When the overhead lights are turned on, the light rays from the bulbs spread out and fill the room. However, the light rays do not fill the room evenly, because the bulbs emit light in all directions and not all directions are equally filled by the light.
When light rays meet at different points in space, they can either interfere constructively or destructively. Constructive interference occurs when the light rays reinforce each other, resulting in a brighter spot. Destructive interference occurs when the light rays cancel each other out, resulting in a dark spot.
In a room with overhead lights, the light from the bulbs is mostly in the form of parallel rays that do not interact with each other. However, there may be some areas where the light rays from the bulbs intersect, such as where a wall or a piece of furniture is in the way. If the light rays intersect at the same point in space and are in phase (meaning they are in the same position relative to each other), they will reinforce each other and produce a bright spot. If they intersect at the same point in space but are out of phase, they will cancel each other out and produce a dark spot.
Because the light rays are mostly parallel and do not interact with each other, there are not usually random black or bright spots where light has destructively or constructively interfered. However, there may be some minor variations in the intensity of the light in the room due to the way the light rays interact with the walls and other objects in the room.
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Bill Nye- Static Electricity Answer Key?
which process receives geo thermal energy naturally
Please for the love of humanity please answer this question and my other question...
Answer:
It's "C"
Explanation:
Friction slows things down.
"Friction always slows a moving object down. The amount of friction depends on the materials from which the two surfaces are made. The rougher the surface, the more friction is produced. Friction also produces heat. "
When the permanent magnet field type DC motor is not connected to the power, the rotor
When rotating at 500[rpm], the induced electromotive force generated in a armature winding is 30[V].
When a current of 1.5[A] is input to the armature winding of the DC motor,
How much torque is generated?
( assume pie=3 in the calculation )
Expert Answer
To calculate the torque generated by the DC motor, we can use the following formula:
Torque (τ) = (Power (P) / Angular velocity (ω))
First, we need to calculate the power generated by the motor using the induced electromotive force (EMF) and the current.
Power (P) = EMF * Current
Substituting the given values:
Power (P) = 30[V] * 1.5[A] = 45[W]
Next, we need to convert the rotational speed from RPM to rad/s.
Angular velocity (ω) = (500[rpm] * 2π) / 60 = 52.36[rad/s]
Now, we can calculate the torque:
Torque (τ) = 45[W] / 52.36[rad/s] = 0.859[Nm]
Therefore, the torque generated by the DC motor when a current of 1.5[A] is input to the armature winding is approximately 0.859 Nm.
It's important to note that the torque calculation assumes ideal conditions and neglects any losses or inefficiencies in the motor. In practical applications, there may be additional factors to consider.
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A cylindrical pulley with a mass of 7.7 kg, radius of 0.532 m and moment of inertia 1/2 M r^2 is used to lower a bucket with a mass of 2.4 kg into a well. The bucket starts from rest and falls for 4.5 s. a) What is the linear acceleration of the falling bucket? The acceleration of gravity is 9.8 m/s^2. Answer in units of m/s^2. b) How far does it drop? Answer in units of m. c) Find the angular acceleration of the cylinder. Answer in units of rad/s22.
The linear acceleration of the falling bucket can be calculated using the formula.
a = g - (T/M)
where g is the acceleration of gravity (9.8 m/s²), T is the torque exerted by the pulley (T = Iα, where I is the moment of inertia, and α is the angular acceleration), and M is the mass of the bucket. We can calculate the torque of the pulley by substituting the given values:
T = (1/2 M r²) * (α)
T = (1/2) * (7.7 kg) * (0.532 m)² * (α)
T = 2.01 (kg m²) * (α).
Therefore,
a = 9.8 m/s² - (2.01 (kg m^2) * (α) /2.4 kg)
a = 9.58 m/s²
The distance traveled by the bucket can be calculated using the formula
d = (1/2) * a * t²
where a is the acceleration of the bucket (9.58 m/s²) and t is the time it takes to fall (4.5 s).
