Vented reservoir is the one hydraulic component may be shown many times in a schematic without indicating that there are more than one of that components.
What do you mean by hydraulic?
Hydraulics is a technology and applied science that involves the mechanical properties and utilisation of liquids. It is based on engineering, chemistry, and other sciences. Hydraulics is the liquid equivalent of pneumatics, which is concerned with gases. Fluid mechanics serves as the theoretical foundation for hydraulics, which focuses on applied engineering with fluid properties. Hydraulics is utilised in fluid power applications to generate, control, and transmit power using pressurised liquids.
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if the number of dies per wafer is increased by 10% and the defects per area unit increases by 15%, find the die area and yield.
Answer:
We are given:
- Increase in dies per wafer = 10%
- Increase in defects per area unit = 15%
Let's assume the original number of dies per wafer was D, and the original die area was A. Then the new number of dies per wafer is 1.1D, and the new defect density is 1.15 times the original defect density.
The yield Y is defined as the number of good dies per wafer divided by the total number of dies per wafer. So:
Y = (number of good dies per wafer) / (total number of dies per wafer)
To find the die area, we can use the fact that the total wafer area is constant, so:
total wafer area = original number of dies per wafer x original die area
total wafer area = (1.1D) x A
The new die area can be found by dividing the total wafer area by the new number of dies per wafer:
new die area = (total wafer area) / (new number of dies per wafer)
new die area = [(1.1D) x A] / (1.1D)
new die area = A
So the die area is unchanged by the increase in dies per wafer.
To find the new yield, we need to calculate the number of good dies per wafer. Let's assume the original defect density was D0 defects per unit area, and the original yield was Y0. Then the new defect density is 1.15D0 defects per unit area, and the new yield is:
Y = (number of good dies per wafer) / (1.1D)
The number of bad dies per wafer is:
number of bad dies per wafer = (total number of dies per wafer) x (new defect density)
number of bad dies per wafer = (1.1D) x (0.15D0 x A)
number of bad dies per wafer = 0.165D0A
So the number of good dies per wafer is:
number of good dies per wafer = total number of dies per wafer - number of bad dies per wafer
number of good dies per wafer = 1.1D - 0.165D0A
Substituting this into the yield equation, we get:
Y = (1.1D - 0.165D0A) / (1.1D)
Y = 1 - 0.15(D0A/D)
So the new yield is 1 - 0.15(D0A/D) times the original yield.
What arethe two tag codes for performing ordered and un ordered lits using HTML
Answer:
The HTML ul tag is used for the unordered list. There can be 4 types of bulleted list: To represent different ordered lists, there are 4 types of attributes in <ul> tag. This is the default style. In this style, the list items are marked with bullets.
Answer:
Ordered
\({ \tt{ < ol > .... < / ol > }}\)
Unordered
\({ \tt{ < ul > .... < /ul > }}\)
Briefly explain thermal expansion using the potential energy–versus–interatomic spacing curve.
As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.
What are the uses of Thermal Expansion?Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.
It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.
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To measure an object accurately, what point on the ruler would you align with the object edge
Answer:
Along the zero to measure an object on a ruler
All of these are true about using adhesive EXCEPT:
Answer:
Except what? I'm confused
All of these are true about using adhesive except Bilateral. A bilateral contract is defined as an agreements between two parties in which each side agrees to fulfill his or her side of the bargain.
What is bilateral contract?A bilateral contract is defined as an agreements between two parties in which each side agrees to fulfill his or her side of the bargain. According to my research on the different terms used when referencing an insurance contract, I can say that all of the answers provided except for Bilateral are considered typical characteristics describing the nature of an insurance contract.
Since an insurance contract is a fund that the insurance company pays in the case of an accident in which the person is injured, there is only one party that agrees to fulfill their side of the bargain and that is the insurance company.
Therefore, All of these are true about using adhesive except Bilateral. A bilateral contract is defined as an agreements between two parties in which each side agrees to fulfill his or her side of the bargain.
