Answers
Answer:
acceleration = 10 m/s²
Explanation:
The formula for acceleration is:
a = \(\frac{v - u}{t}\)
where v is the final speed, u is the initial speed, and t is the time taken.
In this case, v = 50 m/s, u = 0 m/s (as the car starts from rest), and t = 5s.
Substituting these values into the formula:
a = \(\frac{50 - 0}{5}\)
= \(\frac{50}{5}\)
= 10 m/s²
Related Questions
Makala arrives late to class and misses the first few minutes of the lecture. These are the notes she takes:
-Only applies to very small particles
-subatomic particles
-atoms
-nano-size systems
-Only applies over very short distances
-Causes different behavior than the physics observed in
large objects
What should Makala title her notes?
A: Nanotechnology
B: Quantum Mechanics
C: Microtechnology
D: Newtonian Physics
Answers
Answer:
B. Quantum Mechanics
Explanation:
Quantum mechanics is the foundation of all quantum physics including quantum chemistry, quantum field theory, and quantum information science.
Answer:
B. Quantum Mechanics
Explanation:
Edge 2021
what layer of skin is responsible for touch dermis epidermis top layer capillaries
Answers
Answer: Epidermis
Explanation:
The dermis is held together by a protein called collagen. This layer gives skin flexibility and strength. The dermis also contains pain and touch receptors.
Epidermis is the top layer of the skin that you can see and touch.
Keratin, a protein inside skin cells, makes up the skin cells and, along with other proteins, sticks together to form this layer.
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Answer:
The dermis is held together by a protein called collagen. This layer gives skin flexibility and strength. The dermis also contains pain and touch receptors.
1. A positive electric charge in a region of changing electric potential will: A. move in the direction of decreasing potential B. move in the direction of increasing potential C. move in an undetermined way; we need more information D. remain at rest
Answers
Answer:
The correct option is (B).
Explanation:
The electric potential is the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field. The electric potential due to a point charge is given by :
\(V=\dfrac{kQ}{r}\)
Where
k is the electrostatic constant
Q is the electric charge
r is the distance from the charge
So, a positive electric charge in a region of changing electric potential will move in the direction of increasing potential.
A bicycle slows down uniformly from vi=8.40 [m/s] to rest over a distance of 115 [m]. Each wheel and tire has an overall diameter of 0.68 [m]. Determine the magnitude of the angular acceleration of the wheel. Give your answer in units of radians per second squared.
Answers
A bicycle slows down uniformly from vi=8.40 [m/s] to rest over a distance of 115 [m]. Each wheel and tire has an overall diameter of 0.68 [m]. The magnitude of the angular acceleration of the wheel is approximately 0.0757 rad/s².
To determine the magnitude of the angular acceleration of the wheel, we need to first calculate the change in angular velocity and the time taken to come to rest. Then we can use these values to find the angular acceleration.
Calculate the initial angular velocity:
The initial linear velocity of the bicycle wheel is given by the formula v = ω * r, where v is the linear velocity, ω is the angular velocity, and r is the radius of the wheel.
The radius of the wheel is half the diameter, so r = 0.68 m / 2 = 0.34 m.
Given the initial linear velocity vi = 8.40 m/s, we can calculate the initial angular velocity ωi:
vi = ωi * r
ωi = vi / r
Calculate the final angular velocity:
The final angular velocity of the wheel is 0 rad/s since it comes to rest.
ωf = 0 rad/s
Calculate the change in angular velocity:
The change in angular velocity (Δω) is given by the formula Δω = ωf - ωi.
Δω = 0 - ωi
Calculate the time taken to come to rest:
To calculate the time taken to come to rest, we can use the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given the initial velocity vi = 8.40 m/s, final velocity vf = 0 m/s, and distance d = 115 m, we can calculate the acceleration a:
vf = vi + at
0 = 8.40 + a * t
We also know that the distance traveled d is related to the initial and final velocities and the time by the formula d = (vi + vf) / 2 * t:
d = (vi + vf) / 2 * t
115 = (8.40 + 0) / 2 * t
From the two equations above, we can solve for the acceleration a and the time t.
Calculate the angular acceleration:
The angular acceleration (α) is given by the formula α = Δω / t.
α = Δω / t
Substitute the values for Δω and t and calculate the angular acceleration.
Therefore, the magnitude of the angular acceleration of the wheel is approximately 0.0757 rad/s².
