Which of the following terms represents the debate between genetic and environmental influences on behavior?
A.
stability versus change
B.
continuity versus stages
C.
nature versus nurture
D.
general versus multiple

True.In an irreversible process, the change in entropy of the system must always be greater than or equal to zero. This is known as the second law of thermodynamics.

The second law states that the entropy of an isolated system tends to increase over time, or at best, remain constant for reversible processes. Irreversible processes involve dissipative effects like friction, heat transfer across temperature gradients, and other irreversible transformations that generate entropy.

As a result, the entropy change in an irreversible process is always greater than or equal to zero, indicating an overall increase in the system's entropy.

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The part of the microscope that the objectives are attached to is called the (C) nosepiece.

The nosepiece is a rotating mechanism located below the microscope's body tube. It holds the objectives, which are the lenses responsible for magnifying the specimen. The nosepiece typically has multiple positions, allowing the user to switch between different objective lenses for varying levels of magnification.

This convenient feature eliminates the need to manually remove and replace objectives when changing magnification. By rotating the nosepiece, different objectives can be brought into position above the specimen. This allows for quick and efficient adjustments in magnification without disrupting the viewing process.

Hence, the nosepiece plays a critical role in the microscope's functionality by providing a convenient way to switch between objectives and adjust the magnification level.

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Here is the complete question:

What is the name of the part of the microscope that the objectives are attached to? (Choose the best answer)

A. Ocular

B. Stage

C. Nosepiece

D. Arm

The Greek philosopher Democritus, but not widely accepted until modern times.

According to history, the concept that all matter is composed of atoms was first proposed by: The Greek philosopher Democritus, but not widely accepted until modern times.

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Answer:

Friction

Explanation:

In the event that the power is applied toward the path inverse to the bearing of movement, it goes against the movement of the item and henceforth the speed of the article diminishes.

Then, in the event that the thing continues to move one way, grinding will dominate and go about as the moving variable.

So, the moving factor would be friction.

Answer:

Air moves from the areas of higher temperature to areas of lower temperature.

Explanation:

this is because hotter temperatures seek out colder temps.

hope this helped!

When a teacher opens a window on a cold day. the room starts to feel cooler because air moves from the areas of higher temperature to areas of lower temperature.

The transfer of heat between two bodies by currents of moving gas or fluid is known as convective heat transfer. In free convection, air or water rises and is replaced by a cooler parcel of air or water as it moves away from the hot body.

As air moves from the areas of higher temperature to areas of lower temperature, when the teacher opens a window on a cold day, the air in the room moves out side and cold air takes the position inside the room. So, it feels cooler then.

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The momentum of the car is 9900 kg m/s.

What is momentum?

The momentum of an object is defined as the product of its mass and velocity. In this case, the momentum of the car can be calculated using the following formula:

Momentum = mass x velocity

Here, the mass of the car is 900.0 kg and its velocity is 11.0 m/s. Substituting these values into the formula, we get:

Momentum = 900.0 kg x 11.0 m/s

Momentum = 9900 kg m/s

Therefore, the momentum of the car is 9900 kg m/s.

Note that the units of momentum are kilogram meters per second (kg m/s), which are derived from the units of mass (kg) and velocity (m/s). Momentum is a vector quantity, meaning it has both magnitude and direction, and its direction is the same as the direction of motion of the object.

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Question A.

i. the force you need to apply to the box to move it down the hill at a constant speed is 500 N.

ii. the acceleration of the piano down the ramp is 4.90 m/s^2.

Question b.

the acceleration of the car down the ramp is 5.42 m/s^2, and the velocity of the car at the top of the ramp is 23.7 m/s.

