Answer:
B
Explanation:
One object speeds up before it slows to a stop.
When reading this type of graph, we know that when the points are far apart, then the object is definitely moving quickly. Also again, we know that when the points are besides each other, then we say that the object is moving slow. When the distance that is between the points are changed, the velocity of the object subsequently changes too, and therefore, we say that the object is accelerated. When there are lots of points in one location, we will see that the object is not moving.
This then translates into that
The object(s) at the top begins to slow, eventually, it increases in its speed, going forward, it slows down again, before it finally halts. The object at the bottom on the other hand, starts fast, before slowing down.
then:
"One object speeds up before it slows to a stop "
at 11 °c, the kinetic energy per molecule in a room is kave.
At 11 °C, the kinetic energy per molecule in a room is kave = 6.21 x 10^-21 J.
Why the kinetic energy is per molecule in a gas?The kinetic energy per molecule in a gas is given by the formula:
KE = (3/2) kT
where KE is the kinetic energy per molecule, k is the Boltzmann constant (1.38 x 10^-23 J/K), and T is the temperature in Kelvin.
To convert a temperature from Celsius to Kelvin, we need to add 273.15 to the Celsius temperature.
So if the temperature is 11 °C, then the temperature in Kelvin is:
T = 11 °C + 273.15 = 284.15 K
Substituting this value into the formula for kinetic energy per molecule, we get:
KE = (3/2) kT = (3/2) (1.38 x 10^-23 J/K) (284.15 K)
KE = 6.21 x 10^-21 J
Therefore, at 11 °C, the kinetic energy per molecule in a room is kave = 6.21 x 10^-21 J.
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If the index of refraction for a given material is 1.5, what is the speed of light in that material relative to the speed of light in a vacuum, c?
If the index of refraction for a given material is 1.5, The speed of light in that material relative to the speed of light in a vacuum would be 2c/3 m/s.
We know that refractive index of light is defined by,
η = speed of light that medium/ speed of light in vacuum,
Given,
Index of refraction, η = 1.5,
Speed of light, c = 3 × 10⁸,
Hence, η = c/v
⇒ 1.5 = 3 × 10⁸ / v
⇒ v = 2 × 10⁸ m/s
Also, c = 3 × 10⁸,
So, v = 2c/3 m/s
Therefore, the speed of light in that material relative to the speed of light is 2c/3.
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a baggage handler drops your 9.50 kg suitcase onto a conveyor belt running at 1.80 m/s . the materials are such that μs = 0.470 and μk = 0.210. How far is your suitcase dragged before it is riding smoothly on the belt?
The suitcase is dragged for 7.03 m before it is riding smoothly on the belt.
First, we need to find the initial velocity of the suitcase in the horizontal direction, which is zero. Then, we can use the work-energy principle to find the work done on the suitcase by the friction force:
W = ΔK = (1/2)mvf² - (1/2)mvi²where m = 9.50 kg, vi = 0 m/s, vf = 1.80 m/s.
The work done by the friction force is:
W = f × d = μk × m × g × dwhere μk = 0.210, g = 9.81 m/s².
Setting these two equations equal to each other and solving for d, we get:
d = (vf²/2g) × (1 + (2μkμs/μs²))where μs = 0.470.
Plugging in the values, we get:
d = (1.80²/29.81) × (1 + (20.210×0.470/0.470²)) = 7.03 mTo learn more about work done, here
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The suitcase is dragged for a distance of 8.29 meters before it begins to move smoothly on the conveyor belt.
What is Distance?
Distance is the numerical measurement of the amount of space between two points, typically measured in units such as meters, kilometers, miles, or feet. It is a scalar quantity that only specifies the magnitude of the space between two points and does not consider direction or displacement.
The force of friction acts to oppose the motion of the suitcase, and so the net force on the suitcase is given by:
Fnet = mg - μmg = (1 - μ)mg
Using Newton's second law, Fnet = ma, we can find the acceleration of the suitcase:
a = Fnet/m = (1 - μ)g ≈ 3.23 m/\(s^{2}\)
The time it takes for the suitcase to reach a velocity of 1.80 m/s can be found using the kinematic equation:
v = u + at
where u is the initial velocity, which is zero.
