You want to store 165 g of CO2 gas in a 12.5-L tank at room temperature (25°C). Calculate the pressure the gas would have using the van der Waals equation. (For CO2, a = 3.59 atm L2 /mol2 and b = 0.0427 L/mol and mass = 44)

Answer:

Mediterranean

Explanation:

I remember learning this in class. The Mediterranean has hot summers and mild winters.

Answer:

A & B

Explanation:

Done the Quiz

The mass concentration of sand in the ethanol solution is 0.299 g/dm³.

To find the concentration in grams per cubic decimeter (g/dm³), we first need to convert the volume from liters to cubic decimeters (dm³). Since 1 liter is equal to 1 cubic decimeter, we can directly convert the volume.

Given:

Mass of sand = 0.2 g

Volume of ethanol = two-thirds liter

Converting volume to dm³:

1 liter = 1 cubic decimeter

two-thirds liter = (2/3) cubic decimeter = 0.67 dm³ (rounded to two decimal places)

Now we can calculate the concentration in g/dm³ by dividing the mass of sand by the volume in dm³:

Concentration = Mass / Volume

Concentration = 0.2 g / 0.67 dm³

Concentration ≈ 0.299 g/dm³ (rounded to three decimal places)

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The mass by volume percentage is an important method which is used to calculate the concentration of a solution. This type of concentration is usually expressed as a percentage. Here the amount of solute is

The mass by volume percentage of a solution is defined as the ratio of the mass of solute that is present in a solution relative to the volume of the solution as a whole.

The equation used to calculate the mass by volume percentage is:

m / v = Mass of solute / Volume (mL) of solution × 100 %

m / v = 50 g / 75 mL + 25 mL = 0.5  × 100 % = 50%

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Answer:

Yes the reaction occur when aqueous solutions happened

Answer:

150 mL

Explanation:

Recall that

\(Molarity = \frac{moles}{volume}\)

Now, we are given a Molarity of 0.250 M H2SO4 with a volume of 45 mL. We will convert this to moles

\(mol = \frac{M}{L}\)

Then, since the mole ratio from H2SO4 to NAOH is 1:2, we will multiply by 2

Finally, we will get the volume by dividing by the Molarity of NaOH which is 0.150 M.

The setup for the answer is as follow

\((0.25 M H_2SO_4)(45 mL H_2SO_4)(\frac{2 mol NaOH}{1 mol H_2SO_4} )(\frac{1}{0.15MNaOH})\)

The final answer is 0.150 L or 150 mL.

1. Using your knowledge of the Brønsted-Lowry theory of acids and bases, complete the following acid-base reactions and indicate each conjugate acid-base pair.

i. OH + HPO₂ → H₂O + H₂PO₄²⁻

The conjugate acid-base pair is OH/H₂O, HPO₂²⁻/H₂PO₄²⁻

2) Identify the conjugate acid-base pairs in the following reactions. Write A, B, CA, and CB below the appropriate substance.

i. HCO₃⁻ + NH₃ → NH₄⁺ + CO₃²⁻

The conjugate acid-base pair is HCO₃⁻/CO₃²⁻, NH₃/NH₄⁺

ii. HCI + H₂O → H₃O⁺ + Cl⁻

The conjugate acid-base pair is H₂O/OH⁻, HCI/Cl⁻, H₃O⁺/H₂O, Cl⁻/HCI

iii. CH₃COOH + H₂O → H₃O⁺ + CH₃COO⁻

The conjugate acid-base pair is CH₃COOH/CH₃COO⁻, H₂O/OH⁻, H₃O⁺/H₂O

iv. HOCI + NH₃ → NH₄⁺ + ClO⁻

The conjugate acid-base pair is HOCI/ClO⁻, NH₃/NH₄⁺

3. Write the formula for conjugate bases formed by the following acids.

i. HPO₄²⁻ → PO₄³⁻

ii. H₂O → OH⁻

iii. CN⁻ → HCN

iv. HOOC-COO⁻ → HOOCCOOH

4) Write the formula for conjugate acids formed by each of the following bases.

i. H₃O⁺ → H₂O

ii. HCN → H₂CN⁺

iii. NH₃ → NH₄⁺

5. Classify each of the following pH values as acidic, basic, or neutral.

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Answer:

1.E25 it is the answer the answer to mass of 1×10^25 molecules of water​

Explanation:

this is just EXPLINATION find your answer using this

first divide the number of molecules by Avogadro's number 6.022*10^25

you will

l get no. of Moles of water

multiply the no. of Moles with mass of 1 Mole of water 18g per mole

if get answer you comment

you should try on your own you will understand better

In this solution, sodium ion [Na+] has a molar concentration of 0.02745 M. (or 27.45 mM).

