You are getting ready to transport troops in an M1152 configured with cargo cover and troops seats. Which of the following should you do before starting out?

The Statement: An Android theme can be specified on an activity-by-activity basis is False

It is false to claim that an Android theme can be specified individually for each activity. In Android, themes are typically applied at the application level or for specific components such as the entire application, a group of activities, or certain UI elements.

Once a theme is set for a particular scope, it remains consistent throughout that scope, and it cannot be customized on an activity-by-activity basis. However, it is possible to customize the appearance of individual activities by using styles or modifying specific attributes within the activity's layout file, which allows for visual variations within the constraints of the overall theme.

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Option B is accurate since it indicates that after opening a two-pipe system, the system must be bled to remove any air in the fuel line. This is a false assertion.

There are distinct pipes in a two-pipe fuel delivery system for feeding fuel to the burner and returning surplus fuel to the tank. This method is frequently utilized in oil-fired heating systems.

When the system is first loaded or when it runs out of fuel, bleeding may be required to remove any air that has entered the fuel line. Bleeding entails removing all air from the system and ensuring that only fuel remains in the lines.

Therefore, option B is false because a properly functioning two-pipe system should not require bleeding every time it is opened.

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The complete question:

Which of the following statements regarding two-pipe fuel delivery systems is false?

A. A two-pipe system is self-priming.

B. If a two-pipe system is opened, the system must be bled to get rid of any air in the fuel line.

C. A two-pipe system’s fuel unit pumps more fuel oil in a given time than is burned in that time.

D. All of the above.

The capitalized cost (CC) per mile for the highway, considering the initial construction, resurfacing, installation and replacement of culverts, installation and maintenance of ditches, and annual maintenance, with a 3.0% minimum attractive rate of return (MARR), can be calculated by summing up the present values of all the costs involved over the lifespan of the highway.

To determine the capitalized cost per mile, we need to calculate the present value of each cost component and then sum them up. The present value represents the current worth of future costs, taking into account the time value of money.

First, we calculate the present value of the initial asphalt paving cost, resurfacing cost, and installation of ditches. Since they occur at the beginning of the highway's lifespan, their present values are equal to their actual costs.

Next, we calculate the present value of the culvert costs, including the initial installation and the cost of replacements every 10 years. The present value of each culvert's replacement cost is obtained by discounting the future cost at the given MARR.

Then, we calculate the present value of the annual maintenance costs for the highway, including the cleaning and maintenance of culverts and ditches. These costs occur every year and are discounted to their present value using the MARR.

Finally, we sum up all the present values of the costs mentioned above to obtain the capitalized cost per mile for the highway.

It's important to note that the calculation assumes a constant annual cost for maintenance, cleaning, and repaving of ditches throughout the lifespan of the highway. Adjustments for inflation or other factors may need to be considered for more accurate cost estimation.

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Answer:

y = 0.834X - 1.58015

Slope = 0.8340 ; Intercept = - 1.5802

y = 40.9539

19.93

0.9765

Explanation:

X: Rainfall volume

6

12

14

16

23

30

40

52

55

67

72

81

96

112

127

Y : Runoff

4

10

13

14

15

25

27

48

38

46

53

72

82

99

100

The scatterplot shows a reasonable linear trend between the Rainfall volume and run off.

The estimated regression equation obtained using a linear regression calculator is :

y = 0.834X - 1.58015

y = Runoff ; x = Rainfall volume

Slope = 0.8340 ; Intercept = - 1.5802

Point estimate for Runoff, when, x = 51

y = 0.834X - 1.58015

y = 0.834(51) - 1.58015

y = 40.95385

y = 40.9539

d.)

Point estimate for standard deviation :

s = 5.145

σ = s * √n

σ = √15 * 5.145

= 19.93

e.)

r² = Coefficient of determination gives the proportion of explained variance in Runoff due to the regression line. From the model output, the r² value = 0.9765. Which means That about 97.65% Runoff is due to Rainfall volume.

