Which one is not a way energy is transfered.A: RadiationB: ConductionC: ConvectionD: Electricity

The various parts of galaxy are mentioned in this image.

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Answer:

Nuclear fission is a reaction in which the nucleus of an atom splits into two or more smaller nuclei. The moderator helps slow down the neutrons produced by fission to sustain a chain of reaction. The chains are controlled by Boron control rods when Boron absorbs the neutrons then the chain reaction will slow down due to the lack of neutrons producing reactions due to the absorbent of Boron. Their reaction initiates its own repetition.

Nuclear fission is the splitting of nucleus into two smaller nuclei and high amount of energy.

Nuclear fission is a reaction in which the nucleus of an atom splits into two or more smaller nuclei as well as very high amount of energy. The nuclear fission process produces gamma photons, and releases a very large amount of energy.

Most reactors are controlled with the help of control rods that are made of a strongly neutron-absorbent material such as boron or cadmium so we can conclude that nuclear fission is the splitting of nucleus into two smaller nuclei and high amount of energy.

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Answer:

C: 5

Explanation:

MA = radius of wheel/ radius of axle

MA =2.5/0.5

MA = 5.0

Answer:

The rate of change of velocity is acceleration. Like velocity, acceleration is a vector and has both magnitude and direction. For example, a car in straight-line motion is said to have forward (positive) acceleration if it is speeding up and rearward (negative) acceleration if it is slowing down.

Explanation:

Hope it is helpful....

Answer:

4161 J/kg·°C

Explanation:

We can use the principle of conservation of energy to solve this problem, which states that the total heat energy in a closed system is constant. The heat lost by the tea is equal to the heat gained by the milk.

Let's first calculate the heat lost by the tea:

Q(tea) = mcΔT

Q(tea) = (0.27 kg)(3910 J/kg·°C)(90.0°C - 85.0°C)

Q(tea) = 6555 J

where m is the mass of tea, c is the specific heat of tea, and ΔT is the change in temperature.

Next, let's calculate the heat gained by the milk:

Q(milk) = mcΔT

Q(milk) = (0.02 kg)(c)(85.0°C - 6.0°C)

Now we can equate the two expressions:

Q(tea) = Q(milk)

6555 J = (0.02 kg)(c)(79.0°C)

Solving for c, we get:

c = 4161 J/kg·°C

Therefore, the specific heat of milk is approximately 4161 J/kg·°C.

If the applied force is 20 N and the displacement is from X=0m to X=5.0m, the work done is 100 Joules.

To determine the work done by a force, you need to know the displacement and the component of the force parallel to the displacement.

In this case, if the force applied is 20 N and the displacement is from X=0m to X=5.0m, you need to determine if the force is parallel to the displacement.

If the force is parallel to the displacement, then the work done is simply the product of the force and the displacement, which is:

Work = Force x Displacement

Work = 20 N x (5.0 m - 0 m)

Work = 100 Joules

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The complete question is below:

What is the work done from X =0m to 5.0m? if the applied force is 20 N

The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The fraction of a wavelength represented by the first harmonic is 1/2.

The higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

1. The first harmonic of a standing wave on a string with a loose end occurs when there is a node near the driver end and an antinode at the loose end. To measure the frequency of the first harmonic, we need to determine the fraction of a wavelength represented by this standing wave.

The first harmonic of the standing wave on a string with a loose end represents half a wavelength.

The first harmonic of a standing wave on a string with a loose end consists of a node near the driver end and an antinode at the loose end. This configuration creates the simplest standing wave pattern.

In a standing wave, a node is a point where the amplitude of the wave is always zero, representing a point of minimum displacement. An antinode, on the other hand, is a point of maximum displacement, where the amplitude is at its highest.

Since the loose end does not invert the phase of the wave upon reflection, the reflected wave and the original wave constructively interfere at the loose end, resulting in an antinode.

In the first harmonic, there is exactly half a wavelength between the node near the driver end and the antinode at the loose end.

Therefore, the fraction of a wavelength represented by the first harmonic is 1/2.

2. To predict the frequencies of higher harmonics, we can use the relationship that the frequency of each harmonic is a multiple of the frequency of the first harmonic. The higher harmonics can be calculated as follows:

Second Harmonic: The second harmonic consists of two nodes and one additional antinode compared to the first harmonic. The fraction of a wavelength for the second harmonic is 1/2 * 2 = 1. Thus, the second harmonic has a frequency that is twice that of the first harmonic.

Third Harmonic: The third harmonic consists of three nodes and two additional antinodes compared to the first harmonic. The fraction of a wavelength for the third harmonic is 1/2 * 3 = 1.5. Thus, the third harmonic has a frequency that is three times that of the first harmonic.

