which expressions can we use to describe how many more seconds tatenda spends than ciara spends mowing lawns during 4 weeks?

Answer:

the answer is 120 feet

Step-by-step explanation:

Since angle G and angle H are complementary angles, the value of x is 11 while angle H is equal to 39 degrees.

A complementary angle can be defined as two (2) angles or arc whose sum is equal to 90 degrees (90°).

Mathematically, a complementary angle can be calculated by using this formula:

Q + R = 90°

Where:

Q and R are measure of the angles subtended.

Substituting the given parameters into the formula, we have;

(6x - 15)° + (3x + 6)° = 90°

9x - 9 = 90°

9x = 90 + 9

9x = 99

x = 99/9

x = 11

Next, we would determine the value of H:

H = 3x + 6

H = 3(11) + 6

H = 33 + 6

H = 39 degrees.

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Complete Question:

Angle G and angle H are complementary angles.  If G= (6x-15)° and H= (3x+6)° find the x value and H

The probability that both marbles are red is 9/23.

To find the probability of both marbles being red, follow these steps:

1. Calculate the total number of marbles in the jar: 19 red + 25 blue = 44 marbles.

2. Determine the probability of picking a red marble on the first draw: 19 red marbles / 44 total marbles = 19/44.

3. After picking one red marble, there are 18 red marbles and 43 total marbles left. Calculate the probability of picking a red marble on the second draw: 18 red marbles / 43 total marbles = 18/43.

4. Multiply the probabilities from steps 2 and 3 to find the overall probability: (19/44) x (18/43) = 342/1892.
5. Simplify the fraction: 342/1892 = 9/23.

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The problem can be solved using the simplex method, and the solution can be verified using the graphical method. The optimal solution is X1 = 6, X2 = 0, X3 = 6, Z = 24.

The problem can be solved using the simplex method, and verified using the graphical method. Here are the steps:

Convert the problem to standard form by introducing slack variables:
Min Z = -2X1 - 4X2 - 3X3 + 0S1 + 0S2 + 0S3
St. X1 + 3X2 + 2X3 + S1 = 30
X1 + X2 + X3 + S2 = 24
3X1 + 5X2 + 3X3 + S3 = 60
Xi, Si >= 0

Set up the initial simplex tableau:
| 1 3 2 1 0 0 30 |
| 1 1 1 0 1 0 24 |
| 3 5 3 0 0 1 60 |
| 2 4 3 0 0 0 0 |

Identify the entering variable (most negative coefficient in the objective row): X2

Identify the leaving variable (smallest ratio of RHS to coefficient of entering variable): S1

Pivot around the intersection of the entering and leaving variables to create a new tableau:
| 0 2 1 1 -1 0 6 |
| 1 0 0 -1 2 0 18 |
| 0 0 0 5 -5 1 30 |
| 2 0 1 -2 4 0 36 |

Repeat steps 3-5 until there are no more negative coefficients in the objective row. The final tableau is:
| 0 0 0 7/5 -3/5 0 18 |
| 1 0 0 -1/5 2/5 0 6 |
| 0 0 1 1/5 -1/5 0 6 |
| 0 0 0 -2 4 0 24 |

The optimal solution is X1 = 6, X2 = 0, X3 = 6, Z = 24.

To verify the solution using the graphical method, plot the constraints on a graph and find the feasible region. The optimal solution will be at one of the corner points of the feasible region. By checking the values of the objective function at each corner point, we can verify that the optimal solution found using the simplex method is correct.

In conclusion, the problem can be solved using the simplex method, and the solution can be verified using the graphical method. The optimal solution is X1 = 6, X2 = 0, X3 = 6, Z = 24.

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The COGS of Alpha ore mined and processed by ADP Mining Company is $750,500.ADP Mining Company is an organization that specializes in mining iron ore called Alpha.

During the month of August, 416,000 tons of Alpha were mined and processed at a cost of $750,500. ADP Mining Company extracts the ore and then processes it to generate a finished product that can be sold. ADP Mining Company must maintain a high level of production efficiency to make a profit while keeping the cost of production to a minimum. Alpha ore is processed as it is mined. The processing cost is included in the overall cost of the Alpha ore.The cost of production, also known as the cost of goods sold (COGS), is calculated by summing all of the direct and indirect expenses associated with the production of the finished product. It comprises costs such as raw material costs, wages and salaries, rent, electricity, depreciation, and other indirect expenses.

Direct expenses, such as the cost of processing Alpha ore, are included in COGS since they are incurred while producing the finished product.COFG calculation:

COGS = Raw Material Cost + Direct Labor Cost + Direct Expenses + Other Indirect Expenses

COGS = $750,500 (direct expenses)

The COGS of Alpha ore mined and processed by ADP Mining Company is $750,500.

