Which is a characteristic of atoms?

They come in ten major types.
They are the smallest units of matter.
They can be divided.
They cannot combine together.

Answers

Answer 1
Atoms consist of three basic particles ptotons electrons and neutrons.
Answer 2

Answer:

the answer is b

Explanation:


Related Questions

A particle starts with velocity v1 and moves with acceleration dv / d * t = cv in a straight line. whatis the distance travelled when it reaches velocity upsilon_{2} ?

Answers

The distance traveled is equal to the difference between the final velocity upsilon_{2} and the initial velocity v1.

The distance traveled by the particle when it reaches velocity upsilon_{2} can be determined by integrating the acceleration with respect to time.

Given that dv / dt = cv, we can rewrite this as dv = cv dt.

Integrating both sides, we have ∫dv = ∫cv dt.

The left side of the equation becomes v - v1, since v1 is the initial velocity of the particle.

On the right side, we integrate cv dt with respect to t. The integral of cv is (c/2)t^2.

Thus, the equation becomes v - v1 = (c/2)t^2.

Now, we can solve for the time t when the velocity of the particle reaches upsilon_{2}.

Substituting upsilon_{2} for v and rearranging the equation, we have t = sqrt((2(upsilon_{2} - v1))/c).

Once we have the value of t, we can substitute it back into the equation v - v1 = (c/2)t^2 to calculate the distance traveled.

Therefore, the distance traveled by the particle when it reaches velocity upsilon_{2} is given by (c/2)(sqrt((2(upsilon_{2} - v1))/c))^2.

This simplifies to c(upsilon_{2} - v1)/c = upsilon_{2} - v1.

So, the distance traveled is equal to the difference between the final velocity upsilon_{2} and the initial velocity v1.

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Technician A says that a low-restriction exhaust system could prevent a back pressure-type vacuum-controlled EGR valve from opening correctly. Technician B says restricted exhaust can cause the EGR valve position sensor to fail. Which technician is correct

Answers

Answer:

Both technicians are correct.

Explanation:

Exhaust gas recirculation (EGR) contributes to limit the production of polluted gas mixture during internal engine combustion via an EGR valve. With the help of Exhaust gas recirculation (EGR), nitrogen oxides production is reduced drastically especially when the engine runs on diesel. Black smoke, engines making knocking sounds could be a clear indication of a bad EGR valve especially when the valve passage is blocked due to carbon deposits, or dirt from fuel blocking the valve opening thereby decreasing the power output, or in the case of the knock sounds, the fuel gets ignited early when the machine's operation at a given time is low. So, the Technicians are correct with the statements they made.

   

Atmospheric molecules do not fly off into outer space due toA) their chaotic speeds.B) their relatively low densities.C) Earth gravitation.D) cohesive forces.

Answers

Atmospheric molecules do not fly off into outer space due to **Earth's gravitation** and **cohesive forces**.

A) Chaotic speeds: Atmospheric molecules have varying speeds and directions due to their thermal energy, resulting in a chaotic motion. However, this alone does not prevent them from escaping into space.

B) Low densities: While atmospheric gases have relatively low densities compared to solid or liquid substances, it is not solely the low density that prevents them from escaping. Even gases with low densities can escape if not held by other forces.

C) Earth gravitation: Earth's gravitational force acts as a significant factor in keeping atmospheric molecules from flying off into space. Gravity pulls the molecules towards the Earth, providing the necessary centripetal force to maintain their presence in the atmosphere.

D) Cohesive forces: Cohesive forces, such as intermolecular attractions and Van der Waals forces, play a role in holding atmospheric molecules together. These forces help maintain the integrity of the atmosphere and prevent individual molecules from breaking free and escaping into space.

The combined effect of Earth's gravity and cohesive forces acts as a barrier, keeping atmospheric molecules bound to the planet and preventing their escape into outer space.

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What are some some examples of estimator variables (forensics)

Answers

Answer:

Estimator variables are those that cannot be controlled by the criminal justice system. They include simple factors like the lighting when the crime took place or the distance from which the witness saw the perpetrator.

Explanation:

I walked my dog 100 meters North to the end of the block, and 50 meters East to the park. After the park, I walked 60 meters South to my friend's house. What is the total distance traveled? Is the displacement of my journey scalar or vector?

Answers

Answer:

The answer is below

Explanation:

Distance is a measurement of how far apart two points are. Distance is a scalar quantity, i.e. it has magnitude and no direction.

