When vectors b+a= 5i-j & vectors b-a=i-7j, what is the magnitude and direction of vector a

Answers

Answer 1

Eliminate b by combining b + a and b - a, and solve for a :

(b + a) - (b - a) = (5i - j) - (i - 7j)

2a = 4i + 6j

a = 2i + 3j

Now compute the magnitude and direction.

mag: ||a|| = √(2² + 3²) = √13

dir: tan(θ) = 3/2   ⇒   θ = arctan(3/2) ≈ 56.3°


Related Questions

13) Un móvil A parte de una ciudad a las 12 horas, con una velocidad de 40 Km/h. 2 horas después parte otro con una velocidad de 60 Km/h. Averiguar a qué hora se encuentran y a que distancia de la ciudad

Answers

Answer:

¿Podrías poner la pregunta en inglés por favor?

Explanation:

How will the element Ca + O bond ?

Answers

Answer:

Ionic bonding

Explanation:

Since Ca is a metal and O is a nonmetal, they will experience ionic bonding. This means that Ca will "donate" two of its valence electrons to O. This will give both Ca and O a complete octet.

Answer:

CaO

Explanation:

Depending on the element "a" stands for, there is not enough info to conclude how these elements would bond. however, if they are typed out correctly then one possible bond would be CaO. I am assuming that the C and O represent Carbon and Oxygen.

A concrete parking garage has a 6-in concrete slab at each level. The 6-in slab weighs 75 psf (NOTE : psf =lb/ft∧2). If the columns are placed on a rectangular grid with 25−ft spacing in the long direction and 20 - t spacing in the short direction. What is the concentrated reaction to the column due to the weight of the slab on a single level? Assume all framing is simply supported, with a regular spacing, and equal reactions at each end . ( 25 Points) 37,500lb 30.000lb 225,000fo 46675lb

Answers

The concentrated reaction to the column due to the weight of the slab on a single level is 37,500 lb.

To calculate the concentrated reaction to the column, we need to determine the total weight of the slab on a single level.

Given that the weight of the 6-inch concrete slab is 75 psf (pounds per square foot), we first convert it to pounds per square inch (psi) by dividing by 144 (since 1 square foot is equal to 144 square inches).

Weight of slab per unit area = 75 psf / 144 = 0.5208 psi

Next, we calculate the area of the slab on a single level by multiplying the spacing in the long direction (25 ft) by the spacing in the short direction (20 ft).

Area of slab = 25 ft * 20 ft = 500 sq. ft

Finally, we multiply the weight per unit area by the area of the slab to find the total weight of the slab on a single level.

Total weight of slab = 0.5208 psi * 500 sq. ft = 260.4 lb

Therefore, the concentrated reaction to the column due to the weight of the slab on a single level is 37,500 lb.

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experimenter a creates a magnetic field in the laboratory. experimenter b moves relative to a. experimenter b sees

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The Experimenter B sees both a magnetic and an electric field. The Option E.

What does Experimenter B see when moving relative to Experimenter A's created magnetic field?

When Experimenter B moves relative to Experimenter A's created magnetic field, Experimenter B would observe both a magnetic and an electric field.

This phenomenon is known as electromagnetic induction where a changing magnetic field induces an electric field. As Experimenter B moves through the magnetic field, the magnetic flux through a loop of wire changes leading to the generation of an electric field according to Faraday's law of electromagnetic induction.

Thus, Experimenter B would observe the presence of both magnetic and electric fields due to their relative motion with respect to the magnetic field.

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On launch, the space shuttle does not directly inject into its final orbit. rather, main-engine shutdown occurs at the apogee of an elliptical orbit at 100 km altitude. the perigee of this orbit is only 30 km altitude, to ensure that the discarded external tank will safely burn up over open ocean. after the external tank is jettisoned, the orbiter uses its orbital maneuvering system (oms) to maneuver into another elliptical orbit with a perigee at 100 km altitude, and an apogee at 250 km. this is called the oms-1 burn. at the new apogee the shuttle performs the oms-2 burn to circularize the orbit at the mission altitude of 250 .

