Explanation:
The angle that represents an exterior angle of is: d. ∠CAB
An exterior angle of a triangle is an angle outside the triangle that is adjacent to an interior angle of a triangle, and also shares same side together.
An illustration of an exterior angle of a typical triangle has been shown in the diagram attached below.
The angle that is marked green is an exterior angle.
Analyzing the diagram given for this question, the only exterior angle of triangle ABF from the list of answer choices given is <CAB.
Therefore, the angle that represents an exterior angle of is: d. ∠CAB
A body is found at 9:30pm. The temperature of the liver registers 84.6F what is the approximate TOD of the victim
The approximate TOD of the victim is Maybe around 4:30 pm.
How can you gauge the temperature of your liver?The liver temperature can provide a more accurate representation of the genuine core body temperature, hence it is ideal to take the temperature either rectally or by monitoring the liver temperature.To do this, a tiny incision must be made in the right upper belly, and the thermometer must be inserted into the liver tissue.
How is the death date determined?This stiffening process, known as rigor mortis, occurs at a fairly known time, making it possible to predict when someone will pass away.In overall: If the body is warm and there is no rigidity, the time of death was less than three hours ago.If the body is stiff and warm, death happened 3 to 8 hours earlier.
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Three long, straight wires separated by 0.10 m carry currents of 18 A and 6 A in the directions shown below. 18 A 18A 0.05 m 6 A P wire 1 0.10 m 0.10 m 09 11. Determine the magnitude of the magnetic field at point P.
The magnetic field at point P is 2.4 x \(10^-^5\) T.
To determine the magnitude of the magnetic field at point P, we can use the formula for the magnetic field created by a straight current-carrying wire. The magnetic field created by wire 1 carrying a current of 18 A is given by:
B1 = μ0I1/2πr1
where r1 is the distance from wire 1 to point P, I1 is the current flowing through wire 1, and μ0 represents the permeability of empty space.
Substituting the given values, we get:
B1 = (4π x \(10^-^7\) Tm/A) x (18 A)/(2π x 0.05 m) = 0.45 x \(10^-^5\) T
Similarly, the magnetic field created by wire 2 carrying a current of 6 A is:
B2 = μ0I2/2πr2
where r2 is the distance between wire 2 and point P, and I2 is the current flowing via wire 2.
Substituting the given values, we get:
B2 = (4π x \(10^-^7\) Tm/A) x (6 A)/(2π x 0.10 m) = 1.2 x \(10^-^6\) T
The magnetic field created by wire 3 can be ignored since it is perpendicular to the plane containing wires 1 and 2.
Hence, the vector combination of the magnetic fields produced by wires 1 and 2 at location P represents the entire magnetic field there:
B = √(\(B1^2\) + \(B2^2\)) = √((0.45 x \(10^-^5\) \(T)^2\) + (1.2 x \(10^-^6\) \(T)^2\)) = 2.4 x \(10^-^5\) T
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Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?
Answer:
Explanation:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.
Hence, his average velocity is 300m/150s=2ms^−1
(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.
Therefore, his average speed for this journey is 400m210s=1.9ms−1.
For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.
Hence, his average velocity for this case is 200m/210s=0.95ms^−1
A part is specified with a tensile strength minimum only (no maximum specification).
It has a Cp = 1. 2. Please determine the reject rate. RR = _______________
1. A part is specified with a tensile strength 2 sided specifications. Assume process average is centered and two sided specifications. It has a Cpk = 1. 2. Please determine the reject rate. RR = _______________
2. A part is specified with a tensile strength 2 sided specifications.
It has a Cp = 0. 7. Please determine the reject rate. RR = _______________
3. A part is specified with a tensile strength minimum only (no maximum specification).
It has a Cp = 1. Please determine the reject rate. RR = _______________
4. A part is specified with a tensile strength minimum only (no maximum specification). Assume process average is centered and one-sided specifications.
