When the sum of all the forces acting on a block on an inclined plane is zero, the block
A) must be at rest
B) must be accelerating
C) may be slowing down
D) may be moving at constant speed

The force of tension in the string at  the lowest point of the circular path is 2.1 N.

The centripetal acceleration of the mass is calculated as follows;

a = v²/r

where;

a = (1.33²) / (0.853)

a = 2.07 m/s²

The force of tension in the string at  the lowest point of the circular path is calculated as follows;

T = ma + mg

T = m(a + g)

where;

T = 0.1773(2.07 + 9.8)

T = 2.1 N

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Answer:

Models change to accommodate new discoveries

Explanation:

Owing to the dynamism of science, scientific models also change to accommodate new ideas and discoveries. Science is not a static body of knowledge. Research consistently brings new information to the fore. This propels a change in certain scientific models to accommodate the new discoveries and present a more accurate representation of phenomena in nature.

Hence, scientific models change to accommodate new discoveries.

Answer:  Models change to accommodate new discoveries.

Explanation: I took the test

Answer:

Explanation:

A leaf appears green becuase of photosyithesis

Milk appears white because all the corols are being aborseb

words on the page are black because all colors are being refcted.

Answer:

hey, please open my account and see my question, please help me solve the task, I have to send it to the teacher soon.

Answer:

When waves are generated and they reflect off a fixed end, the reflected waves are completely out of phase. The reflected waves and the incident waves interfere with each other along the path and results in the formation of nodes and anti-nodes. Nodes are points of completely out of phase interference and anti-nodes are points of completely in phase interference.

The moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.

The moment of inertia of a system about its axis of rotation is the sum of the products of the masses of its constituents and the square of their respective distances from the axis of rotation.

The radius of the rectangular plate is 6 m, and the distance of each particle from the center is half of the sides of the rectangle, which are 4 m and 3 m.

Therefore, using the parallel axis theorem, we get the moment of inertia of the system about the Z-axis as shown below.

\(Iz = ICM + MR^{2}\)

(1)We can obtain the moment of inertia of the rectangle about its center as: \(ICM = (1/12) ML^{2}\)

(2) where M is the mass of the rectangle, and L is the length of the rectangle.

Substituting values, we get: ICM = \((1/12) $\times$ 3.00 $\times$ (4^{2} + 6^{2} )\)

ICM = \(5 kg m^{2}\)

Using the parallel axis theorem, the moment of inertia of the four particles about the center of the rectangle is:

\(IP = 4 $\times$ [(1/12) $\times$ 2.00 $\times$ (4^{2} + 3^{2})] + 2.00 $\times$ (3^{2}) + 4.00 $\times$ (4^{2})IP = 97 kg m^{2}\)

The moment of inertia of the system about Z-axis is: \(Iz = ICM + MR^{2} Iz = 5 kg m^{2} + 3.00 kg $\times$ (6^{2} ) + 4 $\times$ [(4^{2}+ 3^{2} )/4] Iz = 245 kg m^{2}\)

The kinetic energy of a rotating body is given as:\(K.E. = (1/2) I\omega^{2}\) where I is the moment of inertia of the system, and ω is the angular velocity of the system.

The rotational kinetic energy of the system is:\(K.E. = (1/2) I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)

2)\(I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)

Therefore, the moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.

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Explanation:

Without the metric system, we'd have a different International System of Units, the metric system is important because 1mm is 0.1cm, 1 cm is 0.01m, with the imperial system the conversion is tedious. The most important feature of the metric system is its base in scientific fact and repeatable standards of measurement

Answer:

It is A. Light blue

_____________

Hope this helps!

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╭━┻╮╲┗━━━━╮╭╮┈

┃▎▎┃╲╲╲╲╲╲┣━╯┈

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Answer:

As can be seen from the above animation, the package follows a parabolic path and remains directly below the plane at all times.

Explanation:

hope it helps

Answer:

R = 95 km, 30° west of north

Explanation:

You didn't post a figure, but I think I can picture it.