Fourth Harmonic: The fourth harmonic consists of four nodes and three additional antinodes compared to the first harmonic. The fraction of a wavelength for the fourth harmonic is 1/2 * 4 = 2. Thus, the fourth harmonic has a frequency that is four times that of the first harmonic.

In general, the higher harmonics of a standing wave on a string with a loose end are odd-number multiples of the first harmonic.

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a student rises their 15 kg back pack from the floor at a constant velocity of 5.0 m/s then they apply of 37.5 N of force.

Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s². There are two types of forces, balanced force and unbalanced force.

In this problem student rises 15 kg of backpack at constant velocity and it happens in 2s, so consider time t = 2s.

Force is change in velocity with respect to time multiplied by mass.

F = m dv/dt

F = 15 kg × 5.0 m/s/2s

F = 37.5 N

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The kinetic energy of a projectile of mass 8.30 g traveling with a speed of 1.10 km/s in the unit kiloJoules will be (a) 5.0215 KJ (b) 1.2553 KJ (c) 45.1935 KJ.

In the given question, following quantities of the projectile are given:

mass of the projectile, m= 8.30 g= 0.0083 kg

speed of the projectile, v= 1.10 km/s= 1100m/s

Since, according the Newton's law of motion, the formula for Kinetic Energy of an object is:

K.E.= 1/2 x mass of the object x (speed of the object)² Joules

K.E.= 1/2mv²

So,

(a) K.E.= 1/2 x 0.0083 kg x (1100 m/s)² = 5021.5 Joules = 5.0215 KJ.

(b) Since speed is reduced by a factor of 2, then,

new speed= 1100 m/s ÷2= 550 m/s

Now, K.E.= 1/2 x 0.0083 kg x (550 m/s)²= 1255.375 Joules= 1.2553 KJ.

(c) Since speed is increased by a factor of 3, then,

new speed= 1100 m/s x 3= 3300 m/s

Now, K.E.= 1/2 x 0.0083 kg x (3300 m/s)²= 45193.5 Joules= 45.1935 KJ.

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Because of location, the Hartsfield Jackson international airport has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport.

It should be noted that transportation simply means the movement of people and animals from one location to another. It should be noted that there are different means of transportation such as rail, air, road, etc.

In this case, because of location, the Hartsfield Jackson international airport has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport. This is located in Atlanta Georgia.

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Select the correct answer from each drop-down menu. Because of location, the has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport.

a. Dallas International Airport.

b. Denver International Airport.

c. John Kennedy International Airport

d. Hartsfield Jackson international airport

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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The resultant force acting on an aircraft window  is 5670 Newton when the aircraft is  flying at an altitude of 12 km.

The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. The pressure relative to the surrounding air is referred to as gauge pressure.

The pressure applied = 70 kPa = 70000 Pa.

The cross-sectional rea = 810 cm² = 0.081 m².

Hence, the force applied on the window = 70000 Pa × 0.081 m².

= 5670 Newton.

So, the resultant force acting on an aircraft window  is 5670 Newton.

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Answer:

300

Explanation Hope I'm not wrong.

Answer:

735 N

Explanation:

If a woman has mass 75kg and u know that mass is constant everywhere then just apply the formula W=mg...as gravity on earth is 9.8 m/s2 , so her weight will be 735 N...hope it helps...

If a woman has a mass of 75 kilograms then her weight on the earth would be 735.75 Newtons, because the weight of the woman is the multiplication of the mass of the woman and the acceleration due to the gravity of the earth.

It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another,

As given in the problem if a woman has a mass of 75 kilograms we have to find the weight of the woman,

The weight of the woman = mass of the woman × acceleration due to the gravity of the earth

                                           = 75 kilograms × 9.81

                                           =735.75 Newtons

Thus, the weight of a woman who has a mass of 75 kilograms would be 735.75 Newtons

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The speed of the car is 100 meters per second.

Speed is a measure of how quickly an object moves from one place to another. It is calculated by dividing the distance traveled by the time taken to cover that distance.

To find the speed of the car in meters per second, we need to convert the distance traveled from kilometers to meters and the time taken from seconds to hours.

Distance traveled = 4 km = 4,000 meters

Time taken = 40 seconds = 40/3,600 hours = 0.0111 hours

Now, we can use the formula:

Speed = Distance / Time

Speed = 4,000 meters / 0.0111 hours

Speed ≈ 360,360 meters per hour

Finally, to convert the speed to meters per second, we divide by 3,600 (the number of seconds in an hour):

Speed = 360,360 meters per hour / 3,600 seconds per hour

Speed ≈ 100 meters per second

Therefore, the speed of the car is approximately 100 meters per second.

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When a police car in hot pursuit goes speeding past you, the velocity v of the police car is 33 m/s.

The formula is used when there exists a Doppler shift. The Doppler shift is due to the relative motion of sound waves between the source and observer.

The frequency increase by the Doppler effect is represented by the formula

f' = \(\dfrac{v-v_{o} }{v-v_{s} }\)× f

Given the frequency of source f' is 5500 Hz . Velocity of the observer v₀  is 0.

Substituting the value into the equation will give us the velocity of the police car.

\(5500 = \dfrac{330}{330-v} \times f\)...........(1)

When the car is receding, the frequency of the receiving signal f = 4500 Hz.

\(4500 = \dfrac{330}{330+v} \times f\)..........(2)

Solving both equation, we get the velocity of a police car.

v = 33 m/s

Therefore, the velocity v of the police car is 33 m/s.

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The time taken for both trains to meet is 15000 s

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

With the above formula, we can obtain te time. Details b below

The following data were obtained from the question:

Speed = distance / time

80 = 1200000 / time

Cross multiply

80 × time = 1200000

Divide both side by 80

Time = 1200000 / 80

Time = 15000 s

Thus, the time taken for the two trains to meet is 15000 s

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The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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Answer:

Approximately \(9.39 \; {\rm m\cdot s^{-1}}\) after the sphere has travelled a distance of \(5\; {\rm m}\).

Approximately \(16.3\; {\rm m\cdot s^{-1}}\) right before touching the ground (a distance of \(15\; {\rm m}\).)

Assumption: \(g = 9.81\; {\rm N\cdot kg^{-1}}\).

Explanation:

Weight of the sphere: \(m\, g = 9.81\; {\rm N \cdot kg^{-1}} \times 10\; {\rm kg} = 98.1\; {\rm N}\), downwards.

Drag on the sphere: \(10.0\; {\rm N}\) upwards.

Net force on the sphere: \(98.1\; {\rm N} - 10\; {\rm N} = 88.1\; {\rm N}\) downwards.

Acceleration of the sphere: \(a = F_\text{net} / m = 88.1\; {\rm N} / (10\; {\rm kg}) = 8.81\; {\rm m\cdot s^{-2}}\).

Apply the SUVAT equation \(v^{2} - u^{2} = 2\, a\, x\), where \(v\) is the final velocity, \(u\) is the initial velocity (\(0\) in this case, as the sphere was released from rest,) and \(x\) is the distance (displacement) that the sphere has travelled so far.

Rearrange this equation to obtain an expression for \(v\):

\(\displaystyle v = \sqrt{2\, a\, x + u^{2}}\).

For example, after the ball travelled a distance of \(5.00\; {\rm m}\), \(x = 5.00 \; {\rm m}\):

\(\begin{aligned} v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 8.81\; {\rm m\cdot s^{-2}} \times 5.0\; {\rm m} + 0} \\ &\approx 9.39\; {\rm m\cdot s^{-1}}\end{aligned}\).

Similarly, \(x = 15.0\; {\rm m}\) right before landing, such that:

\(\begin{aligned} v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 8.81\; {\rm m\cdot s^{-2}} \times 15.0\; {\rm m} + 0} \\ &\approx 16.3\; {\rm m\cdot s^{-1}}\end{aligned}\).

The statement which best explains how market forces supply and demand guided the development of the new technologies is the statement: Engineers recognized the disparity in access to resources and decided to develop systems that would address the issue; option D.

Technology is the application of knowledge to reach practical goals.

Technology has affected our society and its surroundings in a number of ways which include:

In recent years, assistive technologies have been developed to give people with disabilities equal access to resources. Examples include wheelchair ramps, voice-recognition software, and screen readers.

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Complete question:

In recent years, assistive technologies have been developed to give people

with disabilities equal access to resources. Examples include wheelchair

ramps, voice-recognition software, and screen readers. Which statement best

explains how the market forces of supply and demand guided the

development of these technologies?

O A. As businesses became aware of the demand for equal access,

they began to invest in research and development to meet the

desires of their customers.

O B. As businesses developed assistive technologies, they began to

advertise their ability to provide equal access to consumers.

C. When assistive technologies became widely available, the public

demand for their universal adoption increased.

D. Engineers recognized the disparity in access to resources and

decided to develop systems that would address the issue.

Answer:

-45,597.07

Explanation:

if not in scientific calculator and yung answer nung sa scientific sa comment na lang dinadownload ko ka eh

(a) The average acceleration of this sprinter is 3.31 m/s².

(b) The time taken for the sprinter to reach the speed is 3.5 s.

