Which events are the craters on the moon evidence of?.
Answers
The craters on the moon are evidence of past collisions with asteroids and meteoroids.
When these objects impact the surface, they release a tremendous amount of energy that melts and vaporizes the impacted material,
which then sprays outwards, forming a crater.
Because the moon has no geological activity to erase the evidence of these impacts, the craters are still visible today.
The size and number of craters on the moon provide scientists with valuable information about the history of the solar system.
The craters on the moon are also important because they help scientists understand the impact history of the Earth.
Since the Earth has an atmosphere and geological activity, the evidence of past impacts is often erased.
However, by studying the craters on the moon, scientists can get an idea of how often large objects impact the Earth and what kind of damage they can cause.
In conclusion, the craters on the moon are evidence of past collisions with asteroids and meteoroids. The size and number of these craters provide valuable information about the history of the solar system. By studying these craters, scientists can gain a better understanding of the impact history of both the moon and the Earth.
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Related Questions
when a car drives in a circle there must be ?
Answers
no net force axting on it
Answer:
I think none of above
Explanation:
hioe it's right answer
In a race, you run past another runner and your speed relative to them is 0.3m/s. If you
are running at 8.2m/s, how fast is the other runner running? Give your answer to two
significant figures.
Answers
A 4.28 m deep well acts as a Closed pipe. When wind blows across the top. what is the fundamental frequency it creates? (Speed of sound = 343 m/s) (Unit = H2)
Answers
Answer:
F = v / λ
= 343 / 4.28
= 80.1 Hz
Explanation:
The formula connecting wavelength, frequency and speed is F = v / λ, where frequency is represented by F, speed represented by v and wavelength represented by λ. This applies to mechanical waves, which include both sound waves and electromagnetic waves.
Oxygen has 6 valence electrons. how many hydrogen atoms (who have 1 valence electrons) can bond with it? remember the octet rule.
Answers
Answer:
Oxygen starts with six valance electrons and ends with six valance electrons but after bonding has parts of the densities of 8 electrons
Explanation:
Chemical bonding does not increase the valance electrons. Oxygen has 6 valence electrons. Bonding is sharing of valance electrons
The electron density of two of the valance electrons of Oxygen are shared with the Hydrogen atoms. The Hydrogen atoms is turn share part of the electron density of their single electron with Oxygen.
This means that there are parts of 8 electron densities around the Oxygen. This does not increase the number of valance electrons of Oxygen. (Note the sharing is very unfair, Oxygen gets more than its
share of the electron densities of the two electrons used for the chemical bond.
Explanation:
what seems to control the assembly and disassembly of intermediate filaments?
Answers
The assembly and disassembly of IFs are regulated by a variety of factors, including phosphorylation, subunit availability, pH, and ionic strength.
Intermediate filaments (IFs) are components of the cytoskeleton that control a variety of biological processes. IFs are typically less dynamic than microtubules and actin filaments, and they appear to be more stable. The assembly and disassembly of intermediate filaments are regulated by phosphorylation-dephosphorylation mechanisms.
The assembly and disassembly of intermediate filaments are controlled by a variety of factors. One of the primary determinants of IF dynamics is phosphorylation. Phosphorylation of specific residues on the IF proteins affects both the ability of the protein to form filaments and its stability once it has formed a filament.
In some cases, the presence of free subunits can promote filament formation, while in others, the formation of complexes between subunits can inhibit filament assembly. Changes in pH or ionic strength can also affect the assembly and disassembly of IFs.Intermediate filaments (IFs) are cytoskeletal structures that are typically more stable than microtubules or actin filaments.
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Two layers of fluid are contained between parallel plates, each of 0. 8 m2 area. The fluid viscosities are η1 = 0. 12 N. S. M-2 and η2 = 0. 18 N. S. M-2. The thickness of each layer of fluid is L1 = 0. 62 mm and L2 = 0. 56 mm. What is the fluid relative velocity at the interface between the two plates, if the upper plate has a speed of 1. 3 m. S-1 at the interface?
Answers
According to the given statement , the fluid relative velocity at the interface between the two plates is approximately 0.684 m/s.
To find the fluid relative velocity at the interface between the two plates, we can use the concept of shear rate and the formula for the velocity gradient.