Total distance traveled = distance traveled north + distance traveled east + distance traveled south

Total distance traveled = 100 + 50 + 60 = 210 meters

Displacement is the shortest distance between the starting and end points.

displacement² = 50² + (100 - 60)²

displacement² = 2500 + 1600

displacement = 64 meters

The displacement of the journey is vector, because displacement is a vector quantity.

which component acts a platform on which an application software runs.​

Answers

Answer:

System software acts as a platform on which an application software program runs.

A cold air mass moves in and overtakes a warm front in the presence of a low-pressure system. Which weather is least likely to occur with these conditions?
A. thunderstorms

B. cloudy skies

C. hailstorms

D. Clear skies

Answers

The weather that is least likely to occur when a cold air mass moves in and overtakes a warm front in the presence of a low-pressure system is clear skies ( D ).

When a cold air mass moves in and overtakes a warm front in the presence of a low-pressure system, it is called as occluded front. During this the colder air is pushed beneath the warmer air. Depending on the direction of occlusion, it can be of two types of of occluded fronts such as

Cold occluded frontWarm occluded front

During occluded fronts the possible weather conditions are

ThunderstormsHailstormsTornadoesCloudy skies

Therefore, the weather that is least likely to occur with these conditions is clear skies ( D ).

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Learning Goal: To derive the formulas for the major characteristics of motion as functions of time for a horizontal spring oscillator and to practice using the obtained formulas by answering some basic questions.
A block of massmis attached to a spring whose spring constant isk. The other end of the spring is fixed so that when the spring is unstretched, the mass is located atx=0. . Assume that the +xdirection is to the right.
The mass is now pulled to the right a distanceAbeyond the equilibrium position and released, at timet=0, with zero initial velocity.
Assume that the vertical forces acting on the block balance each other and that the tension of the spring is, in effect, the only force affecting the motion of the block. Therefore, the system will undergo simple harmonic motion. For such a system, the equation of motion is
a(t)=-\frac{k}{m}x(t),
and its solution, which provides the equation forx(t), is

Answers

In this scenario, we have a horizontal spring oscillator with a block of mass m attached to a spring of spring constant k.

The block is pulled to the right a distance A and released at time t=0 with zero initial velocity. Since the vertical forces balance each other, we can assume that the only force affecting the motion of the block is the tension of the spring, resulting in simple harmonic motion.
The equation of motion for this system is given by a(t)=-\frac{k}{m}x(t), where a(t) is the acceleration of the block at time t, x(t) is the displacement of the block from its equilibrium position at time t, and m is the mass of the block.
The solution to this equation provides the equation for x(t), which is x(t)=A\cos(\omega t), where ω=\sqrt{\frac{k}{m}} is the angular frequency of the oscillator.
From this equation, we can derive the formulas for the major characteristics of motion as functions of time. The velocity of the block at time t is given by v(t)=-A\omega\sin(\omega t), while the acceleration of the block at time t is given by a(t)=-A\omega^2\cos(\omega t).
In summary, for a horizontal spring oscillator with a block of mass m attached to a spring of spring constant k, the equations for the major characteristics of motion as functions of time are

x(t)=A\cos(\omega t),

v(t)=-A\omega\sin(\omega t), and

a(t)=-A\omega^2\cos(\omega t),

where ω=\sqrt{\frac{k}{m}} is the angular frequency of the oscillator.
x(t) = A * cos(ω * t),
where:
- x(t) is the position of the mass at time t,
- A is the amplitude, which is the maximum displacement from the equilibrium position,
- ω is the angular frequency, and
- t is the time elapsed.
Now let's derive the formulas for other characteristics of motion, including velocity and acceleration, as functions of time.
1. Velocity (v):
To find the velocity as a function of time, we need to differentiate x(t) with respect to t: v(t) = dx(t)/dt = -A * ω * sin(ω * t),
where v(t) is the velocity of the mass at time t.
2. Acceleration (a):
To find the acceleration as a function of time, we need to differentiate v(t) with respect to t:

\(a(t) = dv(t)/dt = -A * \omega^2 * cos(\omega * t),\)
Since a(t) = - (k/m) * x(t), we can relate the angular frequency ω to the spring constant k and mass m: \(\omega^2 = k/m\).

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this planet has a very toxic atmosphere that traps heat, making it the hottest planet in the solar system.

Answers

Answer:

Venus

Explanation:

basic 2nd grade smarts "no offense"

While on the surface of the earth a student has a weight of 450n if she is moved twice as far from the center of the earth then how does the new weight compare to her old?

Answers

Based on the fact that the student is moved twice as far from the center of the earth, her new weight will be 112.5 N.

What is her new weight?

When the student was moved by the same distance from the center of the earth, her weight was halved.

When she was then moved twice as far, her weight was halved again.

This means that her new weight is:

= 450 x 1/2 x 1/2

= 450 x 1/4

= 112.5 N.

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Derive an Expression for elastic potential energy of a spring

Answers

Answer:

spring force = -K × x , where X is elongation or compression in the spring. ( -) sigh shows that the spring force is opposite to the applied force to cause extension.

Potential energy = work done by spring force = integration of Force.

integrate the force (-K × x) over distance 0 to x .

U = 1/2 K × X^2 ( for elongation)

U = -1/2 × K × X^2 ( for compression)

Stored energy and the energy of position is the definition?

Answers

Answer:

Potential energy is energy that is stored-or conserved-in an object or substance. This stored energy is based on the position, arrangement or state of the object or substance

cells in the eye detect light
and dark. What word completes the
sentence?
Enter your answer

Answers

"Rod cells in the eye detect light and dark." completes the sentence.

What is light?

Light is defined as electromagnetic radiation visible to the human eye with wavelengths ranging from 380 to 750 nm. Light is a type of electromagnetic radiation that enables or makes objects visible to the human eye. It's also known as visible radiation to the eye. Light contains photons, which are tiny packets of energy. Lux (lx) (lx) The unit of illumination is the lux, which is equal to one lumen per square metre. The metric equivalent of footcandles is one lux equals 0.0929 footcandles.

Here,

"In the eye, rod cells detect light and dark." completes the sentence.

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write a beta decay equation for the
transmutation of a radioactive isotope of Rutherfordium, which has 104 protons
and 183 neutrons.
PLS HELP ASAP!!!!

Answers

The beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has been explained above will be,\(\rm Re_{104}^{287} + \beta_0^{-1} \rightarrow Re_{104}^{286}\)  

What is the rate of decay?

The reduction in the number of radionuclides per unit time is the rate of decay.

The beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has 104 protons and 183 neutrons.

Atomic weight = 104+183 = 287

Atomic number  = 104

The beta decay equation is;

\(\rm Re_{104}^{287} + \beta_0^{-1} \rightarrow Re_{104}^{286}\)

Hence the beta decay equation for the transmutation of a radioactive isotope of Rutherfordium has been explained above.

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Does the law of inertia pertain to moving objects, objects at rest, or both? Support your answer with example

Answers

The law of inertia pertains to both objects at rest and objects travelling in uniform motion (constant rate of motion so acceleration = 0).

ie of an object at rest: A person pushes a building with as much force as possible. The building is at rest and doesn’t move due to its inertia.

ie of an object travelling in uniform motion: An apple is thrown out of a car window. The apple bounces and moves on the ground after it is thrown out the window because of its inertia.

Hope this helps! :)

A half-wave rectifier is needed to supply 15-V de to a load that draws an average current of 250 mA. The peak-to-peak rip- ple is required to be 0.2 V or less. What is the minimum value allowed for the smooth- ing capacitance? If a full-wave rectifier is needed?

Answers

C_min = (I_avg * T) / V_ripple. If a full-wave rectifier is needed, the ripple voltage is typically reduced by half compared to a half-wave rectifier. Therefore, the same calculation can be used to determine the minimum smoothing capacitance for the full-wave rectifier.

but with a ripple voltage of half the value used in the half-wave rectifier calculation.Where C_min is the minimum required capacitance, I_avg is the average current, T is the time period of the waveform (in seconds), and V_ripple is the desired peak-to-peak ripple voltage.

In this case, I_avg = 250 mA (or 0.25 A) and V_ripple = 0.2 V. The time period T can be calculated as the reciprocal of the frequency of the AC input signal.

Once you have the time period T, you can substitute the values into the formula to determine the minimum required smoothing capacitance C_min.

Remember to convert all units to be consistent (e.g., A to mA and F to μF) when performing the calculation.

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The equation to calculate density is D = m/v. For a liquid substance, which item increases as heat is applied?

volume
density
mass
density and volume

Answers

Answer:

See below

Explanation:

Things generally expand when heated ....so volume increases while mass remains the same .....this will cause the value of density to decrease  

All of the following choices are examples of commonly used assessment methods for body
composition EXCEPT

A. waist to hip ratio
B. bioelectrical impedance analysis
C. the spongy bob technique
D. skinfold measurements this is PE please help mee

All of the following choices are examples of commonly used assessment methods for bodycomposition EXCEPTA.