Solving for t, we get:
t = v/a ≈ 0.56 s
The distance the suitcase is dragged before it reaches a velocity of 1.80 m/s is given by:
s = ut + (1/2)\(at^{2}\)
where u is the initial velocity, which is zero.
Substituting the values we have found, we get:
s = (1/2)\(at^{2}\) ≈ 8.29 m
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Draw an equilateral triangle with sides of length 5. Draw in an altitude. What is the length of the altitude? 0 Use the lengths of the sides of the triangle and altitude to compute the following trigo
An equilateral triangle is a triangle whose sides are all equal in length and has three equal angles of 60° each. To draw an equilateral triangle with sides of length 5, you can use a compass and a ruler to measure 5 cm. Using the compass, place the needle at one end of the line segment and draw an arc that intersects the line segment at another point.
Place the needle on the intersection point and draw another arc that intersects the first arc at a third point. The line segments connecting the three points are all of equal length 5 and form an equilateral triangle.To draw an altitude in an equilateral triangle, we need to drop a perpendicular line from one of the vertices to the opposite side. This line is known as the altitude.
When the altitude is drawn, it creates two smaller right-angled triangles with the base of the equilateral triangle. We can use this to find the length of the altitude.To find the length of the altitude of the equilateral triangle with sides of length 5, we need to use the Pythagorean theorem since we know that the smaller right-angled triangles have a base of 2.5 (half the side length) and a hypotenuse of 5 (side length). Using a² + b² = c², where a and b are the legs of the right triangle and c is the hypotenuse, we get:a² + (2.5)² = (5)²a² + 6.25 = 25a² = 18.75a ≈ 4.33.
Therefore, the length of the altitude is approximately 4.33 units.To compute the trigonometric ratios of this triangle, we can use the sides and altitude of the equilateral triangle. Using SOHCAHTOA (sine, cosine, tangent, cosecant, secant, and cotangent), we can find the ratios for the angles of the triangle.Sin(60°) = Opposite/Hypotenuse = 4.33/5 = 0.866Cos(60°) = Adjacent/Hypotenuse = 2.5/5 = 0.5Tan(60°) = Opposite/Adjacent = 4.33/2.5 = 1.732Cosecant(60°) = Hypotenuse/Opposite = 5/4.33 = 1.154Secant(60°) = Hypotenuse/Adjacent = 5/2.5 = 2Cotangent(60°) = Adjacent/Opposite = 2.5/4.33 = 0.577
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Convection can occur in which two substances?
wood and air
ice and wood
water and ice
air and water
After considering all the given options we come to the conclusion that the required answer to the given question is Option D.
Convection is generally known as the property that aids the transfer of thermal energy through the movement of particles from one specified area to another. It typically seen to take place in fluids .
When we talk about convection, particles that have a lot of heat energy inside a liquid or gas dominate over the particles that have less heat energy by taking their dedicated space. Then , convection can occur in air and water.
some famous examples of convection are:
Boiling water
Land and sea breeze
Air conditioner
Radiator
Refrigerator
Hot air popper
Hot air balloon
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Forces of 7.6N at 38 degrees and 11.8N at 143 degrees act at a point.Calculate the magnitude and direction of their resultant.
Answer:
Approximately \(12.3\; {\rm N}\) at approximately \(106^{\circ}\).
Explanation:
Assume the two given directions are measured with respect to the positive \(x\) axis.
If a vector of magnitude \(\| a\|\) is at an angle of \(\theta\) from the positive \(x\) axis, this vector can be written in the component form as:
\(\begin{aligned}\| a\|\begin{bmatrix}\cos(\theta) \\ \sin(\theta)\end{bmatrix}\end{aligned}\);
Or equivalently:
\(\begin{aligned}\begin{bmatrix}\|a\|\, \cos(\theta) \\ \|a\|\, \sin(\theta)\end{bmatrix}\end{aligned}\).