The average acceleration of this sprinter is calculated as follows;

v² = u² + 2as

where;

v² = 0 + 2as

a = v² / 2s

a = ( 11.5² ) / ( 2 x 20 )

a = 3.31 m/s²

The time of motion of the sprinter is calculated as follows;

v = u + at

v = 0 + at

t = v / a

t = ( 11.5 ) / ( 3.31 )

t = 3.5 s

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The de- Broglie wavelength of 2.80× 10⁻¹⁰ m is associated with a momentum of 2.36 × 10⁻²⁴ Kg m/s. The kinetic energy will be 3.07 × 10⁻¹⁸ J which is equal to 19.015 ev.

De-Broglie proposed  the dual nature of matter which stated that matter can behave as both wave and particle. For a matter wave, the wavelength of the wave will be the ratio of the Planck's' constant h and its momentum p.

thus, λ = h/p

Given the wavelength = 2.80× 10⁻¹⁰ m.

momentum p = h/λ

= 6.62 × 10 ⁻³⁴ / (2.80× 10⁻¹⁰ m)

=  2.36 × 10⁻²⁴ Kg m/s

The kinetic energy ke = 1/2 mv² = p² /2m.

mass of an electron = 9.1 × 10 ⁻³⁴ Kg.

hence, Ke =  (2.36 × 10⁻²⁴ Kg m/s )² /  9.1 × 10 ⁻³⁴ Kg

                 = 3.07 × 10⁻¹⁸  J.

1 J = 6.24 × 10¹⁸ ev.

thus, KE in ev = 3.07 × 10⁻¹⁸  J ×  6.24 × 10¹⁸ ev = 19 ev.

Therefore, the kinetic energy of the electron is 19 ev.

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Answer:

The act of 'seeing' an object is the result of light from any luminous source e.g. the Sun, a glowing candle or a torch, radiating outwardly from the source until it strikes the object and is reflected to travel to the observer's eyes where if it retains sufficient intensity it will form an image on the retina. i hope this helps

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To determine the maximum velocity at which you can make a turn without slipping in the rain at the intersection, we need to consider the changes in friction.

Let's assume the normal static friction and normal kinetic friction are represented by μs and μk, respectively.

In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To avoid slipping during the turn, we need to ensure that the centripetal force required for the turn is less than or equal to the maximum frictional force available.

The centripetal force is given by the equation mv²/r, where m is the mass, v is the velocity, and r is the radius of the turn.

The maximum frictional force in the rain can be calculated as (0.5μs)mg, where g is the acceleration due to gravity.

Thus, to avoid slipping, we set the centripetal force equal to the maximum frictional force:

mv²/r = (0.5μs)mg

Simplifying the equation, we find:

v = √(0.5μsgr)

By plugging in the values for μs, g, and the radius of the turn, we can calculate the maximum velocity.

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The power of the motor can be calculated by dividing the work done (2400J) by the time taken (2 minutes). Therefore, the power of the motor is 2400J/120s = 20W.

Motor is a mechanical or electrical device that converts energy into motion. Motors are used in a variety of applications, including industrial, commercial, and residential. Examples of motors include electric motors, steam engines, and internal combustion engines. Electric motors use electrical energy to produce rotational mechanical energy, while steam engines produce rotational mechanical energy through the use of steam pressure. Internal combustion engines produce rotational mechanical energy through the combustion of fuel. Motors are used in a variety of applications, ranging from powering household appliances to running industrial machinery. In addition, motors are used to power various types of transportation, such as cars and boats. Motors are also used to power robotics in a variety of industries, including manufacturing and healthcare.

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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As there is only one force acting on the ball i.e. gravitational force, the acceleration will be constant and downward. Also because ball moves in the direction of the acceleration, the velocity increases.

Acceleration - constant; velocity - increasing.

What is Acceleration?

Acceleration is the rate of change of velocity of an object over time. It can be positive, negative, or zero. Positive acceleration is when an object speeds up, negative acceleration is when an object slows down, and zero acceleration is when an object's velocity remains constant.

What is velocity?

Velocity is a measure of the speed and direction of an object's motion. It is typically measured in meters per second (m/s) or kilometers per hour (km/h). Velocity can also be expressed in other units, such as miles per hour (mph) or feet per second (ft/s). Velocity is related to a object's acceleration, as an object's acceleration is the rate of change in its velocity over time.

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Answer:

No. A is correct because both warming up and cooling down are important

Both warming up and cooling down are important.

This is based on aerobics and human body balance regulation as regards exercising.

Warming up and cooling down in exercising are just based on the level of intensity at which the exercise is carried out.

Thus, Both warming up and cooling down are important.

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