Answers

The other responses are all essentially correct, but I'd want to offer a somewhat different perspective. This one is a little more technical, but it offers an intriguing perspective, in my opinion.

One of the first things I would mention is the fact that orbits are ellipses rather than circles. The phrases apogee and perigee are used because of this. The apogee is the orbit's highest point, while the perigee is its lowest point, giving the shape of an ellipse. A circular orbit is just an ellipse with the same apogee and perigee. However, apogee and perigee are not the crucial variables from an orbital perspective; rather, apoapsis and periapsis are.

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The energy of violet light is approximately twice that of red light. How do the wavelengths of violet and red light compare?.

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The wavelength of violet light is approximately half that of wavelength of red light.

Light energy is a form of kinetic energy that has the ability to make some kind of light visible to the human eye. Light is defined as a form of electromagnetic radiation emitted by hot objects such as lasers, incandescent bulbs, and the sun.

Light contains photons, which are tiny packets of energy. When the atoms of an object heat up, they produce photons.

Mathemaically, E = hv

where, E ----> energy of a light wave .

h ---> Planck's constant.

v---> frequency.

we have provided that, energy of violet light is twice of energy of red light.

E₁ = 2E₂ where, E₁----> energy of violet light

E₂----> energy of red light

from above formula, hν₁= 2 hν₂=> ν₁= 2ν₂

Using the relation, v = c/λ

for violet light ,ν₁ = c/λ₁ and ν₂= c/λ₂

λ₁ --> wavalenght of violet light

λ₂--> wavelength of red light

c/λ₁= 2 c/λ₂

=> λ₁= 1/2 λ₂

Hence, wavelength of violet light is half of wavelength of red light.

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A group of K stations share a 1-Mbps pure ALOHA channel. Each station outputs a 1024-bit frame on average once every 50 sec, even if the previous one has not yet been sent (e.g., the station can buffe

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It can be concluded that the efficiency of the channel decreases as the number of stations using it increases. ALOHA is a random access protocol that is used in wireless networks.

It is used to allow a lot of computers to share a single channel and at the same time, the computers can randomly transmit data without waiting for other computers. The following are the steps that are used for this protocol:

A computer sends a frame. The computer waits for a while to get an acknowledgement. If the frame was received correctly, the computer proceeds to the next step. If the computer does not receive an acknowledgement for the frame, it waits for a random amount of time before resending the frame. In the case of K stations sharing a 1-Mbps pure ALOHA channel, each station outputs a 1024-bit frame on average once every 50 sec, even if the previous one has not yet been sent. Therefore, the average rate of transmission, G for the 1-Mbps pure ALOHA channel can be calculated as follows:

G = (K × 1024 bits × 1 second) / (50 seconds)G = 20.48K bps

Therefore, the channel efficiency is calculated as follows:

Efficiency = (Useful data transmitted) / (Total amount of data transmitted)Efficiency = [(G × 50 seconds) / (K)] / (G × 50 seconds)Efficiency = 1 / K

Therefore, the efficiency for K = 2, 5, 10 and 20 are as follows:

K = 2, Efficiency = 1 / 2 = 0.5 or 50%K = 5, Efficiency = 1 / 5 = 0.2 or 20%K = 10, Efficiency = 1 / 10 = 0.1 or 10%K = 20, Efficiency = 1 / 20 = 0.05 or 5%

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V1 = 7.5L
P1= 100.0 kPa
v2=11L
P2=
solve for P2

Answers

Answer:

Formula =   P1V1 = P2V2

                   7.5 x 100000 = p2 X 11

                   750000 / 11 = P2

                      P2 = 68181.81 Pa

                                  or

                            =  68.18181 kPa

Explanation:

A solid metal ball of radius 1.5 cm bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing a uniformly distributed charge of -7 nC (see the figure) on its outer surface. The distance between the centers of the balls is 9 cm.Assume the +x axis runs to the right, the +y axis runs up and the +z axis is out.What is the electric field at the center of the metal ball due only to the charges on the surface of the metal ball?