For example, the \(7.6\; {\rm N}\) force is a vector with magnitude \(7.6\; {\rm N}\) at a direction of \(38^{\circ}\) from the positive \(x\) axis. This vector can be represented as:
\(\begin{aligned} 7.6\, \begin{bmatrix}\cos(38^{\circ}) \\ \sin(38^{\circ})\end{bmatrix} &= \begin{bmatrix}7.6\, \cos(38^{\circ}) \\ 7.6\, \sin(38^{\circ})\end{bmatrix} \approx \begin{bmatrix}5.9889 \\ 4.6790 \end{bmatrix}\end{aligned}\).
Similarly, the \(11.8\; {\rm N}\) vector can be represented as:
\(\begin{aligned}11.8\, \begin{bmatrix}\cos(143^{\circ}) \\ \sin(143^{\circ})\end{bmatrix} &= \begin{bmatrix}11.8\, \cos(143^{\circ}) \\ 11.8\, \sin(143^{\circ})\end{bmatrix} \approx \begin{bmatrix}-9.4239 \\ 7.1014 \end{bmatrix}\end{aligned}\).
To find the sum of the two vectors, take the sum of each component separately:
\(\begin{aligned}& \begin{bmatrix}5.9889 \\ 4.6790 \end{bmatrix} + \begin{bmatrix}-9.4239 \\ 7.1014\end{bmatrix} \\ =\; & \begin{bmatrix}5.9889 + (-9.4239)\\ 4.6790 + 7.1014\end{bmatrix} \\ \approx\; & \begin{bmatrix}-3.4350 \\ 11.780\end{bmatrix} \end{aligned}\).
Apply the Pythagorean Theorem to find the magnitude of this vector sum:
\(\displaystyle \sqrt{(-3.4350)^{2} + (11.780)^{2}} \approx 12.271\).
Note that the first component (\(x\)-component) of this vector is negative, such that this vector would point to the left of the vertical axis. Since the second component (\(y\)-component) of this vector is positive, this vector would point above the horizontal axis. Hence, the direction of this vector (relative to the positive \(x\!\)-axis) would be an angle between \(90^{\circ}\) and \(180^{\circ}\).
Divide the \(x\)-component of this vector by its magnitude to find the cosine of the angle between this vector and the positive \(x\!\)-axis. Apply the inverse cosine function to find this angle:
\(\begin{aligned}\arccos \left(\frac{-3.4350}{12.271}\right) \approx 106^{\circ}\end{aligned}\).
Where would you find the photosphere
Explain the difference between weight and mass.
Answer:
Mass is a measure of how much force it will take to change that path. ... Weight, on the other hand, is a measure of the amount of downwards force that gravity exerts on an object. This force increases with the object's mass: the more inertia it has, the harder gravity pulls.
Explanation:
4 diagrams that show existence of atmospheric pressure
Explanation:
lift pumpdrinking strawFind the allowed energies of the half-harmonic oscillator (a quantum spring which can be stretched but not compressed). The corresponding potential is:
The specific form and values of the potential will determine the allowed energies of the half-harmonic oscillator.
A half-parabolic potential may be used to explain the potential energy function for a half-harmonic oscillator, commonly referred to as a quantum spring that can be expanded but not crushed.
We solve the Schrödinger equation for the specified potential in order to determine the system's permitted energies. However, it is not feasible to give a precise description of the permitted energies in the absence of specified characteristics or boundary conditions. The half-harmonic oscillator's energy levels and related wavefunctions will depend on the precise shape and values of the potential.
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The complete question is attached below.
42) An ideal gas occupies 6.00 × 102 cm3 at 20°C. At what temperature will it occupy 1.20 × 103 cm3 if the pressure is held constant?
A) 10°C
B) 40°C
C) 100°C
D) 313°C
According to the question the pressure is held constant 40°C.
What is pressure?Pressure is a physical quantity that describes the internal forces exerted on an object by its environment. It is defined as the force per unit area on a surface, and is measured in units of pascals (Pa). Pressure is an expression of the amount of work done by a force applied over a given area, and is a major factor in the dynamics of fluid flow. Pressure is a scalar quantity, meaning it has magnitude but no direction.
