The amount of energy required to boil water depends on the initial temperature of the water, the mass of the water, and the heat of vaporization of water.
The heat of vaporization of water is 40.7 kJ/mol or 2.26 kJ/g.
To completely boil 500g of water that is at 15°C, we need to first heat the water to its boiling point (100°C), and then provide the energy required for the phase change from liquid to gas.
The amount of energy required to heat the water from 15°C to 100°C can be calculated using the specific heat capacity of water, which is 4.184 J/g°C:
Q1 = m * c * ΔT
Q1 = 500g * 4.184 J/g°C * (100°C - 15°C)
Q1 = 191,020 J
The amount of energy required for the phase change from liquid to gas can be calculated as follows:
Q2 = m * Hv
Q2 = 500g * 2.26 kJ/g
Q2 = 1,130 kJ
Therefore, the total amount of energy required to completely boil 500g of water that is at 15°C is:
Qtotal = Q1 + Q2
Qtotal = 191,020 J + 1,130 kJ
Qtotal = 1,321,020 J
So, it would require 1,321,020 joules of energy to completely boil 500g of water that is at 15°C.
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HELP PLS! Pb(NO3)2 (aq) + 2 KBr (aq) --> PbBr2 (s) + 2 KNO3 (aq)
1. If this reaction starts with 32.5g lead (II) nitrate and 38.75g potassium bromide, how many grams of the precipitate will be produced?
2. How many grams of the excess reactant will remain?
59.96 grams of PbBr₂ will be produced and 5.47 grams of Pb(NO₃)₂ will remain after the reaction.
How many grams of the precipitate will be produced?The balanced equation shows that 1 mole of Pb(NO₃)₂ reacts with 2 moles of KBr to produce 1 mole of PbBr₂. We can use this ratio to calculate how many moles of Pb(NO₃)₂ and KBr are required for complete reaction:
Moles of Pb(NO₃)₂ = 32.5 g / 331.2 g/mol = 0.098 mol
Moles of KBr = 38.75 g / 119.0 g/mol = 0.325 mol
According to the stoichiometric ratio, 2 moles of KBr are required for every mole of Pb(NO₃)₂. Since we have less than half the required amount of KBr, it is the limiting reactant.
Therefore, we can calculate the moles of PbBr₂ produced based on the amount of KBr:
Moles of PbBr₂ = Moles of KBr / 2 = 0.325 mol / 2 = 0.163 mol
Finally, we can calculate the mass of PbBr₂ produced using its molar mass:
Mass of PbBr₂ = Moles of PbBr₂ x Molar mass
Mass of PbBr₂ = 0.163 mol x 367.01 g/mol
Mass of PbBr₂ = 59.96 g
Therefore, 59.96 grams of PbBr₂ will be produced.
How many grams of the excess reactant will remain?We already calculated the moles of KBr that reacted to be 0.325/2 = 0.163 mol. To calculate the moles of Pb(NO₃)₂ that reacted, we use the stoichiometric ratio from the balanced equation:
1 mole Pb(NO₃)₂ : 2 moles KBr
So, the moles of Pb(NO₃)₂ that reacted is:
0.163 mol KBr x (1 mol Pb(NO₃)₂ / 2 mol KBr) = 0.0815 mol Pb(NO₃)₂
Subtracting this from the moles of Pb(NO₃)₂ we started with gives:
Moles of Pb(NO₃)₂ remaining = 0.098 mol - 0.0815 mol = 0.0165 mol
Finally, we can calculate the mass of Pb(NO₃)₂ remaining using its molar mass:
Mass of Pb(NO₃)₂ remaining = Moles of Pb(NO₃)₂ remaining x Molar mass
Mass of Pb(NO₃)₂ remaining = 0.0165 mol x 331.2 g/mol
Mass of Pb(NO₃)₂ remaining = 5.47 g
Therefore, 5.47 grams of Pb(NO₃)₂ will remain after the reaction.
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suppose you have an alkaline buffer consisting of .2m aqueous ammonia and .1 ammonsium chlorisde what is the ph of the solution
The pH of the alkaline buffer consisting of 0.2 M aqueous ammonia and 0.1 M ammonium chloride is 9.55.
