which is an indication that a pump is cavitating? select one: a. pump does not make any working noises b. a decrease in the throttle will decrease discharge pressure c. an increase in the throttle will increase discharge pressure d. lack of reaction on the pressure gauge to increases in the throttle

Answers

Answer 1

The indication that a pump is cavitating is option D, which is a lack of reaction on the pressure gauge to increases in the throttle.

The lack of reaction on the pressure gauge to increases in the throttle. When a pump is cavitating, increasing the throttle will not result in an expected increase in discharge pressure, indicating a potential cavitation issue.

This means that even if the throttle is increased, there is no corresponding increase in discharge pressure, which is a clear sign of cavitation.

It is important to address cavitation promptly to prevent damage to the pump and ensure proper functioning.

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Related Questions


Technician A says that a mounting plate may be considered a piece of pulling hardware
Technician B says that a chain tensioner may be considered a piece of pulling hardware.
Who is right?

Answers

Answer:

technician b

Explanation:

Technician A and Technician B are saying about mounting plates. The statement of Technician B says that a chain tensioner may be considered a piece of pulling hardware. Technician B is right.

What is the mounting plate?

The component of a joint, handle, or lock that attaches the hardware to a cabinet is called a mounting plate. Doors can be fastened to frames more easily with mounting plates. The part of a joint that matches to the wood is called a mounting plate. Furniture, cabinets, and doors can all use mounting plates.

A sort of mechanical tool called chain tensioner aids in preserving the ideal tension in a chain. Inanition in a chain or belt can result in noise and vibration, as well as make it difficult for the chain to engage with the correct and function properly.

Therefore, technician B is correct.

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For a bronze alloy, the stress at which plastic deformation begins is 275 MPa, and the modulus of elasticity is 115 GPa. (a) What is the maximum load that may be applied to a specimen with a cross-sectional area of 325 mm2 without plastic deformation

Answers

Answer:

89375 N

Explanation:

Rearrange the formula for normal stress for F:

\(\sigma=\frac{F}{A}\)

\(F=\sigma*A\)

Convert given values to base units:

275 MPa = \(275*10^{6}\) Pa

325 \(mm^{2}\) = 0.000325 \(m^{2}\)

Substituting in given values:

F = \((275*10^{6})*(0.000325)=89375\) N

what is the division of demand

Answers

Answer:Demand is the number of goods that the customers are ready and able to buy at several prices during a given time frame.Division of demand:Composite demand.Short-run and long-run demand.Price demand.Income demand.Competitive demand.Direct and derived demand.


Any one know the answer?​

Any one know the answer?

Answers

Answer:

  151.2 N

Explanation:

The upward force at A is 135/(135+325) times the total weight of the generator. The CW torque about point O that produces is ...

  (460 mm)(135/460)(160 kg)(9.8 m/s^2) = 211.68 N·m

For F to produce half that torque, it must be ...

  F(0.7 m) = (211.68 N·m)/2

  F = 211.68 N·m/(1.4 m) = 151.2 N

in software engineering how do you apply design for change?

Answers

Answer:

it is reducely very iloretable chance for a software engineer to give an end to this question

How might an operations manager alter operations to meet customer demand? Name at least two ways.

Answers

Answer:

Some ways that an operations manager may alter operations to meet customer demand include understanding who the customer is (this could be conducted through surveys and feedback opportunities for the customer) and making stock demand be more efficient to meet customer demand.

A TV USE 75 WATTS WHILE IN USED ASSMING THAT ITIS USED 4 HOURS EVERY DAY HOW MUCH ENERGY IN 4 IN KWH WOULD THE TV CONSUME ANNUALLY?.

Answers

Answer:

Explanation:

The wattage listed is the maximum power drawn by the ... If John uses a window fan (200 watts) 4 hours a day for 120 ... TV, 120V, 75W.

                                                  or

75 w 4 hrs 30 days. So your total consumption is 75*4*30= 9000watt hr.

1 unit = 1000 watt hr.

9000 watt hr = 9 unit.

Total cost 9*2.5= RS 22.5

pls mark me as brainliest and this is a usefull answer pls dont delete

Please help ASAP and show all work. Thanks

1. An industrial water shutoff valve is designed to operate with 10 lb of effort force. The valve will encounter 100 lb of resistance force applied to a 2 in. diameter axle.
--a. What is the required actual mechanical advantage of the system?
--b. What is the required wheel diameter to overcome the resistance force?

