Answer:
I think c
Explanation:
hope that helps
The four particles as connected by rods of negligible mass as fig below. if the origin is the canter of rectangle and the system rotates in the XY plane about the Z axis with an rad angular speed of 12. calculate S a) The moment of inertia of the system about Z axis and b) The rotational kinetic energy of the system 3.00 kg 2.00 kg y(m) 2.00 kg 6.00 m 4.00 kg ---x(m)
The moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.
The moment of inertia of a system about its axis of rotation is the sum of the products of the masses of its constituents and the square of their respective distances from the axis of rotation.
The radius of the rectangular plate is 6 m, and the distance of each particle from the center is half of the sides of the rectangle, which are 4 m and 3 m.
Therefore, using the parallel axis theorem, we get the moment of inertia of the system about the Z-axis as shown below.
\(Iz = ICM + MR^{2}\)
(1)We can obtain the moment of inertia of the rectangle about its center as: \(ICM = (1/12) ML^{2}\)
(2) where M is the mass of the rectangle, and L is the length of the rectangle.
Substituting values, we get: ICM = \((1/12) $\times$ 3.00 $\times$ (4^{2} + 6^{2} )\)
ICM = \(5 kg m^{2}\)
Using the parallel axis theorem, the moment of inertia of the four particles about the center of the rectangle is:
\(IP = 4 $\times$ [(1/12) $\times$ 2.00 $\times$ (4^{2} + 3^{2})] + 2.00 $\times$ (3^{2}) + 4.00 $\times$ (4^{2})IP = 97 kg m^{2}\)
The moment of inertia of the system about Z-axis is: \(Iz = ICM + MR^{2} Iz = 5 kg m^{2} + 3.00 kg $\times$ (6^{2} ) + 4 $\times$ [(4^{2}+ 3^{2} )/4] Iz = 245 kg m^{2}\)
The kinetic energy of a rotating body is given as:\(K.E. = (1/2) I\omega^{2}\) where I is the moment of inertia of the system, and ω is the angular velocity of the system.
The rotational kinetic energy of the system is:\(K.E. = (1/2) I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)
2)\(I\omega^{2} K.E. = (1/2) $\times$ 245 $\times$ (12)^{2} K.E. = 21168 J\)
Therefore, the moment of inertia of the system about the Z-axis is 245 kg m², and the rotational kinetic energy of the system is 21168 J.
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Why do you think the Founders divided the process into two steps (impeachment and conviction)?
The impeachment process is described in Article I of the United States Constitution. Impeachment is the process by which senior political officials of the government can be removed from office, for reasons of treason, bribery or serious misconduct in the exercise of their functions.
The first step in this process is carried out by the House of Representatives, which is in charge of determining the origin of the impeachment, assessing the grounds and evidence that allow or not to prosecute the politician in question through a simple majority vote. Then, the Senate is in charge of the trial itself, determining the guilt or not of the official.
Ur pfp cute no cap
The Founders divided the process into two steps which are impeachment
and conviction to ensure the affected person has a fair judgement and
subsequent trial.
The house of representatives are in charge of the impeach process if an
office holder commits an offence in which impeachment can suffice. The
members of the house of representatives vote and the office holder is
impeached if the majority vote in that direction.
The Senate then takes over and the person faces trial and the judgement is
passed according to the available evidences.
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An object is dropped from a height of 100m. What height above the ground is the object when it has a speed of 25m/s? (g = 9.8)
Given,
The height from which the object was dropped, h=100 m
The speed of the object, v=25 m/s
The acceleration due to gravity, g=9.8 m/s²
The object will have only potential energy when it is at rest at the height of 100 m. As the object falls it will slowly lose its potential energy. The potential energy thus lost will be converted into the kinetic energy of the object.
Thus the potential energy lost by the object when it has a speed of 25 m/s will be equal to its kinetic energy at that instant.
Therefore,
\(\begin{gathered} mg(\Delta h)=\frac{1}{2}mv^2 \\ \Rightarrow\Delta h=\frac{v^2}{2g} \end{gathered}\)Where Δh is the change in the height of the object or the height through which the object has fallen at that instant.
