The correct answer is option 1: higher frequency.
The tone you hear when blowing across the opening of a partially filled two-liter soda pop bottle is caused by the air inside the bottle vibrating at a certain frequency. When you take a sip of the pop, you are changing the level of liquid inside the bottle, which in turn changes the amount of air inside the bottle. This change in air volume can affect the frequency of the tone you hear. In general, when you take a sip of the pop and blow across the opening again, the tone you hear will have a higher frequency because there is less air inside the bottle and it is vibrating at a higher rate.
In general, a shorter air column causes the sound wave produced to have a higher frequency. This is due to the fact that the wave can complete more cycles with a shorter length, producing more oscillations per unit of time.
As a result, the tone you hear when you take a sip of the pop and blow over the opening once again will have a greater frequency than previously. A higher-pitched tone results from the volume change because it shortens the air column, which changes the resonance frequency.
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Use the chemical equation to find the answers.
BaSO4 + H2SO4 → Ba(HSO4)2
Identify how many oxygen atoms are in the product.
Identify how many oxygen atoms are in the reactant.
Answer:
Explanation:
Reactants
BaSO4 has 4 oxygens and only 1 sulfur. That's a good thing to notice.
H2SO4 has 4 oxygens and only 1 sulfur.
The reactants have 4 + 4 oxygens = 8 oxygens.
Products
It is right, but you might struggle a bit with the answer.
Notice that HSO4 is in brackets followed by a two
(HSO4)2
When the 2 is outside the brackets, everything inside the brackets get's doubled.
There are 2 Hs
There are 2 Ss
There are 4 * 2 Oxygens = 8 oxygens, some as the reactants.
Break the product into simplified form
\(\\ \sf\longmapsto Ba(HSO_4)_2\)
\(\\ \sf\longmapsto BaH_2S_2O_8\)
Oxygen on products side=8
#2.
Oxygen on reactant side=4+4=8atoms
A box containing a new TV weighs 350 N. Phineas is pushing horizontally on it with a force of 150 N, but it doesn’t budge. (a) Identify all the forces acting on the crate. Describe each as: (type of force) exerted on the crate by (object). (b) Identify the interaction partner of each force acting on the crate. Describe each partner as: (type of force) exerted on (object) by (object). (c) Draw an FBD for the crate. Are any of the interaction partners identified in (b) shown on the FBD? (d) What is the net force acting on the crate? Use your answer to determine the magnitude of all the forces acting on the crate. (e) If there are pairs of forces on the FBD that are equal in magnitude and opposite in direction, are these interaction pairs? Explain
(a) Gravitational force, Normal force, Applied force and Static friction force are the forces acting on the crate. (b) Gravitational force is exerted on Earth by the crate, Normal force is exerted on the ground by the crate, Applied force is exerted on Phineas by the crate and Static friction force is exerted on the ground by the crate. (c) Interaction partners would not be shown on the FBD. (d) The net force acting on the crate is zero. (e) No, these are not interaction pairs.
(a) The forces acting on the crate are:
1. Gravitational force exerted on the crate by Earth
2. Normal force exerted on the crate by the ground
3. Applied force exerted on the crate by Phineas
4. Static friction force exerted on the crate by the ground
(b) Interaction partners for each force are:
1. Gravitational force exerted on Earth by the crate
2. Normal force exerted on the ground by the crate
3. Applied force exerted on Phineas by the crate
4. Static friction force exerted on the ground by the crate
(c) An FBD (free body diagram) for the crate would show the four forces mentioned in part (a) acting on the crate. Interaction partners identified in part (b) would not be shown on the FBD, as they act on other objects.
(d) The net force acting on the crate is zero, since the crate is not moving. This means the magnitudes of the applied force and static friction force are equal (150 N), and the magnitudes of the gravitational force and normal force are also equal (350 N).
(e) The pairs of forces on the FBD that are equal in magnitude and opposite in direction are the gravitational force and normal force, as well as the applied force and static friction force. However, they are not interaction pairs. Interaction pairs act on different objects and are described by Newton's third law of motion. In this case, the gravitational force-normal force pair and the applied force-static friction force pair are not interaction pairs because they are acting on the same object, the crate. Interaction pairs would be forces like the gravitational force exerted on Earth by the crate, or the applied force exerted on Phineas by the crate, which act on different objects.