It has a Cpk = 1. 3. Please determine the reject rate. RR = _______________
5. A part is specified with a tensile strength minimum only (no maximum specification).
It has a Cp = 1. 2. Please determine the reject rate. RR = _______________
6. A part is specified with a tensile strength 2 sided specifications. Assume process average is centered and two sided specifications. It has a Cpk = 1. 1. Please determine the reject rate. RR = _______________
7. A part is specified with a tensile strength 2 sided specifications.
It has a Cp = 0. 6. Please determine the reject rate. RR = _______________
8. A part is specified with a tensile strength minimum only (no maximum specification).
It has a Cp = 1. 25. Please determine the reject rate. RR = _______________
9. A part is specified with a tensile strength minimum only (no maximum specification). Assume process average is centered and one-sided specifications.
It has a Cpk = 0. 8. Please determine the reject rate. RR = _______________
To determine the reject rate (RR) for each scenario, we need to consider the capability indices Cp and Cpk along with the specifications for tensile strength. The reject rate represents the proportion of parts that do not meet the specifications.
1. RR = 0.27%
2. RR = 16.03%
3. RR = 0%
4. RR = 0.003%
5. RR = 0.27%
6. RR = 2.28%
7. RR = 29.93%
8. RR = 0%
9. RR = 5.87%
Please note that these calculations assume a normal distribution of tensile strength and that the process is in statistical control. The reject rate is obtained by evaluating the proportion of values falling outside the specified limits based on the process capability indices Cp and Cpk.
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2
Select the correct answer.
What does the law of conservation of energy state?
OA.
Energy can be created from nothing.
OB.
Energy cannot be destroyed.
O C.
Energy cannot change forms.
OD.
The total amount of energy in a system changes continuously.
Answer:
D
Explanation:
The total amount of energy and matter in the Universe remains constant, merely changing from one form to another. The First Law of Thermodynamics (Conservation) states that energy is always conserved, it cannot be created or destroyed. In essence, energy can be converted from one form into another.
Answer: B) Energy cannot be destroyed
Explanation:
I had this question on a recent test and I got it right
Hope this helps! :)
A wave is sent down a thick rope that is attached to a thinner rope. What happens when the wave reaches the junction? Explain in words, or draw a diagram.
Answer:
A fraction of the wave will be reflected at the junction and the remainder will be transmitted through the junction into the thin rope
Explanation:
When the junction of the thin and the thick rope is reached by the wave, the wave behaves in the following two ways;
1) A fraction of the incident wave from the thick rope to the junction/boundary of the thin rope will be reflected back to in the direction of the thick rope with a lower amplitude and upright
2) A fraction of the incident wave from the thick rope to the junction/boundary of the thin rope will be transmitted through the thin rope such that the transmitted pulse on the thin rope will have an higher amplitude than that of the thick rope due to the available energy in the wave pulse and the lesser weight of the thin rope.
Qs # 1. A satellite orbits earth with a mean altitude of 361 Km. If the orbit is
circular, what are the satellite's time period and speed?
Qs # 2. The same satellite from problem # 1 orbits Jupiter at the same altitude
as before i.e 361 Km. what are the new Time Period and speed?
Answer:
40.6789km
243.098km
Explanation:
Apartment traveling on a straight road at 15.0m/s accelerate uniformly to a speed of 21.0m/s in 12.0 seconds the total distance traveled by the car in this 12.0 seconds time interval is
By using uniform motion, the distance traveled by the car is 216 m.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 15 m/s
vt = 21 m/s
t = 12 s
Find the acceleration
vt = vo + a . t
21 = 15 + a . 12
12a = 6
a = 0.5 m/s²
By using the third equation, we can calculate the distance
s = vo . t + 1/2 . a . t²
s = 15 . 12 + 1/2 . 0.5 . 12²
s = 180 + 36
s = 216 m
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Select the part of a plant which plays the most important role in the germination cycle. fruit pistil seed stamen
The seed is the most important part of a plant for the germination cycle.
The seed plays the most important role in the germination cycle as it contains the embryo of the plant and all the necessary nutrients for growth. The other parts of the plant such as the fruit, pistil, and stamen have roles in reproduction but not directly in the germination process.
The part of a plant that plays the most important role in the germination cycle is the seed.
In summary, the seed is the most important part of a plant for the germination cycle.
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How much heat is required to increase the temperature of 1 kg of steel from 21 °C to 22 °C?
9,000 j
306j
1j
500j
Answer:
466J
Explanation:
Given parameters:
Mass of steel = 1kg = 1000g
Initial temperature = 21°C
Final temperature = 22°C
Unknown:
Amount of heat required for this temperature increase = ?
Solution:
To solve this problem, we use the expression below:
So;
Heat absorbed = mass x specific heat of steel x change in temperature
Specific heat of steel = 0.466J/g°C
Therefore;
Heat absorbed = 1000 x 0.466 x (22 - 21) = 466J
henry bought 1/4 pound of screws and 2/5 pounds of nails to build a skate board ramp what is the total of the screws and nAils
The total weight of screws and nails that Henry bought to build the skate board ramp is 13/20 pounds.
To find the total weight of screws and nails, we need to add the weight of the screws and the weight of the nails.
Henry bought 1/4 pound of screws and 2/5 pounds of nails, so
Total weight = 1/4 + 2/5 pounds
Total weight = (1 x 5)/(4 x 5) + (2 x 4)/(5 x 4) pounds
Total weight = (5/20) + (8/20) pounds
Now that both fractions have the same denominator, we can add them together,
Total weight = 13/20 pounds
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--The complete question is, henry bought 1/4 pound of screws and 2/5 pounds of nails to build a skate board ramp what is the total weight of the screws and nails?--
The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis. Which best lists the titles of each column?
Column 1 should be titled “Time,” and Column 2 should be titled “Velocity.”
Column 1 should be titled “Velocity,” and Column 2 should be titled “Time.”
Column 1 should be titled “Time,” and Column 2 should be titled “Acceleration.” Column 1 should be titled “Acceleration,” and Column 2 should be titled “Time.”
Answer:
the correct answer is A
Answer:
Column 1 should be titled “Time,” and Column 2 should be titled “Velocity.”
Explanation:
A 25.0 kg door is 0.925 m wide. A customer
pushes it perpendicular to its face with a 19.2
N force, and creates an angular acceleration
of 1.84 rad/s2. At what distance from the axis
was the force applied?
[?] m
Hint: Remember, the moment of inertia for a panel
rotating about its end is I = mr².
The distance from the axis of the force applied is 2.05 m.
What is the distance from the axis of the force applied?The distance from the axis of the force applied is calculated as follows;
The formula for torque;
τ = Fr
where;
F is the applied forcer is the distance from the axis of the force appliedAnother formula for torque is given as;
τ = Iα
where;
I is the moment of inertia of the doorα is the angular acceleration;τ = (mr²)α
τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)
τ = 39.36 Nm
The distance is calculated as;
r = τ/F
r = ( 39.36 Nm ) / (19.2 N)
r = 2.05 m
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A baseball is thrown horizontally at 46 m/s. The ball slows down at a rate of 5 m/s2. How long
is the ball in the air before coming to rest?
Answer:
9.2 sExplanation:
Using one of the equation of motion v = u + at where;
v is the final velocity = 0m/s (the ball comes to rest after throw)
u is the initial velocity = 46m/s
a is the acceleration = -5m/s² (the body decelerates)
t is the time taken by the ball in air
substituting the given parameters into the formula to get t, we will have;
0 = 46 +(-5)t
0 = 46 - 5t
subtract 46 from both sides
0-46 = 46-5t-46
-46 = -5t
Divide both sides by -5
-46/-5 = -5t/-5
t = 46/5
t = 9.2seconds
Hence it will take the ball 9.2seconds in the air before coming to rest.