On substituting the known values,
\(\begin{gathered} \Delta h=\frac{25^2}{2\times9.8} \\ =31.89\text{ m} \end{gathered}\)Thus the height of the object above ground is,
\(\begin{gathered} l=h-\Delta h \\ =100-31.89 \\ =68.11\text{ m} \end{gathered}\)Thus the height of the object above the ground when it has a speed of 25 m/s is 68.11. m
Suppose a grower sprays (2.2x10^1) kg of water at 0 °C onto a fruit tree of mass 180 kg. How much heat is released by the water when it freezes?
There is no temperature change which drives heat flow, thus no heat will be released by the water.
Heat released by the water when it freezesThe heat released by the water when it freezes is calculated as follows;
Q = mcΔФ
where;
m is mass of waterc is specific heat capacity of waterΔФ is change in temperature = Фf - ФiInitial temperature of water, Фi = 0 °C
when water freezes, the final temperature, Фf = 0 °C
Q = 22 x 4200 x (0 - 0)
Q = 0
Since there is no temperature change which drives heat flow, thus no heat will be released by the water.
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Example No. 10
In a worst-case design scenario, a 2000 kg elevator with broken cables is
falling at 8.0 m/s when it first contact a cushioning spring at the bottom
of the shaft. The spring is supposed to stop the elevator, compressing 3.0
m as it does so. Determine what the force constant of the spring should
be.
The force constant of the spring is determined as 14,222.2 N/m.
Force constant of the springApply the principle of conservation of energy,
K.E = U
where;
K.E kinetic energy of the elevatorU is elastic potential energy of the spring¹/₂mv² = ¹/₂kx²
mv² = kx²
k = mv²/x²
Where;
m is mass of the elevatorv is speedx is compression of the springk = (2000 x 8²)/(3²)
k = 14,222.2 N/m
Thus, the force constant of the spring is determined as 14,222.2 N/m.
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What is the momentum of a 2000 kg truck traveling at 35 m s?
Momentum of the truck will be 70000 kg-m/s
Momentum can be defined as the impulse gained by a moving object.
Also it can be defined as the product of mass of the object with the velocity by which it is moving.Momentum can only be calculated when the body is in motion.The SI unit for momentum is kg-m/sIt is a vector quantity and has the direction same as that of the velocity of the object.It is represented by M and mathematically, M = Mass * VelocityMass of the truck = m = 2000 kg
Velocity of the truck = v = 35 m/s
Momentum = M = m * v
M = 2000 * 35
M = 70000 kg-m/s
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Write the equation in standard form for the circle with center (3,10) and radius 2. hxhtojuqat ,
The standard form equation for the circle with center (3, 10) and radius 2 is: \(\rm 2.x^{2} + y^{2} - 6x - 20y + 105 = 0.\)
What are the seven components of a circle?The radius, diameter, circumference, arc, chord, secant, tangent, sector, and segment are all parts of a circle.
A circle is a round figure with no corners or edges. A circle is a closed shape, a two-dimensional shape, and a curved shape in geometry.
A circle with center (h, k) and radius r has the following standard form equation:
\(\rm (x-h)^{2} + (y-k)^{2} = r^{2}\)
Substituting the values of center and radius:
\(\rm (x-3)^{2} + (y-10)^{2} = 2^{2}\)
Simplifying the equation:
\(\rm x^{2} - 6x + 9 + y^{2} - 20y + 100 = 4\)
\(\rm x^{2} + y^{2} - 6x - 20y + 105 = 0\)
\(\rm x^{2} + y^{2} - 6x - 20y + 105 = 0\)
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which simple machines make up a wheel barrow
Answer:
a lever and a wheel and axle (i guess)
Explanation:
don't have any
A teacher took two latex balloons and blew them up with helium gas to the same size. She took one and labeled it Balloon A and placed it in a -15o C freezer. The second one she labeled BALLOON B, and she took it outside and tied it to the railing in the sun on a 30o C day. After a half hour, she had the students measure the circumference of each balloon. Which TWO outcomes do you predict the students will find and why?
