Why are models of atoms and molecules useful explain

Answers

Answer 1

Answer:

The models are larger versions of atoms/molecules. It is a visualization so we can understand the super small particles.

Explanation:

Atoms and molecules are very, very, small. They average 100 picometers across.

They definitely cannot be seen with the naked human eye. We can only see them with special microscopes (electron, optical, etc).  that magnify hundreds of thousands of times.

So, we use models of atoms and molecules. It allows us to study, visualize, understand,  and "see" the particles on a much larger scale.


Related Questions

A merry-go-round is spinning in a circle at a constant speed. A child is 4 meters away from the center of the merry-go-round and experiences a centripetal acceleration of 6 m/s^2. What is the tangential velocity of the child?

A.) 1.5 m/s
B.) 24.0 m/s
C.) 9.1 m/s
D.) 4.9 m/s

Answers

The velocity is 4.9 m/s.

What is the centripetal acceleration?

Centripetal acceleration is the acceleration that acts towards the center of a circular path and is required to maintain an object in circular motion. It is defined as the rate of change of velocity of an object moving in a circular path.

The formula for centripetal acceleration can be expressed as:

a_c = v^2 / r

Given that;

a = v^2/r

a = acceleration

v = tangential velocity

r = radius

Thus;

v = √ar

v = (6 * 4)^1/2

v = 4.9 m/s

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A steel ring with a hole having area of 3.99 cm² is to be placed on an aluminum rod with cross- sectional area of 4.00 cm². Both rod and ring are initially at a temperature of 35.0 °C. At what common temperature can the steel ring be slipped onto one end of the aluminum rod? ​

Answers

The common temperature at which the steel ring can be slipped onto one end of the aluminum rod is 33.0°C. This is because the expansion of both materials due to the temperature rise need to be balanced for the steel ring to fit on the aluminum rod. The equation for this is A1T2 = A2T1, where A1 and A2 are the areas of the steel ring's hole and the aluminum rod, respectively, and T1 and T2 are the initial and the common temperatures. Solving this equation yields T2 = 33.0°C.

Gary is on the space shuttle. It takes off and lifts him to a height of 300 km above Earth's surface.

a. How has Gary's mass changed? Explain.

b. How has Gary's weight changed? Explain.

Answers

Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.

What is Earth's surface?

The Earth's surface is a living union of its solid crust, atmosphere, hydrosphere, and biosphere, all of which have worked together to create a continually regenerating and dynamic symphony of form. From the Solar System Encyclopedia.

It has a substantial and dynamic surface with mountains, valleys, canyons, plains, and a variety of other features. Earth is unique in that it is an ocean world. 70% of the Earth's surface is covered by water. The Earth's atmosphere is mainly nitrogen, with enough of oxygen for humans to breathe.

a) The mass of an object is an intrinsic attribute, which means that it is determined only by the qualities of the thing and is not affected by its position. As a result, Gary's mass at 300 kilometers above the Earth's surface equals his mass at the Earth's surface.

b) The weight of an object is given by, W = mg

where

m is the mass and g = GM /r²

It is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.

At the Earth's surface, g = 9.81 m/sec²

so Gary's weight is W = mg

W = 9.81 m  ...........(1)

where m is Gary's mass.

Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is, R = 6370 Km.

So the distance of Gary from the Earth's center is:

r = R + h

r = (6370 +300) Km

r = 6670 km

r = 6.67 × 10⁶ m

The Earth's mass is M = 5.97 × 10²⁴ Kg , so the gravitational acceleration is, g₁ = GM /r²

g₁ = [(6.67 10⁻¹¹ m³ kg⁻¹ s⁻²) × (5.97 × 10²⁴ Kg)] ÷ (6.67 × 10⁶ m)²

g₁ = 8.95 m/sec²

Therefore, Gary's weight at 300 km above Earth's surface is:

W₁ = mg₁

W₁ = 8.95 m  ............(2)

If we compare (1) and (2), we find that Gary's weight has changed by

W₁/W = 8.95 m/ 9.81 m

W₁/W = 0.91

So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.

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The scale on the horizontal axis is 8 s per division and on the vertical axis 5 m per division. What is the time represented by the third tic mark on the horizontal axis

Answers

Answer:

24 s

Explanation:

8 s / tic    *    3 tic = 24 sec from origin

A thorium atom of mass 232.038 u decays by the emission of an alpha pa a radium atom of mass 228.031 u. If the alpha particle has a mass of 4.00 w much energy in J is released in the process?​

Answers

The energy released in the decay of a thorium atom to a radium atom and an alpha particle is 6.43 × 10^-13 J.