The volume of an ideal gas is directly proportional to its temperature when the pressure is held constant. To calculate the new temperature, use the equation:
T2 = T1 (V2/V1), where T1 is the initial temperature, V1 is the initial volume, T2 is the new temperature, and V2 is the new volume.
In this case, T1 = 20°C, V1 = 6.00 × 102 cm3, V2 = 1.20 × 103 cm₃.
Therefore, T2 = 20°C (1.20 × 103 cm3/6.00 × 102 cm3) = 40°C.
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a spherical cavity is hollowed out of the interior of a neutral conducting sphere. at the center of the cavity is a point charge, of positive charge q.
Only the charge present inside the cavity can explain the electric field that exists there. The electric field inside the hollow would remain unchanged as a result.
Each point in space has an electric field associated with it when there is charge present in any form. E, often known as electric field strength, electric field intensity, or just the electric field, is a mathematical constant that expresses the strength and direction of an electric field. To predict what would happen to electric charges nearby a specific point, one only needs to be aware of the value of the electric field there, without having any precise knowledge of what generated the field.
When one charge is thought of as the generator of an electric field that spreads outward into the surrounding space, the electric force is not thought of as a direct interaction of two electric charges that are separated from one another.
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A 300 kg wooden raft floats on a lake. When a 75 kg man stands on the raft, it sinks 4.0 cm deeper into the water. When he steps off, the raft vibrates for a while.
(a) What is the frequency of vibration?
(b) What is the total energy of vibration (ignoring damping)?
The frequency of vibration is 24.6 Hz and the total energy of vibration is 14.715 J.
Here,
mass of the person, m = 75 kg
sink depth, d = 4 cm = 0.04 m
mass of wooden shaft, ms = 300 kg
From newton second Law : SUM(F) = 0
this whole system will act spring-mass system :
so
mg = k*d
spring constant, k = m*g/d
spring constant, k = 75*9.81/0.04
spring constant, k = 18393.75 N/m
Frequency of oscillation, f = (1/2*pi)*sqrt(k/m)
Frequency of oscillation, f = (1/2*pi)*sqrt(18393.75/75)
Frequency of oscillation, f = 24.6 Hz
Energy, E = 0.5 * k * x^2
Energy, E = 0.5 * 18393.75 * 0.04^2
Energy, E = 14.715 J
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a
It do
While doing dishes, Zvi drops his
3.0x10 3kg platinum wedding band
into the dishwater, displacing a
volume of 1.40x107m3 of water,
what is the density of the platinum
band?
n
CSS c
sion
im
al
Select one:
a. 2.56x104 kg/m3
b. 1.0x104 kg/m3
Di
c. 0.5x104 kg/m3
IL
d. 2.14x104 kg/m3
IL:
Answer:
d. 2.14 x 10⁻⁴ kg/m³
Explanation:
Density is defined as the mass of an object per unit volume occupied by that object. The formula of density is, therefore, given as follows:
\(\rho = \frac{m}{V}\)
where,
ρ = density of platinum band = ?
m = mass of platinum band = 3 x 10³ kg
V = Volume displaced by Platinum band = 1.4 x 10⁷ m³
Therefore,
\(\rho = \frac{3\ x\ 10^{3}\ kg}{1.4\ x\ 10^{7}\ m^{3}}\\\\\rho = 2.14\ x\ 10^{-4}\ kg/m^{3}\)
Hence, the correct option is:
d. 2.14 x 10⁻⁴ kg/m³
In the diagram, A(-7; 4), B(-6; 6), C(0; 3) and D(-1; t) are the vertices of a rectangle. Calculate the: a) length of the diagonal AC.
Explanation:
150 km North, 50 km West,
True or false the ranking of a link on a search engine is based on how many clicks it gets
false
i just researched it it’s not true
when a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied: group of answer choices (b) there is a large increase in the magnetic induction (b) (a) the magnetic induction (b) is decreased both a
When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, the magnetic induction (B) is increased.