60 west of north = 30 north of west

sin30 = y/95

y = sin30(95) = 47.5

cos30 = x/95

x = cos30(95) = 82.3

∑y = 20 + 47.5 = 67.5

∑x = 82.3

R² = 82.3² + 47.5² = 9029.54

R = √9029.54 = 95 (magnitude of the Resultant vector)

∅ = tan⁻¹ 47.5/82.3 = 30 north of west

Answer:

C

Explanation:

Answer:

160 meters

Relative of speed Vr = 10 -2 = 8 m/s    (horizontal speed)

20 sec * 8 m/s = 160 m      since ball travels 20 sec

Answer:

160 meters

Explanation:

Answer:

25.13274 W (WATT) (Sound Power of the Sound Source)

134.002 dB (Sound Power Level)

The lines of the iron filings illustrate the law of magnetism that like poles repel each other.

The lines of the iron writings illustrate the rule of magnetism that unlike poles attract each other.

Glass or plastic was used to separate the writings from the magnets in the experiments because it is transparent and does not interfere with the magnetic fields.

The glass or plastic did not stop the passage of the magnetic lines of force, but it did contain the iron filings so they could be used to visualize the magnetic field.

The iron filings almost completely bridged the open end of the horseshoe magnet, demonstrating that the magnetic field continues through the gap and connects the two poles.

The most fundamental law of magnetism states that opposite poles attract one another and that like poles repel one another.

This can be observed when trying to align the like poles of two magnets, like poles (north-north; south-south), will repel each other. Unlike poles (north-south) will attract each other

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Given :

A spring has an elastic constant of 8.75 x 10³ N/m.

To Find :

The magnitude of the force required to stretch this spring a distance of 28.6 cm from its equilibrium position.

Solution :

We know, force required to stretch a spring of spring constant k and distance x is given by :

\(F = \dfrac{kx^2}{2}\)

Putting all given values, we get :

\(F = \dfrac{8.75\times 10^3 \times 0.286^2}{2}\\\\F = 357.86\ N\)

Hence, this is the required solution.

Answer: C. A large force over a long distance.

Answer:

The electric field strength at the location of the metal ball bearing is 1.8 * 10^2 N/C.

Explanation:

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The energy went into heating up the air molecules and the pendulum's support structure, as well as into sound waves and other forms of energy that dissipated into the environment.

What is Sound Wave?

A sound wave is a type of mechanical wave that travels through a medium, such as air, water, or solid objects. When an object vibrates, it creates pressure variations in the surrounding medium, which cause particles in the medium to vibrate and transfer energy from one place to another. These pressure variations create compressions and rarefactions in the medium, which are perceived by our ears as sound.

The pendulum stopped swinging because the energy that was initially provided to it was gradually lost to the surrounding air molecules, friction and other forms of resistance, causing the pendulum to gradually slow down and eventually stop.

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In the divergence theorem, F refers to a vector field. The theorem relates a surface integral of the vector field to a volume integral of its divergence over a solid region.

The divergence theorem, also known as Gauss's theorem, relates a surface integral of a vector field to a volume integral of its divergence over a solid region. It is expressed mathematically as:

∫∫(F · dA) = ∫∫∫ (div F dV)

where F is a vector field, div F is its divergence, ∫∫ represents the surface integral over a closed surface, and ∫∫∫ represents the volume integral over the solid region enclosed by the surface. So F refers to a vector field.

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Since, density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.

To know if the bracelet is pure gold, we calculate the density of the bracelet and compare it to the density of pure gold (19.3 g/cm³).

That is, for the bracelet to pure gold,

Density of bracelet ≈ 19.3 g/cm³

Density can be defined as the ratio of the mass and the volume of a substance.

The formula of Density is give as

⇒ Where:

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

Hence, since the density of the bracelet is not equal to the density of gold, then, the bracelet is not pure gold.

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Between 400 nm and 700 nm of the electromagnetic spectrum, vegetation has the strongest response.

The electromagnetic spectrum travels in waves and spans an extensive spectrum from very long radio waves to very brief gamma rays. The human eye can simplest come across only a small portion of this spectrum called visible light.

In order from maximum to lowest power, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible mild, infrared radiation, and radio waves.

In a tumbler, the purple mild travels the fastest, and the violet light travels the slowest of all seven hues. Velocity and wavelength are without delay proportional.

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A state of character arises from the repetition of similar activities

Aristotle was a renowned scientist and philosopher. He has made significant contributions to society. He is renowned for his quotable sayings as well. Because of the correlation between the states of character and the distinctions between them, the behaviors we display must be of a specific type. States of character: The traits that "allow us to stand well or poorly in relation to the passions." Because: We are not commended and criticized only for having the ability to feel pleasure, grief, etc., virtues are not capacities.

Here in this quote, similar behaviors give birth to similar states of character

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Answer:

general steps of performing an autopsy:

1. The body is identified and the relevant information about the deceased is collected.

2. A visual examination of the body is performed to look for any abnormalities or signs of injury.

3. The external examination is followed by an internal examination. The body is opened up to examine the organs, including the brain, heart, lungs, liver, and kidneys, for any signs of disease or injury.

4. The organs are weighed, measured and dissected.

5. Tissue samples are taken and sent for laboratory analysis.

6. The cause of death is determined based on the autopsy findings, and a report is generated.

7. The body is then closed and prepared for release to the family for funeral arrangements.

It is important to note that the specific steps involved may vary depending on the type of autopsy being conducted and the circumstances surrounding the death.

Explanation:

Answer:

Thirty years ago, the culture of American sports took a new course. An idea shouldered by a former sports communication executive, along with his son and other partners, would go on to transform the way we consume, analyze and interpret the world of athletics, and would influence international sport culture as well. While sports have always acted as a medium for those looking to escape the drudgeries of work, a way to channel negative emotions into something engaging and entertaining, ESPN presented a new opportunity for fans: an all-encompassing cable network for not only sports itself but also for the culture surrounding sports.,

Explanation:

Hope this helped!

Answer:

t = 66.7 s

Explanation:

Given that,

Speed of a hare, v = 15 m/s

Speed of a turbocharged tortoise, v' = 3 m/s

The hare in a 250 meter race

Let the Hare takes time t. It can be calculated as follows :

\(t=\dfrac{250}{15}=16.67\ s\)

Let a turbocharged tortoise takes t'. It can be calulated as follows :

\(t'=\dfrac{250}{3}= 83.33\ s\)

To tie the race, required time is given by :

\(\Delta t = t'-t\\\\=83.33-16.67\\\\=66.66\ s\\\\\approx 66.7\ s\)

Hence, the correct option is (b) i.e. 66.7 seconds.

Answer:

Q = 8368 Joules.

Explanation:

Given the following data;

Mass = 50 g

Initial temperature = 30°C

Final temperature = 70°C

Specific heat capacity = 4.184 J/g °C

To find the amount of heat absorbed by the water;

Heat capacity is given by the formula;

\( Q = mcdt\)

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 70 - 30

dt = 40°C

Substituting the values into the equation, we have;

\( Q = 50*4.184*40\)

Q = 8368 Joules.

Explanation:

Given that,

We need to find the orbital speed and period of a satellite in orbit \(1.44\times 10^2\ m\) above Earth.

The formula for the orbital speed is given by :

\(v=\sqrt{\dfrac{GM}{r}} \\\\v=\sqrt{\dfrac{6.67\times 10^{-11}\times5.97\times 10^{24}}{(1.44\times 10^2+6.38\times 10^6)^2}} \\\\v=3.12\ m/s\)

Let T be the time period of the satellite. It can b solved using Kepler's third law i.e.

\(T^2=\dfrac{4\pi^2}{GM}r^3\\\\T^2=\dfrac{4\pi^2\times (1.44\times 10^2)^3}{6.67\times 10^{-11}\times 5.97\times 10^{24}}\\\\T=5.44\times 10^{-4}\ s\)

Hence, this is the required solution.

The orbital speed of the satellite is 3.13 m/s and the period of the satellite in orbit is 5.44 × 10⁻⁴ s.