We apply Newton's Second Law of Motion, which states that the net force acting on an object is equal to the product of its mass and acceleration:

F_net = m*a

v_f = v_i + at

d = v_it + 0.5at^2

Given values: :

Force F = 13000 N

Angle of incline θ = 30°

Mass of the car m = 1200 kg

we find  the component of the force that is parallel to the incline, which will cause the car to move down the ramp:

F_parallel = Fsin(θ) = 13000sin(30°) = 6500 N

we then find  acceleration of the car using Newton's Second Law:

F_net = m*a

a = F_net / m

a = F_parallel / m

a = 6500 N / 1200 kg

a = 5.42 m/s^2

we then  the velocity of the car at the top of the ramp using the kinematic equations:

v_f^2 = v_i^2 + 2ad

d = 125 m

v_i = 0 (the car starts from rest)

v_f = sqrt(2ad)

v_f = sqrt(25.42 m/s^2125 m)

v_f = 23.7 m/s

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Answer:

if we use gravity that is 9.8m/s then we get the answer 4.42 seconds

Explanation:

lets do it steps by steps, s=u/t +1/2 at square

100=0+1/2×9.8 time square

100=4.9 time square

100/4.9= time square

t= 10×2.21. as sides changed the signs also changed

t=4.42

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Answer:

7 feet because 2 feet and 5 feet make seven.

The acceleration of the first block is 1.55 m/s². The tension in the string is -8.25 m2 N (downwards). The maximum value of m2 is 7.49 kg to prevent sliding.

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The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.

d (distance) from A to B is = √2gh

In this case given are, g = 9.8 m/s² and h = 100m,

so here d = √(2⋅9.8⋅100) = 44.3m.

Final velocity ,v = √2gh

Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,

g = 9.8 m/s² ,h = 100m,

v = √(2⋅9.8⋅100)

= 44.3 m/s (final velocity)

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Answer:

The kinetic energy of an object can be found if the object's mass and velocity are know because kinetic energy is energy possessed by a body due to its motion

Explanation:

The impedance of the circuit expressed in rectangular form is 1600Ω +j 1200Ω.

So, the correct answer is C

A circuit with a power factor of 0.8 lagging dissipates 100W of power with an input voltage of 500V.

To find the impedance of the circuit in rectangular form, first calculate the apparent power (S) using P = S * power factor. In this case, S = 100W / 0.8 = 125VA.

Next, calculate the reactive power (Q) using Q = √(S² - P²), which is Q = √(125² - 100²) = 75VAr.

The current (I) can be found by dividing the apparent power by the input voltage, I = 125VA / 500V = 0.25A.

Now, using Ohm's Law (V = IZ), we can calculate the impedance (Z) as Z = 500V / 0.25A = 2000Ω.

Finally, we can express the impedance in rectangular form by splitting it into real and imaginary components: Z = 1600Ω + j1200Ω, which corresponds to option (c).

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Answer:

35

Explanation:

total magnification = eyepiece lens x objective lens

TM = 10X x 25X

TM = 250X

The first dark fringe is located approximately 7.35 mm from the central maximum on the screen.

The location of the first dark fringe can be found using the formula:

y = (mλD) / d

where y is the distance from the central maximum to the first dark fringe, m is the order of the fringe (m = 1 for the first dark fringe), λ is the wavelength of light, D is the distance from the double-slit to the screen, and d is the slit spacing (which is the sum of the slit width and the distance between the centers of the two slits).

The slit width is given as 0.15 mm = 0.00015 m, and the wavelength of light is 450 nm = 0.00045 m. The distance from the double-slit to the screen is 2.3 m.

To find the slit spacing, we need to know the distance between the centers of the two slits. If the double-slit is a single piece with two slits, the distance between the centers of the slits is usually given as the width of the slits plus the distance between them. If this information is not provided, we can assume that the distance between the centers of the slits is approximately equal to the width of each slit. Therefore, we can estimate the slit spacing as:

d ≈ 2 × 0.00015 m = 0.0003 m

Substituting the values into the formula, we get:

\(y = (1 × 0.00045 m × 2.3 m) / 0.0003 m\)

y ≈ 7.35 m

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Answer:

d

Explanation:

the correct chemical formula of a compound with its name is NO₂, Nitrogen Dioxide, the correct option is D.

The chemical compound is a combination of two or more  either similar or dissimilar chemical elements

for example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom

The correct chemical formula for nitrogen Dioxide is NO₂

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Answer:

Wouldn't it be 17.5. Force doubles in weight.

Explanation:

The proper order of the layers of a generic atmosphere, from lowest altitude to highest, is B) troposphere, stratosphere, thermosphere, exosphere.

The layers of the atmosphere, from lowest altitude to highest, are organized as follows:

Troposphere: This is the lowest layer of the atmosphere, extending from the Earth's surface up to an altitude of approximately 7-17 kilometers (depending on the location and season). It is where weather phenomena occur and temperature generally decreases with increasing altitude.

Stratosphere: The stratosphere is located above the troposphere and extends from approximately 17-50 kilometers in altitude. In this layer, temperature generally increases with increasing altitude due to the presence of the ozone layer.

Thermosphere: The thermosphere is the layer above the stratosphere, ranging from approximately 50-600 kilometers in altitude. It is characterized by extremely high temperatures due to the absorption of high-energy solar radiation. However, since the density of molecules is very low, the heat is not felt as the kinetic energy of the molecules.

Exosphere: The exosphere is the outermost layer of the atmosphere, extending from the upper limit of the thermosphere to the edge of space. It is characterized by an extremely thin density of gas molecules, and its boundary with space is not clearly defined.

The proper order of the layers of a generic atmosphere, from lowest altitude to highest, is the troposphere, stratosphere, thermosphere, and exosphere.

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Answer:

7.7 N to left or -7.7 N

Explanation:

slippery floor means no frictional force

Equation for force

F = m * a , where F is force, m is mass in kg, and a is acceleration in m/s²

F = 3.5 * -2.2 m/s² = -7.7 N

Answer:

The acceleration of proton is 5.56 x 10^10 m/s^2 .

Explanation:

initial velocity, u = 0

Electric field, E = 580 N/C

final speed, v = 10^6 m/s

(a) Let the acceleration is a.

According to the Newton's second law

F = m a = q E

where, q is the charge of proton and m is the mass.

\(a= \frac{q E}{m}\\\\a = \frac{1.6\times10^{-19}\times 580}{1.67\times 10^{-27}}\\\\a= 5.56\times 10^{10} m/s^2\)

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__________________________

Existing rocks come together under great heat and pressure to generate metamorphic rocks. Marble, schist, slate, and quartzite are examples of metamorphic rocks. Heat and pressure cause chemical changes in minerals, resulting in metamorphic rocks. They are frequently encountered near magma, but unlike igneous rock, they do not melt.

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Answer:

a) 72 europeos viajan en el avión, b) 132 pasajeros viajan en el avión, c) Hay una proporción de 3 africanos a 5 americanos en el avión.

Explanation:

a) Si 30 % son asiáticos, 15 % africanos y 25 % americanos, entonces 30 % son europeos. La cantidad de europeos en el avión es:

\(x = 0.3\cdot (240)\)

\(x = 72\)

72 europeos viajan en el avión.

b) El total de asiáticos y americanos en el avión se determina mediante la siguiente expresión:

\(x = (0.3 + 0.25)\cdot (240)\)

\(x = 132\)

132 pasajeros viajan en el avión.

c) En primer lugar, se calculan los números de africanos y americanos en el avión:

Africanos

\(x_{1} = 0.15\cdot (240)\)

\(x_{1} = 36\)

Americanos

\(x_{2} = 0.25\cdot (240)\)

\(x_{2} = 60\)

Y la razón de viajeros africanos a viajeros americanos es:

\(r = \frac{r_{1}}{r_{2}}\)

\(r = \frac{36}{60}\)

\(r = \frac{3}{5}\)

Hay una proporción de 3 africanos a 5 americanos en el avión.

Answer:

5 cm

Explanation:

We can say that the circular convolution of x₁ and x₂ is y = [14 14 11 11].

Given the sequences x₁ = [1230] and x₂ = [1321], you are required to manually compute y[n] = x₁[n] circularly convolved with x₂[n] and show all work. The hint suggests that we should make x₁ the outer circle in the ccw direction.

Let us first consider the sequence x₁ = [1230]. We can represent this sequence in a circular form as follows:1   2   3   0

As per the given hint, this is the outer circle, and we need to move in the ccw direction. Now, let us consider the sequence x₂ = [1321]. We can represent this sequence in a circular form as follows:

1   3   2   1

As per the given hint, this is the inner circle. Now, let us write the circular convolution of x₁ and x₂ using the equation for circular convolution:

y[n] = ∑k=0N-1 x₁[k] x₂[(n-k) mod N]

where N is the length of the sequences x₁ and x₂, which is 4 in this case.

Substituting the values of x₁ and x₂ in the above equation, we get:

y[0] = (1×1) + (2×2) + (3×3) + (0×1) = 14y[1] = (0×1) + (1×1) + (2×2) + (3×3) = 14y[2] = (3×1) + (0×1) + (1×2) + (2×3) = 11y[3] = (2×1) + (3×1) + (0×2) + (1×3) = 11

Therefore, the sequence y = [14 14 11 11].

Hence, we can say that the circular convolution of x₁ and x₂ is y = [14 14 11 11].

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5.22N is the thrust of the thruster.

The thrust is the force that propels the rocket through the atmosphere and into space. Newton's third law of motion, which states that every action has an equal and opposite reaction, is used to generate thrust by the rocket's propulsion system.

\(m_{A}\) = 70kg

M = 110kg

a = 0.029m/s²

\(V_{N_{2} }\) = 490m/s

The gas (mass)\(d_{m}\) ejected by the thruster and the thrust can now be calculated using the two equations below F:

a = - \(V_{N_{2} }\)/m dm/dt (1)

F = - \(V_{N_{2} }\) dm/dt (2)

Where,

m = \(m_{A}\) +M

m = 70+110

m = 180kg

The entire mass of the astronaut-MMU system is 180 kg.

\(d_{m}\) is the fuel's ejected mass

dt =5sec is the window of time during which this occurs

Since the mass of the fuel is so small in relation to the total mass, we must separate from (1) here and assume it to be constant:

dm = -ma/\(V_{N_{2} }\) dt

dm = - (180)(0.029)/490 ×5

dm = -0.053kg

The reason for the negative sign is that the ejected mass is moving in the opposite direction from where the astronaut-MMU system is moving. The value of is 0.053 kg, though.

Use equation (2) and the results from the calculation in

F = -490× -0.0593/5

F = 5.22N.

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Answer: \(0.708\ mA\)

Explanation:

Given

\(E_o=20\ V/m\)

\(\omega =10^7\ s^{-1}\)

Cross-sectional area \(A=0.40\ m^2\)

Current density is given by

\(J=\epsilon_o \dfrac{dE}{dt}\)

Displacement current

\(\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A\)

The required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

Given data:

The intensity of electric field is, \(E_{0}=20 \;\rm V/m\).

The angular frequency of electric field is, \(\omega=1.0 \times 10^{7} \;\rm s^{-1}\).

The cross-sectional area of space is, \(A =0.40 \;\rm m^{2}\).

In the given problem, the instantaneous electric field is given by \(E = E_{0} \times cos(\omega t)\)

So, the expression for the current density is,

\(J= \epsilon_{0} \times \dfrac{dE}{dt}\)

Here, \(\epsilon_{0}\)  is the permittivity of free space. Solving as,

\(J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)\)

And the expression for the maximum displacement current is,

\(I = J \times A\)

And the maximum displacement current is possible only when, J is positive and J will be positive for  \(sin(\omega t)=-1\).

Then solving as,

\(I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A\)

Thus, we can conclude that the required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

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When a comet comes near the Sun, its volatile ice sublimates and changes directly from the solid to the gas phase.

Comets are cosmic snowballs of frozen gases, dust, and rocks, orbiting the Sun. When frozen, comets are the size of a small town. As the comet's orbit approaches the Sun, it heats up, spewing gases and dust onto its giant glowing head, larger than most planets.

Comets vaporize when their orbits come to close to the Sun. Comets do not melt in the strict sense of chinging to liquid. However, since they are made up partly of ice and other volatile compounds, comets vaporize (turn directly to gas) when warmed in the vacuum of space by orbiting near the sun.

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Answer:

see below

Explanation:

1000 m / 60 s = 16 2/3  m/s

Answer:

\(4.5\times 10^{-10}\ N\)

Explanation:

The gravitational force between two masses is inversely proportional to the square of the distance between them such that,

\(\dfrac{F_1}{F_2}=\dfrac{r_2^2}{r_1^2}\) .....(1)

We have,

r₁ = 208 m, \(F_1=1.8\times 10^{-9}\ N\), r₂ = 416 m, F₂ = ?

Put all the values in relation (1) such that,

\(F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{1.8\times 10^{-9}\times 208^2}{416^2}\\\\F_2=4.5\times 10^{-10}\ N\)

So, the required force is \(4.5\times 10^{-10}\ N\). Hence, the correct option is (d).