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TypeError Traceback (most recent call last) Input In [34], in () ----> 1 statistics([1, 1, 1, 1]) Input In [29], in statistics(x) 22 mean= round(np_list.mean(), 2) if str(type(np_list[0]))=="" else [round(i.mean(), 2) for i in np_list] 23 # find standard deviation ---> 24 std= round(unbias_std(np_list), 2) if str(type(np_list[0]))=="" else [round(unbias_std(i), 2) for i in np_list] 25 # find mininum 26 mini= np_list.min() if str(type(np_list[0]))=="" else [i.min() for i in np_list] Input In [29], in (.0) 22 mean= round(np_list.mean(), 2) if str(type(np_list[0]))=="" else [round(i.mean(), 2) for i in np_list] 23 # find standard deviation ---> 24 std= round(unbias_std(np_list), 2) if str(type(np_list[0]))=="" else [round(unbias_std(i), 2) for i in np_list] 25 # find mininum 26 mini= np_list.min() if str(type(np_list[0]))=="" else [i.min() for i in np_list] Input In [21], in unbias_std(lists) 15 def unbias_std(lists): 16 mean=lists.mean() ---> 17 var = sum(pow(x-mean,2) for x in lists) / (len(lists)-1) 18 std = np.sqrt(var) 19 return std TypeError: 'numpy.int32' object is not iterable
statistics([1, 1, 1, 1]) == {'mean': 1, 'std': 0, 'min': 1, 'median', 1, 'max': 1}
statistics([1, 2, 2, 3, 4]) == {'mean': 2.4, 'std': 1.14, 'min': 1, 'median': 2.0, 'max': 4}
TypeError: 'numpy.int32' object is not iterable
statistics([1, 1, 1, 1]) == {'mean': 1, 'std': 0, 'min': 1, 'median', 1, 'max': 1}
statistics([1, 2, 2, 3, 4]) == {'mean': 2.4, 'std': 1.14, 'min': 1, 'median': 2.0, 'max': 4}
good day
when i run the above i get this error message . TypeError: 'numpy.int32' object is not iterable. i need a code to rectify this error message and run all three
thank you.
this code provided below works for the code below to run.
statistics([[1, 2], [3, 4]]) == { 'mean': [1.5, 3.5], 'std': [0.71, 0.71], 'min': [1, 3], 'median': [1.5, 3.5], 'max': [2, 4] }
def calculate(lst):
import numpy as np
if len(lst) != 9:
return "List must contain nine numbers."
x = np.array(lst).reshape(3, 3)
result = {
k: [func(x, axis=ax).tolist()
for ax in [0, 1, None]]
for (k, func)
in zip(["mean", "variance", "standard deviation"],
[np.mean, np.var, np.std])
}
statistics([[1, 2], [3, 4]]) == { 'mean': [1.5, 3.5], 'std': [0.71, 0.71], 'min': [1, 3], 'median': [1.5, 3.5], 'max': [2, 4] }
It checks the type of the first element in `x` to determine if it's a single list or nested lists, and performs the calculations accordingly. The results are returned in a dictionary format.
"Could you provide a concise code snippet that calculates statistics (mean, standard deviation, minimum, median, and maximum) for a given list or nested lists, handling both cases in a single line?"Here's a version of the code that accomplishes the task in a single line:
import numpy as np
statistics = lambda x: {'mean': round(np.mean(x), 2) if isinstance(x[0], int) else [round(np.mean(i), 2) for i in x],
'std': round(np.std(x), 2) if isinstance(x[0], int) else [round(np.std(i), 2) for i in x],
'min': np.min(x).tolist() if isinstance(x[0], int) else [np.min(i).tolist() for i in x],
'median': round(np.median(x), 2) if isinstance(x[0], int) else [round(np.median(i), 2) for i in x],
'max': np.max(x).tolist() if isinstance(x[0], int) else [np.max(i).tolist() for i in x]}
This lambda function takes a list or nested lists as input (`x`) and calculates the mean, standard deviation, minimum, median, and maximum values.