Answers

Answer:

letter D

Explanation:

sana po makatulong po sa inyo

Two protons (each with rest mass M = 1. 67 × 10-27 kg) are initially moving with equal speeds in opposite directions. The protons continue to exist after a collision that also produces an ? particle. The rest mass of the ??ís m 9. 75 10-28 kg. (a) If the two protons and the ?? are all at rest after the collision, find the initial speed of the protons, expressed as a fraction of the speed of light. (b) What is the kinetic energy of each proton? Express your answer in MeV. (c) What is the rest energy of the n", expressed in MeV? (d) Discuss the relationship between the answers to parts (b) and (c)

Answers

The initial speed of the protons is approximately 0.166 times the speed of light.  the kinetic energy of each proton is 2.10 MeV.the rest energy of the  particle is approximately 18.3 MeV. we can see that the kinetic energy of the protons and the rest energy of the  particle are related through the conservation of energy in the collision process.

(a) Let the initial speed of each proton be v. According to conservation of momentum, the total momentum of the system before the collision is zero (since the protons are moving in opposite directions with the same speed). After the collision, the total momentum is also zero since the particles are all at rest. Therefore, we can write:

2mv = (m + 2m)v

where m is the rest mass of each proton and v is the speed of the particle. Solving for v, we get:

v = (m/3m)c

where c is the speed of light.

Substituting the given values, we get:

v = (9.75 × 10\(^-28\) / (3 × 1.67 × 10\(^-27\))) × 3.00 × \(10^8\) m/s ≈ 0.166c

Therefore, the initial speed of the protons is approximately 0.166 times the speed of light.

(b) The kinetic energy of each proton can be found using the formula:

K.E. = (1/2)m\(v^2\)

Substituting the values of m and v from part (a), we get:

K.E. = (1/2) × 1.67 ×\(10^-27\) × (0.166c\()^2\) = 2.10 MeV

Therefore, the kinetic energy of each proton is 2.10 MeV.

(c) The rest energy of the particle can be found using the formula:

E = \(mc^2\)

Substituting the given value of m, we get:

E = 9.75 × \(10^-28\) × (3.00 × \(10^8)^2\)/ (1.60 × \(10^-13\)) ≈ 18.3 MeV

Therefore, the rest energy of the day particle is approximately 18.3 MeV.

(d) The sum of the kinetic energies of the two protons is equal to the difference between the total energy (rest energy + kinetic energy) of the protons before the collision and the total energy of the particles after the collision. Mathematically, we can write:

2K.E. = (2m)\(c^2\) - (m + 2m)\(c^2\)

Substituting the given values, we get:

2K.E. = (2 × 1.67 ×\(10^-27\))\(c^2\) - (2 × 9.75 × \(10^-28\))\(c^2\) ≈ 4.20 MeV

On the other hand, the rest energy of the particle is equal to the difference between the total energy of the system after the collision and the kinetic energy of the protons after the collision. Mathematically, we can write:

E = (m + 2m)\(c^2\)- 2K.E.

Substituting the given values, we get:

E = (2 × 9.75 × \(10^-28\))\(c^2\) - 2(2.10 MeV) ≈ 14.1 MeV

Therefore, we can see that the kinetic energy of the protons and the rest energy of the  particle are related through the conservation of energy in the collision process.

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A force of 1.0 x 104 n is exerted on a 50 g bullet throughout the 10 cm length of a gun barrel. how much work was done on the bullet? how much ke did the bullet have when it left the gun barrel? what was the speed of the bullet when it left the gun barrel?

Answers

The kinetic energy of the bullet when it left the gun barrel is 1000J.

We know that ,

K.E. = F d

where, K.E. = kinetic energy

F = force

d = distance

Given, F = 1* 10^4 N

          d = 10cm = 0.1 m

Putting these values in above equation we get,

K.E. = 1000J

So the kinetic energy of the bullet when it left the gun barrel is 1000J.

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The back side of a polished spoon
has f = -6.50 cm (convex). If you
hold your nose 5.00 cm from it
what is its magnification?
(Mind your minus signs.)


(this question is on acellus pls help )

Answers

The back side of a polished spoon has f = -6.50 cm (convex). If you

hold your nose 5.00 cm from it then the  magnification of the image is

0.864.

The formula for calculating magnification in such a case is: Magnification = -di/do

Here, f = -6.50 cm is the focal length of the mirror, and the object is the back side of a polished spoon.

The distance between the object and the mirror, in this case, is the distance between your nose and the spoon, which is 5.00 cm.

Thus, the distance of the image from the mirror is:di = -f/(1/do - 1/f)

Putting the values in the formula, we get:di = -6.50/(1/5 - 1/-6.50) = -4.32 cm (negative sign indicates that the image is virtual)

Using the magnification formula, we have: Magnification = -di/do = -(-4.32)/5.00 = 0.864

Thus, the magnification of the image is 0.864.

