When negative charges concentrate at one end of an object that is made of a conducting material, the object is

Answer:

about 2s or 3s,

Explanation:

15 m/s - 9.8 m/s = 5.2 m/s (1 sec)

5.2 m/s - 9.8 m/s = -4.6 m/s (2 sec)

Answer:2.01201

Explanation:

Answer:

69.42 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (vᵢ ) = 4.9 m/s

Acceleration (a) = 4.2 m/s²

Time (t) = 4.7 s

Displacement (Δx) =?

Thus, we can obtain the displacement by using the following formula:

Δx = vᵢt + ½at²

Δx = (4.9 × 4.7) + (½ × 4.2 × 4.7²)

Δx = 23.03 + (2.1 × 22.09)

Δx = 23.03 + 46.389

Δx = 69.419 ≈ 69.42 m

Thus, the distance travelled is 69.42 m

When starting a single-speed bicycle, you have to push harder on the pedals to overcome the initial inertia and get the bike moving from a stationary position.

When starting a single-speed bicycle, you have to push harder is because the bike has to overcome the force of friction between the tires and the ground, as well as any other resistive forces like air resistance or the weight of the bike and rider.

Once the bike is in motion, however, it requires less force to maintain a constant velocity because the bike has already overcome the initial inertia and has momentum working in its favor. As long as the resistive forces like air resistance and friction are not too strong, the bike can continue to move at a constant velocity with relatively little effort from the rider.

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The statement that describes what the hand shows is:

"When the current flows up the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire."

The angular velocity of the propeller in radians per second is 125.66 rad/s.

To convert revolutions per minute to radians per second, we need to multiply by 2π/60. Therefore:

Angular velocity = (1200 rev/min) x (2π/60) = 125.66 rad/s

So the angular velocity of the propeller is 125.66 rad/s.

The angular velocity is a measure of the rate of rotation of an object. In this case, the propeller is rotating at a high speed of 1200 revolutions per minute, which corresponds to an angular velocity of 125.66 rad/s. This high angular velocity is necessary to provide the necessary thrust for the fighter plane to fly at high speeds and perform various maneuvers.

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Answer:

Explanation:

Use the kinematic formula:

\(V_f=V_i+at\)

\(V_f=(40m/s)+(10m/s^2)(6s)\)

\(V_f=40m/s+60m/s\)

\(V_f=100m/s\)

Answer:

Friction

Explanation:

In the event that the power is applied toward the path inverse to the bearing of movement, it goes against the movement of the item and henceforth the speed of the article diminishes.

Then, in the event that the thing continues to move one way, grinding will dominate and go about as the moving variable.

So, the moving factor would be friction.

We cannot determine the speed at which a star in the galaxy is moving away from us based on its mass, luminosity, age, or color alone. it is false

The speed at which a star in the galaxy is moving away from us is determined through the measurement of its spectrum using a technique known as redshift.

When a star or galaxy moves away from us, its light is shifted towards longer wavelengths, resulting in a redshift. By analyzing the degree of redshift, astronomers can estimate the speed at which the star is receding.

However, factors such as mass, luminosity, age, and color do not provide direct information about the star's motion away from us.

These characteristics are important for studying other properties of stars, such as their composition, brightness, evolutionary stage, and temperature. To determine the motion of a star in the galaxy, redshift measurements are essential.

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Answer:

Explanation:

Let's analyze the situation presented in order to know which answer is correct.

When the stick collides with the puck, it exerts a force for a certain time and discants. / After this time the horizontal force decreases to zero and the disk continues to move by the action of the initial velocity on the x axis and the acceleration of gravity on the y axis.

Therefore, after the collision, the only force that acts on the disk is the gravitational attractive force (WEIGHT), directed on the axis and in a negative direction.

The correct answer is:

C)           Since there is no frictional force exerted on the puck, a normal force is not exerted on the puck, but the gravitational force is exerted on the puck

(a) The electric dipole moment is 3.46 x 10-29 C*m in size.

(b) The potential energy of dipoles with parallel and antiparallel orientations to E differ by 9.91 x 10-20 J.

In order to determine the dipole moment, we utilize the equation p = qd, where q denotes the charge and d is the separation between the charges. The result is that p = 3.80 nC x 9.10 um = 3.46 x 10-29 C*m.

We apply the equation U = -pEcos, where cos = cos(180°) - cos(0°) = -1, to determine the difference in potential energy. When the values are plugged in, we get U = - (3.46 x 10-29 C*m) x (1260 N/C) x (-1) = 9.91 x 10-20 J. This is the energy needed to change the dipole's orientation with regard to the electric field from one that is antiparallel to one that is parallel.

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Answer:

E=72000J or 72kj

Explanation:

The formula is E=pt you need to convert your t from minutes to seconds before proceeding

The parametric equations for the line are:Hence, the vector equation and parametric equations for the line are: The vector equation for the line can be written as: Comparing the above equation with \(x = −1 3t, y = 6 − 3t, z = 3 7t\)

The vector equation and parametric equations for the line that goes through the point (0, 12, −12) and is parallel to the line x = −1 3t,

y = 6 − 3t,

z = 3 7t are as follows.