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Shifting the position of the center of gravity forward will decrease the magnitude of the required control forces exerted by the pilot during normal operations.T/F
True. Shifting the position of the center of gravity (CG) forward will decrease the magnitude of the required control forces exerted by the pilot during normal operations. The center of gravity is the point at which an aircraft's mass is evenly distributed, and it plays a crucial role in maintaining stability and control during flight.
When the CG is located forward of its optimal position, the aircraft becomes more stable due to the increased distance between the CG and the center of lift. This increased stability requires less control input from the pilot to maintain the desired flight path, thereby reducing the magnitude of the control forces exerted.
However, it is important to note that an excessively forward CG can lead to issues with aircraft handling and control. While a forward CG reduces the required control forces, it can also make the aircraft less maneuverable and more challenging to control during takeoff, landing, and in-flight maneuvers. In extreme cases, a forward CG can even lead to a condition called "nose-heavy," making it difficult for the pilot to raise the nose during takeoff or maintain altitude during flight.
In conclusion, while shifting the position of the center of gravity forward does decrease the magnitude of the required control forces exerted by the pilot during normal operations, it is essential to ensure that the CG remains within the aircraft's specified limits to maintain safe and efficient flight characteristics.
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A spherical ball has 3cm internal diameter and its inner surface temperature is 250˚C and the outer surface temperature is 30˚C. Calculate the outer diameter of the ball if the heat loss from the ball is 1600W and has 2.75W/m.˚C thermal conductivity.
Answer:
The outer diameter of the ball is 6.2138 cm
Explanation:
The formula to apply is ;
Heat loss ,
\(Q/t=kA*\frac{( T_1-T_2)}{d}\)
where ;
Q/t=total heat loss from the ball = 1600 w
k=coefficient of heat transmission through the ball= 2.75 W/m.˚C
A=area in m² of the ball with the coefficient of heat transmission
T₁=Hot temperature
T₂=Cold temperatures
d=thickness of the ball
Area of spherical ball using internal diameter, 3cm= 0.03 m will be
Radius = half the diameter = 0.03/2 = 0.015
Area = 4 *π*r²
Area = 4*π*0.015² = 0.002827 m²
Apply the formula for heat loss to get the thickness as:
1600 = {2.75 * 0.002827 *(250-30 ) }/d
1600 =1.711/d
1600d = 1.711
d=1.711/1600 = 0.001069 m
d= 0.1069
Using internal radius and the thickness to get outer radius as;
3 + 0.1069 = 3.1069 cm
Outer diameter will be twice the outer radius
2*3.1069 = 6.2138 cm
A 1m diameter thin pressure vessel (wall thickness of 10 mm) is
internally pressurized. If the pressure is equal to P = 2 MPa, what
is the value of the radial stress
The value of the radial stress is 100 MPa:
Internal pressure, P = 2 MPa
Diameter, D = 1 m
Wall thickness, t = 10 mm
= 0.01 m
The radial stress in a thin-walled pressure vessel is given byσr = P*D/2tw
hereσr = radial stress
P = internal pressure
D = diameter of the cylinder (vessel)
t = thickness of the cylinder (vessel)
r = 2*1/2*0.01 = 100 MP
Therefore, the value of the radial stress is 100 MPa. The expression for radial stress for thin-walled pressure vessel is σr = P*D/2t where
σr = radial stress,
P = internal pressure,
D = diameter of the cylinder (vessel), and
t = thickness of the cylinder (vessel).
Given, internal pressure, P = 2 MPa,
diameter, D = 1 m,
wall thickness, t = 10 mm
= 0.01 m.
Substituting the values,
we get radial stress asσr = 2*1/2*0.01
= 100 MPa.
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An mos capacitor biased so that majority carriers in the semiconductor pile up at the oxide semiconductor interface is biased in which region? a. accumulation b. flat band c. depletion d. inversion
The MOS capacitance is a very helpful tool for assessing the construction of MOS integrated circuits and forecasting the properties of MOS transistors.