Answer:

Final Length = 11.992 in

Final Diameter = 6.001 in

Explanation:

First we calculate the cross-sectional area:

Area = A = πr² = π(3 in)² = 28.3 in²

Now, we calculate the stress:

Stress = Compressive Load/Area

Stress = - 150 kips/28.3 in²

Stress = -5.3 ksi

Now,

Modulus of Elasticity = Stress/Longitudinal Strain

8000 ksi = -5.3 ksi/Longitudinal Strain

Longitudinal Strain = -6.63 x 10⁻⁴

but,

Longitudinal Strain = (Final Length - Initial Length)/Initial Length

-6.63 x 10⁻⁴ = (Final Length - 12 in)/12 in

Final Length = (-6.63 x 10⁻⁴)(12 in) + 12 in

Final Length = 11.992 in

we know that:

Poisson's Ratio = - Lateral Strain/Longitudinal Strain

0.35 = - Lateral Strain/(- 6.63 x 10⁻⁴)

Lateral Strain = (0.35)(6.63 x 10⁻⁴)

Lateral Strain = 2.32 x 10⁻⁴

but,

Lateral Strain = (Final Diameter - Initial Diameter)/Initial Diameter

2.32 x 10⁻⁴ = (Final Diameter - 6 in)/6 in

Final Diameter = (2.32 x 10⁻⁴)(6 in) + 6 in

Final Diameter = 6.001 in

Answer:

The mechanism that is typically used to bring a carbureted engine to a fast idle is a throttle cable or linkage. This allows the driver to adjust the throttle and increase the engine speed to a designated fast idle setting. This is often used when the engine is cold to help it warm up more quickly, or when the vehicle is stopped and the engine needs to be kept running at a higher speed.

We can assume that the water is initially at a pressure of 500 kPa in a compressed liquid condition, and that as it is progressively drained, its state shifts from a compressed liquid to a compressed vapor state, and finally to a superheated vapor state.

Subcooled liquid: A substance that has not yet vaporized. Also known as compressed liquid. A liquid that is nearly vaporizing is said to be saturated.

The liquid water progressively drains from a rigid container while being held at a pressure of 500 kPa.

During this process, the water changes states from compressed liquid to compressed vapor to finally superheated vapor.

The - diagram makes it easier for us to see this state shift and comprehend how water behaves in this scenario.

Thus, this happens to the water during the process.

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Answer:

Python optimizes memory utilization by allocating the same object reference to a new variable if the object already exists with the same value

The switch connects several cable segments or devices together and forwards frames to the desired segment or device. Thus, the correct answer pertains to (a) i.e. ‘It connects multiple cable segments/devices and forwards data frames to the appropriate device’.

The switch is a data link layer network device. The main function of the switch device is to connect multiple devices on the network together in order to enable data transmission between them. The switch forwards data frames selectively to the appropriate device. Before forwarding data frames to the correct destination device, the switch performs error checking. In case errors are found in any data frames, the switch does not forward those data frames to the destination device and discards them.

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Answer:

first is the parentheses, (3+2)=5 next is the exponent 5^2=25, next is the division 5 / 5 = 1, then the multiplication 4*1=4 and then you add 4+25=29. so the answer is 29.

Answer:

Water is pumped from a lake to a storage tank of 15 m above at a rate of 70 L/s while consuming 15.4 kW of electric power. Disregarding any frictional losses in the pipes and any changes in kinetic energy, determine (a) the overall efficiency of the pump-motor unit and (b) the pressure difference between the inlet and the exit of the pump.Explanation:

Answer:

» Microsoft word ( word processing )

» Microsoft powerpoint ( presentation )

» Microsoft access ( database mamagement )

» Microsoft excel ( spread sheets )

Explanation:

\(.\)

Answer:

Microsoft Teams.

Word.

Excel.

PowerPoint.

Outlook.