Vector equation for the line:

We know that the given line is parallel to x = −1 3t, y = 6 − 3t, z = 3 7t. Hence, the direction vector of the given line will be the same as the direction vector of x = −1 3t,

y = 6 − 3t,

z = 3 7t.

Direction vector of x = −1 3t, y = 6 − 3t, z = 3 7t is given by the following vector:

Therefore, the vector equation of the line that passes through (0, 12, −12) and is parallel to x = −1 3t, y = 6 − 3t, z = 3 7t is:

Parametric equations for the line:

The vector equation for the line can be written as:

Comparing the above equation with x = −1 3t, y = 6 − 3t, z = 3 7t,

Therefore, the parametric equations for the line are:

Hence, the vector equation and parametric equations for the line are:

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The remaining area of the square is (768 - 4π) in².

The area of the square before any circles are removed is given by the formula A = s², where A is the area and s is the length of a side of the square. If we remove four circles, each with a radius of 2 inches, from the square, we are essentially removing a square that has sides equal to the diameter of the circles (which is 4 inches) from each corner of the original square.

The area of each circle is given by the formula A = πr², where A is the area and r is the radius. Substituting r = 2, we get A = 4π. The area of each square that is removed is given by the formula A = s², where s is the length of a side of the square. Since s = 4 inches (the diameter of the circle), we get A = 16 in².

Therefore, the total area of the four squares that are removed is 4 x 16 = 64 in², and the total area of the four circles that are removed is 4 x 4π = 16π in². The area of the remaining square is the original area minus the area of the four squares that were removed and the area of the four circles that were removed.

Substituting the values, we get:

A = s² - 64 - 16π

A = (4s²)/4 - 64 - 16π

A = 4(s²/4 - 16 - 4π)

A = 4((s² - 64) - 4π)

A = 4((16²) - 64) - 4π)

A = 4(256 - 64) - 4π

A = 4(192) - 4π

A = 768 - 4π

The complete question is

Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square?

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Once the engine has fired, the rocket's final speed is 29.16 m/s whose impulse is of 3.5 kgm/s and mass is 120g.

We match the momentum data to the amount of movement using the momentum and amount of movement concept to determine the speed.

Given the mass of rocket (m) = 120g = 0.12kg

Impulse of engine (I) = 3.5kg-m/s

Let the final speed of rocket = v

We know that Impulse is equal force multiplied by time. I = F x t

Then, impulse can also be calculated mass multiplied by velocity according to momentum of rocket. So, I = m x v

Then, m x v = I

Here we neglect the weight force during the brief engine firing as well as the change in mass that occurs.

v = 3.5/0.12 = 29.16m/s

Hence once the engine has fired, the rocket's final speed is 29.16 m/s.

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complete question: Model rocket engines are rated by the impulse that they deliver when they fire. A particular engine is rated to deliver an impulse of 3.5 kg⋅m/s. The engine powers a 120g rocket, including the mass of the engine. Part A What is the final speed of the rocket once the engine has fired? (Ignore the change in mass as the engine fires and ignore the weight force during the short duration of the engine firing.)

Answer:

1 gm

Explanation:

.05 g/cm^3   *  20 cm^3 =   1 gm

Answer:

yes

Explanation:

its awesome

Answer:

P = 22 watts

Explanation:

Given that,

The output power of the generator = 2 a

The output potential difference = 11 V

We need to find the output power of the generator. The formula for the output power is given by :

\(P=V\times I\\\\P=11\times 2\\\\P=22\ W\)

So, the output power of the generator is equal to 22 Watts.

The net force required to accelerate a car is 6000 N.

Force is defined as the product of the mass and acceleration of the body. Force is used to changing the velocity that is to accelerate an object or a body of a particular mass. The unit of Force is Newton or kg m/s^2.

The formula used to calculate the net force is :

F = ma

where, F = Force

m = mass = 2000 kg

a = acceleration = 3.00 m/s^2

∴ F = 2000*3

F = 6000 N

Thus, to accelerate the car at 3.00 m/s^2 of mass 2000 kg net force required is 6000 N.

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The velocity of the 10-kg object is 4 m/s in the positive x-direction.

To solve the problem, we can use the conservation of momentum and the conservation of energy principles. Initially, the spring is compressed and both objects are at rest. When the spring is released, it exerts a force on both objects, causing them to move in opposite directions. As there is no external force acting on the system, the momentum is conserved. Similarly, the total mechanical energy of the system is conserved as there is no energy dissipation due to friction.

Let the velocity of the 10-kg object be v. Using the conservation of momentum, we have:

5 kg * (-8 m/s) + 10 kg * v = 0

Solving for v, we get:

v = 4 m/s

Thus, the velocity of the 10-kg object is 4 m/s in the positive x-direction, which is half of the velocity of the 5-kg object in the negative x-direction.