How much energy released in the process?​

The mass defect, Δm, is the difference in mass between the initial thorium atom and the final products (radium and alpha particle), and is given by:

Δm = (mass of initial thorium atom) - (mass of radium atom + mass of alpha particle)

Δm = 232.038 u - 228.031 u - 4.00 u

Δm = 0.007 u

where;

u stands for atomic mass unit.

The energy released in the decay is equal to the mass defect multiplied by the speed of light squared, according to Einstein's famous equation

E = Δmc^2

E = Δm * c^2

where;

c is the speed of light.

Substituting the values, we get:

E = 0.007 u * (1.66054 × 10^-27 kg/u) * (2.998 × 10^8 m/s)^2

E = 6.43 × 10^-13 kg m^2/s^2

E = 6.43 × 10^-13 J

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The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.

Answers

The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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how long would it take for a resultant upward force of 100 N to increase the speed of 50 Kg object from 100 m/s to 150 m/s ?

With explanations please....and the very ways..

Answers

Answer:

\(force = mass \times acceleration \\ 100 = 50 \times a \\ a = 2 \: {ms}^{ - 2} \\ from : \: \: v = u + at \\ 150 = 100 + (2 \times t) \\ 50 = 2t \\ time = 25 \: seconds\)

PLEAS HELP
Answer the questions in the picture pleas

PLEAS HELPAnswer the questions in the picture pleas

Answers

False - Not all poisons are made in labs. Many naturally occurring substances can also be poisonous, such as certain plants and animals.

True - People can be exposed to toxins through ingestion (eating or drinking), inhalation (breathing in), injection (such as with drugs), and absorption through the skin.

False - Poisoning is not a very common method of murder today. While it does happen, other methods such as firearms, suffocation, and blunt force trauma are more common.

False - There are more than 4 types of controlled substances. In the United States, controlled substances are categorized into 5 schedules based on their potential for abuse and medical use.

Wat are the controller substance?

The 5 groups of controlled substances in the US are:

Schedule I: Substances with no currently accepted medical use and a high potential for abuse, such as heroin and LSD.

Schedule II: Substances with a high potential for abuse and dependence, but also with currently accepted medical uses, such as morphine and cocaine.

Schedule III: Substances with a lower potential for abuse and dependence than Schedule II drugs, but still with accepted medical uses, such as anabolic steroids and some barbiturates.

Schedule IV: Substances with a lower potential for abuse and dependence than Schedule III drugs, such as benzodiazepines and some prescription stimulants.

Schedule V: Substances with the lowest potential for abuse and dependence, such as cough medicines containing small amounts of codeine.

The common effects of each group vary, but they can include pain relief, sedation, euphoria, and other psychoactive effects.

Anabolic steroids can have many harmful effects on the body, including:

Liver damageHigh blood pressureIncreased risk of heart disease and strokeDecreased fertilityMood swings and aggressionAcne and other skin problemsHair loss

Alcohols can be toxic to many tissues in the body, including the liver, brain, and gastrointestinal tract.

Bioterrorism is the deliberate release of biological agents (such as bacteria or viruses) with the intent to harm or kill people, animals, or plants.

Strychnine is a highly toxic substance that can cause muscle spasms and convulsions, leading to respiratory failure and death. Other symptoms can include restlessness, agitation, and high blood pressure.

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RI, SI
-HALF-LIVES-
DIRECTIONS: Each circle represents the sample of parent and daughter material after
half-life. Shade the fraction of the circle that is pareat material. Write the fraction belom the
circle. The element that you are working with is a hypothetical and is called Brownlim. The
half-life of Brownism is 500 years.
оно
Ө 10
о
роз
о
010

Answers

If you need to shade the part of a circle indicative of parent material, these are the guidelines:

Start by drawing a circle that embodies the entire region under discussion.Assess the proportion of the circle illustrating the parent material. Suppose that the parent material comprises 60% of the total surface area; in this instance, you would have to fill in or darken 60% of the circle.

How to explain the information

It should be noted that to complete the shading process, employ techniques such as utilizing solid colors with pencils, markers, cross-hatching, or diagonal lines.

Ensure that you correctly portray the shaded fraction of the circle and provide clear contrasts between the unshaded segment.

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What phase of matter has the highest energy?

Answers

Answer:

plasma is the state with the highest energy level.

quark-gluon plasma. aka just plasma

A radio is rated as 50 W. Calculate the energy transferred in Joules by the radio when it has been switched on for 2 minutes?

Answers

The energy transferred in Joules by the radio when it has been switched on for 2 minutes would be 6000 Joules.

Energy transfer

Power is defined as the rate of energy transfer or the rate at which work is done, and is given by the equation:

Power = Energy transferred / Time

Rearranging the equation to solve for energy transferred, we get:

Energy transferred = Power x Time

We are given:

Power = 50 W

Time = 2 minutes = 120 seconds

Therefore, the energy transferred by the radio when it has been switched on for 2 minutes is:

Energy transferred = Power x Time = 50 W x 120 s = 6000 J

In other words, the energy transferred by the radio is 6000 Joules.

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A mass with a charge of 4.60 x 10-7 C rests on a frictionless surface. A compressed spring exerts a force on the mass on the left side. Three centimeters to the right of the mass is a 7.50 x 10-7 C fixed charge. How much is the spring compressed if its spring constant is 14 N/m

Answers

Answer:

The compression of the spring is 24.6 cm

Explanation:

magnitude of the charge on the left, q₁ = 4.6 x 10⁻⁷ C

magnitude of the charge on the right, q₂ = 7.5 x 10⁻⁷ C

distance between the two charges, r = 3 cm = 0.03 m

spring constant, k = 14 N/m

The attractive force between the two charges is calculated using Coulomb's law;

\(F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(4.6\times 10^{-7})(7.5\times 10^{-7})}{(0.03)^2} \\\\F= 3.45 \ N\)

The extension of the spring is calculated as follows;

F = kx

x = F/k

x = 3.45 / 14

x = 0.246 m

x = 24.6 cm

The compression of the spring is 24.6 cm

PLS HELP FAST!!

A ball is rolling along a frictionless track as shown. If it starts at A. with a speed of 12m / s , what is its speed when it arrives at B? Use the conservation of mechanical energy to arrive at the answer. Assume no non- conservative forces. Show complete work for full credit.

PLS HELP FAST!!A ball is rolling along a frictionless track as shown. If it starts at A. with a speed

Answers

The speed of the object that the point that have been marked as B is 14 m/s

What is the conservation of mechanical energy?

The conservation of mechanical energy is a fundamental principle in physics that states that the total mechanical energy of a system remains constant as long as no external forces do work on the system. This principle applies to systems where only conservative forces are involved, meaning forces that can be derived from a potential energy function.

We know that the kinetic energy is equal to the potential energy thus we have that;

\(1/2mv^2 = mgh\\1/2v^2 = gh\)

v = √2gh

v = √2 * 9.8 * 10

v = 14 m/s

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If distance between two charges increased 5 times then force between them

If distance between two charges increased 5 times then force between them

Answers

decreased 5 times

Explanation: if the force increases 5 times between them would decrease 5 times

= 1.2M²₂// then taking a penedy A constant force of 5N ads to 5 sec. on a mass of 5 kg initially at rest. calculate the final momentum!​

Answers

The final momentum is 25 Kg m/s

What is the momentum?

In physics, momentum is a measure of an object's motion, calculated by multiplying the object's mass by its velocity. Mathematically, momentum is represented by the symbol "p" and can be expressed as:

p = mv

where "p" is momentum, "m" is mass, and "v" is velocity. Momentum is a vector quantity, meaning that it has both a magnitude (the amount of momentum) and a direction (the direction of the motion).

Given that;

Ft = mv - mu

It then follows that;

F = force

m = mass

v and u are the initial and the final velocities

Thus;

5 * 5 = 5v

v = 25/5

= 5 m/s

The final momentum is thus;

5 m/s * 5 Kg

= 25 Kg m/s

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help me................ its two parts

help me................ its two parts

Answers

Your answer would be 21!

A 10 cm wide box is held between two springs in a 1 m gap on a frictionless surface. The left spring has a natural length of 80 cm and spring constant of 200 N/m. The right spring has a natural length of 90 cm and spring constant of 350 N/m. How far is the center of the box from the left edge in m

Answers

Answer:

The distance is  \(x =0.291 \ m\)

Explanation:

From the question we are told that

     The width of the box is \(b = 10 \ cm = \frac{10}{100} = 0.10 \ m\)

     The gap is of length \(l = 1\ m\)

    The natural length of the first spring is \(y = 80 \ cm = \frac{80 }{100} = 0.8 \ m\)

     The spring constant of the first spring is  \(k_1 = 200 N/m\)

