To calculate the approximate semimajor axis of the orbit of a planet, we can use Kepler's third law of planetary motion.
which states that the square of the orbital period (in years) is proportional to the cube of the semimajor axis (in astronomical units or AU).
Mathematically, Kepler's third law can be expressed as:
T^2 = (4π^2 / GM) x a^3
where T is the orbital period in years, G is the gravitational constant, M is the mass of the star, and a is the semimajor axis of the orbit in AU.
To solve for the semimajor axis, we can rearrange the equation as follows:
a = (T^2 x GM / 4π^2)^(1/3)
Let's assume that the mass of the star is similar to that of the Sun, which is approximately 1.99 x 10^30 kg, and that G is the universal gravitational constant, which is approximately 6.674 x 10^-11 m^3 kg^-1 s^-2.
Converting the orbital period of the planet to years, we have T = 0.3 years.
So, the semimajor axis of the planet's orbit is:
a = (0.3^2 x 6.674 x 10^-11 x 1.99 x 10^30 / 4π^2)^(1/3)
a = 0.174 AU (approximately)
Therefore, the approximate semimajor axis of the planet's orbit is 0.174 AU.
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The male african elephant at the city zoo has a mass of 5450kg.what is its mass in scientific notation?
Answer:
5.45 x 10^3
Explanation:
Answer:
the top guy was right
Explanation:
Its right
What is the variable unit for acceleration,gravity and height
Answer:
HLW ITS JESS BREGOLI
YOUR ANSWER IS HERE
At different points on Earth's surface, the free fall acceleration ranges from 9.764 m/s2 to 9.834 m/s2[2] depending on altitude and latitude, with a conventional standard value of exactly 9.80665 m/s2 (approximately 32.17405 ft/s2). Locations of significant variation from this value are known as gravity anomalies.
Explanation:
HOPE IT MAY HELP YOU !!
what would it weigh on the surface of pluto, where g is 0.0673 times that on earth? give your answer in units of newtons
The weight of the object on Pluto would be 6.587 Newtons (N).
To calculate the weight on Pluto, we need to use the formula:
Weight = Mass x Gravity
where Mass is the mass of the object and Gravity is the gravitational acceleration on Pluto.
Let's assume the mass of the object is 10 kg.
On Pluto, the gravitational acceleration is 0.0673 times that on Earth, which means:
Gravity on Pluto = 0.0673 x 9.81 m/s² = 0.6587 m/s²
Therefore, the weight of the object on Pluto would be:
Weight = 10 kg x 0.6587 m/s² = 6.587 N
So, the calculation says that the weight of the 10 kg object on Pluto would be 6.587 Newtons (N).
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A science student observes three lines in an emission spectrum, one red, one yellow, and one blue. Which one was caused by an electron jumping the shortest distance
The transition that produced red light was caused by an electron jumping the shortest distance.
Visible light is made up of seven wavelengths the magnitude of the wavelength of a transition reflects the energy associated with such transition. The longer the wavelength shorter the transition that produced it.
Given that three lines in the visible spectrum produced three lines as follows;
Red - 625 - 740 nm
Yellow - 565 - 590 nm
Blue - 445 - 520 nm
We can see that the longest wavelength corresponds to red light hence it was caused by an electron jumping the shortest distance.
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a plant that is 4.0 cm tall is placed 15 cm from a concave spherical mirror having a focal length of magnitude 20 cm. where is the image located?
The image of the 4.0 cm tall plant is located 10 cm in front of the mirror. It is virtual, upright, and magnified.
The given problem involves the use of the thin lens equation, which relates the object distance, image distance, and focal length of a lens or mirror.
Using the equation 1/f = 1/do + 1/di, where f is the focal length, do is the object distance, and di is the image distance, we can solve for di. Plugging in the values given, we get:
1/20 = 1/15 + 1/di
Solving for di, we get di = 10 cm.
Since di is positive, the image is located on the same side of the mirror as the object, which means it is virtual and upright. The magnification of the image can be found using the equation M = -di/do, which gives M = -2.5. This means that the image is magnified by a factor of 2.5 compared to the object.
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You connect a 12 V battery across the terminals leading to a pair of parallel plates (e.g. a configuration like what you had as your setup in the electric field mapping lab). The plates are each 36 cm long, and they are placed 24 cm apart. What will be the electric field strength midway between the plates
The electric field strength midway between the plates is 100 V/m.
Electric field strengthThe electric field strength experienced by the charge is the force per unit charge flowing in the field.
The electric field strength midway between the plates is calculated as follows;
E = V/d
where;
d is the distance between the platesMidway between the plates = 12 cm = 0.12 m
E = 12/0.12
E = 100 V/m
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1. Draw the following free-body diagrams. Label the forces with their appropriate symbol, and includethe magnitude of each force if it is known.a) A basketball player shoots the ball,and it is flying through the air toward the basket.(Ignore air resistance.)b) A wheeled cart on a track (similar to whatyou used in the lab) weighs 0.5 N. It is pulledto the right with an applied force of 0.25 N, andexperiences rolling friction of 0.03 N. Ignore airresistance.c) A cart is on an air track (a frictionlesssurface similar to an air hocket table). Mrs. Hountonpushes the cart, and then lets go. It is travelingtoward the left. Include air resistance. The free-bodydiagram should be for the situation after Mrs. Hountonlets go of the cart.
To draw a free-body diagram, identify all the forces acting on an object and draw them including their magnitude and direction. Use a point to represent the object.
a)
While the ball is flying through the air, the only force acting on the ball is its weight (due to gravitational attraction to the Earth).
b)
There are three forces acting on the cart: its weight, the pull to the right and the rolling friction to the left:
c)
There are three forces acting on the cart: The gravitational pull downwards, the push upwards of the air that compensates the weight, and the air resistance to the right (since the cart is traveling toward the left).
Pleeeease help! I'll give brainliest if possible!! :)))
Use the scenario to answer the question.
An astronomer discovers a new galaxy using a telescope. The astronomer wants to investigate how the galaxy is moving relative to the Milky Way galaxy.
In one or two sentences, make a hypothesis about the movement of the galaxy and explain at least one way to test the hypothesis.
The most scientific guess (hypothesis) based on what is known about the behavior of galaxies is that Galaxies are continuously moving away from each other. This hypothesis can be tested using Hubble's Law.
What does Hubble's Law Say?Hubble's law indicates that almost all galaxies are moving apart from one another because the universe as a whole is expanding. Choose any two galaxies at arbitrarily, and they're most likely traveling apart from each other.
Hubble discovered that galaxies move away from us at a rate proportionate to their distance: more distant galaxies move away faster than closer ones. The accompanying graphic shows Hubble's classic graph of measured velocity vs. distance for neighboring galaxies.
The graph shows a linear relationship between galaxy velocity (v) and distance (d).
The equation for the above linear relationship is:
v = H₀ x d
Where:
H₀ is the expansion rate
v = velocity of the galaxy; and
d = distance.
Using the above formula, the astronomer can measure or test to know whether indeed the new galaxy is moving relative to the Milky Way galaxy and at what rate.
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A wrecking ball has a mass of 650 kg. It swings from a cable that is 21 m long. The centripetal force on the ball is 56 N. What is the tangential speed of the wrecking ball? 1. 3 m/s 1. 8 m/s 46 m/s 870 m/s.
Hi there!
For an object moving in a circle:
Centripetal force = ∑F = mv²/r
Thus:
56 = mv²/r
Rearrange to solve for velocity:
√(56r/m) = v
√(56 × 21)/650 = 1.345 m/s
Answer:
AExplanation:
have a good day
fill in the blank. _____is the force acting on a surface per unit area, which may be stronger in some directions than others.
The process of learning is a complex and multi-faceted activity that involves numerous factors such as motivation, attention, memory, and problem-solving.
One of the key components of effective learning is the ability to manage one's own cognitive processes or metacognition. Metacognition refers to an individual's awareness and understanding of their own thinking processes and strategies, as well as their ability to monitor and regulate their own learning.
Effective metacognitive strategies include setting goals, planning and organizing information, monitoring one's own comprehension, and evaluating learning outcomes.
These strategies can be taught and learned, and they can significantly enhance learning and academic performance.
Additionally, metacognitive strategies can help learners to identify and address areas of weakness or challenge, such as difficulties with attention or memory, and develop more effective learning strategies to compensate.