Answers

We have that the electric field at the center of the metal ball due only to the charges on the surface of the metal ball is

\(E=7*10^{9}N/C\)

From the question we are told that

A solid metal ball of radius 1.5 cm

bearing a charge of -15 nC is located near a hollow plastic ball of radius 1.9 cm bearing

uniformly distributed charge of -7 nC

The distance between the centers of the balls is 9 cm

Generally the equation for the electric field  is mathematically given as

\(E=\frac{kq_2}{d^2}\\\\E=\frac{(9*10^9)7*10^{-2}}{9*10^{-2}}\\\\\)

\(E=7*10^{9}N/C\)

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What fitness level is helpful to know when a person is starting an exercise program

Answers

Answer:

There are various areas that should be considered to access the fitness level of an individual.

Explanation:

Knowing the specific details can help an individual to set realistic fitness goals, monitor their progress, and retain motivation. Fitness is typically measured in four main areas: cardiovascular fitness, muscle strength and endurance, flexibility, and composition of the body. It is important to evaluate these vital components of fitness so that one gets a fair knowledge of present fitness level and plan for the future accordingly.

Which orbital is the first to fill with electrons in a given principal energy level?

Answers

Answer:

s orbital

Explanation:

that the answer

4. while sitting in a canoe, you encounter a wave disturbance created by a passing motorboat. your canoe bobs up and down every 2.5 s and the average distance between wave crests moving your boat is 3.6 m. how fast is the wave moving?
5. electromagnetic radiation travels at a speed of 3.0 x 108 m/s.
a. what is wavelength of a radio wave that has a frequency of 3.5 x105 hz?
b. what is the frequency of an x-ray that has a wavelength of 2.5 x 10-10 m?

Answers

The wave is moving at speed of 1.44 m/s.Wavelength radio wave that has a frequency of 3.5 x105 Hz is 857.1 m.The frequency of an x-ray that has a wavelength of 2.5 x 10⁻¹⁰m is 1.4 x 10¹⁸ Hz.

The magnitude of the wave speed is the ratio between the distance of one wavelength and the period. The wave speed formula is the wavelength divided by the wave period or written v = λ/T.

The symbol λ (lambda) is the wavelength that has units of meters (m).

It is given a canoe up and down every 2.5 s. So, the period of a wave is T = 2.5 s

It is given that the average distance between a passing motorboat is 3.6 m. The distance between the crest of the wave is equal to the wavelength.

So, λ = 3.6 m

Then the speed of the wave is

v = λ/T

v = 3.6 m/2.5 s

v = 1.44 m/s

So, the wave is moving at speed of 1.44 m/s.

Wavelength is the length of one peak and one valley in the string which is denoted by lambda (λ). The wave period is the time it takes to travel one wavelength.

Given in the problem that electromagnetic radiation travels at a speed of 3.0 x 10⁸ m/s and frequency of 3.5 x10⁵ Hz, the wavelength is:

λ = v/f

λ = (3.0 x 10⁸) ÷ (3.5 x10⁵)

λ = 857.1 m

X-ray that has a wavelength of 2.5 x 10⁻¹⁰m.

f = v/λ

f = (3.0 x 10⁸) ÷ (2.5 x 10⁻¹⁰)

f = 1.4 x 10¹⁸ Hz

So, the frequency of an x-ray is 1.4 x 10¹⁸ Hz.

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Which of the following are steps for balancing chemical equations?
A. Add all the elements together.
B. Count the atoms in each substance in the reactants and products.
C. Subtract the total amount of elements from the products.
D. Write the chemical equation using formulas and symbols. ​

Answers

The answer should be B

If you have 100 kg of each of these substances, which would require the most energy to increase its temperature by 25 Kelvin?

A. Iron
B. Carbon
C. Rubber
D. Air

If you have 100 kg of each of these substances, which would require the most energy to increase its temperature

Answers

Answer:

iron

Explanation:

A 2400W electric toaster is connected to a standard 120 V wall outlet. A family

measured their monthly toaster usage to be 6.5 hrs.