     The second spring has a natural length of \(z = 90 \ cm = \frac{90}{100} = 0.9 \ m\)

      The spring constant of the first spring is  \(k_2 = 350 \ N/m\)

Let the distance from the center of the box to the left edge be x

      So at equilibrium

The force applied by the first spring is

      \(F_1 = k_1 * (0.8 -x)\)

and

The force applied by the second spring is

        \(F_2 = k_2 * [ 0.9 - (0.9 -x)]\)

Now at equilibrium

       \(F_1 = F_2\)

So

     \(k_1 * (0.8 -x) = k_2 * [ 0.9 - (0.9 -x)]\)

    substituting values

      \(200 * (0.8 -x) = 350 * [ 0.9 - (0.9 -x)]\)

        =>   \(160 -200x) = 350x\)

        =>  \(160 =550x\)

          =>   \(x =0.291 \ m\)

at which point is the object most likely to land assuming that it was subject to air resistance

Answers

The point at which the object from a free fall is mostly likely to land on the ground assuming that it was subject to air resistance is that point when the upward force of the air resistance of the object equals the force of gravity downward wise.

What is meant by air resistance?

Air resistance simply refers to that special force which is made manifest in an opposite direction to an object moving through air. In order words, it is a kind of force which exert a frictional force against an object in motion.

That being said, from the context of the problem given above, this body will land the moment it attains what we call a terminal velocity.

In conclusion, we can now confirm and deduce from the explanation made from above that until the terminal velocity is achieved before the object on a free fall will be able to land ignoring air resistance.

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at which point is the object most likely to land assuming that it was subject to air resistance

Ultrasonic images are obtained from the inside organs of our body. This process uses which property of sound wave?

Answers

This question involves the concepts of echo, ultrasonic images, ultrasonic sound waves.

The process of ultrasonic images uses the "echo" property of the sound waves.

Echo is the property of the sound wave by the virtue of which the sound wave reflects back to the source of the sound after hitting a surface or an object.

Ultrasonic images are obtained from inside organs of our body. This process involves the use of ultrasonic sound waves that have a frequency greater than 20,000 Hz. These sound waves are out of the range of audible sound by the human ear. When these ultrasonic sound waves are sent in form of pulses into the human body by the use of probes, they reflect back from the tissues of different organs to the probe. The probe then records the reflection properties of these sound waves and displays them in form of an image, known as ultrasonic images.

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The attached picture shows the process of ultrasonic imaging.

Ultrasonic images are obtained from the inside organs of our body. This process uses which property of

How long does it take light from a camera to travel to the face of someone standing 7 meters away?

Answers

The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

Speed = distance / time

With the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:

Distance = 7 m

Speed of light = 3×10⁸ m/s

Time =?

Time = Distance / speed

Time = 7 / 3×10⁸

Time = 2.33×10¯⁸ s

Therefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

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Jonny is pushing a 50-kg large package along the dorm room floor with 150 N force. Both the direction of push and the floor are horizontal. While he is pushing the package, it moves in a straight line with constant 0.6 m/s speed. Please ignore air-resistance and make sure to justify your answers to the questions below.
a) (10 points) Write down as much information as you can about the main horizontal forces exerted on the package (names, directions, and if enough information is given, numerical values).
b) (10 points) Write down as much information as you can about the main vertical forces exerted on the package (names, directions, and whenever possible, if enough information is given, numerical values).
c) (5 points) How far did the package move during 3 seconds of pushing? Explain
d) (5 points) What was the package’s acceleration during that time? Explain
2

Answers

a. The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

b. The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

c. The package moves 1.8 m

d. The package's acceleration is 0 m/s²

a. The horizontal forces

The push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.a

Since the direction of push and the floor is horizontal, and first horizontal force acting on the package is the push and its magnitude is 150 N.

Also, a frictional force also acts to oppose the motion of the package.

Since the packge moves at a constant velocity of 0.6 m/s, its acceleration is zero and thus the net force on the package is zero.

Let

F = push force and f = frictional force

So, F - f = 0

F = f

= 150 N

So, the frictional force is 150 N and opposite to the push.

So, the push is 150 N and acts to the right while the frictional force is 150 N and acts to the left.

b Vertical forces on package

The weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

Since the floor is horizontal, the vertical forces that act on the package are its weight and the normal force due to the ground.

The direction of the weight is downwards while the direction of the normal force is upwards.

Since the floor is horizontal and the package does not move in the vertical direction, the net vertical force is zero.