Therefore,
d = (1/2) * (9.58 m/s²) * (4.5 s)²
d = 98.2 m
The angular acceleration of the cylinder can be calculated using the formula
α = T/I
where T is the torque exerted by the pulley (2.01 (kg m²) * (α)) and I is the moment of inertia (1/2 M r²).
Therefore,
α = 2.01 (kg m²) * (α) / (1/2) * (7.7 kg) * (0.532 m)²
α = 10.3 rad/s²
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Two circuits have identical voltage sources. The only other elements in the circuits are resistors. The resistor in circuit A has a resistance that is one half as large as the resistance of the resistor in circuit B (RA= RB). Which statement below best describes the current flowing through the two circuits? (Ohm's law: V = IR)
The correct statement that describes the current flowing through the two circuit based on Ohm's Law is "The current flowing through circuit A is 1/4th or 0.25 times as large as the current flowing through circuit B."
Why is the current flowing through circuit A 1/4 as large as the current flowing through B when we consider Ohm's Law ?Ohm's Law states that the voltage (V) across a resistor is equal to the current (I) flowing through it times its resistance (R) ⇒ V = I × R.
We rearrange this equation to solve for current, ⇒ I = V / R
This tells you that the current is inversely proportional to the resistance.
So, in the case of two circuits with identical voltage sources, if the resistance in circuit A (RA) is four times largr than the resistance in circuit B (RB), the current in circuit A (IA) will be a quartr of the current in circuit B (IB).
The above answer is based on the full question below;
Two circuits have identical voltage sources. The only other elements in the circuits are resistors. The resistor in circuit A has a resistance that is four times as large as the resistance of the resistor in circuit B (RA = 4RB ). Which statement below best describes the current flowing through the two circuits? (Ohm's law: V = IR) A. The current flowing through circuit A is as large as the current flowing through circuit B. B. The current flowing through circuit A is 2 times as large as the current flowing through circuit B. C. The current flowing through circuit A is 4 times as large as the current flowing through circuit B. D. The current flowing through circuit A is as large as the current flowing through circuit B.
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a resistance of 325 n is raised by using a ramp 5.76 m long and by applying a force of 75.0 n. how high, in meters, can it be raised?
A resistance of 325 n is raised by a ramp 5.76 m long and a force of 75.0 n. 1.32 m high, in meters, can be raised.
H=Fe*L/Fr
H = 75 x 5.76/325
H = 1.32 m
A circuit's resistance to current flow is measured by its resistance. The Greek letter omega () stands for ohms, which is used to measure resistance. Ohm defines the measure of resistance "1 Ohm" as the distance between two points of a conductor at which 1 volt causes a flow of 1 ampere or 6.241 1018 electrons. The Greek letter "," also known as omega and pronounced "ohm", is usually used in schematics to indicate this number. Much like batteries are used to change the flow of tap water, resistors are used in electrical circuits to adjust current and voltage. They can be used in a circuit to distribute voltage and control current flow.
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ice crystals that form by accretion are fairly large. explain why they fall slowly.
Ice crystals that form by accretion are fairly large, they fall slowly because of there high surface area to volume ratio, which cause high air resistance.
Ice crystals that form by accretion are large and have a high surface area to volume ratio. This high surface area causes more air resistance, which slows their fall. The larger the surface area, the more air resistance there is, and the slower the crystals fall. Additionally, the shape of the crystals can also affect their fall speed, with more irregular shapes experiencing more air resistance and thus falling slower. Ice crystals are the building blocks of snowflakes and have a well-defined and ordered internal structure. The structure of an ice crystal depends on the conditions under which it forms, such as temperature and humidity. At very cold temperatures, the crystals are usually simple hexagonal structures, while more complex branching structures can form at warmer temperatures.
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Objects in motion tend to stay in motion in a straight line at a constant velocity unless acted on by a(n) force
Answer:
Newton's first law of motion
Explanation:
Newton's first law of motion states that an object will continue to remain at rest or move with uniform motion unless it is acted upon by an external force.
This law is known as the law of inertial.
Unless a net force greater than zero acts on a body, it will continue to remain at rest or move uniformly.