What does semiconductor mean in plain English?A semiconductor is what. Semiconductors. Semiconductors are substances with conductivity intermediate between that of conductors (often metals) and that of nonconductors or insulation (such as most ceramics). Semiconductors can be made of compounds like indium gallium or cadmium selenide or pure elements like silicon or germanium.
What makes anything a semiconductor?The reason a material is termed a semiconductor is because it has a resistance that is between the resist typical of insulators and metals, or that "semi"-conducts electricity in a way.
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Chlorine is one of the important commodity chemicals for the global economy. Before the advent of large scale
production of chlorine from electro-chemical processes, the direct catalytic oxidation of hydrochloric acid with oxygen
is used to produce chlorine. It is known as ‘Deacon process’
In production of chlorine gas by oxidation of hydrochloric acid gas, air is used 30% excess of the theoretically used.
4kmol/h of hydrochloric acid is fed to the reactor. The percentage conversion of reaction is 80%.
Reaction: 4 HCL + O2 −−→ 2 Cl2 + 2 H2O
a Calculate the composition of gas in the product stream on mole basis
The composition of gas in the feed, the percentage conversion and the
theoretical yield are combined to give the product stream composition.
Response:
The composition of gas in the product stream are;
HCl: 0.4 kmol/h, Cl₂: 1.6 kmol/h, H₂O: 1.6 kmol/h, O₂: 0.5 kmol/hHow can percentage conversion give the contents of the product stream?The amount of oxygen used = 30% exceeding the theoretical amount
Number of moles of hydrochloric acid = 4 kmol/h
Percentage conversion = 80%
Required:
The composition of the gas in the product feed.
Solution;
The given reaction is; 4HCl + O₂ \(\longrightarrow\) 2Cl₂ + 2H₂O
\(Percentage \ conversion = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{Moles \ of \ limiting \ reactant \ supplied \ in \ the \, feed}}\)
Which gives;
\(80 \% = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{4 \, kmol/h}}\)
Moles of limiting reactant reacted = 4 kmol/h × 0.80 = 3.6 kmol/h
Which gives;
Number of moles of HCl in the stream = 4 kmol/h - 3.6 kmol/h = 0.4 kmol/h
Number of moles of Cl₂ produced = 2 kmol/h × 0.8 = 1.6 kmol/h
Similarly;
Number of moles of H₂O produced = 2 kmol/h × 0.8 = 1.6 kmol/h
Number of moles of O₂ in the product stream = 30% × 1 kmol/h + 20% × 1 kmol/h = 0.5 kmol/h
The composition of the production stream is therefore;
HCl: 0.4 kmol/hCl₂: 1.6 kmol/hH₂O: 1.6 kmol/hO₂: 0.5 kmol/hLearn more about theoretical and actual yield here:
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what is a JK flip flop?
One of the most popular flip flips in digital circuits is the JK flip flop. A global flip flop with two inputs, the JK flip flop has the letters "J" and "K."
What does J and K in JK flip-flop mean?Although it has two inputs, typically denoted J and K, it has the input-following behaviour of the clock-driven D flip-flop. The output Q takes the value of J at the following clock edge if J and K are not the same. In honour of the device's creator, Jack Kilby, the inputs are designated J and K.
JK flip-flop is employed where?In shift registers, counters, PWM, and other devices that toggle between two states, the JK Flip-Flop is a common flipflop.
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two technicians are describing how an air-conditioning system gets rid of the heat. Technician A says that heat always flows from the hotter to the colder object. Technician B says that as refrigerant evaporates, it absorbs heat as it changes from a liquid to a gas. which technician is correct?
Based on the information provided by these technicians, both of them are correct.
How does heat flow?According to heating, ventilation, and air conditioning (HVAC), heat in an air-conditioning system generally flows from the hotter object to the colder object.
As the refrigerant evaporates in a small radiator-type unit (evaporator), it absorbs heat as it changes phase from liquid to gas. Also, as the heat is being absorbed by the refrigerant, the small radiator-type unit (evaporator) becomes cold.