1) How much electrical energy (in kilowatt hours - kWh) did the toaster dissipate

during the measured month? (round to 1 decimal place & do not include units)

2) If the local power company charges $0.13/ kWh, then calculate (in $) the monthly

total cost of this toaster. (round to 2 decimals & do not include units)

Answers

Answer:

1)  energy = 15.6 kWh,  2)    total_cost = $ 2.03

Explanation:

1) The energy dissipated is the product of the power and the time of use In a month it was used t = 6.5 h and the power of the toaster is

P = 2400 W = 2,400 kW

       energy = P  t

       energy = 2,400  6.5

        energy = 15.6  kWh

using rounding to a decimal

        energy = 15.6 kWh

2) The cost of energy is unit_cost = $ 0.13 / kWh

so the total cost

         total_cost = energy    unit_cost

         total_cost = 15.6   0.13

         total_cost = $ 2.028  

rounding to two decimal places

         total_cost = $ 2.03

it is moving day and you are in a hurry! you drop a fridge from a height of 75.0m out a window. a stool is thrown down from the same height 0.091s later if both objects hit the ground at the same time what was the initial

Answers

Answer:

Explanation:

Given:

H = 75 m

Δt = 0.091 s

g =9.81 m/s²

_________

V₀ - ?

Assume that the stool fell freely, then the time of its fall:

H = g·t²/2

t = √ (2·H / g) = √ (2*75 / 9.81) ≈ 3.910 s

The refrigerator was thrown down with initial speed and fell:

t₁ = t - Δt = 3.910 - 0.091 ≈ 3.82 s

Find the initial chip of the refrigerator:

H = V₀·t₁ + g·t₁²/2

V₀·t₁ = H - g·t₁²/2

V₀ =H / t₁ - g·t₁ / 2

V₀ = 75 / 3.82 - 9.81·3.82 / 2 ≈ 0.90 m/s

So, at first, the stool is simply released from the hands, and the refrigerator is thrown down with the initial speed 0.90 m/s

A 1210-kg car travels 1. 20 km up an incline at constant velocity. The incline is 15° measured with respect to the horizontal. The change in the car's potential energy is

Answers

The change in the car's potential energy is approximately 3,615,124 joules.

The change in the car's potential energy can be calculated using the formula:

ΔPE = m * g * h

where:

ΔPE = change in potential energy

m = mass of the car (1210 kg)

g = acceleration due to gravity (approximately 9.8 m/s²)

h = change in height

In this case, the change in height can be determined by calculating the vertical displacement of the car as it travels up the incline.

The vertical displacement (h) can be calculated as:

h = d * sin(θ)

where:

d = distance traveled along the incline (1.20 km = 1200 m)

θ = angle of the incline (15°)

Substituting the values:

h = 1200 m * sin(15°)

h ≈ 308.41 m

Now, we can calculate the change in potential energy:

ΔPE = (1210 kg) * (9.8 m/s²) * (308.41 m)

ΔPE ≈ 3,615,124 J (joules)

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What are the common sedimentation tanks found in waste treatment
plants and what is the purpose of each tank

Answers

In waste treatment plants, there are several common types of sedimentation tanks .some of the most common sedimentation tanks and their purposes: Primary Sedimentation Tank , Secondary Sedimentation Tank ,Tertiary Sedimentation Tank:

1. Primary Sedimentation Tank: The primary sedimentation tank, also known as a primary clarifier or primary settling tank, is designed to remove settleable solids and heavy particles from wastewater. It allows the heavier particles to settle at the bottom of the tank, forming sludge, while the lighter particles float to the top and are skimmed off. The primary sedimentation tank helps in the removal of large suspended solids and organic matter.

2. Secondary Sedimentation Tank: The secondary sedimentation tank, also called a secondary clarifier or final settling tank, is used in biological treatment processes. It receives the treated wastewater from the biological reactor, such as an activated sludge process or a trickling filter, and allows the remaining suspended solids, microorganisms, and flocs to settle. This tank separates the treated wastewater from the biological sludge or biomass before the water is discharged or subjected to further treatment.

3. Tertiary Sedimentation Tank: Tertiary sedimentation tanks, also known as tertiary clarifiers or polishing basins, are used for additional treatment after the secondary sedimentation tank. These tanks further remove fine suspended solids, residual organic matter, and nutrients, such as phosphorus or nitrogen, from the wastewater. Tertiary treatment is often required to meet strict effluent quality standards before the wastewater is discharged into the environment.

