Which process( photosynthesis, cellular respiration, both) do algae preform when incubated in the light? in the dark?
Answers
When algae are incubated in the light, they preform both photosynthesis and cellular respiration.
Photosynthesis is the process by which algae use energy from the sun, carbon dioxide, and water to create energy-rich molecules such as glucose and oxygen.
During this process, light energy is converted into chemical energy, which is then used by the cells of the algae to create the molecules they need for growth and development.
In contrast, when algae are incubated in the dark, they are unable to perform photosynthesis since the light energy needed for the process is not available. In this case, the algae rely solely on cellular respiration to generate the energy they need to survive.
During cellular respiration, the algae break down stored molecules such as glucose to generate energy. This energy is then used to power the cell’s activities, allowing the algae to continue to grow and develop even in the absence of light.
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Related Questions
what differences can you see between the fibers at this microscale? list at least two differences
Answers
When it comes to the differences between fibers at the microscale, there are several differences that can be observed.
When it comes to the differences between fibers at the microscale, there are several differences that can be observed. Here are two of the most prominent ones:Color - Fibers at the microscale differ in color. In particular, different types of fibers tend to have different hues, which makes it easy to differentiate between them. Some fibers, for instance, are white, while others are off-white, gray, or brown. Microscope - The type of microscope used to view fibers at the microscale can also make a significant difference. Different microscopes have different lenses, which can affect the way that the fibers appear. For example, some microscopes have polarizing filters that can be used to view fibers in different colors or patterns. Others have higher magnification levels, which can reveal more details about the fiber's structure. Finally, some microscopes have a built-in light source that can be used to illuminate fibers from different angles, which can also affect their appearance.
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Science!
7. The final stage in the sun's life cycle will be the ___?
1. planetary nebula stage
2. white dwarf stage
3. black dwarf stage
4. Ored giant stage
Answers
The sun will run out of nuclear fuel and slowly cool down over many billions of years.
the human intestinal tract has been likened to a culture vessel. the most commonly used lab culture systems include batch culture (growth in a test tube or flask) and chemostats. sort the following list of features into the appropriate categories depending on whether they are characteristic of a batch culture, the gut tract, a chemostat, or gut and chemostat. items (11 items) (drag and drop into the appropriate area below) a. fluid absorbed during culture
b. continuous removal of cells and fluid
c. mixed species
d. one-time supply of nutrients
e. cells do not exit
1. gut tract 2. chemostat
3. batch culture
4. gut & chemostat
Answers
1. Gut tract: c. mixed species, e. cells do not exit, a. fluid absorbed during culture
2. Chemostat: b. continuous removal of cells and fluid
3. Batch culture: d. one-time supply of nutrients
4. Gut & chemostat: none
The gut tract can be compared to a batch culture system, where the nutrients are supplied only once and the microbes grow in a closed system. The gut tract contains a mixed species of microbes, and the cells do not exit the system but are instead absorbed by the body or excreted.
The fluid in the gut tract is constantly being absorbed during the culture, which is not seen in batch cultures or chemostats.
A chemostat, on the other hand, is a continuous culture system where nutrients are constantly supplied to the system, and the waste and excess cells are continuously removed. This creates a more stable environment for the microbes to grow, and it can be used to study the effects of different nutrient levels on microbial growth.
Therefore, both the gut tract and chemostats are characterized by continuous growth, but the former has a mixed species and a one-time supply of nutrients, while the latter has a continuous supply of nutrients and continuous removal of waste and excess cells.
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I'll give you brainliest if u help me asap
Answers
Answer:
paramecium
Explanation:
How fast is the fastest growing plant?
Answers
The fastest growing plant is called the giant bamboo, which can grow up to 91 cm in just one day.
Detailed explanation: The giant bamboo, also known as Phyllostachys bambusoides, is considered the fastest growing plant in the world. It belongs to the bamboo family and is native to China.
