Wind provides which kind of energy ? o The wind provides heat energy. o The wind provides chemical energy. The wind provides electrical energy. The wind provides energy of motion

The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)

Pressure (P) = Density (ρ) × g × Depth (h)

Given: Density of water (ρ) = 1000 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Depth (h) = 6 m

Using the given values, one can calculate the pressure:

Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure

= 58800 kg·m⁻¹·s⁻²

Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:

Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)

Pressure = 580.124 atm

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Answer:

Explanation:

Mass ( m ) = 2 kg

Speed of the object (v) = 6 metre per second

Kinetic energy =?

Now,

We have,

Kinetic Energy = \( \frac{1}{2} \times m \times {v}^{2} \)

Plugging the values,

\( = \frac{1}{2} \times 2 \times {(6)}^{2} \)

Reduce the numbers with Greatest Common Factor 2

\( = {(6)}^{2} \)

Calculate

\( = 36 \: joule\)

Hope this helps...

Good luck on your assignment...

The Kinetic energy of the object will be "36 joules".

The excess energy of moving can be observed as that of the movement of an object, component, as well as the group of components. There would never be a negative (-) amount of kinetic energy.

According to the question,

Mass of object, m = 2 kg

Speed of object, v = 6 m/s

As we know the formula,

→ Kinetic energy (K.E),

= \(\frac{1}{2}\) × m × v²

By substituting the values, we get

= \(\frac{1}{2}\) × 2 × (6)²

=  \(\frac{1}{2}\) × 2 × 36

= 36 joule

Thus the above answer is appropriate.

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Answer:

make a pineapple schematic

Explanation:

Answer:

Umm that's a personal question. All u have to do is say when have u pushed your personal limits....... Ummm one for me is when i had to try out for a select soccer and that is past my comfort zone.  

Explanation:

Answer:

You typically push past your personal limits when you are tired or worn out. As an athlete I tend to do this a lot, whether it’s in practice or in a game. One time I pushed past my personal limits is when I came back home to play football (soccer) on break, and ended up playing in a tournament with my team. We had made it to the finals and the other team had their two biggest, most physical guys marking me. They ended up stepping on my foot a few times and getting a bit too physical resulting in fouls, which I typically shrugged off, but one time they got me right in my toe joint. This made it extremely difficult to run and kick the ball due to the severe pain in my strong foot. I was also really tired considering I had been putting a lot of effort into making runs as a winger. To make matters even worse, my team had nobody to sub on for me, considering I’m the only one my coach uses for left wing. I ended up playing through these conditions and winning the tournament with my team, however I ended up being injured for the next 1-2 weeks.

This is more of a personal question but since you asked I'll answer

Via moving one vector so that its tail sits on the tip of the first vector, you may add by the tip-to-tail approach. New vector drawn from first vector's origin to the second vector's arrow is the resulting vector, A+B, or the sum of the two.

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Answer:

4th

Explanation:

Rise and fall of the water level on the sea shore

Answer:

Vy = g T       where T is the time taken to fall

1 = 1/2 g T^2      time to fall 1 m

T = (2 / 9.8)^1/2 = .45 sec

Vy = 9.8 * .45 = 4.43 m/s

V = (Vx^2 + Vy^2)^1/2 = (16 + 19.6)^1/2 = 5.97 m/s

.

(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.

Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.

The gravitational potential energy is given by:

mgh = (1.9 kg)\((9.8 m/s^2)h\)

The elastic potential energy stored in the spring is given by:

1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.

The kinetic energy of the box just before it makes contact with the spring is given by:

\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.

Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.

mgh = 1/2 \(kx^2\)

Substituting the given values, we have:

\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)

Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.

(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.

At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.

mgh = 1/2 \(kx^2\)

Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.

It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.

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Answer:

Brakes unevenly adjusted: Brakes pulling in one direction or the other can lead to a skid. Tires with worn tread: Tread is necessary for traction in wet weather

Explanation:

Answer: exhaust pipe

Explanation: It doesn't really control anything so I'm assuming this is the answer

Answer:

h = 57.6 m

Explanation:

First, we find the linear speed of the ball while in circular motion:

v = rω

where,

v = linear speed of ball = ?

r = radius of circle = length of rope = 1.75 m

ω = angular speed = (3 rev/s)(2π rad/1 rev) = 18.84 rad/s

Therefore,

v = (1.75 m)(18.84 rad/s)

v = 32.98 m/s

Now, we apply the 3rd equation of motion on the ball, when it breaks:

2gh = Vf² - Vi²

where,

g = - 9.8 m/s² (negative sign due to upward motion)

h = height covered = ?

Vf = Final Velocity = 0 m/s (since, the ball finally stops at highest point for a moment)

Vi = Initial Velocity = 32.98 m/s

Therefore,

2(- 9.8 m/s²)h = (0 m/s)² - (32.98 m/s)²

h = ( - 1088.12 m²/s²)/( - 19.6 m/s²)

h = 55.5 m

since, the ball was initially at a height of 2.1 m from ground. So, the total height from ground, will now become:

h = 55.5 m + 2.1 m

h = 57.6 m

Answer:

The frequency is  5.4 × 10^14Hz

Explanation:

The frequency of yellow-green light with a wavelength of 560 nm is approximately 5.4 x 10¹⁴ Hz.

The frequency of yellow-green light with a wavelength of 560 nm can be calculated using the formula:

frequency = speed of light/wavelength

Where the speed of light is approximately 3.0 x 10⁸ meters per second.

First, we need to convert the wavelength from nanometers to meters by dividing by 10⁹:

560 nm = 560 x 10⁻⁹ m

Then, we can plug in the values and calculate the frequency:

frequency = (3.0 x 10⁸ m/s) / (560 x 10⁻⁹ m)

frequency ≈ 5.4 x 10¹⁴ Hz

Therefore, yellow-green light with a wavelength of 560 nm has a frequency of approximately 5.4 x 1014 Hz.

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Answer:

A light-year is the distance light travels in one year.

Answer:

Explanation:

a unit of astronomical distance equivalent to the distance that light travels in one year, which is 9.4607 × 1012 km (nearly 6 million million miles).

Answer:  60 Joules (J)

Explanation:

To compute the work done by a force, you can use the formula:

Work = Force × Distance × cosθ

In this case, the force applied is 300 N, and the distance is 20 cm (which can be converted to meters by dividing by 100, giving us 0.20 m).

The angle θ represents the angle between the direction of the force and the direction of displacement. Since the force is used to compress the spring, the displacement is in the same direction as the force, and the angle θ is 0 degrees. The cosine of 0 degrees is 1, so we can omit the cosine term.

Now we can calculate the work done:

Work = 300 N × 0.20 m

Work = 60 Joules (J)

Therefore, the work done by the force in compressing the spring is 60 Joules (J).

When evaluated at 20 feet per second in a water tunnel, a parachute model that is one-fifth the size does have a drag of 450 pounds. When Reynolds Negligible consequences don't exist.

Something graded, especially if used as a benchmark or guideline, such as to show how far points on a map are from their corresponding real-world distances.

It was created to measure the body temperature of people. It has a mercury-filled bulb at the end of a long, narrow glass tube. The average body temperature of a person might vary between these ranges. Hence, the selection of clinical thermometers.

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Question :-

Answer :-

Explanation :-

As per the provided information in the given question, The Resistance is given as 330 Ohm . The Voltage is given as 5 Volt . And, we have been asked to calculate the Current .

For calculating the Current , we will use the Formula :-

\( \bigstar \: \: \: \boxed{ \sf{ \: Current \: = \: \dfrac{Voltage}{Resistance} \: }} \)

Therefore , by Substituting the given values in the above Formula :-

\( \dag \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } \)

\( \longmapsto \: \: \: \sf {Current \: = \: \dfrac {5}{330} } \)

\( \longmapsto \: \: \: \sf {Current \: = \: \dfrac {1}{66} } \)

\( \longmapsto \: \: \: \textbf {\textsf {Current \: = \: 66 }} \)

Hence :-

\( \underline {\rule {180pt} {4pt}} \)

Additional Information :-

\( \Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} \)

\( \Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } \)

\( \Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } \)

Thermal Window Curtains and Insulation are the two macroscopic properties that should be considered when constructing a home in the desert.

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Answer:

At zero kelvin (minus 273 degrees Celsius) the particles stop moving and all disorder disappears. Thus, nothing can be colder than absolute zero on the Kelvin scale. Physicists have now created an atomic gas in the laboratory that nonetheless has negative Kelvin values.

Explanation:

The United States still makes use of the form of measure that includes the units: feet, miles, and gallons while others make use of yards, kilometers and liters

This refers to the classification that describes the nature of the information within the values assigned to variables.

Therefore, we can see that the United States still makes use of the form of measure that includes the units: feet, miles, and gallons while others make use of yards, kilometers and liters

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The part of a road vehicle which must be tested to ensure that there is sufficient friction to stop the vehicle in an emergency is the tyre.

This is referred to as a force that resists the motion of one object against another when they roll or slide against each other.

When dealing with braking, the main factor is to have sufficient friction between the road surface and tyre to bring the vehicle to a standstill. If the tyres are wornout there won't be enough friction to make the vehicle stop during emergencies which is therefore the reason why it was chosen as the correct choice.

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The circuit in which lamps Q and R light but not lamp P when switch S is open is circuit B.

An electric circuit is a path for transmitting electric current.

Given the circuits below, when switch S is open, we want to determine the circuit in which lamps Q and R light but not lamp P.

To determine the circuit, we proceed as follows.

To determine the circuit in which lamps Q and R light but not lamp P, it must satisfy this condition

Looking at all the circuits, the circuit which satisfy these condition is circuit B

So, the circuit in which lamps Q and R light but not lamp P is circuit B.

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The net work done on the baseball to bring it to rest is -130.953 J or approximately 131 J. The negative sign indicates that the force has been applied opposite to the direction of motion of the baseball.

The work-kinetic energy theorem states that an object's change in kinetic energy is equivalent to the work that has been done on it.

\(W_{net} = KE_{f} -KE_{i}\)

Here,

\(W_{net}\) = Net work done

\(KE_{f}\) = Final Kinetic Energy

\(KE_{i}\) = Initial Kinetic Energy

We know,

\(KE = \frac{1}{2} mv^{2}\)

Here, m = Mass of the object

v = velocity of the object

Now,

\(W_{net} = KE_{f} -KE_{i}\\W_{net}= \frac{1}{2} mv^{2}_{f} - \frac{1}{2} mv^{2}_{i}\)

Given,

Mass of baseball (m) = 145g = 0.145 kg

Initial velocity (\(v_{i}\)) = 42.5 m/s

Final velocity (\(v_{f}\)) = 0 m/s  (since, the baseball comes to rest.)

Inserting these values in the above equation we get,

\(W_{net}= \frac{1}{2} mv^{2}_{f} - \frac{1}{2} mv^{2}_{i}\\ = 0- \frac{1}{2} *0.145*42.5*42.5 \\= -130.953\)

Hence, the net work done on the baseball to bring it to rest is -130.953 J or approximately 131 J.

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The interval of acceleration of the bus will be 2.19 seconds.

An object is considered to have been accelerated if its velocity changes. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change.

Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. These examples demonstrate how acceleration occurs whenever a moving object modifies its direction, speed, or both.

Acceleration is a vector quantity.

SI unit of acceleration is m/s.

According to the question, the given values are :

Acceleration, a=-4.1 m/s²

Initial velocity, u=9.0 m/s and,

Final velocity, v=0 m/s

By using Equation of motion, i.e.,

v=u+at

⇒0 m/s=9m/s+(-4.1 m/s²)(t)

⇒-9 m/s=-4.1 m/s²×t

t=(-9 m/s)/(-4.1 m/s²)

t= 2.19 seconds.

Hence, the time interval of acceleration of the bus will be 2.19 seconds.

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Answer:

They are used in periscopes, for signalling, in kaleidoscopes, to see round dangerous bends, in meters, as mirror tiles, in a sextant, in an overhead projector, an SLR camera, car wing mirrors, in microscopes and as reflecting number plates to mention only some!

Explanation:

Hope it is helpful....

Answer:

two uses are:

The frames will experience an induced electric current throughout their perimeter as they enter the magnetic field. For C, current will be at its best. Frame C will have greatest current among the three frames.

Velocity is constant if the displacement is persistent. The acceleration is constant if the rate of change velocity is maintained. Time is obviously continually changing and irreversible, just as the displacement in the object's position is.

The current brought on by the electromagnetic induction phenomena is known as the induced current. Electric power generation depends heavily on electromagnetic induction.

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The correct answer is Option B. The statement "they have the same A-number but different Z-number" is true .

Atoms of the same element only differ because one of the atoms has more electrons, making it an ion.

This difference does not affect the mass of the atom, which is determined by the sum of its protons and neutrons, represented by the atomic mass or A-number.

The number of protons in an atom is called the atomic number or Z-number.

The Z-number of an element is unique to it. All the atoms of a given element have the same number of protons.

Thus, for example, all carbon atoms have six protons, making the Z-number of carbon 6.

However, different isotopes of an element can have different numbers of neutrons.

This means that they have a different atomic mass or A-number.

Therefore, they have the same A-number but different Z-number.

Therefore the correct Option is B.

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Power is the energy per unit time. When the current flow is needed to produce the beam. The voltage that produced the current is 7.5 x 10⁶ Volts.

When voltage difference is created between the end of the conductor, the the power produced is the product of voltage and current.

P =VI

The power output of the beam is 6.0 x 10¹³ W and 8.0 x 10⁶ A of current was needed to produce this beam.

The voltage is calculated as

V= P / I

V=  (6.0 x 10¹³ ) / (8.0 x 10⁶)

V= 7.5 x 10⁶ Volts

Therefore, the voltage that produced the current is 7.5 x 10⁶ Volts.

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Answer:

apple

Explanation:

Answer:

D. It must have mass and volume

Explanation:

In science, matter is referred to as any substance that has weight and occupies space. This means that the substance must have a MASS of its own when weighed and also a VOLUME.

Matter include elements, molecules, humans, etc. In fact, almost every substance on Earth is considered MATTER. Therefore, the fact that a substance must "have mass and volume" is true for all matter.

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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