4. Imhoff Tank: An Imhoff tank is a type of sedimentation tank used for the treatment of sludge or sewage solids. It consists of two chambers: an upper chamber for settling and a lower chamber for anaerobic digestion of the settled sludge. The Imhoff tank allows for the natural decomposition of organic solids in the lower chamber, reducing the volume of sludge and producing biogas.

These sedimentation tanks play a crucial role in wastewater treatment by allowing the separation and removal of solids from the wastewater, improving the overall quality of the treated effluent. The specific design and purpose of each tank may vary depending on the treatment process and the requirements of the wastewater treatment plant.

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This is about the law of conservation of energy and work/energy. What force prevents 100% of the energy in a system from being used to do work?

Answers

Answer:

The law of conservation of energy is one of the basic laws in physics. It governs the microscopic motion of individual atoms in a chemical reaction. The law of conservation of energy states that “In a closed system, i.e., a system that is isolated from its surroundings, the total energy of the system is conserved.” According to the law, the total energy in a system is conserved even though the transformation of energy occurs. Energy can neither be created nor destroyed, it can only be converted from one form to another.

Explanation:

You push a 400 kg car for 6 m with a force of 300 N? What is the car’s final speed if all your work became kinetic energy?

Group of answer choices

3 m/s

5.8 m/s

80 m/s

0.40 m/s

Answers

Answer:

3m/s

Explanation:

KE = ¹/₂ mv²

But workdone = F x d

Workdone = 300 x 6

Workdone = 1800J

Now per the question.

assuming

workdone= KE

Then

KE = ¹/₂ mv²

1800J = ¹/₂ 400kg x V²

3600J = 400 x V²

3600J / 400kg = V²

9 =V²

V =√(9)

V = 3m/s

Roshan makes the table below to describe how to draw a ray diagram for a convex lens.

A 2-column table with 3 rows. The first column labeled Ray from Object to Lens has entries draw through the focal point on the same side of the lens as the object, draw parallel with the main axis, draw to the center of the lens. The second column labeled After passing through the lens has entries the ray goes parallel to the main axis, the ray goes away from the main axis as though it came from the focal point near the object, the ray goes straight through and does not bend.

What error did Roshan make?

The ray that goes through the center should bend and go through the focal point on the other side.
The ray that starts out parallel with the main axis should bend toward the axis and go through the focal point on the other side.
The ray that goes parallel to the main axis after passing through the lens should also be parallel from the object to the lens.
The rays in the table describe how rays are drawn for a concave lens rather than for a convex lens.
Mark this and return

Answers

Roshan made an error in the second column of the table, because the ray goes away from the main axis as though it came from the focal point near the object is wrong.

What error did Roshan make?

The error Roshan made is analyzed as follows;

The entry "the ray goes away from the main axis as though it came from the focal point near the object" should be "the ray goes through the focal point on the other side".

This is because for a convex lens, a ray that starts out parallel with the main axis should bend toward the axis and go through the focal point on the other side.

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pulsars are thought to be group of answer choices rapidly rotating neutron stars. accreting white dwarfs. accreting black holes. unstable high mass stars.

Answers

Pulsars are thought to be a group of rapidly rotating neutron stars.

A neutron star is the dense remnant left behind after the collapse of a massive star during a supernova explosion. Neutron stars are incredibly compact and contain a high concentration of neutrons. They have masses typically around 1.4 times that of the Sun but are compressed into a sphere with a radius of only about 10 kilometers.

When a massive star undergoes a supernova explosion, the core collapses under gravity, causing the protons and electrons to merge and form neutrons. This collapse results in a highly dense neutron star with a strong gravitational field.

Pulsars, a type of neutron star, are characterized by their rapid rotation and the emission of beams of electromagnetic radiation that are observed as regular pulses of radiation. These pulses occur at precise intervals and are detectable across a range of wavelengths, from radio waves to X-rays.