The growth rate of giant bamboo can reach up to 91 cm in just one day under optimal conditions, which is an astonishing rate compared to other plants. This rapid growth is possible due to the plant's efficient system of nutrient absorption and photosynthesis.
However, it's important to note that the giant bamboo's growth rate may vary depending on various factors such as soil type, temperature, humidity, and the availability of water and light. Despite its rapid growth, the giant bamboo has a lifespan of about 15-20 years, after which it begins to deteriorate and eventually dies.
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Task:
write in tabular form
1. The method, observation and conclusion when carrying out tests for the following:
a. Reducing sugars
b. Lipids
c. Proteins
d. Starch
Thank you
Answers
Reducing Sugars : 1. Benedict's test2. Fehling's test3. Barfoed's test.. A brick-red precipitate indicates the presence of reducing sugar.The absence of a brick-red precipitate implies that there is no reducing sugar.The reddish-brown precipitate suggests the existence of monosaccharides.The existence of disaccharides is revealed by the green precipitate.
When conducting tests for reducing sugars, lipids, proteins, and starch, different methods, observations, and conclusions are employed. The methods used to carry out these tests differ depending on the substances being tested.The table below shows the methods, observations, and conclusions when carrying out tests for reducing sugars, lipids, proteins, and starch. Method Observation Conclusion
Lipids : 1. Emulsion test2. Solubility test .The formation of a milky white layer indicates the presence of lipids.The absence of a milky white layer implies the absence of lipids.The sample forms two separate layers during the test.The fat in the sample is the upper layer.
Proteins : 1. Biuret test2. Xanthoproteic test3. Millon's test The sample turns purple when Biuret's reagent is added to it.A yellow colour develops when Xanthoproteic acid is added to the sample.A brick-red precipitate shows that Millon's reagent was present.The existence of peptides or proteins is revealed by a purple or violet colour.
Starch : 1. Iodine testThe blue-black colour in the sample indicates the existence of starch.Absence of a blue-black colour shows the absence of starch.
Therefore, the above table indicates that the methods used, observations made, and conclusions drawn when carrying out tests for reducing sugars, lipids, proteins, and starch differ depending on the substances being tested.
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in a certain breed of plants, dark green is determined by the dominant allele 'g' and light green is determined by the recessive allele 'g'. all gg plants are dark green. however, in heterozygous gg plants penetrance of the dark green trait is only 75%.the parental cross gg x gg was made and dark green f1 offspring were intercrossed, and 400 f2 offspring resulted. how many dark green f2 plants would be seen? answer
Answers
If the parental cross GG x gg was made and dark green F1 offspring were intercrossed, and 400 F2 offspring resulted, the dark green F2 plants would be seen 300.
From the description, we are given:
Dark green = dominant allele GLight green = recessive allele gWhen we cross GG аnd gg, 100% of the offspring will be heterozygous. If the heterozygotes show 75% penetrаnce meаning thаt there is а 75% probаbility thаt the plаnt thаt hаs the G gene will аctuаlly show it in it's phenotype.
So thаt meаns thаt 75% of the offspring should hаve dаrk green color, which meаns thаt 300 plаnts will hаve the expected phenotype аnd 100 will not.
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True or false: The size and complexity of organisms is directly related to the number of total chromosomes it has. If false, make it a correct statement
Answers
I think the answer to this is true, but I'm not really for sure
Examine figure 2. How can MI be used as a predictor of survivability for
mast cell cancer? Be detailed in your explanation, citing evidence from the
data shown in Figure 1 and Figure 2.
Answers
It is to be noted that typically, a lower mitotic index is better. Rarer dividing cells mean a less aggressive cancer. The preferred number to hope for is a mitotic index of 5 or less.
What is a Mitotic Index?The mitotic index is defined as the ratio of the number of mitotic cells in a population to the total number of cells.