In conclusion, we can logically deduce that both of them are correct.
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Which control would be used to manually feed a cutting tool longitudinally across the workpiece?
The carriage handwheel is used to manually position and/or hand feed the carriage in the longitudinal or Z axis.
IamSugarBee
Having established in parts of Chapter 2 that establishing the goals of a system is a key initial aspect of the systems development process, we will demonstrate in Chapter 3 how this goal-setting process is not only an interesting undertaking but also rather critical if the system is to perform to the expectations of its users, the owner, and the community at large. EXERCISES 1. Give an example of a "system" in (a) your preferred branch of engineering and (b) everyday life.
In the field of civil engineering, an example of a "system" could be a transportation network, such as a highway system or a railway system. In everyday life, a common example of a "system" is a smartphone or a mobile communication network.
(a) In civil engineering, a transportation network is a complex system comprising various components, including roads, bridges, traffic signals, and vehicles. It aims to facilitate the efficient movement of people and goods from one location to another.
(b) In everyday life, a smartphone can be seen as a system that consists of hardware components like the screen, processor, and battery, as well as software applications and connectivity features. It operates within a broader mobile communication network, which includes cellular towers and internet infrastructure, enabling communication and access to various services.
Both examples demonstrate the interconnectedness of components and their coordination to achieve specific goals. Understanding the goals and objectives of these systems is essential for their successful design, operation, and user satisfaction.
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Laws vs Morals vs Ethics Q No. 1 Consider the Following Scenario ? Speeding on Motorway • Illegal, moral ("everyone" does it), maybe ethical Speeding within city • Illegal, immoral(dishonest), unethical What might a software engineer do that is… • Illegal, immoral, unethical ? • Legal, immoral, unethical ? • Legal, moral, unethical ? Q No. 2 By Considering 8 Principles of IEEE Code of Ethics, How would you respond in a way that is legal, moral, and ethical for the following scenarios? 1. You are the owner of a software engineering company. Your employees (engineers) want you to let them do pro bono work for a local non-profit organization on company time. 2. You are the head of a computer science department at a university. Your boss (a "dean") wants you to find a way to change your curriculum so undergrads are more likely to choose your department for their major. 3. You are a software engineer working at a large publicly-traded corporation, where a colleague invents a new kind of compiler. Your managers see it as a huge potential cash cow. 4. You are a software engineer at a company where management routinely encourages you and your colleagues to use pirated software
A software engineer might engage in any of the following activities that could be deemed illegal, immoral, and unethical:
Software piracy, security breaches, data theft, software spying or snooping, creating viruses or other harmful code, intentionally producing defective code, and knowingly releasing software with bugs or security flaws.
Creating software that serves a beneficial social or moral purpose, such as software that promotes environmental sustainability, public safety, and public health. Software that serves the public good is legal, but some software might have unintended or unforeseen ethical implications.
According to the IEEE code of ethics, engineers should support and participate in pro bono and charitable work that promotes the public good. Therefore, as a software engineering company owner, you should allow your employees to do pro bono work on company time as long as it does not interfere with their assigned tasks or affect the company's productivity.
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For the circuit shown below
Answer:
48.00 microamps
Explanation:
The base voltage is limited by the zener to 5.5 V. If we assume the B-E voltage drop is 0.7 V, then the voltage across RE is 5.5-0.7 = 4.8 volts. That means the emitter current is 4.8/2.0k = 2.4 mA.
The base current is that amount divided by (1+β), so is 2.4 mA/(1+49) = 48 μA.
What does abbreviation vom stand for
Answer:
vom = Volt Ohm Meter
Explanation:
Refrigerant leaving the metering device going to the evaporator should be________________
Refrigerant leaving the metering device and entering the evaporator should be in a **low-pressure liquid state**.
The metering device in a refrigeration system, such as a thermostatic expansion valve (TXV) or an orifice tube, plays a crucial role in controlling the flow and pressure of the refrigerant. Its primary function is to regulate the refrigerant flow rate into the evaporator, ensuring proper cooling and heat absorption.
When the refrigerant passes through the metering device, it undergoes a pressure drop, transitioning from a high-pressure liquid state to a low-pressure liquid state. This pressure reduction allows the refrigerant to expand and evaporate inside the evaporator coil, absorbing heat from the surrounding air or space.
It is important for the refrigerant leaving the metering device and entering the evaporator to be in a low-pressure liquid state rather than a vapor or high-pressure liquid. A low-pressure liquid state ensures efficient heat transfer within the evaporator, as the liquid refrigerant can absorb heat effectively from the system's surroundings.
If the refrigerant were to enter the evaporator as a vapor or a high-pressure liquid, it could lead to several issues. Vapor entering the evaporator would hinder the heat transfer process, as it would need to undergo additional phase change from vapor to liquid before effectively absorbing heat. On the other hand, a high-pressure liquid entering the evaporator could result in reduced evaporator efficiency and potential damage to the system components.
Therefore, maintaining the refrigerant in a low-pressure liquid state as it leaves the metering device and enters the evaporator is essential for optimal refrigeration system performance and efficient heat transfer.
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Find the function f and the value of the constant a such that: 2 ∫ f(t)dt x a = 2 cos x − 1
Answer:
The function is \(-\sin x\) and the constant of integration is \(C = - 1\).
Explanation:
The resultant expression is equal to the sum of a constant multiplied by the integral of a given function and an integration constant. That is:
\(a = k\cdot \int\limits {f(x)} \, dx + C\)
Where:
\(k\) - Constant, dimensionless.
\(C\) - Integration constant, dimensionless.
By comparing terms, \(k = 2\), \(C = -1\) and \(\int {f(x)} \, dx = \cos x\). Then, \(f(x)\) is determined by deriving the cosine function:
\(f(x) = \frac{d}{dx} (\cos x)\)
\(f(x) = -\sin x\)
The function is \(-\sin x\) and the constant of integration is \(C = - 1\).
a 120-m long copper wire (resistivity = 1.68x10^-8 *m) has a resistance of 6.0 . what is the diameter of the wire?
diameter of the copper wire is approximately 2.06x10^-4 m (or 0.206 mm).
To find the diameter of the copper wire, we can use the formula for resistance of a wire:
R = (ρ x L) / A
Where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.We know that the length of the wire is 120 m, the resistivity of copper is 1.68x10^-8 Ω·m, and the resistance is 6.0 Ω. We can rearrange the formula to solve for the cross-sectional area of the wire:
A = (ρ x L) / R
A = (1.68x10^-8 Ω·m x 120 m) / 6.0 Ω
A = 3.36x10^-7 m^2
Now we can use the formula for the area of a circle to find the diameter of the wire:
A = π x (d/2)^2
Where π is the mathematical constant pi (approximately 3.14), and d is the diameter of the wire.
We can rearrange this formula to solve for the diameter:
d = √(4 x A / π)
d = √(4 x 3.36x10^-7 m^2 / π)
d = 2 x √(3.36x10^-7 m^2 / π)
d = 2 x √(1.07x10^-7) m
d = 2 x 1.03x10^-4 m
d = 2.06x10^-4 m
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A contractor excavates 10,000 m3 soil at moist unit weight of 17.5 kN/m3 and moisture content of 10% from a borrow pit and transports it to a project site. The project has an area of 20,000 m2 to be filled with this compacted soil. If the required dry unit weight and moisture content of the compacted soil are 18.3 kN/m3 and 12.5% (assume there is no soil loss during transportation and compaction), what is the thickness of the compacted soil and how much water needs to be added?
Answer:
Part A
The thickness of the compacted soil is approximately 4.3467 × 10⁻¹ m
Part B
The weight of water to be added is approximately 19886.\(\overline{36}\) kN, the volume of the water added is approximately 2,027.77 m³
Explanation:
The parameters of the soil are;
The volume of sol the excavator excavates, \(V_T\) = 10,000 m³
The moist unit weight, W = 17.5 kN/m³
The moisture content = 10%
The area of the project, A = 20,000 m²
The required dry unit weight = 18.3 kN/m³
The required moisture content = 12.5%
Part A
Therefore, we have;
The moist unit weight = Unit weight = (\(W_s\) + \(W_w\))/\(V_T\)
The moisture content, MC = 10% = (\(W_w\)/\(W_s\)) × 100
∴ \(W_w\) = 0.1·\(W_s\)
∴ The moist unit weight = 17.5 kN/m³ = (\(W_s\) + 0.1·\(W_s\))/(10,000 m³)
1.1·\(W_s\) = 10,000 m³ × 17.5 kN/m³ = 175,000 kN
\(W_s\) = 175,000 kN/1.1 = 159,090.\(\overline{09}\) kN
For the required soil, we have;
The required dry unit weight = 18.3 kN/m³ = \(W_s\)/\(V_T\) = 159,090.\(\overline{09}\) kN/\(V_T\)
\(V_T\) = 159,090.\(\overline{09}\) kN/(18.3 kN/m³) ≈ 8,693.4923 m³
The total volume of the required soil ≈ 8,693.4923 m³
Volume \(V_T\) = Area, A × Thickness, d
∴ d = \(V_T\)/A
d = 8,693.4923 m³/(20,000 m²) ≈ 4.3467 × 10⁻¹ m
The thickness of the compacted soil ≈ 4.3467 × 10⁻¹ m
Part A
The moisture content, MC = 12.5% = (\(W_w\)/\(W_s\)) × 100
\(W_w\) = \(W_s\) × MC/100 = 159,090.\(\overline{09}\) kN × 12.5/100 = 19886.\(\overline{36}\) kN
The weight of water to be added, \(W_w\) = 19886.\(\overline{36}\) kN
Where the density of water, ρ = 9.807 kN/m³
Therefore, we have;
The volume of water, V = \(W_w\)/ρ
∴ V = 19886.\(\overline{36}\) kN/(9.807 kN/m³) ≈ 2027.77 m³
The volume of water, V ≈ 2027.77 m³
All of these are part of the seat belt assembly EXCEPT the:
O latch plate
O D-ring
O retractor.
O cushion
Match the scenario with the term it represents. Jonathan designs a new car. The car can run 48 miles per gallon, or 48:1. Justin’s car can drive 10 miles per gallon, or 10:1. He wants to travel 40 miles, meaning he needs at least 4 gallons in his car (10:1 = 40:4). Kinsey’s sketches show the design of her lawn mower with its exact proportions but in a smaller size. ratioproportionscale
The scenario with the terminology it represents should be matched as follows:
Ratio: Jonathan designs a new car. The car can run 48 miles per gallon, or 48:1. Proportion: Justin’s car can drive 10 miles per gallon, or 10:1. He wants to travel 40 miles, meaning he needs at least 4 gallons in his car (10:1 = 40:4). Scale: Kinsey’s sketches show the design of her lawn mower with its exact proportions but in a smaller size.What is a ratio?A ratio can be defined as a mathematical expression that's used to denote the proportion of two (2) or more quantities with respect to one another and the total quantities.
What is a proportion?A proportion can be defined as an expression which is typically used to represent (indicate) the equality of two (2) ratios. This ultimately implies that, proportions can be used to establish that two (2) ratios are equivalent and solve for all unknown quantities.
What is scale factor?A scale factor can be defined as the ratio of two (2) corresponding length of sides or diameter in two similar geometric figures such as polygons.
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Answer:
Ratio: Justin’s car can drive 10 miles per gallon, or 10:1. He wants to travel 40 miles, meaning he needs at least 4 gallons in his car (10:1 = 40:4).
Proportion: Jonathan designs a new car. The car can run 48 miles per gallon, or 48:1.
Scale: Kinsey’s sketches show the design of her lawn mower with its exact proportions but in a smaller size.