2. A worker on a zip line crew lifts participants weighing approximately 200 lb several times a day from the ground 20 feet below. A block and tackle system is designed with 50 lb of effort force designed to lift the materials.
--a. What is the required actual mechanical advantage?
--b. How many supporting strands will be needed in the pulley system?

3. A simple gear train is composed of three gears. Gear A is the driver and has 10 teeth, gear B has 8 teeth, and gear C has 20 teeth.
--a. If the output is at C, what is the gear ratio?
--b. If gear A rotates at 60 rpm, how fast is gear C rotating?
--c. If the output of torque at gear C is 150 ftlb, what is the input torque at gear A?

4. Look at the picture provided.
--a. What class of lever is shown in the figure? (How do you know?)
--b. How much effort force is needed to balance the 100 lb load?

Please help ASAP and show all work. Thanks1. An industrial water shutoff valve is designed to operate

Answers

Answer:

1. --a 10

--b 100 in.

2. --a 4

--b 4

3. --a 2

--b 30 rpm

--c 75 ft.·lb.

4. --a Second class lever

--b 50 lbs.

Explanation:

The Actual Mechanical Advantage, AMA, is given as follows;

\(AMA = \dfrac{F_R}{F_E}\)

Where;

\(F_R\) = The resistance force magnitude

\(F_E\) = The effort force magnitude

1. a. We have;

\(F_R\) = 10 lb.

\(F_E\) = 100 lb.

\(AMA = \dfrac{100 \ lb}{10 \ lb} = 10\)

b. \(Mechanical \ advantage, \ M.A. = \dfrac{Distance \ moved \ by \ load}{Distance \ moved \ by \ effort}\)

The diameter of the axle, d = 2 in.

Let 'D' represent the diameter of the wheel, we have;

The distance moved by the axle, c = π·d

The distance moved by the load, C = π·D

\(M.A. = 10 = \dfrac{\pi \cdot D}{\pi \times 2}\)

∴ 2 × 10 = D

D = 20 in.

The required wheel diameter to overcome the resistance force, D = 100 in.

2. --a The mass of the participants, m = 200 lb.

The depth of the ground of the participants = 20 feet

The effort force = 50 lb

Actual Mechanical Advantage, AMA = 200 lb./(50 lb.) = 4

--b. The number of strands of pulley needed ≈ The mechanical advantage = 4

3. The number of gears on Gear A = 10 teeth

The number of gears on Gear B = 8 teeth

The number of gears on Gear C = 20 teeth

-a. Given that the driver gear = Gear A

The output gear = Gear C

\(The \ gear \ ratio = \dfrac{The \ number \ of \ teeth \ on \ the \ driven \ gear}{The \ number \ of \ teeth \ on \ the \ driver \ gear}\)

The driver gear = The input gear

Therefore, we have;

\(The \ gear \ ratio = \dfrac{20 \ teeth}{10 \ teeth} = 2\)

The gear ratio = 2

-b \(The \ gear \ ratio = \dfrac{The \ driver \ gear\ speed}{The \ driven \ gear\ speed}\)

Therefore, we have;

\(The \ gear \ ratio = 2 = \dfrac{60 \ rpm}{Gear\ C \, speed}\)

\(Gear\ C \, speed = \dfrac{60 \ rpm}{2} = 30 \ rpm\)

-c The output (driven) gear torque at Gear C = 150 ft.·lb.

\(The \ gear \ ratio = \dfrac{Driven \ gear \ torque}{Driver \ gear \ torque}\)

Therefore;

\(2 = \dfrac{150 \ ft \cdot lb}{Driver \ gear \ torque}\)

\(Driver \ gear \ torque = \dfrac{150 \ ft \cdot lb}{2} = 75 \ ft \cdot lb\)

The input (driver) torque at Gear A = 75 ft·lb

4. -a Given that the load is between the effort and the fulcrum, we have;

The type of lever is a second class lever

-b The distance between the load and the fulcrum = 4 feet

The distance between the effort and the fulcrum = 8 feet

We have;

100 lbs × 4 ft. = Effort × 8 ft.

∴ Effort = 100 lbs × 4 ft./(8 ft.) = 50 lbs.