This is very correct and has a wide range of application for many mechanics studies. In that we know that an object can only change motion or accelerate by adding external force to act on it.
Cars B and C are identical, each weighing 2820 lb (including driver), driving at the exact same speed of 58.5 ft/s on the same road that has coefficients of riction µs = 0.855 and µk = 0.715. Car B is at the bottom of a dip (radius = 775 ft) at exactly the same time car C is at the crest of a hill (radius also = 775 ft) when both drivers slam on their brakes simultaneously and both cars begin to slide
(they do not have anti-lock brakes).
a) What is the tangential acceleration (i.e., the
acceleration parallel to the road) of each car as it slides on the road at the positions described?
b) What is the magnitude of the total force that the road exerts on each car?
The tangential acceleration (i.e., the acceleration parallel to the road) of each car as it slides on the road at the positions described is -6.61 ft/s². Weight of car = 2820 lbSpeed of cars = 58.5 ft/s. Coefficient of friction,μs = 0.855μk = 0.715.
Radius of the dip, r = 775 ft.a) What is the tangential acceleration (i.e., the acceleration parallel to the road) of each car as it slides on the road at the positions described?Now, we need to find the tangential acceleration of each car during sliding.Let F be the frictional force exerted by the road on the car.Using, the following formula we can find the force exerted on the cars.
F=μs N = μs m g = 0.855 × 2820 × 32.2 lb = 80445.6 lb.a = F/ma = 80445.6 lb/2820 lba = 28.54 ft/s²The total tangential acceleration is the acceleration due to gravity subtracted by the frictional force, which is as follows,a = -g sinθ - μs g cosθa = -32.2 sin(0) - 0.855 × 32.2 cos(0)a = -27.53 ft/s²The tangential acceleration is,-6.61 ft/s².b) What is the magnitude of the total force that the road exerts on each car?The force acting on the cars can be found by,Force = mass × acceleration (F = ma)Force, F = 2820 × 6.61 lbForce, F = 18,601.4 lb.The force exerted on each car is 18,601.4 lb.
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A 1,100 kg car comes uniformly to a stop. If the vehicle is accelerating at 1.2 m/s", which
force is closest to the net force acting on the vehicle?
Answer:
Gravitaitional pull
Explanation:
Guessing
a narrow slit is illuminated with sodium yellow light of wavelength 589 nm. if the central maximum extends to ±30.0°, how wide is the slit?
Answer:
because of the gravity of the earth
6. A balloon gathers -0.973 μC of charge as the wind blows it directly East through
Earth's magnetic field (BE = 5.01 x 10-5 T). If the magnetic force on the balloon is
8.11 x 10-10 N West.
what is the
velocity of the balloon?
a.-16.6 m/s
c. 8.44 m/s
b. 3.95 x 10-20 m/s
d. 16.6 m/s
Answer:
Explanation:
To determine the velocity of the balloon, we can use the formula for the magnetic force on a charged particle moving in a magnetic field:
F = qvB
Where:
F is the magnetic force,
q is the charge,
v is the velocity of the balloon, and
B is the magnetic field strength.
Given:
F = -8.11 x 10^-10 N (West)
q = -0.973 μC = -0.973 x 10^-6 C (the negative sign indicates the charge is negative)
B = 5.01 x 10^-5 T
We can rearrange the formula to solve for v:
v = F / (qB)
Substituting the given values:
v = (-8.11 x 10^-10 N) / (-0.973 x 10^-6 C * 5.01 x 10^-5 T)
v ≈ 16.6 m/s
Therefore, the velocity of the balloon is approximately 16.6 m/s. Option (d) is the correct answer.