OneNote.

OneDrive.

Answer:

The correct answer will be "2".

Explanation:

Given:

Heat generated through wall,

= 15000 kJ/h

= \(\frac{15000}{3600}\)

= \(4.17 \ KW\)

Heat generated by bulbs,

= \(10(100) \ W\)

= \(1000\)

= \(1 \ KW\)

Heat generated by people,

= \(40(360) \ KJ/h\)

= \(\frac{14400}{3600}\)

= \(4 \ KW\)

Heat removed by 1 AC,

= 5 KW

Now,

The total increase in heat will be:

= \(4+1+4.17\)

= \(9.17 \ KW\)

hence,

The required number of AC will be:

⇒ \(5n=9.17\)

⇒   \(n=\frac{9.17}{5}\)

⇒       \(=1.83\)

0r,

⇒       \(2\)

I inferred you meant emerging technologies we see today.

Explanation:

1. 3D Printing

A three dimensional printing allows a digital model to be printed (constructed) into a physical object.

A box, an industrial design and many more could be printed within minutes.

2. AI voice recognition devices

Another trend in the tech world is the rise in artificial intelligence been used in voice recognition devices that not only recognize one's voice but also take commands from the user.

This technology allows one to listen to the internet, such as listening to music online.

The tech world is ever changing with new technology beyond one's consumption on the increase daily.

Complete Question:

Problem 8 Determine the horsepower required to compress 1 lbm/min of ethylene oxide from 70 °F and 1 atm to 250 psia. The compressor has an efficiency of 75%. The molar heat capacity of ethylene oxide is given by

C_p=10.03+0.0184T  C_p[=]Btu/lbmole- "F ; T[=] °F C,

Answer:

\(P'=0.377hp\)

Explanation:

From the question we are told that:

Initial Temperature T_1=70 F

Final Temperature \(T_2=250pisa =114.94F\)

Efficiency \(E=75\%=0.75\)

Generally the equation for Work-done  is mathematically given by

 \(W=\int C_pT\)

 \(W=10.03(114.94-70 )+0.0184((114.94)^2-70^2 )\)

 \(W=527.21btu/ibmole\)

 \(W=11.982btu/ibm\)

Generally the equation for Efficiency  is mathematically given by

 \(E=\frac{isotropic Power}{Actual P'}\)

 \(E=\frac{P}{P'}\)

Since

Isotropic Power

  \(P=0.0167*11.982btu/ibm\)

 \(P=0.2btu/s\)

Therefore

 \(P'=\frac{0.2}{0.75}\)

 \(P'=0266btu/s\)

Since

 \(1btu/s=1.4148hp\)

Therefore

 \(P'=0.377hp\)

The tension forces in cables AC and AB is 99.2 N respectively. The dimension d required for force in cable AC to be zero is approximately 1.492 m.

To find the tensions in cables AC and AB, we can analyze the forces acting on the ball D in equilibrium.

The forces acting on the ball D are its weight (W = mg) and the tensions in cables AC and AB.

Since the ball is in equilibrium, the net force on it is zero.

Therefore, the tensions in cables AC and AB must balance the weight of the ball.

Let's assume that the tension in cable AC is \(T_{AC}\) and the tension in cable AB is \(T_{AB}.\) Then, we can write the following equations:

\(T_{AC} *cos(60^o) - T_{AB}*cos(60^o) = 0\)   (horizontal equilibrium)

\(T_{AC}*sin(60^o) + T_{AB}*sin(60^o) - W = 0\)    (vertical equilibrium)

Substituting the values of   \(W, T_{AB},T_{AC}\) we get:

\(T_{AC}*cos(60^o) - T_{AB}*cos(60^o) = 0\)

\(T_{AC}*sin(60^o) + T_{AB}*sin(60^o) - 20*9.81 = 0\)

Simplifying these equations, we get:

\(T_{AC} = T_{AB}\)

\(T_{AC} + T_{AB} = 20*9.81/sin(60^o)\)

Substituting \(T_{AC} = T_{AB}\)    into the second equation, we get:

\(2T_{AC} = 209.81/sin(60^o)\)

\(T_{AC} = T_{AB} = 99.2 N\)

Therefore, the tensions in cables AC and AB are both 99.2 N.

