Write an INSERT statement that adds a row to the VendorCopy table for each --non-California vendor in the Vendors table.

Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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If you see an edge line that angles inward on a road, it means that you are approaching a narrowing in the road. This narrowing can be caused by a variety of factors, including road construction, a bridge or tunnel ahead, or simply a change in the width of the road.

In most cases, the inward angle of the edge line will be accompanied by other warning signs, such as reduced speed limits, flashing lights, or road cones. These signs are intended to alert drivers to the upcoming hazard and to encourage them to slow down and proceed with caution.When approaching a narrowing in the road, it is important to be aware of your surroundings and to adjust your speed accordingly. You should also be prepared to yield to other vehicles, especially if the road is too narrow for two cars to pass safely side-by-side.In general, it is always a good idea to obey all warning signs and signals on the road, and to stay alert for any changes in the road conditions. By doing so, you can help to ensure that you and other drivers stay safe while traveling on the road.

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The solar system is populated with swarms of comets and asteroids. is not among the four key components of the solar system.

Which characteristics of the solar system offer hints as to how it came into existence? Large body movements: the same direction and plane for everyone - There are two primary categories of planets: Jovidian and terrestrial - Asteroid and comet swarms, which are groups of tiny bodies The rotation of Uranus, the big moon of Earth, etc. are notable outliers.

A solar energy system's four main parts are its panels, inverter or inverters, racking, and solar battery storage unit(s) (if desired). Your system's most noticeable component is its solar panels.

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The dry adiabatic rate refers to the rate at which a dry air parcel cools or heats as it rises or falls without exchanging heat with the environment. It typically has a value of 9.8°C per kilometer.

The moist adiabatic rate is the rate at which a saturated air parcel cools or heats as it rises or falls without exchanging heat with the environment. The moist adiabatic rate varies with temperature and moisture content and is usually less than the dry adiabatic rate, ranging from 4°C to 9°C per kilometer.  It can vary widely, depending on factors such as the time of day, season, location, and weather conditions .

The average lapse rate is the rate at which the temperature of the Earth's atmosphere decreases with increasing altitude, taking into account both the environmental lapse rate and the lapse rate of a parcel of air as it rises or falls through the atmosphere. The adiabatic rates are useful for predicting the behavior of individual air parcels, while the lapse rates are useful for predicting the overall temperature structure of the atmosphere.

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Answer:

The original seven wastes, or muda, are transportation, inventory, motion, waiting, overproduction, overprocessing and defects. ... When manufacturers are able to identify the seven wastes, they can correct and prevent further loss of time, money and other resources.

Explanation:

Answer:

transportation, inventory,motion, waiting,overproduction,overprocessing,and defects

Explanation:

they are often referred to by the acronym TIMWOOD

A visual aid for classifying a problem's possible origins is a fishbone diagram.

Thus,  This technique is used to determine the underlying causes of issues. A fishbone diagram combines the technique of brainstorming with a form of mind map template, and is frequently used for root cause analysis. As a test case technique to ascertain cause and effect, it ought to be effective.

In product development and troubleshooting procedures, a fishbone diagram is helpful because it may be used to centre a discussion on a specific issue.

The facilitator works with the group to rank potential causes in order of priority and create a hierarchy once the group has brainstormed every potential source of the issue. The diagram's design, which closely resembles, the source of the name and fishbone.

Thus, A visual aid for classifying a problem's possible origins is a fishbone diagram.

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Answer:

35.92 kpsi

Explanation:

Given data:

diameter of the steel bar d = 0.875 in

Area A = πd^2/4 = π(0.875)^2/4

length L = 15.0 ft

Load P = 21.6 kip

Modulus of elesticity E = 29×10^6 Psi

Assume we are asked to determine axial stress in the bar which is given as

\(\sigma = Load, P/ Area, A\)

\(\sigma = 4P/\pi d^2\)

substitute the value

\(\sigma = \frac{4\times 21.6}{\pi \times (0.875)^2} \\=35.92\ kpsi\)

Answer:

The answer to the question is True

On wet roads, the chance of hydroplaning increases with the increase of speed. Thus, the given statement is true.

During rainy weather, roads may become slippery and difficult to drive on. Slippery roads may also arise as a result of snow or ice. The fact that the road surface has less traction than normal is what makes it slippery. On slippery roads, it is recommended that drivers slow down to reduce the risk of skidding, sliding, or losing control of their cars, especially when taking turns.

Drivers should also increase their following distance and avoid abrupt braking or accelerating. Drivers should not drive faster than 25 mph on slippery roads, and they should not increase their speed to avoid hydroplaning. Instead, drivers should slow down.

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Note that Option B - ∀x P(x) ∨¬P(x) is a valid sentence.

Option B is known as the law of the excluded middle, which states that for any proposition P, either P is true or its negation, ¬P, is true. This law holds for all values of x, so the statement ∀x P(x) ∨¬P(x) is always true.

An argument is valid if and only if it is required that if all of the premises are true, then the conclusion must be true; it is impossible that all of the premises are true and the conclusion is false. An invalid argument is one that is not legitimate.

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a) The Gantt chart view for the project is shown below. The finish date is April 6, 2023. The critical path is A-B-E-F-H-I-K-L and its duration is 25 days.

b) The critical chain view of the schedule without buffers is shown below. The critical chain is A-C-D-E-G-H-I-J-K-L and its duration is 18 days. Adding the project buffer of 25% of the critical chain duration (4.5 days) and the feeding buffers, the end date is April 10, 2023.

c) The Gantt chart view for all three projects with doubled task durations is shown below. The finish date is May 13, 2023.

d) The critical chain view of the schedule with aggressive durations and no multi-tasking is shown below.

The critical chain is A-C-D-E-G-H-I-J-K-L-M-N-O-P-Q-R-S-T-U-V-W-X-Y-Z-AA-AB-AC-AD-AE and its duration is 21 days. Adding the project buffer of 25% of the critical chain duration (5.25 days) and the feeding buffers, the end date is May 23, 2023.

e) Adding a capacity buffer of 50% of the last task Jack is on before moving to the next project between projects, the end date is May 30, 2023.

f) Assuming the test lab is the drum resource, adding a capacity buffer of 50% of the last task in the test lab before moving to the next project, the end date is June 3, 2023. If both Jack and the test lab are drum resources, capacity buffers need to be added between projects for both resources. The overall end date will depend on the size of the buffers added.

g) This exercise highlights the importance of using critical chain method for scheduling projects and the impact of multi-tasking on project schedules.

Organizations can use software tools to manage multiple projects and resources, such as resource leveling and critical chain scheduling, to ensure that resources are not overworked and that project schedules are realistic. In addition, clear communication and collaboration among project teams and stakeholders are essential to manage risks and resolve conflicts in a timely manner.

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'Capturing a photon by isomerization and rhodopsin of retinal' is the first step necessary for initiating the visual transduction cascade in rods.

Visual transduction refers to the process in the eye where absorption of light in the 'retina' is translated into electrical signals that then reach the brain. It is correct to state that visual transduction is the photochemical reaction that takes place when light or photon is converted to an electric signal in the retina. The visual pigment in the rods, called rhodopsin, is a membrane protein placed in the outer segments of the rods.

When initiating the visual transduction cascade in rods the first vital step is to capture a photon by isomerization and rhodopsin of retinal'.

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Answer:

Understand how the network works where she is working at

Explanation:

a. a = 12 is the solution to the given congruence relation. b. the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

(a) The main answer: The integer a that satisfies a ≡ -15 (mod 27) is 12.

To find the value of a, we need to consider the congruence relation a ≡ -15 (mod 27). This means that a and -15 have the same remainder when divided by 27.

To determine the value of a, we can add multiples of 27 to -15 until we find a number that falls within the range of {0, 1,..., 26}. By adding 27 to -15, we get 12. Therefore, a = 12 is the solution to the given congruence relation.

(b) The main answer: The positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

Supporting explanation: Two integers are relatively prime if their greatest common divisor (GCD) is 1. In this case, we are looking for positive integers that have no common factors with 12 other than 1.

To determine which numbers satisfy this condition, we can examine each positive integer less than 12 and calculate its GCD with 12.

For 1, the GCD(1, 12) = 1, which means it is relatively prime to 12.

For 2, the GCD(2, 12) = 2, so it is not relatively prime to 12.

For 3, the GCD(3, 12) = 3, so it is not relatively prime to 12.

For 4, the GCD(4, 12) = 4, so it is not relatively prime to 12.

For 5, the GCD(5, 12) = 1, which means it is relatively prime to 12.

For 6, the GCD(6, 12) = 6, so it is not relatively prime to 12.

For 7, the GCD(7, 12) = 1, which means it is relatively prime to 12.

For 8, the GCD(8, 12) = 4, so it is not relatively prime to 12.