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To display the terms in the Fibonacci sequence, starting with Fib(0) and continuing as long as the terms are less than 10,000, a program is written with a loop construct. This loop is implemented using a `while` loop with a header line that looks like this: `while term < 10000:`.

Fibonacci sequence is named after the Italian mathematician Leonardo Fibonacci who developed a mathematical sequence in the 13th century to explain the geometric growth of a population of rabbits.

The first two terms in this sequence, Fib(0) and Fib(1), are 0 and 1, and every subsequent term is the sum of the preceding two.

The first several terms in the Fibonacci sequence are:

Fib(0) = 0, Fib(1) = 1, Fib(2) = 1, Fib(3) = 2, Fib(4)= 3, Fib(5)=5.

This program continues as long as the value of the term is less than the maximum

The output is as follows:

```1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181 6765```

The while loop could also be used to achieve the same goal.

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If you are considering speed regardless of direction, the average speed is:

(24 + 16) / 2 = 40 / 2 = 20mph

Although if direction matters, then one number has to be negative since the directions are opposite:

(24 - 16) / 2 = 8 / 2 = 4mph (in the positive direction)

Answer:

0,-3

Step-by-step explanation:

because its across it so it probbly dose not cam o it dose poloyn it

Answer:

Answer is B

Step-by-step explanation:

The the equation of a line that passes through the point (2, −10) and is parallel to 14x+2y=6 is 7x + y + 8 = 0.

A straight line is just a line with no curves. So, a line that extends to both sides till infinity and has no curves is called a straight line.

The equation of a line parallel to a given line will have the same slope as the given.

The equation of a line having a slope m and passing through the point (x', y') is written as

y - y' = m (x - x').

This is called point - slope equation of a straight line.

In the given equation,

14x+2y=6

⇒ 2y = -14x + 6

⇒ y = -7x + 3

Comparing it with standard equation of a straight line; y = m x + c, the slope m of the given line = -7

Therefore equation of the line parallel to the given line and passing through point (x', y') = (2, -10) would be:

y - (-10) = -7x + 2

⇒ y + 10 = -7x + 2

⇒ 7x + y + 8 = 0

Hence the required equation of line 7x + y + 8 = 0

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Answer:

1.Equivalent

2.Equaivalent

3.Not Equivalent

4.Equivalent

In polar coordinates, the equation for (a) is r = 10sinθ, the equation for (b) is r = √10, the equation for (c) is r = 6cosθ, and the equation for (d) is r = 10sinθ / (cos^2θ - sin^2θ).

In polar coordinates, a point (r, θ) represents the distance r from the origin and the angle θ measured counterclockwise from the positive x-axis. To express each equation in polar coordinates, we can substitute x = rcosθ and y = rsinθ, then simplify using trigonometric identities and algebraic manipulations.

(a) y = 10

Substituting y = rsinθ, we get rsinθ = 10, or r = 10sinθ.

(b) x^2 + y^2 = 10

Substituting x = rcosθ and y = rsinθ, we get r^2 = 10, or r = √10.

(c) x^2 + y^2 - 6x = 0

Substituting x = rcosθ and y = rsinθ, we get r^2 - 6rcosθ = 0, or r = 6cosθ.

(d) x^2(x^2 + y) = 10y^2

Substituting x = rcosθ and y = rsinθ, we get r^2cos^2θ(r^2cos^2θ + rsinθ) = 10r^2sin^2θ, or r = 10sinθ / (cos^2θ - sin^2θ).

Therefore, in polar coordinates, the equation for (a) is r = 10sinθ, the equation for (b) is r = √10, the equation for (c) is r = 6cosθ, and the equation for (d) is r = 10sinθ / (cos^2θ - sin^2θ).

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Using the order of operations, the expression can be simplified as  

9 + 1.34 + 62.88 = 73.22

The order of operations instructs us on how to solve steps in multi-step expressions. Any operations contained within parenthesis or brackets are first solved. After that, we handle any exponents. Third, we perform all division and multiplication operations from left to right. Fourth, all addition and subtraction problems are solved from left to right.

Remember PEMDAS when simplifying multi-step expressions, i.e.:

P (Parentheses)

E (Exponents, Powers and Square Roots)

MD (Multiplication and Division, left-to-right)

AS (Addition and Subtraction, left-to-right)