The emission of radiation from pulsars is believed to be caused by two main factors:

1. Rotation: Pulsars rotate rapidly, often spinning hundreds of times per second. As the neutron star rotates, it emits beams of radiation from its magnetic poles. These beams are not aligned with the rotational axis, resulting in a lighthouse-like effect where the beams sweep across space. When the beams pass through Earth's line of sight, we detect them as regular pulses of radiation.

2. Magnetic Field: Pulsars possess extremely strong magnetic fields, typically billions of times stronger than Earth's magnetic field. This powerful magnetic field interacts with the charged particles surrounding the pulsar, causing them to emit radiation in the form of radio waves, X-rays, and gamma rays.

Accreting white dwarfs, black holes, and unstable high-mass stars are not typically associated with pulsars. Accreting white dwarfs are white dwarf stars that accrete material from a companion star, black holes are formed from the collapse of massive stars, and unstable high-mass stars are stars that undergo various stages of stellar evolution before potentially exploding as supernovae.

In summary, pulsars are believed to be rapidly rotating neutron stars with strong magnetic fields that emit beams of radiation as they rotate. Their distinct pulsing behavior makes them observable as regular pulses of electromagnetic radiation across different wavelengths.

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Compare two electrons meeting to tossing a ball up in the air.

Answers

Answer:

Two electrons receive treacherous and formidable power when met while the atoms in the ball move slowly around with great space.

Explanation:

hope this helped!

A tank is full of water. Find the work required to pump the water out of the spout. (use 9. 8 m/s2 for g. Use 1000 kg/m3 as the density of water. Assume r = 6 m and h = 2 m. ).

Answers

70.934648 MJ of work is needed to pump the water out of the spout.

The tank is shaped like a globe. the distance to the mass's center = h+r =6+2=8

Weight of water in tank = 9.8×π×6³×1000×4/3

= 8.866831×10⁶ N

to empty the tank Work done  = 8 × 8.866831×10⁶

=70.934648×10⁶ J

= 70.934648 MJ.

A pump is a mechanical device used to transport fluids (liquids, gases, or occasionally slurries). It commonly converts electrical energy into hydraulic energy. Pumps can be divided into three main categories based on how they move the fluid: direct lift, displacement, and gravity pumps.

Pumps use a mechanism to move the fluid (usually a rotary or reciprocating one) and require energy to operate. Pumps exist in a variety of sizes, from microscopic for use in medical applications to enormous industrial pumps, and they can be powered by a variety of energy sources, including electricity, manual operation, engines, or wind power.

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A car travels 10.0 m/s. What is its velocity in km/h? A. 0.6 km/h B. 36,000 km/h C. 36 km/h D. 360 km/h

please show work, like using the equation.
Thank you

Answers

Answer:

36km/h C.

Explanation:

10* 3600/1000= 10*18/5= 36km/h

C. 36km/h

When you hear sounds through a wall, you can hear lower pitched sounds more clearly than higher pitched sounds. Use a model to explain why.

Answers

Sound waves travel through the air and can be blocked by walls. When a sound wave passes through a wall, the wall absorbs some of the sound energy, resulting in the higher-pitched sound waves being blocked more than lower-pitched sound waves.

This is because higher-pitched sound waves have shorter wavelengths, making them more susceptible to being blocked than lower-pitched sound waves, which have longer wavelengths.

This phenomenon is known as wave-particle duality, which states that sound waves have both particle-like and wave-like properties. The particle-like property of higher-pitched sound waves makes them more susceptible to being blocked by walls than lower-pitched sound waves. This is why you can hear lower-pitched sounds more clearly when they pass through a wall.

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What happens to a waves energy when amplitude is doubled? Halved? Tripled?

Answers

Answer:

This means that a doubling of the amplitude of a wave is indicative of a quadrupling of the energy transported by the wave. A tripling of the amplitude of a wave is indicative of a nine-fold increase in the amount of energy transported by the wave. So when doubling, you are quadrupling, tripling, you are 9x it, and for  halve, it cuts in half.

Explanation:

If the mass of an object is 100 and Net force is 400, what would be the Acceleration?
And explain.

Answers

Answer:

\(4m/s^{2}\)

Explanation:

I'm assuming the units for force and mass are Newtons and kilograms, respectively.

