why does aluminum dent when hit with a hammer whereas glass shatters?

Answer:

Adding the length of the tape measure case.

Answer:

the equivalent resistance of the circuit decreases and the total current of the circuit increases. 

Explanation:

hope this helps

False.Drain-induced barrier lowering (DIBL) is not desirable for CMOS devices in general. Explanation:Drain-induced barrier lowering (DIBL) is the reduction of the threshold voltage of a MOSFET (metal-oxide-semiconductor field-effect transistor) that occurs as the drain voltage increases.

This can lead to a reduction in the transistor's switching speed, which is undesirable for most CMOS devices.The threshold voltage, which determines whether the transistor is on or off, is reduced by DIBL. When the voltage at the drain terminal of the MOSFET is increased, the electric field generated by the drain voltage interacts with the charge distribution at the channel surface, causing it to expand, and reducing the potential barrier between the source and channel regions, reducing the threshold voltage.In general, DIBL is not desirable for CMOS devices since it limits their switching speed. Therefore, circuit designers aim to minimize DIBL by controlling the transistor's channel length and other device parameters to ensure that the threshold voltage remains relatively constant regardless of the drain voltage.

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Note that the above prompt is related to the use of Autodesk Software. The cause of the above warning is: "The Revit or view settings prohibit the newly generated object from being displayed."

Autodesk is a design software firm that serves customers in the manufacturing, architectural, building, and construction sectors, as well as media and entertainment. Autodesk has been in the forefront of robotics, augmented and virtual reality, and 3D printing.

It is to be noted that the Autodesk design tool is important because it is extensively utilized in many sectors.

It helps professionals in designing, testing, and visualizing goods and systems in a virtual environment, which may be more efficient and cost-effective than doing so in the actual world.

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Full Question:

Autodesk Related Prompt

Issue:

When creating an element, section, or linking a file within Revit, you receive the following warning message:

Warning

"None of the created elements are visible in Floor Plan: Level 2 View. You may want to check the active view, its Parameters, and Visibility settings, as well as any Plan Regions and their settings."

What is the cause of the above warning?

102 sheets of 4' x eight' pieces of plywood will it take to cover a 24' wall.


locating the quantity of sheets of plywood wanted for a ground, wall, ceiling, or cabinet starts with locating the vicinity that wishes to be covered. vicinity may be located with the aid of multiplying the period and width of the gap in toes. find the rectangular pictures of each space and upload together to locate the whole square photos wanted. Divide by way of the entire square footage by the square footage of a sheet of  to discover the range of sheets required to cover the gap. A 4×eight sheet of plywood is 32 ft².
for example, if the place to be blanketed in plywood is 800 ft² then 25 sheets of plywood can be had to cowl it.
800 ÷ 32 = 25 sheets

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Answer:

The risks associated with the handling of liquid hydrogen are fire, explosion, asphyxiation and extremely low temperature exposure.

Answer:

fire, explosion, asphyxiation, extremely low temperature exposure/cold burns

Explanation:

Answer:

C) Prospective Cohort study

Explanation:

prospective cohort study can be regarded as longitudinal cohort study that comes up with periods of time when group of individuals that are different in terms of some factors that are undergoing some study, so that how theses factors influence rates of some particular outcomes can be known.

The angular velocity of the bracket is 0.773 rad/s.

To solve this problem, we can use the equation for relative velocity between two points on a rotating object:

v_B = v_A + ω x r_A/B

Where v_B is the velocity of point B, v_A is the velocity of point A, ω is the angular velocity of the object, r_A/B is the position vector from point A to point B, and x denotes the cross product.

First, we need to find the position vector r_A/B. We can use the law of cosines to find the length of the vector:

| r_A/B |^2 = | L_A |^2 + | L_B |^2 - 2 | L_A | | L_B | cos θ

Substituting the given values, we get:

| r_A/B |^2 = 2^2 + 2.5^2 - 2(2)(2.5) cos 30° = 4.5625

Taking the square root, we get:

| r_A/B | = 2.135 m

Next, we can plug in the given values for v_A and r_A/B:

-0.9198i - 3.89j = v_A + ω x (2.135i - 2j)

Expanding the cross product, we get:

-0.9198i - 3.89j = v_A + (-2ω j - 2.135ω k)

Equating the i and j components, we get two equations:

-0.9198 = v_Ax
-3.89 = v_Ay - 2ω

Solving for v_Ax and v_Ay, we get:

v_Ax = -0.9198 m/s
v_Ay = -2.135ω - 3.89 m/s

Finally, we can use the formula for angular velocity:

ω = v_Ay / (-2 | L_B |)

Substituting the given value for L_B, we get:

ω = (-2.135ω - 3.89) / (-2 * 2.5)

Simplifying, we get:

ω = 0.773 rad/s

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As a general overview, the term "Weld Center Vertices" typically refers to a feature or option that is used in 3D modeling or computer-aided design (CAD) software.

