The altimeter is not very accurate and is likely to have an error of at least 10cm due to high variability in measurements. This is confirmed by the z-score calculation, which shows that a 10cm error is far outside the normal range of variation.
We can use the standard normal distribution to calculate the probability of an error of less than 10cm for a single measurement. First, we need to convert the measurement error of 10cm to a z-score by using the formula:
\(z = (x - \mu) / \sigma\)
where x is the measurement error, μ is the mean altitude reading, and σ is the standard deviation.
Substituting the given values, we get:
z = (0.10 - 1.00) / 0.13 = -7.69
Using a standard normal distribution table or calculator, we can find the probability that z is less than -7.69. This probability is essentially zero, which means that it is highly unlikely that the altimeter gives an error of less than 10cm for a single measurement.
In summary, the probability that the altimeter gives an error of less than 10cm for a single measurement is essentially zero.
This is because the mean altitude reading of 1.00 meter and the standard deviation of 13cm indicate a high degree of measurement variability, and the z-score calculation shows that the error of 10cm is far outside the normal range of measurement variation.
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at highway speeds, a particular automobile is capable of an acceleration of 1.6 m/s2. at this rate, how long does it take to accelerate from 80 km/h to 110 km/h?
By using uniform motion, the time taken to accelerate is 5.21 second.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 80 km/h = 80 x 1000/3600 m/s = 22.22 m/s
vt = 110 km/h = 110 x 1000/3600 m/s = 30.56 m/s
a = 1.6 m/s²
By using first equation, we can calculate the time taken
vt = vo + a . t
30.56 = 22.22 + 1.6 . t
1.6t = 8.34
t = 5.21 second
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lithification is a process of:
a. melting igneous rock
b. eliminating spaces between grains
c. forming sedimentary rock
d. causing uplift
Lithification is a process of forming sedimentary rock. The correct option is D.
What do you mean by lithification?The challenging process of lithification converts loose silt grains that have recently been deposited into rock. Once a silt is deposited, lithification may occur immediately or later. Cementation is one of the crucial processes, particularly for sandstones and conglomerates.
What makes lithification significant?Fresh sediment is often a loose substance that has several pores or open holes that are either filled with air or water. Lithification works to fill in the reduced pore space with a mineral deposits substance. Compaction and cementation are the major lithification processes.
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Which of the following, by scientific definition is NOT work? lifting boxes of books, pedaling on your bike, holding a book over your head, pushing a chair across the room
Answer:
holding a book over your head
a deer with a mass of 176 kg is running head-on towards you with a velocity of 19 m/s. you are going north. find the magnitude and direction of the deer's momentum
Momentum = Mass × Velocity
According to this formula,
Momentum of deer = 176 × 19 = 3344 kg•m/s.
Since you are heading north and the deer is running towards you, the direction of the deer' s momentum is north as well.
| 1)
Students investigating chemical reactions conducted the
experiment you see here. An antacid tablet was dropped in to plastic
bag containing 10 ml at 22°C distilled water. The bag was
immediately zipped closed and the chemical reaction proceeded until
completion. Cite evidence to confirm that this was a chemical reaction
A)
A gas was produced.
B)
The tablet disappeared.
C) There was a color change.
D) There was a change in mass.
Evidence that supports the occurrence of a chemical reaction includes the production of gas, the disappearance of a reactant, the formation of a new substance, a color change, or a release of energy. The correct answer is A).
In this experiment, an antacid tablet was dropped into a bag containing water, and the bag was sealed. The fact that a gas was produced during the reaction indicates that a chemical reaction occurred. Gas production is often a sign of a chemical reaction, as it means that new chemical bonds have formed, releasing gas as a byproduct. Therefore, option A is the correct answer.
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what is the total work wfric done on the block by the force of friction as the block moves a distance l up the incline? express the work done by friction in terms of any or all of the variables μ , m , g , θ , l , and f1 .
The work done by friction W = (F1 - mg sin θ) L, W = -μ mg cos θ L.