In summary, metacognition is an essential component of effective learning. By developing awareness and control of their own thinking processes, learners can improve their academic performance, identify and address areas of challenge, and become more effective and efficient learners.
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Courtney wants to practice doing science. Which example best illustrates her
using inquiry?
A. Courtney decides to drop several different objects off her
apartment's porch to see which falls the fastest.
B. Courtney pays close attention in her physical science class to see
if her teacher explains the speed of falling objects.
C. Courtney reads about the history of the study of gravity and learns
about why scientists first studied falling objects.
D. Courtney finds a calculation that explains the speed of falling
objects. She tries to understand the calculation by writing it down.
Answer:
A
Explanation:
because she wants to practice science and A is the practical option.
What physical property of matter is always the same no matter the size or amount
Answer:
Characteristic Property
Explanation:
A property of matter that is always the same, no matter what size the sample. These are used to help identify substances. Examples are density, solubiility, flammability, reactivity
A wire of radius 6mm and length 400 is melted into a sphere, calculate the radius of the sphere in centimeters
The radius of the sphere in centimeters is 50 cm
The wire has a certain volume that can be calculated as follows:
V_wire = πr²l
where r is the radius of the wire and l is its length.
If the wire is melted and formed into a sphere, it will still have the same volume as before, which can now be expressed as:
V_sphere = (4/3)πr³
where r is the radius of the sphere.
Since the wire and the sphere have the same volume, we can equate the two expressions for volume:
πr²l = (4/3)πr³
Simplifying this equation by dividing both sides by πr² and then multiplying both sides by 3/4, we get:
r = (3/4)l/r
Substituting the given values, we get:
r = (3/4)(0.4 m)/(0.006 m) ≈ 50 cm
Therefore, the radius of the sphere is approximately 50 centimeters.
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A 30 kg child is sitting on a swing. Their weight is exerting a downward force on the swing. The ropes are exerting an upward force on the swing. The swing is not moving. What is the net force on the swing?
A.294 N down
B.294 N up
C.0 N
D.30 kg
In outer space rock 1 with mass 5 kg and velocity < 3800 rock 27 2900 2800 > m/s, struck rock 2, which was at rest. After the collision, rock 1's velocity is < 3300 2200 3200 > m/s what is the final momentum of kg m/s 2r Before the collision, what was the kinetic energy of rock 1? Before the collision, what was the kinetic energy of rock 2?
The kinetic energy of rock1 before the collision is 27,225,000J, and the kinetic energy of rock2 before the collision is 0J.
The final momentum of the system and the kinetic energies of rock1 and rock2 are calculated by principles of conservation of momentum and kinetic energy.
The total momentum before the collision should be equal to the total momentum after the collision because there is no external force acting on the system. Therefore, the final momentum of the system is the same as the initial momentum.
Initial momentum = (mass of rock1) x (velocity of rock1) + (mass of rock2) x (velocity of rock2)
= (5 kg) x (<3800, 2900, 2800> m/s) + (27 kg) x (0 m/s) [since rock 2 was at rest]
= <19,000, 14,500, 14,000> kgm/s
Final momentum of the system is <19,000, 14,500, 14,000> kgm/s.
To calculate the kinetic energy of rock1 before the collision,
Kinetic energy = (1/2) x (mass) x (velocity)^2
Kinetic energy of rock1 = (1/2) x (5 kg) x (3300 m/s)^2
= 27,225,000J
Before the collision, rock2 was at rest, so its kinetic energy is zero.
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When using a liquid as a solvent, what could be the state(s) of matter of the solute?
Answer:
Explanation:
it can be a gas like carbon dioxide in soda
it can be liquid like alcohol in water
it can be solid like sugar and salt
Answer
✔ all three states
Explanation:
TOOK THE TEST
The frequency, or number of waves that pass a given point per second, of
sound is measured in:
A. hertz
B. meters
C. cycles
D. frequencies
Answer:
Hertz is the answer for this question
can someone pls help me create a lab trying to prove steam is hotter than boiling water.
Answer:
More energy
Explanation:
Steam is hotter than boiling water because it contains more energy
An object appears red when viewed with white light. What color would it appear when viewed with blue light?