Rearranging Newton's first law (F=m*a) to solve for acceleration:

F=m*a

\(a=\frac{F}{m}=\frac{400 N}{100 kg}=4m/s^{2}\)

The acceleration is 4 meters per second squared and was found by rearranging Newton's first law in order to solve for acceleration.

You are looking straight down on a magnetic compass that is lying flat on a table. A wire is stretched horizontally under the table, parallel to and a short distance below the compass needle. The wire is then connected to a battery so that a current I flows through the wire. This current causes the north pole of the compass needle to deflect to the left. The questions that follow ask you to compare the effects of different actions on this initial deflection. If the wire is lowered farther from the compass, how does the new angle of deflection of the north pole of the compass needle compare to its initial deflection? You did not open hints for this part. It is larger. It is smaller. It is unchanged.

Answers

The new angle of deflection of the north pole of the compass needle compare to its initial deflection is smaller.

The new angle of deflection north pole becomes smaller

The angle of deflection is the angle formed when an object changes course from its original course of direction or target.

The angle of deflection of a particular particle is directly proportional to its charge to mass ratio as it passed through an electric field.

As the wire is continuously being lowered farther from the compass, the angle of deflection of the north pole continues to become smaller when compared to its initial deflection.

Therefore, the new angle of deflection of the north pole of the compass needle compare to its initial deflection is smaller.

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How does the change in the volume of air in the bubble affect the density?

Answers

it affects the amount of air in a bubble because the bubble is getting larger which brings in more air do make the bubble more dense
Other Questions
Which expression is undefined?A. 07B. 9/(-6+6)C.(5-5)/8D.(0-10/-5 The chemical form of energy that is usable by the cell to do work. NADPHATPglucoseNADH if there are 5280 feet in every mile, then what is the soeed if the car that is traveling 35 miles per hour in feet per second please help please thankyou How many atoms are in 0.250 moles of Rb? Is a simile an example of imagery? Tezcatlipoca was a trickster god in Aztec mythology. He played several tricks. How did Tezcatlipoca trick his fellow god Quetzalcoatl into leaving the world to him?A: Tezcatlipoca killed Quetzalcoatl. B: Tezcatlipoca convinced Quetzalcoatl to leave.C: Tezcatlipoca tricked Quetzalcoatl into eating too much. D: Tezcatlipoca showed Quetzalcoatl that he was a weak god. unless otherwise agreed, an agent making a contract for an unidentified principal is not a party to the contract. 2. List three effects of Western education on the life of Ghanaians. A ball is thrown directly downward with an initial speed of 7.60 m/s, from a height of 29.3 m. after what time interval does it strike the ground? Test scoring a2-4+3a-3 What is the purpose of the poet? what effect does the poem have on you 10. What is an expression for the perimeter of the triangle?11. What is an expression for the area of the triangle?12. Think about values for x, y, and z that would make the following statements true. If you think these values exist, give anexample of them. If you think they do not exist, explain why.a.The perimeter and area are both rational numbers.b.The perimeter is an irrational number and the area is a rational number.C.The perimeter and area are both irrational numbers. What story is the artist El Anatsui telling in Dusasa I? aArt should be small in scale bArt can be realistic by using soft textiles cArt can be created by recycling objects dArt should be limited to traditional materials A scale factor of 5 was applied to this figure. What would be the new length of the height and width of the triangle? Which animal is closer to sea level? O Lobster: -10 feet Mussel: -- 6 feet A circular tablecloth has a radius of 2.5 feet. Kyle is sewing a piece of ribbon around the edge of the tablecloth. If Kyle has exactly enough ribbon, which measurement is closest to the length of the piece of ribbon in feet? Kelly Industries is given the opportunity to raise $5 million in debt through a local government subsidized program. While Kelly normally raises debt at 12% interest, the government program sets the interest rate at 9%. If the debt issue expires in 4 years, calculate the PV of interest subsidy. what important things were going on at the time these observations about the Spanish conquistadors were written?how do the historical events help you understand the document? A metal disk of radius 10 cm has a hole at a distance of 2.5 cm from the center. The size of the hole is 1 cm in diameter. If you heat the disk, what will happen to the size of the disk .