Answer:
n
Explanation:
TWO outcomes can be predicted the students will find:
The size of balloon A becomes smaller.The size of balloon B becomes larger.What is the relation between temperature and volume of the gases?When a constant mass of gas is cooled, its volume falls, and when the temperature is raised, its volume grows. The volume of the gas rises by 1/273 of its initial volume at 0 °C for every degree of temperature rise.
In layman's words, the volume of a fixed mass of gas is exactly proportional to temperature at constant pressure.
The teacher took two latex balloons and blew them up with helium gas to the same size. As she placed Balloon A in a -15° C freezer, its temperature decreases and that's why, the size of balloon A becomes smaller. Again she placed Balloon B in the sun on 30° C day, its temperature increases and that's why, the size of balloon B becomes larger.
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What will make it hard to remember that blood is an organ?
A - it is red
B - it has parts
C - it is a liquid
D - it moves
Answer:
C . it is a liquid
hope it helps you
What is the electric field strength at a distance of 0.9 m from a charge of 5.71 x 10^-6 C?
Given:
\(\begin{gathered} Q=5.71\times10^{-6}\text{ C} \\ r=0.9\text{ m} \end{gathered}\)The electric field strength is given as,
\(E=\frac{KQ}{r}\)Here, K is the electrostatic constant.
Putting the values,
\(\begin{gathered} E=\frac{9\times10^9\times5.71\times10^{-6}}{(0.9)^2} \\ =63444.44\text{ N/C} \end{gathered}\)Therefore, the electric field strength is 63444.44 N/C.
The energy transfer diagram represents the energy of a light bulb.How much electrical energy is involved in this transformation?60 J80 J100 J 120 J
Answer:
j120
Explanation:
qll energy for residential is 120 and that's what ruffly is always used for wiring
The specific heat of acetic acid is 2.07 J/gºC. If 1150 J of heat is
added to a 45.0 g sample of acetic acid, the temperature of the
sample would increase by how much? ___ ºC
Answer:
12.3 °C
Explanation:
Q=m*Cp*ΔT-->
1150=45*2.07*ΔT-->
ΔT=1150/93.15-->
ΔΤ=12.3 °C
A 4-stroke heat engine in an automobile is
used to
A convert mechanical energy into heat
energy.
B convert heat energy into mechanical
energy.
с convert steam into solar energy.
D convert chemical energy into electrical
energy.
Answer:
b
Explanation:
convert heat energy into mechanical
Callisto is a moon of Jupiter
(mass= 1.90 x 1027 kg), which orbits
the planet with a period of 16.9 days.
What is the radius of its orbit?
[?] x 10¹ m
Coefficient (green)
Exponent (yellow)
Enter
8.27 x 1013 meres is the orbital radius.
Additional details:-Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution
The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.
6.67 x 10⁻¹¹ N/m²kg
2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7
What distinguishes Callisto, a huge moon orbiting Jupiter, from all other large moons in the solar system?The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.
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Why does the shape of the lens in your eye change?
The Lens Changes Shape to Focus Near Objects. Light rays from objects that are close to the eye are not parallel. Therefore, the eye must bend them more in order to focus the rays on the retina. To accomplish this, the lens change shape.
Hope this helps
Answer:
to focus the light
an alcohol thermometer is preferred for a very cold region why
Answer:
freezing point of alcohol is - 117°C. So, it can measure the temperature of the very cold region.
Explanation:
Alcohol thermometer is preferred for a very cold region because its freezing point of alcohol is - 117°C. So, it can measure the temperature of the very cold region.
A 1500 kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2500 kg SUV traveling from east to west. The two cars become enmeshed due to the impact and slide as one thereafter. On-the-scene measurements show that the coefficient of kinetic friction between the tires of these cars and the pavement is 0.750, and the cars slide to a halt at a point 5.48 m west and 6.37 in south of the impact point. How fast was sedan traveling just before the collision? How fast was SUV traveling just before the collision?
Answer:
v = 19.33 m / s South
Explanation:
To solve this exercise we must use the conservation of momentum, for which we must define a system formed by the two cars, therefore the forces during the collision are internal and therefore the moment is conserved.
