Which statement is true regarding the circuit schematic below?


A.
The resistor is connected near the negative terminal of the battery.
B.
At the present time, the circuit is complete.
C.
This is a direct current circuit.
D.
This is an alternating current circuit.

The resistance of the gold wire cannot be determined with the information given. The resistance of a wire depends on several factors, including its length, cross-sectional area, and resistivity.

While we know the resistance of the aluminum wire, we do not know any of these other factors for the gold wire. Additionally, the resistivity of gold is different from that of aluminum, so even if we did know all the other factors, we could not simply use the same resistance value for the gold wire.

Therefore, to determine the resistance of the gold wire, we would need more information, such as its length and cross-sectional area.

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Answer:

4 times what it is now.

Explanation:

g=G(M/r^2)

G is constant, so ignore.

We have (1M/0.5r^2), or 4.

Answer:

4g

Explanation:

the equation of g (field gravity)

g = G M/R²

because G (Contant of Gravitasion) and M (Mass of earth) same, them

g2/g1 = R1²/R2²

g1 = g now

g2 = g which the value we looking for

g2/g = 1/(1/2)²

g2/g = 1/(1/4)

g2/g = 4

g2 = 4g

Answer:

Option (b) he is moving with a constant speed (on average)

Explanation:

To know which option is correct, let us calculate the speed at each time.

Case 1:

Distance = 10 yard

Time = 1 s

Speed =?

Speed = distance / time

Speed = 10 / 1

Speed = 10 yard/s

Case 2:

Distance = 20 yard

Time = 2 s

Speed =?

Speed = distance / time

Speed = 20 / 2

Speed = 10 yard/s

Case 3:

Distance = 30 yard

Time = 3 s

Speed =?

Speed = distance / time

Speed = 30 / 3

Speed = 10 yard/s

Case 4:

Distance = 40 yard

Time = 4 s

Speed =?

Speed = distance / time

Speed = 40 / 4

Speed = 10 yard/s

From the calculations made above, we can see clearly that the speed at each case is the same i.e constant. This is true because he is covering the same distance with respect to time.

This also means that the footballer is not accelerating as his speed remains the same i.e constant.

Thus, option B gives the correct answer to the question.

The answer is option B.

The compound Ammonia (NH3) is an example of a molecular compound.

What are Molecular Compounds?

Molecular compounds are chemical substances that are formed by the combination of atoms of two or more distinct elements and are held together by covalent bonds.

The elements in molecular compounds share electrons.

These compounds have a simple structure and low boiling and melting points and are mostly in the gaseous phase at room temperature.

How are molecular compounds formed?

Molecular compounds are formed by the combination of two or more nonmetals.

The elements share their electrons, forming covalent bonds.

This allows them to form new molecules that have different physical and chemical properties than the elements they were made of.

For example, water (H2O) and methane (CH4) are two common molecular compounds.

Other compounds such as ionic compounds, atomic elements, and molecular elements do not share electrons between atoms, hence they are not considered molecular compounds.

Thus, the compound Ammonia (NH3) is an example of a molecular compound.

The answer is option B.

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Answer:

Object distance should be 48

Explanation:

in pic

_____________________________

(hope this helps can I pls have brainlist (crown)☺️)

The force exerted by the fire hose is 2.827 kN

First, we need to calculate the area of the jet using the formula for the area of a circle:

Area = π x (radius)^2

We know the diameter of the jet is 0.6m, so the radius is half of that

radius = 0.6m / 2 = 0.3m

Plugging this value into the formula, we get:

Area = π x (0.3m)^2 = 0.2827 m^2

Next, we can use the formula for pressure to calculate the force exerted:

Pressure = Force / Area

Rearranging this formula to solve for force, we get:

Force = Pressure x Area

Plugging in the given values, we get:

Force = 10 kPa x 0.2827 m^2 = 2.827 kN

Therefore, the force exerted by the fire hose is 2.827 kN (kilonewtons).

