A ball is launched horizontally at 150 m/s from a cliff.
The vertical velocity of the ball changes during the projectile motion.
On the other hand, the horizontal velocity of the ball is constant and remains the same until the ball hits the ground.
This means that the horizontal velocity of the ball is still 150 m/s after 5 seconds.
Therefore, 150 m/s is the correct answer.
Which of the following quantitative research methods should a researcher use when trying to understand the political views held by the young population of a specific area? a.) Participant observation b.) Written surveys c.) Secondary data analysis d.) Laboratory experiments
Answer:
Options B
Explanation:
The appropriate quantitative research method for understanding political views held by the young population of a specific area is written surveys (option b). Surveys allow for the collection of data from a large number of participants, and specific questions can be asked to gather data on political views.
Participant observation (option a) involves direct observation of individuals in a natural setting, which may not be practical for studying political views.
Secondary data analysis (option c) involves analyzing data that has already been collected, and may not be specific to the young population or the area of interest.
Laboratory experiments (option d) are typically used to study cause-and-effect relationships between variables, which may not be applicable to studying political views.
Therefore, the best option for understanding the political views held by the young population of a specific area is written surveys.
To understand the political views of the young population of a specific area, a researcher can use written surveys, participant observation, and secondary data analysis as quantitative research methods.
Explanation:If a researcher is trying to understand the political views held by the young population of a specific area, they should use written surveys, participant observation, and secondary data analysis as quantitative research methods.
Written surveys: This method involves distributing survey questionnaires to gather data on political opinions from a sample of the young population in the area. Participant observation: This method involves the researcher immersing themselves in the community and directly observing and interacting with individuals to understand their political views.Secondary data analysis: This method involves analyzing existing data sources, such as census records or previous surveys, to gain insights into the political views of the young population in the area.Learn more about Quantitative Research Methods here:https://brainly.com/question/33505242
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I have a material thats 65 cubic feet totaling 40000 cubic yards. How many dump trucks will it take to haul this material?
It will take about 2,500 dump trucks to haul the material. Assuming the capacity of the dump truck is 16 cubic yards.
Note: A standard dump truck is between 10 -16 cubic yards.
1 cubic yard = 27 cubic feet.
from the question:
40,000 cubic yards= 65 cubic feet
hence,
Assuming the dump truck capacity is 16 cubic yards
Then,
number of dump trucks = 40,000 cubic yards/16 cubic yards
=2,500
Therefore a dump truck of 16 cubic yards capacity, will need about 2,500 dump trucks to haul the material totaling 40,000 cubic yards.
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1. An MR-2 starts from rest and accelerates westward to a speed of 27 m/s in
11.8 seconds.
a) What is its acceleration?
b) What is the displacement it covered?
Answer:
a) 2.28 m/s²
b) 159.86 m
Explanation:
Part A:
u = 0 m/s
v = 27 m/s
t = 11.8 seconds
a = ?
Formula:
v = u + at
=> 27 = 0 + a(11.8)
=> 27 = a(11.8)
=> a(11.8) = 27
=> a = 27/11.8
=> a = 2.28 m/s²
Part B:
s = ?
Formula:
s = (v² - u²)/2a
s = (27² - 0²) /2(2.28)
= 729/4.56
= 159.86 m
Which of these expressions yields the speed of sound in air in SI units if the air temperature is 163 degrees Celsius? [Describe the properties of sound waves] 331.5 divided by 0.607 times 163 331.5 + 0.607 times 163 331.5 times 0.607 times 163
Given:
the temperature of the air is
\(T=163\text{ C}\)Required: velocity of the wave in air
Explanation: At normal atmospheric pressure, the temperature dependence of the speed of wave is given by
\(v=331\text{ m/s +0.6 m/s}\times T\)Plugging the value of T in above relation we get
\(v=331\text{ m/s+ 0.6 m/s}\times163\text{ }\)Thus, the speed of the wave is
\(331\text{ m/s+ 0.607 times 163}\)An object is placed at the position x1 = 73 cm and a second mass that is 4/3 times as large is placed at x2 = 247 cm. Find the location of the center of mass of the system.
If An object is placed at the position x1 = 73 cm and a second mass that is 4/3 times as large is placed at x2 = 247 cm, the location is at 172.44cm
How to find the locationThe location of he center of the mass of the object would be
73 cm + (4/3 * 247) / 1 + 4/3
= 73 CM + 329.3 / 2.333
= 402.3 /2.33
= 172.44 CM
Hence we can conclude that the location is at If An object is placed at the position x1 = 73 cm and a second mass that is 4/3 times as large is placed at x2 = 247 cm, the location is at 172.44cm
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10. As a spaceship is moving toward Earth, an Earthling measures its length to be 325 m, while the captain on board radios that her spaceship's length is 1150 m. (c = 3.00 × 108 m/s) (a) How fast is the rocket moving relative to Earth? (b) What is the TOTAL energy of a 75.0-kg crewman as measured by (i) the captain in the rocket and (ii) the Earthling?
Answer:
Explanation:
10. As a spaceship is moving toward Earth, an Earthling measures its length to be 325 m, while the captain on board radios that her spaceship's length is 1150 m. (c = 3.00 × 108 m/s) (a) How fast is the rocket moving relative to Earth? (b) What is the TOTAL energy of a 75.0-kg crewman as measured by (i) the captain in the rocket and (ii) the Earthling?
A 17-kg
piece of metal displaces 2.8 L
of water when submerged. what is its density?
Answer: Density = 6071.428571 kg/m³
Explanation: Given that mass m=17 kg
volume displaced v=2.8L
We know that
density = mass/volume
Here density=17kg/2.8L
Also 1L=1000m³ Hence
density=17kg/2.8×10⁻³m³
=6071.428571 kg/m³
In the 4.6 billion year history of the Earth, how many times have continents of our planet gone through major shifts if these shifts happen on average every 395 million years?
Continents have undergone major shifts around 12 times.
To calculate the number of times continents have gone through major shifts in the 4.6 billion year history of the Earth, we can divide the total time span by the average duration between shifts.
Total time span = 4.6 billion years
Average duration between shifts = 395 million years
To convert the total time span to years, we multiply 4.6 billion by 1 billion (1 billion = 1,000 million).
Total time span in years = 4.6 billion years × 1 billion = 4.6 × 10^9 years
Now we can calculate the number of shifts by dividing the total time span by the average duration between shifts:
Number of shifts = Total time span / Average duration between shifts
= (4.6 × 10^9 years) / (395 million years)
≈ 11.65
Therefore, continents of our planet have gone through major shifts approximately 11.65 times in the 4.6 billion year history of the Earth. Since we cannot have a fraction of a shift, we can round the result to the nearest whole number. Thus, continents have undergone major shifts around 12 times.
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The sound from a clarinet at a distance of 5 m from a sound level meter is found to be 52 dB. If
the frequency is 1000 Hz, find (a) the sound loudness level in phons, (b) the sound intensity in
watts/meter2, and (c) the power of the source in watts.
There are 90 phones of volume, 10-7 W/m2 of sound intensity, and 0.0314 watts of source power.
Which frequency is the simplest?A straightforward frequency analysis compares the values of the fields you provide and generates a report listing each value for those fields along with the frequency at which each value occurs.
How often does sound occur?The rate at which a sound power wave repeats itself, also known as frequency or pitch, is measured in cycles per second. Bullfrog calls and cricket chirps have lower frequencies than drum beats and whistles, respectively.
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A 4kg mass is placed on an inclined plane. A 5 N, a 4 N and a second 5 N force each act on the mass, as shown on the free body diagram below. There are no other forces acting.
Answer: A
Explanation:
What is acceleration
\({\tt{\red{\underline{\underline{\huge{Answer:}}}}}}\)
\(\longrightarrow\) The rate of change of velocity per unit time is called acceleration.
\(\longrightarrow\) Its SI unit is m/s².
\(\huge\boxed{\fcolorbox{blue}{red}{Thank you}} \)
Alois is an astronomer. He is trying to find evidence that a galaxy has a supermassive black hole at its center. What should he look for?.
Scientists can search for numerous signs of a supermassive black hole at the heart of a galaxy. Here are a few of the typical techniques astronomers employ to research supermassive black holes:
What is the supermassive black hole?The gravitational pull of it revealed it to be dense and unmoving. There is a supermassive black hole in the centre of the Milky Way, and this was the first proof of it.
Astronomers can monitor the motion of stars close to a galaxy's centre. Supermassive black holes are most likely located at the core of an invisible entity that has a very strong gravitational attraction and the stars are orbiting it.
A supermassive black hole's gravitational pull can cause it to bend the path of light around it if it is situated between Earth and a faraway light source.
This phenomenon is known as gravitational lensing. Astronomers may see this “lensing” phenomenon and utilize it to investigate the black hole.
Therefore, Astronomers may create a thorough picture of the characteristics of a supermassive black hole at the heart of a galaxy by examining these and other observational data.
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An electron moves in the positive x-direction a distance of 2.39 m in 2.89⋅10-8 s, bounces off a moving proton, and then moves in the opposite direction a distance of 1.65 m in 3.37⋅10-8 s.
a) What is the average velocity of the electron over the entire time interval?
b) What is the average speed of the electron over the entire time interval?
The average velocity of the electron over the entire time interval is 1.182 x 10⁷ m/s.
The average speed of the electron over the entire time interval is 6.454 x 10⁷ m/s.
What is average velocity?
The average velocity of an object is the change in the displacement of the object with time.
average velocity = total displacement / total time of motion
average velocity = (final position - initial position)/total time
average velocity = (2.39 m - 1.65)/(2.89 x 10⁻⁸ + 3.37 x 10⁻⁸)
average velocity = 1.182 x 10⁷ m/s
What is average speed?The average speed of an object is ratio of total distance to total time of motion of the object.
average speed = (2.39 m + 1.65 m)/(2.89 x 10⁻⁸ + 3.37 x 10⁻⁸)
average speed = 6.454 x 10⁷ m/s
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How are magnetic fields like vectors?
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
While car A has stopped, car B passes that with velocity 50 m/s. If after 5 seconds car A start to move with constant acceleration 8 m/s^2 and car B continues to move with constant velocity. How many meters from passing point car A will catch car B.
The distance travelled by car A before catching car B is 363.3 m.
What is the distance travelled by car AThe distance travelled by car A is the total path covered by car A before catching up with car B.
The distance between car A and car B is calculated by applying the principle of relative velocity as follows;
(Va - Vb)t = d
where;
Va is the velocity of car AVb is the velocity of car Bt is the time of motiond is the distance between them when car A start movingVa = acceleration x time
Va = 8t
distance between car A and car B when car A start moving = 50 m/s x 5 s = 250 m
The time taken for car A to catch car B is calculated as;
(Va - Vb)t = d
(8t - 50)t = 250
8t² - 50t = 250
8t² - 50t - 250 = 0
solve the quadratic equation using formula method;
a = 8, b = -50, c = -250
t = 9.53 seconds
The distance travelled by car A before catching car B is calculated as;
s = vt + ¹/₂at²
where;
v is the initial velocity of car A = 0t is the time of motion = 9.53 sa is the acceleration of car A = 8 m/s²s = ¹/₂(8)(9.53²)
s = 363.3 m
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which one defines force?
Answer:
a
Explanation:
a push or a pull that occurs when an object interacts with another object or field.
pls mrk me brainliest
What does meaningful learning require the learner to do? 1.Relate new knowledge to what is already known 2.Use rote learning strategies to memorize facts 3.Eliminate prior schema 4.Teach others
Answer: I think the answer is A Relate new Knowledge
Explanation:
It kinda just makes sense.
Answer:
A. Relate new knowledge to what is already known
Explanation:
I took the test
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of 0.110 N when their center-to-center separation is 57.3 cm. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres repel each other with an electrostatic force of 0.0489 N. Of the initial charges on the spheres, with a positive net charge, what was (a) the negative charge on one of them and (b) the positive charge on the other
Answer:
q₂ = ± 1.306 10⁻⁶ C
q₂ = ± 3.073 10⁻⁶ C
Explanation:
We must solve this exercise using Coulomb's law, let's write the equilibrium equation for each case
first case
F₁ = k q₁ q₂ / r² (1)
where F1 is the force on sphere 1, with a value of F₁ = 0.110 N; r is the distance between them r = 0.573 m
second case.
The spheres were joined with a conductive wire, so the charge of the two is equal, then the wire is removed and
-F₂ = k q₃ q₃ / r² (2)
In this case the force is expelling and is equal to F₂ = 0.0489 N
when the spheres are joined with the wire the charge of the spheres is distributed evenly between them two
q₁ + q₂ = 2 q₃ (3)
we can see that there are three equations with three unknowns for which the system can be solved
let's substitute equation 3 in 2
- F₂ = k (q₁ + q₂)² / r²
we join this equation with equation 1
F₁ = k q₁ q₂ / r²
-F₂ = k (q₁ + q₂)²/4r²
q₁ = F₁ r² / k q₂
- F₂ = k (F₁ r² / k q₂ + q₂)²/4r²
Let's replace the values and work out
- 0.0489 = 9 109 (0.110 0.573² / (9 10⁹ q₂) + q₂)² / 0.573²
- 0.0489 4 0.573²/9 10⁹ = (0.110 0.573² / (9 10⁹ q₂) + q₂)²
- 7.1356 10⁻¹² = (4.013 10⁻¹² / q₂ + q₂)²
- 7.1356 10⁻¹² = 1 / q₂² (4.013 10⁻¹² + q₂² )²
- 7.1356 10⁻¹² q₂² = (16.104 10⁻²⁴ + 4.013 10⁻¹² q₂² + q₂⁴
q₂⁴ + q₂² (4,013 10⁻¹² + 7,1356 10⁻¹²) + 16,104 10⁻²⁴ = 0
we change variables
q’ = q₂²
q'² + q' 11.1486 10⁻¹² + 16.104 10⁻²⁴ = 0
we solve this quadratic equation
q '= [- 11.1486 10⁻¹² ±√ ((11.1486 10⁻¹² )² - 4 16.104 10⁻²⁴)] / 2
q '= [- 11.1486 10 12 ±√ (59.8753 10⁻²⁴)] / 2
q '= [- 11.1486 ± 7.7379] / 2 10⁻¹²
q'1 = -1.70535 10⁻¹²
q'2 = -9.44325 10⁻¹²
q' = q₂²
q₂ = √ q'
q₂ = ± 1.306 10⁻⁶ C
q₂ = ± 3.073 10⁻⁶ C
since q 'is squared of these charges they can be positive or negative giving the same result.
find the decrease in kinetic energy from the collision for the system containing both hockey players .
a 90.0 -kg hockey player moves at 5.0 m/s and collides head-on with a 110-kg player moving at 3.0 m/s in the opposite direction. after the collision, they move off together at 1.0 m/s.
Answer:
c h i c k e n n u g g e t s . . . . . .
jk its 2.6
The levels of organization are Cell, Tissue, Organs, ____________, and Organism. what goes in the blank?
Answer:
Organ system because multiple organs make up an organ system and multiple organ systems make up an organism
In the diagram below, a 5 kg object is moving with a speed of 10 m/s, and a 10 kg object is moving with a speed of 5 m/s.
Which object in the diagram has more kinetic energy?
A. The 5 kg object has more kinetic energy.
B. The 10 kg object has more kinetic energy.
C. Both of the objects have the same amount of kinetic energy.
D. Neither object has any kinetic energy.
Answer:
C.Both objects have the same amount of kinetic energy.
Explanation:
different masses can have the same kinetic energy
Hope it helps
If a 5 kg object is moving with a speed of 10 m/s, and a 10 kg object is moving with a speed of 5 m / s, then the 5 kg object has more kinetic energy, therefore the correct answer is option A.
What is mechanical energy?The sum of all the energy in motion (total kinetic energy) and all the energy that is stored in the system (total potential energy) is known as mechanical energy.
The expression for total kinetic energy can be given as follows
KE = 1/2 mv²
As given in the problem, In the diagram below, a 5 kg object is moving at a speed of 10 m/s, and a 10 kg object is moving at a speed of 5 m/s.
Thus, the 5 kg object has more kinetic energy .
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in a closed system three objects have the following momentum: 11 kg* m/s, -65 kg*m/s and -100 kg m/s. the objects collide and move together. What is the total momentum after the collision? 55 kg*m/s 275 kg * m/s -55kg * m/s -275 kg m/2
Explanation:
The momentum of the three objects are as follow :
11 kg-m/s, -65 kg-m/s and -100 kg-m/s
Before collision, the momentum of the system is :
\(P_i=11+(-65)+(-100)\\\\P_i=-154\ kg-m/s\)
After collison, they move together. It means it is a case of inelastic collision. In this type of collision, the momentum of the system remains conserved.
It would mean that, after collision, momentum of the system is equal to the initial momentum.
Hence, final momentum = -154 kg-m/s.
A 227.1 g sample of water at 12.2°C is heated to steam at 115.6°C. How much heat was absorbed?
??? kcal
According to the given statement the heat absorbed is 43676.78 J .
How do you calculate heat absorbed?The water's specific heat and the formula Q= mcΔT are used to compute the amount of heat absorbed. At 100°C, water vaporizes into steam. Calculating the amount of heat absorbed requires multiplying the number of moles of water by the molar heat of vaporization.
Briefing:Mass, m = 227.1grams
To find how much heat is absorbed when 227.1 grams of steam is heated from 115.6°C to 12.2°C.
Heat absorbed is given by :
Q= mcΔT
c is specific heat of water
Put all the values, we get :
Q = 227.1 * 1.86 * (115.6 - 12.2)
Q = 43676.78 J
43676.78 J heat is absorbed.
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how does increasing energy affect the amplitude of a wave?
Answer:
The amount of energy carried by a wave is related to the amplitude of the wave
Explanation:
A high energy wave is characterized by a high amplitude; a low energy wave is characterized by a low amplitude. The energy imparted to a pulse will only affect the amplitude of that pulse.
Hope this helped!!!
A student slides a 0.45 kg textbook across a table. What will be the kinetic energy of the textbook
if its speed is 0.20 m/s?
Answer:
Below
Explanation:
Kinetic Energy = 1/2 * m * v^2
= 1/2 * .45 * .2^2 = .009 J
Important Formulas:
\(KE=.5mv^2\)
Kinetic Energy(measured in joules) = .5 * mass(measured in kg) * velocity(measured in m/s)^2
__________________________________________________________
Given:
\(m=0.45kg\)
\(v=0.20m/s\)
\(KE=?\)
__________________________________________________________
\(KE=.5mv^2\)
\(KE=.5(0.45)(0.20)^2\)
__________________________________________________________
\(\fbox{KE = 0.009J}\)
research the legend of king arthur. !! HELP ME!!
According to the legend, Arthur was the son of King Uther Pendragon. After Arthur was born, he was given to Merlin. Merlin was a magician and wise man who advised the kings of Britain. Once Uther died, it was said that the next king would be able to pull the sword Excalibur out of a stone.
this is just a summary
A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.
When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e
Answer:
e
Explanation:
An iron railroad rail is 800 ft long when the temperature is 31°C. What is its length (in ft) when the temperature is −17°C?
Answer:
799.54 ft
Explanation:
Linear thermal expansion is:
ΔL = α L₀ ΔT
where ΔL is the change in length,
α is the linear thermal expansion coefficient,
L₀ is the original length,
and ΔT is the change in temperature.
Given:
α = 1.2×10⁻⁵ / °C
L₀ = 800 ft
ΔT = -17°C − 31°C = -48°C
Find: ΔL
ΔL = (1.2×10⁻⁵ / °C) (800 ft) (-48°C)
ΔL = -0.4608
Rounded to two significant figures, the change in length is -0.46 ft.
Therefore, the final length is approximately 800 ft − 0.46 ft = 799.54 ft.
A radioactive isotopes has a life-life of 15 days and an initial
count-rate is 2000 counts per second. Determine the count-rate after
45 days.
Counts/s
The activity is a radioactive material is the number of counts per second it produces. 1 count per second (cps) = 1 Becquerel (Bq).
What is radioactive?As its name implies, radioactivity is the act of emitting radiation spontaneously. This is done by an atomic nucleus that, for some reason, is unstable; it "wants" to give up some energy in order to shift to a more stable configuration. During the first half of the twentieth century, much of modern physics was devoted to exploring why this happens, with the result that nuclear decay was fairly well understood by 1960. Too many neutrons in a nucleus lead it to emit a negative beta particle, which changes one of the neutrons into a proton. Too many protons in a nucleus lead it to emit a positron (positively charged electron), changing a proton into a neutron. Too much energy leads a nucleus to emit a gamma ray, which discards great energy without changing any of the particles in the nucleus. Too much mass leads a nucleus to emit an alpha particle, discarding four heavy particles (two protons and two neutrons).To learn more about neutrons refer to:
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