The effort = 50 lbs.

A coastal engineer is to an oil platform as a structural engineer is to:

a freeway.

a skyscraper.

submarine pipelines.

an underground tunnel.

Answers

Answer:

I think the answer is d: underground tunnel

Explanation:

Hope this helps

The answer is Dan unground tanel

if both the ram air input and drain hole of the pitot system become blocked, the indicated airspeed will

Answers

If both the ram air input and drain hole of the pitot system become blocked, the indicated airspeed will: a) increase during a climb.

What is a ram air input?

A ram air input can be defined as an air intake system which is designed and developed to use the dynamic air pressure that is created due to vehicular motion, or ram pressure, in order to increase the static air pressure within the intake manifold of an internal combustion engine of an automobile.

This ultimately implies that, a ram air input allows a greater mass-flow of air through the engine of an automobile, thereby, increasing the engine's power.

In conclusion, indicated airspeed will increase during a climb when both the ram air input and drain hole of the pitot system become blocked.

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Complete Question:

If both the ram air input and drain hole of the pitot system become blocked, the indicated airspeed will

a) increase during a climb

b) decrease during a climb

c) remain constant regardless of altitude change

PLEASE HURRY!!!!
Which of the following can be inferred about Bill in the following scenario?

Bill has graduated and obtained a job as a geographer. He develops environmental models to analyze soil and water issues for a chemical company.

A) Bill studied environmental geography.
B) Bill earned a bachelor’s degree.
C) Bill earned a graduate degree.
D) Bill earned a certification in GIS technology.

Answers

I want to say your answer is C) Bill earned a graduate degree. I am so sorry if it is wrong! Hope this answer helps though! HAVE A GREAT REST OF YOUR DAY!!

Suppose a TCP connection is transferring a payload of 300 bytes. The furst byte is numbered 21050 . The sequence number of the segment if all data is sent in only one segment is____

Answers

If all the data is sent in only one segment, the sequence number of that segment would be 21349.

To determine the sequence number of the segment if all the data is sent in only one segment, we need to consider the following:

In a TCP connection, each byte of data is assigned a sequence number. The sequence number represents the byte's position within the stream of data being transmitted.

Given that the first byte is numbered 21050 and the payload is 300 bytes, we can calculate the sequence number for the segment as follows:

Sequence number = First byte number + Payload length - 1

Sequence number = 21050 + 300 - 1

Sequence number = 21349

Therefore, if all the data is sent in only one segment, the sequence number of that segment would be 21349.

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A scientist observes that both birds and snakes in the same ecosystem depend on the same mouse species as a food source. The relationship between the birds and the snakes is an example of

Answers

The relationship between the birds and the snakes in this scenario is an example of interspecific competition.

What is interspecific competition?

The friendship between the birds and the snakes in this scenario is an model of interspecific competition. The fowls and snakes are two different species playing for the same fare source (mice) in the unchanging ecosystem.

This type of contest is a common ecological wonder and can have significant impacts on the people sizes and dynamics of the species complicated. In some cases, individual species may outcompete the different, leading to a decline in the populace of the weaker competitor. In different cases, the species can coexist by partitioning resources or complying to different environmental niches.

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What is the study of how organisms interact with each other and their environment?

Answers

Answer:

Ecology

Explanation:

Utility company power lines carry what kind of current?

Answers

Answer:

Alternating

Explanation:

When an evaporator float switch is used in the drain pan of an air conditioner or heat pump, if the drain pan fills up, the float will interrupt the low-voltage circuit to:

Answers

The float will interrupt the low-voltage circuit to: The compressor contactor.

What is compressor contactor?

A compressor contactor can be defined as a tool that enables voltage with high energy to reach  the compressor so as to effectively run the compressor.

Evaporator float switch tend to disrupt  low voltage circular path  to the compressor contactor and this occur when the drain pain is filled to the brim.

Therefore the float will interrupt the low-voltage circuit to the compressor contactor.

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If your accelerator is stuck while driving what do you do first

Answers

If your accelerator gets stuck down, do the following:

Shift to neutral.

Apply the brakes.

Keep your eyes on the road and look for a way out.

Warn other drivers by blinking and flashing your hazard lights.

Try to drive the car safely off the road.