Answer: 9.2sec
Explanation. 9.2sec
find vector fields hx,hy,hz such that for a body w immersed in a liquid of density ⇢0 at height z0 the total buoyancy force f = hfx, fy, fzi exerted on w is given by surface integrals
These equations represent the vector fields Hx, Hy, Hz that describe the total buoyancy force exerted on the body immersed in the liquid.
To find the vector fields Hx, Hy, Hz that represent the buoyancy force exerted on a body immersed in a liquid, we can start with the definition of buoyancy force.
The buoyancy force is equal to the weight of the fluid displaced by the body. Mathematically, it can be expressed as:
F = ∫∫∫ (ρ_0 - ρ(z)) * g dV,
where F is the buoyancy force vector, ρ_0 is the density of the surrounding fluid at height z0, ρ(z) is the density of the fluid at height z, g is the acceleration due to gravity, and dV is the differential volume element.
Now, we can write the vector fields Hx, Hy, Hz in terms of the surface integrals of the density function ρ(z) over the body's surface.
Hx = ∫∫ (ρ_0 - ρ(z)) * nx dS,
Hy = ∫∫ (ρ_0 - ρ(z)) * ny dS,
Hz = ∫∫ (ρ_0 - ρ(z)) * nz dS,
where nx, ny, nz are the components of the outward unit normal vector to the surface, and dS is the differential surface element.
Note that the integral is taken over the surface of the body. The direction of the normal vector should be outward, pointing away from the body.
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An airplane is trying to land on the runway using the path below. (The vectors are drawn in the diagram)
terminal building
200 m
150 m
200 m
250 m
Tunway
What is the total distance traveled by the airplane? Please include the number and unit.
What is the magnitude of the airplane's displacement? Please include the number and unit.
What was the direction of the airplane's displacement? Please abbreviate (N, S, E, W. or some combination)
Explanation:
The given figure shows the path of an airplane that is trying to land on the runway using the path below.
(a) Distance is the total path covered.
D = (200+150+200+250) m
D = 800 m
(b) Initially, it was moving 200 m due east and finally it reaches 250 m due south. But displacement is the shortest path covered. O is the initial position and B is the final position.
Displacement = OA+AB
=(150 +250) m = 400 m
(c) The Airplane's displacement is in the south direction.
a galvanometer can be converted to an ammeter by the addition of a select one: a. large resistance in series. b. small resistance in parallel. c. small resistance in series. d. large resistance in parallel.
A galvanometer can be converted to an ammeter by the addition of a c. small resistance in series.
A galvanometer is a device used to measure current, and by adding a small resistance in series, the current can be limited, allowing for more accurate measurements. To put it simply, a galvanometer consists of a coil of wire, which has a needle attached to it. When a current is passed through the wire, the needle will deflect, showing the direction and magnitude of the current. By adding a small resistance in series, the current can be limited, and the resulting current can be measured with an ammeter. This process allows for more accurate measurements and can be used in many different scenarios, such as in circuit design.
To summarize, a galvanometer can be converted to an ammeter by adding a small resistance in series. This allows for more accurate measurements of current and can be used in many different scenarios.
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_______________ is the name for the process that causes fertile land to become desert-like.
Answer:
desertification
Explanation:
sorry if wrong
Answer:
The answer is Desertification.
Explanation:
Desertification causes land to dry up and become desert-like making the land lose its fertileness.
Write two reasons for using mercury in a thermometer ️️
Answer:
my first reason is that Mercury is the only one in liquid state at room temperature and thermometers because it has high coefficient of expansion . my second reason is that mercury its can changes in temperature, the mercury expands and contracts, and the temperature can be read from the scale, and also Mercury thermometers can be used to determine body, liquid, and vapor temperature.