A 4.0 g string, 0.36 m long, is under tension. The string produces a 500 Hz tone when it vibrates in the third harmonic. The speed of sound in air is 344 m/s. In this situation, the wavelength of the standing wave in the string, in SI units, is closest to:
Answer:
\(\lambda = 0.24 m\)
Explanation:
The string vibrates in the third harmonics, n = 3
Length of the string, l = 0.36 m
Frequency of the tone produced, f = 500 Hz
The speed of sound in air is 344 m/s
Calculate the speed of sound produced by the string in the third harmonics:
The frequency of sound is given by the formula:
\(f = \frac{nv}{2l} \\500 = \frac{3v}{2*0.36}\\500 * 2 * 0.36 = 3v\\v = 360/3\\v = 120 m/s\\v = \lambda f\\\lambda = v/f\\\lambda = 120/500\\\lambda = 0.24 m\)
Given:
String vibrates, \(n = 3\)Strings' length, \(l = 0.36 \ m\)Frequency, \(f = 500 \ Hz\)Speed of sound, \(v = 344 \ m/s\)As we know,
→ \(f = \frac{nv}{2l}\)
then,
→ \(500 = \frac{3v}{2\times 0.36}\)
→ \(360 = 3v\)
\(v = \frac{360}{3}\)
\(= 120 \ m/s\)
hence,
The wavelength will be:
→ \(v = \lambda f\)
or,
→ \(\lambda = \frac{v}{f}\)
By substituting the values,
\(= \frac{120}{500}\)
\(= 0.24 \ m\)
Thus the approach is correct.
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Sound waves move the fastest through which medium?
Answer:
Sound travels fastest through solids.
Explanation:
This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.
Sound waves move the fastest through the solid. The speed of the sound wave in the liquid and gas is low,
What is sound wave?A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.
Solids transmit sound the fastest. Because the molecules in a solid medium are much closer together than in a liquid or gas, sound waves can move through it much faster.
Hence, sound waves move the fastest through the solid.
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The amount of air drag on an 0. 8n flying squirrel dropping vertically at terminal velocity is.
The amount of air drag on an 0. 8N flying squirrel dropping vertically at terminal velocity is 0.8N.
The terminal velocity is the highest constant velocity attained by a body when falling through a viscous medium.When the force of resistance of a medium equals and opposes the force of gravity, it is said to be accomplished.It is seen that the sum total of the buoyancy and drag force is equal to the force of gravity moving downward affecting the object. The acceleration of the object is considered as zero since the net force affecting the object is zero. An object is considered to be moving at terminal velocity in fluid dynamics if its speed remains constant, a restraining force put on it by the fluid in which it is moving.To know more about air drag visit:
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what is the relationship between mass and acceleration on an object when the force is held constant?
Answer:
according to newtons second law of motion,
Force = mass * acceleration
The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body.
I. e mass and acceleration are directly proportional to each other.
Gibbs sum for ideal gas. (a) With the help of Zn = (nov)N/N! from Chapter 3, show that the Gibbs sum for an ideal gas of identical atoms is Z = exp(an,V). (b) Show that the probability there are N atoms in the gas in volume V in diffusive contact with a reservoir is P(N) = (N)\exp(-(N>)/N!, (82) which is just the Poisson distribution function (Appendix C). Here (N) is the thermal average number of atoms in the volume, which we have evaluated previously as (N) = 1Vno. (c) Confirm that P(N) above satisfies P(N) = 1 and ļNP(N) = (N).
Gibbs sum for an ideal gas of identical atoms is Z = exp(an,V), using the expression Zn = (nov)N/N! from Chapter 3.
What is Probability?
Probability is a measure of the likelihood of an event occurring, expressed as a number between 0 and 1, where 0 indicates that the event is impossible and 1 indicates that the event is certain. It is a fundamental concept in mathematics and statistics that is used to analyze and predict the outcomes of uncertain events.
The probability of N atoms in the gas in volume V is given by P(N) = (N)exp(-(N>)/N!, which is the Poisson distribution function. Here, (N) is the thermal average number of atoms in the volume, previously evaluated as (N) = 1Vno.
(c) P(N) satisfies P(N) = 1 and ļNP(N) = (N).
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What is the velocity of a car that travels 400meters in 16 seconds
Answer:
The answer is 25 m/sExplanation:
The velocity of the car can be found by using the formula
\(v = \frac{d}{t} \\ \)
d is the distance
t is the time taken
From the question we have
\(v = \frac{400}{16} \\ \)
We have the final answer as
25 m/sHope this helps you
The Weight of an object is more at pole and less at equator of the earth. Give reason
The Weight of an object is more at pole and less at equator of the earth because the distance of the pole is less than the distance of the equator from the centre of the earth.
A 1. 2-m3 rigid tank contains nitrogen gas at 200 kpa and 350 k. Heat is transferred to the nitrogen in the tank and the pressure of nitrogen rises to 900 kpa. Determine the work done during this process.
Using the concepts of work, we got that 0 joule is the amount of the work done during the process in which 1.2-m3 rigid tank contains nitrogen gas at 200 kpa and 350 k and heat is transferred to the nitrogen in the tank and the pressure of nitrogen rises to 900 kpa.
We are given some values of the rigid tank which are
Volume of the tank (V) = 1.2 m³
Initial pressure of the nitrogen (P₁) = 200 kPa
Initial temperature of the nitrogen (T₁) = 350 K
Final pressure of the nitrogen (P₂) = 900 kPa
The volume of nitrogen gas is same as volume of tank. Now, as the tank is rigid so, the volume of nitrogen gas remains the same.
We know that,
Work done on a gas is given as: PΔV
Where, ΔV is the change in volume.
But, the volume here is constant. So, ΔV = 0.
Therefore, work done=P×0=0Joules.
Hence, if 1. 2-m3 rigid tank contains nitrogen gas at 200 kpa and 350 k and Heat is transferred to the nitrogen in the tank and the pressure of nitrogen rises to 900 kpa, then the work done during this process is 0 joules.
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what is the hidden gene called
What is the current in a 110V circuit with resistance is 10Ω?
Answer:
using V= IR
I= 11Ampere
point p divides the directed line segment from point a(-4 -1) to ppoint b(6,4) in the ratio 2:3. the coordinates of point p are
The coordinates of point P has coordinates (0,1).
It can be found by using the ratio formula for dividing a line segment, which states that the coordinates of the point dividing the line segment AB in the ratio m:n are given by the formula:
P(x,y) = ((n*x1)+(m*x2))/(m+n), ((n*y1)+(m*y2))/(m+n)
where A(x1,y1) and B(x2,y2) are the given endpoints of the line segment, and m:n is the ratio in which the segment is divided.
Using this formula with the given coordinates of A(-4,-1), B(6,4) and the ratio 2:3, we get:
P(x,y) = ((3*(-4))+(2*6))/(2+3), ((3*(-1))+(2*4))/(2+3)
P(x,y) = (-12+12)/5, (-3+8)/5
P(x,y) = 0, 1
Therefore, the coordinates of point P are (0,1).
Hence , using the formula with the given values, we found that point P has coordinates (0,1).
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What was one benefit that the louisiana purchase provided for the united states?
The Louisiana Purchase eventually doubled the size of the United States, significantly strengthened it militarily and strategically, spurred the country’s westward expansion, and established the federal Constitution’s doctrine of implied powers.
Prior to 1803 there had been considerable Old-World interest in the Louisiana Territory. France had gained authority over the river and ownership of the majority of the Mississippi valley thanks to explorations and sporadic colonies in the 17th and 18th centuries.
The greatest land deal in American history was the Louisiana Purchase, when the United States acquired the western half of the Mississippi River basin from France in 1803 for less than three cents per acre, or 828,000 square miles (2,144,520 square kilometers).
The acquisition increased the United States’ size by twofold.
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if the pressure at b is atmospheric, determine the pressure at point (0.5 m, 0)
To determine the pressure at point (0.5 m, 0) when the pressure at point B is atmospheric, we will use the hydrostatic pressure formula.
Here's the step-by-step explanation:
Step 1: Identify the given information.
- Pressure at point B (P_B) = atmospheric pressure
- Point A coordinates: (0.5 m, 0)
Step 2: Use the hydrostatic pressure formula.