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Stars began to develop as the Big Bang's cloud the cosmic gas and dust began to cool, and these stars eventually coalesced to create galaxies. In such stars and in enormous stellar bursts known as supernovae.

In the instants following the Big Bang, the majority of the helium and hydrogen inside the universe were produced. Afterwards came the heavier components. A large variety of elements are created and dispersed by supernova explosions.

There was hydrogen, a little amount of helium, and a trace amount of lithium in the beginning, and at least immediately after the Big Bang and over 14 billion years ago. a total of three components. With hundreds of variations, currently there are only about 100 recognised naturally occurring elements.

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When a person blacks out, their hippocampus is unable to record new memories.

In a region of the brain known as the hippocampus, our brain retains a short-term memory of the experience. Later, the memories are consolidated, or moved to a different region of the brain, where they will be stored for a longer period of time.

Alzheimer's disease normally starts by destroying neurons and the connections between them in the cortex and hippocampus, two regions of the brain essential in memory.

Later, it has an impact on the parts of the cerebral cortex that control language, thought, and social interaction. The majority of short-term memory is kept in the frontal lobe of the cerebral cortex.

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Answer:

The potential energy of the roller coaster increases as the coaster goes up a hill and can be converted to kinetic energy.

Answer:

see my answer

Explanation:

1.A wood

2.Plastic stuffs

3.A stone

Answer:

Explanation:

Answer:

B. Displacement

Explanation:

The area under a velocity time graph is equal to the displacement of objects.

The change in gravitational potential energy, GPE for the 8 Kg object which is lowered from a height of 10 m to 4 m is -470.4 J

We'll begin by obtaining the initial potential energy. Details below:

PE₁ = mgh₁

PE = 8 × 9.8 × 10

PE = 784 J

Next, we shall determine the final potential energy. Details below:

PE₂ = mgh₂

PE = 8 × 9.8 × 4

PE = 313.6 J

Finally, we shall determine the change in the potential energy. This is shown below:

ΔPE = PE₂ - PE₁

ΔPE = 784 - 313.6

ΔPE = -470.4 J

Thus, the change in potential energy is -470.4 J

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The optimal values of \(q_1\) and \(q_2\) are determined by these equations, which are functions of Michael's income and the prices of the goods.

The given problem describes Michael's utility maximization problem with a constant elasticity of substitution (CES) utility function. The objective is to find the optimal values of \(q_1\) and \(q_2\) in terms of Michael's income (Y) and the prices of the two goods (\(p_1\) and \(p_2\)).

1. Substitute the income constraint into Michael's utility function:

\(U(q_1, q_2) = (q_1^\rho + q_2^\rho)^(1/\rho)\)

  s.t. \(Y = p_1q_1 + p_2q_2\)

  We can rewrite Michael's budget constraint as \(q_2 = (Y - p_1q_1)/p_2\). Substituting this expression into his utility function, we have:

 \(U(q_1, p_2, Y) = (q_1^\rho + [p_2(Y - p_1q_1)/p_2]^\rho)^{(1/\rho)\)

  By making this substitution, we have converted the constrained maximization problem with two control variables (\(q_1\) and \(q_2\)) into an unconstrained problem with one control variable \((q_1)\).

2. Use the standard unconstrained maximization approach to determine the optimal value for \(q_1\). To obtain the first-order condition, we differentiate the utility function with respect to \(q_1\) and set it equal to zero:

\(\delta U / \delta q_1 = \rho(q_1^{(\rho-1)} + \rho[p_2(Y - p_1q_1)/p_2]^{(\rho-1)}(-p_1/p_2)) = 0\)

Simplifying and solving for \(q_1\):

\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[p_2(Y - p_1q_1)/p_2]^{(\rho-1)} = 0\)

\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)} = 0\)

\(\rho q_1^{(\rho-1)} = \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)}\)

\(q_1^{(\rho-1)} = (p_1/p_2)[Y - p_1q_1]^{(\rho-1)\)

\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}[Y - p_1q_1]^{(\rho-1)}\)

\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y - p_1q_1)^{(\rho-1)}\)

\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y^{(\rho-1)} - (\rho-1)p_1q_1(Y - p_1q_1)^{(\rho-2)})\)

  This equation represents Michael's optimal \(q_1\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).