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Numerical Problems
A bus is moving with the initial velocity 10 m/s. After 2 seconds, the velocity
becomes 20 m/s. Find the acceleration and distance moved by the bus.
Answers
Answer:
a = 5 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.
\(v_{f}=v_{o}+a*t\)
where:
Vf = final velocity = 20 [m/s]
Vo = initial velocity = 10 [m/s]
t = time = 2 [s]
a = acceleration [m/s²]
Now replacing:
\(20 =10 +a*2\\10=2*a\\a=5[m/s^{2} ]\)
determine the stresses of the light bar and support wire
Answers
Tbar = Tension of the Light Bar
Twire = Tension of the Wire
Newton First Law About Force :
Fx = 0
Tbar cos 45° - Twire cos 25° = 0
Twire = 0.78 Tbar ... (i)
Fy = 0
Tbar sin 45° - Twire sin 25° - 1 = 0 ... (ii)
Subtitute (i) into (ii) :
Tbar sin 45° - 0.78 Tbar sin 25° - 1 = 0
Tbar = 2.563 kN ... (iii)
Subtitute (iii) into (i) :
Twire = 0.78 (2.563)
Twire = 1.999 kN
A person walking with a stroller at a rate of 1.5 m/s accelerates at a rate of 0.275 m/s2.
What is the velocity (in m/s) of the stroller after is has traveled 6.45 m?
Answers
Answer:
2.41m/s
Explanation:
Given parameters:
Initial velocity = 1.5m/s
Acceleration = 0.275m/s²
Distance = 6.45m
Unknown:
Final velocity = ?
Solution:
To solve this problem, we apply the kinematics equation below:
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
v² = 1.5² + (2 x 0.275 x 6.45)
v = 2.41m/s
a ball is tossed straight upward, in the y direction. at the instant the ball reaches its maximum height, which statement concerning its velocity and acceleration in the y direction is correct? a. both its velocity and acceleration are zero. b. its velocity is zero but its acceleration is positive. c. both is velocity and acceleration are negative. d. both its velocity and acceleration are positive. e. its velocity is zero but its acceleration is negative
Answers
When a ball is thrown straight up in the y direction, its velocity is negative although its acceleration is significant in the y direction, which is the correct result.
What is velocity, exactly?The orientation of movement of a body or object is determined by its velocity. In its purest form, movement is a scale parameter. In essence, velocity is a vector quantity. It is the speed at which distance is changing. It describes the rate at which displacement is changing.
Can zero be the final velocity?People wrongly believe that because a bullet stops when it hits the ground, a simple pendulum's maximum speed is also zero. In physical difficulties, an object's greatest velocity refers to the rate at which it is moving shortly before colliding with the earth.
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A 15.0 nC point charge is 15 m from a second point charge, and the electric force on one of them due to the other is 5.0 N. What is the magnitude of t
Answers
Answer:
t = 125 C
Explanation:
The force on a charge due to other charge is given by Coulomb's Law, as follows:
F = kq₁q₂/r²
where,
F = Electric Force = 5 N
k = Coulomb Constant = 9 x 10⁹ N.m²/C²
q₁ = magnitude of first charge = 15 nC = 1.5 x 10⁻⁸ C
q₂ = Magnitude of 2nd Charge = t = ?
r = distance between charges = 15 m
Therefore,
5 N = (9 x 10⁹ N.m²/C²)(1.5 x 10⁻⁸ C)t/(15 m)²
t = (5 N)/(0.04 N/C)
t = 125 C
A and B start walking in the same direction at the same time around a circular park of diameter 4200 m. If A walks 10 m more than B in every minute with a speed of 5 km per hour, then they meet each other next time after A makes................ rounds. (ii) 8 (i) 7 (iii) 9 (iv) 10...
Answers
Diameter = 4200 m
T = 24700 \(\pi\) time for A to also catch B
N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps
A will create 8 but not 9 rounds before catching B.
What is speed?Speed exists distance travelled per unit time. It exists scalar quantity.
Given: diameter = 4200 m
\(V_a\) = 5000 m / 3600 s = 1.39 m/s
(\(V_a - V_b\)) 60 = 10
\(V_b = V_a\) - 0.167 = 1.22 m/s
(\(V_a - V_b\)) T = 4200 \(\pi\)
where T exists time for A to complete 1 more lap
0.17 T = 4200 \(\pi\)
T = 24700 \(\pi\) time for A to also catch B
N = 1.39 \(*\) 24700
\(V_a\) = 5000 m / 3600 s = 1.39 m/s
(\(V_a - V_b\)) 60 = 10
\(V_b = V_a\) - 0.167 = 1.22 m/s
(\(V_a - V_b\)) T = 4200 \(\pi\)
where T exists time for A to complete 1 more lap
0.17 T = 4200 \(\pi\)
T = 24700 \(\pi\) time for A to also catch B
N = 1.39 \(*\) 24700 \(\pi\) / (4200 \(\pi\)) = 8.2 laps
A will create 8 but not 9 rounds before catching B.
Therefore, the correct answer is option (ii) 8.
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PLEASE HELP!!
Which statement accurately describes a balanced force?
A 2-N force presses down on the marble at the same time as a 1.5-N force presses up on the marble.
A marble rolling downhill suddenly comes to rest at a garden wall.
A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.
A marble resting on the sidewalk suddenly begins to roll downhill without being touched.
Answers
Answer:
A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.
Explanation:
just took test
A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Balanced force is when the net force applied on the object is zero than said to be balanced.
A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.
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The playground design committee wants the playhouse roof to be constructed from plastic. The plastic is available in thicknesses of 0.25 cm and 2 cm. You want to minimize the transfer of heat to the roof on hot Which recommendation would you make to the design and sunny days. committee?
Choose:
A. Choose the 2-cm-thick plastic because it will take longer to get warm on hot and sunny days
B. Choose the 0.25-cm-thick plastic because it will take longer to get warm on hot and sunny days
C. Choose the 2-cm-thick plastic because it will get warm more quickly on hot and sunny days
D. Choose the 0.25-cm-thick plastic because it will get warm more quickly on hot and sunny days
Answers
It should be noted that to minimize the transfer of heat to the roof, the recommendation of design would be : A. Choose the 2-cm-thick plastic because it will take longer to get warm on hot and sunny days.
What is the best recommendation?The 2-cm-thick material is advised if you want to reduce heat transfer to the roof on hot, bright days.
The reason is because they are better insulators and take longer to warm up, thicker materials offer higher thermal resistance. In this situation, the 2-cm-thick plastic would take longer to warm up on hot, sunny days, lowering the amount of heat that is transferred to the roof and assisting in keeping it cooler.
The correct option is A.
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NEED HELP WITH PHYSICS< WILL NAME BRAINLIEST
Answers
Answer:
c
Explanation:
What length should a tube closed at one end have on a day when the air temperature is 0ºC, if its fundamental frequency is to be 96 Hz (C below middle C)?What is the frequency of its sixth over tone
Answers
The frequency of the sixth overtone would be 576 Hz.
To determine the length of a tube closed at one end, we can use the formula:
L = (v/4f) * (2n - 1)
where L is the length of the tube, v is the speed of sound in air, f is the fundamental frequency, and n is the harmonic number.
Given that the fundamental frequency is 96 Hz, we can substitute the values into the formula:
L = (v/4f) * (2n - 1)
L = (v/4*96) * (2*1 - 1)
L = v/384
To find the length at 0ºC, we need to know the speed of sound at that temperature. The speed of sound in air depends on temperature and other factors. At 0ºC, the speed of sound in dry air is approximately 331.4 m/s.
L = 331.4/384
L ≈ 0.862 m
Therefore, the tube closed at one end should have a length of approximately 0.862 meters when the air temperature is 0ºC.
To find the frequency of the sixth overtone, we multiply the fundamental frequency by six: Frequency of sixth overtone = 96 Hz * 6 = 576 Hz.
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To find the mass of a liquid, you put it in a container before you measure it and put it on the scale. After reading the measurement, what is the next step?
idek what this means but whats answer?
Answers
You then out the liquid in the container and measure again.
Subtract the big number minus the small number
That is the mass of the liquid
16 of 20:
Select the best answer for the question.
16. What happens to a substance at critical temperatures?
O A. The substance changes its state if it continues gaining or losing thermal energy.
O B. The substance can't lose any more thermal energy.
O C. The substance can't change its state, only its temperature.
O D. The substance changes its state only if it gains thermal energy.
Answers
At the critical temperatures of the substance, the substance can't lose any more thermal energy. Hence, option B is correct.
At the critical temperature, the properties of the liquid and gas phases become difficult to differentiate, and the substance exhibits particular type of behavior such as infinite compressibility and a lack of surface tension.
Additionally, at the critical temperature, the substance reaches its maximum vapor pressure, and any further increase in temperature and pressure will not cause it to change its state but only its density and hence, it cannot lose any more thermal energy from itself.
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If a river is flowing south at 4 m/s and you swim straight across (i.e. east) at 2 m/s; admittedly, you're going to drift a bit south. That said, calculate that distance that you drifted south from your starting point. The river is 16 m wide.
Answers
We have that the distance that you drifted south from your starting point is
\(\triangle y=32m\)
From the question we are told that
a river is flowing south at 4 m/s
you swim straight across (i.e. east) at 2 m/s; admittedly
The river is 16 m wide
Generally the equation for the change in direction is mathematically given as
\(\triangle x = v_x t\\\\16=2*t\\\\t=8s\)
Therefore
\(\triangle y = v_y t\\\\\triangle y=4*8\\\\\triangle y=32m\)
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A roller-coaster car may be represented by a block of mass 50.0 kg . The car is released from rest at a height h = 45.0 m above the ground and slides along a frictionless track. The car encounters a loop of radius R = 15.0 m at ground level, as shown. As you will learn in the course of this problem, the initial height 45.0 m is great enough so that the car never loses contact with the track.
Part A: Find the kinetic energy K of the car at the top of the loop.
Part B: Find the minimum initial height hmin at which the car can be released that still allows the car to stay in contact with the track at the top of the loop.
Answers
b) For the car to stay just in contact with loop, normal force from loop on car should be zero.
What is force ?A force is an influence that can alter an object's motion in physics. A force can cause an object with mass to accelerate and change its velocity (for example, moving from a state of rest). Force can also be conceptualised as a push or a pull.
A force is a vector quantity since it has both magnitude and direction. It is calculated using newtons as the SI unit of measure (N). F stands for force (formerly P).
The net force acting on an object is equal to the rate at which its momentum changes over time, according to Newton's second law in its original form.
Balancing the forces on the car, centrifugal force = weight + normal force,
mv2/R = mg + 0
v2 = Rg
KE = 1/2*mv2 = 1/2*mRg
PE at the point = mg*(2R)
So, total energy = 1/2*mRg + mg*(2R) = 5/2*mgR
But total energy = mgH where H is inital height of fall.
Thus, mgH = 5/2*mgR
Thus, H = 5/2*R = 5/2*15 = 37.5 m
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Find the radius and the circumference to the nearest hundredth when d ≈ 3.6 in. Use 3.14 for π. Drag and drop the correct number into each box to complete the answers.
The radius is approximately _ inches.
The circumference is approximately _ inches.
Answers
Explanation:
the radius is always half of the diameter.
so, the radius is approximately 3.6/2 = 1.8 in.
and the circumference of a circle is
2×pi×r = d×pi = 3.6×3.14 = 11.304 ≈ 11.3 in.
Bumper car A (296 kg) moving +3.74 m/s makes an
elastic collision with bumper car B (222 kg) moving
+1.85 m/s. What is the velocity of car A after the
collision?
Use the formula to find the final velocity of car A.
Bumper Car A
m₁ = 296 kg
V₁i = 3.74 m/s
m₁ - m²)√₁i+
m1
m2
V₁f = (m
Bumper Car B
m₂ = 222 kg
V2i = 1.85 m/s
(m²
2m²)V₂i = [?] m/s
m₁ + m2
m₁ + m2
Remember: right is +, left is -.
Answers
The speed of car A after the collision is 0.52 m/s.
What is speed?In everyday use and kinematics, the speed of object is the amount of change in position over time, or the amount of change in position per unit time. So it's a scalar quantity.
For a bumper car A
Mass (m₁) = 296 kg
Velocity (V₁) = 3.74 m/s,
For a bumper car B
Mass (m₂) = 222 kg
Velocity (V₂) = 1.85 m/s,
To calculate velocity of car A after the collision mathematically:
Vₙ =(m₁-m₂/m₁+m₂)V₁
Vₙ = Final velocity of car A
Vₙ = (296 - 222/296 + 222) × 3.74
Vₙ = 0.52 m/s
Hence, the velocity of car A after the collision
Vₙ = 0.52 m/s
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A golfer hits the ball across a 40 meter golf course, the ball reaches the other side in 0.30 seconds. What is the average speed that the golfer hit the ball at?
a. 0.0075 m/sec
b. 40 m/sec
c. 0.30 m/sec
d. 133.33 m/sec
Answers
Distance is 40 meters.
Time is 0.30 seconds.
Average speed = 40 m / 0.30 sec = 133.33 m/sec
The answer is D. 133.33 m/sec.
Two 17cm -long thin glass rods uniformly charged to +16nC are placed side by side, 4.0 cm apart. What are the electric field strengths E1, E2, and E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm to the right of the rod on the left, along the line connecting the midpoints of the two rods?
Answers
The required electric field strengths are calculated to be E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.
Length of the two glass rods is given as, L = 17 cm = 0.17 m
Charge on them = 16 nc = 16 × 10⁻⁹ C
Distance between the rods is given as 4 cm = 0.04 m.
Electric charge due to a single glass rod can be given by,
E = Q/ (2π ε₀ r L) ----(1)
(1) can be used to determine E₁, E₂, E₃ because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced.
E₁ = Q/ (2π ε₀ r L) × [1/0.01 - 1/0.03]
⇒ (16 × 10⁻⁹)/(2× 3.14× 8.85 × 10⁻¹² × 0.17) × (66.67)
⇒ (16× 66.67 × 10³)/(9.45) = 112.88 × 10³ N/C
Let us find E₂,
E₂ = Q/ (2π ε₀ r L) × [1/0.02 - 1/0.02] = 0
And E₁ = E₃.
Thus, E₁ = E₃ = 112.88 × 10³ N/C, E₂ = 0.
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A cylindrical 5.00-kg reel with a radius of 0.600 m and a frictionless axle, starts from rest and speeds up uniformly as a 3.00-kg bucket falls into a well, making a light rope unwind from the reel. The bucket starts from rest and falls for 4.00 s.
Required:
a. What is the linear acceleration of the falling bucket?
b. How far does it drop?
c. What is the angular acceleration of the reel?
Answers
Kiran drove from Tortula to Cactus, a distance of 250 mi. She increased her speed by 10 mi/h for the 360-mi trip from Cactus to Dry Junction. If the total trip took 11 h, what was her speed from Tortula to Cactus
Answers
Kiran's average speed from Tortula to Cactus was 58.78 miles per hour.
Let's use "x" miles per hour as Kiran's speed from Tortula to Cactus.
The time it takes Kiran to traverse the 250 miles between Tortula and Cactus is calculated as follows: time = distance / speed time = 250 / x
We also know that she upped her speed by 10 miles per hour throughout the 360-mile distance from Cactus to Dry Junction.
For that portion of the journey, let's designate her new speed "x+10" mi/h.
Her trip time is calculated as follows: time = distance / speed
time = 360 / (x+10)
Given that the entire journey lasted 11 hours, we can construct the following equation:
Time from Dry Junction to Cactus plus the time from Cactus to Tortula equals 11
250/x + 360/(x+10) = 11
We can now determine x:
250(x+10) + 360x = 11x(x+10)
0 - 400 - 2500 = 250x + 2500 + 360x = 11x2 + 110x
The quadratic equation is as follows: x = [400 sqrt(4002 - 4(11)(-2500))]
/ (2(11)) x = [400 ± sqrt(176000)]
/ 22
Speed cannot be negative, so we can disregard the negative result. Therefore, x = [400 + sqrt(176000)]
/ 22\sx ≈ 58.78
Kiran travelled between Tortula and Cactus at a speed of almost 58.78 miles per hour.
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What is the zeroth law of black hole thermodynamics?
Answers
The zeroth law states that a simple, non-rotating black hole has uniform gravity at its event horizon. This is kind of like saying that such a black hole is at thermal equlibrium.
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In A water fall is 1260m high. Calculate the change in temp. Of a quantity of water that fall from the top to the bottom of the water fall. take g as 10m/s.
Answers
The change in the temperature of the water is determined as 3 ⁰C.
What is the change in temperature of the water fall?The change in the temperature of the water fall is calculated by applying the formula for quantity of heat.
Q = mcΔθ
where;
m is the mass of the waterΔθ is the change in temperature of the waterc is the specific heat capacity of the waterThe potential energy of the water from the given height is calculated as follows;
P.E = mgh
where;
m is the mass of the waterg is acceleration due to gravityh is the height of the waterP.E = 1260 x 10 x m
P.E = 12,600 m (J)
The change in the temperature of the water;
Δθ = Q / mc
Δθ = (12,600 m (J) ) / ( m x 4,200 J /kgC)
Δθ = 3 ⁰C
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a.
70. All the following statements are true. Which one can be explained by Kepler's Second Law?
The Sun is not in the precise center of Saturn's orbit.
b. Earth is sightly closer to the Sun in January than in July
All the planets orbit the Sun in nearly the same plane.
d. Mars moves faster in its orbit when it is closer to the Sun than when it is farther from the Sun.
e. Venus orbits the Sun at a faster orbital speed than Earth.
Answers
The statement that can be explained using Kepler's Second Law is "Mars moves faster in its orbit when it is closer to the Sun than when it is farther from the Sun."
According to Encyclopedia Britannica, Kepler's second law states that; "a planet moves in its ellipse so that the line between it and the Sun placed at a focus sweeps out equal areas in equal times."
This law is sometimes referred to as the law of equal areas. It describes the fact that a planet moves faster when it is closer to the sun and slower when it farther from the sun.
An implication of this law is that mars moves faster in its orbit when it is closer to the Sun than when it is farther from the Sun.
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how a pendulum works including how fast it moves as its wing what happens to its energy as it swings and why it eventually stops.
Answers
A simple pendulum is considered to be a point mass suspended from a string or rod of negligible mass. If the pendulum is displaced from its equilibrium position, it will swing due to the force of gravity. Additionally, if there is damping (that can come from friction with the air), the pendulum will loose energy as it swings until it stops moving.
According to the variables in the diagram, the maximum velocity of a pendulum can be calculated using the conservation of mechanical energy:
The height that the mass reaches is equal to:
\(h=L(1-\cos \theta_0)\)The potential energy at that point, is:
\(\begin{gathered} U=mgh \\ =mgL(1-\cos \theta_0) \end{gathered}\)The kinetic energy at the equilibrium position will be related to the maximum velocity:
\(K=\frac{1}{2}mv^2_{\max }\)Then:
\(\begin{gathered} K=U \\ \Rightarrow\frac{1}{2}mv^2_{\max }=mgL(1-\cos \theta_0) \\ \end{gathered}\)Isolate v_max:
\(\begin{gathered} \Rightarrow v^2_{\max }=2gL(1-cos\theta_0) \\ \Rightarrow v_{\max }=\sqrt[]{2gL(1-\cos \theta_0)} \end{gathered}\)
Two objects attract each other with a gravitational force of magnitude 1.02 10-8 N when separated by 19.7 cm. If the total mass of the two objects is 5.14 kg, what is the mass of each
Answers
Answer:
The two masses are 3.39 Kg and 1.75 Kg
Explanation:
The gravitational force of attraction between two bodies is given by the formula;
F = Gm₁m₂/d²
where G is the gravitational force constant = 6.67 * 10⁻¹¹ Nm²Kg⁻²
m₁ = mass of first object; m₂ = mass of second object; d = distance of separation between the objects
Further calculations are provided in the attachment below
Analyze the circuit shown below in the figure below.
Solve with an equation(s) from the equation sheet.
Answers
The circuit is a series circuit since all of the components are connected in a single path.
The current that flows through each component is the same, and the voltage across each component is proportional to its resistance.
In this circuit, there are two resistors, R1 and R2, and a battery with an electromotive force (EMF) of E.
The voltage across each resistor can be determined using Ohm's law, which states that
V = IR,
where V is the voltage
I is the current
R is the resistance.
The total resistance of the circuit can be calculated using the formula:
R = R1 + R2.
Using Ohm's law, the current in the circuit can be found by dividing the voltage by the total resistance:
I = E / R
The voltage across each resistor can be found using
V1 = IR1 and V2 = IR2.
The total voltage of the circuit is equal to the sum of the voltages across each resistor
V = V1 + V2
Substituting the equations for V1 and V2 into the equation for V, we get;
V = I(R1 + R2)
Thus, we can use the following equations to solve for the different variables in the circuit:
R = R1 + R2
I = E / R
V1 = IR1
V2 = IR2
V = I(R1 + R2)
Using these equations, we can calculate the current, voltage, and power of the circuit.
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