Your dad is designing a new garden for your backyard. He has 20 feet of fencing to go around the garden. He wants the length of the garden to be 2 1/2 feet longer than the width. How long should he make the garden?

Given: The limit below

To Determine: The limit and the vertical asymptotes

Solution

For the vertical asymptote

The denominator of the rational function given is

Hence:

limit = - ∞

Vertical asymptote: x = 7

Answer:

Step-by-step explanation:

Answer: All three sides are congruent

The problem is with A. It's true as well. At least 2 of the sides are congruent. The way to eliminate it is to say that does not mean specifically that all three sides are congruent.

I would argue that this is a faulty question, and watch someone squirm as they try to explain to you why a is not the answer. I don't know how to comply with your request. How are the choices designated

A

B

C

or

1  

2

3

Answer:

C. All three sides are congruent.

Step-by-step explanation:

Answer:

ill suck ya wang

Step-by-step explanation:5$ and ill suck yo wang to do your homework

Answer:

It is C.

Step-by-step explanation:

If you multiply 2 times 2 you get 4. Then multiply 4 by 5 and you get 20.

Therefore, it is C.

Answer:

x if -3is less than x is less than -1

5 is -1 is less than x is less than 1

Step-by-step explanation:

You find the slope of the line for the first piece when the x-values range from -3 to -1.

For the second piece, the line is y=5 because the line is horizontal.

Answer:

x+3; 5

Step-by-step explanation:

The first piece, shows the diagonal part in Quadrant II.

The line segment is colinear with the line y=x+3, because the slope is 1, and the y-intercept is 3. So the piece would be defined as x+3.

The second line segment is the flat one, which has a slope of 0 and its y-intercept is 5. So the piece would be defined as 0x+5 or 5

Answer:

If it lost 20% of the original value per year, it lost $4,400 in value in the first year.

There are 12 months in a year.

4,400 divided by 12 is 366.67 (rounded since this is about money)

So the boat lost $366.67 in value each month for the first year.

Or 1.67% value per month

Answer: 1/3

Explanation: because I'm right

The average value over the given interval can be calculated by using the formula;\(\bar{f}=\frac{1}{b-a}\int_{a}^{b}f(x)dx\)Where a and b are the lower and upper limits of the interval.

Given;\(f(x)=x^2+x-5, [0,10]\)The average value of f(x) over [0,10] can be obtained as follows:

Step 1Calculate the definite integral of f(x) within the interval [0,10].\(\int_{0}^{10}f(x)dx=\int_{0}^{10}(x^2+x-5)dx=\frac{x^3}{3}+\frac{x^2}{2}-5x\Big|_{0}^{10}\)

Substitute the values of upper and lower limits of the interval into the integral expression.\(=\left[\frac{(10)^3}{3}+\frac{(10)^2}{2}-5(10)\right]-\left[\frac{(0)^3}{3}+\frac{(0)^2}{2}-5(0)\right]\)\(=\frac{1000}{3}+50-0= \frac{1150}{3}\)Step 2

Calculate the average value of f(x) by substituting the values into the formula.\(\bar{f}=\frac{1}{b-a}\int_{a}^{b}f(x)dx\)\(=\frac{1}{10-0}\int_{0}^{10}(x^2+x-5)dx=\frac{1}{10}\cdot\frac{1150}{3}\)\(=\frac{115}{3}\text{ or }38\frac{1}{3}\)

Therefore, the average value of f(x) over the interval [0,10] is \(\frac{115}{3}\) or \(38\frac{1}{3}\). The answer requires 250 words which have been used up in the working.

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Answer:

It looks like the Bears have the higher wins, as they won 40 games while the Bulls won only 32 games.

Answer:

Image result for kumon level C

This award is presented to a student who has completed Level C10 or higher during or before their 1st-grade year. Math Level C covers multiplication and division.

Step-by-step explanation:

Answer:

280 ≥ 20 + 40x

Step-by-step explanation:

$280 is the total they can spend. and since parking is $20 it is added to the amount of people that can go x 40. This is because 40 is the amount per person.

pls mark brainliest

Based on the given dataset and information that the last digit of the CUNY ID is 5, the following steps are taken to analyze the data. The OLS estimates of coefficients B and β are calculated, and the predicted values of Y for each observation are determined. Residuals are calculated, along with the explained sum of squares (ESS), total sum of squares (TSS), and residual sum of squares (RSS). The coefficient of determination (R²) is calculated to assess the goodness of fit. Finally, the predicted value of Y is determined when X is equal to the last digit of the CUNY ID + 1.

a) To regress Y on X, we use ordinary least squares (OLS) estimation. The OLS estimates of coefficients B and β represent the intercept and slope, respectively, of the regression line. The coefficients are determined by minimizing the sum of squared residuals.

