Which represents the self-ionization of water at 25°C?
O A. H2O + H20 = 2H2 + O2
OB.
H2O + H2O = H2O2 + H2
O C.
H2O + H2O = 4H+ + 202-
OD.
H2O + H20 = H30+ + OH-

Answer:

³₂He

Explanation:

From the question given above, the following equation was obtained

²₁H + ²₁H —> ¹₀n + __

Let ᵇₐX be the missing part of the equation. Thus, the equation becomes:

²₁H + ²₁H —> ¹₀n + ᵇₐX

Next, we shall determine b, a, and X. This can be obtained as follow:

2 + 2 = 1 + b

4 = 1 + b

Collect like terms

b = 4 – 1

b = 3

1 + 1 = 0 + a

2 = 0 + a

a = 2

ᵇₐX => ³₂X => ³₂He

Thus the equation is:

²₁H + ²₁H —> ¹₀n + ᵇₐX

²₁H + ²₁H —> ¹₀n + ³₂He

The missing part is ³₂He

Answer:

because the outermost shell of electrons orbiting the nucleus is full, giving these gases no incentive to swap electrons with other elements.

Explanation:

here

Answer:

The Empirical Formular is given as; Ti₆Al₄V

Explanation:

The percent composition of the material is 64.39% titanium, 24.19% aluminum, and 11.42% vanadium.

Elements                        Titanium            Aluminium        Vanadium

Percentage                    64.39                 24.19                   11.42

Divide all through by their molar mass

                                     64.39 / 47.87      24.19 / 27               11.42 / 50.94

                                       =  1.345                = 0.896                 = 0.224

Divide all though  by the smallest number (0.224)

                                     1.345 / 0.224        0.896 / 0.224       0.224 / 0.224

                                     = 6                         = 4                             = 1

The Empirical Formular is given as; Ti₆Al₄V

Using the stepwise procedure for obtaining the empirical formula of a compound, the empirical formula is \( T_{6}Al_{4}V\)

Titanium :

Divide by Molar mass : = 64.39/47.87 = 1.345

Aluminum :

Divide by Molar mass : = 24.19/27 = 0.896

Vanadium :

Divide by Molar mass : = 11.42/50.94 = 0.224

Divide by the smallest :

Titanium = 1.345 / 0.224 = 6.00

Aluminum = 0.896 / 0.224 = 4

Vanadium = 0.224 / 0.224 = 1

Hence, the empirical formula is \( T_{6}Al_{4}V\)

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Answer:

C. Their exact amounts are not currently known.

Explanation:

The statement that best describes the availability of nonrenewable energy resources is that their exact amounts are not currently known.

Non-renewable sources of energy are those sources that are subject to exhaustion from usage i.e. cannot replenish itself.

Non-renewable sources unlike their renewable counterparts are exhaustible because they don't replenish themselves over a short time.

Examples of non-renewable sources of energy are:

Therefore, the statement that best describes the availability of nonrenewable energy resources is that their exact amounts are not currently known.

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Answer:

0.99986

Explanation:

attached below is the detailed solution to the given problem

Express the ratios of the ground state energies of these atoms

ground state energies ( Ed , Ehe )

= Ed / Ehe = -13.5963 / -13.59815

                 = 0.99986

Answer:

0.252

Explanation:

Answer:

866.142 inches

Explanation:

By formula

Answer:

B

Explanation:

i just read it na, but i forgot the explanation

Answer:

A. and B.

Explanation:

Anion is negative as well as a negative ion.

(Just took the quiz)

Answer:

D. It formed solely from atoms generated by the Big Bang.

Explanation:

From the history of the earth and it's solar system, options A to C are all correct ways of summarizing the Solar System's development. Because they have been proven to be in sync with reality of the solar system whereas the Bing bang theory has not done so as we know it says the universe was birthed from a huge explosion called big bang.