Use Newton's Second Law to find the force of friction. In these tasks, the X-axis will be parallel to the plane and the Y-axis will be perpendicular to the plane:
Y-Axis
N - =\(w_{y}\)
N = W_{y}
X axis
F1 - fr - Wₓ = 0
fr = F1 - Wₓ
Let's use trigonometry to find the components of the weight
sin θ = Wₓ / W
cos θ = W_{y} / W
Wₓ = W sin θ
W_{y} = W cos θ
We substitute
fr = F1 - W sin θ
Work is defined by
W = F .dx
W = F dx cos θ
Since the friction force is in the negative direction parallel to the plane and the displacement along the plane is positive, the angle is 180° and cos θ = -1
W = -fr x
W = (F1 - mg sin θ) L
Another way to calculate is
fr = μ N
fr = μ W cos θ
the work is
W = -μ mg cos θ L.
Zero work can occur in any of the following situations When a single force is applied but no displacement. There are gaps but the power of the individual is not showing. A single force is applied in a direction perpendicular to the direction of displacement.
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This table shows Wayne’s weight on four different planets.
Planet Wayne’s weight
(pounds)
Mars 53
Neptune 159
Venus 128
Jupiter 333
Arrange the planets in decreasing order of their strength of gravity.
Answer: Jupiter > Neptune > Venus > Mars
Explanation: edmentum
a circular loop of wire of radius 5.00 cm carries a current of 3.00 a. find the magnetic induction at the center of the current loop
Answer: 5+ 3 cm
Explanation:look all
Nearly the entire world uses the metric system for their measurements. The US is 1 of 3 countries that does not use metric. Would you support changing school curriculum to teach the metric system as the primary measurement system in the US? Why or why not?
The answer is yes, I would suggest using the same metric system because in whole world the metric system is same then it will be easy to solve the problems.
What is metric system?The progressions metric system, which had been implemented in France in the 1790s, was the measuring system that was replaced by the metric system. The International System of Units (SI), which was created in the middle of the 20th century with the help of an international standards body, was the historical culmination of the evolution of these systems. The term "metrication" refers to the adoption of the metric system.
The acknowledgement of various principles is the result of the historical development of metric systems. One base unit of measurement can be used to express each of nature's essential dimensions.
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Accounts for about 70% of the mass-energy content of the universe. It acts in opposition to gravity.
a
pressure eventually become, causing nuclear fusion
b
objects shift toward red on the spectrum & objects are moving away
c
Spiral galaxies appear to be a rotating disk of stars and dust
Why are the electric lines never hung tightly to the poles?
The reason is to minimize the tension in the wire. The wires expand when exposed to intense heat from sun and contract during cold weather. Stretching the wire and connecting to the poles will make the wires loosen up and tear easily.
#hope it helps ^_^
mark me as brainliest please
Which simple machines are used in the tool or device?
The simple machines that are used in the tool or device include all of the following:
Wheel and axle to wheel carry-on luggage.Lever as a see saw.ScrewPulley in flag poles.Inclined planeWedgeWhat is a simple machine?In Science, a simple machine can be defined as a type of machine that is designed and developed with no moving parts, but can be used to perform a specific work.
Additionally, there are six (6) simple machines and these include the following;
Inclined plane.Screw.Wheel and axle.Lever.Wedge.Pulley.Generally speaking, a simple machine allows for the transformation of energy into work.
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Which of the following is a part of a constitutional republic
Laws are written by a king
People must obey the president.
People vote for representatives.
People cannot affect the government.
a resistive loop sits in a region of uniform magnetic field that increases linearly with time. there is no accumulation of net charge anywhere. a. is the induced current clockwise in the loop or counterclockwise? if there is no induced current, state so explicitly.
The correct answer for a resistive loop sits in a region of uniform magnetic field that increases linearly with time where there is no accumulation of net charge anywhere is that the induced current is counterclockwise in the loop.
According to Faraday's Law of Electromagnetic Induction, a change in the magnetic field within a loop of wire will cause an induced current to flow in the loop. The direction of the induced current is such that it will create a magnetic field that opposes the change in the original magnetic field.
In this case, the magnetic field is increasing linearly with time, which means that the induced current will flow in a direction that creates a magnetic field that opposes this increase. Using the right-hand rule, we can determine that the induced current will flow counterclockwise in the resistive loop.
Therefore, the answer to the question is that the induced current is counter clockwise in the loop.
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is 0.5 a strong correlation?
In most situations, the strong correlation usually ranges between 0.7 to 0.9. So 0.5 is not a strong correlation.
Correlation is an important concept in statics. This helps to associate the relationship between two variables. This is of two types namely positive correlation and negative correlation.
In a positive correlation, the association of two variables occurs in the same way. That is they both decrease or increase. In a negative correlation, the association of one variable occurs oppositely to another variable. That is, when one variable decreases, another variable increases.
This correlation is represented by the symbol r. This r-value range from +1 to -1. So the perfect positive correlation is +1 and the perfect negative correlation is -1.
In, the positive correlation, the values from 0.1 to 0.3 is considered weak or low correlation. The values from 0.4 to 0.6 are considered a moderate correlation and the values from 0.7 to 0.9 are considered a strong correlation.
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a 102-m wide river flows with a uniform speed of 3.2 m/s toward the east. it takes 14 minutes for a boat to cross the river to a point directly north of its departure point on the south bank. what is the speed of the boat relative to the water?
The speed of the boat relative to the water is 9.08 m/s, when the boat takes 14 minutes to cross the river.
We can decompose the velocity of the boat into two components: one parallel to the river, and one perpendicular to it. Let's call the parallel component \(v_p_a_r\) and the perpendicular component \(v_p_e_r_p\):-
\(v_p_a_r = v_b_o_a_t cos\theta\)
\(v_p_e_r_p = v_b_o_a_t sin\theta\)
The boat will travel a distance of 102 m across the river, which will take 14 minutes or 840 seconds. Therefore, the distance traveled parallel to the river will be:
\(d_p_a_r = v_p_a_r * t = v_b_o_a_t cos\theta * 840 s\)
The distance traveled perpendicular to the river will be:
\(d_p_e_r_p = v_p_e_r_p * t = v_b_o_a_t sin\theta * 840 s\)
The boat will end up at a point directly north of its departure point on the south bank, which means that \(d_p_e_r_p = 102 m\). Therefore, we can solve for \(v_b_o_a_t\) as follows:
\(v_b_o_a_t sin\theta * 840 s = 102 m\)
\(v_b_o_a_t sin\theta = 102 m / 840 s\)
\(v_b_o_a_t sin\theta = 0.1214 m/s\)
To solve for \(v_b_o_a_t\):-
\(tan\theta = d_p_a_r / d_p_e_r_p\)
\(tan\theta = (v_p_a_r * t) / (v_p_e_r_p * t)\)
\(tan\theta = v_p_a_r / v_p_e_r_p\\tan\theta = v_b_o_a_t cos\theta / (v_b_o_a_t sin(\theta))\\\)
Reserving the value of \(d_p_e_r_p\) and solving for \(\theta\):-
\(\theta = arctan(v_p_a_r / (102 m / 840 s))\\\theta = arctan(v_b_o_a_t cos(\theta) / 0.1214 m/s)\)
\(v_p_a_r^2 + v_p_e_r_p^2 = v_b_o_a_t^2\\(v_b_o_a_t cos(\theta))^2 + (v_b_o_a_t sin(\theta))^2 = v_b_o_a_t^2\)
\(v_b_o_a_t^2 (cos^2(\theta) + sin^2(\theta)) = v_b_o_a_t^2\\v_b_o_a_t^2 = 102^2 / (cos^2(\theta) + sin^2(\theta))\\v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]}\)
Reserving the value of \(\theta\):-
\(v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]} \\v_b_o_a_t = 9.08 m/s\)
Therefore, the speed of the boat relative to the water is 9.08 m/s.
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L= 1 H and R = 3.9 KQ. V (w) Vi (w) b) Sketch the magnitude of the frequency response function H(w). c) Determine what type of ideal filter is approximated by this circuit. a) Find H (w) = + vi(t) L R + vo(t)
The circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. To find the frequency response function H(w) for the given circuit, we need to determine the transfer function H(w) = V0(w) / Vi(w), where V0(w) is the output voltage and Vi(w) is the input voltage in the frequency domain.