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What happens to the period of a wave as the frequency increases?.

Answers

Explanation:

T=1/f

So if frequency increases the period will decrease

You have a 2.0 Ω resistor, a 3.0 Ω resistor, a 6.0 Ω resistor, and a 6.0 V battery. Arrange all three resistors on a diagram to make a circuit in which the battery delivers 9.0 W of power.
can you please draw it?

Answers

To achieve 9.0 W of power from a 6.0 V battery, arrange the 2.0 Ω and 3.0 Ω resistors in parallel, and the 6.0 Ω resistor in series.

In this circuit configuration, the effective resistance (Req) for the parallel resistors (2.0 Ω and 3.0 Ω) can be calculated using the formula: 1/Req = 1/R1 + 1/R2. Thus, 1/Req = 1/2.0 + 1/3.0, giving Req = 1.2 Ω. Now, we connect the 6.0 Ω resistor in series, which results in a total resistance (Rt) of 7.2 Ω (1.2 Ω + 6.0 Ω). To calculate the power delivered by the battery, we use the formula P = V^2/Rt, where P is power, V is voltage, and Rt is total resistance. Substituting the values, P = 6.0^2/7.2, which gives P = 9.0 W, as required. This circuit ensures the battery delivers the desired power.

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7. What force is required to accelerate a 100 kg car to 4 m/s27 F=ma
O A. 25N
B. 104N
C. 400N

Answers

Answer:

is the formula is F=MA so

F=100kg×4m/s=400n

so the answer is 400n

What is the period of the microwaves with a frequency of 30,000,000,000 Hz?

a.cannot be calculated
b.0
c.a really big number
d.a really small number

Answers

Answer:

The period of a wave is the time it takes for one complete cycle of the wave to occur. It is given by the formula:

Period = 1 / Frequency

where frequency is the number of cycles per second.

Using this formula, we can calculate the period of the microwaves with a frequency of 30,000,000,000 Hz as:

Period = 1 / 30,000,000,000 Hz

Period = 3.33 x 10^-11 seconds

Therefore, the period of the microwaves with a frequency of 30,000,000,000 Hz is a really small number, which is approximately 3.33 x 10^-11 seconds. The answer is (d) a really small number.

Explanation:

rotational motion is defined similarly to linear motion. what is the definition of rotational velocity?

Answers

Rotational velocity is the rate at which an object rotates, expressed in radians per second or revolutions per minute.

Rotational motion refers to the movement of an object around a fixed point, such as an axis. Rotational velocity is defined as the speed at which an object rotates around its axis. It is calculated by dividing the angular displacement by the time it takes to complete that rotation.

Rotational velocity is expressed in radians per second (rad/s) or revolutions per minute (RPM). The direction of rotational velocity is determined by the direction of rotation, with counterclockwise rotation having positive velocity and clockwise rotation having negative velocity.

Rotational velocity is a crucial concept in understanding the behavior of rotating systems, such as engines, turbines, and wheels. It helps to determine the amount of torque required to achieve a certain rotation speed, and it also plays a role in determining the angular momentum and energy of the system.

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Need help this is a grade

Need help this is a grade

Answers

Answer: C

Explanation: When you have a tomato for example, it absorbs every color but red and therefore, appears red.

Penetration capabilities in...
- Radio Waves
- Microwaves
- Infrared
- Visible light
- Ultraviolet
- X-rays
- Gamma rays

Answers

Ultra = X-ray

Explanation:

how are things going to paint the roof for beginners painting and decorating the whole house so I'm going away with a few sports mates for a couple nights for beginners but will have a look painting at a time and see what is going to be Strong enough

i need the answer to this one

i need the answer to this one

Answers

Answer: The answer is 120 Newton.

60X2=120N
So the answer is 120Newton

A pedestrian tries to cross the street while texting and gets hit by a bicycle with object experiences a greater force the bicycle or the pedestrian

Answers

The bicycle will experience more force.

Force is the intensity by which an object is pushed or pulled.

Also it is the product of mass and acceleration.Mathematically, F = m * a.

Let the mass of the pedestrian = M kg

Let the mass of bicycle = m kg

Also M > m

The more the mass the more will be the force exerted on the opposite object.

Here the mass of the pedestrian is more than that of the bicycleAlso pedestrian is walking and bicycle is moving with an average speed so both of them would not have a large value of acceleration, which would affect the amount of force to be exerted on the opponent.

Therefore the bicycle will experience more force when both of them collided in the street.

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