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Answer:

E = 2.7 x 10¹⁶ J

Explanation:

The release of energy associated with the mass can be calculated by Einstein's mass-energy relation, as follows:

\(E = mc^2\)

where,

E = Energy Released = ?

m = mass of material reduced = 0.3 kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

\(E = (0.3\ kg)(3\ x\ 10^8\ m/s)^2\)

E = 2.7 x 10¹⁶ J

Answer:

Distance travelled is 7 meters and the displacement is 3 meters

Answer:

C. diet pills

Explanation:

Diet pills affect the body and they can cause serious side effects.

Diet pills represent the type of diet that would most likely cause these types of health problems or difficulties (Option C).

Diet pills are different types of medications that can be used to reduce weight and improve the physical body state.

In conclusion, diet pills represent the type of diet that would most likely cause these types of difficulties (Option C).

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1. To find the time when the body reaches the ground, we can use the vertical motion equation:

h = v₀y * t + (1/2) * g * t²

where:

h = height of the tower = 15m

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

t = time

Plugging in the values:

15 = (30 * sin(30°) * t) + (0.5 * 9.8 * t²)

Simplifying the equation:

15 = 15t * 0.5t² + 4.9t²

Combining like terms:

15 = 7.5t² + 4.9t²

Simplifying further:

15 = 12.4t²

Dividing both sides by 12.4:

t² = 15 / 12.4

Taking the square root of both sides:

t = √(15 / 12.4)

Calculating the value:

t ≈ 1.01 seconds

Therefore, the time it takes for the body to reach the ground is approximately 1.01 seconds.

2. To find the displacement vector, we need to calculate the horizontal and vertical components separately.

Horizontal component:

The horizontal displacement can be calculated using the formula:

x = v₀x * t

where:

v₀x = initial horizontal velocity = v₀ * cos(θ) = 30m/s * cos(30°)

t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)

Plugging in the values:

v₀x = 30m/s * cos(30°)

t = 1.01 seconds

Calculating the value:

v₀x ≈ 26.02 m/s

Vertical component:

The vertical displacement can be calculated using the formula:

y = v₀y * t + (1/2) * g * t²

where:

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)

Plugging in the values:

v₀y = 30m/s * sin(30°)

t = 1.01 seconds

Calculating the value:

v₀y ≈ 15 m/s

Now we have the horizontal and vertical components of the displacement vector:

Horizontal component: x ≈ 26.02 m/s

Vertical component: y ≈ 15 m/s

Therefore, the displacement vector of the body is approximately (26.02 m/s, 15 m/s).

3. To find the angle when the body hits the ground, we can use the vertical and horizontal components of the velocity.

The horizontal component of the velocity, v₀x, can be calculated using the formula:

v₀x = v₀ * cos(θ)

where:

v₀ = initial velocity = 30m/s

θ = angle of projection = 30 degrees

Plugging in the values:

v₀x = 30m/s * cos(30°)

Calculating the value:

v₀x ≈ 26.02 m/s

The vertical component of the velocity, v₀y, can be calculated using the formula:

v₀y = v₀ * sin(θ)

where:

v₀ = initial velocity = 30m/s

θ = angle of projection = 30 degrees

Plugging in the values:

v₀y = 30m/s * sin(30°)

Calculating the value:

v₀y ≈ 15 m/s

Now, to find the angle when the body hits the ground, we can use the inverse tangent function:

θ = arctan(v₀y / v₀x)

Plugging in the values:

θ = arctan(15 m/s / 26.02 m/s)

Calculating the value:

θ ≈ 30.96 degrees

Therefore, the angle when the body hits the ground is approximately 30.96 degrees.

4. To find the maximum height, we can use the vertical motion equation:

h = v₀y² / (2 * g)

where:

h = maximum height

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

Plugging in the values:

h = (30 * sin(30°))² / (2 * 9.8)

Calculating the value:

h ≈ 27.55 meters

Therefore, the maximum height reached by the body is approximately 27.55 meters.

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Explanation:

Starting position at x  = 16m

Ending position at x  = -25m

Time of flight  = 4s

Unknown:

Distance flown  = ?

Displacement  = ?

Speed  = ?

Velocity  = ?

Solution:

To find the distance flown, we should understand that the body is moving on the x - plane;  

  So distance  = 16 + 25  = 41m

Displacement is 41m to the left or -x axis

Speed is the distance divided by the time taken;

      Speed  = \(\frac{distance}{time}\)   = \(\frac{41}{4}\)   = 10.25m/s

Velocity is 10.25m/s along -x axis

Answer:

2.56 N/m

Explanation:

The force exerted by a spring is given by the equation:

\(F_s = kx\)

where \(k\) is the spring constant, and \(x\) is the distance that the spring is stretched or compressed from its equilibrium.

To find \(x\), we will simply subtract the spring's initial position from its final position:

\(x = 1.50 m - 0.25 m\\x = 1.25 m\)

It is given in the problem that the force exerted by the spring is 3.20 Newtons. So, we can solve the equation for \(k\) and calculate the spring constant.

\(k = \frac{F_s}{x} \\k = \frac{3.20N}{1.25m} \\k = 2.56 N/m\)