A salt combining sodium and phosphate, sodium phosphate has the chemical formula Na3PO4. It is an inorganic chemical that comes in a variety of shapes, including hydrated and anhydrous versions.

The amount of sodium phosphate in the solution must first be determined in moles:

Number of moles of Na3PO4 = Mass of Na3PO4 / Molecular weight of Na3PO4

Number of moles of Na3PO4 = 1.500 g / 163.94 g/mol

Number of moles of Na3PO4 = 0.00915 mol

The total number of moles of sodium ions in the solution is because one molecule of sodium phosphate (Na3PO4) contains three sodium ions (Na+). 

Number of moles of Na+= 3 x Number of moles of Na3PO4

Number of moles of Na+ = 3 x 0.00915 mol

Number of moles of Na+ = 0.02745 mol

The sodium ion [Na+] molar concentration in the solution can then be calculated as follows:

Moles of Na+ / volume of solution = number of moles of Na+

Na+ has a molar concentration = 0.02745 mol / 1.00 L.

Na+ has a molecular weight = 0.02745 M.

As a result, this solution has a molar sodium ion concentration of 0.02745 M. (or 27.45 mM).

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The difference in the number of cations and anions in the given mixture is approximately 0.0005 mol.

The molar mass of Na2SO4 (sodium sulfate) can be calculated as follows:

2(Na) + 1(S) + 4(O) = 2(22.99 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 142.04 g/mol

The number of moles of Na2SO4 :

moles of Na2SO4 = mass of Na2SO4 / molar mass of Na2SO4

moles of Na2SO4 = 1.49 g / 142.04 g/mol ≈ 0.0105 mol

Similarly, the molar mass of Al2(SO4)3 (aluminum sulfate) :

2(Al) + 3(S) + 12(O) = 2(26.98 g/mol) + 3(32.07 g/mol) + 12(16.00 g/mol) = 342.15 g/mol

The number of moles of Al2(SO4)3:

moles of Al2(SO4)3 = mass of Al2(SO4)3 / molar mass of Al2(SO4)3

moles of Al2(SO4)3 = 3.42 g / 342.15 g/mol ≈ 0.0100 mol

For Na2SO4, the ratio of cations (Na+) to anions (SO42-) is 2:1. So, the number of cations in 0.0105 mol of Na2SO4 is 2 * 0.0105 mol = 0.0210 mol, and the number of anions is 0.0105 mol.

For Al2(SO4)3, the ratio of cations (Al3+) to anions (SO42-) is 2:3. So, the number of cations in 0.0100 mol of Al2(SO4)3 is 2 * 0.0100 mol = 0.0200 mol, and the number of anions is 3 * 0.0100 mol = 0.0300 mol.

Calculating the difference in the number of cations and anions:

Difference = (Number of Cations in Na2SO4 + Number of Cations in Al2(SO4)3) - (Number of Anions in Na2SO4 + Number of Anions in Al2(SO4)3)

Difference = (0.0210 mol + 0.0200 mol) - (0.0105 mol + 0.0300 mol)

Difference = 0.0410 mol - 0.0405 mol

Difference ≈ 0.0005 mol

Therefore, the difference in the number of cations and anions in the given mixture is approximately 0.0005 mol.

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Explanation:

Conversion -

CH₃–CH₂–OH → CH₃–CH₂– CH(OH)–CH₃

Explaination -

CH₃–CH₂–OH + HCl → CH₃–CH₂– Cl + H₂O

Now,

CH₃–CH₂– Cl + 2Na + Cl–CH₂–CH₃ → CH₃–CH₂–CH₂–CH₃ + 2NaCl (wurtz reaction)

Now,

CH₃–CH₂–CH₂–CH₃ + Cl₂ → CH₃–CH₂–CH₂–CH₂–Cl + HCl (Halogenation)

Now,

CH₃–CH₂–CH₂–CH₂–Cl + KOH (alc.) → CH₃–CH₂–CH=CH₂ + KCl + H₂O

Now,

CH₃–CH₂–CH=CH₂ + H₂O → CH₃–CH₂–CH(OH)–CH₃ (Hydration of alkene by MR addition rule)

The best way to measure the pH of a natural solution while out in a forest is to use a portable pH meter or pH test strips specifically designed for field use. These instruments provide accurate and reliable pH measurements and are convenient for outdoor applications.

1. Prepare the necessary equipment: Before heading out to the forest, gather the required tools. You will need a portable pH meter or pH test strips, as well as the necessary reagents or calibration solutions if using a pH meter.

2. Collect the sample: Locate the natural solution you want to measure the pH of, such as a stream, pond, or soil. Use a clean container to collect a representative sample of the solution.

3. Calibrate the pH meter (if applicable): If you are using a portable pH meter, it is essential to calibrate it before taking measurements. Follow the manufacturer's instructions to calibrate the meter using the provided calibration solutions.

4. Conduct the measurement: For pH meters, immerse the electrode into the collected sample. Allow some time for the reading to stabilize, and then record the pH value indicated on the meter's display.

5. Using pH test strips: If you are using pH test strips, dip the strip into the collected sample for the recommended amount of time. Remove the strip and compare the color change with the provided color chart. Determine the corresponding pH value from the chart.

6. Repeat for accuracy: To ensure reliability, repeat the measurement process at least once and compare the results. This step helps confirm the accuracy of your measurements.

7. Record and analyze the data: Note down the pH values obtained and any relevant observations. Analyze the data as needed for your research or monitoring purposes.

By following these steps and using the appropriate equipment, you can effectively measure the pH of a natural solution while in a forest setting.

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Problem 1:

we need 80 g of the 15% solution and 120 g of the 20% solution.

Let x be the mass of the 15% solution needed and y be the mass of the 20% solution needed.

x + y = 200 (total mass of the two solutions)

0.15x + 0.2y = 0.17(200) (total amount of solute in the two solutions)

Solving these equations,  x = 80 g and y = 120 g.

Therefore, we need 80 g of the 15% solution and 120 g of the 20% solution.

Problem 2:

we need 120 g of the 18% solution and 180 g of the 5% solution.

Let x be the mass of the 18% solution needed and y be the mass of the 5% solution needed.

x + y = 300

0.18x + 0.05y = 0.07(300)

Solving these equations, x = 120 g and y = 180 g.

Therefore, we need 120 g of the 18% solution and 180 g of the 5% solution.

Problem 3:

The mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.

The total mass of the final solution is 200 g + 350 g = 550 g.

The total amount of solute in the final solution is:

0.15(200 g) + 0.20(350 g) = 65 g + 70 g = 135 g.

Therefore, the mass percentage of the final solution is 135 g/550 g × 100% = 24.55%.

Problem 4:

The mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.

The total mass of the final solution is 300 g + 35 g = 335 g.

The total amount of solute in the final solution is:

0.15(300 g) + 35 g = 75 g + 35 g = 110 g.

Therefore, the mass percentage of the final solution is 110 g/335 g × 100% = 32.84%.

Problem 5:

The mass percentage of the final solution is 18.18%.

Calculate the final mass of the solution:

Final mass = 400 g + 150 g = 550 g

Calculate the mass of solute in the 25% solution:

Mass of solute = 0.25 x 400 g = 100 g

Calculate the mass percentage of the final solution:

Mass percentage = (mass of solute ÷ final mass) x 100%

Mass percentage = (100 g ÷ 550 g) x 100%

Mass percentage = 18.18%

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An element is a substance that cannot be broken down by chemical means. Elements are extremely particular compounds that serve as the foundation for all life and matter (well other than the stuff smaller than atoms). It can contain one atom or trillions of them for anything to be an element, however atoms of different types cannot be combined in. That is to say, every atom has a set number of protons, ranging from 1 to 118. You can be positive that the substance you have is hydrogen if there is just one proton present. Mercury is what you get if you have 80 protons. Atoms of pure hydrogen only contain one proton. As most people are aware, if you add oxygen to it, it turns into water, which is no longer an element but a compound. Nevertheless, the building blocks are the elements. Every single object you can see is composed of elements, whether there are many of them, as there are in the human body, or only a few, as there are in salt.

A compound is a substance with a definite composition (with some leeway there, there are 'non-stoichiometric' compounds), that is composed of 2 or more elements.

Further explanation:

A compound in chemistry is a material that is created by mixing two or more distinct chemical elements in such a way that the atoms of the various elements are kept together by strong chemical bonds. These bonds form as a result of the sharing or exchange of electron s among the atoms. A molecule is the smallest, unbreakable unit of a substance.

A mixture is not a compound since there is no bonding between the atoms of the constituent substances in a mixture. In certain cases, mixing dissimilar elements causes chemical reactions that result in the formation of bonds between the atoms and the molecules of a compound. Other possibilities allow mixing distinct components without causing a reaction, preserving the separate identities of the elements. When elements are combined, reactions can happen quickly or slowly (for example, when iron is exposed to oxygen) (as when lithium is exposed to oxygen). There are times when an element is introduced to a chemical, a reaction takes place, creating new compounds (as when pure elemental sodium is immersed in liquid water).

A compound frequently looks and acts quite different from any of the constituent parts. Think about hydrogen (H) and oxygen, for instance (O). At standard atmospheric pressure and room temperature, both of these substances are gases. However, they combine to form the well-known material known as water, which is a liquid at room temperature and at normal atmospheric pressure and whose molecules each contain two hydrogen atoms and one oxygen atom (H2O).

Few elements' atoms readily combine with those of other elements to produce compounds. These gases—helium, neon, argon, krypton, xenon, and radon—are referred to as noble or inert gases. Compounds made of certain elements can be formed easily with other elements. Examples include fluorine, chlorine, and oxygen.

2) The adjective compound refers to something that is made up of several different components. Examples of this usage include compound eyes, which are found in a variety of insects, compound microscopes, which are high-power magnifying devices made up of multiple lenses, compound sentences, which are organized collections of smaller sentences that form a single integrated perceptual environment, and compound documents.

The solubility of a substance, such as sugar, depends on several factors, including temperature, pressure, and the presence of other solutes. In this case, the student adds the same amount of sugar and tea bag to the same amount of hot water every day, but the temperature of the water could vary from day to day, affecting how much sugar dissolves.

According to the graph, the least amount of sugar dissolved on day 3, while the most sugar dissolved on day 5. The difference in temperature on these days could explain this variation. On day 3, the water may have been cooler, making it more difficult for the sugar to dissolve. On the other hand, on day 5, the water may have been hotter, which could have increased the solubility of the sugar.

To increase the amount of sugar that dissolves in the tea, the student could try using hotter water or stirring the sugar more vigorously to distribute it evenly throughout the water. Alternatively, the student could try adding the sugar gradually while stirring to give it more time to dissolve before adding more.

Answer:

I'm not 100% sure on this because mine hasn't been graded yet, but here are the answers I submitted.

Explanation:

Which day the least sugar dissolved and which day the most sugar dissolved:

Day 4 is when the least sugar dissolved, and Day 2 is when the most sugar dissolved.

What could have caused less sugar to dissolve on some days:

The temperature of the tea could have caused the sugar not to dissolve on some days.

What the student could do to his drink to make more sugar dissolve.

The student would need to add the sugar to the tea as soon as it's done boiling.  The Sugar will dissolve faster in a warmer tea due to more energy of movement.  

Be sure to stir the tea as you add the sugar.  Stirring the sugar into the tea speeds up the rate of dissolving by helping distribute the sugar particles throughout the tea.  

If the student were to use granulated sugar, those are smaller particles and have greater surface area.  Greater surface area allows for more contact between the tea and the sugar.

Answer:

Explanation:

green

Answer:

There are 23 electrons in Fe3+

Answer:

C is the correct answer

Explanation:

Hope this helps:)

If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.

The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.

According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:

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By 2100, CO2 levels rise to about 420 ppm, almost 20 ppm over current levels, which, when additional forcings are taken into account, equals 475 ppm (in CO2e). Global temperatures are predicted to increase by 1.3–1.9C over pre-industrial levels by 2100.

According to climate models that simulate a high emissions scenario (RCP8.5), the world's average temperature will rise by at least 4 °C by 2100. Model simulations based on scenarios that would reduce emissions significantly and continuously through the end of the century (RCP2). According to climate models that simulate a high emissions scenario (RCP8.5), the world's average temperature will rise by at least 4 °C by 2100. Model simulations based on scenarios that would reduce emissions significantly and continuously through the end of the century (RCP2).

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Answer:

The answer is

Plant also use cellular respiration

Answer:

B - Plants also use cellular respiration.

Explanation:

Did the test.

Meniscus. The graduated cylinder is calibrated so that, when viewed at eye level, reading the bottom of the meniscus will produce precise readings.

A popular piece of scientific equipment used to measure the volume of a liquid is a graduated cylinder, sometimes referred to as a measuring cylinder or mixing cylinder. Its form is slender and cylindrical. The measured amount of liquid is shown by each marked line on the graduated cylinder.

An item of laboratory equipment known as a measuring cylinder, graduated cylinder, cylinder measurement, or mixing cylinder is used to measure the number of liquids, chemicals, or solutions during routine lab work. Compared to standard laboratory flasks and beakers, graduated cylinders are more exact and accurate.

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The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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The value of the equilibrium constant shows the relative amounts or concentrations of the reactants and products.