Why is electrical energy considered as potential energy as its the energy of moving electrons?

The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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Answer:

Use the drop-down menus to complete the statements.

All protists live in environments that are

✔ wet

.

All protists must

✔ reproduce

.

All protists have

✔ a nucleus

.

All protists make or consume

✔ food

Explanation:

I got it right hope its the right one

Answer:

Use the drop-down menus to complete the statements.

All protists live in environments that are  

✔ wet

.

All protists must  

✔ reproduce

.

All protists have  

✔ a nucleus

.

All protists make or consume  

✔ food

.

Explanation:

The acceleration of the Boeing 737 during takeoff is 1.389 m/s^2. This value represents the rate at which the aircraft's velocity changes with time.

The takeoff speed of an aircraft is the minimum speed required for the aircraft to become airborne and climb safely into the sky. The acceleration of an aircraft during takeoff is the rate at which its velocity changes with time. In this case, the takeoff speed of a Boeing 737 is 250 km/h and it reaches this speed after 50 seconds. To determine the acceleration, we need to calculate the change in velocity (final velocity minus initial velocity) and divide it by the time taken.

Detailed Explanation:

The initial velocity of the Boeing 737 is 0 km/h (assuming the aircraft is at rest before takeoff). The final velocity is 250 km/h. To convert these speeds from km/h to m/s, we divide by 3.6. The initial velocity is 0 m/s and the final velocity is 250/3.6 = 69.44 m/s. The change in velocity is 69.44 m/s - 0 m/s = 69.44 m/s. To find the acceleration, we divide the change in velocity by the time taken, which is 50 seconds.

Acceleration (a) = (change in velocity) / time

a = (69.44 m/s) / (50 s)

a = 1.389 m/s^2

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The kinetic energy of the car is calculated using the formula KE = (1/2)mv^2. By plugging in the mass of the car (1489 kg) and the speed (95.4 km/h), we can calculate the kinetic energy in kilojoules.

The kinetic energy of a 1489 kg car traveling at a speed of 95.4 km/h can be calculated using the formula for kinetic energy, which is given by the equation KE = (1/2)mv^2. By converting the speed from km/h to m/s, the kinetic energy can be determined in joules and then converted to kilojoules.

First, we need to convert the speed from km/h to m/s. We know that 1 km/h is equal to 0.2778 m/s. Therefore, the speed of the car in m/s is 95.4 km/h * 0.2778 m/s = 26.5 m/s.

Next, we can plug the values into the formula for kinetic energy: KE = (1/2)mv^2. Using the given mass of the car (1489 kg) and the calculated speed (26.5 m/s), we have KE = (1/2) * 1489 kg * (26.5 m/s)^2.

Calculating this expression gives us the kinetic energy of the car in joules. To convert it to kilojoules, we divide the result by 1000. The final answer will be in kilojoules, representing the amount of energy possessed by the car due to its motion.

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Answer:

u go to vanguard? in 6th grade

Answer:

is it correct ? sorry of it is incorrec

If the score is 8-3, it is impossible to determine from which side of the court the server should serve without additional information about the current game's score and which side the server served from in the previous point.

The score in a game does not determine which side of the court a player should serve from in tennis.

Instead, the server's position on the court depends on the number of points they have won in the current game and which side of the court they served from in the previous point.

In tennis, players switch sides of the court after every odd-numbered game (i.e., after the first, third, fifth games, etc.). In each game, the server serves from one side of the court for the first point, and then from the opposite side for the second point. The server then alternates sides every two points until the end of the game.

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Answer:

That is very true, there can never be 100% energy conversion.

Explanation:

A=b+d that is the way to rewrite the equation

When the resistor in the circuit has a larger resistance value, it will lower the total current that flows in the circuit.

In an electric circuit, resistance is the opposition that an electrical circuit exhibits to the flow of electric current. In general, resistance is measured in ohms (Ω).

When large resistance used:

When large resistor added:

As a result, adding a larger resistor to a circuit would lower the total current that flows in the circuit.

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Answer:

C. gravitational

Explanation:

Answer:

c

Explanation:

edge

If you fly at 100 miles per hour for a time of 2 hours and 30 minutes you will be a: 250 miles far

The formula and procedure we will use to solve this exercise is:

x = v * t

Where:

Information about the problem:

Applying the distance formula we have that:

x = v * t

x= 100 miles/h * 2,5 h

x = 250 miles

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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When standing on a train accelerating at 0.30 g, there is an effective force acting on you due to the acceleration. This force is equivalent to the force that would be experienced by an object with mass m = your mass under the influence of gravity and this force is resisted by the static friction force:

F = m * a

where a is the acceleration of the train and g is the acceleration due to gravity (approx. 9.81 m/s^2).

To avoid sliding on the floor of the train, the static friction force between your feet and the floor must be greater than or equal to the force due to the acceleration of the train. Therefore, we have:

f_s >= m * a

where f_s is the static friction force.

The maximum static friction force that can act between your feet and the floor is given by:

f_s = μ_s * N

where μ_s is the coefficient of static friction between your feet and the floor, and N is the normal force acting on your feet.

Since you are standing still relative to the train, the normal force acting on your feet is equal to your weight, which we can express as:

N = m * g

Substituting this into the expression for the maximum static friction force, we get:

f_s = μ_s * m * g

Substituting this expression for f_s into the inequality above, we get:

μ_s * m * g >= m * a

Simplifying this expression, we get:

μ_s >= a / g

Substituting a = 0.30 g and g = 9.81 m/s^2, we get:

μ_s >= 0.30

Therefore, the minimum coefficient of static friction that must exist between your feet and the floor to avoid sliding on the train is 0.30.

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The distance between the two point charges is 3.88 x 10⁻⁵ meters.

We use the Coulomb's law to solve this problem. Coulomb's law states that the electric force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Formula for Coulomb's law is;

F = k × (q₁ × q₂)/r²

where; F = electric force between the two charges

k = Coulomb's constant, approximately equal to 8.99 x 10⁹ Nm²/C²

q₁ and q₂ = charges of the two point charges

r = distance between the two point charges

Given; q₁ = -13 uC = -13 x 10⁻⁶ C (converting from microCoulombs to Coulombs)

q₂ = -16 uC = -16 x 10⁻⁶ C (converting from microCoulombs to Coulombs)

F = 12.5 N

We can put these values into the formula and solve for r;

12.5 = (8.99 x 10⁹) × ((-13 x 10⁻⁶) × (-16 x 10⁻⁶)) / r²

Simplifying;

12.5 = (8.99 x 10⁹) × (208 x 10⁻¹²) / r²

12.5 = (8.99 x 10⁹) × (2.08 x 10⁻¹⁰) / r²

Now, we can rearrange equation to solve for r;

r² = (8.99 x 10⁹) × (2.08 x 10⁻¹⁰) / 12.5

r² = 1.508 x 10⁻⁹

Taking the square root of both sides;

r = √(1.508 x 10⁻⁹)

r ≈ 3.88 x 10⁻⁵ meters

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Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

The relationship between the incident and reflected angles of a beam of light with different types of mirrors that both the angles are equal

According to the law of reflection, the angle of incidence equals the angle of reflection. Irrespective of mirror , whether it is a concave mirror , convex mirror or plane mirror , this law remain same in all condition where the incident angle is always equal to reflected angle .

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So here, we use the equation:

W = ΔKE + ΔPE

Recall that: KE = 0.5mv^2, and PE = qdΔV/D

ΔKE = 0.5m(v2)^2 - 0.5m(v1)^2, where v2 and v1 are Initial and final velocity respectively.

ΔPE = PE2 - PE1

PE2 = 0, since all energy is converted to other forms, mainly kinetic energy.

PE1 = q(d1)ΔV/D

Here, W = 0.

0 = 0.5m(v2)^2 - 0.5m(v1)^2 + 0 - q(d1)ΔV/D

Simplifying a bit, and knowing that d1 = D,

0 = 0.5m((v2)^2 - (v1)^2) - qΔV

Moving qΔV to the other side,

qΔV = 0.5m((v2)^2 - (v1)^2)

Dividing by q and isolating ΔV,

ΔV = 0.5m * ((v2)^2 - (v1)^2) / q

Now, we have ΔV, which is the electric potential difference, in terms of all the variables we know.

m = 9.1 * 10^-31

v2 = 1 * 10^6

v1 = 5 * 10^6

q = 1.602 * 10^-19 (this is a well known constant)

ΔV = 0.5*9.1*10^-31 * ((5*10^6)^2 - (1*10^6)^2) / 1.602*10^-19

Solving and simplifying all of this, we get that

ΔV = 68.25 V

Answer:

To find the work done in moving the particle from the origin to x = 2, we need to integrate the force over the given interval.

The work done (W) is calculated by integrating the force function with respect to displacement (dx) from the initial position (0) to the final position (2):

W = ∫(0 to 2) (10x³ - 5) dx

Integrating the force function, we get:

W = ∫(0 to 2) (10x³ - 5) dx = [2.5x⁴ - 5x] evaluated from 0 to 2

Now, substituting the upper limit (2) and lower limit (0) into the equation:

W = [2.5(2)⁴ - 5(2)] - [2.5(0)⁴ - 5(0)]

 = [2.5(16) - 10] - [0 - 0]

 = 40 - 10

 = 30

Therefore, the work done in moving the particle from the origin to x = 2 is 30 units of work.

Explanation:

The mass of the blood denoted is 501.6 g.

The mass of the blood denoted by Keona is calculated by applying the formula for density of a liquid as shown below.

density = mass/volume

mass = density x volume

The given parameters include;

The mass of the blood is calculated as follows;

mass = 1.06 g/mL x 473.176 mL

mass = 501.6 g

Thus, the mass of the blood is calculated from the formula of density.

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The complete question is below

While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of blood, which is equal to 473.176 mL. find the mass of the blood denoted.

Answer:

6

.40 recharge

1.0v

45.0v

We have:

vi = initial speed = 4 m/s

vf = final speed = 25 m/s

t= time = 5 s

a = acceleration = ?

Apply:

Replace with the values given:

Answer: 4.2 m/s^2

The Acceleration of the car is 4.2 m/s.

We will use the formula of acceleration.

a = vu - vi / t

Given:

vi = initial speed = 4 m/s

vu = final speed = 25 m/s

t= time = 5 s

a = acceleration = ?

Now, we will put the given values in the formula,

a = vu - vi / t

a = 25 - 4 / 5

a = 21 / 5

a = 4.2 m/s

Therefore, the Acceleration of the car is 4.2 m/s.

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The upward force exerted by the athlete's two arms is 33.9 N

To find the upward force exerted by the athlete's two arms during the press-up exercise, we need to consider the torques acting on the athlete-load system. The torque is the product of force and the perpendicular distance from the point of rotation.

The athlete-load system can be treated as a rigid body with a combined center of mass (CM) located between the athlete's and the load's center of mass. Assuming the system is in static equilibrium, the total torque acting on the system must be zero.

The torques acting on the system are due to the weight of the athlete, the weight of the load, and the upward force exerted by the arms. The weight of the system acts downwards, through the combined center of mass.

The torque due to the weight of the athlete is given by:

70 kg * g * 0.45 m, where g is the acceleration due to gravity (approx. 9.8 m/s^2) and 0.45 m is the perpendicular distance between the CM and the athlete's center of mass.

The torque due to the weight of the load is:

6.0 kg * g * 1.0 m, where 1.0 m is the perpendicular distance between the CL and the CM.

Since the system is in static equilibrium, the sum of the torques due to the upward force exerted by the arms must be equal and opposite to the sum of the torques due to the weights of the system. Therefore, we can write:

Sum of moments about CM:

0.3F - 0.1F = (0.9-0.6)Fg_athlete + (0.9-1.2)Fg_load

Simplifying and substituting the values of Fg_athlete and Fg_load:

0.2F = 6.78 Nm

Solving for F:

F = 33.9 N

Therefore, the upward force exerted by the athlete's two arms is approximately 33.9 N using torque to calculate it.

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When the parallel-plate capacitors are disconnected from a battery and plates are pulled a small distance farther apart then Q remains the same, C decreases, Change in potential increases, Energy stored increases and E stays the same.

Solution:

Let's take C as the capacitance of parallel plates and Q as the Charge stored and 'd' is the distance between a plate of capacitors.

In the case of disconnection between plate capacitors, the capacitance of a parallel-plate capacitor becomes equal.

Then, charge Q remains the same i.e.

Q = εA / d = Q / Ed = Q/V

Here Q refers to the charge stored in a capacitor, E is the Electric field, V is the potential difference, and 'd' is the separation between plates.

There is an inverse relationship between potential difference and distance against the capacitance between a plate of the capacitor.

Similarly, the potential difference will increase when capacitance decreases.

E = V/d

While the values of V and d show a gradual decrease, E remains constant, therefore energy stored in the capacitor will be E = 1/2CV^2

The decrease in C causes an increase in V, as a result of which energy stored in the capacitor increases.

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Answer:

The book remained in its state of rest before the car started to move forward as no direct force acted on it.

Explanation:

According to Newton's first law of motion, a body will continue in its present state of rest, or if it is in motion, will continue to move with uniform speed in a straight line unless aced upon by an external force. This tendency of a body to remain in its state of reset or uniform motion in a straight line is known as inertia and is directly proportional to the mass of the body. The more massive a body, the more inertia it possesses. Thus Newton's first law is also known as the law of inertia.

Considering the case of the book on the dashboard of a stationary car which suddenly starts to move. While the car is stopped at the traffic light, the dashboard where the book sits and the book are both at rest. When the car begins to move forward, the dashboard moves forward with it. However as the book is not a part of the car, no force is directly acting on it, so the book so it stays at rest due to its inertia.

Therefore, as the car is moving forward, the stationary book appears to move backward from the reference point of the car, sliding off the dashboard.

Answer:

dont know

Explanation:

need points

Answer:

d / λ = 26.7

Explanation:

In Young's double slit experiment, constructive interference is described by the expression

   d sin θ = m λ

In the case of destructive interference we must add half wavelength (λ/2)

   d siyn θ = (m + ½) λ

Let's clear

    d / λ = (m + ½) / sin θ

Let's calculate

   d / λ = (2+ ½) / sin 5.4

   d / λ = 5 / (2 sin 5.4)

   d / λ = 26.7

The ratio of the slit separation, d, to the wavelength of the light, λ will be 26.7.

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The expression for the constructive interference is given as;

\(\rm d sin\theta= m \lambda\)

For the destructive interference;

\(dsin \theta = (m+\frac{1}{2} )\lambda \\\\ \frac{d}{\lambda} =\frac{ (m+\frac{1}{2} )}{ sin \theta} \\\\ \frac{d}{\lambda} =\frac{(2+\frac{1}{2}) }{sin 5.4^0} \\\\ \frac{d}{\lambda} =26.7\)

Hence the ratio of the slit separation, d, to the wavelength of the light, λ will be 26.7.

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The scientist who suggested that the earth was at the center of the solar system is Ptolemy. His theory is known as the Ptolemaic system.

The Ptolemaic system was a geocentric model of the universe that was developed by the ancient Greek astronomer Ptolemy. According to this theory, the Earth is at the center of the universe, and the Sun, Moon, planets, and stars all revolve around it. Ptolemy's model was widely accepted and was considered to be the most accurate description of the universe until the Copernican system was proposed in the 16th century.

The Copernican system was a heliocentric model of the universe that suggested that the Sun was at the center of the universe, and the Earth and other planets revolved around it. Despite being proven incorrect, Ptolemy's theory had a significant impact on the history of science and astronomy. It laid the groundwork for future observations and discoveries, and it paved the way for the development of more accurate models of the universe.

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Correct answer is blue-purple.

Let's discuss it further below.

To find the wavelength most strongly reflected at the center of the outer surface when a soap bubble with a thickness of 120 nm is illuminated by white light, you should use the formula for constructive interference. Assuming the refractive index n = 1.34, follow these steps:

1. Calculate the optical path difference: The path difference is twice the thickness of the soap film multiplied by the refractive index (n). In this case, it is 2 × 120 nm × 1.34 = 321.6 nm.

2. Determine the wavelength of constructive interference: For constructive interference, the optical path difference must be equal to an integer multiple of the wavelength. Since the optical path difference is 321.6 nm, you can approximate the reflected wavelength to be around 321.6 nm.

3. Identify the color: A wavelength of approximately 321.6 nm corresponds to the blue-purple range of the visible light spectrum.

So, when a soap bubble with a thickness of 120 nm and refractive index of 1.34 is illuminated normally by white light, the wavelength most strongly reflected at the center of the outer surface is blue-purple.

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The work done by friction is zero as the rider started with potential energy which got converted into kinetic energy at the bottom of the hill. The rider didn’t apply brakes during the slide down the hill which could have resulted in work done by friction on the rider. Hence, the work done by friction on the rider is zero

The given problem involves the calculation of potential energy, kinetic energy, and work done by friction.

The potential energy gets converted to kinetic energy as the rider goes down the hill. The work done by the friction on the rider results in a reduction of kinetic energy.

The rider starts with potential energy which is given by, PE

where m = mass of the rider = 60 kg,

g = acceleration due to gravity = 9.8 m/s²,

h = height of the hill = 25 m

Hence, PE = (60 kg) x (9.8 m/s²) x (25 m)

                  = 147000 J

At the bottom of the hill, all potential energy gets converted into kinetic energy.

Hence, Kinetic energy = Potential energy = 147000 J

From the work-energy theorem, the work done by friction on the rider is given by,

W = ΔKE Mathematically, the work done by friction on the rider is the difference between the potential energy and the kinetic energy, which is equal to the initial potential energy,

W = PE – KE = 0 J

The work done by friction is zero as the rider started with potential energy which got converted into kinetic energy at the bottom of the hill. The rider didn’t apply brakes during the slide down the hill which could have resulted in work done by friction on the rider. Hence, the work done by friction on the rider is zero

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