b) The predicted value of Y for each observation is obtained by plugging the corresponding X values into the regression equation. In this case, since the last digit of the CUNY ID is 5, the predicted value of Y would be calculated for X = 5.

c) Residuals are the differences between the observed Y values and the predicted Y values obtained from the regression equation. To calculate the residual for each observation, we subtract the predicted Y value from the corresponding observed Y value.

d) The explained sum of squares (ESS) measures the variability in Y explained by the regression model, which is calculated as the sum of squared differences between the predicted Y values and the mean of Y. The total sum of squares (TSS) represents the total variability in Y, calculated as the sum of squared differences between the observed Y values and the mean of Y. The residual sum of squares (RSS) captures the unexplained variability in Y, calculated as the sum of squared residuals.

e) The coefficient of determination, denoted as R², is a measure of the proportion of variability in Y that can be explained by the regression model. It is calculated as the ratio of the explained sum of squares (ESS) to the total sum of squares (TSS).

f) To predict the value of Y when X equals the last digit of the CUNY ID + 1, we can substitute this value into the regression equation and calculate the corresponding predicted Y value.

g) The coefficient B represents the intercept of the regression line, indicating the expected value of Y when X is equal to zero. The coefficient β represents the slope of the regression line, indicating the change in Y associated with a one-unit increase in X. The interpretation of β depends on the context of the data and the units in which X and Y are measured.

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Answer:

Refer to the attachment..

(a) The greatest common divisor of \(x^3\) - 6x - 7 and \(x^4\) is 1.

(b) The greatest common divisor of \(x^2\)- 1 and 2\(x^7\) - 4x\(^5\) + 2 is 1.

(a) To find the greatest common divisor (GCD) of the polynomials, we can use polynomial long division.

Dividing \(x^3\) - 6x - 7 by \(x^4\), we get a remainder of \(x^3\) - 6x - 7.

Since the remainder is non-zero, the GCD of \(x^3\) - 6x - 7 and \(x^4\) is 1.

(b) To find the GCD of \(x^2\) - 1 and 2\(x^7\) - 4\(x^5\) + 2, we can again use polynomial long division.

Dividing 2\(x^7\) - 4\(x^5\) + 2 by \(x^2\) - 1, we get a remainder of 2\(x^5\) + 2.

Since the remainder is non-zero, the GCD of \(x^2\) - 1 and 2\(x^7\) - 4\(x^5\) + 2 is 1.

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The number of postage stamps in John’s collection is 27.

We have given that,

John, Johan, and Jonathan collect postage stamps. Johan and Jonathan have the same number of stamps.

The elimination method is the process of eliminating one of the variables in the system of linear equations using the addition or subtraction methods in conjunction with the multiplication or division of coefficients of the variables.

Johan and Jonathan have the same number of stamps.

Let x be the Johan and Jonathan postal stamps.

Let y be the John postal stamps.

Two times Johan’s collection is eleven less than five times John’s collection.

2x = 5y - 11............(1)

Three times Jonathan’s collection is three less than seven times John’s collection.

3x = 7y - 3............(2)

Multiply equation 1 with 3

3(2x = 5y - 11)

⇒ 6x = 15y - 33.........(3)

Multiply equation 2 with 2

2(3x = 7y - 3)

⇒ 6x = 14y - 6.............(4)

Subtract equation 4 from equation 3

⇒ 6x - 6x = 15y - 33 - (14y - 6)

⇒ 0 = y - 27

⇒ y = 27

Hence, the number of postage stamps in John’s collection is 27.

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The sample size, n is 9 and the sample mean, m is 41.33.

The exam has possible points and the scores for the students in the third classroom are as follows: 30 48 44 32 44 44 32 48 50.

We are asked to determine the sample size(n) and sample mean(m).

Sample size refers to the number of observations included in a study. In this question, the number of observations is equal to the number of scores in the third classroom. Hence, the sample size(n) is equal to n.

Now, the formula of the sample mean(m) is given as  

                m = Sum of all observations/Total Number of observations

          m =  30 + 48 + 44 + 32 + 44 + 44 + 32 + 48 + 50/9

          m = 372/9

          m = 41.33

Hence, the sample mean(m) of the scores for the students in the third classroom is 41.33.

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Answer:

Below

Step-by-step explanation:

Set up a ratio:

7 is to 9   as  8 is to ?

7/9 = 8/?

? = 8 * 9/7 = 72/7  = 10  2/7

Answer: B. -2a^2 + 3a -6

Step-by-step explanation: Hope this helps!

Answer:

If A is the distance from the center of the dilation to a vertex of the pre-image, and B is the distance from the center of the dilation to the corresponding vertex on the image, then B/A is the scale factor of the dilation.

Step-by-step explanation:

The rule about the distance from the center of dilation to the vertices of the pre-image and image is \((x,y) \to (kx,ky)\)

Dilation involves changing the size of a shape.

Assume the image is shape B, and the pre-image is shape A

The scale factor would be to divide the side length of the image, by the corresponding side length of the pre-image

So, the scale factor (k) is:

\(k = \frac BA\)

Hence, the rule of dilation is:

\((x,y) \to (kx,ky)\)

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Answer:

11

Step-by-step explanation:

u do 4x5 which is 20

This system of equations has been placed in a matrix:

y = 650x + 175

y = 25,080 - 120x

The option is ( 32.34, 21,196)

A system of equations, also called a set of simultaneous equations or a system of equations in mathematics, is a finite set of equations for which we have found a general solution. Systems of equations can be classified in the same way as individual equations. Systems of equations are applied in our daily life in modeling problems where unknown quantities can be expressed as variables.

Solving a system of equations means finding the values ​​of the variables used in the system. Calculates the value of an unknown variable while balancing both equations. The main reason for solving a system of equations is to find the values ​​of the variables that satisfy the conditions of all given equations. This system of equations can have different types of solutions.

1. unique solution

2. no solution

3. infinite set of solutions

Now,

We can solve the given system by making the equations equal because

y = y .

The equations are y = 650x + 175 and y= 25,080 - 120x, which forms

   650x + 175 = 25,080 - 120x

⇒ 650x +120x = 25080- 175

⇒ 770x = 24905

⇒ x = 24905 / 770

⇒ x = 32.344

≈ 32.34

Using this value, we find the other one.

   y = 650x + 175

⇒ y = 650 × 32.34 + 175

⇒ y = 21021 + 175

⇒ y = 21196

Therefore, the solution of the system is (32.34 , 21,196).

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Answer:

5 x^2  + 2y^2  + 12x + 5y

Step-by-step explanation:

6x + 2y +y^2 + 6x + 2y + y^2 + 4x^2 + x^2 + y

12x +y^2 + 4y + y^2 + 4x^2 + x^2 + y

12x + 2y^2 + 4x^2 + x^2 + 5y

2y^2 + 5x^2 + 12x + 5y

5 x^2  + 2y^2  + 12x + 5y

Answer:

B 3/32

Step-by-step explanation:

3/8 divided by 4

do the keep change flip method and solve

3/8 x 1/4

The value of the integral (9x + 9y) da over the region r is approximately 14.0625.

To evaluate the given integral using a transformation, we can use the concept of a double integral over a region in the xy-plane.

First, let's define the transformation T from the uv-plane to the xy-plane, where x = 9u and y = 9v. This transformation scales the coordinates by a factor of 9.

Next, let's find the Jacobian determinant of the transformation. The Jacobian determinant of T is given by the absolute value of the determinant of the matrix of partial derivatives of x and y with respect to u and v. In this case, the matrix is:

J(T) = |[∂x/∂u  ∂x/∂v]|
           |[∂y/∂u  ∂y/∂v]|

Taking the partial derivatives, we have:

∂x/∂u = 9   and   ∂x/∂v = 0
∂y/∂u = 0   and   ∂y/∂v = 9

Therefore, the Jacobian determinant is:

J(T) = |[9  0]|
           |[0  9]|

Taking the determinant, we have:

J(T) = (9)(9) - (0)(0) = 81

Now, we can evaluate the integral by transforming it into the uv-plane. The integral becomes:

∬(9x + 9y) dA = ∬(9(9u) + 9(9v))(J(T)) dA

Since x = 9u and y = 9v, we can substitute these expressions into the integral:

∬(9(9u) + 9(9v))(J(T)) dA = ∬(81u + 81v)(81) dA

Now, we need to find the limits of integration in the uv-plane. The region r in the xy-plane corresponds to a parallelogram in the uv-plane with vertices (-1/9, 2/9), (1/9, -2/9), (3/9, 0), and (1/9, 4/9).

Using these vertices, we can determine the limits of integration for u and v:

u ranges from -1/9 to 1/9
v ranges from 2/9 to 4/9

Therefore, the integral becomes:

∬(81u + 81v)(81) dA = ∫[u=-1/9 to 1/9] ∫[v=2/9 to 4/9] (81u + 81v)(81) dudv

Now, we can evaluate this double integral:

∫[u=-1/9 to 1/9] ∫[v=2/9 to 4/9] (81u + 81v)(81) dudv = (81)(81) ∫[u=-1/9 to 1/9] ∫[v=2/9 to 4/9] (u + v) dudv

Evaluating the inner integral with respect to u, we have:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + vu [v=2/9 to 4/9] dv

Simplifying further, we get:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (vu)(4/9 - 2/9) dv

Now, we can evaluate the inner integral with respect to v:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (vu)(4/9 - 2/9) dv = (81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (vu)(2/9) dv

Simplifying further, we have:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (2/9)u(2/9) dv

Now, we can evaluate the inner integral with respect to v:

(81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (2/9)u(2/9) dv = (81)(81) ∫[u=-1/9 to 1/9] (1/2)u^2 + (4/81)u^2 du

Combining like terms, we get:

(81)(81) ∫[u=-1/9 to 1/9] (1/2 + 4/81)u^2 du

Simplifying further, we have:

(81)(81) ∫[u=-1/9 to 1/9] (85/162)u^2 du

Now, we can evaluate the integral:

(81)(81) ∫[u=-1/9 to 1/9] (85/162)u^2 du = (81)(81)(85/162) ∫[u=-1/9 to 1/9] u^2 du

Integrating u^2 with respect to u, we get:

(81)(81)(85/162) ∫[u=-1/9 to 1/9] u^2 du = (81)(81)(85/162) [u^3/3] from -1/9 to 1/9

Plugging in the limits of integration, we have:

(81)(81)(85/162) [(1/9)^3/3 - (-1/9)^3/3]

Simplifying further, we get:

(81)(81)(85/162) [(1/729)/3 - (-1/729)/3] = (81)(81)(85/162) [2/729]/3

Now, we can simplify this expression:

(81)(81)(85/162) [2/729]/3 = (81)(81)(85/162) (2/729)(1/3)

Finally, evaluating this expression, we get:

(81)(81)(85/162) (2/729)(1/3) ≈ 14.0625

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Answer:

60, 120, 180, 240, 300, 360

Step-by-step explanation:

a(n)=60n

At n =1

a(1) = 60(1) = 60

At n = 2

a(2) = 60(2) = 120

At n = 3

a(3) = 60(3) = 180

At n = 4

a(4) = 60(4) = 240

At n = 5

a(5) = 60(5) = 300

At n = 6

a(6) = 60(6) = 360

60, 120, 180, 240, 300, 360

answer: area=b18ft×h13ft

Step-by-step explanation:

area=base×height

The correct statement is three fourths raised to the fourteenth power.

The Power rule for exponents: (am)n = am*n. To raise a number with an exponent to a power, multiply the exponent times the power. Negative exponent rule: x–n = 1/xn. Invert the base to change a negative exponent into a positive.

The important laws of exponents are :

Given:

(((3/4)^4 * (3/4)^3)^2

Now,

((3/4)^ ( 4+3))^2

=((3/4)^7)^2

=(3/4) ^(7*2)

=(3/4)^14

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The option are:

nine sixteenths raised to the twenty fourth power

nine sixteenths raised to the fourteenth power

three fourths raised to the twenty fourth power

three fourths raised to the fourteenth power

I'm sorry, but you have not provided any data or information about the car's motion. Without this information, I cannot answer your questions accurately. Please provide more details or context about the car's motion.

I am unable to answer these specific questions without any given data. Please provide the data related to the car's acceleration, and I will be happy to help you with the analysis.

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Answer:

v=12500-2500h

Step-by-step explanation:

Ok so to create this equation all you need to do is look at what information is given. You start with 12500 gallons of water so we know our equation is going to have 12500 in it.

So far our equation would look like this v=12500

The next information we are given is that it is decreasing by 2500 every hour so we know that we are going to be subtracting 2500 based on how many hours have went by so our equation would then look like this.

v=12500-2500h

we can check this by plugging in some numbers to see if it works. So at Zero hours we should still be at 12500

v=12500-2500(0)

v=12500

Ok so we know that it works for zero, but we should check at least one more number. We know that after 3 hours we would of lost 7500 gallons of water so it should equal 12500-7500=5000 gallons. Lets check this in our equation

v=12500-2500(3)

v=12500-7500

v=5000 Gallons

The length of the rectangle is 19 cm.

The formula for the area of a rectangle,

Area = Length x Width

Given that the area is 336 cm squared.

So, we can set up an equation,

⇒ 336 = (w + 5)w

where w represents the width of the rectangle.

Expanding this equation,

⇒ 336 = w² + 5w

Moving all terms to one side:

⇒ w² + 5w - 336 = 0

This is a quadratic equation that we can solve using the quadratic formula,

⇒ w = (-5 ± √(5² - 4(1)(-336))) / (2(1))

⇒ w = (-5 ± 23) / 2

We'll take the positive value,

⇒ w = 14

So, the width of the rectangle is 14 cm.

We also know that the length is 5 cm more than the width,

Therefore,

⇒ l = w + 5

⇒ l = 14 + 5

⇒ l = 19

Therefore, the length of the rectangle is 19 cm.

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