Which of the following organisms contributes to the production of soil on a newly formed area of land during primary succession?

Answer:

Populations with high levels of genetic diversity are more likely to have individuals with traits that help them survive if conditions change.

Explanation:

Answer:

It is called "Gastric Mill" They have 3 stomachs

Explanation:

The teeth are part of a system called the “gastric mill.” Through rhythmic movements of these large teeth, of which there are three, their stomachs can actually crush food as a prelude to further digestion.

The statement, "the world's natural resource base—the air, water, soil, minerals, and so forth—is essentially finite, or bounded" is true.

A natural resource is a useful or valuable resource that comes from nature. Natural resources include air, water, minerals, soil, animals, and plants, among other things. We depend on natural resources to meet our fundamental needs like shelter, food, and clothing. Natural resources are required for economic growth, health, and social well-being, among other things. However, these resources are not infinite or unlimited in supply.

As a result, the world's natural resource base—the air, water, soil, minerals, and so forth—is essentially finite, or bounded. These finite natural resources are becoming increasingly scarce as the population grows and human demands on natural resources increase. Therefore, the statement, "the world's natural resource base—the air, water, soil, minerals, and so forth—is essentially finite, or bounded" is true.

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Answer:i believe its Biomass sources receive their energy from the sun while living.

Explanation: not sure, but if you research why, it makes the most sense.

Answer:

The sun is what keeps all life on earth alive, the answer from what im guess are choices is: "Biomass sources receive their energy from the sun while living."

Hope this answer was good enough. <3

Answer:

Alec jefferis developed DNA fingerprinting.

Answer: An Autotroph

Explanation: Organisms that can produce their own food using light, water, carbon dioxide, or other chemicals are called Autotrophs.

Answer:

Autotrophs

Explanation:

An autotroph makes its own food using light, water, carbon dioxide, and other chemicals.

Answer:

i believe the basketball falling from the net

Explanation:

Answer:

Thylakoids

Explanation:

If the levels of 285, 185, and 5.85 ribosomal RNAs are depleted, while the level of 55 ribosomal RNA remains normal, the RNA polymerase responsible for transcribing these ribosomal RNAs is likely to be RNA polymerase I.

RNA polymerase I is responsible for transcribing ribosomal RNA genes, including the genes encoding 285, 185, and 5.85 ribosomal RNAs. It specifically transcribes the large precursor rRNA (pre-rRNA) that undergoes processing to generate mature ribosomal RNAs. If there is a defect in RNA polymerase I, it would lead to reduced or depleted levels of these ribosomal RNAs.

On the other hand, RNA polymerase III is responsible for transcribing 5S rRNA, which is a component of the 55 ribosomal RNA. Since the level of 55 ribosomal RNA is normal in the examined cells, it suggests that RNA polymerase III is not affected.

In summary, if the depletion of 285, 185, and 5.85 ribosomal RNAs is observed while the level of 55 ribosomal RNA remains normal, the most likely affected RNA polymerase is RNA polymerase I, responsible for transcribing the larger ribosomal RNA genes.

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seven (7)

Explanation:

The pure water has a pH value 7 because it is neutral

Answer: it is 7

Explanation:

I took the test and got it right

High blood pressure can place increased pressure on the walls of the blood vessels inside the brain, increasing your chances of developing an aneurysm. Also, it forces the heart to work harder to pump blood to the rest of the body. This causes the lower left heart chamber (left ventricle) to thicken. A thickened left ventricle increases the risk of heart attack, heart failure and sudden cardiac death. Moreover, blood vessels damaged by high blood pressure can narrow, rupture or leak. High blood pressure can also cause blood clots to form in the arteries leading to the brain, blocking blood flow and potentially causing a stroke.

So the correct answer is: All of thees choices are correct.

Best Explanation of Evolutionary Advantages of Habituation: Option B - Habituation allows an animal to tune out unimportant stimuli and focus on things that are essential to survival or reproduction.

1. Habituation refers to the process by which an animal becomes accustomed to a repeated or constant stimulus and gradually reduces or eliminates its response to that stimulus.

2. Option A suggests that habituation improves an animal's odds of survival because the habituated animal will not waste energy investigating novel objects. While this may be true to some extent, it does not fully explain the evolutionary advantages of habituation.

3. Option B states that habituation allows an animal to tune out unimportant stimuli and focus on things that are essential to survival or reproduction. This explanation aligns with the concept of selective attention, where an animal can prioritize relevant information and ignore irrelevant or non-threatening stimuli. By filtering out non-essential stimuli, the animal can allocate its limited resources more efficiently, such as energy and attention, towards activities that directly contribute to its survival or reproductive success.

4. Option C proposes that habituation enables an animal to generalize from bad experiences and avoid similar situations in the future. While this can be a potential advantage of habituation, it does not fully capture the evolutionary benefits of the process.

5. Option D suggests that an animal that becomes habituated to a stimulus learns from repeated exposure that positive outcomes, such as food, are associated with the stimulus. While this may be true in some cases, it does not encompass the broader advantages of habituation in terms of selective attention and efficient resource allocation.

In conclusion, option B provides the best explanation for the evolutionary advantages of habituation as it highlights the ability of animals to filter out unimportant stimuli and prioritize essential information for survival and reproduction.

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Answer: Most soil organisms function best at the same temperatures people are comfortable at, or more specifically, in the 70s or low 80s F.

Answer:

Nucleus

Explanation:

The nucleus controls all of the cell's activities, such as growth and metabolism, using the DNA's genetic information.

Answer:

you can learn many things from them

Explanation:

scientists are able to examine, that volcanoes remove much of the earth's trapped heat when volcanoes erupt. Volcanoes also make new islands and scientists love to observe their habitats and the animals that inhabit them

Answer:A

Explanation:it makes sense

The correct option is d ;The population will decrease as it gets stable over a period of time.

If a species' population surpasses its carrying capacity, the ecosystem may become unfit for survival. If the population outnumbers the carrying capacity for an extended length of time, resources may be destroyed totally. If all resources are depleted, populations may perish.

The carrying capacity refers to the maximum population the ecosystem or the environment is able to carry or hold on to. This refers to the max population that can be sustained in the ecosystem and is population dynamics can be modeled from the logistic function. The more the number of species the fewer chances are in their survival as they have reached stability.

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The complete question is :

which of the following is expected to happen to a species' population when resources are stable over a long period of time and the species have reached carrying capacity?(1 point)

A responses the population will die out.

B  the population will die out. the population will increase.

C the population will increase. the population will decrease.

D the population will decrease. the population will stay the same.

Answer:

Carbohydrate is a big source of energy for all living organism on this planet.

Explanation:

The carbohydrate which is a macro-molecule is produced by the producer such as trees and shrubs etc in the process of photosynthesis. These carbohydrates transfer to the primary consumer such as monkey who eat these plants. When the secondary consumer such as jaguar  eat these primary consumer, this carbohydrate again transfer from one organism to another organism. This carbohydrate is a source of energy which is broken down in the stomach into glucose and this glucose is absorbed by the cells and releases energy by mitochondria in the form of ATP. This energy is used in various activities such as walking, running and breathing etc. Carbohydrate, proteins and fats are the examples of macro-molecules.

Answer:

hi

Explanation:

Using your answers from Part 2, trace the path that energy flows in the ecosystem. What evidence does this give you about where energy in an ecosystem comes from?

Answer:

When temperature and wind speed are constant, but humidity increases, the rate of evaporation will decrease. When wind speed and humidity stay constant, and temperature increases, then the rate of evaporation will increase because warmer air can hold more water vapor than colder air.

Answer:

if the rate of evaporation reduces water cylcle will stops and amount of water present in the world will be increase.humifity will be more.

Answer: The answer for Label O is: Organic material. Label A is: topsoil. Label B is: subsoil. Label C is: weathered rock

Explanation:

I hope this helped answer your question and I'm sorry if it didn't help

Answer: O: organic material A: topsoil B: subsoil C: weathered rock

Explanation: Credit to the person above or below me

Answer:The progress of science is the continuous accumulation of knowledge through observation, experimentation, and theory. It involves developing theories, using advanced technology, collaborating across disciplines, and rigorous peer review. Paradigm shifts and breakthrough discoveries challenge existing theories. Science's impact is seen through practical applications in medicine, technology, and other fields, improving our quality of life. It is an iterative process that refines our understanding of the natural world.

Explanation:

Answer:

Cancer

Explanation:

It might be said that a genetic mutation that causes abnormal cells that reproduce and divide rapidly, might lead to a cancer. this is associated with an uncontrolled cell growth in a multicellular organism.

(This is an comfirmation for the answer above )

Answer: fossil molds

Explanation: fossil molds are the most common molds formed

when buried remains of plants and animals decompose or dissolve leaving a space in the rock. these spaces may preserve the texture of remains.

Cell biology: Parts of the cell, Prokaryotic and Eukaryotic Cells.

The Eukaryotic cells are those that have their genetic material within a nucleus. There are three basic types of eukaryotic cells based on their structure: plant cells, animal cells, and fungal cells.

Some of the distinct characteristics of plant cells are:

• The presence of a, cell wall ,composed of ,cellulose, hemicellulose, and pectin,, gives extra protection and support to the cell, and it helps to maintain the shape of the cell.