The mitotic index (the percentage of cells in mitosis at any one time) measures both the capacity and the pace of cell division. It is used to detect growth hotspots inside tissue and which cell types are proliferating.
It is to be noted that the lengths of the cell cycle and mitosis vary amongst cell types. A higher mitotic index suggests that more cells are dividing. The mitotic index in cancer cells may be higher than in normal tissue development or cellular healing at an injured site.
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sublimation process diagram
Answers
Explanation:
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Describe the organism (physical appearance, habitat, function, history, etc.). Draw or find a graphic that represents your organism. Detail the organism's method of reproduction: asexual or sexual type of gametes method of fertilization advantages and disadvantages of the reproduction type Note: your description and detail of the organisms should be at least 300 words.
Answers
Explanation:
In males, the penis comes out of the cloaca into the female cloaca when mating. ... To finish off, turtle mating, if the female's egg is fertilized, results in, with some exceptions of course, the female laying an average of a 100 to 200 eggs.
All turtles lay their eggs on land, and none show parental care. Amidst this apparent uniformity, however, there is a variety of reproductive behaviours, ecologies, and physiologies.
The age at which turtles first reproduce varies from only a few years to perhaps as many as 50, with small species typically reaching sexual maturity sooner. Female false map turtles (Graptemys pseudogeographica) of the central United States, for example, are about 8 cm (3.2 inches) long and become sexually mature at two to three years.
A train moving at speed of 50km/h. How many hours will it take the train to travel 600km
Answers
Answer: 12
Explanation:
600/50 is 12 so the answer is twelve
:
HELP ASAP
1 The intestines breed both helpful and harmful microorganisms.
True
False
2 A child is born with many microbes in his or her body.
True
False
3 A child is usually born with all of microorganisms that live in the human mouth.
True
False
4 The intestines are a good breeding place for microbes.
True
False
5 Animals provide a means to test and understand various disease germs.
True
False
Answers
Answer:
1. True.
2. False.
3. False.
4. True.
5. True.
Explanation:
1. True: The intestines breed both helpful and harmful microorganisms. This relationship between the host and these microorganisms is called a symbiotic relationship.
2. False: A child is born with many microbes in his or her body. Basically, it has been established that there are no microbes in the womb of pregnant women (mothers) and as such babies are not exposed to any microbe until when they are born.
3. False: A child is usually born with all of microorganisms that live in the human mouth. This is false as well because the womb and placenta is essentially free of bacterias, fungi and other microbes.
4. True: The intestines are a good breeding place for microbes. This is completely true because of the regulated temperature and it mainly contains foods which the microorganisms live on.
5. True: Animals provide a means to test and understand various disease germs. Animals such as squirrels, rats, mice, frogs, monkeys are all used as specimens for testing and understanding various diseases and germs.
Bats have oversized ears which help the pets you sound waves to detect the motion of their prey which example of the characteristics of life is most similar
Answers
the relationship between the steroid hormone, estrogen, and the peptide hormone, insulin, is being investigated. in order to quantify levels of each of these hormones, tissue samples were homogenized and then placed in a mixture of 2:1 hexane/water. what is the expected result from this extraction method?
Answers
The correct option is a) oestrogen would be in the hexane phase; and insulin would be in the aqueous phase.
The regulation of the female menstrual cycle and the growth and development of females depend on the hormone oestrogen. An essential hormone that controls blood sugar is insulin. According to the structural characteristics of peptides and steroids, oestrogen is hydrophobic and insulin is hydrophilic. The hydrophobic oestrogen hormone would segregate into the hexane phase, whereas the hydrophilic insulin peptide would be anticipated to be present in the aqueous phase.
Hexane and water in a 2:1 ratio are combined with the hormones insulin and oestrogen. Because it is a hydrophilic molecule, insulin dissolves readily in water. Hydrophobic molecules like oestrogen readily dissolve in hexane.
Thus, alternative is the right response (A).
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Explain how the atoms in sugar molecules can be used to form amino acids and other large carbon based molecules?
