Why didn't the liquid methane change phase before the year 2007? Use all the words in the word bank provided to you to complete the response.
Due to the lack of supply of energy the methane could not change its phase before 2007.
What is the main reason behind this question?Even though it has been summer since 2002, the lake didn't dry up until 2007. After 2007, the sun had given out enough energy for the methane molecules' kinetic energy to rise enough to outweigh their attraction to one another. The methane molecules in the lake were gaining kinetic energy at this moment, but the lake was still liquid. The temperature of the molecules remains constant while they melt because the average kinetic energy of the molecules does not vary.
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Calculate the approximate volume of a 0.600 mol sample of gas at 15 °C and a pressure of
1.0 atm.
1) List known values.
sample: 0.600 mol
Pressure: 1.0 atm
Temperature: 15ºC
Constant: 0.082057 L⋅atm⋅K−1⋅mol−1
List unknown values
Volume:
2) Set the equation and solve for V.
\(PV=\text{nRT}\)\(\frac{PV}{P}=\frac{nRT}{P}\)\(V=\frac{nRT}{P}\)3) Converting to proper units.
15ºC + 273.15 = 288.15 K
4) Plug in known values.
n: 0.600 mol
R: 0.082057 L⋅atm⋅K−1⋅mol−1
T: 288.15 K
P: 1.0 atm
\(V=\frac{(0.600\text{mol)}(0.082057L\cdot\text{atm}\cdot K^{-1}\cdot mol^{-1})(288.15\text{ K)}}{1.0\text{ atm}}=14.18683\text{ L}\)The sample will occupy a volume of 14.19 L.
How many moles of glucose (C,H,,,) can be made from 12.5 moles of carbon?
Answer: 25 moles
Explanation:
I remember learned this in last year AP Chemistry class
Cu2O + C -> Cu + CO2 balanced equation
Answer:
2Cu2O + C --> 4Cu + CO2
Explanation
The Law of conservation of Mass states You can not destroy or create math in a chemical reaction, meaning you must have the same amount at the beginning and the end. This equation keeps the same amount of atoms on both sides.
Answer: Yes, it is a balanced equation.
Explanation:
https://chemequations.com/en/?s=Cu2O+%2B+C+%3D+Cu+%2B+CO2
This is where I got the answer so you know. Hope this helps :)
Which of the following can be used without coordinating with managers of succeeding activities? A. Total slack B. Free slack C. Critical float D. Float pad
Total slack can be used without coordinating with managers of succeeding activities. The correct option is A.
Total slack refers to the amount of time that an activity can be delayed without affecting the overall project completion time or the start time of the succeeding activities. It is an indicator of the flexibility of the schedule and can be used by a project manager to identify activities that can be delayed without affecting the overall project completion time.
Total slack can be calculated by subtracting the duration of the activity from the difference between the late finish time and the early start time of the succeeding activity. Since total slack does not affect the start time of succeeding activities, it can be used without coordinating with the managers of the succeeding activities.
On the other hand, free slack, critical float, and float pad all require coordination with the managers of the succeeding activities as they can impact the start time of the succeeding activities. Therefore, correct option is A. Total slack.
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If a core of a planet is destroyed there's the planet gets destroyed as well?
xXBailyXx hurrry
Answer:
Most chunks of land will probably explode into a giant dust cloud if you hit them together at hundreds of miles per hour. with these types of collisions, the densest stone will turn to gravel. people will be flung into the air. people will tumble across the ground, or be flattened by a sudden acceleration.
Explanation:
Thank you Charlie
,SJhfgaiuehrg;oiaerhgoaw
?
Answer:
nah man
Explanation:
Carbon dioxide is used by plants for ___?
Answer:
photosynthesis
Explanation:
that's the way plants feed themselves
Answer:
photosynthesis
Explanation:
I hope i helped
someone help me what is the difference between alchemy and chemistry
Answer:
Alchemy is based on mystic view of reality whereas chemistry is based on experiments, observations and facts.
it takes 7 drops of our sodium carbonate solution to neutralize 3 drops of our citric acid solution. this means that our: * the citric acid is more acidic than the sodium carbonate is basic the citric acid is less acidic than the sodium carbonate is basic the citric acid is equally as acidic as the sodium carbonate is basic
If it takes 7 drops of an alkaline to neutralize 3 drops of acid it means that acid is much stronger than the alkaline. So more is needed to be used.
HELLO PLSS I DONT KNOW
Answer:
C
Explanation:
hope this helps
If you add 25.0 mL of water to 125 mL of a 0.150 M LiOH solution, what will be the molarity of the resulting diluted solution? 0.0450 M LiOH 0.0647 M LiOH 0.125 M LiOH 0.134 M LiOH
Answer:
solute in a fixed volume of solution
Concentration(c) = number of moles of solute(n) / volume of solution (v)
25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.
original solution molarity - 0.150 M
number of moles of LiOH in 1 L - 0.150 mol
number of LiOH moles in 0.125 L - 0.150 mol/ L x 0.125 L = 0.01875 mol
when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases
new volume - 125 mL + 25 mL = 150 mL
therefore new molarity is
c = 0.01875 mol / 0.150 L = 0.125 M
answer is 0.125 M
Explanation:
did this answer got right
Answer:
0.125
Explanation:
Just completed the test and got it correct.
What’s the answer????
Answer:
1. C
2. A
3. A
Explanation:
which risks are involved in both underground mining and surface mining? select the two correct answers.(1 point) responses high water pressure high water pressure uv exposure uv exposure ground instability ground instability methane gas buildup methane gas buildup respiratory disease
The two correct answers for risks involved in both underground mining and surface mining are Ground instability and Respiratory disease.
Ground instability: Both underground mining and surface mining can be susceptible to ground instability, which can lead to cave-ins, landslides, or collapses.
Respiratory disease: Both types of mining can expose workers to dust and harmful particles, which can cause respiratory diseases such as pneumoconiosis (e.g., coal workers' pneumoconiosis) or silicosis.
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The space around the nucleus of an atom that electrons orbit
Answer:
The electron cloud - or - electron orbitals
Explanation:
Protons and neutrons are held in the nucleus of the atom; electrons orbit around the nucleus in orbitals. Modern atomic theory tells us that these orbitals are not necessarily a circular or elliptical path but more like a cloud-like area where electrons are likely to be found at any given time.
The identity characteristics of an element is its number of __
Explanation:
atomic number shows proton
A olution i 0. 0480 m KCl. What i the molarity of the olution if the denity i 1. 10 g/ml
The molarity of the solution of 0.0480 M KCl is 0.05261 M.
Given that:
The solution is 0.0480 mol KClThe density is 1.10 g/mlThe molar mass of KCl is 74.5513 g/molAssuming that 1.0 kg of the solvent is present, we can think that 0.0480 moles of KCl are the moles of solute. Then, we can determine the mass of KCl using the molar mass
0.0480 * (74.5513 / 1) = 3,578 g KCl
The mass of the solution is 1 kg (1000 g) + 3,578 g = 1,003.578 g.
Using the given density and the moles of solute, we can calculate the molarity of the solution as follows:
[KCl} = mol KCl / volume solution
= 0.0480 / (1,003.578 * 1/1.10 * 1/1000)
= 0.05261 M
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According to a recent pol, 25% of adults in a certain area have high levels of cholesterol. They ceport that such elevated fevels "could be financialy devastating to the regions heathcare instem" and are a major concern to health insurance providers. Assume the standard deviation from the recent studies is accurate and known. According to recent studies, cholesterol levels in healthy adults from the area average about 205 mg/dL, with a standard deviation of about 35 mg/dL, and are roughly Normally distributed. If the cholesterol levels of a sample of 46 healthy adults from the region is taken, answer parts (a) through (d)
(a) What is the probability that the mean cholesterol level of the sample will be no more than 205?
Plys 205) 0.5 (Round to three decimal places as needed.)
(b) What is the probability that the mean cholesterol level of the sample will be between 200 and 2107
P(200
(c) What is the probability that the mean cholesterol level of the sample will be less than 1957
Ply<195) (Round to three decimal places as needed)
(d) What is the probability that the mean cholesterol level of the sample will be greater than 2179
Py>217) (Round to three decimal places as needed)
Hence, the probability that the mean cholesterol level of the sample will be greater than 217 is 0.034. Answer: 0.034.According to the given statement, we have the following data.
mean (μ) = 205 mg/dLstandard deviation
(σ) = 35 mg/dLsample size
(n) = 46(a) Probability that the mean cholesterol level of the sample will be no more than 205.To find this, we will use the z-score formula.z
= (x - μ) / (σ/√n)Here,
x = 205
μ = 205
σ =
35n
= 46Plugging in these values, we get,
z = (205 - 205) / (35/√46)
z = 0Hence, the probability that the mean cholesterol level of the sample will be no more than 205 is 0.5. Answer: 0.5
(b) Probability that the mean cholesterol level of the sample will be between 200 and 210:
To find this, we need to standardize the values and use the z-table.P(z < (210 - 205) / (35/√46)) - P(z < (200 - 205) / (35/√46))P(z < 1.65) - P(z < -1.65) = 0.4495 - 0.0505
= 0.3990Hence, the probability that the mean cholesterol level of the sample will be between 200 and 210 is 0.3990. Answer: 0.3990
(c) Probability that the mean cholesterol level of the sample will be less than 195: To find this, we need to standardize the values and use the z-table.P(z < (195 - 205) / (35/√46))P(z < -2.91) = 0.002Hence, the probability that the mean cholesterol level of the sample will be less than 195 is 0.002. Answer: 0.002
(d) Probability that the mean cholesterol level of the sample will be greater than 217: To find this, we need to standardize the values and use the z-table.P(z > (217 - 205) / (35/√46))P(z > 1.82) = 0.034 Answer: 0.034.
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How many moles of solid Ba(NO3)2 should be added to 300. mL of 0.20 M Fe(NO3)3 to increase the concentration of NO3 1- ion to 1.0 M? (Assume that the volume of the solution remains constant)
The number of moles of the solid Ba(NO₃)₂ added to the 300 mL of the 0.20 M Fe(NO₃)₃ to increase the concentration of NO₃⁻¹ ion to 1 M is 0.06 mol
The number of Fe(NO₃)₃ = molarity × volume
The number of Fe(NO₃)₃ = 0.20 × 0.300
The number of Fe(NO₃)₃ = 0.06 mol
Moles of NO₃⁻¹ = 0.18 mols present
Moles of NO₃⁻¹ need = 1 × 0.300 L
Moles of NO₃⁻¹ need = 0.300 mol
Number of moles he have = 0.300 - 0.180
= 0.120 mol
Ba(NO₃)₂ contains 2 moles of NO₃⁻¹, therefore number of moles of Ba(NO₃)₂ added :
Moles of Ba(NO₃)₂ = 0.120 / 2 = 0.06 mol
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What does thermal energy refer to?
Answer:
Thermal energy refers to the energy contained within a system that is responsible for its temperature.
a student was given a dye sample believed to contain several components. in an attempt to determine the identity of those components, she decided to analyze the mixture using tlc. the student used both 100% hexanes and 50% hexanes in ethyl acetate as eluting solvents and spotted known dyes for comparison. the following tlc chromatographs were obtained. which is the best solvent choice for this analysis?
The best solvent choice for this analysis will be 50% hexanes in ethyl acetate.
Ethyl acetate having a molecular weight of 174.28, is observable in chromatography paper.
In the chemical examination, chromatography could be a research facility strategy for the partition of a blend into its components.
The blend is broken down into a liquid dissolvable (gas or fluid) called the versatile stage, which carries it through a framework (a column, a capillary tube, a plate, or a sheet) on which a fabric called the stationary stage is settled.
Since the distinctive constituents of the blend tend to have diverse affinities for the stationary stage and are held for distinctive lengths of time depending on their intuition with their surface destinations causing them to partition.
The partition is based on the differential dividing between the portable and the stationary stages. Unpretentious contrasts in a compound's parcel coefficient result in differential maintenance on the stationary stage and hence influence the division.
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It was a cold December night many, many, years 1___ ___ when young 2___ ___ ___ ___ ___ decided to have some 3___ ___ ___ with his friends. He found a 4___ ___ ___ and brought it home.
Answer: 1) ago
Explanation:
how is ionic radius used to find chemical bonds and reactions
Answer:
Although atoms with equal numbers of protons and electrons exhibit no electrical charge, it is common for atoms to attain the stable electronic configuration of the inert gases by either gaining or losing electrons. The metallic elements on the left side of the periodic table have electrons in excess of the stable configuration. Table 1 shows the electron loss necessary for three light metals to reach a stable electron structure.
The positive charge on the resulting metal ion is due to the atom possessing more nuclear protons than orbital electrons. The valence electrons are most distant from the nucleus; thus, they are weakly held by the electrostatic attraction of the protons and, consequently, are easily stripped from atoms of the metals.
By contrast, the nonmetallic elements on the right side of the periodic table have fewer electrons than that of a stable configuration and can most readily attain the stable configuration of the inert gases by gaining electrons. The negative charge on the resulting nonmetal ion is due to the atom possessing more orbital electrons than nuclear protons. Table 2 compares three nonmetals to the inert gas argon.
Because metallic elements tend to lose electrons and nonmetallic elements tend to gain electrons, a pair of contrasting elements will exchange electrons so that both achieve stable electronic configurations. The resulting ions of opposite charge have a strong force of electrostatic attraction, which is called an ionic bond. Note: This bond forms through the complete transfer of electrons from one atom to another, in contrast to the electron sharing of the covalent bond.
The force of attraction between two points of opposite electrical charge is given by Coulomb's law:
equation
where q + is the positive charge, q – is the negative charge, and d is the distance between the two charges. This law of electrostatic attraction can be used to measure the distance between two spherical ions because the charges can be considered to be located at the center of each sphere. (See Figure 1.)
Figure 1. The distance between ionic charges.
figure
Notice that the distance between the centers of the two ions is the sum of radii of the ions. The appropriate electrostatic force then is calculated from the equation
equation
where q C is the charge of the positive cation, q A is the charge of the negative anion, and the denominator is the sum of their radii.
The strength of ionic bonding, therefore, depends on both the charges and the sizes of the two ions. Higher charges and smaller sizes produce stronger bonds. Table 3 shows the approximate radii of selected ions, which have the electronic configuration of an inert gas. The radii are in equation.
For ions of the same charge, the ionic radius increases as you go down any column because the elements of higher atomic number have a greater number of electrons in a series of electronic shells progressively farther from the nucleus. The change in ionic size along a row in the chart just above shows the effect of attraction by protons in the nucleus.
In Table 4, the five ions O 2– through A1 3+ are all isoelectronic; that is, they have the same number of electrons in the same orbitals.
For continuity, the neutral Ne atom is also in the chart, with its atomic radius. As you proceed to the right in Table 4, the greater number of protons attracts the electrons more strongly, producing progressively smaller ions.
Now use Coulomb's law to compare the strengths of the ionic bonds in crystals of magnesium oxide and lithium fluoride. The sizes of the four ions are taken from the tabulation of radii of cations and anions in Table 5.
equation
Comparing the two relative forces of electrostatic attraction that you calculated, you can conclude that ionic bonding is considerably stronger in magnesium oxide. This affects the physical properties and chemical behavior of the two compounds. For example, the melting point of MgO (2,852°C) is much higher than that of LiF (845°C).
The strength of chemical bonding in various substances is commonly measured by the thermal energy (heat) needed to separate the bonded atoms or ions into individual atoms or ion
Explanation:
is CO(NH2)2 and (NH2)2CO the same thing
Answer:
Explanation: the answer is YES
CO(NH2)2 and (NH2)2 CO is the urea
1
N
3
5
6
7
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Which is evidence that a chemical reaction has likely occurred?
a liquid slowly losing volume
the formation of a precipitate
boiling water releasing steam
a change in the shape of a solid
Answer:
The new substance will need more energy to form its chemical bonds than the old substance will release. ... More energy will be released from the old substance than the new substance will need to form its chemical bonds.
Explanation:
This is the answer I got. Hope it's really helpful
Answer:
"Which is evidence that a chemical reaction has likely occurred?"
The correct answer would be,
B. the formation of a precipitate
Explanation:
Got it right on my test, have a great day!
Consider an enzymatic reaction in which the initial concentration of substrate is low. If the amount of enzyme is held constant, but the amount of substrate is increased, the rate of an enzyme catalyzed reaction will.
Answer:69.8
Explanation:
given the informationa bc⟶2d⟶dδ∘δ∘=661.8 kjδ∘=308.0 j/k=569.0 kjδ∘=−154.0 j/k calculate δ∘ at 298 k for the reactiona b⟶2c δ∘=
To calculate the standard enthalpy change, δ∘, for the reaction A + B ⟶ 2C, we can use Hess's Law and the given information about the enthalpies of formation and standard enthalpy change for the reaction A + B ⟶ 2C at 298 K is +662.4 kJ/mol.
First, we can write the two reactions and their enthalpy changes as follows: A + B ⟶ 2D δ∘ = +661.8 kJ/mol 2D ⟶ D + C δ∘ = -308.0 J/K/mol = -0.308 kJ/mol/K (note that this is given in J/K/mol, so we need to convert it to kJ/mol)
Next, we can use the fact that the enthalpy change is a state function, meaning that it only depends on the initial and final states of the system and not on the path taken between them.
Therefore, we can add the two reactions together to obtain the overall reaction of interest: A + B ⟶ 2C δ∘ = ? To do this, we need to cancel out the intermediate species, D, on both sides of the equation.
We can do this by multiplying the second reaction by 2 and reversing it: 2D ⟶ 2C δ∘ = -2(-0.308 kJ/mol/K) = +0.616 kJ/mol/K A + B ⟶ 2D δ∘ = +661.8 kJ/mol A + B ⟶ 2C δ∘ = +662.4 kJ/mol. Therefore, the standard enthalpy change for the reaction A + B ⟶ 2C at 298 K is +662.4 kJ/mol.
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Why can you not selectively epoxidize an alkene with mcpba in the presence of a ketone?.
MCPBA is useful reagent for epoxide formation and ketone to ester formation and it epoxidized alkene to epoxide and also oxidize ketone to ester and so we can't selectively epoxidize an alkene if both alkene and ketone are present
Purified mCPBA is a useful reagent for the oxidation of various classes of aldehyde α branches aliphatic aldehydes undergo beayer villiger oxidation to form formates and α bramced α-β unsaturated aldehydes yield enol formates and or epoxides and α hydoxylated aldehydes yield ketone and most aldehydes and ketone have a low celling temprature below ambient temprature that is these compound do not polymerize above room temprature and mCPBA is strong oxidant comparable to other peracid and the advantage of 3 chloroperbenzoic acid is it handling
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Pb(NO3)2(aq) + KCl(aq) ---- → KNO3(aq) + PbC12(s)
An atom's electron configuration ends with 3p2. If another atom has eight more electrons, what would be the continuation of the electron configuration?
Answer:
3p6 3d4
Explanation:
3d will come after 3p => 3p 3d
p will hold maximum of 6 electrons while d will hold maximum of 10 electrons.
if there are 8 more electrons to 3p2, then 4 will fill 3p so it will become 3p6
then the other 4 will fill 3d to become 3d4