The hydrostatic pressure formula is: P_A = P_B + ρgh
Where:
- P_A is the pressure at point A
- P_B is the pressure at point B
- ρ (rho) is the fluid density
- g is the acceleration due to gravity (approximately 9.81 m/s²)
- h is the height difference between point A and point B
Step 3: Determine the height difference (h) between points A and B.
Since the point A is at a horizontal position (0.5 m, 0), there is no height difference between point A and point B. Thus, h = 0.
Step 4: Substitute the values into the formula.
P_A = P_B + ρgh
P_A = atmospheric pressure + ρ × 9.81 m/s² × 0
Since h = 0, the second term becomes zero.\
Step 5: Solve for the pressure at point A.
P_A = atmospheric pressure
Therefore, the pressure at point (0.5 m, 0) is equal to the atmospheric pressure since there is no height difference between the two points.
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if a loud machine produces sounds with an intensity level of 110db , what would the intensity level be if the intensity were reduced by a factor of 5?
If the intensity of the loud machine were reduced by a factor of 5, the new intensity level would be 90 dB.
This can be calculated using the formula for decibel levels, which states that the difference in decibel levels is equal to 10 times the logarithm of the ratio of the two intensities. So, if the original intensity level was 110 dB, reducing it by a factor of 5 would result in a new intensity level that is 10 times lower, which is equivalent to a reduction of 20 dB. Therefore, the new intensity level would be 90 dB (110 dB - 20 dB = 90 dB).
If a loud machine produces sounds with an intensity level of 110 dB and the intensity is reduced by a factor of 5, the new intensity level can be calculated using the decibel formula: dB = 10 * log10(I/I₀), where I is the intensity and I₀ is the reference intensity. First, find the original intensity (I) using the inverse formula: I = I₀ * 10^(dB/10). Then, divide the original intensity by 5 and use the decibel formula again to find the new intensity level. The new intensity level will be lower than the initial 110 dB due to the reduced intensity of the sound.
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How much GPE is stored when an 80kg astronaut climbs to the top of a 5m high lunar lander? The gravity strength on the moon is 1.6N/kg.
Answer:
The GPE, stored is 640 Joules
Explanation:
The given parameters are;
The given mass of the astronaut, m = 80 kg
The height of the top of the lunar lander to which the astronaut climbs, h = 5 m
The gravity strength on the moon, g = 1.6 N/kg
The Gravitational Potential Energy, GPE, stored is given according to the following equation;
GPE stored = m·g·h
Therefore, by substituting the known values, we have;
GPE Stored = 80 kg × 1.6 N/kg × 5 m = 640 Joules
The GPE, stored = 640 Joules.
Delphina and Oribus are the same distance from the equator, and they are both near the ocean. Using the information in the map, what is likely to be true about the air temperature of the two places? Why?
The image of the map is missing, so i have attached it.
Answer:
The air temperature at oribus is warmer than the air temperature at Delphina.
Explanation:
Looking at the map, we can say that he wind will push ocean water that is turning and passing the coasts. Now, as a result, Energy will be transferred from the ocean to the air at Oribus and whereas energy is transferred from the air to the ocean at Delphina. Thus, the air temperature at Oribus will be warmer than that at Delphina.
The area of larger piston is 0. 05m2 a force of 100N is applied on the smaller piston. How much force force is produced produced on the larger piston
The force produced on the larger piston is 2500N.
The force exerted on a fluid in a closed system is transmitted equally in all directions, according to Pascal's Principle. In this case, the force of 100N applied on the smaller piston will be transmitted equally to the larger piston through the hydraulic fluid.
The ratio of the areas of the larger and smaller piston is 0.05m² / x m², where x is the area of the smaller piston. We can solve for x by setting the ratio equal to the force ratio:
0.05m² / x m² = F2 / F1where F1 is the force applied on the smaller piston (100N) and F2 is the force produced on the larger piston.
Solving for x, we get:
x = 0.0025m²Using the same equation and plugging in the values for F1, F2, and the areas of the pistons, we get:
0.05m² / 0.0025m² = F2 / 100NF2 = 2500NTherefore, the force produced on the larger piston is 2500N.''
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