This feature is usually used in conjunction with a "Fill Hole" mode, which is a tool that is used to fill in holes or gaps in 3D models.

When the "Weld Center Vertices" option is enabled in a "Fill Hole" mode, the software will attempt to connect the vertices or points around the hole by creating a new surface or face that is centered on the vertices. This can be useful for creating a more uniform and seamless 3D model, particularly when dealing with complex shapes or irregular surfaces.

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Answer:

Explanation:

In this context, we are dealing with the cooling of hot air as it flows through tubes exposed to atmospheric air. Based on this, we can make the following statements:

a. Heat transfer coefficient inside the tube will be higher - This statement is false. As the hot air flows through the tube and comes into contact with the cooler atmospheric air outside the tube, heat transfer occurs between the two fluids. In this process, the temperature difference between the two fluids drives the heat transfer. Therefore, the heat transfer coefficient inside the tube will be lower because the hot air will have a higher temperature than the atmospheric air, and the temperature difference will be smaller.

b. Heat transfer coefficient inside the tube will be lower - This statement is true, as explained in the previous statement.

c. Fins should be attached to the outside of the tube - This statement is true. Fins are used to increase the surface area of the tube, which in turn increases the rate of heat transfer between the hot air inside the tube and the atmospheric air outside. Attaching fins to the outside of the tube will increase the surface area exposed to the atmospheric air, facilitating faster cooling of the hot air.

d. Fins should be attached to the inside of the tube - This statement is false. Attaching fins to the inside of the tube will actually reduce the effective cross-sectional area of the tube, restricting the flow of air and hindering the heat transfer process. Therefore, fins should be attached to the outside of the tube to maximize the surface area and facilitate efficient heat transfer.

Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

Article 430 that is found in  National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .

Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.

Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

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Answer:B

Explanation: Dead Grass more flammable than wood and Green grass contains water.

The type of operational layout for each occupations are as follows: 1) Cold Drink Manufacturer : Process Layout- It is additionally known as a functional layout. The maintenance of identical equipment doing similar tasks in one location is typical of job shop manufacturing. For example, all lathes are kept in one area, all milling machines are kept in another, all ball grinding machines are kept in a third, and so on. When each machine completes a huge number of jobs, we employ process layout.

2. Fashion Designer Specialising in couture evening gowns: Product Layout- This is known as line arrangement. Based on the required sequence of procedures for the product, machines and equipment are arranged in a single line. The primary distinction between the product and process layouts is the workflow pattern. There is no backtracking or variation in the movement of materials from one workstation to the next. Duplicate equipment is employed to prevent backtracking, departments or equipment are dedicated to a specific product line, and material transportation is carried out in a straight line. With storage for works-in-progress and material management, raw material (GOWNS) moves quickly between workstations in this system. When there is a lot of production, the product choices is constrained and the product layout is expensive.

3) Building Contractor :Assembly Line Balancing-The total amount of work assigned to a workstation is equal to the sum of the tasks assigned to that workstation. The assembly-line balancing problem involves allocating all jobs to a series of workstations in a way that each workstation receives no more work than it can process in its cycle time, and idle time is maintained to a minimum across all workstations. The challenge is made more difficult by the connection between demands imposed by product design and process technology. The precedence relationship, which establishes the order in which tasks in the assembly process must be finished, is known as this.

4)Shipbuilding:Group or Cellular layout-The process architecture gets even better when facilities are networked or grouped into cells. This is a step in the right direction towards integrating "Group Manufacturing Systems" into plant designs. This allows for some personalization while yet offering some advantages of mass production. The group layout combines the product and process layouts. The advantages of both designs are combined in it. Identifying families or groups comes first, followed by configuring the plant and equipment to accommodate a particular family of components. The reduction of the overall cost of material handling is the aim of process layout. Equipment costs will be kept to a minimum with this design. Costs associated with material handling will be kept to a minimum in product layout. However, if the equipment is fully utilised, the expense is only little.

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Real-world fluid flows can exhibit a combination of laminar and turbulent characteristics, depending on factors such as flow velocity, fluid properties, and the presence of obstacles or disturbances.

a) Liquid moves faster in a turbulent flow than in a laminar flow.

This statement is generally true. In a turbulent flow, the fluid moves in a chaotic manner, characterized by eddies and swirling motion. This turbulent motion enhances the mixing and transport of fluid particles, which can result in higher overall flow velocities compared to laminar flow, where fluid moves smoothly in parallel layers.

b) Turbulent flow produces more noise than laminar flow.

This statement is generally true. Turbulent flow is associated with fluctuating velocities and pressure fluctuations, which can generate noise. The irregular motion and collisions of fluid particles in turbulent flow create vibrations and sound waves, resulting in higher noise levels compared to the smooth, ordered flow of laminar flow.

c) Laminar flow does not change in time (it is a quasi-steady state), while turbulent flow is unsteady.

This statement is generally true. Laminar flow is characterized by smooth and ordered flow with parallel streamlines. It remains relatively constant over time, assuming steady conditions. On the other hand, turbulent flow is characterized by irregular and unsteady motion with constantly changing velocities and pressure fluctuations. Turbulent flow exhibits fluctuations in time and space due to the presence of eddies and vortices.

d) Streamlines of a laminar flow stick together, but diverge in a turbulent case.

This statement is generally true. In laminar flow function, adjacent fluid particles move smoothly and in parallel along the streamlines without significant mixing or cross-stream diffusion. As a result, the streamlines tend to remain close together and maintain their initial separation. In turbulent flow, however, the chaotic motion and mixing of fluid particles cause streamlines to diverge and become highly convoluted, leading to intermingling and spreading of fluid particles. Real-world fluid flows can exhibit a combination of laminar and turbulent characteristics, depending on factors such as flow velocity, fluid properties, and the presence of obstacles or disturbances.

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Answer:

 So its area A = 4 * 4sqrt(2) = 16sqrt(2) inches^2

Explanation:

In order to find the area of the section, we need to find the length of one of the diagonals.

Using the Pythagorean Theorem, a^2 + b^2 = c^2, we pick any side of the cube which in

itself is a square with sides 4 inches each.  The length of the diagonal of the square is

2(4^2) = c^2  or c = 4sqrt(2).

To calculate the area of the section, we must first determine the length of one of the diagonals. Using the Pythagorean Theorem, \(\bold{a^2 + b^2 = c^2}\), one selects any side of the cube which in its a square with four-inch sides.

           \(\to 2(4^2) = c^2 \\\\ \to c = 4\sqrt{(2)}\)

      \(\to A = 4 \times 4\sqrt{(2)} = 16\sqrt{(2)}\ inches^2\)

Therefore, the answer is "\(\bold{ 16\sqrt{(2)}\ inches^2}\)".

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Answer:

The correct approach is "12.56 Ω".

Explanation:

The given values are:

Frequency,

f = 100 Hz

Inductor length,

L = 20 mH

Now,

The inductive reactance will be:

⇒ \(X_L=2 \pi fL\)

On putting the estimated values, we get

⇒       \(=2 (3.14)\times 100\times 20\times 10^{-3}\)

⇒       \(=12.56 \ \Omega\)

Vector addition parallelogram law :If a force F needs to be broken down into its component parts along the axes b and c, one should start at the head of the force and build lines parallel to the axes until a parallelogram is formed.

Vector addition parallelogram law :If a force F needs to be broken down into its component parts along the axes b and c, one should start at the head of the force and build lines parallel to the axes until a parallelogram is formed.

The parallelogram's sides are represented by Fb and Fc.

Finding the force component F AB and F AC applied at diagram point A is our task.

We can employ the law of sines, as shown in the diagram.

The query is unfinished.

The entire question is included as an image in the attachment, and an explanation is given below.

F AB / sin 60  = 500/ sin 75

F AB = 500/0.965*0.866

F AB =  448.7 N

To find F AC

F AC /sin 45 =500 /sin 75

F AC = 500/0.965* 0.7071

F AC = 366.3 N

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Answer:

sorry im answering questions for the points cuz im built dfferent

Explanation:

Answer: That happens to me too sometimes. I hate when people give the wrong answers...like if u don't know the answer, then don't respond

The fraction of women having ectopic pregnancies who are smokers is 2/3 or approximately 0.67.


The probability of developing an ectopic pregnancy is twice as high for smokers compared to nonsmokers. Let's assume that the probability of developing an ectopic pregnancy for a nonsmoker is x. Then, the probability for a smoker would be 2x. We know that 32% of women of childbearing age are smokers.


Out of the 100 pregnant women, 32% are smokers, which means there are 32 smokers and 68 nonsmokers. If we assume that x women develop ectopic pregnancies, then the number of smokers who develop ectopic pregnancies would be 2x. Therefore, the fraction of women having ectopic pregnancies who are smokers would be: (2x)/(x + 2x)
Simplifying this fraction, we get: (2x)/(3x) which reduces to: 2/3.

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Answer:

20% of the critical value. Determine (a) the damping factor, (b) the

Explanation:

Put your printer through a hard reset. Try turning off both the printer and your computer, then restarting both if that doesn't fix the problem. Then try to remove and reinstall your printer's driver.

A problem with the printer itself may exist if the status of your printer reads "Printer in error state." Check to see if the printer is on and wired or wirelessly linked to your computer. Make sure the cover is closed and the paper isn't jammed, and check if there isn't enough paper or ink.

Of all printer errors, paper jams are arguably the most dreadful. There are a few problems that might be present when it comes to smudges, faded lettering, and poor image quality.

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Answer:

D) AND gate.

Explanation:

Given that:

A certain printer requires that all of the following conditions be satisfied before it will send a HIGH to la microprocessor acknowledging that it is ready to print

These conditions are:

1. The printer's electronic circuits must be energized.

2. Paper must be loaded and ready to advance.

3. The printer must be "on line" with the microprocessor.

Now; if these conditions are met  the logic gate produces a HIGH output indicating readiness to print.

The objective here is to determine the basic logic gate used in this circuit.

Now;

For NOR gate;

NOR gate gives HIGH only when all the inputs are low. but the question states it that "a HIGH is generated and applied to a 3-input logic gate". This already falsify NOR gate to be the right answer.

For NOT gate.

NOT gate operates with only one input and one output device but here; we are dealing with 3-input logic gate.

Similarly, OR gate gives output as a high if any one of the input signals is high but we need "a HIGH that is generated and applied to a 3-input logic gate".

Finally, AND gate output is HIGH only when all the input signal is HIGH and vice versa, i.e AND gate output is LOW only when all the input signal is LOW. So AND gate satisfies the given criteria that; all the three conditions must be true for the final signal to be HIGH.

Answer:

I think it is D

Explanation:

I did a couple mins of research on this topic but there is no clear line that separates a physical and chemical reaction, so do with that as you will. i hope I somewhat helped.

An airstart is an effective and reliable method of starting an engine without the use of electrical power.

An airstart is a type of engine start used in aviation that does not rely on electrical power. Instead, compressed air is used to start the engine. This is accomplished by feeding high-pressure air into the engine's turbine or compressor blades, which in turn causes the blades to rotate and initiate the combustion process.

Airstarts are commonly used in situations where there is no electrical power available, such as in remote locations or in emergency situations. For example, if an aircraft's main engines fail, an airstart from the auxiliary power unit (APU) can be used to restart the engines.

In addition to being a backup method of starting an engine, airstarts can also be used as the primary method of starting certain types of engines, such as small gas turbine engines used in ground support equipment or small aircraft.

Overall, an airstart is an effective and reliable method of starting an engine without the use of electrical power. It has been widely adopted in the aviation industry and is an important tool for ensuring the safety and reliability of aircraft operations.

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Answer: 0

Explanation: i need to add it up to get what u want

Stack with all ARIs (Activation Record Instances) when execution reaches position 1:

ARI for procedure BIGSUB (main program) - Contains variables x and y.

ARI for procedure A (called from BIGSUB) - Contains parameter flag.

ARI for procedure C (called from A) - Contains variable x.

ARI for procedure D (called from C) - No local variables.

ARI for procedure A (called from D) - Contains parameter flag.

Nonlocal reference to x at program point 1, assuming static scoping:

The nonlocal reference to x at program point 1 would be the variable x declared in the ARI of procedure C (the closest enclosing scope), since static scoping uses the lexical nesting of procedures to determine variable bindings.

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Answer:

a) 47500 mg/L

b) 5250366.444  kg/year

Explanation:

Given data:

suspended solids removal efficiency = 20%

Flowrate in the primary clarifier ( Q ) = 20 MGD ( change to Liters/day

Q = 20* 10^6 * 3.785412  Liters /day

settled concentration  ( St ) = 950mg/L * 0.2 = 190 mg/L

amount of settled solid = Q * St

                                   = ( 20* 10^6 * 3.785412 ) * 190  = 14384.5656 kg/day

∴ Amount going into sludge with a flowrate of 0.08 MGD = 14384.5656 kg/day

a) concentration of solid in sludge  ( leaving the clarifier )

= amount of settled solid / flow rate out of the clarifier in liters/day

= 14384.5656 / ( 0.08 * 10^6 * 3.785412 )

= 0.0475 kg/L

= 47500 mg/L

b) Determine mass of solids that is removed annually

= 14384.5656 kg/day * 365 days

= 5250366.444  kg/year