For 9, the GCD(9, 12) = 3, so it is not relatively prime to 12.

For 10, the GCD(10, 12) = 2, so it is not relatively prime to 12.

For 11, the GCD(11, 12) = 1, which means it is relatively prime to 12.

Therefore, the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

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Answer:

I'm good at drawing and computer-animated design

Explanation:

Answer:

2200 watts

Explanation:

# of Watts = Volts × Amps

Have a lovely rest of your day/night, and good luck with your assignments! ♡

Answer:

Continued and/or excessive heat and centrifugal force on turbine engine rotor blades is likely to cause creep.

Explanation:

Creep is a technical term for permanent elongation that happens over time. Heat will result in the rotor blades' material becoming less dense which will allow the material to stretch since the force is centrifugal.

It is not safe to stand on the top step of a stepladder, even if someone is holding the base. The top step is not designed to bear weight and can lead to instability, causing the ladder to tip over.

It is crucial to follow the ladder's safety guidelines and use it as intended, ensuring all steps are used and the ladder is properly stabilized to prevent accidents and injuries.

When someone holds the base of a stepladder, it can provide some additional stability, but it does not make standing on the top step safe. The top step of a stepladder is not designed to bear weight, and it can be dangerously unstable. Even with someone holding the base, there is still a risk of the ladder tipping over, leading to a fall or injury. To ensure safety, it is important to follow the ladder's guidelines, which typically recommend using all steps and maintaining proper stability, such as securing the ladder against a sturdy surface or using

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Answer: C. carbon atoms

Explanation:

Non-renewable energy resources is a term usually used to refer to fossil fuels such as oil, natural gas and coal. These fossil fuels are so termed as they are remains of dead plant and animal matter from millions of years ago.

The main element in these fossil fuels is carbon which is the universal building block of life so will be present in the remains of previously alive matter. When non-renewable energy sources are therefore used, it is energy from carbon atoms that is being harnessed.

A. The Sun

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(a) The mass flow rate of the air entering the control volume is 0.0651 lb/s.    (b) The exit flow area required for the given conditions is 0.0004775 ft².

a. In this problem, we are given the properties of air entering and exiting a control volume. To determine the mass flow rate, we need to apply the principle of mass conservation. By using the ideal gas law and assuming steady state operation, we can calculate the mass flow rate based on the given information, including the inlet and exit conditions, the gas constant, and the specific heat ratio of air.

To solve this problem, we can apply the conservation laws of mass and momentum. Let's go step by step.

(a) First, we need to find the mass flow rate (ṁ).

The mass flow rate can be calculated using the equation:

ṁ = ρ₁ * A₁ * V₁

where:

ṁ = mass flow rate

ρ₁ = density of air at inlet conditions

A₁ = inlet area

V₁ = inlet velocity

We need to find ρ₁, the density of air at inlet conditions. The ideal gas law can be used to calculate the density:

ρ₁ = P₁ / (R * T₁)

where:

P₁ = pressure at inlet conditions

R = specific gas constant

T₁ = temperature at inlet conditions

Given values:

P₁ = 116 psi

T₁ = 1080 °R

A₁ = 3.1 in²

V₁ = 131 ft/s

We need to convert the given values to consistent units before proceeding with the calculations.

Conversions:

P₁ = 116 psi = 116 * 144 lb/ft² = 16624 lb/ft²

T₁ = 1080 °R

A₁ = 3.1 in² = 3.1 / (12^2) ft² = 0.01736111 ft²

V₁ = 131 ft/s

Now we can calculate ρ₁:

ρ₁ = P₁ / (R * T₁)

= 16624 lb/ft² / (53.35 lb/(ft·°R) * 1080 °R)

≈ 0.288 lb/ft³

Now we can calculate the mass flow rate (ṁ):

ṁ = ρ₁ * A₁ * V₁

= 0.288 lb/ft³ * 0.01736111 ft² * 131 ft/s

≈ 0.0651 lb/s

So, the mass flow rate is approximately 0.0651 lb/s.

(b)  To find the exit flow area, we can use the equation of continuity, which states that the mass flow rate is equal to the product of density, velocity, and area. By rearranging the equation, we can solve for the exit flow area, considering the known values of mass flow rate, density, and exit velocity.

(b) Next, we need to find the exit flow area (A₂).

The mass flow rate (m) remains constant throughout the control volume, so we can write:

m = ρ₂ * A₂ * V₂

where:

ρ₂ = density of air at exit conditions

A₂ = exit area

V₂ = exit velocity

To find A₂, we need to rearrange the equation:

A₂ = m/ (ρ₂ * V₂)

We need to find ρ₂, the density of air at exit conditions. Using the ideal gas law:

ρ₂ = P₂ / (R * T₂)

where:

P₂ = pressure at exit conditions

T₂ = temperature at exit conditions

Given values:

P₂ = 29 psi = 29 * 144 lb/ft² = 4176 lb/ft²

T₂ = 720 °R

V₂ = 1148 ft/s

Conversions:

P₂ = 4176 lb/ft²

T₂ = 720 °R

V₂ = 1148 ft/s

Now we can calculate ρ₂:

ρ₂ = P₂ / (R * T₂)

= 4176 lb/ft² / (53.35 lb/(ft·°R) * 720 °R)

≈ 0.145 lb/ft³

Now we can calculate the exit flow area (A₂):

A₂ = ṁ / (ρ₂ * V₂)

= 0.0651 lb/s / (0.145 lb/ft³ * 1148 ft/s)

≈ 0.0004775 ft²

So, the exit flow area is approximately 0.0004775 ft².

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Provide final answer in 1-2 lines

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(a) The mass flow rate of the air entering the control volume is [insert calculated value] kg/s.

(b)) The mass flow rate of the air entering the control volume is [insert calculated value] kg/s.

In this problem, we are given the properties of air entering and exiting a control volume. To determine the mass flow rate, we need to apply the principle of mass conservation. By using the ideal gas law and assuming steady state operation, we can calculate the mass flow rate based on the given information, including the inlet and exit conditions, the gas constant, and the specific heat ratio of air.

(b) The exit flow area required for the given conditions is [insert calculated value] in2.

To find the exit flow area, we can use the equation of continuity, which states that the mass flow rate is equal to the product of density, velocity, and area. By rearranging the equation, we can solve for the exit flow area, considering the known values of mass flow rate, density, and exit velocity.

It is important to note that the calculations involve the assumption of ideal gas behavior for air and the steady state condition. Real-world factors such as turbulence, friction, and heat transfer may affect the accuracy of the results. Therefore, it is essential to consider these factors in more complex scenarios or actual engineering applications.

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The depths immediately upstream and downstream of the lowered segment, or normal depth, are those in the approach flow.

The amount of water that might theoretically flow out of your kitchen faucet or bathtub each minute is measured by your water flow rate, sometimes referred to as your gallons per minute (GPM).

Assuming your flow rate is currently standard, your home will never need to exceed that final GPM unless you intend to build more kitchens, bathrooms, or laundry rooms. The typical residential water flow rate for small homes is between 6 and 12 gallons per minute.

Add the average breadth (in m), the average depth (in m), and the average water velocity (in m/s) together to get the water flow (in m3) (in m). Water flow equals 0.255 m3/s (0.425 m/s x 1 m x 0.6 m).

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The answer is , the work produced in the ideal Rankine cycle using steam as the working fluid is 22.29 kJ/kg.

The Ideal Rankine cycle is a thermodynamic cycle that describes the operation of a steam power plant. It is named after William John Macquorn Rankine, a Scottish engineer and physicist who developed it in the 19th century.

we can use the following steps:

Given:

Assuming,

State 1: Saturated vapor at the boiler pressure of 2 MPa.

State 2: Saturated liquid at the condenser pressure of 10 kPa.

State 3: Saturated liquid at the boiler pressure of 2 MPa (after the pump).

State 4: Saturated vapor at the condenser pressure of 10 kPa (after the turbine).

Using steam tables, we can find the specific enthalpy at each state as follows:

State 1: h1 = 2776.6 kJ/kg (from the saturated vapor table at 2 MPa)

State 2: h2 = 191.81 kJ/kg (from the saturated liquid table at 10 kPa)

State 3: h3 = h2 + v2(P1 - P2) = 191.81 + 0.00106(2 - 0.01) = 192.82 kJ/kg

State 4: h4 = h1 - v1(P1 - P2) = 2776.6 - 0.00618(2 - 0.01) = 2753.3 kJ/kg

Work produced by the turbine:

Wturbine = h1 - h4 = 2776.6 - 2753.3 = 23.3 kJ/kg

Work required by the pump:

Wpump = h3 - h2 = 192.82 - 191.81 = 1.01 kJ/kg

Net work produced:

Wnet = Wturbine - Wpump = 23.3 - 1.01 = 22.29 kJ/kg.

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Workers should always be educated about hand tool safety and taught to use the appropriate tool for the job, maintain their tools, and work in a safe manner.

Hand tools are the most common tools used in workplaces across the globe. Hand tools are used in a variety of industries, including construction, manufacturing, and maintenance. Hand tools may cause a variety of injuries, including cuts, punctures, bruises, broken bones, and amputations. The greatest hazards posed by hand tools result from misuse, poor maintenance, and failure to select the correct tool for the job.

The incorrect usage of hand tools can cause a variety of injuries, ranging from minor cuts and punctures to serious injuries such as fractures, amputations, and even fatalities. The hazards are amplified when the hand tools are of inferior quality or have not been adequately maintained or repaired.

Hand tools are subject to many types of wear and tear over time, including bending, blunt edges, and worn grips. Using a hand tool in such a condition can be extremely hazardous, resulting in injuries that could have been avoided by repairing or replacing the tool at the right time.Another significant hazard is using the wrong tool for the job. For example, using a chisel instead of a screwdriver or pliers to tighten a screw can damage the screw head or damage the chisel, which can lead to injuries or accidents.

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In this scenario, we have an aqueous alumina slip containing 45 volume % alumina particles being cast into a gypsum mold. The alumina particles are monodisperse with a size of 1 µm and well-stabilized.

The as-cast layer has a 65% theoretical density, and the gypsum mold has a specific resistance of 2 x 100 cm² and a void fraction of 0.5. The total pressure drop from the slip to the saturation interface in the mold is 0.1 MPa.To plot the cast layer thickness as a function of time, we can utilize Darcy's Law, which governs the flow of a fluid through a porous medium. However, without specific numerical values for the slip's viscosity and the mold's permeability, it is not possible to directly calculate the layer thickness and time relationship.

Nevertheless, to predict the time needed to cast a 1 mm thick layer and the position of the saturation front in the gypsum mold, we would need to perform experiments or numerical simulations based on the given parameters, such as particle size, slip composition, and mold properties. These results could then be used to develop an empirical or theoretical relationship between cast layer thickness and time, enabling accurate predictions for the given conditions.

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i think it's c. bread.

Answer:I think raw meat because if you eat raw meat you get sick and get stomach aches so always when you cook meat it kill the bacteria

Explanation:what I'm trying to says is stay safe

Explanation:

Wear protective leathers/pads  and a helmet.  Stay visible....don't ride in blind spots of other drivers.   Don't speed or weave in and out of traffic.  Use turn signals and headlight/taillight.   Make sure your 'cycle is in good working order / maintained properly.   Do not drink and ride.   Avoid bad weather and winter weather.   Ride defensively.  Use your mirrors. Swivel your head ....be aware of your traffic surroundings. Take a rider safety course.   Learn how to ride the bike you are on in a safe place ...etc etc

Answer:

Switching on and off

Explanation:

No starters are often caused by a faulty crankshaft actuator. The signals from this transmitter is sent to the ignition module, which turns in and out of the ignition system. If you already have an RPM sign, it's possible that a faulty ignition unit or PCM isn't turning the coils on and off. Along with button on and the motor cranking, testing for volts at the contacts with a voltmeter.

The given code includes function declarations of func1() and func2() and the question asks for the correct statement about their declarations. The correct statement is that the extern keyword applied to func1() makes it global, while func2() will only be visible within the current source file scope.

To explain further, the extern keyword extends the visibility of a function or variable to the entire program, allowing it to be accessed from other files. By using extern with func1() and not with func2(), func1() becomes global, which means it can be accessed by other files as well. On the other hand, func2() will only be visible within the current file and cannot be accessed from other files.

Therefore, option A is the correct answer as it explains that func1() is global due to the extern keyword, while func2() is only visible to the current source file scope. The use of extern keyword is to declare a global variable or function in another file, which can also be used in the current file.

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There is no dominant strategy in this game, but the Nash equilibrium occurs when both players choose Right. The payoff matrix shows the payoffs that Hubert and Kate will receive based on their choices in the game.

To analyze the matrix, we can start by looking at the options available to each player and their corresponding payoffs.

Let's consider the first row of the matrix, which represents Hubert's choices. If Hubert chooses Left and Kate also chooses Left, Hubert will receive a payoff of 4 and Kate will receive a payoff of 4.

Finally, if Hubert chooses Right and Kate also chooses Right, Hubert will receive a payoff of 5 and Kate will receive a payoff of 3.

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