The formula for calculating the force between two charged particles is expressed as
F = kq1q2/r^2
where
F is the forck is the Coulomb's constant
q1 and q2 are the magnitude of the charges
r is the distance between the charged bodies
23. What mass of water will give up 240 calories
when its temperature drops from 80°C to 68°C?
Answer:
20g
Explanation:
Given parameters:
Quantity of heat = 240calories
Initial temperature = 80°C
Final temperature = 68°C
Unknown:
Mass of water = ?
Solution;
To solve this problem, we use the expression:
Q = m c (t₂ - t₁)
Q is the quantity of heat
m is the mass
c is the specific heat = 1 cal/g°C
t₂ is the final temperature
t₁ is the initial temperature
Insert the parameters and solve;
Change in temperature is an absolute value
240 = m x 1 x (68 - 80)
m = 20g
How has Physics improved
or affected our society?
By supplying the fundamental knowledge required to create new instruments and techniques for medical use, physics enhances our quality of life
From can openers, light bulbs, and mobile phones to muscles, lungs, and brains; from paintings, piccolos, and pirouettes to cameras, vehicles, and cathedrals; from earthquakes, tsunamis, and storms to quarks, DNA, and black holes, physics aids us in understanding the workings of the world around us.
The science of physics is the most fundamental and has many applications in contemporary technology. Because it makes it possible for smartphones, computers, televisions, watches, and many other modern technologies to function automatically, physics is crucial to modern technology.
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Help pleasessssssssssssss
Sorry I had the answer but it wont let me type numbers :(.:
The efficiency of the power station is 0.38(38%). Its electrical power output is 1.9x10^9 W. Calculate the input to the power station
The input to the power station is 5x10^9 W. This means that the power station requires an input of 5x10^9 watts to produce an electrical power output of 1.9x10^9 watts with an efficiency of 38%.
The efficiency of a power station is defined as the ratio of its output power to input power. Therefore, we can use the efficiency and the electrical power output of the power station to calculate its input power as follows:
Efficiency = Output power / Input power
Solving for input power, we get:
Input power = Output power / Efficiency
Substituting the given values, we get:
Input power = 1.9x10^9 W / 0.38
Input power = 5x10^9 W (to two significant figures)
The rest of the input power is lost as heat due to inefficiencies in the power generation process.
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how do you mountaineers reduce the effects of changes in atmospheric pressure?
What/Where is the area of the mantle is reaching the Earths surface?
Explanation: The mantle is divided into several layers: the upper mantle, the transition zone, the lower mantle, and D” (D double-prime), the strange region where the mantle meets the outer core. The upper mantle extends from the crust to a depth of about 410 kilometers (255 miles).
Where do you feel that you are traveling at the fastest speed when on the swing?
Answer:
C
Explanation:
I think it's C, because at that point, you are going fastest. Sorry if im wrong, hope this helps.
Answer:
In between and the middle one
Explanation:
Two identical cars A and B are at rest on a loading dock with brakes released. Car C, of a slightly different style but of the same weight, has been pushed by dock workers and hits car B with a velocity of 3.25 m/s. Knowing that the coefficient of restitution is 0.8 between B and C and 0.5 between A and B, determine the velocity of each car after all collisions have taken place.
Answer:
V(c)' = 0.325 m/s
V(a)' = 2.19375 m/s
V(b)'' = 0.73125
Explanation:
See attachment for explanation.
In order for an object to accelerate (blank) must be applied.
Answer:
a force
Explanation:
a force causes a certain object to move and make a displacement.
Answer:
A force must be applied.
With out force there is no movement that causes friction. Gravity is a force but doesn't affect all movement.
4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.
a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.
The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.
The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.
b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.
The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.
In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.
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2. A 60 kg diver jumps off a diving board with a height of 10
meters and accelerates toward the ground. At the point shown
in the diagram, she has 1,764 Joules of gravitational energy
and 4,116 Joules of kinetic energy. What is the diver's total
mechanical energy at that point?
Answer:5,880
Explanation:Lol if I get this wrong sorry I’m trying to do this also but if you add the 1,764 joules and 4,116 joules in total if you add them all up it’ll give you 5,880 hope that helps.
Determine the magnitude and direction of the electric field at a point midway between a –8.0 µC and a +5.8 µC charge 6.0 cm apart. Assume no other charges are nearby.
The magnitude and direction of the electric field is equal to 3.45 x10^13 N/m and the direction in towards the negative charge.
Electric field
To calculate the electric field of a point it is necessary to use the following expression:
\(E = k\frac{Q}{d^{2}}\)
Thus, calculating the field formed by each charge we have:
–8.0 µC
\(E = 9 \times 10^{9} \times \frac{8}{36\times 0.0001}\)
\(E = 2\times 10^{13} V/m\)
+5.8 µC\(E = 9 \times 10^{9} \times \frac{5.8}{36\times 0.0001}\)
\(E = 1.45 \times 10^{13} N/m\)
The direction of the electric field of the negative charge is towards the charge (attracted) and of the positive charge is repelled.
So, we can add the two values of field found, since the two are directed towards the negative charge, so that :
\(E = 2 \times 10^{13} + 1.45 \times 10^{13}\)
\(E = 3.45 \times 10^{13} N/m\)
So, the magnitude of eletric field is equal to 3.45 x10^13 N/m and the direction in towards the negative charge.
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.Given the displacement vectors A = 6f-4j+8k B = 2î+4ƒ^ − 14k
Find the magnitude and the unit vector of the vector 0.5A + 0.5B
Answer:
Explanation:
A = 6i - 4j + 8k
B = 2i + 4j - 14k
A + B = (6+2)i + (-4+4)j + (8-14)k
A + B = 8i +0j -6k
A + B = 8i - 6k
(1/2)(A + B) = 4i - 3k
d = √ (4² + 3²) = 5
e = (4/5)i -(3/4)j
Ellie is shooting a free throw. At the instant the ball leaves her hand the ball is traveling at a velocity of 9 m/sec, at an angle above the horizontal of 29.5 degrees. If you are standing beneath the basketball rim, videotaping, you can only see the vertical motion of the ball, since its horizontal motion is straight towards you. What is the magnitude of the ball's initial vertical velocity (if you measured it using your video data, in m/sec)
Answer:
Vy = 4.43 m/s
Explanation:
given data
velocity = 9 m/sec
angle horizontal = 29.5 degrees
solution
we get here ball initial vertical velocity will be here
Vy = v sinθ ...........................1
put here value and we get
Vy = 9 × sin(29.5 )
Vy = 4.43 m/s
What is the mass of mars
the mass of mars is
6.39 × 10^23 kg
Contamination of food in a storage area can be reduced by: making sure that the temperature is kept at 98°F removing all wrapping from food before storage putting cardboard on the floor of the store room to keep food off the floor keeping raw and ready to eat food separated
Of the options provided, keeping raw and ready-to-eat food separated is likely the most effective way to reduce contamination of food in a storage area.
When raw meat and ready-to-eat foods come into contact with each other, there is a risk of cross-contamination, which can lead to foodborne illness. This can happen if bacteria from the raw meat are transferred to the ready-to-eat food, where they can grow and cause illness.
Keeping raw and ready-to-eat food separated helps to reduce this risk by preventing direct contact between the two types of food. This can be done by storing raw meat on the bottom shelf of a refrigerator or in a separate area from ready-to-eat food in a storage room.
While keeping the temperature at 98°F can help prevent the growth of some types of bacteria, it may not be effective in preventing contamination from other sources. Removing wrapping from food before storage and putting cardboard on the floor can also help with cleanliness and organization, but may not directly address the issue of cross-contamination.
Overall, it is important to use a combination of food safety practices to prevent contamination of food in a storage area. This includes proper storage, handling, and preparation of food, as well as maintaining a clean and organized storage environment.
In terms of electric pressure, describe a charged capacitor.
Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.
The rate of change of work with respect to time is called
1) power
2) momentum
3) energy
4)force
Answer:
Power
Explanation:
Power, by definition, is the rate of doing work (aka, work with respect to time).
Elements at the top right of the periodic table have high ionization energies
because
A. their atomic radius is small
B. these elements are high in electronegativity
D C. layers of electron shells shield the protons' attractive force
D. they have fewer electron shells to shield the protons from the
electrons
Answer:
B.) These elements are high in electronegativity
Explanation:
As you move right on the periodic table, the atoms get bigger. Atoms with more electrons have more shells. As the number of shells increase, the outermost electrons get further from the nucleus. As they get further from the nucleus, the protons have less of a hold on the electrons. This means they are more easily removed.
The elements on the top right of the table are smaller, and this means that the protons exert a greater force on their electrons. These factors make it difficult to remove their outermost electrons, increasing ionization energy.
Answer:
A. their atomic radius is small
and
D. they have fewer electron shells to shield the protons from the electrons
Explanation:
Got it right on test.
Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.
A.)What is the amplitude of the wave ? Include correct units.
B.)Use the graph to determine the time of one wave. Use it to find the frequency.
C.)If the speed of the wave is 25 m/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.
(a) The amplitude of the wave is 0.2 m.
(b) The period of the wave is 4 s.
(c) The wavelength of the wave is 100 m.
What is the amplitude of the wave?(a) The amplitude of the wave is the maximum displacement of the wave.
amplitude of the wave = 0.2 m
(b) The period of the wave is the time taken for the wave to make one complete cycle.
period of the wave = 5.5 s - 1.5 s = 4 s
(c) The wavelength of the wave is calculated as follows;
λ = v / f
where;
v is the speed of the wavef is the frequency of the wavef = 1/t = 1 / 4s = 0.25 Hz
λ = ( 25 m/s ) / 0.25 Hz
λ = 100 m
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1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.
2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.
A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed . The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time . a. What is the value of ? b. What is the y position of the cannonball at the time c. Find the initial speed of the projectile.
a) The value of t u = 140/t`b.
b) The y position of the cannonball at the time t is 55.5 mc.
c) The initial speed of the projectile is 52.4 m/s.
Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.
a. To find the value of t:Here, we have to use the formula of distance
i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`
Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is
(2H) = 2 × 55.5
= 111 m`2H/g
= 111/9.8`
= 11.32653 s
From equation (1),u×t = 140u = 140/t
Therefore, `u = 140/t`b.
b)To find the y position of the cannonball at the time t:
Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,
Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².
We have already calculated the time taken by the cannonball to hit the ground in the previous step.`
y = 140 - (1/2) × 9.8 × t²`
On substituting the value of t as `t = 11.32653`,
we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.
c) To find the initial speed of the projectile:
To calculate the initial speed of the projectile, we need to use the formula of range of projectile
.i.e.,R = u²sin2θ/g
Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)
u² = R × g/sin2θ
= 140 × 9.8/sin0°
= 2744m²/s²u
= \(\sqrt(2744m^2/s^2)\)
= 52.4 m/s
Hence, the initial speed of the projectile is 52.4 m/s.
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use equivalent ratios in higher terms to eliminate decimals from the following ratio 3.04 to 6 and ratio is ?
The equivalent ratio in higher terms to eliminate decimals from the ratio 3.04 to 6 is 76 to 150.
To eliminate decimals from the ratio 3.04 to 6, we can multiply both terms of the ratio by a common factor that will result in whole numbers.
First, let's convert 3.04 to a fraction:
3.04 = 3 + 0.04 = 3 + 4/100 = 3 + 1/25 = 75/25 + 4/100 = 76/25
Now, the ratio 3.04 to 6 can be written as:
3.04/6 = 76/25 / 6
To eliminate the decimal, we can multiply both the numerator and denominator by 25:
(76/25) * 25 / (6 * 25) = 76 / 150
Therefore, the equivalent ratio in higher terms to eliminate decimals from the ratio 3.04 to 6 is 76 to 150.
By multiplying both terms by 25, we effectively scale up the ratio to eliminate the decimal and create whole numbers. This allows us to express the ratio in higher terms without decimals. The final ratio 76 to 150 represents the same relationship as the original ratio 3.04 to 6, but in whole number form.
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Using the density- temperature graph, compare the behaviour of water density and the density of any other liquid as the temperation increases
Which explicit definition matches this sequence? an={10,if n=1an−1−4,if n>1 A. an = 10 + 4(n – 1) B. an = 10 – 4(n – 1) C. an = 4 + 10(n – 1) D. an = 4 – 10(n – 1)
Answer:
Añ=10+4(n-1)
Explanation:
The explicit definition which matches the sequence an={10,if n=1an−1−4,if n>1 } is option A that is an = 10 + 4(n – 1) . Where the value of a correct matches with the sequence.
What are sequences?Sequences are a particular set or collection of values that obey a certain criteria where repetition is allowed.The length of the sequence is called its limits. Thus a sequence can have a lower limit and upper limit.
The criteria of function of a sequence are represented in brackets '{}'. Only the values which are included within the limits are there in the set.
Given that the function of sequence is an={10,if n=1an−1−4}. As per this function, if n=1 an= 10 which means a = 10. If n >1 , then the function is an = an-1-4. That is 10n-1-4.
Option A satisfices the first condition where, an = 10 + 4n-4. Thus for n=1 the equation comes equal to 10. Not any other option satisfies this condition and thus option A is correct.
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a block of mass 5.0 kg starts at point A with a speed of 15.0 m/s on a flat frictionless surface. At point B, it encounters an incline with coefficient of kinetic friction uk 0.15. The block makes it up the incline to a second flat frictionless surface. What is the work done by friction? What is the velocity of the block at point C? The incline is 2.2m long at an angle 0=15
44.4 is the work done by friction 14.4 s the velocity of the block at point C . Correct Option a)
What is friction and example?Friction is the force that prevents solid surfaces, fluid layers, and material components from moving against each other. There are various kinds of friction.
Dry friction is the force that resists the relative lateral motion of two in touch solid surfaces. Dry friction is further classified as static friction ("stiction") between non-moving surfaces and kinetic friction ("stiction") between moving surfaces. Dry friction, with the exception of atomic or molecular friction, is caused by the interplay of surface characteristics known as asperities . Fluid friction explains the friction that occurs between sliding segments of a thick fluid.
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Full Question: In the figure below, a block of mass 5.0 kg starts at point A with a speed of 15.0 m/s on a flat frictionless surface. At point B, it encounters an incline with a coefficient of kinetic friction uk = 0.15. The block makes it up the incline to B a second flat frictionless surface. The incline is 22 m long at an angle = 15° What is the total work done in joules when the block goes from A to C and what is the speed of the block at point C in m/s? (fist value is work, second is speed) A) 44.4; 14.4 B) 44.4, -14.4 C) 14.4, 44.4 D) 44.4, 14.4 E) 44.4, 44.4
A problem says a car is initially driving 19.4 m/s due north. Which one of these tables includes that information correctly?
Answer: B
Explanation: because x is 19.4 and then the y is m/s north
Find the work done on the T-shirt by student 3. Express your answer in terms of the variables F0, G, and d, if needed.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is
Explanation:
From the question we are told that
The force exerted by student 1 is \(\vec F_1 = F_0 \^ i\)
The force exerted by student 2 is \(\vec F_2 = - 3 F_o \^ j\)
The force exerted by student 3 is \(\vec F_3 = -4F_o \^ i + G \^ j\)
The displacement of the T-shirt is \(\vec D = 2d\^ i + d\^ j\)
Generally workdone is mathematically represented as
\(W = \vec F * \vec d\)
Generally workdone is student 3 mathematically represented as
\(W_3 = \vec F_3 * \vec D\)
=> \(W_3 = -4F_o \^ i + G \^ j * [2 d \^ i + d\vec j ]\)
=> \(W_3 = -8F_o d * Gd\)
Hellooooooooooopooooooo
Answer:
Hi ??? what is your question
3) A 30 kg child slides freely across a "Slip and Slide" on LEVEL GROUND. While the child slides, the force applied to keep them sliding is 0 N. The coefficient of kinetic friction is 0.02. What is the acceleration experienced by the child?
Answer:
a = 0.1962 m/s^2
Explanation:
The magnitude of kinetic friction exerted is given by
\(F_k=\mu_kN\)
Where, μ_k= coefficient of kinetic friction= 0.02 and N = reaction force = mg
Where m= mass = 30 Kg and, g is acceleration due to gravity =9.81 m/s^2
F_k=0.02×30×9.81 =5.886 N
Now, since, there is no applied force this kinetic friction force will cause acceleration of the child
⇒ ma = F_k
here, a is the acceleration
⇒30a = 5.886
⇒ a = 0.1962 m/s^2