Answers
Answer: Sugar molecules contain carbon, hydrogen, and oxygen: Their hydrocarbon backbones are used to make amino acids and other carbon-based molecules that can be assembled into larger molecules (such as proteins or DNA), used for example to form new cells.
Explanation:
easy points i think. Just find the definitions and post here please dw abt the sources I'll do that part easy peasy.
Answers
Anti-codon- a sequence of three nucleotides forming a unit of genetic code in a transfer RNA molecule
Ribosome- a complex molecular machine that produces proteins from amino acids. They are found in both prokaryotic and eukaryotic cells
Double-helix- the structure formed by double-stranded molecules of nucleic acids
Lysine- a building block for protein and an essential amino acid
What is 3.5% of 11? Round to the nearest hundredth
Answers
Answer:
. 39
Explanation:
11 times 0.035 equals .385
hope this helps you :)
Answer:
\(\huge\boxed{\sf 0.39}\)
Explanation:
=> 3.5 % of 11 [% means out of 100 and of means to multiply]
=> \(\sf \frac{3.5}{100} * 11\)
=> 0.035 * 11
=> 0.385
≈ 0.39 [Nearest hundredth]
Hope this helped!
~AnonymousHelper1807
QUESTION 1 Exercise 11.10. Butterflies. Alice, Bob, and Charlotte are looking for butterflies. They look in three separate parts of a field, so that their probabilities of success do not affect each other. • Alice finds 1 butterfly with probability 17%, and otherwise does not find one • Bob finds 1 butterfly with probability 25%, and otherwise does not find one • Charlotte finds 1 butterfly with probability 45%, and otherwise does not find one Let X be the number of butterflies that they find altogether. Write X as the sum of three indicator random variables, X1, X2, X3 that indicate whether Alice, Bob, Charlotte (respectively) found a butterfly. Then X= X1+X2 +X3. Find the expected value of X by finding the expected value of the sum of the indicator random variables. Your answer will have two decimal places. **This is a straight forward expected value of a sum of random variables, nothing fancy here! QUESTION 2 Exercise 11.16. Flipping coins. Flip a coin until the second head comes up. Let X be the number of flips needed to get the second head. What is the E(X). The first step is to find the expected value of getting the first head. Is this like Example 11.10, sampling without replacement, OR like Example 11.11, sampling with replacement? O A. Example 11.10, sampling without replacement O B. Example 11.11, sampling with replacement QUESTION 3 Exercise 11.16. Flipping coins. Flip a coin until the second head comes up. Let X be the number of flips needed to get the second head. What is the E(X). The first step is to find the expected value of getting the first head. What is the expected value of getting the first head? This will be an integer answer. QUESTION 4 Exercise 11.16. Flipping coins. Flip a coin until the second head comes up. Let X be the number of flips needed to get the second head. What is the E(X). The next step is to find the expected value of getting the second head. Because this is identical to finding the expected number of rolls for the first head (independent events), we just multiply the first head's expected value by 2. This will be an integer answer. QUESTION 5 Exercise 11.17 (a). Waiting for favorite song. Michael puts his iTunes on shuffle mode where songs are not allowed to be replayed. He has 2,781 songs saved on iTunes, and exactly one of these is his favorite. How many songs is he expected to have to listen to until his very favorite song comes up? Is this like Example 11.10, sampling without replacement, OR like Example 11.11, sampling with replacement? A. Example 11.11, sampling with replacement B. Example 11.10, sampling without replacement
Answers
In Exercise 11.10, the expected value of the number of butterflies found by Alice, Bob, and Charlotte is obtained by finding the expected value of the sum of three indicator random variables.
In Exercise 11.16, the expected value of the number of flips needed to get the second head in a coin flipping experiment is determined. These exercises involve different scenarios of sampling with and without replacement.