Answer:
Colour of any object is by the colour of light it reflects i.e if white light is incident on the object,it will reflect blue color.so it will appear blue.But if red light is incident on it,it will not reflect that and absorb it.so as it will not reflect any light it will appear black.
Explanation:
PLEASE HURRY!!!!!!!!
Your brother pulls up to a corvette at a stop light and revs his engine. When the light turns green he slams the gas pedal to the floor. He begins at 9km/hr and after 6 seconds is going 82Km/hr. What was his acceleration rate? (Hint: your label with be Km/hr/s)
Answer:
9.1km/hr...................I think I'm not %100
ANSWER THE FOLLOWING QUESTION Which of the following statements are TRUE statements about exomoons? (Select all that apply) Select one or more alternatives:
A. Exomoons are likely to exist.
B. Exomoons are unlikely to exist.
C. Exomoons must be only made of ice.
D. Exomoons are have been used as locations within science fiction stories.
E. Exomoons are moons that orbit exoplanets.
The true statements about exomoons are:
A. Exomoons are likely to exist
D. Exomoons have been used as locations within science fiction stories
C. Exomoons must be only made of ice
A. Exomoons are likely to exist: It is believed that exomoons could exist in planetary systems beyond our own. While the detection and confirmation of exomoons remains a challenge, their existence is considered plausible based on the understanding of moon formation and the prevalence of exoplanets.
D. Exomoons have been used as locations within science fiction stories: Exomoons, being a fascinating concept, have captured the imagination of science fiction writers. They have been depicted in various stories and movies as intriguing and potentially habitable worlds.
E. Exomoons are moons that orbit exoplanets: An exomoon refers to a moon that orbits an exoplanet, which is a planet outside our solar system. Just like moons in our own solar system, exomoons are expected to orbit exoplanets, providing additional complexity and dynamics to the planetary systems.
C. Exomoons must be only made of ice: This statement is not true. Exomoons can be composed of various materials depending on their formation and composition. While some exomoons could have icy surfaces or subsurface oceans, others may be rocky or have diverse compositions.
It is important to note that our understanding of exomoons is still limited, and further research and observations are required to confirm their existence and study their characteristics.
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True or False. Friction can be reduced by lubricating or changing the shape of objects.
O True
OFalse
Answer: true
Explanation:
Answer:
true
Explanation:
Using lubricants such as oil or grease can reduce the friction between the surfaces
A 20000 kg rocket has a rocket motor that generates 3.0×10^5 n of thrust. part a what is the rocket's initial upward acceleration?
The rocket's initial upward acceleration is 15 m/s^2.
To find the rocket's initial upward acceleration, we need to use Newton's second law of motion, which states that the force applied to an object is equal to its mass multiplied by its acceleration:
F = m × a
Where F is the force applied, m is the mass of the object, and a is its acceleration.
In this problem, we know that the mass of the rocket is 20000 kg, and the rocket motor generates a force of 3.0×10^5 N in the upward direction. Therefore, we can calculate the rocket's initial upward acceleration as follows:
F = m × a
3.0×10^5 N = 20000 kg × a
a = 3.0×10^5 N / 20000 kg
a = 15 m/s^2
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Why would a nation most likely use military force? select three options. to remove trade restrictions to defend territory to support allies to promote political relationships to protect economic interests
Answer:
-to defend territory
-to support allies
-to protect economic interests
Explanation:
100% on edge
A nation most likely uses military force-
to defend territoryto support alliesto protect economic interestsWhat is the significance of military force?To defend the nation and its population from immediate danger, military superiority contributes to the maintenance of peace and stability in areas crucial to national interests and finances international security commitments.
The current method used by countries to obtain emergency recruits during times of conflict is drafting. This act, known as conscription in medieval and ancient periods, frequently involved taking young boys against their will from their homes.
Most of the time, leadership is crucial. The Army upholds national laws, accomplishes national goals, and prevents any nation's aggressive actions in order to maintain peace.
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A 2500 kg car with a speed of 15 m/s collides with a stationary car with a mass of 900 kg. On impact they hook together and move away. Their new mass is 3400 kg and new velocity is 0.05 m/s. What type of collision is being explained in the question?