First, let's calculate the shear rate (γ) using the formula:
γ = Δv / Δx
Where:
- Δv is the velocity difference between the two plates, which is given as 1.3 m/s (since the upper plate has a speed of 1.3 m/s at the interface).
- Δx is the distance between the two plates, which is the sum of the thicknesses of the two fluid layers:
Δx = L1 + L2.
Given that L1 = 0.62 mm and L2 = 0.56 mm, we need to convert these values to meters:
L1 = 0.62 mm = 0.62 × 10⁻³ m
L2 = 0.56 mm = 0.56 × 10⁻³ m
Now we can calculate Δx:
Δx = L1 + L2
Substituting the values, we get:
Δx = 0.62 × 10⁻³ m + 0.56 × 10⁻³ m
= 1.18 × 10⁻³ m
Now we can calculate the shear rate:
γ = Δv / Δx
= 1.3 m/s / 1.18 × 10⁻³ m
Performing the division, we find:
γ ≈ 1101.7 s^-1
The shear rate (γ) represents the velocity gradient between the two fluid layers. To find the fluid relative velocity at the interface, we need to multiply the shear rate by the thickness of the first layer (L1).
Relative Velocity = γ * L1
Substituting the values, we get:
Relative Velocity = 1101.7 s⁻¹ * 0.62 × 10⁻³ m
Performing the multiplication, we find:
Relative Velocity ≈ 0.684 m/s
Therefore, the fluid relative velocity at the interface between the two plates is approximately 0.684 m/s.
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Students are completing a lab in which they let a lab cart roll down a ramp. The students record the mass of the cart, the height of the ramp, and the velocity at the bottom of the ramp. The students then calculate the momentum of the cart at the bottom of the ramp.
A 4 column table with 3 rows. The first column is labeled Trial with entries 1, 2, 3, 4. The second column is labeled Mass of Cart in kilograms with entries 200, 220, 240, 260. The third column is labeled Height of ramp in meters with entries 2.0, 2.1, 1.5, 1.2. The fourth column is labeled Velocity at Bottom in meters per second with entries 6.5, 5.0, 6.4, 4.8.
Which trial’s cart has the greatest momentum at the bottom of the ramp?
Answers
Answer:
second column
Explanation:
Answer:
Trial 3 is the answer.
Explanation:
A 3,000 kg truck moving at +10 m/s hits a 1,000 kg parked car which moves off at +15 m/s. What is the velocity of the truck?.
Answers
The velocity of the truck is 5m/s.
Given:
m1 = 3000 (mass of truck)
m2 = 1000 (mass of car)
u1 = 10m/s( initial velocity of truck)
u2=0 (initial velocity of the car)
v1 = ? (final velocity of the truck )
v2 = =15m/s (final velocity of the car)
The momentum of the system initially,
pi=m1u1+m2u2
\(pi = 3000 * 10 + 1000 * 0\\pi = 30000 + 0\\pi=30000\)
We know that pi = pf
m1u1+m2u2=m1v1+m2v2
\(30000=3000v1+15000\)
\(3000v1=30000-150003000v1=15000v1=15000/3000v1=5m/s\)
What is conservation of momentum?
The conservation of momentum states that, within some problem domain, the amount of momentum remains constant; momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton's laws of motion.
What is the formula law of conservation of momentum?
As a result, the equation of the law of conservation of momentum is as follows: m 1 u 1 +m 2 u 2 represents the total momentum of particles A and B before the collision, and m 1 v 1 +m 2 v 2 represents the total momentum of particles A and B after the collision.
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PLEASE HELP!!
A student fires a cannonball diagonally with a speed of 34.om/s from a height of 66.0m as shown. Neglect drag. Determine all unknowns and answer the following questions.
How long did the ball rise?
What was the ball's maximum height above the ground?
How long did the ball remain in the air?
How far from the base of the building did the ball land?
How fast was the ball moving as it struck the ground?
Answers
We can use the equations of projectile motion to determine the unknowns and answer the following questions:
The time it takes for the ball to reach its maximum height can be found using the following equation:
Vy = Voy - gt
where Voy is the initial vertical velocity and g is the acceleration due to gravity. At the maximum height, the vertical velocity of the ball is zero, so we have:
0 = Voy - gt
t = Voy/g
t = (34.0 m/s)sin(73°)/9.81 m/s^2 ≈ 3.6 s
The maximum height reached by the ball can be found using the following equation:y = Voyt - 1/2 gt^2
where y is the vertical displacement of the ball. At the maximum height, the vertical displacement is equal to the initial height of the ball, so we have:
66.0 m = (34.0 m/s)sin(73°)t - 1/2 (9.81 m/s^2)t^2
t ≈ 3.6 s
y = (34.0 m/s)sin(73°)(3.6 s) - 1/2 (9.81 m/s^2)(3.6 s)^2 ≈ 117 m
The total time of flight can be found using the following equation:t_total = 2t
where t is the time it takes for the ball to reach its maximum height. Substituting the value of t from above, we get:
t_total = 2(3.6 s) ≈ 7.2 s
The horizontal distance traveled by the ball can be found using the following equation:x = Vx t
where Vx is the initial horizontal velocity of the ball. Substituting the given values, we get:
x = (34.0 m/s)cos(73°)(7.2 s) ≈ 241 m
The final velocity of the ball can be found using the following equation:Vf = sqrt(Vx^2 + Vy^2 - 2gy)
where Vx and Vy are the horizontal and vertical components of the velocity, respectively, and y is the vertical displacement of the ball. At the instant of impact, the vertical displacement is equal to the initial height of the ball, so we have:
y = 66.0 m
Substituting the given values, we get:
Vf = sqrt[(8.9 m/s)^2 + (32.7 m/s)^2 - 2(9.81 m/s^2)(66.0 m)] ≈ 29.1 m/s
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what is the meaning of vitality
Answers
Which of the following is not an acid? A. HCI B. H2SO4 C.HNO3 D. NaOH
Answers
Answer:
NaOH
Explanation:
oxide of a non-metal element is acidic. Na is metal. so NaOH is basic.
Answer:
d is the answer
Explanation:
wheres my lil mama?
Answers
Answer:
Explanation:
I FOUND YOUUU
Answer:
300,000
Explanation:
right here dad_0 ;) u got snap?
What is density meaning
Answers
Answer:
Density is defined as how tightly or loosely packed a substance is, or to the number of things or people in a certain area.
Explanation:
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which car has traveled farther after 10 s ? which car has traveled farther after 10 ? car a car b both cars travel the same distance. request answer part e after 10 s which car has a larger kinetic energy? view available hint(s)for part e after 10 which car has a larger kinetic energy? car a car b both cars have the same kinetic energy. part f after 10 s which car has a larger momentum? view available hint(s)for part f after 10 which car has a larger momentum? car a car b both cars have the same momentum. provide feedback correct. no additional followup.
Answers
1. Car A will travel farther than Car B after 10 s.
2. Car A will have a larger kinetic energy due to its greater mass.
3. Car A will have a larger momentum due to its greater mass.
Assuming both cars have the same constant acceleration, the car with the greater weight (Car A) will travel farther after 10 s according to the equation d = 0.5at^2, where d is the distance, a is the acceleration, and t is the time. Therefore, Car A will travel farther than Car B after 10 s.
The kinetic energy of a moving object is given by the equation KE = 0.5mv^2, where KE is the kinetic energy, m is the mass, and v is the velocity. Both cars have the same acceleration, so after 10 s, the car with the higher velocity will have a larger kinetic energy. Assuming both cars accelerate uniformly, Car A will have a larger kinetic energy due to its greater mass.
The momentum of an object is given by the equation p = mv, where p is the momentum, m is the mass, and v is the velocity. After 10 s, the car with the higher velocity will have a larger momentum. Assuming both cars accelerate uniformly, Car A will have a larger momentum due to its greater mass.
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--The complete question is, Car A is 1000g in weight and B is 800g. Both car begin from rest and start at same position.
1. which car has traveled farther after 10 s?
2. after 10 s which car has a larger kinetic energy?
3. after 10 s which car has a larger momentum?--
H+ H+He
A. alpha decay
B. beta decay
C. nuclear fusion
D. nuclear fission
Help
Answers
Answer:
c. nuclear fusión oh A. alpha decay
if a stone falls vertically downward from a roof 20m above the ground to a behicle 2m above the ground, the car is known as the________
Answers
an object is at a position 6.0 cm from a converging lens with a focal length of 3.0 cm. the position of the image relative to the lens is
Answers
Using the lens formula and magnification equation, we find that the position of the image relative to the lens is real and upright.
Object distance (u) = -6.0 cm (since the object is located to the left of the lens)
Focal length (f) = 3.0 cm
We have already determined that the position of the image relative to the lens is -6.0 cm.
Now, we calculate the magnification (m) using the formula:
m = -v/u
where:
v = image distance from the lens
Plugging in the values:
m = -(-6.0 cm) / (-6.0 cm)
m = 1
The positive magnification value (m = 1) indicates that the image is of the same size as the object.
Now, based on the magnification value and the position of the image, we can determine the nature and orientation of the image:
If the magnification (m) is positive and the image is formed on the same side as the object (left of the lens), the image is real and upright.
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Is there evidence to support the claim that the higher baking temperature results in wafers with a lower mean photoresist thickness? use = 0.05.
Answers
To determine if there is evidence to support the claim that higher baking temperature results in wafers with a lower mean photoresist thickness, we can conduct a hypothesis test.
Null hypothesis (H0): Higher baking temperature does not result in wafers with a lower mean photoresist thickness.
Alternative hypothesis (Ha): Higher baking temperature results in wafers with a lower mean photoresist thickness.
We will use a significance level (α) of 0.05.
Next, we need to collect data on photoresist thickness at different baking temperatures. Let's assume we have two groups: Group A with a lower baking temperature and Group B with a higher baking temperature.
We will calculate the mean photoresist thickness for each group.
Then, we will conduct a two-sample t-test to compare the means of the two groups.
If the p-value obtained from the t-test is less than 0.05, we will reject the null hypothesis and conclude that there is evidence to support the claim that higher baking temperature results in wafers with a lower mean photoresist thickness.
If the p-value is greater than or equal to 0.05, we will fail to reject the null hypothesis and conclude that there is not enough evidence to support the claim.
It is important to note that conducting the actual experiment, collecting data, and performing the statistical analysis is required to provide a definitive answer to the question.
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Determine the free vibration response of the structure of Problem 10.6 (and Problem 9.5) if it is displaced as shown in Fig. P10.8a and b and released. Comment on the relative contributions of the two vibration modes to the response that was produced by the two initial displacements. Neglect damping. Chap. 10 Problems 443 ml2 Rigid beams 2" 1"-1" EI EL Figure P10.8
Answers
To determine the free vibration response of the structure of Problem 10.6 (and Problem 9.5) when it is displaced as shown in Fig. P10.8a and b and released, follow these steps:
1. First, identify the natural frequencies and mode shapes of the structure from Problems 9.5 and 10.6.
2. Next, apply the initial displacement conditions from Fig. P10.8a and b to the mode shapes.
3. Calculate the modal participation factors by taking the dot product of the initial displacement vector with the mode shapes.
4. Determine the amplitude of vibration for each mode by dividing the modal participation factor by the natural frequency of the corresponding mode.
5. The free vibration response can now be calculated as a linear combination of the mode shapes, scaled by their respective amplitudes and time-varying factors (e.g., sine or cosine of the natural frequency multiplied by time).
Regarding the relative contributions of the two vibration modes to the response produced by the initial displacements:
- If the modal participation factor for one mode is significantly larger than the other, it indicates that the corresponding mode contributes more to the overall response.
- In contrast, if the modal participation factors are similar in magnitude, both modes contribute comparably to the overall response.
It is important to neglect damping in this analysis to focus on the inherent characteristics of the structure and the initial displacements.
This will provide a simplified yet insightful understanding of the structure's free vibration response.
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Gwen is completing a physics investigation involving the speeds of toy cars on a track. Two cars are going to be released from the top of a ramp and timed until they reach the bottom. Before her investigation, Gwen comes up with a hypothesis. She states that toy car A will be faster than toy car B. She runs three trials of her investigation and records her data.
20 POINTS PLSSS help...During her investigation, Gwen is using a reference point to help her in her measurements. What is a reference point used to measure?
A. energy
B. magnetism
C. mass
D. movement
Answers
Magnetism is using a reference point to help her in her measurements.
What is Magnetism?The force that magnets use to either attract or repel one another is known as magnetism.
The force that magnets use to either attract or repel one another is known as magnetism. Electric charges in motion are the source of magnetism.
Atoms, the smallest building blocks of matter, make up every substance. There are electrons in every atom, which are charged particles. The electrons that make up an atom's nucleus, or core, spin like tops.
Therefore, Magnetism is using a reference point to help her in her measurements.
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help!!!!!!!! ill give brainliest
Answers
Answer:
Below
Explanation:
Final velocity (m/s ) - Initial velocity (m/s) is the change in velocity
this will be units of m/s
then change in velocity ( m/s) / change in time (s) = accel ( m/s^2 )
You accidentally drop an eraser out of the window of an apartment 15 m above the ground
Answers
Answer:
hello, yes or nou sorry jaja
3. A 700 kg horse has 4000 J of kinetic energy as it is running.
What is the velocity of the horse?
K=
m.v2
2
< PREVIOUS
1
2
O
Answers
Answer:
Explanation:
FREE BRAINLIEST! if you can answer this correctly ill give you brainliest and answer some of the questions you have posted :) thank you very much!!! (22pts)
Answers
b) accelerate to the left as much more pressure is pulling it in that direction and on the right however , there is less force .
ok pls answer at least one-
Answers
Answer:
1. Thermal energy and Chemical it think and 2. Mecanical energy and potental
Explanation:
SOOO SORRY if wrong ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
The populations P (in thousands) of a particular county from 1971 through 2014 can be modeled byP = 71.7e0.0345twhere t represents the year, with t = 1 corresponding to 1971.(a) Use the model to complete the table. (Round your answers to the nearest whole number.)YearPopulation1980101240 Correct: Your answer is correct.1990142949 Correct: Your answer is correct.2000201843 Correct: Your answer is correct.2010285000 Correct: Your answer is correct.(b) According to the model, when will the population of the county reach 350,000?2018 Incorrect: Your answer is incorrect.
Answers
ANSWERS
(a) Year - Population
• 1980 - 101,240
,• 1990 - 142,949
,• 2000 - 201,843
,• 2010 - 285,000
(b) 2016
EXPLANATION
(a) The population (in thousands) each year is given by,
\(P=71.7\cdot e^{0.0345t}\)If t = 1 represents year 1971, then for each year we have to find the difference between the year and 1970.
For year 1980,
\(P=71.7\cdot e^{0.0345(1980-1970)}\approx101.240\)The population is 101,240.
For year 1990,
\(P=71.7\cdot e^{0.0345(1990-1970)}\approx142.949\)The population is 142,949.
For year 2000,
\(P=71.7\cdot e^{0.0345(2000-1970)}\approx201.843\)The population is 201,843.
For year 2010,
\(P=71.7\cdot e^{0.0345(2010-1970)}\approx285.000\)The population is 285,000.
(b) In this problem we're given the population 350,000 and we have to find in what year the county will reach that population. In other words, we have to find t and then add that to 1970 to find the year.
Let's solve for t,
\(P=71.7\cdot e^{0.0345t}\)Divide both sides by 71.7,
\(\begin{gathered} \frac{P}{71.7}=\frac{71.7}{71.7}\cdot e^{0.0345t} \\ \frac{P}{71.7}=e^{0.0345t} \end{gathered}\)Apply natural logarithm to both sides,
\(\begin{gathered} \ln \frac{P}{71.7}=\ln e^{0.0345t} \\ \ln \frac{P}{71.7}=0.0345t \end{gathered}\)Divide both sides by 0.0345,
\(\begin{gathered} \frac{\ln \frac{P}{71.7}}{0.0345}=\frac{0.0345t}{0.0345} \\ \frac{\ln\frac{P}{71.7}}{0.0345}=t \end{gathered}\)And finally replace P and solve. Remember that P is in thousands of years, so we have to replace it by 350,
\(t=\frac{\ln \frac{350}{71.7}}{0.0345}=45.955\approx46\)This is 46 years after 1970,
\(1970+46=2016\)Let's see what's the population in 2016 to check the answer,
\(P=71.7\cdot e^{0.0345(2016-1970)}\approx350.546\)It is a bit more than 350,000. But let's see what's the population in 2015,
\(P=71.7\cdot e^{0.0345(2015-1970)}\approx338.658\)In 2015 population of the county won't reach 350,000. Thus, the county will have a population of 350,000 in 2016
Cars B and C are identical, each weighing 2820 lb (including driver), driving at the exact same speed of 58.5 ft/s on the same road that has coefficients of riction µs = 0.855 and µk = 0.715. Car B is at the bottom of a dip (radius = 775 ft) at exactly the same time car C is at the crest of a hill (radius also = 775 ft) when both drivers slam on their brakes simultaneously and both cars begin to slide
(they do not have anti-lock brakes).
a) What is the tangential acceleration (i.e., the
acceleration parallel to the road) of each car as it slides on the road at the positions described?
b) What is the magnitude of the total force that the road exerts on each car?
Answers
The tangential acceleration (i.e., the acceleration parallel to the road) of each car as it slides on the road at the positions described is -6.61 ft/s². Weight of car = 2820 lbSpeed of cars = 58.5 ft/s. Coefficient of friction,μs = 0.855μk = 0.715.
Radius of the dip, r = 775 ft.a) What is the tangential acceleration (i.e., the acceleration parallel to the road) of each car as it slides on the road at the positions described?Now, we need to find the tangential acceleration of each car during sliding.Let F be the frictional force exerted by the road on the car.Using, the following formula we can find the force exerted on the cars.
F=μs N = μs m g = 0.855 × 2820 × 32.2 lb = 80445.6 lb.a = F/ma = 80445.6 lb/2820 lba = 28.54 ft/s²The total tangential acceleration is the acceleration due to gravity subtracted by the frictional force, which is as follows,a = -g sinθ - μs g cosθa = -32.2 sin(0) - 0.855 × 32.2 cos(0)a = -27.53 ft/s²The tangential acceleration is,-6.61 ft/s².b) What is the magnitude of the total force that the road exerts on each car?The force acting on the cars can be found by,Force = mass × acceleration (F = ma)Force, F = 2820 × 6.61 lbForce, F = 18,601.4 lb.The force exerted on each car is 18,601.4 lb.
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What is kinetic energy
Answers
Answer:
Kinetic energy, form of energy that an object or a particle has by reason of its motion. ... Kinetic energy is a property of a moving object or particle and depends not only on its motion but also on its mass.
Credits to britannica.com
Explanation:
Hope this helps
Kinetic energy of an object is the energy that it possesses due to its motion.
According to the conservation of momentum, if a small football player collides with a much larger football player, which of the following statements will be true? a The larger football player will move, but because of his larger mass, his velocity will be much slower than the smaller player b The smaller football player will be stopped completely, his mass being not enough to move the larger one c The larger football player will have to start moving towards the smaller one as it collides if there is to be any effect d The smaller football player will experience a larger force than the larger football player
Answers
Answer:
a The larger football player will move, but because of his larger mass, his velocity will be much slower than the smaller player
Explanation:
When the collision takes two equal and opposite forces are created at the point of collision . The force created on the bigger mass will force it to accelerate and the force on moving smaller mass will force it to slow down .
Because of bigger mass , acceleration on bigger mass will be less and hence its velocity will be less .
Hence option a is the right answer.
What happened as the mass of the Sun increased during the formation of the
solar system?
A. The gravitational force of the Sun stayed constant.
B. The gravitational force of the Sun decreased.
C. The gravitational force of the Sun increased.
D. The gravitational force of the Sun gained inertia.
Answers
Answer:
C
Explanation:
The gravitational force of the Sun increased
If the mass of the Sun increased during the formation of the solar system, the gravitational force of the Sun increased.
What is the formation of the solar system?A massive concentration of interstellar gas and dust formed a molecular cloud that would become the sun's birthplace before the solar system existed. Cold temperatures caused the gas to clump together, increasing its density steadily.
Gravity continued to collapse the material onto the developing solar system, resulting in the formation of a star and a disc of material from which the planets would form. According to NASA, the newborn sun eventually accounted for more than 99% of the mass of the solar system (opens in new tab).
When the pressure inside the star became so high that fusion occurred, converting hydrogen to helium, the star began to blast a stellar wind, which helped clear out debris and prevented it from falling inward.
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