In Exercise 11.10, the expected value of X, the total number of butterflies found, is found by calculating the expected value of each indicator random variable (X1, X2, X3) representing whether Alice, Bob, and Charlotte found a butterfly, respectively.
The expected value of each indicator variable can be obtained by multiplying the probability of success (finding a butterfly) by 1 and the probability of failure (not finding a butterfly) by 0. Then, the expected value of X is calculated as the sum of the expected values of the indicator variables.
In Exercise 11.16, the expected value of X, the number of flips needed to get the second head, is determined. To find this value, we first need to find the expected value of getting the first head. This scenario is similar to Example 11.11, which involves sampling with replacement.
Each coin flip is an independent event, and the probability of getting a head is constant at 0.5.
Therefore, the expected value of getting the first head is 1/p, where p is the probability of success (0.5 in this case).
In Exercise 11.17 (a), the scenario of waiting for a favorite song in Michael's iTunes playlist involves sampling without replacement. Each song played is not replayed, and there is only one favorite song among the total number of songs.
Therefore, this scenario is similar to Example 11.10, sampling without replacement.
To find the expected number of songs Michael needs to listen to until his favorite song comes up, the formula for sampling without replacement is used, which is the reciprocal of the probability of selecting the favorite song at each step.
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Sheryl is observing ovarian slides taken from a female ape. All the cells show crossover chromosomes. What is this stage?
A.
meiotic prophase I
B.
meiotic prophase II
C.
meiotic metaphase
Answers
The ovarian slides taken from the female ape will show crossover chromosomes in (A) meiotic prophase I.
Crossing over is the event that occurs during Prophase of Meiosis I. During this event, the exchange of genetic material occurs between two non-sister chromatids of two homologous chromosomes. This occurs to produce the recombinants having genotype different from both the parents.
Meiotic Prophase I is the longest and most complex phase of Meiosis. The phase is further divided into stages. These are: Leptotene. Zygotene. Pachytene, Diplotene and Diakinesis. Many of the crucial events of Meiosis like synapsis formation, recombination, etc. occur in this phase.
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during inoculation, the blood agar plate should be stabbed with the inoculating loop. the purpose of this is to:
Answers
During inoculation, the blood agar plate should be stabbed with the inoculating loop. The purpose of this is to increase the surface area of the agar exposed to the bacteria and ensure growth of bacteria both aerobically and anaerobically.
When the inoculating loop is stabbed in the blood agar plate, the surface area of the agar that is exposed to the bacteria is increased. This allows the bacteria to grow more easily, which is crucial for identifying and studying the microorganisms present in the sample.
Stabbing the agar also enables the bacteria to grow both aerobically and anaerobically by allowing oxygen to diffuse into the agar at the surface and enabling bacteria to grow anaerobically in the deeper regions of the agar. It also helps to distribute the bacteria evenly throughout the agar and prevents the formation of concentric colonies. By using this technique, the growth of bacteria is ensured and the presence of various microorganisms can be accurately observed.
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A blood test to measure cholesterol and triglycerides in the circulating blood is a(n):
Answers
A blood test to measure cholesterol and triglycerides in the circulating blood is a lipid profile.
The lipid profile assesses several different elements of cholesterol in your blood that play important roles in heart disease development. The test will assess your entire cholesterol profile, which includes your levels of high-density lipoprotein (HDL) or "good" cholesterol, low-density lipoprotein (LDL) or "bad" cholesterol, and triglycerides, a type of fat that is stored in your body. This test is crucial for people with an increased risk of heart disease or with a history of heart disease in their family. The triglyceride blood test measures the amount of triglycerides in the bloodstream. Triglycerides are a type of fat that the body utilizes for energy. People with high triglycerides levels have a higher risk of cardiovascular disease. A blood test is the only way to diagnose high triglycerides, and a lipid panel or a fasting triglyceride test are two types of blood tests that can help diagnose this condition.
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What are some specific decomposers of the savanna?
Answers
Answer:
Bacteria. Bacteria are key decomposers of any biome, their large numbers allowing them to widely colonize a habitat's soil. ...
Fungi. In drier climates like savannas, lower soil moisture leads to fungi being less widely distributed than decomposers like bacteria. ...
Earthworms. ...
Insects.
Explanation:
Hope this helps.
In the Lysozyme Activity portion of this exercise, lysozyme will be added to a microbial culture. Predict what you will observe in this activity if your culture is affected by the action of lysozyme O A decrease in absorbance will be observed over time, An increase in absorbance will be observed over time An increase in turbidity will be observed over time. A change in color will be visible in the tube
Answers
A decrease in absorbance will be observed over time," is the correct answer.
If the culture is affected by the action of lysozyme, a decrease in turbidity will be observed over time. Lysozyme is an enzyme that degrades the cell wall of bacteria, causing the cells to lyse or rupture. As a result, the number of intact bacterial cells in the culture will decrease, leading to a decrease in turbidity. The decrease in turbidity can be measured by a decrease in absorbance at a specific wavelength using a spectrophotometer. Therefore, option A, "A decrease in absorbance will be observed over time," is the correct answer.
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Can anybody help answer this? please, thank you
Answers
Answer:
They all have leaves, petals, and stems.
Acknowledgment messages are a fast and efficient way of transmitting frequently recurring messages to which receiver reaction is likely favorable or neutral.
Indicate whether the statement is true or false
Answers
The statement is true. Acknowledgment messages are indeed a fast and efficient way of transmitting frequently recurring messages to which the receiver's reaction is likely to be favorable or neutral.
Acknowledgment messages are commonly used to acknowledge receipt of information or confirm the completion of a task. They are typically brief and serve to indicate that a message has been received and understood. These types of messages are often used in various communication channels, such as email, instant messaging, or even automated systems.
The statement suggests that acknowledgment messages are effective when the receiver's reaction is expected to be favorable or neutral. This implies that the receiver is likely to appreciate or have no objections to the message being acknowledged. In such cases, acknowledgment messages can be sent quickly and efficiently, without requiring a lengthy response or further discussion.
For example, in a business setting, when an employee submits a report to their supervisor, the supervisor can simply send an acknowledgment message to confirm receipt of the report. This saves time for both parties involved and allows them to proceed with their respective tasks. Similarly, in customer service, an automated acknowledgment message can be sent to customers after they make a purchase or submit a support request, assuring them that their transaction or inquiry has been received.
By using acknowledgment messages for recurring scenarios where the receiver's reaction is likely to be favorable or neutral, organizations can streamline their communication processes and enhance efficiency. It eliminates the need for unnecessary back-and-forth exchanges, enabling individuals to focus on more critical tasks or address issues that require further attention.
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pls i want help on this sum
Answers
━━━━━━━☆☆━━━━━━━
▹ Answer
a. $103.50
b. £4400
▹ Step-by-Step Explanation
$90 * 0.15 = $13.50
$90 + $13.50 = $103.50
£5000 x 0.12 = £600
£5000 - £600 = £4400
Hope this helps!
- CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
Which statement is true based on the data in the table ?
Answers
Answer:
Hey there is no complete question, we can't understand
Please write a complete question so that we can answer
Answer:
is c
Explanation:
The United States uses more land for parks and forests than for urban areas.
A 2 column by 6 row table. Column 1 is titled Land and contains the following entries: crop, forest, grass or range, parks or wildlife or others, urban. Column 2 is titled Size of Land in million acres, and contains the following entries: 408, 671, 614, 313, 61.
Which statement is true based on the data in the table?
a The United States uses more land to grow crops than to maintain forests.
b The United States uses more land for parks and wildlife than for forests.
c The United States uses more land for parks and forests than for urban areas.
d The United States uses more land for urban areas than for grasslands and ranges.
Can you help me please?
Answers
Pls help meeeeee plsssssss