This is an example of an inelastic collision. In an inelastic collision, some of the initial kinetic energy is lost, and the objects move away from each other with a reduced speed, as is the case here.
What is collision?Collision is the physical contact between objects, causing them to interact and exchange energy. This can occur when two or more objects come into contact with each other while moving at different speeds. Collisions can be elastic or inelastic, depending on the type and amount of energy lost in the interaction. Elastic collisions are those in which the total kinetic energy of the objects is the same before and after the collision, while in inelastic collisions some energy is lost in the form of heat, sound, or other forms of energy.
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what is the temperature of the moon?
Moon's temperature is 127 degrees Celsius on its sunlit side while minus 173 degrees Celsius on its dark side, based on sunlight exposure.
The temperature of the moon varies greatly depending on its location, time of day, and other factors. The moon has no atmosphere, so it has no insulating effect, and its temperature can range from extremely hot to extremely cold. The moon's temperature can reach up to 127 degrees Celsius (261 degrees Fahrenheit) on its sunlit side, which is exposed to the sun's radiation, while the temperature can drop down to minus 173 degrees Celsius (-280 degrees Fahrenheit) on its dark side, which is not exposed to sunlight.
In addition to the temperature differences between the sunlit and dark sides of the moon, the moon's temperature also varies with the lunar day, which is about 29.5 Earth days long. During the lunar day, the temperature rises steadily as the sun rises and reaches its maximum when the sun is directly overhead. During the lunar night, the temperature drops rapidly as the surface loses heat through radiation.
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two negatively charged objects are 2 meters apart. the student adds electrons through conduction to one of the objects.
Two negatively charged objects are 2 meters apart. the student adds electrons through conduction to one of the objects, then the force of repulsion between the two objects will decrease.
The reason for this is that the negatively charged electrons on the first object will repel the negatively charged electrons on the second object, creating a force of repulsion between them. Adding electrons to one of the objects will increase the number of electrons on that object, resulting in a stronger negative charge. This increase in the negative charge on one object will make it more difficult for the electrons on the other object to push against it, reducing the force of repulsion between the two objects. It's important to note that the amount of decrease in the force of repulsion will depend on the amount of electrons added and the initial charge of the objects. Also, If the distance between the two objects does not change and the charges on the objects are not affected by other factors, the electrostatic force of repulsion between the objects will be inversely proportional to the square of the distance between them.
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Question - Two negatively charged objects are 2 meters apart. The student adds electrons through conduction to one of the objects. What is the force of repulsion between the two objects?
A riddle for you
In some situations, I oppose the motion
in other situations, I facilitate the motion
but, I always oppose
the relative motion
between two moving surfaces.
Put some lubricant, and
I become small there.
Make the moving surfaces rough
I make the movement tough.
I may be
static, sliding or rolling
but whenever two surfaces are in motion
I am always there,
Tell me who I am!
The person who answers it correctly will be marked as brainlist
Answer:
The Answer is FRICTION!
A push and pull is an example of
Answer: A push and pull is an example of a force.
Explanation:
Colloid osmotic pressure (COP) is an osmotic pressure gradient equal to a. interstitial OP – capillary OP b. interstitial OP + capillary OP c. capillary OP – interstitial OP d. hydrostatic pressure + net filtration pressure
Colloid osmotic pressure (COP) is an osmotic pressure gradient equal to c. capillary OP – interstitial OP.
Colloid osmotic pressure, also known as oncotic pressure, is the osmotic pressure exerted by proteins and other colloidal particles present in the blood plasma. It plays a vital role in maintaining the balance of fluids between the capillaries and the surrounding interstitial fluid.
The capillary osmotic pressure refers to the osmotic pressure exerted by the proteins and colloids within the capillaries, which tends to draw fluid back into the capillaries. On the other hand, the interstitial osmotic pressure represents the osmotic pressure in the interstitial fluid, which is typically lower than the capillary osmotic pressure.
The colloid osmotic pressure gradient is the difference between these two pressures: capillary osmotic pressure minus interstitial osmotic pressure. This gradient helps to counterbalance the hydrostatic pressure and maintain fluid balance by preventing excessive filtration of fluid from the capillaries into the interstitial space.
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