PLEASE HELP, NO ONE IS HELPING MEEEE :(
While taking the stairs it takes you 10 seconds to reach the top. The next time you take the same stairs, it takes you 5 seconds to reach the top stair. During which of these trips up the stairs did you use more power to climb?
Answer:
probably the trip where it took u 5 seconds
One more bulb is added to the circuit and the location of the switch is changed. The new circuit is shown in the figure. (figure 2) bulbs a, b, c, and d are identical and the switch is an ideal conductor. How does closing the switch in the figure affect the potential difference?.
The potential difference across a, b is mathematically given as
E_a=0.5
E_b= 0
Potential difference across a, bGenerally the equation for the switch when closed is mathematically given as
\(Rc=Ra+\frac{Rb}{2}\)
Therefore
Rc=3R/2
Where
\(va=2R/3R *e\)
va=2/3* e
vb=vc=(2/3e)
When switch is closed
va=e
vb=vc=0
Therefore potential difference across a is
\(E_a=\frac{e-2/3e}{2/3e}\)
E_a=1/2
E_a=0.5
And potential difference across b is
E_b= 0
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Which gas makes up approximately 1% of Earth’s atmosphere?
Answer:
Argon is the third most abundant gas in our atmosphere, making up about one percent in terms of moles of gas.
Explanation:
Roughly, our atmosphere is 78% nitrogen, 21% oxygen, 1% argon, and trace amounts of many other gases plus variable amounts of water vapor.
what are the S.I units of K so that the equation Velocity = K × density is dimensionally correct ? Give your answer in terms of the basic units. ( Kg-¹m45-¹)
The S.I units of K so that the equation Velocity = K × density is dimensionally correct is M^-1.L^3.T^-1 [L^3.M^-1.T^-1]
What is an S. I Unit?The most extensively used system of measuring in the world is the International System of Units, sometimes known as the SI system and abbreviated SI in all languages. It is the current version of the metric system.
Attached in this answer is the straightforward solution of the question and this shows the dimensional correctness needed after the equation Velocity = K × density has been solved,.
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A 90.0 kg person is sitting 1.00 m away from a 60.0 kg person at a football game. What is the gravitational force between them
Answer:
The force is \(36*10^-^9 N\)Explanation:
According to newtons law on gravitation formula, which we are going to apply,
\(F= \frac{Gm1m2}{d^2}\)
Where G represents universal gravitation constant, \(6.67*10^-^1^1 N.m^2/kg^2\)
Given data
m1= 90 kg
m2= 60 kg
d= 1 m
Substituting our given data into the formula we have
\(F= \frac{6.67*10^-^1^1*90*60}{1^2}\)
\(F= \frac{6.67*10^-^1^1*5.4*10^3}{1^2}\\\\F= 36*10^-^9 N\)
The gravitational force between the two people in the football game is 3.6 * 10⁻⁷ N
Newton's law of gravitation states that the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
F = Gm₁m₂/r²
G is the gravitational constant = 6.67 * 10⁻¹¹ N.m²/kg, m₁ = first mass = 90 kg, m₂ = second mass = 60 kg, r = distance = 1 m
F = Gm₁m₂/r²
F = 6.67 * 10⁻¹¹ N.m²/kg * 90 kg * 60 kg / 1² = 3.6 * 10⁻⁷ N
The gravitational force between the two people in the football game is 3.6 * 10⁻⁷ N
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A car travels 18 km / h to the northwest. What is the speed of this car seen from another car going south at 60 km / h?
Answer:
73.8 km/h
Explanation:
The velocity of object A relative to object B is:
v = va − vb
Let's say east is +x and north is +y, and angles are measured from +x.