Ferromagnetic materials, such as iron, nickel, and cobalt, have unique properties that make them highly responsive to magnetic fields. When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, several factors contribute to the increase in magnetic induction (B):Alignment of Magnetic Domains: In the absence of an external magnetic field, the magnetic domains within a ferromagnetic material are randomly oriented, resulting in a net magnetic moment of zero. However, when a magnetic field is applied, the domains align themselves in the direction of the field, leading to an increase in the overall magnetic induction.Magnetic Saturation: Ferromagnetic materials have a saturation point, beyond which further increase in the magnetic field does not significantly increase the magnetic induction. This saturation point is typically higher than that of other magnetic materials, allowing ferromagnetic materials to exhibit a larger increase in magnetic induction.Amplification of Magnetic Field: The presence of a ferromagnetic material within an electromagnetic coil enhances the magnetic field generated by the coil. This phenomenon is known as magnetic amplification or magnetic flux concentration. The ferromagnetic material acts as a magnetic conductor, guiding and intensifying the magnetic field lines, resulting in a larger magnetic induction.In contrast, option (a) stating that the magnetic induction (B) is decreased is incorrect. When a ferromagnetic material is subjected to an external magnetic field, the magnetic induction increases due to the alignment of magnetic domains and the amplification of the magnetic field.Therefore, the correct answer is:
(a) There is a large increase in the magnetic induction (B)
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The asteroid has an estimated mass of 4000 kg and an orbital speed of 10 m/s. Determine the amount of kinetic energy of the asteroid. *
Answer:
40,000J
Explanation:
why are unit of length mass and time independent with each other?
A car going around a curve with a radius of 15m experiences a centripetal acceleration of 2.5 m/s2. How fast is the car going?
0.17m/a
38 m/s
6.1 m/s
6.0 m/s
Answer:
Explanation:
The formula for centripetal acceleration is
\(a_c=\frac{v^2}{r}\) . Filling in:
\(2.5=\frac{v^2}{15}\) and
\(v=\sqrt{2.5(15)}\) so
v = 6.1 m/s
A glass test tube rubbed with silk and an acrylic rod rubbed with a paper towel become charged due to the process of charging by friction. How do the test tube and rod interact?
Answer:
Attraction.
Explanation:
Charging by friction involves rubbing of objects against one another so that one loses electron(s), while the other gains the electron(s). Thus, the objects would have opposite charges after the process.
The glass test tube rubbed with silk loses electron, thus becomes positively charged. While the acrylic rob rubbed with paper towel becomes negatively charged. Since the two rods have opposite charges, then the interaction between them would be attraction. A force of attraction between the rods would be experienced while the rods are brought to a required close range.
The coefficient of multiple determination (R) showsA) the effect of the control variable after removing the independent from the equationB) essentially the same thing as a partial gammaC) the combined effects of all independents on the dependentD) the zero-order relationships after controlling for the independents
The coefficient of multiple determination (R) shows the combined effects of all independents on the dependent.
So option C is correct.
The coefficient of multiple determination (R) represents the proportion of the variance in the dependent variable that can be explained by the independent variables collectively. It reflects the combined influence of all independent variables on the dependent variable. It measures the goodness of fit of a regression model and indicates how well the independent variables predict the variation in the dependent variable when used together. A partial gamma is a measure of the association between two variables, while the coefficient of multiple determination is a measure of the association between a dependent variable and all of the independent variables in a model. The coefficient of multiple determination is a more comprehensive measure of association than a partial gamma.
The control variable is not removed from the equation when calculating the coefficient of multiple determination. The control variable is used to control for the effects of other variables that may be related to the dependent variable.Therefore, option C correct.
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Energy can neither be created nor destroyed. Why?
Answer:
The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside
Which is a characteristic of all waves
Waves share common characteristics such as wave motion, amplitude, wavelength, frequency, wave speed, and interactions with boundaries. These properties are fundamental to understanding the behavior and properties of various types of waves, including sound waves, electromagnetic waves, water waves, and seismic waves.
