Which diagram represents this molecule?

Answer:

2.282 atm

P1V1/T1 = P2V2/T2

2.70atm / (50+273) = X/ 273

make x subject of formula

:. X = 2.28 atm

or 2.28 * 1.01 *10⁵ N/m²

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If it took 412.5 J of heat to raise the temperature of 24.6 g of a substance from 14.5°C to 52.6°C, the specific heat of the substance is 0.44 J/g°C.

The specific heat of a substance can be calculated by using the following formula:

Q = m × c × ∆T

Where;

412.5 = 24.6 × c × (52.6 - 14.5)

412.5 = 937.26c

c = 412.5/937.26

c = 0.44 J/g°C

Therefore, If it took 412.5 J of heat to raise the temperature of 24.6 g of a substance from 14.5°C to 52.6°C, the specific heat of the substance is 0.44 J/g°C.

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The empirical formula of polyethylene can be determined by converting the given percentages of carbon (C) and hydrogen (H) into grams. To find the grams of each element, we assume a 100.0 g sample of polyethylene.

For carbon:

Mass of carbon = 86.0% × 100.0 g = 86.0 g

For hydrogen:

Mass of hydrogen = 14.0% × 100.0 g = 14.0 g

Therefore, in a 100.0 g sample of polyethylene, there are 86.0 grams of carbon and 14.0 grams of hydrogen.

The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. To determine the empirical formula, we need to find the ratio of carbon to hydrogen in terms of moles.

First, we convert the masses of carbon and hydrogen into moles using their respective molar masses. The molar mass of carbon is approximately 12.01 g/mol, and the molar mass of hydrogen is approximately 1.008 g/mol.

Number of moles of carbon = 86.0 g / 12.01 g/mol ≈ 7.162 mol

Number of moles of hydrogen = 14.0 g / 1.008 g/mol ≈ 13.89 mol

Next, we divide the number of moles of each element by the smallest number of moles to get a simplified ratio.

Carbon: Hydrogen ≈ 7.162 mol : 13.89 mol ≈ 1 : 1.939

Since we want to express the ratio in whole numbers, we multiply both sides by 2 to get a whole number ratio.

Carbon: Hydrogen ≈ 2 : 3.878

Rounding to the nearest whole number, we find that the empirical formula of polyethylene is CH₂.

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Answer: Corona

Explanation: hope this help

The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.

The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.

Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.

Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.

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1. Using your knowledge of the Brønsted-Lowry theory of acids and bases, complete the following acid-base reactions and indicate each conjugate acid-base pair.

i. OH + HPO₂ → H₂O + H₂PO₄²⁻

The conjugate acid-base pair is OH/H₂O, HPO₂²⁻/H₂PO₄²⁻

2) Identify the conjugate acid-base pairs in the following reactions. Write A, B, CA, and CB below the appropriate substance.

i. HCO₃⁻ + NH₃ → NH₄⁺ + CO₃²⁻

The conjugate acid-base pair is HCO₃⁻/CO₃²⁻, NH₃/NH₄⁺

ii. HCI + H₂O → H₃O⁺ + Cl⁻

The conjugate acid-base pair is H₂O/OH⁻, HCI/Cl⁻, H₃O⁺/H₂O, Cl⁻/HCI

iii. CH₃COOH + H₂O → H₃O⁺ + CH₃COO⁻

The conjugate acid-base pair is CH₃COOH/CH₃COO⁻, H₂O/OH⁻, H₃O⁺/H₂O

iv. HOCI + NH₃ → NH₄⁺ + ClO⁻

The conjugate acid-base pair is HOCI/ClO⁻, NH₃/NH₄⁺

3. Write the formula for conjugate bases formed by the following acids.

i. HPO₄²⁻ → PO₄³⁻

ii. H₂O → OH⁻

iii. CN⁻ → HCN

iv. HOOC-COO⁻ → HOOCCOOH

4) Write the formula for conjugate acids formed by each of the following bases.

i. H₃O⁺ → H₂O

ii. HCN → H₂CN⁺

iii. NH₃ → NH₄⁺

5. Classify each of the following pH values as acidic, basic, or neutral.

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The desired reaction is 2Al(s) + 3CO2 from Al2O3(s) + 3CO(g) (g) The reactions include 2 Al(s), 3/2 O2(g), and Al2O3(s), with H = 1675.7kJ. ————————— (1) CO(g) = CO2 + 1/2 O2(g) (g).

As a result, the enthalpies of a reactants and products are added together, and the result is used to compute the enthalpy of a reaction. This endothermic process generates and absorbs environmental heat if H is positive. This reaction is exothermic so emits heat into the environment if H is negative.

A negative H indicates that heat is transferred from the a system towards its surroundings, whereas a positive H indicates that heat is transferred from the surroundings into the system. An enthalpy of reaction (Hrxn) for a chemical reaction is the difference of enthalpy between the products and reactants; Hrxn is measured in kilojoules per mole.

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Answer:

C

Explanation:

it should be C

Answer:

Solid piece of ice.

Explanation:

Solid piece of ice can easily melt due to heat radiation

Moles can be converted to liters by the use of the stoichiometry of the reaction and the gas laws.

To convert moles to liters, you need to use the Ideal Gas Law. The Ideal Gas Law states that the number of moles of a gas is proportional to its volume at a given temperature and pressure. The equation is:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

By rearranging the equation, you can find the volume of a gas in liters when the number of moles is known:

V = nRT / P

Since the volume is in liters, the number of moles can be converted to liters by multiplying it by the volume.

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Answer:

When a photon of light hits an electron, the photon transfers some of its energy to the electron. If the photon has enough energy, it can excite the electron, which means that it can raise the electron to a higher energy state. In other words, the photon's energy can be absorbed by the electron, causing the electron to move to a higher energy level within an atom or molecule.

Answer:

Explanation:

As we know that in the photoelectric effect, a low-energy gamma photon that collides with an atom can tranfer all its energy to an inner orbital electron and cause the ejection of the ELECTRON FROM THE ATOM

The amount of energy required to eject the electrons depends upon on the atomic number.

Answer:

In this experiment, the amount of ice is the independent variable, and the temperature change is the dependent variable.

Rounding to the appropriate number of significant figures, the equilibrium constant (Kc) for the reaction is approximately 1.66.

To calculate the equilibrium constant (Kc) for the given reaction, we can use the formula:

Kc = ([H2]^3 * [N2]) / [NH3]^2

Plugging in the given equilibrium concentrations, we have:

Kc = (0.470^3 * 0.800) / (0.250^2)

Calculating the numerator:

(0.470^3 * 0.800) = 0.1037032

Calculating the denominator:

(0.250^2) = 0.0625

Now, dividing the numerator by the denominator:

Kc = 0.1037032 / 0.0625 = 1.6592512

The equilibrium constant represents the ratio of the concentrations of products to reactants at equilibrium. In this case, the equilibrium constant is greater than 1, indicating that the products (H2 and N2) are favored at equilibrium. This means that the forward reaction is favored, leading to the formation of more products compared to reactants.The equilibrium constant value of 1.66 suggests that the forward reaction is moderately favored at equilibrium, but without additional context, it is difficult to determine the extent of the reaction or the relative concentrations of reactants and products at the beginning of the reaction.

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Answer:

A. 2 : 13

B. 10 : 13

C. 10 moles of water, H₂O.

D. 2 moles of butane, C₄H₁₀

E. 116 g of butane, C₄H₁₀

F. 13 moles of oxygen, O₂

G. 416 g of oxygen, O₂

Explanation:

The equation for the reaction is given below:

2C₄H₁₀ + 13O₂ —> 8CO₂ + 10H₂O

A. Determination of the mole ratio between butane and oxygen gas.

Mole of butane, C₄H₁₀ = 2 moles

Mole of oxygen, O₂ = 13 moles

Mole ratio of butane and oxygen = 2 : 13

B. Determination of the mole ratio between water and oxygen gas

Mole of the water, H₂O = 10 moles

Mole of oxygen, O₂ = 13 moles

Mole ratio of water and oxygen = 10 : 13

C. Determination of the moles of water formed.

From the balanced equation above,

10 moles water, H₂O were produced.

D. Determination of the moles of butane burned.

From the balanced equation above,

2 moles of butane, C₄H₁₀ were burned.

E. Determination of the mass of butane burned.

Molar mass of C₄H₁₀ = (12×4) + (10×1)

= 48 + 10 = 58 g/mol

Mole of C₄H₁₀ = 2 moles

Mass of C₄H₁₀ =?

Mass = mole × molar mass

Mass of C₄H₁₀ = 2 × 58

Mass of C₄H₁₀ = 116 g

Thus, 116 g of butane, C₄H₁₀ were burned.

F. Determination of the number of mole of oxygen used.

From the balanced equation above,

13 moles of oxygen, O₂ were used.

G. Determination of the mass of oxygen used.

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ = 13 moles

Mass of O₂ =?

Mass = mole × molar mass

Mass of O₂ = 13 × 32

Mass of O₂ = 416 g

Thus, 416 g of oxygen, O₂ were used.

Answer:

In general, a falling barometer indicates the approach of a storm. If the mercury is over 30.20 inches but falling quickly, warmer, cloudier weather is coming. If the mercury continues to fall, the weather will worsen. When the mercury level is between 30.20 and 29.80 inches and dropping rapidly, expect precipitation.

Explanation:

Answer: idek warm?

Explanation:

1. 21.67g/ml

2. aluminium

Explanation:

1. density = mass/volume

385.8/17.8= 21.67ml

2. 1g/ml=0.1g/cm^3

21.67g/ml = 2.167g/cm^3

..... substance is probably aluminium

1.  the density of the metal is 21.67g/ml

2.  This metal is most likely aluminum

1.

\(density = mass \div volume\)

\(385.8\div 17.8= 21.67ml\)

2.

1g/ml=0.1g/cm^3

So,  

21.67g/ml = 2.167g/cm^3

Therefore,  substance is probably aluminum

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Answer:

I THINK IT IS TRUE  BECAUSE THEY ERE FIRST FOUND TO DEMOCRITUS ARISTOTLE AND PLATO THE ROMANS AND GREEK CHEMISTS .

Explanation:

Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

The order of reaction is defined as the power to which the concentration of the reactants are raised in the rate equation of the reaction.

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The mass of the solid aluminum that forms are 192.73 grams

To determine the mass of solid aluminum that forms, we need to use stoichiometry and the balanced chemical equation for the reaction between magnesium and aluminum nitrate.

The balanced chemical equation is:

3 Mg + 2 Al(\(NO_{3}\))3 → 3 Mg(\(NO_{3}\))2 + 2 Al

The equation shows that 3 moles of magnesium react with 2 moles of aluminum to produce 2 moles of aluminum nitrate.

To calculate the mass of solid aluminum, we need to know the amount of magnesium used. Given that the volume of the magnesium is 150.0 mL and its density is 1.738 g/cm³, we can calculate the mass of magnesium using the formula:

Mass = Volume × Density

Mass of magnesium = 150.0 mL × 1.738 g/cm³ = 260.7 g

Now, using the molar mass of magnesium (24.31 g/mol) and the molar ratio from the balanced equation, we can determine the moles of magnesium used:

Moles of magnesium = Mass of magnesium / Molar mass of magnesium

= 260.7 g / 24.31 g/mol

= 10.72 mol

According to the stoichiometry of the balanced equation, the ratio of moles of magnesium to moles of aluminum is 3:2. Therefore, the moles of aluminum formed will be:

Moles of aluminum = (2/3) × Moles of magnesium

= (2/3) × 10.72 mol

= 7.15 mol

Finally, we can calculate the mass of solid aluminum using its molar mass (26.98 g/mol):

Mass of aluminum = Moles of aluminum × Molar mass of aluminum

= 7.15 mol × 26.98 g/mol

= 192.73 g

Therefore, the mass of the solid aluminum that forms is approximately 192.73 grams.

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The helium tank has a pressure of 650 torr at 25 degree Celsius and when the temperature is tripled, the pressure will be approximately 1945.71 torr

To find the new pressure when the temperature is tripled, we can use the ideal gas law, which states that the pressure of a gas is directly proportional to its temperature when the volume and the number of particles remain constant. The ideal gas law is given by the equation:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to convert the initial temperature of 25 degrees Celsius to Kelvin. Adding 273.15 to the Celsius temperature gives us 298.15 K.

Let's assume that the volume, number of moles, and the gas constant remain constant.

If the temperature is tripled, the new temperature would be 3 times the initial temperature, which is 3 * 298.15 K = 894.45 K.

Now, we can set up a proportion to find the new pressure:

P1 / T1 = P2 / T2

Solving for P2 (the new pressure), we get:

P2 = (P1 * T2) / T1

Plugging in the values, we have:

P2 = (650 torr * 894.45 K) / 298.15 K

Calculating this expression, we find:

P2 ≈ 1945.71 torr

Therefore, when the temperature is tripled, the pressure will be approximately 1945.71 torr.

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Heat flows from our body to iron

Answer:

To calculate the heat released in this reaction, we need to use the formula:

Q = mcΔT

where Q is the heat released, m is the mass of the solution, c is the specific heat capacity of the solution, and ΔT is the change in temperature.

Assuming the density of the solution is 1 g/mL, the mass of the solution is 100 g (50 mL HCl + 50 mL NaOH). The specific heat capacity of the solution can be assumed to be the same as that of water, which is 4.18 J/g°C.

The change in temperature can be calculated as the final temperature minus the initial temperature:

ΔT = 30°C - 22°C = 8°C

Therefore, we have:

Q = (100 g) * (4.18 J/g°C) * (8°C) = 3344 J

The heat released in the reaction is 3344 J.

The value of ΔH for the reaction can be calculated using the formula:

ΔH = -Q/n

where Q is the heat released, and n is the number of moles of limiting reactant used in the reaction. In this case, the limiting reactant is NaOH, and we can calculate the number of moles of NaOH from its concentration and volume:

n(NaOH) = (0.1 L) * (1 mol/L) = 0.1 mol

Therefore, we have:

ΔH = -(3344 J) / (0.1 mol) = -33,440 J/mol

The value of ΔH for the reaction is -33,440 J/mol, which is negative because the reaction is exothermic (heat is released).

There would be 10 moles of cobalt in 6.022 x \(10^{24\) atoms of cobalt.

In order to calculate the number of moles in a given number of particles, we need to divide the number of particles by Avogadro's number.

6.022 x \(10^{24\) atoms of cobalt:

Therefore, there are 10 moles of cobalt in 6.022 x \(10^{24\) atoms of cobalt.

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Answer:

KE = 1/2*m*v^2

KE = 1/2*150kg*(20 m/s)^2

KE = 75kg * 400m²/s²

KE = 30,000 kg*m²/s²

KE = 30,000 N*m

KE = 30,000 J

Explanation:

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At equilibrium, the number of moles of Cl2(g) present is approximately 347.37 mol.

To determine the number of moles of Cl2(g) at equilibrium, we need to use the given equilibrium constant (Kc) and set up an ICE table to track the changes in the reactants and products.

The balanced equation for the reaction is:

CO(g) + Cl2(g) ⇌ COCl2(g)

Let's set up the ICE table:

  CO(g)     +     Cl2(g)     ⇌     COCl2(g)

Initial: 0.3500 0.05500 0

Change: -x -x +x

Equilibrium: 0.3500 - x 0.05500 - x x

Using the equilibrium concentrations in the ICE table, we can write the expression for the equilibrium constant (Kc) as:

Kc = [COCl2(g)] / [CO(g)][Cl2(g)]

Substituting the values into the equation, we have:

1.2 × 10^3 = (0.05500 - x) / [(0.3500 - x)(0.05500 - x)]

Simplifying the equation, we can cross-multiply and rearrange:

1.2 × 10^3 × (0.3500 - x)(0.05500 - x) = 0.05500 - x

Expanding and rearranging, we get:

0 = (1.2 × 10^3 × 0.05500 - 1.2 × 10^3x + 0.05500x) - x

Simplifying further:

0 = 66 - 1.245x + 0.05500x - x

0 = 66 - 0.19x

0.19x = 66

x = 66 / 0.19

x ≈ 347.37

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Water molecules did not have a slight negative charge on one end and a slight positive charge on another, the loss of polarity would have profound effects on various biological, chemical, and physical processes. The unique properties of water that are vital for life as we know it would be significantly altered, potentially rendering many biological systems nonfunctional and disrupting the stability of ecosystems.

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