We must utilize the ammonium ion's (\({NH_4}^+\)) \(pK_a\) value of 9.25 to determine the pH of an alkaline buffer made up of 0.2 M aqueous ammonia (\(NH_3\)) and 0.1 M ammonium chloride (\(NH_4Cl\)). The following reaction takes place in this buffer solution:
\(NH_3 + H_2O\) ↔ \({NH_4}^+ + OH^-\)
The ammonium chloride will dissociate to form ammonium ion and chloride ion, but the ammonium ion will react with the hydroxide ion (\(OH^-\)) produced by the reaction above to form ammonia and water, effectively preventing any significant increase in the pH of the solution.
To calculate the pH of the buffer, we can use the Henderson-Hasselbalch equation:
\(pH = pK_a + log(\frac{base}{acid})\)
Where [base] is the concentration of the base (\(NH_3\)) and [acid] is the concentration of the acid (\({NH_4}^+\)).
Putting in the values, we get:
\(pH = 9.25 + log(\frac{0.2}{0.1})\)
⇒ \(pH = 9.25 + log(2)\)
⇒ \(pH = 9.25 + 0.301\)
⇒ \(pH = 9.55\)
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what does le chateliter's principle state
2. As the concentration of a solution increases how does the amount of light absorbed vary?.
Answer:
Absorbance increases.
Explanation:
Recall that absorbance is directly proportional to concentration as illustrated by Beer's Law:
\(\displaystyle A = \epsilon bC\)
Where A is the absorbance and C is the concentration of the solution.
Therefore, as the concentration of a solution increases, the amount of light absorbed (absorbance) likewise increases.
What formula is used for solving problems involving Boyle’s law?P1T1=P2T2P1T1=P2T2P1=V2P1=V2V1T1=V2T2V1T1=V2T2P1V1=P2V2
Step 1 - Brief revision of Boyle's Law
Boyle's law is a law concerning the behavior of gases. It states that the pressure and the volume are inversely proportional given that the temperature is kept constant.
That is, if we increase the pressure, the volume will decrease. This principle is behind the proper functioning of our lungs, for example. This can also be described mathematically as:
\(P_1V_1=P_2V_2\)Step 2 - Choosing the right alternative
As we have seen in step 1, we can use the following formula to work with Boyle's Law:
\(P_1V_1=P_2V_2\)Therefore, the correct alternative is item d.
1. Draw the molecule that corresponds to each of the names given. a. m-chlorobenzoyl chloride b. methyl butanoate c. butanoic anhydride d. N,N-diethylhexanamide
a. m-chlorobenzoyl chloride: Cl-C(O)Cl
b. methyl butanoate: CH3-CO-O-CH3
c. butanoic anhydride: (CH3CH2CH2CO)2O
d. N,N-diethylhexanamide: HN(C2H5)2-C6H13-C=O
What are the molecular structures of m-chlorobenzoyl chloride, methyl butanoate, butanoic anhydride, and N,N-diethylhexanamide?a. m-chlorobenzoyl chloride:
Cl
|
C6H4-CO-Cl
b. methyl butanoate:
O
||
CH3-CH2-CH2-COOCH3
c. butanoic anhydride:
O
||
CH3-CH2-CH2-CO-O-CO-CH2-CH2-CH3
d. N,N-diethylhexanamide:
H H H H H H H H
| | | | | | | |
CH3-CH2-C-C-C-C-C-C-N(C2H5)2
| | | | | | |
H H H H H H H
These drawings represent the molecular structures of the given compounds: m-chlorobenzoyl chloride, methyl butanoate, butanoic anhydride, and N,N-diethylhexanamide.
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The amount of calcium present in milk can be determined through gravimetric analysis by adding oxalate to a sample and measuring the mass of calcium oxalate precipitated. What is the mass percent of calcium in milk if 0. 429 g of calcium oxalate, cac2o4, forms in a 125-g sample of milk when excess aqueous sodium oxalate is added?.
Calcium content as a mass percentage in milk is 0.106%.
To calculate the number of moles, we use the equation shown below:
Given mass ÷ Molar mass = number of moles
Given that 0.429 g of calcium oxalate is present
Calcium oxalate has a molar mass of 128.1 g/mol.
By changing the values,
A number of moles = 0.429 ÷ 128.1 g/mol = 0.0033 mol
The given chemical equation follows:
\(Na_2C_2O_4(aq.) + Ca^{2+}(aq.)\) → \(CaC_2O_4(s) + 2Na^{+}(aq.)\)
Overabundant sodium oxalate is found. Therefore, it is regarded as an excess reagent. Additionally, calcium ion is a limiting reactant since it restricts the product's ability to form.
Using the reaction's stoichiometry:
From 1 mole of calcium ion, 1 mole of calcium oxalate is created.
Thus, produces 0.0033 moles of calcium oxalate.
(1 ÷ 1) × 0.0033 = 0.0033 mol of calcium ions.
Using equation 1, we can now calculate the mass of calcium ions and obtain:
Calcium ions in moles equal 0.0033 moles.
Calcium ions have a molar mass of 40 g/mol.
Equation 1 is solved for the following values:
0.0033 mol = Mass of calcium ions ÷ 40 g/mol
Mass of calcium ions = 0.0033 mol × 40 g/mol = 1.132
We employ the following equation to get the mass proportion of calcium ions from milk:
The mass percent of calcium ions = (Mass of calcium ions ÷ Mass of milk) × 100
Milk weighs 125 g.
Calcium ions' mass is 0.132 g.
By entering data into the aforementioned equation, we obtain the following,
The mass percent of calcium ions = (0.132g ÷ 125g) × 100 = 0.106%
As a result, milk has a mass percent of calcium of 0.106%.
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The question is -
The amount of calcium present in milk can be determined through gravimetric analysis by adding oxalate to a sample and measuring the mass of calcium oxalate precipitated. What is the mass percent of the calcium in milk if 0.429 g of calcium oxalate, CaC2O4, forms in a 125-g sample of milk when excess aqueous sodium oxalate is added?
Na2C2O4 (aq) + Ca2+ (aq) → CaC2O4 (s) + 2 Na+ (aq)
4. Anh measured the temperature of a pond near his house. Before he left for school, the water in the
pond was 18°C. When he came home from school, the temperature of the pond was higher than it
was in the morning. What happened to the water molecules while he was at school?
The water molecules must have gained more thermal energy while Anh was away from the house.
An increase in the temperature of a body means that the body has gained more energy in the form of heat, also known as thermal energy.
The thermal energy represents the characteristic of a body responsible for its temperature.
An increase in the temperature of the water molecules increases their kinetic energy and, thus, makes the water molecules move around faster than before.
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Which dosage form is a semisolid preparation that contains very small solid particles that are suspended in a liquid
A GEL is a semisolid preparation that contains very small solid particles that are suspended in a liquid. A gel always contains an agent (e.g., agarose) that provides stiffness to the preparation.
A gel is a semisolid preparation that contains a gelling agent which provides stiffness to the preparation.
The gelling agent can be, for example, agarose (this gelling agent is used to prepare gels in electrophoresis).
In an agarose gel, agarose molecules are organized into three-dimensional (3D) structures similar to pores, which allow the passage of DNA fragments during electrophoresis.
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A 500-ml glass beaker is filled to the brim with ethyl alcohol at a temperature of 5. 00ºc. how much will overflow when its temperature reaches 22. 0ºc?
The volume of ethyl alcohol overflow will be 9.265mL.
To calculate the volume of ethyl alcohol overflow, we will use
∆V=V(á∆T)
Where,
∆V=volume expand
á=volumetric expansion Coefficients =0.00109/°C
V=initial volume =500ml
T'=final temp. =22°C
T=initial temp=5°C
Now,
∆V=500×(0.00109/°C) ×(22-5)
=500×(0.00109) (17)
=9.265ml
Thus, we find that the volume of ethyl alcohol overflow will be 9.265 mL.
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How do operators analyze the ability of a treatment process to remove or an activate oocysts
Coagulation, flocculation , and sedimentation
Operators analyze the ability of a treatment process to remove or an activate oocysts by coagulation and flocculation.
Coagulation and flocculation are methods that are used to separate the suspended solids portion from the water. Suspended particles may vary in source, charge, particle size, shape, and density. Correct application of coagulation and flocculation usually depends upon these factors.
Coagulation is also defined as the destabilization of colloidal particles brought about by the addition of a chemical reagent called as coagulant. Flocculation is defined as the agglomeration of destabilized particles into micro-floc and after into bulky floccules which can be settled called floc.
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A family is driving to a nearby city. If they traveled 224.4 miles for 3.3 hours how fast were they traveling?
Why do we need units of pressure?
Answer:Because there are so many units for energy.
Explanation:
a mixture of two ideal gases is made from ideal gases at temperature t and pressure p by flowing them separately into a mixing chamber. if no heat is transferred during the charging process and t and p remain the same at the exit, how do the enthalpy h and entropy s change for each component?
Since the ideal gases are being mixed at constant temperature and pressure, the enthalpy change for each component would be zero, as there is no change in heat transfer. However, the entropy change for each component would increase due to the mixing process. The increase in entropy is due to the fact that there are more ways to arrange the molecules in a mixed gas than in separate gases, resulting in an increase in disorder. Therefore, the entropy change for each component would be positive.
When two ideal gases are mixed in a chamber at a constant temperature (T) and pressure (P), the enthalpy (H) and entropy (S) changes can be analyzed as follows:
For each component of the ideal gas mixture, the enthalpy (H) remains constant. This is because the temperature (T) and pressure (P) do not change during the mixing process, and for ideal gases, enthalpy depends only on temperature.
However, the entropy (S) for each component will change during the mixing process. This is due to the increase in the number of accessible microstates for each gas molecule as they mix, leading to a higher level of disorder in the system. The overall entropy change (ΔS) for the system will be positive, indicating an increase in entropy.
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A pipe leaks water at a rate of 1.24 mL/s. What is the rate of the water leak in L/hr?
Select one:
a)0.344 L/hr
b)4.46 L/hr
c)0.0744 L/hr
d)20.7 L/hr
Answer:
b)4.46 L/hr
Explanation:
To solve this question we need to convert the mL to liters (Using the conversion of 1000mL = 1L) and convert the time from seconds to hours (3600s = 1hr)
mL to L:
1.24mL/s * (1L / 1000mL) = 0.00124L/s
seconds to hours:
0.00124L/s * (3600s / 1hr) = 4.46L/hr
Right answer is:
b)4.46 L/hrAt pH 3, how many charged groups are present in the pentapeptide Ala-Asp-His-Ser-Lys?
a) 1
b) 2
c) 3
d) 4
e) 5
There are 4 charged groups present in the pentapeptide at pH 3. Therefore, the correct answer is (d) 4.
At pH 3, the carboxyl group of Ala, Asp, and Lys will be protonated, making them positively charged. The amino group of the N-terminal Ala will also be protonated, making it positively charged. The imidazole group of His, however, will be fully protonated, making it neutral. Therefore, there are a total of four charged groups present in the pentapeptide Ala-Asp-His-Ser-Lys at pH 3. The answer is d) 4.
At pH 3, the charged groups present in the pentapeptide Ala-Asp-His-Ser-Lys are:
1. Asp (aspartic acid) with a carboxyl group (COOH), which is negatively charged at pH 3.
2. Lys (lysine) with an amino group (NH3+), which is positively charged at pH 3.
3. The N-terminal amino group (NH3+) of Ala, which is positively charged at pH 3.
4. The C-terminal carboxyl group (COOH) of Lys, which is negatively charged at pH 3.
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What is meant by the term chemical bond? What subatomic particles(protons, neutrons, electrons) are most important in bonds?
Explanation:
Chemical Bonding refers to the formation of a chemical bond between two or more atoms, molecules, or ions to give rise to a chemical compound.
The subatomic particles that participate are electrons.
A catabolic process is a process in which
molecules are broken down and energy is released.
molecules are broken down and energy is absorbed.
molecules are combined and energy is released.
molecules are combined and energy is absorbed.
Answer:
a) molecules are broken down and energy is released.
Explanation: edge 2021
Answer:
a
Explanation:
edge2022
That's just the tip of the iceberg" is a popular expression you may have heard. It means that what you can see is only a small part of the overall problem. As the diagram shows, most of an iceberg is actually out of sight, below the water level. Based on this diagram, what is the most likely density of the iceberg? (Assume a density of 1.03 g/mL for seawater.)
A. 0.88 g/cc
B. 1.23 g/cc
C. 0.23 g/cc
D. 4.14 g/cc
the enantiomer of thalidomide that causes developmental defects is______
The thalidomide catastrophe led to stricter rules for medication approval in numerous nations. Thalidomide is a racemic combination of the (R)- and (S)-enantiomers and exists in two mirror-image forms. The (S)-isomer is teratogenic, whereas the (R)-enantiomer has sedative properties.
What enantiomer of thalidomide causes defects?Enantiomer theory enters the picture at this point. The thalidomide molecule can be found in two different forms in nature, (R)-thalidomide and (S)-thalidomide, which are enantiomers, or molecules that are mirror images of one another.
While the (S)-form is a teratogen, an agent that can result in birth abnormalities, the (R)-form possesses therapeutic qualities.
Therefore, It is extremely difficult and dangerous to isolate pure (R)- thalidomide because the two enantiomers of the drug regularly interconvert in the body to create a mixture that contains both enantiomers.
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What conclusions can be drawn regarding the molecule C6H12O6?
1. The molecule is inorganic; it is a salt.
2. The molecule is organic; it is a salt.
3. The molecule is inorganic; it is a carbohydrate.
4. The molecule is organic; it is a carbohydrate.
Which answer best describes the relationship between sodium and aluminum?
1. Sodium and aluminum have similar chemical properties because they are in the same group.
2. Sodium and aluminum have similar chemical properties because they are in the same period.
3. Sodium and aluminum have the same number of electron shells because they are in the same group.
4. Sodium and aluminum have the same number of electron shells because they are in the same period.
the process of breathing involves exchanging oxygen for which other gas?
The process of breathing involves exchanging oxygen for carbon dioxide gas.
The process of breathing involves inhalation and exhalation.
Inhalation is the process of taking in oxygen and Exhalation is the process of taking out carbon dioxide. Air contains 21 % oxygen and 71 % nitrogen and 8 % other gases.
When we breathe in(inhalation) our diaphragm contracts downward while during breath out(exhalation) our diaphragm contracts upward. As food and water are important for us in similar way breathing is also essential for life.
So during the process of breathing, we take in oxygen and take out carbon dioxide.
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Use a linear system to balance the chemical equation S
2
O
3
2−
+H
2
O+CrO
4
2−
⟶SO
4
2−
+Cr(OH)
4
2−
+OH
−
The balanced chemical equation using a linear system is:
3S2O32- + 2H2O + CrO42- -> 3SO42- + Cr(OH)42- + 2OH-
To balance the given chemical equation, we can set up a system of linear equations based on the number of atoms of each element on both sides of the equation.
In this case, we have 3 sulfur (S) atoms, 6 oxygen (O) atoms, 4 hydrogen (H) atoms, 1 chromium (Cr) atom, and 4 hydroxide (OH-) ions on the left-hand side. On the right-hand side, we have 3 sulfate (SO42-) ions, 1 chromium hydroxide (Cr(OH)42-) ion, and 2 hydroxide (OH-) ions.
By setting up and solving a system of equations, we can determine the coefficients that balance the equation. The coefficients obtained through the linear system are 3, 2, and 1 for S2O32-, H2O, and CrO42-, respectively, on the left-hand side, and 3, 1, 1 for SO42-, Cr(OH)42-, and OH- ions, respectively, on the right-hand side. This ensures that the number of atoms of each element and the charge is conserved in the balanced equation.
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0.20 g of sodium hydroxide (NaOH) pellets are dissolved in water to make 4.5 L of solution. What is the pH of this solution? Express the pH numerically to two decimal places.
Answer:
11.05( to 2 decimal places).
Explanation:
Without mincing words let's dive straight into the solution the above problem. So, we are given the following parameters which are going to help us in solving this problem;
The mass of sodium hydroxide (NaOH) pellets given = 0.20g and the volume = 4.5 L of solution.
Therefore, the concentration of the solution = number of moles/ volume.
Note that The numbers of moles = mass/molar mass= 0.20g / 40 = 0.005 moles.
Hence, the concentration of the solution = number of moles/ volume = 0.005 moles / 4.5L = 0.00111 M.
pOH = - log[ OH^-] = - log [ 0.00111] = 2.955.
Note that; pH + pOH = 14.
Therefore, pH = 14 - pOH.
pH = 14 - 2.955 = 11.045 = 11.05( to 2 decimal places).
why is m3 is derived unit?
Answer and Explanation:
There are 7 base units, m is one of them. Any unit made up of a combination of them is a derived unit. Also, any unit that is defined to be equivalent to a combination of base units is a derived unit.
If the earth's mantle were completely solid,__________ plates could not move around.
Answer:tectonic
Explanation:
Answer:
TECTONIC
Explanation:
Use thermodynamics and the concept of energy quality to explain why we can only burn a gallon of oil as fuel once
Thermodynamics is the branch of science that deals with energy conversion and the rules governing the movement of energy from one form to another. Energy quality refers to the level of usefulness of energy. It refers to the amount of useful energy that is available to perform a given task.
The first law of thermodynamics, also known as the Law of Conservation of Energy, states that energy can neither be created nor destroyed; it can only be converted from one form to another.
This means that the energy that we get from burning a gallon of oil cannot be destroyed but can be converted to other forms of energy like heat, electricity, and kinetic energy.
However, the second law of thermodynamics tells us that every energy conversion comes at the cost of some energy loss.
This means that every time we convert energy from one form to another, some of the energy gets lost in the form of heat. So, when we burn a gallon of oil, we cannot get all the energy that it contains in a useful form.
Instead, we get only a fraction of it as useful energy, and the rest is lost as heat.
Energy quality refers to the level of use of energy.
It refers to the amount of useful energy that is available to perform a given task.
Some forms of energy, like electricity, are very useful because they can be easily converted to other forms of energy.
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Elemental bromine reacts vigorously with elemental sodium metal to form a white solid. Does this characteristic of elemental bromine represent a physical or a chemical property?
The characteristic of elemental bromine reacting vigorously with elemental sodium metal to form a white solid represents a chemical property.
Chemical characteristics define how substances react or change chemically. A white solid forms when elemental bromine and sodium metal combine, suggesting a chemical transition.
However, a substance's physical attributes can be detected or quantified without changing its chemical composition. Colour, density, melting, and boiling points are physical qualities.
It is a chemical property of elemental bromine to react with sodium metal and generate a new compound.
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How many moles of silver chloride will be produced if 2 moles of silver is allowed to react with an
unlimited amount of chlorine?
When two moles of silver are allowed to react with an unlimited amount of chlorine, 2 moles of silver chloride (AgCl) is produced.
When a chemical reaction takes place, it is important to know the amount of products that will be formed from the reactants used. In order to do this, we need to know the balanced chemical equation for the reaction and the number of moles of reactants used.The balanced chemical equation for the reaction between silver and chlorine gas is given by:
2Ag + Cl2 → 2AgCl
Here, we can see that 2 moles of silver react with 1 mole of chlorine gas to produce 2 moles of silver chloride.Since an unlimited amount of chlorine is allowed to react with 2 moles of silver, the number of moles of silver chloride produced will be equal to the number of moles of silver reacted. Hence, 2 moles of silver chloride will be produced.Therefore, we can say that if 2 moles of silver is allowed to react with an unlimited amount of chlorine, 2 moles of silver chloride will be produced. This is because the balanced chemical equation shows that 2 moles of silver react with 1 mole of chlorine gas to produce 2 moles of silver chloride.
When a chemical reaction takes place, it is important to know the amount of products that will be formed from the reactants used. In this case, we have determined that if 2 moles of silver is allowed to react with an unlimited amount of chlorine, 2 moles of silver chloride will be produced. This is because the balanced chemical equation shows that 2 moles of silver react with 1 mole of chlorine gas to produce 2 moles of silver chloride.
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please help me
16 1 point What is the decay rate of a sample of Oxygen-21 if the sample has 8.31x1017 atoms and a decay constant of 0.203/s? 4.09x1018Bq 1.69x10¹7Bq 0.203Bq 2.44x10-1⁹Bq Previous
decay rate of approximately 1.69x10^17 Bq (becquerels),
The decay rate of a radioactive sample is determined by the number of radioactive atoms present and the decay constant, which represents the probability of decay per unit of time.
To calculate the decay rate, we multiply the number of atoms in the sample by the decay constant. In this case, the sample has 8.31x10^17 atoms and a decay constant of 0.203/s. Multiplying these values gives a decay rate of approximately 1.69x10^17 Bq (becquerels), which represents the number of decays per second in the sample.
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