Which three terms are needed to describe the energy a BASE jumper has as

she falls toward the ground?

O A. Potential

B. Electromagnetic

C. Gravitational

D. Kinetic

The coefficient of static friction between the block of wood and the table is 0.449.

The weight of the block of wood is Mg = 4.0 kg × 9.81 m/s^2 = 39.24 N.

The coefficient of static friction μs is given by the equation μ_s = fs/N, where N is the normal force from the table.

Since the block is not accelerating vertically, we know that N = Mg, so we have:

μs = fs/N = 17.64 N / 39.24 N = 0.449

Therefore, the coefficient of static friction between the block of wood and the table is 0.449.

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The average velocity of the car is 100 kilometers/hour south. This means that, on average, the car is traveling 100 kilometers per hour in the south direction relative to its starting point.

To determine the average velocity of the car, we need to calculate the displacement and divide it by the time taken. Velocity is defined as the rate of change of displacement with respect to time.

In this case, the car is traveling south, and its displacement is 200 kilometers from its starting point after 2 hours.

The average velocity is given by the formula:

Average velocity = Displacement / Time

The displacement is 200 kilometers south, and the time is 2 hours. Therefore, we have:

Average velocity = 200 kilometers south / 2 hours

Simplifying the calculation:

Average velocity = 100 kilometers/hour south

Hence, the correct answer is B. 100 kilometers/hour south. This indicates that the car's average velocity is 100 kilometers per hour towards the south direction.

It's important to note that velocity is a vector quantity and includes both magnitude (speed) and direction. In this case, the direction is specified as south, which indicates that the car is moving towards the south relative to its starting point.

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Answer:

The options that increase greenhouse gases are:

Coal burning power plant

Exhaust from a car

Wind power and solar power do not increase greenhouse gases, as they are considered renewable energy sources that do not produce direct emissions of greenhouse gases during their operation.

Explanation:

Answer:

Explanation:

Coal burning power plants and exhaust from a car increase greenhouse gases

Wind power and solar power do not produce greenhouse gases

I hope this helps!

Answer:

Lower than it should be.

Explanation:

Hello.

In this case, since the density is computed by:

\(\rho =\frac{m}{V}\)

And we obtain the volume of the solid by substracting the mass of the water and the solid minus the mass of water:

\(V_{solid}=V_{solid\ with \ water}-V_{water}\)

If some water is splashed out of the cylinder, the volume of water will be lower than originally measured, it means that the volume of the solid will be higher than real. In such a way, since the density is in an inversely proportional relationship with volume, as the volume of the solid is wrongly increased, therefore the density of the solid will be lower than in should be.

Regards.

Answer:

increace

Explanation:

they are both going up

"Distance" here is the total distance traveled along the red path (see attached) from point A to point B. Just count how many how sides of each square in the grid are touched by the path. Then distance = 24 units.

"Displacement" is the net distance covered by moving from point A to point B, or the length of the green path. So displacement = 2 units to the right. Of course, your question seems to ask for the displacement in terms of units to the left, in which you could say -2 units to the left.

Answer:

1 km

Explanation:

displacement =velocity ×time

displacement =40m/s ×25s

displacement =1000m equivalent to 1km

The spring stiffness constant of the spring is 1276.44 N/m.

We know that Hooke’s Law is given by, F = -kx, where F is the force applied to an object, x is the displacement caused by the force, and k is the spring constant.

Therefore, the spring stiffness constant of the spring is given by k = -F / x.Let us first determine the potential energy of the ball, which will be equal to the kinetic energy of the ball when it strikes the spring. We can use the formula, PE = mgh, where m is the mass of the ball, g is the acceleration due to gravity, and h is the vertical distance fallen by the ball.

Therefore, the potential energy of the ball is given by,PE = mgh= 2.60 kg × 9.81 m/s² × 0.55 m= 14.38 JNow, the ball will transfer all its potential energy to the spring, which will store it as potential energy in the form of elastic potential energy. Therefore, the elastic potential energy stored in the spring is given by, PE = (1/2)kx², where x is the compression of the spring.

Therefore, we have,PE = (1/2)kx²

= (1/2)k (0.15 m)²

= 0.01125 k J

Setting the two expressions for PE equal to each other, we get,1

4.38 J = 0.01125 k JK

= (14.38 J) / (0.01125 J/k)

= 1276.44 N/m

Therefore, the spring stiffness constant of the spring is 1276.44 N/m.

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Answer:

C

Explanation:

I think it's C, because at that point, you are going fastest. Sorry if im wrong, hope this helps.

Answer:

In between and the middle one

Explanation:

The  example that represents a class 2 lever is: D. a screwdriver opening a paint can.

The load is situated in a class 2 lever halfway between the fulcrum and the effort. The screwdriver's resting place against the paint can's rim serves as the fulcrum in this scenario.

The paint can's lid serves as the load, and the force exerted by the hand on the screwdriver's handle serves as the effort. A class 2 lever can be identified by the load being situated between the fulcrum and the effort.