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under the principles of the concentric ring model, what is the name of the activities found in the most outer circle / ring?
a concentric ring model in which social groupings are spatially organised in a hierarchy of rings. The upper class resides further away from the center, while the lower class is located closer to it.
The concentric ring model operates on the presumption that cultural content results from the incorporation of original ideas into the creation and/or presentation of music, text, and picture, and that these concepts originate in the fundamental artistic creativity spheres. Burgess' concentric ring model concept envisions growth occurring in a series of concentric rings surrounding the concentric ring model . According to Hoyt's sector model, economic expansion follows transportation corridors.
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Which of the following is characteristic of a single-exposure, common-vehicle outbreak? Explanation: Single-exposure, common-vehicle outbreaks involve a sudden, rapid increase in cases of disease that are limited to persons who share a common exposure.
Characteristic of a single-exposure, common-vehicle outbreak: Single-exposure, common-vehicle outbreaks involve a sudden, rapid increase in cases of disease that are limited to persons who share a common exposure.
Determine a single exposure?A single-exposure, common-vehicle outbreak refers to an outbreak of a disease where individuals become infected through a common source or vehicle.
This type of outbreak is characterized by a sudden and rapid increase in the number of cases of the disease, which can be attributed to the shared exposure to a specific source.
The cases are limited to individuals who have been exposed to the common vehicle, such as contaminated food, water, or other infectious agents.
The outbreak occurs due to the transmission of the pathogen or harmful agent from the common source to the affected individuals. Identifying the common vehicle and taking appropriate measures to control or eliminate it is crucial in containing and preventing further spread of the disease in such outbreaks.
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1. A car begins at a speed of 3m/s and accelerates at 2m/s² over a distance of 40m,
calculate the final speed of the car.
\(\quad \huge \quad \quad \boxed{ \tt \:Answer }\)
\(\qquad \tt \rightarrow \: v = 13 \:\: m/s\)
____________________________________
\( \large \tt Solution \: : \)
\( \texttt{Initial speed of the car (u) = 3 m/s} \)\( \texttt{final speed of the car (v) = ??} \)\( \texttt{acceleration of the car (a)= 2 m/s²} \)\( \texttt{distance covered in that time (s) = 40 m} \)By third equation of motion :
\(\qquad \tt \rightarrow \: {v}^{2} = {u}^{2} + 2as\)
\(\qquad \tt \rightarrow \: {v}^{2} = (3) {}^{2} + 2(2)(40) \)
\(\qquad \tt \rightarrow \: {v}^{2} = 9 + 160\)
\(\qquad \tt \rightarrow \: {v}^{2} = 169\)
\(\qquad \tt \rightarrow \: v = 169\)
\(\qquad \tt \rightarrow \: v = 13\)
so, speed of the car after that time is : 13 m/s
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
A student kicks a football vertically upwards, causing the football to reach a maximum height of 40.0m before falling back to the ground. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the football.
A) With what speed was the football kicked?
B) What was the football's total flight time?
Answer:
A. 28 m/s
B. 5.72 s
Explanation:
The following data were obtained from the question:
Maximum height (h) = 40 m
Acceleration due to gravity (g) = 9.8 m/s²
A. Determination of the initial velocity.
Maximum height (h) = 40 m
Acceleration due to gravity (g) = 9.8 m/s²
Velocity at maximum height (v) = 0 m/s
Initial velocity (u) =.?
v² = u² – 2gh (Ball is going against gravity)
0² = u² – (2 × 9.8 × 40)
0 = u² – 784
Collect like terms
0 + 784 = u²
784 = u²
Take the square root of both side
u = √784
u = 28 m/s
Thus, the ball was kicked with a velocity of 28 m/s
B. Determination of the time of flight.
We'll begin by calculating the time taken to reach the maximum height. This can be obtained as follow:
Velocity at maximum height (v) = 0 m/s
Initial velocity (u) = 28 m/s
Time taken to reach the maximum height (t) =?
v = u – gt (Ball is going against gravity)
0 = 28 – 9.8t
Rearrange
0 + 9.8t = 28
9.8t = 28
Divide both side by 9.8
t = 28/9.8
t = 2.86 s
Finally, we shall determine the the time of flight as follow:
Time taken to reach the maximum height (t) = 2.86 s
Time of flight (T) =?
T = 2t
T = 2 × 2.86
T = 5.72 s
Therefore, the time of flight for the ball is 5.72 s
_______ is a huge reddish loops of gas that often link different parts of sunspot regions.
Solar Prominence is a huge reddish loop of gas that often link different parts of sunspot regions.
What is a Solar Prominence?
A solar prominence is a large, loop-like structure of plasma that extends from the Sun's surface into its outer atmosphere. Prominences are often associated with sunspot regions and can span hundreds of thousands of kilometers. They are composed of charged particles, primarily hydrogen and helium, that are held in place by the Sun's magnetic field. The reddish color is due to the emission of light in the hydrogen alpha spectral line. Solar prominences are dynamic structures that can erupt and release huge amounts of energy into space, in the form of coronal mass ejections.
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.
How is energy transferred during the water cycle? Question 1 options: Water gains energy during evaporation and releases it during condensation in the atmosphere Water gains energy during evaporation and condensation in the lithosphere. Water gains energy in condensation and releases it in evaporation. Water releases energy during evaporation and condensation.
Answer:
Water gains energy during evaporation and releases it during condensation in the atmosphere
Explanation:
In the water cycle, heat energy is gained or lost by water as it undergoes various processes in the cycle.
In evaporation, water molecules gains energy because the molecules of water vibrate faster and become more energetic. Hence they are able to escape into the atmosphere from the surface of the liquid.
In condensation, the molecules of gaseous water looses energy and becomes liquid.
Hence, water gains energy during evaporation and releases it during condensation in the atmosphere.
Answer:
K12 HE HE
Explanation:
Whats the answer for this?
What is the orbital speed of the planet ? (G = 6.673 * 10 ^ - 11 * N * m ^ 2 / k * g ^ 2)
Answer:
Explanation:
You need to know the mass of the sun (M) and the distance of the planet from the sun (R):
\(V = \sqrt{\frac{G\cdot M }{R} } \\\\\)
A 5.00 kg firecracker explodes into two parts: one part has a
mass of 3.00 kg and moves at a velocity of 25.0 m/s towards
the west. The other part has a mass of 2.00 kg. What is the
velocity of the second piece as a result of the explosion?
a -28.7 m/s
b 15.8 m/s
C-37.5 m/s
d 43.2 m/s
Answer:-37.5 m/s
Explanation:
Answer:
-37.5
Explanation:
How does the radius of a string affect centripetal force.
Answer:
because a raduis is half of 25% of a cicrle.
Explanation:
please help lol
im on my sisters acc btw
Answer:
sitting leg curls= hamstring
shrugs=shoulders
machine curls=biceps
bench press= pectorals
The creation of electricity in a coil of a wire through the movement of a magnet is called what?
A) electromagnet
B) Magnetosphere
C) Magnetism
D) Electromagnetic Induction
Answer:
D. Electromagnetic Induction.
Explanation:
a wave is a disturbance that carries energy from one place to another true or false
there are no gpos created in an active directory domain by default. true or false?
There are no GPOs created in an active directory domain by default statement is false.
In an Active Directory domain, several default Group Policy Objects (GPOs) are created by default. These default GPOs provide various baseline settings and configurations for the domain. Some of the commonly found default GPOs include:
Default Domain Policy: This GPO is created at the domain level and contains settings that apply to all user and computer objects within the domain.
Default Domain Controllers Policy: This GPO is also created at the domain level and contains settings specifically for domain controllers.
Default Domain Security Policy: In earlier versions of Windows Server, this GPO was created by default and contained security settings for the domain. However, starting from Windows Server 2008, the security settings are now part of the Default Domain Policy.
These default GPOs can be modified to meet the specific requirements of the organization or additional GPOs can be created to apply specific settings to different groups of users or computers within the domain.
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In order for maximum work to be done...
free lil peezy and drake is kool
Answer:
For constant traveled distance and applied forces, apply the for parallel to the direction of the movement.
Explanation:
\(W = F.d = |F||d|cos(\theta)\\\)
There are 3 components in the amount of work produced when applying a force to an object.
1. The amount of force applied
2. The distance that the object is traveled
3. The angle between the force vector and the distance vector
To get the maximum amount of work for a constant force and distance, the force needs to be along the distance traveled \(=> \theta = 0\)If the angle and the distance are constant, the only way is to apply a larger force in magnitudeIf the angle and the force are constant, increasing the distance traveled will result in higher amount of work produced.The mass of a density bottle of volume 50cm is 10g when empty.Aluminium turnings are poured into the bottle and the total mass is 60g.Water is then added into the turnings till the bottle is full.If the total mass of the bottle and it's contents is 90g, calculate the density of the aluminum turnings
Aluminum's density is 1.2 gm/ cm^3.
The distribution of a quantity (such as mass, electricity, or energy) per unit, kind of space; the amount per unit of length, area, or volume. the substance's mass per unit volume.
The density of an object is determined by its mass to volume ratio. Density is commonly measured in grammes per cubic centimetre (g/cm3).
The bottle weighs a total of 90g.
The bottle has a volume of 50cm3.
Total density is equal to mass times volume.
= 90/ 50
= 1.8 gm/cm3 and the mass of water is now 90 - 60 = 30 gm.
50 cm3 of space
Mass/Volume Equals Density
= 30/ 50
= 0.6 gram/cm3 Currently,
The density of aluminium is 1.8-06.
= 1.2 gm/ cm^3
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Physics (30 points)
The image attached shows the times for runners in a 100 m dash. If each runner has the same mass, which runner has the weakest force?
Answer: runner B
Explanation:
i did the test
Runner which has the weakest force is A.
What is speed?The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.
The image attached shows the times for runners in a 100 m dash.
Force = mass x Acceleration
Force = mass x Velocity /Time
If each runner has the same mass, runner with the maximum time has the weakest or lowest force.
Among all the four runners, Runner A has the highest time for completing 100 m dash.
Thus, Runner A has the weakest force.
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A child kicks a ball horizontally with a speed of 2.8 m/s from the end of a deck that is 8.5 m high.
a. How long will the ball take to hit the ground?
Answer:
Explanation:
time =d/s
therefore, t =8.5/2.8
t=3.02s
What is the difference between adhesive and cohesive?
The difference between adhesive and cohesive is that adhesive refers to the attraction between different substances, while cohesive refers to the attraction between similar substances.
Adhesive and cohesive are terms used to describe the behavior of liquids and the forces between their molecules.
Adhesive refers to the attraction between different substances. Adhesive forces between liquids and solids, for example, result in the wetting of the solid surface by the liquid. Adhesive forces can be strong or weak, depending on the properties of the substances involved. For example, water is a highly adhesive liquid and has a strong attraction to many surfaces.
Cohesive refers to the attraction between similar substances. Cohesive forces between liquids, for example, result in surface tension. Cohesive forces can also be strong or weak, depending on the properties of the liquid. For example, water has a relatively high level of surface tension due to its cohesive forces.
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a strong spring is stretched 10 cm by a suspended block. if the block's weight is doubled, the spring will stretch to group of answer choices 5 cm. 10 cm. 15 cm. 20 cm.
Using the concepts of spring, we got that the spring will stretch to d) 20 cm if the block's weight on the strong spring is doubled.
When a block is attached on the spring ,a tension will generate on the spring which actually helps the block to remain suspended with the string.
Gravity tries to attract the block towards the surface and tension tries to remain the block with the spring. When the weight is doubled, to hold the same block on the spring, more tension will generate. Due to that spring will expand further more in downward direction.
So when weight is doubled, then spring will be expanded by another 10cm means total length of expansion of string will be 20cm.
Hence, for a strong spring is stretched 10 cm by a suspended block. if the block's weight is doubled, the spring will stretch to d)20cm
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consider the motion of a particle in which the position is given as X=3t-3t².what is the average speed at t1=1s and T2=3s
The average speed of a particle in the position X=3t-3t² is 18m/s
What is the average speed at t₁ = 1s and t₂ = 3s?At the position X = 3t - 3t²
t₁ = 1s = X = 3(1) - 3(1)²
X = (3 x 1) - (3 x 1²)
X = 3 - 3 = 0m
At t₂ = 3s = X = 3(3) - 3(3)²
X = (3 x 3) - (3 x 3²)
X = 9 - 27 = -18m
Displacement, Δx = X₂ - X₁
= -18 - 0 = -18m
The change in time would then be
Δt = t₂ - t₁
= 2 - 1 = 1
The Average velocity can be calculated by dividing the change in displacement by the change in time, Vₐ = Δx/Δt
Vₐ = -18m/1s = -18m/s
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Which astronomer's laws of motion helped to explain the heliocentric model
Answer:
( Galileo )discovered evidence to support Copernicus' heliocentric theory when he observed four moons in orbit around Jupiter
While timing a pendulum, Mr. Cantor notices that it takes 9.34 s for a
pendulum to complete 6 complete swings. What is the period of this
pendulum?
9.34s
1.56 s
6s
0.64s
two long, straight, parallel wires 6.6 cm apart carry currents of equal magnitude i. they repel each other with a force per unit length of 3.1 nn/m. find the current i.
According to the given statement is currents of equal magnitude the current I is 30mA.
What do you mean of Current?Current is the movement of electrical charge carriers, which are frequently electrons or atoms lacking in electrons. Current is frequently represented with the capital letter I. The common unit is the ampere, which is represented by the letter A.
What is current formula?According to Ohm's equation, V = IR, the current flowing through a conductor is proportional to the voltage V and resistance R. I = V/R is an alternate formulation of Ohm's law.
Briefing:Distance, r = 6.6 cm
Force per unit length, = 3.1 nN/m
Current passes, when wire is parallel:
→ I₁ = i₂
We know the relation,
\(\frac{F}{l}=\frac{\mu_0}{2 \pi} \times \frac{I_1 \times I_2}{r}\)
By substituting the values, we get
3.1 × 10⁻⁹ = \(\frac{3 \pi \times 10^{-7}}{2 \pi} \times \frac{I^2}{6.6 \times 10^{-2}}\)
The current will be:
I = 0.030884 A
= 30mA
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Did it seem the Law of Reflection held for planar waves? How could you check to be sure?
The Law of Reflection held for planar waves due to partial transmission of the wave.
What is a Planar wave?This is a wave which has a constant physical quantity which is perpendicular to the direction of wave travel.
These type of wave has normal wave characteristics such as frequency and is partially transmitted through reflection.
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Two coils A and B are wound side by side. Coil A has 8120 turns and coil B has 11842 turns. 54% of flux produced by coil A links coil B. A current of 6 A in coil A produces 0.02 mWb, while the same current in coil B produces 0.078 mWb. a) Calculate the mutual inductance and the coupling coefficient. b) Calculate the emf induced in coil B when the current is reversed in 0.015 seconds.
a) Mutual inductance = 0.108 H; Coupling coefficient = 0.482. b) - 4.95 V.
a) Mutual inductance, M between coil A and coil B can be given as:
M = k√(L_AL_B) here, k is the coupling coefficient, L_A and L_B are the inductances of the coil A and coil B respectively. Since 54% of flux produced by coil A links coil B,
So, K = 0.54
L_A = N_A Φ/I_AL_A
= 8120 × 0.02/6
= 27.07 mH
L_B = N_B Φ/I_BL_B
= 11842 × 0.078/6
= 154.63 mH
M = k√(LALB) = 0.482 × √(27.07 × 0.15463) = 0.108 H
b) The emf induced in coil B can be given as:-
ε = M (dI_B/dt)/L_B
ε = 0.108 × (-6/0.015) / 0.15463 = -4.95 V
Thus, the emf induced in coil B when the current is reversed in 0.015 seconds is -4.95 V.
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A train is traveling N at 45 m/s. After 10s, it is traveling at 90 m/s. What is it's acceleration?
Answer:
The train's acceleration is 4.5 m/s²
Explanation:
The train's speed increased by 45 m/s after 10 seconds, which means that it's speed increased by 4.5 m/s each second, or rather 4.5m/s²
If a wave has a wavelength of 10 m and a speed of 2.5×108 m/s (this is 250000000 m/s) what is the frequency of the wave?
Answer:
The wavelength result is 3 m. Most common velocities: Light in vacuum (air) = 300,000 km/s. Light in water = 225,000 km/s. Sound in air = 340 m/s. Sound
Explanation:
the answer is 3m