Turn off the ignition when you no longer need to change direction.

Answer:Kick the accelerator to dislodge it

Explanation:

Never reach down with your hand while driving, it's not safe.

R = 4MN and C= 0.75μF.
v(0)
v¡(t) = −t²V for 0s ≤ t ≤ 5s. What is the value of v
at time t = 5s, if v (0)
5s, if = 0? You can assume the
operational amplifier behaves as an ideal op amp with
power supplies of +15V and −15V. Give your answer
in volts, and omit the units from your answer.

R = 4MN and C= 0.75F.v(0)v(t) = tV for 0s t 5s. What is the value of vat time t = 5s, if v (0)5s, if

Answers

Answer:

45.9m

Explanation:

Given parameters:

Final velocity = 30m/s

Initial velocity = 0m/s

Unknown:

Height of fall = ?

Solution:

The motion equation to solve this problem is given below;

V² = U² + 2gH

V² = 0 + (2 x 9.8 x H)

Determine the critical load if the bottom is fixed and the top is pinned. ewew = 1. 6 ×(10)3ksi×(10)3ksi ,σyσy = 5 ksiksi

Answers

What is a Critical Load?

Critical load Fcr or buckling load is the value of load that causes the phenomenon of change from stable to unstable equilibrium state.

With that beign said, first it is neessary to calculate the moment of inercia about the x-axis:

\(Ix= \frac{db^3}{12}\\ Ix = \frac{2.(4)^3}{12} = 10.667in\)

Then it is necessary to calculate the moment of inercia about the y-axis:

\(Iy = \frac{db^3}{12}\\ Iy = \frac{4.(2)^3}{12} = 2.662in\)

Comparing both moments of inercia it is possible to assume that the minimun moment of inercia is the y-axis, so the minimun moment of inercia is 2662in.

And so, it is possible to calculate the critical load:

\(Pc\gamma = \frac{2046\pi ^2E.I}{L^2} \\Pc\gamma= \frac{2046.\pi ^2.(1,6.10^3.10^3).2662}{(10.12)^2} \\Pc\gamma= 5983,9db\)

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Using the attached file, please answer the following questions:
1. Use non-correlated sub-query, find the names of employees who are not working on any projects.
2. Use correlated sub-query, find the names of employees who are not working on any projects.
3. Use non-correlated sub-query, find the names of the employees who work on projects that are located in the same city where the employees are located.
4. Use correlated sub-query, find the names of the employees who work on projects that are located in the same city where the employees are located.
5. Use sub-query, find the names of the employees with the highest rate.
6. Use sub-query and the ALL operator, find the names of the employees with the highest rate.
7. Use inline views and sub-query, find the names of employees with the highest rate.
8. Use self-join, find the names of the employees who work on more than one project.
9. Use non-correlated sub-query, find the names of the employees who work on more than one project.
10. Use correlated sub-query, find the names of the employees who work on more than one project

Answers

1. Using a non-correlated sub-query, the names of employees who are not working on any projects can be found using the following query:

SELECT name FROM Employees WHERE employee_id NOT IN (SELECT employee_id FROM Projects);

2. Using a correlated sub-query, the names of employees who are not working on any projects can be found using the following query:

SELECT name FROM Employees WHERE NOT EXISTS (SELECT * FROM Projects WHERE Employees.employee_id = Projects.employee_id);

3. Using a non-correlated sub-query, the names of the employees who work on projects that are located in the same city where the employees are located can be found using the following query:

SELECT e.name FROM Employees e INNER JOIN Projects p ON e.employee_id = p.employee_id WHERE e.city = p.city;

4. Using a correlated sub-query, the names of the employees who work on projects that are located in the same city where the employees are located can be found using the following query:

SELECT name FROM Employees e WHERE EXISTS (SELECT * FROM Projects p WHERE e.employee_id = p.employee_id AND e.city = p.city);

5. Using a sub-query, the names of the employees with the highest rate can be found using the following query:

SELECT name FROM Employees WHERE rate = (SELECT MAX(rate) FROM Employees);

6. Using a sub-query and the ALL operator, the names of the employees with the highest rate can be found using the following query:

SELECT name FROM Employees WHERE rate >= ALL (SELECT rate FROM Employees);

7. Using inline views and sub-query, the names of employees with the highest rate can be found using the following query:

SELECT name FROM (SELECT name, MAX(rate) AS max_rate FROM Employees GROUP BY name) AS e WHERE e.max_rate = (SELECT MAX(rate) FROM Employees);

8. Using self-join, the names of the employees who work on more than one project can be found using the following query:

SELECT DISTINCT e1.name FROM Employees e1 INNER JOIN Projects p1 ON e1.employee_id = p1.employee_id INNER JOIN Projects p2 ON e1.employee_id = p2.employee_id WHERE p1.project_id != p2.project_id;

9. Using a non-correlated sub-query, the names of the employees who work on more than one project can be found using the following query:

SELECT name FROM Employees e WHERE e.employee_id IN (SELECT employee_id FROM Projects GROUP BY employee_id HAVING COUNT(*) > 1);

10. Using a correlated sub-query, the names of the employees who work on more than one project can be found using the following query:

SELECT name FROM Employees e WHERE EXISTS (SELECT * FROM Projects p WHERE e.employee_id = p.employee_id GROUP BY p.employee_id HAVING COUNT(*) > 1);

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what substance does light travel through before putting water in the cup

Answers

Bend surface in water! Hopefully this helps, I looked it up!
what substance does light travel through before putting water in the cup

A jet aircraft is in level flight at an altitude of 30,000 ft with an airspeed of 500 ft/s. The aircraft has a gross weight of 19,815 lb, a wingspan of 53.3 ft, and an average chord length of 6 ft. The Oswald efficiency factor is 0.81 and the zero-lift drag coefficient is equal to 0.02. The jet has two turbofan engines, each producing a maximum thrust of 3,650 lb at sea level.

Required:
a. Create a plot of the drag polar for this aircraft for CL from 0 to 5. Plot CL on the vertical axis, CD on the horizontal axis, and do not include negative CL values.
b. What is the total drag coefficient at the flight condition described above?
c. What is the required thrust for level flight at this altitude in lb?
d. If the pilot runs the engines at maximum thrust, what is the instantaneous rate of climb at this altitude and velocity?

Answers

Answer:

a) attached below

b) 0.0337

c) 2730.206 Ib

d) 2320.338 ft/min

Explanation:

a) Plot of the drag polar for this aircraft

first we will calculate :

Wing area (s) = Wing span (b) * Average chord length(c)

                       = 53.3 * 6 = 319.8 ft^2

Aspect ratio =  b^2 / s = 8.883

K = 1 / \(\pi\)eAR = 1 /

Drag polar ( Cd ) = 0.02 + 0.044 C^2L

attached below is a plot of the drag polar

Attached below is the detailed solution of the remaining part of the question

A jet aircraft is in level flight at an altitude of 30,000 ft with an airspeed of 500 ft/s. The aircraft
A jet aircraft is in level flight at an altitude of 30,000 ft with an airspeed of 500 ft/s. The aircraft
A jet aircraft is in level flight at an altitude of 30,000 ft with an airspeed of 500 ft/s. The aircraft
A jet aircraft is in level flight at an altitude of 30,000 ft with an airspeed of 500 ft/s. The aircraft

All these are returnless fuel systems EXCEPT ?

Answers

Answer:

we need to see what you're being asked about

Explanation:

In engineering economic analysis, it is permissible to sum dollar amounts without conversion only when __________ .

Answers

Answer:

they occur at the same time

Explanation:

What this means is that if let's say on a particular cash record we have two transactions on the same date: For example,

11th/20/2020 received $50 from Jude and received $950 from Paul to pay his credit balance.12th/20/2020

Only the two transactions on the 11th are permissible to sum the dollar amounts without conversion.

the most notable aspect in managing C/N for downlink designs is

Answers

Answer:

Explanation:

In satellite communications, downlink is the establishment of a communications link from an orbiting satellite down to one or more ground stations on Earth. Contrast with uplink.

A video store rents movies to members. Each movie in the store has a title and is identified by a unique movie number. A movie can be in VHS, VCD, or DVD format. Each movie belongs to one of a given set of categories (action, adventure, comedy, horror). The store stores a name and a unique phone number for each member. There are two types of members:
Golden Members: Require their credit card and can rent more than one movie each time.
Bronze Members: Don't require a credit card and can rent only one movie each time.
Make a class diagram for it.

Answers

Here's a class diagram that represents the entities and their relationships for the video store scenario described:

The Class Diagram

+---------------------+        +---------------+       +-----------------+

|      Movie          |        |    Member     |       |    Rental       |

+---------------------+        +---------------+       +-----------------+

|  movie_id : int     |        |   member_id : |       | rental_id : int |

|  title : string     |        |   int        |<-------| movie : Movie    |

|  format : string    |        |   name : str |        | member : Member |

|  category : string  |        |   phone : str|        | rental_date : dt|

+---------------------+        |   type : str |        | is_returned : bool |

                               +---------------+        +-----------------+

                               |  credit_card: |                

                               +---------------+                

                               | rent_movies() |                

                               +---------------+                

                                         ^                      

                                         |                      

                               +---------------+                

                               | GoldenMember  |                

                               +---------------+                

                               | rent_limit:   |                

                               +---------------+                

                               | return_movies()|                

                               +---------------+                

                                         ^                      

                                         |                      

                               +---------------+                

                               | BronzeMember |                

                               +---------------+                

                               | rent_limit:   |                

                               +---------------+                

                               | return_movie()|                

                               +---------------+                

The Movie class has attributes movie_id, title, format and category. Each Member has a member_id, name, phone, and type. The Rental class is the association class that connects Movie and Member through the movie and member attributes, respectively, and adds rental_id, rental_date, and is_returned attributes.

There are two sub-classes of Member: GoldenMember and BronzeMember. The GoldenMember has an additional credit_card attribute and a rent_limit method that allows them to rent multiple movies at once. The BronzeMember has a rent_limit method that allows them to rent only one movie at a time. Both sub-classes have a return_movie or return_movies method, respectively, to allow them to return the rented movies.

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What is the first thing a technician should check when a new drive is not recognized by the operating system

Answers

The  first thing a technician need to check if a new drive is not recognized by the operating system are:

Look at the Hard Drive Cable Connection.Do Initialize and then Format Hard Drive.Why does Hard Drive Not Showing Up in system?

The issues on how to fix it are:

Check and then one can change Hard Drive ConnectionDo Format Hard Drive to NTFS. Recover Data and make a Partition.

Hence, The  first thing a technician need to check if a new drive is not recognized by the operating system are:

Look at the Hard Drive Cable Connection.Do Initialize and then Format Hard Drive.

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An airplane is flying at a standard altitude of 5 km. A pitot tube mounted at the nose measures a stagnation pressure of 0. 957 bar. Assume the airplane is flying at high subsonic speed and flow is compressible.


Required:

Calculate the velocity of airplane

Answers

The velocity of airplane will be 317.4 m/s.

The velocity of an airplane flying at a standard altitude of 5 km can be calculated using the stagnation pressure of the pitot tube mounted at the nose.

The stagnation pressure of the pitot tube was measured at 0.957 bar. Assuming the airplane is flying at high subsonic speed and flow is compressible, the velocity of the airplane can be calculated using the equation:

Velocity (v) = sqrt[2*(pstag-pamb)/ρ]

Where pstag is the stagnation pressure (0.957 bar), pamb is the ambient pressure (0.1013 bar at 5 km altitude), and ρ is the air density (1.225 kg/m3).

Plugging in the given values, the velocity of the airplane is 317.4 m/s.

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which of these is a term for a person who does not share the belief of the dominant religion of a society ?
A. a heathen
B. Assimilated
C. Uncivilized
D. A savage

Answers

Answer: a heathen

Explanation:

The term for a person who does not share the belief of the dominant religion of a society is "a heathen". The correct option is A.

What is society?

A society is a group of people who interact with one another on a regular basis, or a large social group that shares the same spatial or social territory and is typically subject to the same political authority and dominant cultural expectations.

"A heathen" is a person who does not share the beliefs of a society's dominant religion.

The term is frequently used to describe someone who is considered uncivilized or primitive because of their religious beliefs, especially in societies where the dominant religion wields significant power and influence.

However, it is important to note that the term can be considered derogatory and offensive, and it is generally more respectful to refer to people of different religious beliefs using neutral or positive terms.

Thus, the correct option is A.

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what is a shim in cybersecurity

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A software modification inserted into an operating system or application, to intercept the normal data flow and provide additional functionality
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