Tweezers, salad tongs, and opening and closing a car door are not examples of class 2 levers. Class 1 levers include things like tweezers and salad tongs, whereas class 3 levers include things like car doors that open and close.

Therefore the correct option is D.

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Volume air = 1700 L(7.50 ⋅ 10^−4 K ^− 1 − 3 ⋅ 1.20 ⋅ 10^−5 K^−1) ⋅ 9 K ≈ 10.9L

Volume is a measurement of three-dimensional space that is occupied. [1] Numerous imperial units or SI-derived units, such as the cubic metre and litre, are frequently used to quantify it numerically (such as the gallon, quart, cubic inch). Volume and length (cubed) have a symbiotic relationship. The volume of a container is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the amount of fluid (liquid or gas) that the container may hold.

Arithmetic formulas can be used to quickly calculate the volume of several straightforward three-dimensional shapes. If a formula for the shape's boundary is known, it is possible to use integral calculus to determine the volumes of more complex shapes. Nothing in the dimensions of zero, one, or two has volume.

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The time the force was applied to the obeject of mass 0.4 kg is 12 seconds

Impulse is the product of force and time.

To calculate how long the force was applied, we use the formula of impulse.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for t

Hence, the time is 12 seconds

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(a) The time of flight be for a tennis ball launched by the ball machine is 0.19 s.

(b) The range of the tennis ball be is 1.01 m.

(c)  The final velocity of the ball with which it reaches the ground is 7.16 m/s.

The time of flight of the tennis ball is calculated as follows;

h = vt + ¹/₂gt²

1.2 = 5.3t + 0.5(9.8)t²

1.2 = 5.3t + 4.9t²

4.9t² + 5.3t - 1.2 = 0

a = 4.9, b = 5.3, c = 1.2

solve using quadratic formula

t = 0.19 s

Thus, the time of flight be for a tennis ball launched by the ball machine is 0.19 s.

The range of the tennis ball is calculated as follows;

R = vt

R = 5.3 x 0.19

R = 1.01 m

The final velocity of the ball with which it reaches the ground is calculated as follows;

vf = vo + gt

vf = 5.3 + 9.8(0.19)

vf = 7.16 m/s

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Answer:

what does the outer part of the disk turn into

Explanation:

4) it gets sucked into the star

Answer:

The building was Painted

The building was painted last year by someone.

Answer:

True

Explanation:

The intensity of the sound is determined as 0.36 W/m².

The intensity of a sound is defined as the amount of energy transmitted per unit area.

I = P/A

where;

The area is calculated as follows;

A = 4πr²

A = 4 x π x (5.8²)

A = 422.73 m²

The intensity of the sound is calculated as follows;

I = 150 W / 422.73

I = 0.36 W/m²

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The intensity of a sound wave can be calculated using the formula:

Intensity = Power / Area

In this case, we are given that the power of the speaker is 150 Watts. To calculate the area, we need to consider the distance at which the sound wave is measured. The area of a sphere can be calculated using the formula:

Area = 4πr^2

where r is the radius of the sphere. In this case, the distance from the speaker to the measuring point is given as 5.8 meters. So, the radius of the sphere is half of this distance, which is 2.9 meters.

Plugging these values into the formula, we get:

Area = 4π(2.9)^2 = 105.52 square meters

Now we can calculate the intensity:

Intensity = 150 / 105.52 = 1.42 Watts per square meter

Therefore, the intensity of the sound wave produced by the 150 Watt speaker from a distance of 5.8 meters is approximately 1.42 Watts per square meter.

The cannon and ball are initially moving at a speed of 1.27 m/s. The cannon is fired, propelling the ball forward at a speed of 75 m/s. The post-explosion velocity of the gun is 6.18 m/s.

Total momentum prior = Total momentum subsequent

(3.5 kg + 0.52 kg) × 1.27 m/s = 3.5 kg × \(v_{cannon}\) + 0.52 kg × 75 m/s

where \(v_{cannon}\)is the velocity of the gun following the explosion.

When we simplify and solve for \(v_{cannon}\), we get:

\(v_{cannon}\) = (0.52 kg × 75 m/s - (3.5 kg + 0.52 kg) × 1.27 m/s) / 3.5 kg

\(v_{cannon}\) = 6.18 m/s.

Velocity is a measure of how quickly an object changes its position in a particular direction. It is commonly represented as a vector quantity with both magnitude and direction. The magnitude of velocity is the speed at which an object is moving, while the direction is the path it is following.

In physics, velocity is a fundamental concept used to describe motion in various contexts, including mechanics, kinematics, and dynamics. It is calculated as the rate of change of displacement with respect to time, expressed in meters per second (m/s) or other units.

Velocity is a critical parameter in understanding the behavior of objects and systems, such as vehicles, projectiles, fluids, and celestial bodies. It affects their acceleration, force, energy, and other characteristics that determine their motion and interactions. Engineers, scientists, and other professionals use velocity to design, analyze, and optimize a wide range of applications, from transportation to manufacturing to space exploration.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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The owl started out at a height of about 3.2 metres.