Since it is a vector quantity, we are going to work on each axis, the x axis is in the East-West direction
initial instant. Before the crash
p₀ = m 0 + M v₂ₓ
final instant. Right after the crash
p_f = (m + M) vₓ
p₀ = 0_pf
M v₂ₓ = (m + M) vₓ
In this case m is the mass of the car and M the mass of the SUV
vₓ = \(\frac{M}{m+My}\) v₂ₓ (1)
in the Y axis (North - South direction)
initial instant
p₀ = m v_{1y} + M 0
final moment
p_f = (m + M) v_y
p₀ = p_f
m v_{1y} + M 0 = (m + M) v_y
v_y = \(\frac{m}{m+M} \ v_{1y}\) (2)
With these speeds we can use the relationship between work and the variation of kinetic energy, in this part the two cars are already united.
W = ΔK
friction force work is
W = - fr d
the friction force is described by the equation
fr = μ N
Newton's second law
N-W = 0
N = W
we substitute
W = - μ (m + M) g d
as the car stops the final kinetic energy is zero and
the initial kinetic energy is
K₀ = ½ (m + M) v²
we substitute
- μ (m + M) g d = 0 - ½ (m + M) v²
μ g d = ½ v²
v² = 2 μ g d
the distance traveled can be found with the Pythagorean theorem
d = \(\sqrt{x^2+y^2}\)
d = \(\sqrt{5.48^2 + 6.37^2}\)
d = 8.40 m
let's calculate the speed
v² = 2 0.75 9.8 8.40
v = √123.48
v = 11.11 m / s
this velocity is in the direction of motion so we can use trigonometry to find the angles
tan θ = y / x
θ = tan⁻¹ y / x
θ = tan⁻¹ (-5.48 / -6.37)
θ = 40.7º
Since the two magnitudes are negative, this angle is in the third quadrant, measured from the positive side of the x-axis in a counterclockwise direction.
θ'= 180 + 40.7
θ’= 220.7º
In the exercise they indicate the the sedan moves in the y-axis, therefore
sin θ'= v_y / v
v_y = v sin 220.7
v_y = 11.11 sin 220.7
v_y = -7.25 m / s
the negative sign indicates that it is moving south
To find the speed we substitute in equation 2
v_y = \(\frac{m}{m+M} \ v_{1y}\)
v_{1y} = v_ y \(\frac{m+M}{m}\)
let's calculate
v_{1y} = -7.25 \(\frac{1500+2500}{1500}\)
v_{1y} = - 19.33 m/s
therefore the speed of the sedan is v = 19.33 m / s with a direction towards the South
Many elite runners will train with a speed chute. Explain how wearing a speed chute will change the net forces acting on the runner. What can be said about the force the runner is applying if they run at the same sped with the speed chute as they did without the speed chute.
Elite runners follow a rigid training schedule that gradually increases their capacity for the longer distances. Additionally, they run regularly (often 5 to 6 times per week). On the other hand, the typical runner might run significantly more when the weather is favorable or when they have more time.
What are the elite runners will train with a speed chute?Running speed is influenced by stride cadence and stride length. The number of steps made in a second is referred to as the stride cadence, and the distance covered by each step is referred to as the stride length.
Therefore, running speed can be mathematically described using the product of these variables.
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how do rubber bands act like Springs use in a sentence
Answer:
Both springs and rubber bands store potential energy, and the energy turns into kinetic energy when that energy is released.
Explanation:
An apple is dropped from the top of a 200 m tall building. Its acceleration plotted against height fallen is shown in the following graph.
At what height (to one significant figure) above the ground is terminal velocity reached? Give your answer with an appropriate unit.
Answer:
Explanation:
From the graph, acceleration is zero if a distance of 130 m is overcome. The maximum speed at a height from the ground equal to 200 m - 130 m = 70 m. Further, the apple falls evenly!
According to the graph, if a distance of 130 m is overcome, acceleration is zero. The maximum speed at a height of 200 m - 130 m = 70 m from the ground. In addition, the apple falls evenly.
Terminal velocity is the constant maximum velocity reached by an object falling through a fluid (such as air) when the force of gravity pulling the object downward is balanced by the opposing force of air resistance. Initially, as an object falls, its velocity increases due to the acceleration from gravity. However, as the object accelerates, the air resistance acting upon it also increases. Eventually, a point is reached where the air resistance becomes equal to the force of gravity, resulting in zero net force and a constant velocity. This constant velocity is the terminal velocity.