Explanation:
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The pneumatic (reed) type stall warning system installed in some light aircraft is activated by
A- static air pressure
B- positive air pressure
C- negative air pressure
The pneumatic (reed) type stall warning system installed in some light aircraft is activated by "A- static air pressure."
In this type of stall warning system, static air pressure is used to trigger the activation of the warning mechanism. The system typically consists of a small opening on the leading edge of the aircraft's wing or other aerodynamic surfaces. This opening is connected to a tube that leads to the cockpit where the warning device is located.
During normal flight conditions, the static air pressure entering the opening is relatively steady. However, when the angle of attack of the aircraft increases and reaches a critical point, the airflow over the wing becomes disrupted, causing a decrease in static air pressure at the opening. This drop in pressure is sensed by a reed or a similar mechanism within the warning system.
The decrease in static air pressure causes the reed to vibrate or oscillate, creating an audible warning sound or activating a visual indicator in the cockpit. This serves as an alert to the pilot that the aircraft is approaching a stall condition, indicating the need to take corrective action to prevent an aerodynamic stall.
By utilizing static air pressure as the triggering mechanism, the pneumatic (reed) type stall warning system provides a simple and reliable means of alerting pilots to potential stall conditions during flight.
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What are the advantages to a quality
saw?
Tech A says that radial ply tires have much more flexible sidewalls than bias-ply tires because of their construction. Tech B says that bias-ply tires have a more durable construction than radial tires. Who is correct?
Answer:
Tech A and Tech B are correct
Explanation:
Tech A is correct because radial ply tires have more flexible sidewalls than radial tires due to the fact that radial tires make use of two or more layers of casing piles and are thus not much flexible.
Also, tech B is correct because bias-ply tires typically have more durable construction than radial tires
Explain packaging films and how gums are used in packaging films
Air at 40°C flow steadily through the pipe shown in Fig. 1 below. If P1 = 40 kPa (gage), P2 = 10 kPa (gage), D = 3d, Patm ≅ 100 kPa, the average velocity at section 2 is V2 = 25 m/s, and air temperature remains nearly constant, determine the average speed at section 1.
Based on the average velocity at section 2, and the absolute pressures at both sectors, the average speed at section 1 is 2.226 m/s.
What is the average speed at section 1?Density at P₁:
= (40 + 100) / (0.287 x (40 + 273))
= 1.5585 kg/m³
Density at P₂:
= (10 + 100) / (0.287 x (40 + 273))
= 1.2245 kg/m³
The average speed at section 1 is:
= (Density at P₂ x d² x 25.5) / (Density at P₁ x 9d²)
= 2.226 m/s
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A belt sander has a belt speed of 1500 ft/min. The coefficient of friction between the sander and the plywood being finished is 0.2. If the downward (normal) force on the sander is 15 bf, determine (a) the power transmitted by the belt, in Btu/s and hp, and (b) the work done in one minute of sanding, in Btu.
The power transmitted by the belt in a belt sander can be calculated using the formula P = F * V, where P is power, F is the force, and V is the velocity. Therefore, by applying the given values and calculations, we can determine the power transmitted by the belt in Btu/s and hp, as well as the work done in one minute of sanding in Btu.
In this case, the downward force on the sander is given as 15 bf (pound-force) and the belt speed is 1500 ft/min. The coefficient of friction between the sander and the plywood is 0.2. To calculate the power transmitted by the belt, we use the formula P = F * V, where P is power, F is the force, and V is the velocity. Substituting the given values, we have P = 15 bf * 1500 ft/min.
To convert the power from British thermal units per second (Btu/s) to horsepower (hp), we need to use the conversion factor of 1 hp = 2544 Btu/s. So, we divide the power in Btu/s by 2544 to get the power in horsepower.
To determine the work done in one minute of sanding, we multiply the power by the time. Since the time given is in minutes and the power is in Btu/s, we need to convert the time to seconds before performing the calculation. Finally, the work done can be expressed in Btu.
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