Which equations are examples of the Distributive Property of Multiplication over Addition? (choose two)

A: 3d + 3e = 3(d + e)
B: c(-5) +c (b) = c (-5 + b)
C: a + (b + c) = (a + b) + c
D: (a + b) × c = c × (a + b)

Answer:

37.5

Step-by-step explanation:

cosФ = \(\frac{A}{H}\)

cos(33°35') = \(\frac{m}{45}\)

m = 45 × cos(33°35')

m = 37.5 (1d.p.)

Answer:

They are similar, so 6/5 = 10/x.

You can do the rest yourself!

Answer:

Step-by-step explanation:

$723.98 x 0.0925= $66.96815

$723.98+$66.97= $790.95

Round up to $791

Answer:

120

Step-by-step explanation:

used a calculator :)

If this is asking 5% of $530 then the answer is 26.5

If this is asking that 530 is 5% then the answer is 10600

Answer:

The second graph

Step by Step

First, note down the points given.

(-2, -1) etc

Then find the points on the graphs and see if the line of the graph goes through the point.

(-2,-1): both lines go through this point

(0,0) both lines go through this point

(2,1) only the second graph goes through this point

Therefore, the second graph is the correct answer. You can check the last point if you want to double check.

Answer:

\(d = 13\)

General Formulas and Concepts:

Pre-Algebra

Algebra I

Slope-Intercept Form: y = mx + b

The y-intercept is the y value when x = 0.  Another way to reword that is when the graph crosses the y-axis.

The x-intercept is the x value when y = 0.  Another way to reword that is when the graph crosses the x-axis.

Algebra II

Step-by-step explanation:

Step 1: Define

Equation 5x - 12y = 60

Step 2: Rewrite in slope-intercept form

Step 3: Find x and y intercept

x-intercept

y-intercept

Step 4: Write coordinates

x-int (12, 0)

y-int (0, -5)

Step 5: Find distance d

Answer:

B

Step-by-step explanation:

If we are working in base five, then in the 1203, there would be 3 in the ones place. 3

In the 5 place, there is 0.

In the 25's place, there is a 2, which means 2*25=50

In the 125's place, there is a 1, 1*125=125.

125+50+3=178

Answer:

B. 178

Step-by-step explanation:

1203 to base 5 equals:

\((1 \times {5}^{3} ) + (2 \times {5}^{2} ) + (3 \times 1)\)

\(125 + 50 + 3 = 178\)

Answer:

d is the answer

Step-by-step explanation:

just read the statements properly

Answer: Move 3 and one-half units right because the x-coordinate is Negative 3 and one-half. Negative 3 and one-half is between 3 and 4.

IT'S A

Answer:

hello

Step-by-step explanation:

The required probability that William worked on last year was an anniversary party is 1/ 36.

As mentioned in the quesiton,
William is a very busy professional DJ. Last year, he worked at 10-anniversary parties and 26 other events.

Probability can be defined as the ratio of favorable outcomes to the total number of events.

Here,
Total sample space = 26 + 10 = 36
Number of favorable outcomes = 1
the probability that William worked on last year is was an anniversary party,
= Favorable outcome/sample space
= 1 / 36

Thus, the required probability that William worked last year is 1/ 36.

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Answer:

Domain={2,5,8}

Range={1,3,6}

Function: YES

Step-by-step explanation:

The Domain of a Function

Is the set of values the input variable x takes.

Range of a Function

It's the set of values the output function takes when x moves into the function's domain.

A function is a relation between an input and an output set of values with the condition that every element in the domain relates only with one element in the range.

Following the definitions above, the domain of the relationship is the set of input values:

Domain={2,5,8}

The range is the set of output values:

Range={1,3,6}

Since each element in the input set is related only to one element in the range, the given relationship is a function.

Answers:

Domain={2,5,8}

Range={1,3,6}

Function: YES

36/15 = 8/a

multiply a .. on both sides

a×36/15= 8

multiply 36/15 reciprical on both sides

a= 8 × 15/36

a= 120/36

a= 3.33

Answer:

a = 10/3 , a = 3.3

Step-by-step explanation:

1: determine the defined range

36/15 = 8/a  a=0

2: reduce the fraction with 3

12/5 = 8/a

3: simplify the equation using cross-multiplication

12a = 40

4: divide both sides of the equation by 12

a = 10/3 , a=0

5: check if the solution is in the defined range

a = 10/3

Part A: To calculate the measures of center, we can find the median and the mean for each school.

For Bay Side School, the median class size is the average of the 8th and 9th values when the data is sorted in ascending order. The 8th and 9th values are both 25, so the median class size is 25.

To find the mean class size for Bay Side School, we can add up all the class sizes and divide by the total number of classes. The sum of the class sizes is 12 + 12 + 12 + 14 + 15 + 15 + 16 + 16 + 18 + 18 + 20 + 20 + 23 + 25 + 25 = 243. There are 15 classes, so the mean class size is 243/15 ≈ 16.2.

For Seaside School, the median class size is the average of the 8th and 9th values when the data is sorted in ascending order. The 8th and 9th values are both 15, so the median class size is 15.

To find the mean class size for Seaside School, we can add up all the class sizes and divide by the total number of classes. The sum of the class sizes is 10 + 10 + 10 + 11 + 12 + 15 + 15 + 16 + 17 + 17Part A (continued):

18 + 18 + 20 + 20 + 25 = 222. There are 14 classes, so the mean class size is 222/14 ≈ 15.9.

Therefore, the measures of center for Bay Side School are: median = 25, mean ≈ 16.2.

The measures of center for Seaside School are: median = 15, mean ≈ 15.9.

Part B: To calculate the measures of variability, we can find the range and the interquartile range (IQR) for each school.

For Bay Side School, the range is the difference between the largest and smallest class sizes. The largest class size is 25, and the smallest class size is 12, so the range is 25 - 12 = 13.

To find the IQR for Bay Side School, we need to find the first quartile (Q1) and the third quartile (Q3) of the data. From the stem-and-leaf plot, we can see that Q1 is 15 and Q3 is 20. Therefore, the IQR is 20 - 15 = 5.

For Seaside School, the range is the difference between the largest and smallest class sizes. The largest class size is 25, and the smallest class size is 10, so the range is 25 - 10 = 15.

To find the IQRPart B (continued): for Seaside School, we need to find the first quartile (Q1) and the third quartile (Q3) of the data. From the stem-and-leaf plot, we can see that Q1 is 12 and Q3 is 18. Therefore, the IQR is 18 - 12 = 6.

Therefore, the measures of variability for Bay Side School are: range = 13, IQR = 5.

The measures of variability for Seaside School are: range = 15, IQR = 6.

Part C: If you are interested in a smaller class size, Seaside School is a better choice because its measures of center are lower than those of Bay Side School, indicating that its class sizes tend to be smaller on average. Additionally, Seaside School has a smaller range and IQR, indicating less variability in class size. Therefore, there is less chance of encountering very large classes at Seaside School compared to Bay Side School.

Answer: I'm pretty sure

Step-by-step explanation:

Answer: This situation cannot be true for any positive value of x. The valid range would be 0 < x < 4. If the x is less than 4, the perimeter of triangle 1 is always greater than triangle 2.

Explanation: We need to add up the lengths of the sides for obtaining the perimeters first.

Triangle 1: 5x + 57

Triangle 2: 11x + 33

Then, we need to build up an inequality for the case which the perimeter of triangle 1 is always greater than triangle 2.

This means => 5x + 57 > 11x + 33

If we write "x" values on one side:

24 > 6x

Then dividing by 6 for both sides:

4 > x

This means that a positive value of x should be less than 4 for this particular situation.

(4)(25) - 300 can be written as an addition equation: 100 + (-300).

An equation is a pair of algebraic equations with the equal sign (=) in the middle and the same value.

Given:

An equation is (4)(25)-300.

To write (4)(25)-300 as an addition equation,

we can break it down into two separate addition equations as follows:

(4)(25) - 300 = (4)(25) + (-300)

To solve this further,

substitute the value 25 x 4 = 100 to the above equation, we get,

= 100 + (-300)

Therefore, the equation in the required form is  100 + (-300).

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Answer:

  Maybe congruent

Step-by-step explanation:

You have two isosceles triangles, one with a marked base angle of 49° and the other marked with an a.pex angle of 82°. One side of one triangle is marked as 11 cm.

In order for the triangles to be congruent, corresponding angles must be congruent, and corresponding sides must be congruent.

Each isosceles triangle has two congruent base angles and an a.pex angle that total 180°. The base angles in the triangle on the right are ...

  2x +82° = 180°

  2x = 98°

  x = 49° . . . . . . congruent with the base angles of the other triangle

Corresponding angles of the triangles are congruent, so the triangles are similar.

Only one side in the diagram is marked, so we cannot make any claim regarding the measures of corresponding sides in the two triangles. If corresponding sides are congruent in the similar triangles, then the triangles will be congruent.

We can only conclude that the triangles may be congruent.

Answer:

a)180-57-20=103

b)180-103=77

Step-by-step explanation

Answer:

Exact Form = 83/24

Decimal Form = 3.458333333

Mixed Number Form= 3 11/24

Step-by-step explanation:

Answer:

I need points thanks

Step-by-step explanation:

Answer:

1/12 of the original amount

Step-by-step explanation:

All you need to do is multiple 1/3 (the fraction left over) by him and his friends (4).

1/3x1/4=1/12

You make 4 into 4/1 and then flip it making it 1/4 since we are dividing.

The final answer is 1/12.

Answer:

she can make a maximum of 4 bags.

peach bags containing 7 pencils and 18 erasers.

Step-by-step explanation:

find all the factors each numbers are divisible by:

28 => 1, 2, 4, 7, 14, 28

72 => 1, 2, 3, 4, 8, 9, 18, 24, 36, 72

choose the maximum common denominator.

Answer:

its 1 48 and 4 12

Step-by-step explanation:

1X48=48

4X12=48

=48 and 48

two pairs

After analyzing each factor pair of 48, the two factor pairs that contain at least one prime factor are option b) 2 and 24 (2 is prime) and option c) 3 and 16 (3 is prime).

The factors of 48 can be found by dividing it by different numbers and identifying the pairs. The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48 itself, as mentioned in the question.

Now, let's analyze each factor pair and check if they contain a prime factor:

a) 1 and 48: Both 1 and 48 are not prime, as they have other factors besides themselves.

b) 2 and 24: Among these two, only 2 is a prime number, as it has no divisors other than 1 and 2. However, 24 is not a prime number since it has divisors such as 1, 2, 3, 4, 6, 8, and 12.

c) 3 and 16: Among these two, only 3 is a prime number (divisors: 1 and 3). On the other hand, 16 is not prime, as it has divisors like 1, 2, 4, 8.

d) 4 and 12: Among these two, only 2 is a prime number, and 4 is not a prime (divisors: 1 and 4). 12 is also not a prime number, as it has divisors like 1, 2, 3, 6.

e) 6 and 8: Neither 6 nor 8 is a prime number, as both have divisors other than 1 and themselves.

So, the Main Answer: b) 2 and 24, c) 3 and 16

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