Now to determine dimension d so that the force in cable AC is zero.

Let's assume that the tension in cable AC is zero when d = x. Then, the moment equation around point C becomes:

\(T_{AB}*d - F(d+1) = 0\)

Substituting the values of  \(T_{AB}\) and F, we get:

\(99.2x - 300(x+1) = 0\)

\(99.2x - 300x - 300 = 0\)

\(-200.8*x = -300\)

\(x = 1.492 m\)

Therefore, the dimension d that makes the tension in cable AC zero is approximately 1.492 m.

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The airworthiness certificate of an aircraft remain valid as long as the aircraft is maintained and operated as required by Federal Aviation Regulations.

An FAA document known as an airworthiness certificate gives permission to fly an aircraft. As long as an aircraft adheres to its approved type design, is fit for safe operation and maintenance, receives preventative maintenance, and adjustments are carried out in conformity with 14 CFR sections 21, 43, and 91, it maintains its standard airworthiness certificate.

An application for an airworthiness certificate may be made by the registered owner or owner's agent of an aircraft. Two classifications can be made for air worthiness certificate- Standard Airworthiness Certificate, and Special Airworthiness Certificate.

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Your question is incomplete, but most probably the full question was,

How long does the Airworthiness Certificate of an aircraft remain valid?

A. As long as the aircraft has a current Registration Certificate.

B. Indefinitely, unless the aircraft suffers major damage.

C. As long as the aircraft is maintained and operated as required by Federal Aviation Regulations.

To calculate the flowrate through the bend, use Bernoulli's equation. Connect the velocities and cross-sectional areas at sites 1 and 2 using the continuity equation.

ρA1V1=ρA2V2. The Principle of Continuity is the name given to this equation. Let's say we need to determine the efflux speed for the following configuration. Bernoulli's equation, applied at points 1 and 2, reads as follows: p + 1 2 v 1 2 + g h = p 0 + 1 2 v 2 2.

\(P1 + 0.5rhoV1^2 + rhogh1 = P2 + 0.5rhoV2^2 + rhogh2\)

\(P1 + 0.5rhoV1^2 = P2 + 0.5rhoV2^2\)

The mass flow rate is constant along a streamline, hence when we solve for V2 using the continuity equation, we obtain:

\(V2 = sqrt(2*(P1-P2)/rho + V1^2)\)

\(Q = A1V1 = A2V2\)

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vote

We must break down the forces acting on the eyeball into their component parts to calculate the required values ​​of T and (theta), and we must use the concept of equilibrium, which states that the net force acting on an object and net torque are both zero.

Let us examine in more detail the forces affecting the eyeball:

The equations for balancing in the x and y directions will now be presented as:

No pressure is acting in the x-direction, so the tension force is zero in that direction: T * cos(θ) = 0

T * sin(θ) + \(\rm F_1 + F_2 - F_3\)= 1200N (net pull force of 1200N in y-direction due to tension force in y-direction, f1, f2 and f3)

Let us now find the value of T and θ:

From the x-direction equation, we get:

T * cos(θ) = 0

T = 0

From the y-direction equation, we get:

0 + 500N + 800N - 600N = 1200N

T * sin(θ) = 1200N

T = 1200N / sin(θ)

Since T cannot be both 0 and 1200N, it implies that sin(θ) must be equal to 1:

sin(θ) = 1

To find θ, we take the inverse sine (or arcsine) of 1:

θ = arcsin(1)

The arcsine of 1 is 90 degrees or π/2 radians.

Therefore, the values are T = 1200N / sin(θ) = 1200N / 1 = 1200N and θ = 90 degrees or π/2 radians.