L = 1 H (inductance)
R = 3.9 KΩ (resistance)
The circuit can be represented by the following equation:
H(w) = (jwL + R) / (jwL + R + 1)
To sketch the magnitude of the frequency response function H(w), we need to plot the magnitude |H(w)| as a function of frequency w.
Taking the magnitude of the transfer function, we have:
|H(w)| = |(jwL + R) / (jwL + R + 1)|
Next, let's analyze the type of ideal filter approximated by this circuit. We can examine the transfer function to determine the filter characteristics.
From the transfer function:
H(w) = (jwL + R) / (jwL + R + 1)
As w approaches infinity, the jwL term dominates the transfer function, and the transfer function becomes:
H(w) ≈ jwL / jwL = 1
This indicates that the circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. It allows low-frequency signals to pass through relatively unattenuated while attenuating high-frequency signals.
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Why can chemical energy and nuclear energy be considered a potential energy
Answer:
because it is due the Intrecation between sub atomic particles
HELP PLZ HELP !!!!!!!!!!!
Answer:
From least to greatest: Neon, Sodium, Silicon, Iron, Uranium
Explanation:
Here are all the atomic numbers for each one:
Iron = 26
Sodium = 11
Uranium = 92
Neon = 10
Silicon = 14
Hope this helps! :D
How is the density of a fish controlled? how is the density of a submarine controlled?
The density of a fish is controlled by the expansion and contraction of its air sacs while the density of a submarine is controlled by ballast tanks. It was emphasized earlier that buoyant forces does not equal an objects weight but does equal the weight of displaced water.
What are mass, density, and volume ?The three most fundamental characteristics of an object are mass, volume, and density. Volume indicates something's size, mass indicates how heavy it is, and density is calculated as mass divided by volume. Although you deal with mass and volume on a daily basis, the concept of density is less clear-cut and requires careful consideration.
Mass divided by density equals volume; and. Volume times density equals mass. A liquid's density is a gauge of how heavy it is relative to the amount being measured. The liquid that weighs heavier is more dense if you weigh two liquids with similar volumes or amounts.
The relationship between a substance's mass and the amount of space it occupies is known as its density (volume). The density of a substance is determined by the mass, size, and arrangement of its atoms.
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please help me out i'm so depressed and such a failure
how does the brightness of the lamp (L) vary if we dispalce the cursor (C) of the rheostat
a)Towards A
b) Towards B
Answer:
b mate im pretty sure ig :)
What is the force between a 3 C charge and a 4 C charge separated by a distance of 2 meter
Answer:
\(fr = \frac{9 \times 10 {}^{9} \times 3 \times 4}{2 {}^{2} } \\ fr = 27 \times 10 {}^{9} n\)
Come on! Please answer... :( WILL GIVE BRAINLYEST TO BEST ANSWER!!! PLEASE PLEASE PLEASE PLEASE ANSWER!!!
How do the potential and kinetic energy of the cart change at each point in the diagram?
Answer:
Potential -> Kinetic -> Potential ->
Explanation:
Point A is potential becuase it's stopped (its energy isn't released). Point B is where that potential energy is released and turned into Kinetic energy. And point C is where potential energy is stored again. Same with point D.
A hill that has a 31.7% grade is one that rises 31.7 m vertically for every 100.0 m of distance in the horizontal direction. At what angle is such a hill inclined above the horizontal
The grade is also the tangent of the angle above horizontal.
The angle whose tangent is 0.317 is called the "arctangent" of 0.317
It's 17.6 degrees.
8
A tennis ball machine fires a ball vertically upwards at time
t=0 at 19.6 m/s. Assume that air resistance is negligible and
take g =9.8 m/s
a) Calculate the displacement and velocity of the ball at
t=1.0 s, 2.0 s, 3.0 s and 4.0 s.
b) Use your answers to part a) to draw
i) a graph of displacement against time for the ball
ii) a graph of velocity against time for the ball.
Answer:
table and graph are attached
Explanation:
a) The velocity of the ball will be ...
v(t) = v0 -at
v(t) = 19.6 -9.8t
The position of the ball will be the integral of this:
h(t) = ∫v(t)·dt = 19.6t -(1/2)(9.8t^2)
The attached table calculates the vertical position in meters for the required times.