Answer:

1. saturated

2. fatty acids

3. fatty acids

Explanation:

Answer:

option 2 is correct

Explanation:

24. The IUPAC name of the compound is 2,4-dimethyl-1-pentanal (Option B)

25. The IUPAC name of the compound is 5-methyl-3-octanone (Option C)

The international union of pure and applied chemistry (IUPAC) standard for naming organic compounds is given below:

24. The name of the compound is given as follow:

Thus, the IUPAC name of the compound is:

2,4-dimethyl-1-pentanal (Option B)

25. The name of the compound is given as follow:

Thus, the IUPAC name of the compound is:

5-methyl-3-octanone (Option C)

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Answer:  Blood alcohol levels at autopsy are valid up to 48 hours after death when simple principles are observed in the collection and storage of samples. Alcohol levels in samples of blood taken from the intact heart are as significant as levels of blood from the femoral veins.

Explanation:

Answer:

If the victim was submerged in water

Explanation:

Answer:

Can you provide the options pls

Explanation:

Answer:

The beta-lactam ring, the thiazolidine/dihydrothiazine ring and the side-chains are all potentially immunogenic. Cross-reactivity between penicillin and third-generation cephalosporins occurs in 2% to 3% of penicillin-allergic patients.

This is one of the answers.

The second is

The cephalosporin medications that are likely to cross-react after penicillin allergies have been established and include: Cephalexin. Cefadroxil. Ceflaclor.

The total mass , reported to the appropriate number of significant figures of three samples of granite when it were massed is 137.9 g .

Here we know that ,

Mass of the first granite sample = 67.4 g

Mass of the second sample = 43.2  g

Mass of the third sample = 27.3 g

We want to get the total mass for the three granite samples ,  then what we need to do is just add the three values that we know , this will give:

Total mass = 67.4 g + 43.2 g + 27.3 g = 137.9 g .

We conclude that the total mass of the three samples is 137.9 g .

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Answer:

the answer is A

Explanation:

Answer:

a

Explanation:

the roller coaster is at the highes pont witch is a .

Answer:

show me a pic of the problem

Explanation:

show me a pic of the problem

Like charges repel each other, while opposite charges attract each other. This principle is one of the fundamental aspects of electrostatics. According to Coulomb's law, the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

As the distance between two charged particles decreases, the force between them increases. This is because the closer the particles are, the stronger the electric field they create, leading to a stronger force of interaction.

On the other hand, as the magnitude of the charges decreases, the force between the particles also decreases. This is because the force is directly proportional to the product of the charges. If one or both of the charges are smaller, the force they exert on each other will be weaker.

In summary, according to Coulomb's law, decreasing the distance between charged particles increases the force between them, while decreasing the magnitude of the charges decreases the force. This understanding of the relationship between charge, distance, and force is crucial in explaining the behavior of charged particles and the interactions between them.

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Answer:

A prokaryotic cell is shown in the image

Explanation:

Prokaryotic cells are the most basic types. Since they are basic, they don't have a nucleus. All eukaryotic cells have it but prokaryotic cells don't have it. A nucleus contains organelles such as a mitochondria which the diagram doesn't show as well. Thus a prokaryotic cell is shown in the image.

Answer:

holaholaholaholaholaholaholahola

The volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C is 0.126 liters, rounded to three significant figures.

To calculate the volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C, we can use the ideal gas law equation:

PV = nRT

where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15:

T = 50°C + 273.15 = 323.15 K

Next, we rearrange the ideal gas law equation to solve for volume:

V = (nRT) / P

To find the number of moles (n), we can use the answer from question 27, which is the mass of oxygen gas:

m = 32 g

Using the molar mass of oxygen (O₂) which is approximately 32 g/mol, we can calculate the number of moles:

n = m / M = 32 g / 32 g/mol = 1 mol

Now we have all the values needed to calculate the volume:

V = (1 mol * 8.314 J/(mol*K) * 323.15 K) / 210,000 Pa

Using the ideal gas constant (R) of 8.314 J/(mol*K) and the pressure of 210 kPa (which is equivalent to 210,000 Pa), we can substitute these values into the equation and solve for volume.

V = 0.126 liters.

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From the given graph, it is clear that the element with highest mass ate a volume of 3 cm³is lead and that with least mass is aluminium.

Density of a substance is the measure of its mass per unit volume. Thus, mathematically it is the ratio of mass to the volume. Therefore, as the mass increases density also increase.

Density of an element depends on its mass, volume, temperature and pressure. In periodic table, from left to right density decreases whereas down a group density increases.

From the graph showing the mass-volume-density relation it is clear that the element with with higher mass at a particular volume is lead and the element with least mass among the group is aluminium. The density of these elements also showing the same trend.

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Answer:

conservation of mass

Answer:

4.50 L

Explanation:

First we calculate how many moles are there in 3.84 L of a 8.50 mol/L solution:

Now, keeping in mind that

we can calculate the volume of a 7.25 mol/L solution that would contain 32.64 moles:

So we could take 4.50 L of the 7.25 mol/L solution and evaporate the solvent until only 3.84 L remain.

The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.

The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.

Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.

Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.

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All of the lipid compounds are soluble in organic solvents but not in water. Among the given examples, the lipids are oils, cholesterol and phospholipids. The correct options are A, B and D.

The organic compounds which consists of carbon, hydrogen and oxygen atoms and they form the framework for the structure and function of living organisms are called lipids.

These compounds are non-polar molecules which are soluble only in non-polar solvents and it is insoluble in water. They are composed of fats and oils. They are energy rich molecules which provide energy to perform different processes.

Thus the correct options are A, B and D.

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N2 is a homonuclear molecule and NO+ is a heteronuclear molecular ion hence the  MO structure of NO+ different than that of N2.

The molecular orbital is formed by the combination of atomic orbitals. We should note that the number of molecular orbitals must be equal to the number of combining atomic orbitals.

Now we know that N2 is a homonuclear molecule and NO+ is a heteronuclear molecular ion hence the  MO structure of NO+ different than that of N2.

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Answer:

Consequence

The mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

The half-life of a radioactive isotope is the amount of time it takes for one-half of the radioactive isotope to decay.

The half-life of a specific radioactive isotope is constant; it is unaffected by conditions and is independent of the initial amount of that isotope.

The number of half lives in 27 days;

n = 27 days/14 days

n = 1.929

The mass of P-32 remaining after 27 days, if the initial mass is 40g;

mass remaining = 40 g / (2^1.929)

mass remaining = 40 g / 3.808

mass remaining = 10.5 g

Thus, the mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

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The moles of nitrogen produced is 0.40 moles of ammonia.

The Percent yield of ammonia is 81.2%

The moles of ammonia produced is obtained from the mole ratio of the reaction.

The mole ratio of hydrogen to nitrogen is 3 : 2

Based on the mole ratio, the limiting reactant is hydrogen.

Moles of nitrogen produced = 0.600 * 2/3 = 0.40 moles of ammonia.

mass of ammonia expected = 0.4 * 17 g = 6.8 g

Percent yield = 5.52/6.8 * 100% = 81.2%

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Answer:

1.1 g Na2SO4

Explanation:

First convert mL to L. Then multiply by the Molarity to get moles, then multiply by the molar mass to get grams.

15 mL x     1 L       x       0.50 mol Na2SO4     x        142 g        =          1.1 g

              10^3 mL                 1 L                                   mol                     Na2SO4

In a formula unit, there are 48 gram of Na2SO4 atoms of each element. In terms of molar mass (gram mass unit): 45.98 g Na2SO4 in total 142.04 g sodium sulphate

A mole of sodium sulphate is created when two moles of sodium (45.98 g), one mole of sulphur (32.06 g), and four moles of oxygen (64.00 g) are combined (142.04 g).

The atomic mass of sodium sulphite is equal to 10 moles times the molecular mass, or 1260 grams. Consequently, 1260 grams are the mass of 10 moles of sodium sulphite (Na2SO4).

We first obtain the atomic weights of the different elements in a periodic table in order to compute the molar mass of a molecule. Then, we multiply the total number of atoms by each one's atomic mass. Finally, we calculate the molar mass by combining all the atomic masses.

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The IUPAC name for each of the compounds would be:

A. 2,6-Dimethyl octane

B. Octane

IUPAC naming is a system of naming organic compounds according to the rules set up by the International Union of Pure and Applied Chemistry.

According to these rules:

Applying these rules to the structures in the image, the IUPAC names would be as follows:

A. 2,6-Dimethyl octane

B. Octane

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