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Answer: -8.51 ft^3/lbm

Explanation:

In this question, to find the change in volume, we will use the ideal gas law.

\(\begin{aligned}&n_{1}=1 \text { mole }\\&\mathrm{P}_{1}=20 \mathrm{psia}\\&\mathrm{T}_{1}=70^{\circ} \mathrm{F}\\&T_{1}=(70+460)^{0} \mathrm{R}\\&v_{1}=\frac{\left(0.3704 \frac{psia \cdot_{\text { } ft^{3}}}{l \mathrm{lbm} \cdot R}\right)(70+460)^{0} \mathrm{R}}{20 \mathrm{psi}}\\&v_{1}=9.816 \frac{\mathrm{ft}^{3}}{\mathrm{lbm}}\end{aligned}\)

\(\begin{aligned}&\mathrm{n}_{2}=1 \text { mole } \\&\mathrm{P}_{2}=150 \mathrm{psia} \\&\mathrm{T}_{1}=\mathrm{T}_{2}=70^{0} \mathrm{~F} \\&\mathrm{~T}_{1}=\mathrm{T}_{2}=(70+460)^{0} \mathrm{R} \\&v_{2}=\frac{\left(0.3704 \frac{\text { psia} \cdot \mathrm{ft}^{3}}{\mathrm{lbm} \cdot R}\right)(70+460)^{0} \mathrm{R}}{150 \mathrm{psi}} \\&v_{2}=1.309 \frac{\mathrm{ft}{ }^{3}}{\mathrm{lbm}}\end{aligned}\)

\($$The change in volume is,$$\begin{aligned}&\Delta v=v_{2}-v_{1} \\&\Delta v=1.309-9.816 \\&\Delta v=-8.51 \frac{\mathrm{ft}^{3}}{\mathrm{lbm}}\end{aligned}\text{The negative sign shows that the gas was compressed during this process}\)

Explanation:

the resultant force =

\( \sqrt{} {x}^{2} + {y}^{2} \)

A resultant force is the single force and corresponding torque that are produced when adding vectors to a system of forces and torques acting on a rigid body.

R = A + B. Instance 2 To create the resulting vector, two vectors facing the opposite direction are subtracted from one another. Here, the vector B is pointing in the opposite direction of the vector A, and the resulting vector is called R.

A force system is a group of forces that interact at specific locations (may also include couples). Therefore, the collection of forces shown on any free body diagram is a force system. A group of forces is simply referred to as a force system.

Therefore, When an item is under the influence of two or more forces, the combined force can be calculated by adding up the separate forces.

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The covers and guardrails are required in all of the following areas except ditches.

Yes, they do need a covers and/or guardrails and it is one that is known or shall be provided to help in the protection of personnel from the hazards that pertains to open pits, tanks, vats and others.

Note that they are often needed that is covers and/or guardrails need to be provided to help to protect personnel.

Therefore, The covers and guardrails are required in all of the following areas except ditches.

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a) The final composition of the pressurizer will be 50% water and 50% steam by volume.
b) The final system pressure will be 2040 psia.

Pressurizer is a tool used to measure and adjust the pressure of liquids, gases and vapors. It is used to maintain the pressure within a system, to regulate the flow of fluids and to monitor the health of the system. It is a crucial instrument in many industrial processes and helps to ensure the safety of personnel and equipment. It is easy to use, cost-effective and reliable, and helps keep operations running smoothly.

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Answer:

\(D=4.02\)

Explanation:

From the question we are told that:

Part Dimension \(x=4.00in\)

Generally the equation for the corresponding dimension to which the mold cavity should be machined is mathematically given by

\(D=x-(xS)+(4S^2)\)

Where

S= Value for Skinage

From Table pf AB's

\(S=0.006\)

Therefore

\(D=4-(4*0.006)+(4(0.006)^2)\)

\(D=4.02\)