The orbital speed of an astronomical object in a gravitational system is the speed at which it revolves around the central point or the speed required to keep an artificial or natural satellite in orbit.

It can be expressed by using the formula:

\(\mathbf{v = \sqrt{\dfrac{GM}{r}}}\)

where;

\(\mathbf{v = \sqrt{\dfrac{6.67 \times 10^{-11} \times 5.97 \times 10^{24}}{(1.44 \times 10^2 + 6.38 \times 10^6)^2}}}\)

v = 3.13 m/s

In planetary motion, Kepler's third law states that the square of the period of a planet varies directly proportional to the cubes of the planets' mean distances (d).

The period of the satellite can be estimated by using Kepler's third law. It can be computed by using the formula:

\(\mathbf{T^2 =\dfrac{4 \pi^2}{GM}\times r^3}\)

\(\mathbf{T^2 =\dfrac{4 \pi^2}{6.67 \times 10^{-11} \times 5.97 \times 10^{24}}\times (1.44 \times 10^2)^3}\)

\(\mathbf{T^2 =2.96037718\times 10^{-7}}\)

\(\mathbf{T =5.44 \times 10^{-4} \ s}\)

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Answer:

A 50 kg boulder suspended from a cliff.

Explanation:

In this case, that totally depends on the velocity of the object, In case of car, that's just parked so the velocity is zero and a fish can't swim with higher velocity than a boulder which is suspended from a cliff.

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Cube moves first, that the cube which is neutral in nature. Hence, the cube which is neutral will move.  

To solve this problem, we need to calculate the electrostatic force between the two charged cubes and compare it with the force of static friction between the cubes and the surface. The cube with the smaller force of friction will begin to move first. The parameter panel and sketch of the problem are shown below:

Parameter Panel:

Mass of cube 1 (m1) = 2.0 g = 0.002 kg

Mass of cube 2 (m2) = 4.0 g = 0.004 kg

Distance between the centers of the cubes (d) = 6.0 cm = 0.06 m

Charge rate of each cube (q) = 7.0 nC/s

Coefficient of static friction (μ) = 0.65

Sketch:

     |-----------|        |-----------|

     |     2     |        |     1     |

     |-----------|        |-----------|

           |                 |

          d=6.0 cm          d=6.0 cm

           |                 |

           |-----------------|

(a) To determine which cube moves first, we need to calculate the electrostatic force between the charged cubes and compare it with the force of static friction between the cubes and the surface. The electrostatic force between two charged objects is given by Coulomb's law:

F = (k * q1 * q2) / d^2

where k is the Coulomb constant (9.0 x 10^9 N m^2/C^2), q1 and q2 are the charges on the cubes, and d is the distance between them. For each cube, the charge is increasing at a rate of 7.0 nC/s, so the charge at any time t is given by:

q = 7.0 x 10^-9 C/s * t

At t = 0, the cubes are neutral and have no charge. At some later time t, the charges on the cubes are:

q1 = 7.0 x 10^-9 C/s * t

q2 = 7.0 x 10^-9 C/s * t

The electrostatic force between the cubes is then:

F = (9.0 x 10^9 N m^2/C^2) * (q1 * q2) / d^2

= (9.0 x 10^9 N m^2/C^2) * [(7.0 x 10^-9 C/s * t)^2 / (0.06 m)^2]

The force of static friction between each cube and the surface is:

Ff = μ * N

= μ * m * g

where N is the normal force, m is the mass of the cube, μ is the coefficient of static friction, and g is the acceleration due to gravity (9.81 m/s^2).

The normal force N is the force exerted by the surface on the cube, and is equal in magnitude to the weight of the cube:

N = m * g

Plugging in the values for each cube, we get:

Ff1 = μ * m1 * g

= 0.65 * 0.002 kg * 9.81 m/s^2

= 0.0127 N

Ff2 = μ * m2 * g

= 0.65 * 0.004 kg * 9.81 m/s^2

= 0.0254 N

Comparing the electrostatic force between the cubes and the force of static friction, we find:

F - Ff1 = (9.0 x 10^9 N)

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