3. Similarly, we can derive a similar expression for his optimal \(q_2\):

\(q_2^{(\rho-1)} = (p_2/p_1)^(1-\rho)(Y^{(\rho-1)} - (\rho-1)p_2q_2(Y - p_1q_2)^{(\rho-2)})\)

  This equation represents Michael's optimal \(q_2\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).

Therefore, these equations, which depend on Michael's income and the prices of the commodities, determine the ideal values of \(q_1\) and \(q_2\).

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62.53 ohms

Explanation

Ohm's law states that the voltage or potential difference between two points is directly proportional to the current or electricity passing through the resistance, and directly proportional to the resistance of the circuit.

then

Step 1

a)let

now, replace in the formula

therefore, the answer is

62.53 ohms

I hope this helps you

Answer:

\(q_1=\pm0.03 \mu C\) and \(q_2=\pm0.02 \mu C.\)

Explanation:

According to Coulomb's law, the magnitude of  force between two point object having change \(q_1\) and \(q_2\) and by a dicstanced is

\(F_c=\frac{1}{4\pi\spsilon_0}\frac{q_1q_2}{d^2}-\;\cdots(i)\)

Where, \(\epsilon_0\) is the permitivity of free space and

\(\frac{1}{4\pi\spsilon_0}=9\times10^9\) in SI unit.

Before  dcollision:

Charges on both the sphere are \(q_1\) and \(q_2\), d=20cm=0.2m, and \(F_c=1.35\times10^{-4}\) N

So, from equation (i)

\(1.35\times10^{-4}=9\times10^9\frac{q_1q_2}{(0.2)^2}\)

\(\Rightarrow q_1q_2=6\times10^{-16}\;\cdots(ii)\)

After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.

Charges on both the sphere are mean of total charge, i.e

\(\frac{q_1+q_2}{2}\)

d=20cm=0.2m, and \(F_c=1.406\times10^{-4}\) N

So, from equation (i)

\(1.406\times10^{-4}=9\times10^9\frac{\left(\frac{q_1+q_2}{2}\right)^2}{(0.2)^2}\)

\(\Rightarrow (q_1+q_2)^2=2.50\times10^{-15}\)

\(\Rightarrow q_1+q_2=\pm5\times 10^{-8}\)

As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.

\(\Rightarrow q_1+q_2=5\times 10^{-8}\;\cdots(iii)\)

\(\Rightarrow q_1=5\times 10^{-8}-q_2\)

The equation (ii) become:

\((5\times 10^{-8}-q_2)q_2=6\times10^{-16}\)

\(\Rightarrow -(q_2)^2+5\times 10^{-8}q_2-6\times10^{-16}=0\)

\(\Rightarrow q_2=3\times10^{-8}, 2\times10^{-8}\)

From equation (iii)

\(q_1=2\times10^{-8}, 3\times10^{-8}\)

So, the magnitude of initial charges on both the sphere are \(3\times10^{-8}\) Coulombs\(=0.03 \mu C\) and \(2\times10^{-8}\) Colombs or \(0.02 \mu C\).

Considerion the nature of charges too,

\(q_1=\pm0.03 \mu C\) and \(q_2=\pm0.02 \mu C.\)

Answer:

Heat Input = Work Output       (at 100% efficiency)

ΔQ = ΔW

(you cannot get something for nothing)

need more context than that to answer

The 5-volt reading we can expect between the two test points if the reference lead is on the lowest voltage.

The given data is as follows:

The first test marked voltage = 5 volts

The second test marked voltage = -3.3 volts

Let us assume that the two test points are there is a conductive track between them, the voltage between the two points can be calculated using the voltage difference between the two test points.

The voltage difference between the  two test points is calculated as:

5 volts - (-3.3 volts) = 8.3 volts

If the reference lead is on the lowest voltage, It means that the negative side of the voltmeter is attached to the test point with the lower voltage which is -3.3 volts.

The voltage difference between the  two test points is

8.3 volts - 3.3 volts = 5 volts

Therefore we can conclude that the 5-volt reading we can expect between the two test points.

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Answer:

A

Explanation:

I took that test

Answer:

D

Explanation:

Through the process of cellular respiration, Energy in food is converted into energy that can be used by the body.

During cellular respiration, glucose and oxygen are converted into carbon dioxide and water, energy is transferred  to ATP  

Amphibians retain a set of gills their whole lives that help them to breathe in the water. So, the correct option is D.

Amphibians are defined as the class of cold-blooded vertebrates which is made up of frogs, toads, salamanders, newts, and caecilians. All amphibians that spend part of their lives in water and part of their lives on land.

Amphibians are born with gills, and some outgrow them when they become adults while others retain them for their entire lives.

Thus, the correct option is D.

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The two parts of 'measurements' are precision and accuracy. The maximum weight that can be accurately measured in a top-loading electronic balance in your lab depends on the specifications and capacity of the balance.

To determine the maximum weight, you need to consult the user manual or specifications provided by the manufacturer. Similarly, the minimum weight that can be accurately measured depends on the balance's sensitivity and resolution. Again, you should refer to the specifications or user manual to determine the minimum weight that can be accurately measured by your specific balance.

Electronic balances have different weight capacities and sensitivities, so it is crucial to consult the manufacturer's specifications. For example, a top-loading electronic balance might have a maximum weight capacity of 300 grams with a readability of 0.01 grams. This means that the balance can accurately measure weights up to 300 grams with a precision of 0.01 grams. The minimum weight that can be accurately measured might be specified as the balance's minimum sample weight, which could be, for instance, 0.1 grams. It is important to adhere to these specifications to ensure accurate and reliable measurements.

To determine the specific maximum and minimum weights for your top-loading electronic balance, please refer to the manufacturer's specifications or user manual.

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Answer:

mercury

Explanation:

edge 2020

The speed of the platform so that the person detects a beat frequency of 1.00 Hz is 5.286m/s.

The speaker moving towards the wall is emitting the sound of frequency of 115Hz and the platform right next to the speaker is detecting the sound reflected by the wall and emitted by the speaker.

Now, to find the speed of the platform so that the person here the beta frequency pf 1.00Hz, we will use the relation,

F = (c+v/c-v)f

c = Speed of waves in the medium

u = Speed of the receiver relative to the medium

v = Speed of the source relative to the medium

f = emitted frequency

Our values are given,

Beat frequency = 7Hz

Reflective Doppler frequency = 225+7=232Hz

Putting values,

232 =  (c+v/c-v)225

solving further,

v = 5.286 m/s.

So, the speed of the platform shoud be 5.286m/s.

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The electric force is small in comparison because charges are VERY small but the

gravitational force has to do with the mass of the Earth and Moon.

The football player applies a pressure of 30 Newtons per square meter (N/m²) to the grass.

Pressure is a physical quantity that measures the force exerted per unit area on a surface. It is defined as the force applied perpendicular to the surface divided by the area over which the force is distributed. In simpler terms, pressure is the amount of force distributed over a given area.

To calculate the pressure the football player applies to the grass, we can use the formula:

Pressure = Force / Area

Given that the force exerted by the player's shoes on the grass is 12N and the surface area of the shoes is 0.4m², we can substitute these values into the formula:

Pressure = 12N / 0.4m²

Pressure = 30 N/m²

Therefore, the football player applies a pressure of 30 Newtons per square meter (N/m²) to the grass.

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Answer:

10 m/s

Explanation: