = - 3(1) - 3 = - 3 - 3 = - 6
a₃ = - 3a₂ - 3 = - 3(- 6) - 3 = 18 - 3 = 15
a₄ = - 3a₃ - 3 = - 3(15) - 3 = - 45 - 3 = - 48
a₅ = - 3a₄ - 3 = - 3(- 48) - 3 = 144 - 3 = 141
simplify (a+1/a)^2-(a-1/a)^2
At a university, 34% of undergraduate students love spicy food, while 45% of graduate students love spicy food. Let P hat Subscript u and P hat Subscript g be the sample proportions of undergraduate and graduate students at this university, respectively, who love spicy food. Suppose 35 undergraduate students and 28 graduate students from this university are selected at random and asked if they love spicy food.
Which of the following is the correct calculation and interpretation of the standard deviation of the sampling distribution of P hat subscript u Baseline minus p hat subscript Upper G ?
The difference (undergraduate students – graduate students) in the sample proportions of those who love spicy food typically varies about 0.006 from the true difference in proportions.
The difference (undergraduate students – graduate students) in the sample proportions of those who love spicy food typically varies about 0.015 from the true difference in proportions.
The difference (undergraduate students – graduate students) in the sample proportions of those who love spicy food typically varies about 0.078 from the true difference in proportions.
The difference (undergraduate students – graduate students) in the sample proportions of those who love spicy food typically varies about 0.123 from the true difference in proportions.
Therefore, 65% of all nurses have a starting salary, z = invNorm(0.35) ≈ -0.3853 and z = (41861.5 - 67694) / 10333 ≈ -2.49.
b) We need to find P(X ≥ 78371.8). To do this, we can standardize the value using the formula z = (x - μ) / σ, where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation. Then we can look up the probability in a standard normal distribution table or use a calculator.
\(z = (78371.8 - 67694) / 10333 \approx 1.04\)
Using a standard normal distribution table or calculator, we find that P(Z ≥ 1.04) ≈ 0.1492. Therefore, the probability that a randomly selected nurse has a starting salary of 78371.8 dollars or more is about 0.1492.
c) We need to find P(X ≤ 91407.1). Again, we can standardize the value and look up the probability in a standard normal distribution table or use a calculator.
\(z = (91407.1 - 67694) / 10333 \approx 2.30\)
Using a standard normal distribution table or calculator, we find that P(Z ≤ 2.30) ≈ 0.9893. Therefore, the probability that a randomly selected nurse has a starting salary of 91407.1 dollars or less is about 0.9893.
d) We need to find P(78371.8 ≤ X ≤ 91407.1). We can standardize the values and use a standard normal distribution table or calculator to find the probability.
z1 = (78371.8 - 67694) / 10333 ≈ 1.04
z2 = (91407.1 - 67694) / 10333 ≈ 2.30
Using a standard normal distribution table or calculator, we find that P(1.04 ≤ Z ≤ 2.30) ≈ 0.4657. Therefore, the probability that a randomly selected nurse has a starting salary between 78371.8 and 91407.1 dollars is about 0.4657.
e) We need to find P(X ≤ 41861.5). Again, we can standardize the value and use a standard normal distribution table or calculator.
z = (41861.5 - 67694) / 10333 ≈ -2.49
Using a standard normal distribution table or calculator, we find that P(Z ≤ -2.49) ≈ 0.0062. Therefore, the probability that a randomly selected nurse has a starting salary that is at most 41861.5 dollars is about 0.0062.
f) Yes, a starting salary of 41861.5 dollars is unusually low for a randomly selected nurse. This is because the probability of getting a starting salary at or below this value is very small, as we calculated in part (e).
g) We want to find the value x such that 65% of all nurses have a starting salary greater than x. This means we need to find the 35th percentile of the distribution, which we can do using a standard normal distribution table or calculator.
z = invNorm(0.35) ≈ -0.3853
Using the formula z = (x - μ) / σ, we can solve for x:
-0.3853 = (x - 67694) / 10333
x - 67694 = -0.3853 * 10333
x ≈ 63757.72
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