The velocity of the first car in the x direction is:
18 km/h cos 135° = -9√2 km/h
The velocity of the first car in the y direction is:
18 km/h sin 135° = 9√2 km/h
The velocity of the second car in the x direction is:
60 km/h cos 270° = 0 km/h
The velocity of the second car in the y direction is:
60 km/h sin 270° = -60 km/h
The relative velocity in the x direction is:
vₓ = -9√2 km/h − 0 km/h = -9√2 km/h ≈ -12.7 km/h
The relative velocity in the y direction is:
vᵧ = 9√2 km/h − (-60 km/h) = 9√2+60 km/h ≈ 72.7 km/h
The speed, or magnitude of the velocity, is:
v = √(vₓ² + vᵧ²)
v = √((-12.7 km/h)² + (72.7 km/h)²)
v ≈ 73.8 km/h
Which situation results in no work being done?
O lifting an object off the ground
O throwing a baseball to your friend
O carrying a book at a constant velocity
O pushing a car that will not start out of the garage
Answer:
C
Explanation:
C should be the right answer
An object weighing 1.840 kg has a volume of 0.0015 m 3. what is the density of the object in g/cm3?
Answer:
1,226,666.6666 g/cm3
Explanation:
Density =Mass/Volume
=1.840 kg(×1000g) / 0.0015
=1,226,666.6666666 g /cm3
multiple choice
15) A coiled spring used to help a door close has ________ ________energy when the door is open.
16) After braking, a bicycle's tires increase in temperature as friction causes some of the
mechanical energy to transfer to ________ energy.
According to conservation of energy, the energy of interacting bodies in a closed system remains constant. The total energy of an isolated system remains constant; it is said to be conserved over a period of time.
Elastic energy is the mechanical implicit energy stored in the configuration of a material or physical system as it's subjected to elastic distortion by work performed upon it. Elastic energy occurs when objects are impermanently compressed, stretched or generally misshaped in any manner.
The mechanical energy is never lost forever , rather it gets converted to thermal energy because of the friction .
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the particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, increasing its kinetic energy by 1.12×10−18 j . in what direction and through what potential difference vb−va does the particle move?
Particle moves from point a to point b in direction of increasing electric potential, and potential difference between point a and point b is positive.
Electric force is conservative, so work done by electric force is equal to change in potential energy. We know that ΔK = 1.12×10−18 J, and since the particle is initially at rest, its initial kinetic energy is zero. 1.12×10−18 J = -ΔU or ΔU = -1.12×10−18 J
Since electric force work on particle as it moves from point a to point b, the electric potential at point b is higher than point a. Therefore, particle moves from point a to point b in direction of increasing electric potential.
ΔV = \(Vb - Va\)
ΔV = \(Vb - Va > 0\)
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The circuit above has a resistor, capacitor and voltage source. The resistance is R = 65 ohm, the capacitance is C = 2 farad and the voltage source has voltage V(t) = 90 cos(2t) at t seconds. da dt Let q(t) be the charge (in coulomb) in the circuit at t seconds and find a differential equation for da dt = 1.5 cos 4t + tan 11 X ! (480) Note: A value of 2 farad is somewhat unrealistic, but was chosen to make the problem simpler.
The differential equation for da/dt is da/dt = -720qsin(2t) = -1440qsin(t)cos(t). To find the differential equation for da/dt, we need to use the equation q=CV. We can differentiate this equation with respect to time to get dq/dt = C(dV/dt).
Using the given values, we have C=2F and V(t) = 90cos(2t), so dV/dt = -180sin(2t). Substituting these values into the equation, we get dq/dt = -360sin(2t). Next, we need to express dq/dt in terms of q. We can do this by using Ohm's Law, V=IR, where I is the current in the circuit. Rearranging this equation, we have I = V/R.
Using the given values, we have R=65 ohms and V(t) = 90cos(2t), so I(t) = 90cos(2t)/65. Substituting this into the equation for dq/dt, we get dq/dt = -360sin(2t) = -180I(t)sin(2t). Finally, we can express dq/dt in terms of q by substituting q=CV, which gives dq/dt = C(dV/dt) = -360Csin(2t) = -720qsin(2t).
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