• Special pathways of communication are called ,plasmodesmata,, which go through the cell wall.

• A large central, vacuole,, that serves as, storage, of water and other substances.

• Chloroplasts,, ,produce sugars, using the carbon dioxide available and the energy of sunlight.

They also have other structures common to all eukaryotic cells, such as mitochondria and Golgi apparatus.

Now let's compare this information to the statements:

• Statements a ,and ,b, are, false ,because is the chloroplast that makes sugar using sunlight

• Statement c is true,, because the vacuole stores many substances, and plant cells also have mitochondria to break down sugar.

• Statement d is true, because plants and animal cells are two types of eukaryotic cells, and this means they have a nucleus.

Answer:

Experiments involving the cloning of DNA encoding for a low LD50 toxin or work with vectors that express toxins with a low LD50 (less than 100 nanograms per kilograms body weight) fall under Section III-F-2 of the NIH Guidelines for Research Involving Recombinant or Synthetic Nucleic Acid Molecules. This section states that experiments involving the cloning of DNA encoding for a low LD50 toxin or work with vectors that express toxins with a low LD50 pose extreme biosafety risks, and must be conducted in the highest level of containment (BSL-4).

The cloning of DNA encoding for a toxin with a low LD50 falls under Section III-D-4 of the NIH guidelines. This section outlines provisions for research involving dangerous biological agents. Lower LD50 values indicate higher toxicity levels.

Experiments involving the cloning of DNA encoding for a toxin with a low LD50, or work with vectors that express such toxins, fall under the Section III-D-4 of the NIH guidelines. This section is specifically for research involving dangerous biological agents. The LD50 or Lethal Dose 50% measure is used to denote the lethal dose of a substance which can kill 50% of a test population. It's mainly a measure of a substance's toxicity.

A lower LD50 value refers to a higher toxicity level because it requires a smaller amount to cause harm. Therefore, if you're working with vectors that can express toxins with an LD50 of less than 100 nanograms per kilogram body weight, you're working with a highly toxic material, and your experiments must strictly adhere to the guidelines under Section III-D-4 of the NIH Guidelines.

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During the catabolism of glycogen, the glycogen phosphorylase enzyme breaks the option c- c) α‑1,4 linkages, but not the α‑1,6 linkages.

During the catabolism of glycogen, the glycogen phosphorylase enzyme breaks the α-1,4 linkages between glucose residues in the glycogen molecule. However, it cannot break the α-1,6 linkages present at the branch points of the glycogen molecule.

Therefore, the correct answer is: c) α-1,4 linkages, but not the α-1,6 linkages.

Glycogen phosphorylase is an enzyme that catalyzes the breakdown of glycogen to release glucose-1-phosphate. It cleaves the α-1,4 linkages between glucose residues by adding a phosphate group from inorganic phosphate to the C1 carbon of glucose, forming glucose-1-phosphate.

This process continues until a point of four glucose residues remaining on a branch.

At the branch points of glycogen, there are α-1,6 linkages that hold the glucose residues together. These branch points are cleaved by another enzyme called α-1,6 glucosidase, also known as debranching enzyme.

The debranching enzyme first moves three glucose residues from the branch to the non-reducing end of another chain by breaking the α-1,4 linkage. It then cleaves the α-1,6 linkage, releasing a free glucose molecule and the remaining glucose chain.

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During the catabolism of glycogen, the glycogen phosphorylase enzyme breaks the option c- c) α‑1,4 linkages, but not the α‑1,6 linkages.

During the catabolism of glycogen, the glycogen phosphorylase enzyme breaks the α-1,4 linkages between glucose residues in the glycogen molecule. However, it cannot break the α-1,6 linkages present at the branch points of the glycogen molecule.

Therefore, the correct answer is: c) α-1,4 linkages, but not the α-1,6 linkages.

Glycogen phosphorylase is an enzyme that catalyzes the breakdown of glycogen to release glucose-1-phosphate. It cleaves the α-1,4 linkages between glucose residues by adding a phosphate group from inorganic phosphate to the C1 carbon of glucose, forming glucose-1-phosphate.

This process continues until a point of four glucose residues remaining on a branch.

At the branch points of glycogen, there are α-1,6 linkages that hold the glucose residues together. These branch points are cleaved by another enzyme called α-1,6 glucosidase, also known as debranching enzyme.

The debranching enzyme first moves three glucose residues from the branch to the non-reducing end of another chain by breaking the α-1,4 linkage. It then cleaves the α-1,6 linkage, releasing a free glucose molecule and the remaining glucose chain.

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