The expression given in the problem is:  9 + 1.34 + 1 2 (3.50 +1.74)

Apply the above operation order:

Step 1: solve the addition inside the parenthesis

9 + 1.34 + 1 2 (3.50 +1.74)  =  9 + 1.34 + 1 2 (5.24)

Step 2: Multiply the result by 12

9 + 1.34 + 1 2 (5.24) = 9 + 1.34 + 62.88

Step 3: Apply addition from left to right

9 + 1.34 + 62.88 = 73.22

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The expected value of the number of people selected before and including the first time a woman has a turn is 1.6667 and the standard error is 0.7454.

It should be noted that the expected value will be:

1[p(x = 1)] + 2[p(x = 2)] + 3[p(x = 3)]

= 1(0.5) + 2(0.3333) + 3(0.1667)

= 1.6667

Var(X) = E(X²) - E(X)2

= 3.3335 & (1.6667)²

= 0.555611

The standard error will be:

= ✓0.555611

= 0.7454

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Answer: 200 Students

Step-by-step explanation:

Answer:

ChatGPT

To find the balances for each type of investment after one year, we can use the formula for compound interest:

Treasury bond: A = P(1 + r/n)^(nt)

A = 0.4(30000)(1 + 0.0535/1)^(1*1) = $12,912.00

CD: A = P(1 + r/n)^(nt)

A = 0.1(30000)(1 + 0.0475/1)^(1*1) = $10,316.25

Stock plan: After the first year, 30% is still in the savings account. The other 70% is in the stock plan, which increased by 9%, so the new value is:

0.7(30000)(1 + 0.09) = $23,940.00

Savings account: A = P(1 + r/n)^(nt)

A = 0.2(30000)(1 + 0.039/1)^(1*1) = $6,351.00

To find the total gain from all of the investments combined, we need to add up the gains from each investment:

Treasury bond: $12,912.00 - $12,000.00 = $912.00 gain

CD: $10,316.25 - $9,000.00 = $1,316.25 gain

Stock plan: After the second year, the stock plan decreased in value by 5%, so the new value is:

0.7($23,940.00)(1 - 0.05) = $19,149.00

After the third year, the stock plan increased by 7%, so the final value is:

0.7($19,149.00)(1 + 0.07) = $20,129.57

The gain from the stock plan is:

$20,129.57 - $21,000.00 = -$870.43 loss (since the stock plan decreased in value overall)

Savings account: $6,351.00 - $6,000.00 = $351.00 gain

Total gain = $912.00 + $1,316.25 - $870.43 + $351.00 = $708.82

If you had invested 40% in stock and 30% in Treasury bonds, the calculations would be:

Treasury bond: A = P(1 + r/n)^(nt)

A = 0.3(30000)(1 + 0.0535/1)^(1*3) = $12,853.81

Stock plan: After the first year, 40% is still in the savings account. The other 60% is in the stock plan, which increased by 9%, so the new value is:

0.6(30000)(1 + 0.09) = $16,200.00

After the second year, the stock plan decreased in value by 5%, so the new value is:

0.6($16,200.00)(1 - 0.05) = $15,390.00

After the third year, the stock plan increased by 7%, so the final value is:

0.6($15,390.00)(1 + 0.07) = $16,019.16

Total gain = ($12,853.81 - $12,000.00) + (-$981.84) + ($1,019.16) = $890.13

Therefore, investing 40% in stock and 30% in Treasury bonds

Answer:

  12 meters

Step-by-step explanation:

The assumption regarding shadow lengths is that they are proportional to height at any given place and time.

__

Here, the streetlamp is 9/6 = 3/2 times as tall as the tree, so we expect its shadow to be 3/2 times the length of the tree's shadow.

  (3/2)(8 m) = 12 m

The streetlamp's shadow is 12 meters long.

Answer:

Value for X = 7

Explanation:

Given:

FE parallel to BC

Find:

Value for X

Computation:

EA / CE = FA / BF

So,

18 / 10 = (X+20) / (X+8)

18X + 144 = 10X + 200

8X = 56

X = 56/8

X = 7

Value for X = 7

Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

To find the Taylor polynomials centered at x = 0 for the function f(x) = 16tan(x), we can use the Taylor series expansion for the tangent function and truncate it to the desired degree.

The Taylor series expansion for tangent function is:

tan(x) = x + (1/3)x^3 + (2/15)x^5 + (17/315)x^7 + ...

Using this expansion, we can find the Taylor polynomials of degree 2 and 3 centered at x = 0:

Degree 2 Taylor polynomial:

P2(x) = f(0) + f'(0)(x - 0) + (1/2!)f''(0)(x - 0)^2

= 16tan(0) + 16sec^2(0)(x - 0) + (1/2!)16sec^2(0)(x - 0)^2

= 0 + 16x + 8x^2

Degree 3 Taylor polynomial:

P3(x) = P2(x) + (1/3!)f'''(0)(x - 0)^3

= 0 + 16x + 8x^2 + (1/3!)(48sec^2(0)tan(0))(x - 0)^3

= 16x + 8x^2

Therefore, the Taylor polynomials of degree 2 and 3 centered at x = 0 for the function f(x) = 16tan(x) are:

P2(x) = 16x + 8x^2

P3(x) = 16x + 8x^2

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Glen has knitted 11 centimeter after 4 days  and 14 centimeter after 6 days a carf.

First Glen is knitting a carf, He has already done 5 centimeter so ,

first day he will knit1.5 so the length of the carf of first day will be 5+1.5=6.5 centimeter.

second day he will knit 1.5 again so the length of the carf of first day will be 6.5+1.5=8 centimeter.

third day,  o the length of the carf of first day will be  8+1.5=9.5 centimeter.

the fourth day he will knit 1.5 so the length of the carf of fourth day will be 9.5+1.5=11 centimeter.

Fifth day the length of the carf of fifth day will be 11+1.5=12.5 centimeter.

Thus, the sixth day , the length of the carf of sixth day will be 12.5+1.5=14 centimeter.

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The equation of the tangent line to f(x)=ln(x) at x=2 is given by y = 1/2x - ln(2).

To find the formula for the tangent line to f(x)=ln(x) at x=2, we first need to take the derivative of the function:

f'(x) = 1/x

At x=2, the derivative is:

f'(2) = 1/2

The equation of the tangent line at x=2 is given by:

y - f(2) = f'(2)(x - 2)

Substituting the values of f(2) and f'(2) gives:

y - ln(2) = 1/2(x - 2)

Simplifying this equation gives us the equation of the tangent line:

y = 1/2x - ln(2) + ln(2)

Therefore, the equation of the tangent line to f(x)=ln(x) at x=2 is given by y = 1/2x - ln(2).

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The distance the cyclist traveled into the country, given that he rides into the country at an average speed of 10 miles per hour is 15 miles

Let the total distance traveled into the country be y.

Now, we shall determine the riding time. Details below:

Riding time = Distance / speed

Riding time = y / 10

Next, we shall obtain the walking time of the cyclist. This is shown below:

Walking time = Distance / speed

Riding time = y / 3

Finally, we shall obtain the total distance traveled. This is illustrated below:

Total time = riding time + walking time

6.5 = y/10 + y/3

6.5 = (3y + 10y) / 30

6.5 = 13y / 30

Cross multiply

13y = 6.5 × 30

13y = 195

Divide both sides by 13

y = 195 / 13

y = 15 miles

Thus, the total distance traveled by the cyclist into the country is 15 miles.

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Answer:

x=2645/5832 hope that helped

Step-by-step explanation:

Answer:

Total number of chips Caleb have = 8

Total number of chips Suzanne have = 30

Step-by-step explanation:

In Caleb case -

Three out of every four chips is blue

⇒ If Caleb has total chips = 4

Then Blue chips = 3

⇒White chips = 4 - 3 = 1

Now,

If Caleb have 6 blue chips

⇒3 Blue chips = 4 total chips

  1 Blue chip = \(\frac{4}{3}\) total chips

⇒6 blue chips = \(\frac{4}{3}\) ×6 = 4×2 = 8 total chips

∴ we get

Number of chips become = 8

In Suzanne case -

One out of every five chips are blue.

⇒ If Suzanne has total chips = 5

Then Blue chips = 1

⇒White chips = 5 - 1 = 4

Now,

If Suzanne have 6 blue chips

⇒1 Blue chips = 5 total chips

⇒6 blue chips = 5×6 = 30 total chips

∴ we get

Number of chips become = 30

The bearing between Point A (N 1147.8000 E 710.4700) and Point B (N 1489.1700 E 138.5700) is computed as ON 30°49'59"W.

To compute the bearing between Point A and Point B, we need to determine the directions from Point A to Point B. The coordinates for Point A are N 1147.8000 E 710.4700, while the coordinates for Point B are N 1489.1700 E 138.5700. The bearing is given as ON 30°49'59"W, which means the direction from Point A to Point B is approximately 30 degrees, 49 minutes, and 59 seconds west of north. This indicates the angle between the north direction and the line connecting Point A and Point B.

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Answer:

Option (A)

Step-by-step explanation:

Let the Sine of the given angle θ is,

Sinθ = \(\frac{x}{y}\)

Then θ = \(\text{Sin}^{-1}(\frac{x}{y} )\)

From the given values in the question,

Sinθ = \(\frac{7}{29}\)

θ = \(\text{Sin}^{-1}(\frac{7}{29} )\)

θ = 13.97°

Therefore, measure of the angle 'θ' will be 13.97°.

Option (A) will be the answer.

Answer:

70.95$

Step-by-step explanation:

P = $1000

R = 2.365%

T = 3 years

\(\frac{PRT}{100}\) = \(\frac{1000*2.365 * 3}{100}\) = \(\frac{7095}{100}\) = 70.95$