The graph of acceleration plotted against the height fallen provides information about the changing acceleration of the falling apple as it travels down the building. To determine the height at which terminal velocity is reached, you would need to look for the point on the graph where the acceleration levels off or approaches zero. This indicates that the net force acting on the apple is becoming negligible, implying that terminal velocity has been reached.
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hii guys!! ~ i've comeback again!! could you please help me with an assignment?? i have a couple of i know questions!! thank you for helping me, hehe.
tenise can run the 100 meter dash in 9.77 seconds. what is her speed??
Answer:
Speed = 10.24 m/s.
Explanation:
Given the following data;
Distance = 100m
Time = 9.77
To find her speed;
Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.
Mathematically, speed is given by the equation;
\(Speed = \frac{distance}{time}\)
Substituting into the equation, we have;
\(Speed = \frac{100}{9.77}\)
Speed = 10.24 meter per seconds.
16–2. Just after the fan is turned on, the motor gives the
blade an angular acceleration a = (202-0.6) rad/s'. where :
is in seconds. Determine the speed of the tip P of one of the
blades when i 3 s. How many revolutions has the blade
turned in 3 s? When / O the blade is at rest.
Answer:
P.S My answer may not render so let me know if it doesn't
Explanation:
You want to find out how many atoms of the isotope 65Cu are in a small sample of material. You bombard the sample with neutrons to ensure that on the order of 1% of these copper nuclei absorb a neutron. After activation, you turn off the neutron flux and then use a highly efficient detector to monitor the gamma radiation that comes out of the sample. Assume half of the 66Cu nuclei emit a 1.04-MeV gamma ray in their decay. (The other half of the activated nuclei decay directly to the ground state of 66Ni.) (Enter your answer using one of the following formats: 1.2e-3 for 0.0012 and 1.20e 2 for 120.)
Required:
a. If after 10 min (two half-lives) you have detected 10000 MeV of photon energy at 1.04 MeV, approximately how many 65Cu atoms are in the sample?
b. Assume the sample contains natural copper. Refer to the isotopic abundances listed in your text (Chemical and Nuclear Information for Selected Isotopes) and estimate the total mass of copper in the sample.
Answer:
a) number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶ atoms
b) m_total Cu = 1.585 10⁹ u = 2.632 10⁻¹⁸ kg
Explanation:
a) For this exercise let's start by using the radioactive decay ratio
N = N₀ \(e^{- \lambda t}\)o e - lambda t
The half-life time is defined as the time it takes for half of the radioactive (activated) atoms to decay, therefore after two half-lives there are
N = ½ (½ N₀) = ¼ N₀
N₀ = 4 N
in each decay a photon is emitted so we can use a direct rule of proportions. If an atom emits a photon it has Eo = 1,04 Mev, how many photons it has energy E = 10,000 MeV
# _atoms = 1 atom (photon) (E / Eo)
# _atoms = 1 10000 / 1.04
# _atoms = 9615,4 atoms
N₀ = 4 #_atoms
N₀ = 4 9615,4
N₀= 38461.6 atoms
in the exercise indicates that half of the atoms decay in this way and the other half decays directly to the base state of Zinc, so the total number of activated atoms
N_activated = 2 # _atoms
N_activated = 2 38461.6
N_activated = 76923.2
also indicates that 1% = 0.01 of the nuclei is activated by neutron bombardment
N_activated = 0.01 N_total
N_total = N_activated / 0.01
N_total = 76923.2 / 100
N_total = 7.692 10⁶ atoms
so the number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶
b) the natural abundance of copper is
⁶³Cu 69.17%
⁶⁵Cu 30.83%
Let's use a direct proportion rule. If there are 7.692 10⁶ ⁶⁵Cu that represents 30.83, how much ⁶³Cu is there that represents 69.17%
# _63Cu = 69.17% (7.692 10⁶ / 30.83%)
# _63Cu = 17.258 10⁶ atom ⁶³Cu
the total amount of comatose is
#_total Cu = #_ 65Cu + # _63Cu
#_total Cu = (7.692 + 17.258) 10⁶
#_total Cu = 24.95 10⁶
the atomic mass of copper is m_Cu = 63.546 u
m_total = #_totalCu m_Cu
m_total = 24.95 10⁶ 63,546 u
m_total = 1.585 10⁹ u
let's reduce to kg
m_total Cu = 1.585 10⁹ u (1,66054 10⁻²⁷ kg / 1 u)
m_total Cu = 2.632 10⁻¹⁸ kg
27 1 point
A student has tested several types of wood for density. The best way of presenting this information graphically would be to use which item?
Scatterplot
Pie Chart
Line Graph
Bar Graph
Previous
Search
The best way of presenting the information on density graphically would be to use a D, bar graph.
What is a bar graph?A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.
A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.
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According to Steinberg, which of the following statements is true about creative people
They appreciate art and music.
They always take popular stands.
They accept ideas at fàce value.
They accept their limitations,
3. A 1.23 kg object slides down a 1.25 m incline of 35º. Use the data table to construct a graph for force due to gravity vs. distance. Trial 1 Trial 2 Trial 3 Averages Distance (m) 1.25 1.32 1.28
4. Based on the graph in #3, calculate the work done by gravity. Assume work is constant for this data.
5. Using the data from #3, construct a free body diagram and calculate work done by gravity. Explain how this value compare to the value determined graphically in #4.
Remember that this object is on an angle. You'll need to multiply the value for work by cos0
Keep in mind that you'll need to use the angle that forms between the force of gravity and distance.
Answer:
Explanation:
To construct a graph of force due to gravity vs. distance, we need to collect data for force due to gravity (Fg) and distance (d) and plot the data points on a graph. From the information given, we have the mass of the object (1.23 kg) and the angle of the incline (35º), but we do not have any data for force due to gravity or distance. Without this data, it is not possible to construct a graph for force due to gravity vs. distance.
Since we don't have the data for force due to gravity or distance, it's not possible to calculate the work done by gravity using the data table.
Without the data for force due to gravity, distance, or time it's not possible to construct a free-body diagram or calculate work done by gravity. Also, we don't have the angle of the incline, so we cannot calculate the work done by gravity by multiplying it by the cosine of the angle.
It's important to note that work done by gravity (W) = force due to gravity (Fg) x distance (d) x cos(theta), where theta is the angle between the force of gravity and the distance.
It's also important to remember that work is a scalar quantity and not a vector, and it's the angle between the force and the displacement that is important to calculate the work done by gravity, not the angle of the incline.
A projectile is fired into the air at an angle of 50° above ground level and hits a target downrange. Neglecting air drag, it will also hit the target if fired at the same speed at an angle of
Answer:
18 m/s
Explanation:
Range of a projectile on level ground is:
R = v₀² sin(2θ) / g
14.3 m = v₀² sin(2×13°) / 9.8 m/s²
v₀ = 17.9 m/s
Rounded to two significant figures, the launch speed was 18 m/s.
If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.
Given:
The initial shot was fired at an angle of 50 degrees above ground.
The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.
Let the angle of the projectile is x,
The horizontal component of velocity can be calculated as follows:
\(v(x) = v * cos(x)\)
We can write:
since the horizontal part of velocity remains constant:
\(v(x1) = v(x2)\)
\(cos(50) = cos(x)\)
\(50 = x\)
Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.
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The correct response is given when the angle is asked a question.
How does methodology in natural science influence knowledge produced
The use of queries and reports are key functions of ______ software.
A. Spreadsheet
B. Database
C. Desktop publishing
D. Internet
Answer:
DATABASE!!!! I HOPE I HELPED.
The use of queries and reports are key functions of database software, therefore the correct answer is option B.
What is Information technology?Digital transformation is a wide term that encompasses the creation, application, and use of anything involving computers and telecoms.
An example of information technology is the creation of a new word processing program. A subset of digital technologies is cloud-based.
A planned collection of information that has been organized and is frequently stored electronically in a computerized is referred to as a database. A database is frequently managed with a DBMS.
Thus, The use of queries and reports are key functions of database software, therefore the correct answer is option B.
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