Gravity is the force that draws objects toward the center of a planet or other object.

Gravitational potential energy (GPE) is calculated as follows:

GPE = mass x gravity x height. Since we are aware of the owl's mass (4 kg) and the change in GPE (-800 J) in this case, we can rewrite the formula to account for the height: tallness = GPE / (mass x gravity).

On Earth, the acceleration caused by gravity is roughly 9.8 m/s2.

By entering the known numbers, we obtain the height change as follows: -800 J / (4 kg x 9.8 m/s2) = -0.408 metres.

By combining the ultimate height (which is believed to be 0 metres) with the height change, we may get the initial height as follows: 0 m + (-0.408 m) = -0.408 m = 0.408 m = 3.2m.

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We need the position vectors of a particle at two points along its path and also know the time it took to move from one point to the other to find the instantaneous velocity but not the average velocity.

We need to take a moment to be able to explain to ourselves again the meaning of the term velocity. Let us recall that the term velocity would have to do with the change in the position of an object with time.

We know that the velocity is a vector quantity and as such we must have to look at the direction in which the distance that has been covered has passed through and this is something that we must keep in  mind as we work through this question.

Now, we know that the velocity is the change in position as such we need the two positions of the object and the approximate time taken to make the change.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

Respon

lqiudos ciopatmibes

ly  apsamtios ccoriendor sabe r

llpop

io.

Answer:

Solid, liquid, gas, plasma (your right!)

Explanation:

Think about having to add heat(energy) to each state of matter, and then think of which state of matter would be a result.

Solid ice + heat= liquid water

liquid water+ heat= water vapor (steam which is a gas)

Given,

The height from which the object was dropped, h=100 m

The speed of the object, v=25 m/s

The acceleration due to gravity, g=9.8 m/s²

The object will have only potential energy when it is at rest at the height of 100 m. As the object falls it will slowly lose its potential energy. The potential energy thus lost will be converted into the kinetic energy of the object.

Thus the potential energy lost by the object when it has a speed of 25 m/s will be equal to its kinetic energy at that instant.

Therefore,

Where Δh is the change in the height of the object or the height through which the object has fallen at that instant.

On substituting the known values,

Thus the height of the object above ground is,

Thus the height of the object above the ground when it has a speed of 25 m/s is 68.11. m

Answer:

t = 0.67 [s]

Explanation:

To solve this problem we must use the following kinematics equation.

\(v_{f} =v_{i} +(a*t)\\where:\)

Vf = final velocity = 20[m/s]

Vi = initial velocity = 10 [m/s]

a = aceleration = 15 [m/s^2]

Now replacing in the equation we have:

20 = 10 + (15*t)

t = (20-10)/15

t = 0.67 [s]

Complete question is;

a. Two equal sized and shaped spheres are dropped from a tall building. Sphere 1 is hollow and has a mass of 1.0 kg. Sphere 2 is filled with lead and has a mass of 9.0 kg. If the terminal speed of Sphere 1 is 6.0 m/s, the terminal speed of Sphere 2 will be?

b. The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1. The masses remain 1.0 kg and 9.0 kg, The terminal speed (in m/s) of Sphere 2 will now be

Answer:

A) V_t = 18 m/s

B) V_t = 10.39 m/s

Explanation:

Formula for terminal speed is given by;

V_t = √(2mg/(DρA))

Where;

m is mass

g is acceleration due to gravity

D is drag coefficient

ρ is density

A is Area of object

A) Now, for sphere 1,we have;

m = 1 kg

V_t = 6 m/s

g = 9.81 m/s²

Now, making D the subject, we have;

D = 2mg/((V_t)²ρA))

D = (2 × 1 × 9.81)/(6² × ρA)

D = 0.545/(ρA)

For sphere 2, we have mass = 9 kg

Thus;

V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρA))]

V_t = 18 m/s

B) We are told that The cross sectional area of Sphere 2 is increased to 3 times the cross sectional area of Sphere 1.

Thus;

Area of sphere 2 = 3A

Thus;

V_t = √[2 × 9 × 9.81/(0.545/(ρA) × ρ × 3A))]

V_t = 10.39 m/s

Answer:

true

Explanation:

normally -No system has ever performed well with one object.

A system must contain more than one object is a true statement.

A system is a group of interacting or interrelated objects that act according to a set of rules to form a unified whole.

Normally, no system has ever performed well with one object.

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Answer:   Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.

(The energy acquired by the objects upon which work is done)

The energy efficiency of the car is approximately 16.7%.

The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:

The useful work output can be calculated as the kinetic energy of the car using the equation:

where m is the mass of the car and v is its velocity.

Substituting the given values:

The total energy input is the energy released by burning 0.1 L of gasoline, which is:

Substituting these values into the equation for efficiency:

Therefore, the energy efficiency of the car is approximately 16.7%.

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