Answer:
80N/cm^2
Explanation:
Given data
A car of weight 6,400N
Area= 80cm^2
The weight is distributed evenly on the 4 wheels
hence 6400/4
=1600 N
We know that
Pressure = force/Area
Pressure= 1600/80
Pressure= 20 N/cm^2
For the four wheels, the pressure is
=20*4
=80N/cm^2
A tourist, who weighs 705 N, is walking through the woods and crosses a small horizontal bridge. The bridge rests on two concrete supports, one at each end. He stops on the bridge. Assume that the board of the bridge has negligible weight. Where is he standing if the magnitude of the vertical force that a concrete support exerts on the bridge at the near end is 470 N?
а)one-fifth of the way along the bridge b)one-fourth of the way along the bridge c)one-third of the way along the bridge d)one-half of the way along the bridge f)one-sixth of the way along the bridge
The tourist is standing one-third of the way along the bridge (option c).
How to solveLet's denote the distance from the near end of the bridge to the point where the tourist is standing as x and the total length of the bridge as L.
According to the equilibrium condition, the sum of the forces exerted on the bridge is zero.
So, the vertical forces exerted by the two concrete supports should be equal to the weight of the tourist:
F_near + F_far = 705 N
Given that the magnitude of the vertical force exerted by the near end support is 470 N, we can calculate the force exerted by the far end support:
F_far = 705 N - 470 N = 235 N
Now, we can use the moment equilibrium condition, considering moments around the near end support:
Moment = Force × Distance
For the tourist:
Moment_tourist = 705 N × x
For the far end support:
Moment_far = 235 N × L
For equilibrium, the sum of the moments should be zero:
Moment_tourist - Moment_far = 0
Substituting the moments:
705 N × x - 235 N × L = 0
Now, we can solve for x/L, which represents the fraction of the way along the bridge where the tourist is standing:
x/L = (235 N × L) / 705 N
x/L = 235/705 = 47/141 ≈ 1/3
So, the tourist is standing one-third of the way along the bridge (option c).
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If a skaters mass increases how does that effect kinetic energy
Answer:
By paying close attention to the formula for average kinetic energy, we can see that by increasing the mass by a proportional amount will lead to an increase in the total average kinetic energy. There is a direct relationship being observed between the values.
When three people with a total mass of 2.00 x 102 kg step into their 1.200 x 103 kg car, the car’s
springs are compressed by 3.0 cm.
1.2.a. What is the spring constant of the car’s springs assuming they act as a single spring?
1.2.b. How far will the car lower if loaded with 3.00 x 102 kg rather than 2.00 x 102 kg
Answer:
a
\(k = 457333.3 N/m\)
b
\(x_a =0.09\ m\)
Explanation:
From the question we are told that
The total mass of three people is \(M = 2.00*10^{2} \ kg\)
The mass of the car is \(m_c = 1.200 *10^{3} \ kg\)
The compression of the car spring is \(x = 3 \ cm = 0.03 \ m\)
Generally the spring constant is mathematically represented as
\(k = \frac{F}{x}\)
Here F is the force exerted by the mass of three people and that of the car , this is mathematically represented as
=> \(F = (M +m_c) *g\)
=> \(F = ([2.0*10^{2} ]+[ 1.200*10^{3}]) * 9.8\)
=> \(F = 13720 \ N\)
So
\(k = \frac{13720}{0.03}\)
=> \(k = 457333.3 N/m\)
Generally if the mass which the car is loaded with is \(m = 3.00*10^{2} \ kg\)
Then the force experienced by the spring is
=> \(F_a = (m +m_c) *g\)
=> \(F_a = (3.00*10^{3} + 1.200 *10^{3}) * 9.8\)
=> \(F_a = 41160 \ N\)
Generally from the above formula the compression is
\(x_a = \frac{F_a}{k}\)
=> \(x_a = \frac{41160}{457333.3}\)
=> \(x_a =0.09\ m\)
A person 1.8 m tall is photographed with a 35-mm camera, and the film image is 20 mm. Under the same conditions, how tall is a person whose film image is 16 mm?
Under the same conditions, the height of a person whose film image is 16 mm is 1.44 m.
What is magnification of a lens?
The magnification of a lens is defined as the ratio of the height of an image to the height of an object.
The formula for magnification of a lens is given as;
M = v/u = hi/h
where;
v is image distanceu is object distance hi is image heighth is object heightUnder the same conditions, the height of a person whose film image is 16 mm is calculated as follows
M = 20 mm / 1.8 m = 16 mm/h
20 mm / 1.8 m = 16 mm/h
h = (16 mm / 20 mm) x 1.8 m
h = 1.44 m
Thus, under the same conditions, the height of a person whose film image is 16 mm is 1.44 m.
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Your friend wants to join the school track team, and has asked for your help to determine how fast she can run. 4. What kind of information would you need to collect in order to help your friend?
Answer:
I think you would need too time your friend and know how too divide that time by other racers to see how much faster she needs to get. I THINK.
1. Two charges are separated by a distance of 1 cm. One charge has a value of 7 micro Coulombs. The other charge has a value of 10 micro Coulombs. What is the force between them, in pounds. Make sure to include the sign of the force which will be positive if the charges repel each other and negative if they attract each other.
2. 12 gauge copper wire is normally used in house wiring. When aluminum wire is used one needs to use a smaller gauge size to obtain the same resistance, 40 ft of 12 gauge copper wire was calculated. What would the resistance be if 10 gauge aluminum wire were used?
3. A 12 V automobile battery can supply 51 amps for one hour and cost $194. What is the cost of this electricity in cents per kWh?
4. Most of the body's resistance is in its skin. When wet, salts go into ion form, and the resistance is lowered. Thus, the resistance of the skin can go from 100,000 ohms when dry to 300 ohms when wet. What is the current that would be carried through the body, in milliAmperes, if you touched a 240 V power line while dry? Currents over 10 mA are almost always deadly.
1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.
2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.
3. The cost of electricity from the automobile battery is 38.6 cents per kWh.
4. The current that would be carried through the body is 0.8 mA if dry.
1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.
2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.
Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.
3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.
Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.
4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.
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2(a)Find the density of air filled in polythene container with mass of 0.419kg when it is empty. When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times
When filled with extra air its mass increased to 0.428kg also the top of polythene container mass connected to the perplex box of volume 1000cm³ and the number of times of air inside was 7.2 times. The density of the air filled in the polythene container is approximately 1.25 kg/m³.
The density of air filled in the polythene container can be determined by considering the change in mass and volume of the container before and after filling it with air. Given that the mass of the empty container is 0.419 kg and the mass of the container when filled with extra air is 0.428 kg, and the volume of the perplex box is 1000 cm³.
Calculate the mass of the air inside the container by subtracting the mass of the empty container from the mass of the container when filled with air:
Mass of air = Mass of filled container - Mass of empty container
= 0.428 kg - 0.419 kg
= 0.009 kg
Calculate the volume of the air inside the container using the given number of times the air inside is 7.2:
Volume of air = Volume of perplex box * Number of times air inside
= 1000 cm³ * 7.2
= 7200 cm³
Convert the volume of air to cubic meters (m³) by dividing by 1000000:
Volume of air = 7200 cm³ / 1000000
= 0.0072 m³
Calculate the density of air using the formula:
Density = Mass / Volume
Density = 0.009 kg / 0.0072 m³
≈ 1.25 kg/m³
Therefore, the density of the air filled in the polythene container is approximately 1.25 kg/m³.
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B6. [9 Marks] 30⁰ 20140X20 DE Ofe OTO A stainless-steel orthodontic wire is applied to a tooth as shown in the diagram below. The wire has an unstretched length of 3.1 cm and a diameter of 0.22 mm. If the wire is stretched by 0.10 mm during the procedure, find the magnitude and direction of the force on the tooth. Disregard the width of the tooth and assume Young's modulus for stainless-steel is 18 × 10¹0 Nm-².
The magnitude of the force on the tooth is approximately 0.022 N.
To find the magnitude and direction of the force on the tooth, we can use Hooke's Law, which states that the force exerted on an object is directly proportional to the change in length of a material when it is stretched or compressed.
First, we need to calculate the strain (ε) of the stainless-steel wire.
Strain is defined as the change in length divided by the original length:
ε = ΔL / L₀
Given that the change in length (ΔL) is 0.10 mm \((0.10 \times 10^{-3} m)\) and the unstretched length (L₀) is 3.1 cm \((3.1 \times 10^{-2} m)\), we can calculate the strain:
\(\epsilon=(0.10 \times 10^{-3} m)/(3.1 \times 10^{-2} m)=0.003225\)
Next, we can use Young's modulus (E) to calculate the stress (σ) in the wire.
Stress is defined as the force per unit area:
σ = E * ε
Given that Young's modulus (E) for stainless-steel is 18 × 10¹⁰ N/m², we can calculate the stress:
σ = (18 × 10¹⁰ N/m²) * 0.003225 = 5.805 × 10⁸ N/m²
Now, we can find the force (F) on the tooth by multiplying the stress by the cross-sectional area (A) of the wire:
F = σ * A
The cross-sectional area (A) can be calculated using the formula for the area of a circle:
A = π * (d/2)²
Given that the diameter (d) of the wire is 0.22 mm\((0.22 \times 10^{-3} m)\), we can calculate the cross-sectional area:
\(A = \pi * (0.22 \times 10^-3 m / 2)^{2} = 3.802 \times 10^{-8} m^2\)
Finally, we can calculate the force:
\(F = (5.805 \times 10^{8} N/m^{2}) * (3.802 \times 10^-8 m^{2}) \approx 2.206 \times 10^{-2} N\)
Therefore, the magnitude of the force on the tooth is approximately 0.022 N.
Since the wire is stretched, the force is pulling the tooth in the direction opposite to the stretching.
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What major region does this profile
most likely represent?
Given the information on the graph, we can confirm that this profile represents the Ocean floor profile.
What causes the spike in the graph?The spike in the graph demonstrates a sharp change in depth. This is caused by the irregularities we expect to find on the ocean floor. Many parts of the ocean floor are deeper than others, caused by the movement of tectonic plates over time.Therefore, we can confirm that the profile belongs to the ocean floor profile, firstly because of the information provided, as well as it being consistent with the irregularities in the depth of the ocean floor.
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n his fishing trip, Justin rides in a boat 10 km south. The fish aren’t biting so they go 4 km west. They then follow a school of fish 1 km north. What distance did they cover? What was their displacement?
The displacement covered will be 9.85 km
The distance covered will be = 10 + 4 + 1 = 15 km
using Pythagoras theorem
\(H^{2} = P^{2} + B^{2}\)
H = \(\sqrt{4^{2} + 9^{2} }\)
H = \(\sqrt{97}\)
H = 9.85 km
The displacement covered will be 9.85 km
The distance covered will be = 10 + 4 + 1 = 15 km
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If a batter can apply the same out of maximum force from their hands to each bat to swing it why would the speed of the bat swing decrease as the mass of the bat increases
The speed of the bat swing decrease as the mass of the bat increases because mass is inversely proportional to velocity squared if the centripetal force is constant.
\(F_{c}\) = m v² / r
\(F_{c}\) = Centripetal force
m = Mass
v = Velocity
r = Radius
Rearranging for v,
v² = \(F_{c}\) * r / m
Since \(F_{c}\) and r is constant,
v² ∝ 1 / m
Since v² is inversely proportional to m and vice-versa, as the mass of the bat increases, speed of the bat swing decreases.
A centripetal force is responsible for making a body follow a curved path. The direction of centripetal force is perpendicular to the motion and towards the center of curvature.
Therefore, the speed of the bat swing decrease as the mass of the bat increases because mass is inversely proportional to velocity squared if the centripetal force is constant.
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describe one similarity and one difference between the velocity on the reference circle and the velocity on the pendulum
SHM can be acquired by perpendicular projection of uniform circular motion of a particle on its diameter such a particle is called reference particle and its circular path is called reference circle.
A pendulum reaches its maximum velocity when the block is at its lowest point (the pendulum is vertical and pointing straight down). We can then use the term for conservation of energy to determine the maximum height of the block.
What is the velocity at the bottom of a pendulum?
As the pendulum swings downward, gravity converts this potential energy into kinetic energy, so that at the bottom of the swing, the pendulum bob has zero potential energy, and its kinetic power, (1/2)mv2, equals the initial potential energy (mgh). (So the velocity, v, equals √(2gh).)
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What is the best description of the function of stars?
Stars are the recycling centers of the universe.
Stars are the light bulbs of the universe.
Stars are the batteries of the universe.
Stars are the motors of the universe.
Answer:
Stars are the light bulbs of the universe.
Answer:
Stars are the recycling centers of the universe
Explanation:
I just did on edge C
Can someone please check my review answers before I take my exam (sorry I’m advance for poor quality)
Answer:
Explanation: #1 is A #2 is C #3 is correct #4 is correct #5 is correct
''In general, the normal force is not equal to the weight." Give an example where the two forces are equal in magnitude and at least two examples where they are not.
A normal force is a force applied perpendicular to a surface on an object in contact with it. The weight is the gravitational force imposed on an object, and it is equal to the mass multiplied by the acceleration due to gravity.
When an object is put on a scale at rest on a level surface, the normal force equals the weight. In this instance, the normal force acting upwards from the scale on the object is equal to the weight acting downwards.
Here are two instances of normal forces that are not equal to weight:
When a person stands on an inclined plane or ramp, the normal force applied by the plane is less than the person's weight, because some of the weight is resolved parallel to the plane, causing the person to slide down if enough friction exists.
The normal force exerted by the air or other medium on a person in free fall is zero, while their weight due to gravity stays constant.
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Which theory explains why gravity between two objects changes when the distance between them changes?
Einstein's theory because he suggested that the more distance there is between objects, the more space-time
curves and the greater the strength of gravity is.
Einstein's theory because he suggested that the more distance there is between objects, the more space-time
curves and the weaker the strength of gravity is.
Newton's theory because he suggested that the greater the distance between objects, the greater the pull of gravity.
Newton's theory because he suggested that the greater the distance between objects, the weaker the pull of gravity.
Answer:
Newton's theory because he suggested that the greater the distance between objects, the weaker the pull of gravity.
Answer: The answer is Newton’s theory because he suggested that the greater the distance between objects, the weaker the pull of gravity
Explanation: Just took the test i hope this help you enjoy :D
HELP DUE 3 MINUTESSSSD
Answer:
Break down small pebbles and sediments, like sand
Break down large rocks like mountains
Explanation:
Need help with this assignment please
Torque is a measure of the turning force applied to an object about a rotational axis. It is calculated as the product of the force applied to the object and the distance from the axis of rotation at which the force is applied.
How to explain the informationUse the equation slope = mod to calculate the unknown mass (mo) for parcels A and C, setting d = 1.0 m, and parcels G and H, setting d = 1.5 m.
Record all data, tables, and four graphs for analysis.
The experiment demonstrates the application of torque in determining unknown masses and provides valuable insights into the concept of torque in physics.
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If vector A represents displacement from point O(x1, y1,z1) and P(x2, Yz, Z2) ؟
The magnitude of the displacement of the vector A is determined as 6.2 units.
What is the magnitude of displacement of the vector?The magnitude of the displacement of the vector is calculated as follows;
| A | = √[ (x₂ - x₁ )² + (y₂ - y₁ )² + (z₂ - z₁ )²]
where;
| A | is the magnitude of vector Ax₂ and x₁ are the final and initial position on x - coordinate respectively.y₂ and y₁ are the final and initial position on y - coordinate respectively.z₂ and z₁ are the final and initial position on z- coordinate respectively.The magnitude of vector A is calculated as;
| A | = √[ (2 - 0 )² + (3 - 0 )² + (5 - 0 )²]
| A | = √ (4 + 9 + 25)
| A | = √ ( 38)
| A | = 6.2 units
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The complete question is below;
If vector A represents displacement from point O(x1, y1,z1) and P(x2, Yz, Z2). find the magnitude of the displacement of vector A.
Two bumper cars are moving towards each other. Car A has amass of 200 kg and is moving at a speed of 4 m/s to the right.Car B has a mass of 175 kg and is moving to the left at aspeed of 6.5 m/s. After the cars collide, Car A is moving to theleft at a speed of 2.5 m/s. How fast, and in what direction, iscar B moving after the collision?
Given
Car A has a mass of m=200 kg and is moving at a speed of u=4 m/s to the right.
Car B has a mass of m'=175 kg and is moving to the left at a speed of u'=6.5 m/s.
After the cars collide, Car A is moving to the left at a speed of v=2.5 m/s
To find
How fast, and in what direction, is car B moving after the collision?
Explanation
Let the velocity of car B after collision be v'
Let us consider the direction towards right to be positive
By conservation of momentum before and after collision,
\(\begin{gathered} mu+m^{\prime}u^{\prime}=mv+m^{\prime}v^{\prime} \\ \Rightarrow200\times4-175\times6.5=-200\times2.5+175v^{\prime} \\ \Rightarrow800-1137.5=-500+175v^{\prime} \\ \Rightarrow v^{\prime}=\frac{0.92m}{s} \end{gathered}\)Conclusion
Car B is moving at a velocity 0.92m/s towards the right
What is the main difference between the local families at the ball and the new arrivals, the bingleys and mr. Darcy?.
The main difference between the local families at the ball and the new arrivals, the Bingleys and Mr. Darcy, is their social status and wealth.
How were the local families and the new arrivals different ?In Jane Austen's novel "Pride and Prejudice," the local families, such as the Bennets, Lucas, and Philips, are considered part of the gentry, a class of landed proprietors who are not as wealthy as the aristocracy but who still hold a respected place in society. They are considered to be in the same social class as the Bingleys, who are also part of the gentry.
However, Mr. Darcy is of a much higher social status and greater wealth than any of the local families. He is an aristocrat, a member of the landed gentry with a vast estate and immense wealth.
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describe Piaget's four stages of cognitive development. Include the major hallmarks of each stage.
Answer:
Explanation:
Sensorimotor Infants "think" by acting on the world with their eyes, ears, hands, and mouth.
Preoperational. Development of language and make-believe play takes place.
Concrete Operational children think in a logical, organized fashion only when dealing with concrete information they can perceive directly.
Formal Operational. Adolescences can also evaluate the logic of verbal statements without referring to real-world circumstances.
Sensorimotor, preoperational, concrete operational, and formal operational are Piaget's four phases of cognitive development.
What is cognitive development?The way youngsters think, investigate, and figure things out is referred to as cognitive development.
Piaget defined four stages of cognitive development:
1. Sensorimotor. From birth through the age of 18-24 months.
2. Preoperational.From infancy (18-24 months) until toddlerhood (age 7)
3. Operational concrete. 7 to 11 years old
4. Formal operational. From adolescence to adulthood
Hence, sensorimotor, preoperational, concrete operational, and formal operational are Piaget's four phases of cognitive development.
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a tennis ball rolls horizontally to the left for 30 m at a constant speed. what is the velocity after 15 seconds? what is the speed?
**PLEASE HELP - for physics, list variables
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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For a particular nonlinear spring, the relationship betweem the magnitude of the applied force F and the resultant displacement x from equilibrium is given by the equation F = k x^2 What is the amount of work done by stretching the spring a distace x0? A) kx0^3 B) (1/2)kx0 C) (1/2)kx0^3 D) (1/3)kx0^2 E) (1/3)kx0^3
To get the work, you have to integrate the force as a function of \($x$\) from zero displacement to Xo
\((Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$\)
The work done by stretching the spring to the given distance is \(W=\frac{k x_0}{3}\)
The given parameters:
- Applied force on the spring \($=F$\)
- Extension of the spring \($=x_0$\)
The work done by stretching the spring to the given distance is calculated as follows;
\(W=\frac{k x_0}{3}\)
\($$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}\)
Thus, the work done by stretching the spring to the given distance is
\(W=\frac{k x_0}{3}\)
measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
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If you were standing at the center of a circular wave what would you see in all directions?
a.waves moving away from you
b.waves moving towards you
c.waves moving across you
d.no movement at all
In an application, Germanium is
made p-type material by adding
Indium. The rate of adding is one
indium atom
per
3 Germanium
atom. Assume donor density to be
zero and ni = 6.2 Cubic
metre at room temperature.
Determine the value
of
the
aceeptor atom density
Answer:
produce electronics
Explanation:
The uses of Germanium are recorded beneath: Germanium's principle use is to deliver strong state hardware, semiconductors and fiber optic frameworks. As a phosphor in fluorescent lights.
87% of men in the Silent Generation were employed when they were young. Predict: What percentage of Millennial men do you think are employed today?
The 66 percent of Millennials were employed in the year 2018.
MillennialsMillennials are the people who are born between 1982 and 1998 while on the other hand, 87% of men in the Silent Generation were employed so there is a decrease occur in the employment rate from silent generation to Millennial generation.
ReasonThe reason behind this decrease is the unavailability of employment opportunities and jobs for the people of Millennial generation so we can conclude that 66 percent of of Millennial men were employed in the year 2018.
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When a piece of wood is put in a graduated cylinder containing water the level of water rises from 17.7cm cubic to 18.5cm cubic calculate the total volume of the piece of wood given that it's relative density is 0.60
The total volume of the piece of wood is 1.33\(cm^3\).
To calculate the total volume of the piece of wood, we can use the principle of displacement.
1. First, we need to find the difference in volume between the two water levels. The initial volume is 17.7 \(cm^3\), and the final volume is 18.5 cm^3. The difference is 18.5 \(cm^3\) - 17.7 \(cm^3\) = 0.8 \(cm^3\).
2. Now, we need to find the volume of water displaced by the piece of wood. Since the relative density of the wood is 0.60, it means that the wood is 0.60 times denser than water.
3. The volume of water displaced by the wood is equal to the difference in volume divided by the relative density of the wood. So, the volume of water displaced is 0.8 cm^3 / 0.60 = 1.33 \(cm^3\).
4. Finally, the total volume of the piece of wood is equal to the volume of water displaced. Therefore, the total volume of the piece of wood is 1.33 \(cm^3\).
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If the moon crossed the meridian at midnight what phase must the moon be in?
Answer:
Waxing Gibbous
Explanation:
New Moon Rises at sunrise, transits meridian at noon, sets at sunset
Explanation: