which of the following objects is most likely to have a mass-to-light ratio of 10? question 50 options: small group of galaxies matter around the sun the sun the milky way dense cluster of galaxies

Answers

Answer 1

The object most likely to have a mass-to-light ratio of 10 is a dense cluster of galaxies. This is because mass-to-light ratios are generally higher in such clusters, indicating a larger amount of dark matter in comparison to visible luminous matter.

The object that is most likely to have a mass-to-light ratio of 10 is a small group of galaxies. This is because a small group of galaxies contains a significant amount of dark matter, which contributes to its mass but does not emit light. Therefore, the mass-to-light ratio for a small group of galaxies would be higher compared to the other objects listed.

The object most likely to have a mass-to-light ratio of 10 is a dense cluster of galaxies. This is because mass-to-light ratios are generally higher in such clusters, indicating a larger amount of dark matter in comparison to visible luminous matter.

Matter around the Sun and the Sun itself have much lower masses and do not contain significant amounts of dark matter, so their mass-to-light ratios would be much lower. The Milky Way also has a significant amount of dark matter, but it is not as concentrated as in a dense cluster of galaxies, so its mass-to-light ratio would also be lower compared to a small group of galaxies.

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Related Questions

Need help real quick!!! Make Brainlist!!!!


I need help commenting this post, in a paragraph.

Need help real quick!!! Make Brainlist!!!!I need help commenting this post, in a paragraph.

Answers

It's not just here in the United States that we're seeing this, London has also added this category to their marathon.

How to comment?

This is an example of how society is constantly evolving and recognizing the need for inclusion and diversity. The social construction of gender and gender identity has traditionally been binary, with individuals being categorized as either male or female. However, as society has become more aware and accepting of non-binary gender identities, we are seeing a shift in the way that institutions and organizations are accommodating these individuals.

By creating a non-binary category in marathons, organizers are acknowledging the importance of inclusivity and providing a space for non-binary individuals to participate in sports without being forced to conform to binary gender categories.

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A book is on the table. If the weight of the book is 25 newtons, what is the magnitude and direction of the normal force?A.2.5 newtons in the downward directionB.2.5 newtons in the upward directionC.25 newtons in the upward directionD.25 newtons in the downward directionE.25 newtons perpendicular to the gravitational force

Answers

The normal force has a 25 N force magnitude and an upward force direction.

The force the book exerts on the table is downward-directed and equal to its weight, which is 25 N.

According to Newton's third law, every force an object A applies to an object B is balanced out by an equally strong force applied in the opposite direction to object A.

The book is object A in this instance, while the table is object B. According to Newton's third law, the table pulls on the book with a force that is both equal to and opposite to that of the force exerted by the table. As a result, the normal force's magnitude is the same as the weight of the book (25 N), while its direction is opposite.

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Which of the motion variables is the same in both thex and y axis?
A) velocity
B) acceleration
C) time
D) displacement

Answers

Answer:

Acceleration (b) not sure tho

Explanation:

The speed of sound through air is approximately 340 m/sec. What is the wavelength of a sound wave with a frequency of 706 Hz? Round to the nearest hundredth

Answers

Answer:

Wavelength  = 0.48 m (Approx)

Explanation:

Given:

Speed of sound = 340 m/s

Frequency = 706 hz

Find:

Wavelength

Computation:

Wavelength  = Speed of sound / Frequency

Wavelength  = 340 / 706

Wavelength  = 0.48 m (Approx)

PLEASE HELP!!! I have an electromagnet. If I detach the two wires from the battery and reattach them to the opposite terminals, how would that change the current and magnetic field?

Answers

Explanation:

hope it helps thanks

pls mark me as brainliest

PLEASE HELP!!! I have an electromagnet. If I detach the two wires from the battery and reattach them

If a spring has spring constant of 0.5N/m and it is stretched 0.5m , what is the force of the spring ?​

Answers

Answer:

the force of the spring will be 10n/m

What causes seasons to occur?



A) The revolution of the moon around the earth

B) The rotation of the moon around the Earth

C) The Earths tilt on its axis.

D) The moons tilt on its axis.

Answers

It’s C I hope it helps you

Answer:

C

Explanation:

I believe that it's C

A kid applies a force of 70 N to a ball over 1.1 meters. How much work did he do on the ball?

Answers

Answer:

77J

Explanation:

Not really an explanation to this, I just had this lesson last year and remembered it.

Hope I helped! ☺

When a kid applies a force of 70 Newton to a ball over 1.1 meters, then the work done by the kid would be 77 Newton meters.

What is work done?

The total amount of energy transferred when a force is applied to move an object through some distance

As given in the problems, if a kid applies a force of 70 Newton to a ball over 1.1 meters, then we have to find out the work done by the kid,

The force applied by the kid on the ball = 70 Newton

The displacement of the ball = 1.1 meters

Work done by kid    = 70 Newton×1.1 meters

                                =77 Newton meters

Thus, the work done by the kid comes out to be 77 Newton meters.

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If the angular velocity of a rotating rigid body is increased then its moment of inertia about that axis

Answers

If the angular velocity of a rotating rigid body is increased then its moment of inertia about that axis remains constant. The moment of inertia of a body is not affected by the angular velocity of the body.

Moment of inertia, also known as rotational inertia or angular mass, is a measure of the amount of mass distributed at different distances from an axis of rotation. It is a physical quantity that measures the degree of difficulty experienced by a rotational body in attaining angular acceleration under the influence of torque.

The moment of inertia, represented by I, is given by the product of mass and square of perpendicular distance of the mass from the axis of rotation. It is calculated as, I = mr²Here, m represents the mass of the body and r represents the distance between a point and axis of rotation. Therefore, the main answer to this question is that the moment of inertia of a rotating rigid body remains constant about an axis of rotation, irrespective of the angular velocity.

This is because the moment of inertia is calculated based on the geometry and mass distribution of the body, and does not depend on the rotational speed of the body.

Therefore, if the angular velocity of a rotating rigid body is increased, the moment of inertia of the body remains unchanged.

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What is an example of a wave that is not mechanical and how is it different?

Answers

Answer:

light is an example of a wave that is not mechanical .

it is different as it does not need material medium for its propagation

.2, A car starting from rest has an acceleration of
0.5m/s2, what will be its final velocity after 5
seconds? What distance will be covered by
the car at the end of 5 seconds?​

Answers

Answer: 2.5 m/s and 6.25 m

Explanation:

u = 0

a = 0.5 m/s²

t = 5 s

v = u + at

=  0 + 0.5 × 5

= 2.5 m/s

s = ut + 1/2 at²

= 1/2 × 2.5 × 5

= 6.25 m

18. A vertical spring has a length of 25cm when a 150g mass is hung from its end and its length is 30cm with 250g hanging from it. What is the spring constant? a) 19.6N/cm b) 19.6n/m c) 109.6N/m d) 19.6N/m e) 19.6N/km​

Answers

The spring constant of the spring is 19.6 N/m.

The correct answer is option D.

What is the spring constant of the spring?

The spring constant of the spring is calculated by applying the following equation as shown below.

Mathematically, the formula of Hooke's law is given as;

F = kx

where;

F is the applied forcek is the spring constantx is the extension of the spring

k = F / x

the extension of the spring when the 250 g mass was hung on it is calculated as;

x = 30 cm - 25 cm

x = 5 cm = 0.05 m

The spring constant of the spring is calculated as;

k = ( mg ) / x

where;

m is the additional mass = 250 g - 150 g = 100 g

k = ( 0.1 x 9.8 ) / ( 0.05 )

k = 19.6 N/m

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A particle enters the electric field between two oppositely charged parallel plates, as represented in the diagram below. Which particle will be deflected toward the positive plate as it enters the electric field?

Answers

Electrons are the particle will be deflected toward the positive plate as it enters the electric field.

What is an electric field?

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The field's direction is determined by the direction of the force acting on the positive charge. A positive charge produces a radially outward electric field, whereas a negative charge produces a radially inward electric field.

A physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them, is referred to as an electric field.

Hence,electrons are the particle will be deflected toward the positive plate as it enters the electric field.

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The air pressure variations in a sound wave cause the eardrum to vibrate. (a) Fora given vibration amplitude, and the maximum velocity and acceleration of the eardrum greatest for high-frequency sound of low-frequency sounds? (b) Find the maximum velocity and acceleration of the eardrum for vibrations of amplitude
1.0×10−81.0×10−8
m at a frequency of 20.0 Hz. (c) Repeat (b) for the same amplitude but a frequency of 20.0 kHz.

Answers

The maximum velocity and acceleration of the eardrum are greater for high-frequency sound compared to low-frequency sounds.The wavelength of a sound wave is inversely proportional to its frequency. The maximum acceleration is approximately 1.59×10⁻⁴ m/s².  Amplitude is 1.0×10⁻⁸.

(a) For a given vibration amplitude, the maximum velocity and acceleration of the eardrum are greater for high-frequency sound compared to low-frequency sounds.

The explanation for this can be found in the relationship between frequency and wavelength. The wavelength of a sound wave is inversely proportional to its frequency. The wavelengths of higher-frequency noises are shorter than those of lower-frequency sounds.

It oscillates when the eardrum vibrates in response to a sound wave. How swiftly the eardrum moves determines its velocity, and the acceleration is proportional to how rapidly the velocity varies.

In the case of high-frequency sound waves with shorter wavelengths, the eardrum must resonate more quickly in order to keep up with the wave's compressed and rarified regions. This results in increased speeds and accelerations of the eardrum.

Low-frequency sound waves with longer wavelengths, on the other hand, cause the eardrum to resonate more slowly, resulting in lower velocities and accelerations.

(b) To find the maximum velocity and acceleration of the eardrum for vibrations of amplitude 1.0×10⁻⁸m at a frequency of 20.0 Hz:

The maximum velocity (v_max) of the eardrum can be calculated using the formula:

v\(_{max}\) = 2πfA

Substituting the given values:

v\(_{max}\) = 2π × 20.0 Hz × 1.0×10⁻⁸ m

Calculating the value:

v\(_{max}\) = 1.26×10⁻⁶ m/s (rounded to two significant figures)

The maximum acceleration (a\(_{max}\)) of the eardrum can be found using the relationship: a\(_{max}\) = (2πf)²A

Substituting the given values:

a\(_{max}\) = (2π × 20.0 Hz)² × 1.0×10⁻⁸ m

Calculating the value:

a\(_{max}\) = 1.59×10⁻⁴ m/s² (rounded to two significant figures)

Therefore, for vibrations of amplitude 1.0×10⁻⁸ m at a frequency of 20.0 Hz, the maximum velocity of the eardrum is approximately 1.26×10⁻⁶m/s, and the maximum acceleration is approximately 1.59×10⁻⁴ m/s².

(c) To repeat the calculation for the same amplitude (1.0×10⁻⁸ m) but a frequency of 20.0 kHz:

Using the same formulas as before, we can calculate the maximum velocity and acceleration:

v\(_{max}\) = 2πfA

v\(_{max}\) = 2π × (20.0 × 10³ Hz) × 1.0×10⁻³ m

Calculating the value:

v\(_{max}\) = 1.26 m/s (rounded to two significant figures)

a\(_{max}\) = (2πf)²A

a\(_{max}\) = (2π × (20.0 × 10³ Hz))² × 1.0×10⁻⁸ m

Calculating the value:

a\(_{max}\) = 1.59 × 10⁶m/s² (rounded to two significant figures)

Therefore, for vibrations of amplitude 1.0×10⁻⁸.

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An asteroid falls from the sky and exerts 882 N of force on Earth's ground. How much force does it exert on Mars if the gravity on mar is 3.7m/s??

An asteroid falls from the sky and exerts 882 N of force on Earth's ground. How much force does it exert

Answers

Answer:

333N

Explanation:

=>First you have to find the mass of the asteroid.

so 882N÷9.8m/s²=90Kg

then,multiply it by Mars's gravity

=>90Kg*3.7m/s²=333N

Starting from rest, a car takes 2.4s to travel 15m. Assuming a constant acceleration, how long will it take the car to travel the next 15m?

Answers

Answer:

T = 2.4 + 2.4 = 4.8 [s]

Explanation:

In order to solve this problem, we must use the following kinematics equation and calculate the acceleration value.

\(x=x_{o} +v_{o}*t+(\frac{1}{2})*a*t^{2}\)

Vo = inital velocity = 0

x - xo = 15 [m]

t = time = 2.4 [s]

15 = 0.5*a*(2.4)^2

a = 5.208 [m/s^2]

We can use the same equation to find the time.

30 = 15 + 0.5*(5.208)*t^2

t = 2.4 [s]

T = 2.4 + 2.4 = 4.8 [s]

How would you investigate the relationship between surface-type and frictional force? list the specific steps you would need to take to fully test the relationship between these variables.

Answers

To investigate the relationship between surface-type and frictional force, the steps to be followed are Identify the variables, Select a range of surface types, Prepare the materials, Set up the experiment, Conduct trials, Analyze data and Draw conclusions.

Here's a step-by-step guide:

1. Identify the variables: In this case, the independent variable is the surface-type, while the dependent variable is the frictional force.

2. Select a range of surface types: Choose various surface types, such as smooth (e.g., glass), moderately rough (e.g., wood), and rough (e.g., sandpaper) to test the relationship.

3. Prepare the materials: Gather a flat, rectangular object to slide across the surfaces, a spring scale or force sensor to measure the frictional force, and a device to ensure consistent angle and speed for each trial.

4. Set up the experiment: Lay each surface-type horizontally on a sturdy table. Attach the spring scale or force sensor to the flat object and ensure that the pulling angle and speed remain consistent for each trial.

5. Conduct trials: For each surface type, pull the flat object using the spring scale or force sensor at a consistent speed and angle, and record the frictional force measurements. Perform multiple trials for each surface to account for any discrepancies and improve the accuracy of your results.

6. Analyze data: Calculate the average frictional force for each surface type and create a table or graph to display your findings.

7. Draw conclusions: Based on the data, determine if there's a relationship between surface-type and frictional force. Observe any trends in your results, such as an increase in frictional force with rougher surfaces.

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At t = 3 seconds, what is the velocity of the object

At t = 3 seconds, what is the velocity of the object

Answers

Answer:

NO ANSWER

Explanation:

there is no tragectory or diagram given

WHICH OBJECT?

A ball is thrown vertically upward with a speed of 18m/sec from the edge of 85m tall building.
a. What is the maximum height in which the ball reached from the ground?
b. How much later it took the ball to reach the ground?
c. What is the final velocity of the ball as it hits the ground?

Answers

Answer:

Explanation:

Using the formula to calculate the maximum height

H = u²/2g

u is the initial velocity = 18m/s

g is the acceleration  due to gravity  = 9.81

H = 18²/2(9.81)

H = 324/19.62

H = 16.51m

The maximum height in which the ball reached from the ground = 85m + 16.51m = 101.5m

b) Time of fight = 2u/g

T = 2(18)/g

T = 36/9.81

T = 3.67s

It took the ball 3.67s later to reach the ground

3) To get the final velocity of the ball as it hits the ground, we need to calculate the horizontal component of the velocity,

Ux = Ucosθ

ux = 18cos 90 (angle of launch is 90 since the ball is thrown vertically upwards)

Ux = 18(0)

Ux = 0m/s

Hence the final velocity of the ball as it hits the ground is 0m/s

If the equally massive railroad cars A and B stick together after an inelastic collision, how does their speed after the collision compare with the initial speed of car A?

Answers

Their speed will be  half the initial speed of car A.

what is speed?

The speed of an item, which is a scalar quantity, is the size of the change in its location over time or the size of the change in its position per unit of time.

what is collision?

Any situation in which two or more objects exert forces on one another quickly is referred to as a collision. The scientific definition of the word "collision" makes no reference to the magnitude of the force involved, despite the fact that the most frequent usage of the word relates to instances in which two or more objects clash violently.

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Suppose a blanket has a sock stuck to it due to static electricity. When you pull the sock off of the blanket, what happens to the potential energy between them?

Answers

Explanation:

When you pull the sock off of the blanket, the socks gain electrons out of blanket. This makes socks slightly negatively charged. The potential energy of the socks rise whereas potential energy of the blanket reduces. This happens because of exchange of electrons between socks and blanket.

A bumper car with a mass of 86 kg is traveling at 3.6
m/s. A bumper car with a mass of 98 kg is traveling at
1.6 m/s in the opposite direction. After the collision, the
86 kg bumper car travels at -0.5 m/s. What is the speed
of the 98 kg bumper car after the collision?

Answers

Answer:

2.0 m/s

Explanation:

i found it on quizlet

Use DeMorgan's Theorem, as well as any other applicable rules of Boolean algebra, to simplify the following expression so there are no more complementation bars extending over multiple variables: \[ \

Answers

The expression to be simplified is, A + BC + ABCD. Using De Morgan's theorem, we can convert complementation bars extending over multiple variables into complementation bars over single variables. The De Morgan's theorem states that the complement of a product is equal to the sum of complements. De Morgan's Theorem:

 1.   (AB) = A + B2.  (A + B) = A B The steps to simplify the given expression using De Morgan's theorem are as follows: A + BC + ABCD = A + (BC + ABCD) = A + (BC). (ABCD) = A + (B + C) (A + B + C + D) = A + AB + AC + BC + BD = A + AC + BC + BD.

Hence, the simplified expression is A + AC + BC + BD. Thus, using DeMorgan's Theorem and other applicable rules of Boolean algebra, the given expression is simplified to A + AC + BC + BD.

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Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is________________. the same. greatest to the left of the charge. greatest below the charge. greatest to the right of the charge. greatest above the charge.

Answers

Electric field strength decreases as the distance from the source increases.

How the distance from the charge affects the magnitude of the electric field?

The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.

So we can conclude that Electric field strength decreases as the distance from the source increases.

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Two cars are driving at the same velocity, but one has twice the mass of the other. Is the mechanical kinetic energy of the larger car two times, three times, or four times that of the smaller car

Answers

Answer:

The kinetic energy of the larger car is two times that of the smaller car

Explanation:

Kinetic Energy

Is the energy an object has due to its state of motion. It's proportional to the square of the speed.

The equation for the kinetic energy is:

\(\displaystyle K=\frac{1}{2}mv^2\)

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

It's required to compare the kinetic energy of two cars K1 and K2. Car 2 has twice the mass of car 1: m2=2m1, and they have the same speed.

The kinetic energy of car 1 is:

\(\displaystyle K_1=\frac{1}{2}m_1v^2\)

The kinetic energy of car 2 is:

\(\displaystyle K_2=\frac{1}{2}m_2v^2\)

Substituting the relation of the masses:

\(\displaystyle K_2=\frac{1}{2}(2m_1)v^2\)

Rearranging:

\(\displaystyle K_2=2\left(\frac{1}{2}m_1v^2\right)\)

Substituting the kinetic energy of car 1:

\(\displaystyle K_2=2K_1\)

The kinetic energy of the larger car is two times that of the smaller car

A marble is rolling across a smooth 1.2 m tall table at a velocity of 3 m/s. How far from the edge of the table does it land? (SHOW ALL OF YOUR WORK)

Answers

Answer:

S = 1/2 g t^2      where t is the time to fall 1.2 m

t = (2 S / g)^1/2 = (2 * 1.2 / 9.8) = .495 s

Sy = Vy T = 3 m/sec  * .495  sec = 1.48 m     distance from edge of table

(Rotational speed has no effect since table is smooth)

what is the maximum allowable length for float glass jalousies

Answers

The maximum allowable length for float glass jalousies is 150 cm.

What is Float Glass?

Float glass refers to a type of glass that is made by floating molten glass on a bed of molten metal. Float glass is a popular type of glass because it is both strong and durable.

Float glass is often used in windows, mirrors, and other applications where high-quality glass is required.

What is a Jalousie?

A jalousie is a type of window that consists of a series of parallel glass panes that are set in a frame. Jalousies are typically designed to allow air to flow through them, which makes them ideal for use in hot climates where ventilation is important.

What is the maximum allowable length for float glass jalousies?

The maximum allowable length for float glass jalousies is 150 cm. This means that any jalousies that are made from float glass cannot exceed this length. This limit is in place to ensure that the glass is strong enough to support itself and to prevent it from breaking under its own weight.

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Write a short skit/story about a member of the school choir or band being bullied by two cheerleaders who are jealous of her voice. Show what you would do as a bystander to help

Answers

I was walking down the halls rushing to class. I had to get there quickly or else I would be late little did I know what I was about to witness. Before turning the corner to go to the stairs I heard singing and I immediately thought that this person had a beautiful voice. But the next thing that happened was unbelievable, I saw two cheerleaders going to the stairs they stopped and started at the person who was singing. They stopped singing and got startled and then the girls looked her up and down and started saying she sung horribly and that she dressed horribly as well. They kept laughing at her and they even grabbed her folder and started throwing the papers she had in it everywhere. I knew this was wrong so I went to get a teacher and told her what was happening. We caught the two girls on time and they got in trouble and had to apologize. They even said that they only bullied her because they were jealous and that they were so sorry. The girl thanked me and I told her that her voice was amazing and that if anyone gives her trouble again to get help.





( you can change anything if you want I kinda rushed it so it may not be aMazingg)

the speed of sound in water at a temperature of 25°c is 1500 m/s. what is the wavelength of a 300 hz sound wave traveling through water at a temperature of 25°c?

Answers

Answer:

The speed of sound in water at a temperature of 25°C is 1500 m/s. We can use the formula:

wavelength = speed of sound / frequency

where frequency is given as 300 Hz.

wavelength = 1500 m/s / 300 Hz

wavelength = 5 meters

Therefore, the wavelength of a 300 Hz sound wave traveling through water at a temperature of 25°C is 5 meters.

Explanation:

There is some ice at the beginning of the time interval, but all of the ice disappears before the end of the interval.

There is some ice at the beginning of the time interval, but all of the ice disappears before the end

Answers

This statement suggests that the ice undergoes a phase change from solid to liquid, indicating heat transfer.

If 500 g of ice at -10°C is added to 1000 g of water at 50°C, how much ice melts and what is the final temperature of the mixture?

All of the ice will melt, and the final temperature of the mixture will be 10°C.

What would happen if the surroundings were at a temperature lower than the ice during the time interval?

If the surroundings were at a lower temperature than the ice, heat would flow from the ice to the surroundings, causing the ice to freeze instead of melt.

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