Let W = weight of package = mg where m = mass of package = 50 kg and g = acceleration due to gravity = 9.8 m/s² and N = normal force

So, the net force N - W = 0

N = W

= mg

= 50 kg × 9.8 m/s²

= 490 N

So, the weight is 490 N and acts downwards while the normal force is 490 N and acts upwards.

c. Distance package moves

The package moves 1.8 m

Since distance, d = vt where

v = velocity = 0.6 m/s and t = time = 3 s

So, d = vt

= 0.6 m/s × 3 s

= 1.8 m

So, the package moves 1.8 m

d. The package's acceleration

The package's acceleration is 0 m/s²

Since the net force on the package is zero, its acceleration is also zero. Since force, F = ma where

m = mass of package and a = acceleration of package

Since F = 0,

ma = 0

a = 0

So, the package's acceleration is 0 m/s²

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Which sentence best explains the law of conservation of mass as applied to
chemical reactions?
A. The amount of mass changes only slightly during a chemical
reaction.
B. The volumes of the reactants and products are equal during a
chemical reaction.
C. The types of atoms can change during a chemical reaction, but
their masses cannot.
D. In a chemical reaction, the total mass of the reactants equals the
total mass of the products.

Answers

Answer:

A. The amount of mass changes only slightly during a chemical

reaction.

b) A hammer of weight 100 N falls freely on a nail from height 1.25 m. Find the impulse and average force of blow if impact last for 10-² S.​

Answers

Answer:

Explanation:

When the hammer hits the nail it transfers this energy to the nail in order to move it 1cm (0.01m). A transfer of energy is known as "work done" and work done = force x distance. So, force = work done / distance = 25 / 0.01 = 2500N Answer: Average force = 2500 Newtons.

A wire carries a steady current of 2A.the Charge that passes a cross Section in 2s is

Answers

Answer :

◈ Electric current :

Electric current is defined as the rate of charge flow. (per unit time)

I = Q/t

I denotes current

Q denotes charge

t denotes time

Given : I = 2A and t = 2s

To Find : Charge flow in wire (Q)

\(:\implies\sf\:I=\dfrac{Q}{t}\)

\(:\implies\sf\:2=\dfrac{Q}{2}\)

\(:\implies\:\boxed{\bf{\red{Q=4\:C}}}\)

A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current.  The charge that will be in the wire is 4 C.

What is current?

A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current. The capital letter I is a typical sign for current. The ampere, abbreviated as A, is the standard unit.

As it is given to us that the current in the wire is 2A, while the time for which the current flows through the wire is 2 seconds.

\(\rm I=\dfrac Qt\)

Substitute the value we will get,

\(\rm 2\ A = \dfrac{Q}{2\ sec}\\\\Q = 4\ C\)

Thus, the charge that will be in the wire is 4 C.

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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.

Answers

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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What is A rounded to the nearest tenth?
A
HHHHHHHHHHH
14
14.2 14.4
14.6
14.8
15
14.1 14.3 14.5 14.7 14.9
What is A rounded to the nearest one?

Answers

Answer: B

Explanition:

The rate of decay of a radioactive sample is given by R1 at time t1 and R2 at a later time t2 . The mean life of this radioactive sample is:​

Answers

Hope this answer helps you

The rate of decay of a radioactive sample is given by R1 at time t1 and R2 at a later time t2 . The mean

1 poin 4. If the same strength force is exerted on two objects but the objects have different masses, the object with mass will have a greater change in velocity. O more O less O greater O the same​

1 poin 4. If the same strength force is exerted on two objects but the objects have different masses,

Answers

Answer:

hellli

Explanation:

Sir

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Another elephant pushes with 3500 N on a load of trees. It then pushes these trees for 225 m. How much work did he elephant do?

Answers

Answer:

787, 500 N/m

Explanation:

Work = Force • displacement

\(Work = (3500 N)(225 m) = 787500\frac{N}{m}\)

\(W = (3500 N)(225 m) = 787500\frac{N}{m}\)

Each of the following figures shows a person (not to scale) located on Earth at either 40°N or 40°S latitude. Rank the figures based on how much time the person spends in daylight during each 24-hour period, from most to least. To rank items as equivalent, overlap them.

Answers

Figure at 40°N in June: This figure experiences the most daylight as it is located at a high latitude during the summer solstice, where the days are longest.Figure at 40°S in December: This figure experiences a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.Figure at 40°N in December: This figure experiences less daylight compared to the previous two figures as it is located at a high latitude during the winter solstice.Figure at 40°S in June: This figure experiences the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere.

The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.

The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.

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