A characteristic of all waves is their ability to transfer energy without transferring matter. This fundamental property distinguishes waves from other forms of energy transfer, such as the movement of objects in a solid or the flow of fluids. Waves propagate through various mediums or through empty space, carrying energy from one location to another.
Waves exhibit several common characteristics, including:
1. Wave Motion: Waves involve the transfer of energy through periodic oscillations or vibrations. The particles or fields involved in the wave motion move back and forth around their equilibrium positions, transmitting the energy along the wave path.
2. Amplitude: The amplitude of a wave represents the maximum displacement or disturbance from the equilibrium position. It corresponds to the intensity or strength of the wave and can be measured as the maximum height, displacement, or value of a wave.
3. Wavelength: The wavelength of a wave is the distance between two consecutive points with the same phase or the distance covered by one complete cycle of the wave. It is commonly represented by the symbol λ and is usually measured in meters or other appropriate units.
4. Frequency: The frequency of a wave refers to the number of complete oscillations or cycles that occur per unit of time. It is denoted by the symbol f and is measured in hertz (Hz). The frequency and wavelength of a wave are inversely related and are related to the speed of the wave through the equation v = fλ, where v represents the wave velocity.
5. Wave Speed: The wave speed represents the rate at which a wave travels through a medium or through empty space. It is the product of the wavelength and the frequency of the wave and is usually denoted by the symbol v. The speed of a wave depends on the properties of the medium through which it travels.
6. Reflection, Refraction, and Diffraction: Waves can undergo interactions with boundaries or obstacles, resulting in phenomena such as reflection (bouncing off a surface), refraction (bending when passing through different mediums), and diffraction (spreading out or bending around obstacles).
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A current of 5A flows round a circuit in 2 minutes. How much charge flows round
the circuit in this time?
Answer:
just multiply 2 time 5 a
Explanation:
Which of the following statements is false? Net forces act on the car during intervals A and C. The magnitude of the net force acting during interval C is greater than that during A. No net force acts on the car during interval B. Opposing forces may be acting on the car during interval C. Opposing forces may be acting on the car during interval D.
The amount of net force acting on an item is equal to the object's mass times its acceleration. An object is not speeding and is said to be in an equilibrium state if there is zero net force acting on it. Thus, option B is correct.
What magnitude of the net force acting during the interval?The total amount of forces exerted on an object is referred to as its net force. The product of the object's mass and its acceleration gives the amount of net force that is acting on the object.
An object is not speeding and is said to be in an equilibrium state if there is zero net force acting on it. The magnitude of a force is its measurement or intensity. The magnitude of the net force is the resultant force, which is the total of all forces acting on a body.
Therefore, The magnitude of the net force acting during interval C is greater than that during A.
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The amount of net force acting on an item is equal to the object's mass times its acceleration. An object is not speeding and is said to be in an equilibrium state if there is zero net force acting on it. Thus, option B is correct.
What magnitude of the net force acting during the interval?The total amount of forces exerted on an object is referred to as its net force. The product of the object's mass and its acceleration gives the amount of net force that is acting on the object.
An object is not speeding and is said to be in an equilibrium state if there is zero net force acting on it. The magnitude of a force is its measurement or intensity. The magnitude of the net force is the resultant force, which is the total of all forces acting on a body.
Therefore, The magnitude of the net force acting during interval C is greater than that during A.
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A scientist is examining an unknown solid. Which procedure would most likely help determine a chemical property of the substance?
heating it to find the temperature at which it melts
exposing it to a flame to see if it catches on fire
hitting it with a hammer to determine if it breaks or bends
placing it in water to find out whether or not it dissolves
Answer:
hitting it with a hammer to determine if it breaks or bends
Answer:
exposing it to a flame to see if it catches on fire
Explanation:
A chemical property is when the matter changes into a different substance. This is true when you expose it to a flame because if a substance is burned, it will change into a new substance. All the other options are examples of physical changes.
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Hope this helps!
a particle moving along the x axis in simple harmonic motion starts from its equilibrium position, the ori- gin, at t 5 0 and moves to the right. the amplitude of its motion is 2.00 cm, and the frequency is 1.50 hz. (a) find an expression for the position of the particle as a function of time. determine (b) the maximum speed of the particle and (c) the earliest time (t . 0) at which the particle has this speed. find (d) the maxi- mum positive acceleration of the particle and (e) the earliest time (t . 0) at which the particle has this accel- eration. (f) find the total distance traveled by the par- ticle between t 5 0 and t 5 1.00 s.
(a) The position of the particle as a function of time is given by:
x(t) = A cos(2πft)
where A is the amplitude (2.00 cm), f is the frequency (1.50 Hz), and cos is the cosine function.
Substituting the given values, we get:
x(t) = 2.00 cos(3πt)
(b) The maximum speed of the particle occurs at the equilibrium position, where the displacement is zero. At this point, the velocity is maximum and is given by:
vmax = Aω
where ω is the angular frequency and is equal to 2πf. Substituting the given values, we get:
vmax = 2.00 × 2π × 1.50 = 18.85 cm/s
(c) The earliest time at which the particle has this speed is when it passes through the equilibrium position. This happens at t = 0, so the earliest time is t = 0.
(d) The maximum positive acceleration of the particle occurs at the ends of its motion, where the displacement is maximum. At these points, the acceleration is given by:
amax = Aω^2
Substituting the given values, we get:
amax = 2.00 × (2π × 1.50)^2 = 282.74 cm/s^2
(e) The earliest time at which the particle has this acceleration is when it reaches the maximum displacement. This happens at t = 1/4T, where T is the period of the motion. The period is given by:
T = 1/f = 2/3 s
So, t = 1/4T = 1/4 × 2/3 = 0.33 s
(f) The total distance traveled by the particle between t = 0 and t = 1.00 s is equal to one complete cycle of its motion. The distance traveled in one complete cycle is equal to four times the amplitude, or:
4A = 8.00 cm
Therefore, the total distance traveled is:
8.00
Disk Y of rotational inertia ly=(1/2)MY(RY)^2 about its center is held at rest above disk X of rotational inertia Ix=(1/2)Mx(RY)^2 about its center. Disk
X initially rotates about its center with an angular velocity of +w0. Disk Y is then slowly lowered onto disk X until both disks are in contact and rotate
together with a common angular velocity. Which two of the following predictions are correct about the angular momentum of disk X and disk Y
immediately before and after the rotational collision? Select two answers.
The angular momentum of disk X immediately after the collision is greater than the angular momentum of disk X immediately before the
collision.
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the
collision.
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of the disk X-disk Y system
immediately before the collision.
The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system
immediately before the collision.
The statements that are true are
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the collision.The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system immediately before the collision.What is angular momentum?Angular momentum is the product of the rotational inertia and angular speed of a rotating object.
How to find which statements are true about the angular momentumLet
I₁ = initial angular momentum of disk X = Ixω₀ where Ix = rotational inertia of disk x and ω₀ = angular velocity of disk y, I₂ = initial angular momentum of disk Y = 0 (since it is initally stationary) where I₃ = final angular momentum of disk x = Ixω and I₄ = final angular momentum of disk Y = Iyω where Iy = rotational inertia of disk y and ω = their common angular velocity after the collisionFrom the law of conservation of angular momentum, we have that
initial angular momentum equals final angular momentum
So, I₁ + I₂ = I₃ + I₄
Ixω₀ + 0 = Ixω + Iyω
Ixω₀ = Ixω + Iyω
From the above, we see that
Since I₄ > I₂ = 0,
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the collision.
Also, since I₁ + I₂ = I₃ + I₄,
The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system immediately before the collision.
So, the statements that are true are
The angular momentum of disk Y immediately after the collision is greater than the angular momentum of disk Y immediately before the collision.The angular momentum of the disk X-disk Y system immediately after the collision is equal to the angular momentum of the system immediately before the collision.Learn more about angular momentum here:
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what is meant by tyndall effect? in point wise with example.
Answer:
scattering of light
Explanation:
is the scattering of light as a light beam passes through a colloid. The individual suspension particles scatter and reflect light, making the beam visible. ...