__
b) Graphs of displacement (h(t)) and velocity (h'(t)) are shown in the attachment.
a car drives at a constant acceleration of 7 m/s^2 from rest until it reaches a speed of 54 m/s. how much time did it take to reach this speed and how far did the car go during this time?
The car traveled approximately 1466.48 meters during the time it took to reach a speed of 54 m/s.
To find the time it took for the car to reach a speed of 54 m/s, we can use the formula:
v = u + at
where:
v = final velocity (54 m/s)
u = initial velocity (0 m/s, since the car starts from rest)
a = acceleration (7 m/s^2)
t = time taken
Rearranging the formula, we get:
t = (v - u) / a
Plugging in the values, we get:
t = (54 - 0) / 7 = 7.71 seconds (rounded to two decimal places)
Therefore, it took the car 7.71 seconds to reach a speed of 54 m/s.
To find how far the car traveled during this time, we can use the formula:
s = ut + (1/2)at^2
where:
s = distance traveled
u = initial velocity (0 m/s)
a = acceleration (7 m/s^2)
t = time taken (7.71 seconds)
Plugging in the values, we get:
s = (0 x 7.71) + (1/2)(7 x 7.71^2) = 1466.48 meters (rounded to two decimal places)
Therefore, the car traveled approximately 1466.48 meters during the time it took to reach a speed of 54 m/s.
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.The relation f ~ T tells us that high temperature sources emit electromagnetic waves of _________.
A. low frequency
B. long wavelengths
C. high frequency
D. high penetrating power
A 4.7-kg steel ball is dropped from a height of 21m into a box of sand and sinks 0.20m into the sand before stopping.A. How much energy is dissipated through the interaction with the sand?
The energy that is dissipated through the interaction with the sand is 17 Joules.
To determine the amount of energy dissipated through the interaction with the sand, we need to first calculate the initial potential energy of the steel ball before it was dropped.
This potential energy will then be compared to the final potential energy of the ball after it has sunk into the sand.
The initial potential energy of the steel ball is given by:
\(PE_i_n_i_t_i_a_l\) = mgh
where m = 4.7 kg (mass of the steel ball)
h = 21 m (height from which the ball was dropped)
g = 9.81 m/s^2 (acceleration due to gravity)
\(PE_i_n_i_t_i_a_l\) = (4.7 kg)(9.81 m/s^2)(21 m) = 964.8 J
The final potential energy of the ball is given by:
\(PE_f_i_n_a_l\) = mgh'
where h' = 21 m - 0.20 m = 20.8 m (height to which the ball has risen after sinking into the sand)
\(PE_f_i_n_a_l\) = (4.7 kg)(9.81 m/s^2)(20.8 m) = 947.8 J
The difference between the initial and final potential energies represents the amount of energy that was dissipated through the interaction with the sand:
Energy dissipated = \(PE_i_n_i_t_i_a_l\) - \(PE_f_i_n_a_l\)
= 964.8 J - 947.8 J
= 17 J
Therefore, approximately 17 Joules of energy were dissipated through the interaction with the sand.
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21. When air is blown into a balloon, it expands equally in all directions. The best explanation for this is (circle the correct answer): A - The gas molecules in the balloon are expanding B - Internal air pressure acts at right angles to the balloon surface. C - As more air is blown in, the temperature increases causing the balloon to expand.
Answer:
C
Explanation:
I would have said B but air pressure acts at ALL angles(directions). C makes sense because the increase in the temperature would cause the molecules to bounce off the walls of the balloon and each other which exerts pressure.
Answer:
C c hagwguawnjaahwbhanwbhsqn2nusbwvwf
HELP PLS RIGHT ANSWER GETS BRAINLIEST!!!!
Answer:
♧ Write the correct abbreviation for each metric unit.
kgmgmLmm Lkmcmmg♧ Try these conversions, using the ladder method.
2 g104000 m4.8 m5600 g0.8 cm5000 mL0.198 kg0.075 L0.5 m560 cm160 mm2.5 km65000 mg63 mm0.12 g♧ Compare using <, >, or =.
16. <
17. >
18. =
19. =
20. <
21. >