A crate of mass 25 kg moving with a speed of 3 ms on a tough horizontal floor is brought to rest after sliding a distance of 2.5 m on the floor. The coefficient of sliding friction between the crate and the floor is
A. 0.25 B. 0.40 C. 0.50 D. 080​

Answers

Answer 1

Answer: uk= 0.184

Explanation:

First, to better visualize the situation, draw a force diagram that lists all the components in the equation: (see picture)

Next, list your knowns and unknowns. We know that the mass of the crate is 25 kg and the distance is 2.5 m. These are the standard SI units so no conversion is needed.

First we need to find the acceleration to solve for the net force. This can be done by using a kinematic equation.

Since we know that the final speed (velocity) is 3 m/s, the initial velocity (rest) is 0 m/s, and that the distance is 2.5 meters we can use the equation:

Vf^2= Vi^2 +2ax

Plug in the given values:

(3)^2= (0)^2 +(2)(a)(2.5)

9= 0 + 5a

9=5a

a= 1.8 m/s^2 g

Next, we need to solve for the net force:

NetF = 25*1.8

NetF= 45 N

Because there is no sliding force mentioned, the sliding force will actually be 0. This means that we found our two unknowns, 45 N and 0N, and can resolve them into the equation:

NetForce= SlidingForce - FrictionForce

NetForce-SlidingForce= -Friction Force

(45)-(0)= -45

Friction force is 45 N

We now have our Friction force, but still need the normal force so that we can use the equation:

Fr (Frictionforce) = uk (coefficient of friction) * Fn (normal force)

The normal force is in the y axis, so that means:

No acceleration (Net force= m(0) = 0)

NetForce= Fn - mg

0 = Fn - mg

mg = Fn

To find mg, multiply mass by gravity:

(25)(9.8)

mg=245= Fn

We now have everything we need to solve for the coefficient of friction:

Fr= 45 N

Fn= 245 N

Fr = uk * Fn

Fr/Fn = uk

45/245 = uk

uk= 0.184

I’m not sure why that’s not answer choice, but:

Check

0.184 * 245

=45 N

Netforce= 45-0

NF = 45

NF = ma

45 = m (1.8)

m = 25 kg

It all checks out.

A Crate Of Mass 25 Kg Moving With A Speed Of 3 Ms On A Tough Horizontal Floor Is Brought To Rest After

Related Questions

What is the vector sum of a vector T~ given by 40 m, 30 degrees and a vector U~ given by 12
m, 225 degrees?

Answers

Hence, R = 28.97 m, 24.5 degrees is the vector sum of T and U.

Is a vector at 30 degrees?

A vector's direction is frequently stated as a rotation of the vector's "tail" anticlockwise with respect to due East. In accordance with this practise, a vector having a direction of 30 degrees is a vector that has been anticlockwise rotated 30 degrees with respect to due east.

Let's begin by separating the components of the vector T:

T~ = 40 m, 30 degrees

T_x = 40 cos(30) = 34.64 m

T_y = 40 sin(30) = 20 m

Let's now decompose the vector U into its constituent parts:

U~ = 12 m, 225 degrees

U_x = 12 cos(225) = -8.49 m

U_y = 12 sin(225) = -8.49 m

It is possible to combine elements of the same type (x and y):

R_x = T_x + U_x = 34.64 m - 8.49 m = 26.15 m

R_y = T_y + U_y = 20 m - 8.49 m = 11.51 m

The Pythagorean theorem can be used to determine the size of the resulting vector R:

|R~| = sqrt(R_x² + R_y²) = sqrt((26.15 m)² + (11.51 m)²) = 28.97 m

The inverse tangent function can be used to determine the direction of the resulting vector R:

theta = tan⁻¹(R_y/R_x) = tan⁻¹(11.51 m/26.15 m) = 24.5 degree.

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The theoretical efficiency of an Otto cycle is 63%. The ratio of the Cp and Cv heat capacities for the gas in the engine is (a) What is the compression ratio r? (b) If the net work done per cycle is 12.6 kJ, how much heat is rejected and how much is absorbed by the engine during each cycle?

Answers

A spark is used to ignite the fuel-air mixture with in ideal Otto cycle after it is introduced during induction stroke, compressed to a considerably lower compression ratio, and introduced into the engine.

Tell me about the Otto cycle.

In order for an engine to operate in the Otto cycle, the piston must make four strokes: one for induction, one for compression, one for ignition, and one for exhaust. In order for combustion to begin with only an electric arc or another method, the air-fuel mixture must first be compressed. bearing the name of German engineer Nikolaus Ott.

Otto cycles come in 2 and 4 stroke varieties.

Four engine strokes are required for the Otto Cycle. The term "stroke" refers to a procedure in which the piston of the cylinder goes up or down within the engine.

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A ball starts from rest and rolls down a hill. The height of the hill is not known but when the ball is 3 meters above the ground it is moving at 5 m/s. a) What was the height of the hill? b) What is the total mechanical energy (PE +KE) of the ball at that point if the mass is 1 kg? ignore friction

Answers

Answer:

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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Love, which can't be observed or measured directly, is an example of a psychological construct.
Please select the best answer from the choices provided
О Тrue
O False

Answers

Answer:

True

Explanation:

A psychological construct can't be observed and you can feel this,

Example: anxiety, anger, sadness

The answer is True

Which of these statements is true concerning balanced forces acting on a car?
Balanced forces will cause no change in the car's motion.
Balanced forces will cause the car to accelerate in the direction of the greater force
Balanced forces will cause the object to change direction.
Balanced forces will cause the car to slow down and stop

Answers

Answer:

Balanced forces will cause no change in the car's motion.

Explanation:

Balanced forces are 2 forces that are equal in opposite directions. This means they 'cancel each other out' in a way. Since both are equal, they cause no effect on the motion of the car

As you walk to class with a constant speed of 1.70 m/s , you are moving in a direction that is 22.7 ∘ north of east. How much time does it take to change your displacement by 18.0 m east? How much time does it take to change your displacement by 32.0 m north?

Answers

a. It takes 13.94 seconds to change your displacement by 18.0m east.

b. It takes 28.9 seconds to change your displacement by 32.0m north,

What is displacement?

In geometry and mechanics, a displacement is described as a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.

To change your displacement by 18.0m east, we use the

X direction = \(\frac{18}{1.70 cos 22.7}\)

x direction = 13.94 seconds

To change your displacement by 32.0m north, we use the

Y direction = \(\frac{32}{1.70 sin 22.7}\)

y direction= 28.9 seconds

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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the

Answers

Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

A bowling ball of mass m = 1.1 kg is resting on a spring compressed by a distance d = 0.35 m when the spring is released. At the moment the spring reaches its equilibrium point, the ball is launched from the spring into the air in projectile motion at an angle of θ = 39° measured from the horizontal. It is observed that the ball reaches a maximum height of h = 4.4 m, measured from the initial position of the ball. Let the gravitational potential energy be zero at the initial height of the bowling ball.
a) what is the spring constant, k, in newtons per meter?

(I got that the speed of the ball after the launch is 14.76)

Answers

The spring constant, k, in newtons per meter is 1,955.9 N/m.

Speed of the ball after the launch

h = v²sin²θ/2g

v = √[(2gh)/sin²θ]

v = √[(2 x 9.8 x 4.4)/ (sin 39)²]

v = 14.76 m/s

Energy of the ball at top

E = K.E + P.E

E = ¹/₂m(v cosθ)²  +  mgh

E =  ¹/₂(1.1)(14.76 cos39)²  +  (1.1 x 9.8 x 4.4)

E = 119.8 J

Spring constant

E = ¹/₂kx²

k = 2E/x²

k = (2 x 119.8)/(0.35²)

k = 1,955.9 N/m

Thus, the spring constant, k, in newtons per meter is 1,955.9 N/m.

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Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct?

Answers

We can see here that the statement that is correct will be: B. The rock display with larger holes shows petroleum drilling, which is deep underground.

Who is a geologist?

A geologist is a scientist who focuses on the solid components of the Earth, such as minerals and rocks, as well as the processes that shape the planet's surface.

Geologists study the make-up, structure, and past of the Earth's crust in order to comprehend geological processes including mountain creation, earthquake and volcanic activity, and the exploitation of natural resources. They frequently perform fieldwork, gathering samples, running surveys, and researching geological formations.

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The complete question is that:

Your class goes on a field trip to observe drilling machinery. The geologists at the drill site show you displays of drilled rocks to compare different types of drills and methods. The drilled holes in one rock display are significantly larger than the holes drilled in the display next to it. Given this information, which statement is correct? (1 point)

A. The rock display with smaller holes shows copper drilling, which is deep underground.

B. The rock display with larger holes shows petroleum drilling, which is deep underground.

C. The rock display with smaller holes shows petroleum drilling, which is closer to the surface.

D. The rock display with larger holes shows copper drilling, which is closer to the surface.

A solid weighs 237.5 g in air and 12.5 g in a liquid in which it is wholly submerged. The density of the liquid is 900 kg/m³.

Calculate (1) the density of the solid (il) the density of another liquid in which the same solid would float with one-fifth of its volume exposed above the liquid surface.​

Answers

(i) The density of the solid is 950 kg/m³

(ii) the density of another liquid in which the same solid would float is 200 kg/m³

The given parameters;

mass of the solid in air, Ma = 237.5 g

mass of the solid in liquid, Ms = 12.5 g

density of the liquid, \(\rho_l = 900 \ kg/m^3\)

(i) The density of the solid is calculated as follows;

Weight in air - Weight in liquid = upthrust

\(\frac{\rho_o}{\rho_l} = \frac{Ma}{M_a - Ms} \\\\\frac{\rho_o}{900} = \frac{237.5}{237.5 - 12.5}\\\\\frac{\rho_o}{900} =1.0556\\\\\rho_o = 1.0556 \times 900\\\\\rho_o = 950 \ kg/m^3\)

(ii) the density of another liquid in which the same solid would float with one-fifth of its volume exposed above the liquid surface.​

This is a low density liquid, because one-fifth of the solid is above the liquid surface while four-fifth is below the liquid surface.

the specific gravity of the liquid = ¹/₅ = 0.2

density of water , \(\rho_w = 1000 \ kg/m^3\)

\(S.G = \frac{\rho_l}{\rho_w} \\\\0.2 = \frac{\rho_l}{1000} \\\\\rho_l = 0.2 \times 1000\\\\\rho_l = 200 \ kg/m^3\)

Thus, the density of another liquid in which the same solid would float is 200 kg/m³

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19. In a turtle race, a 20 kg turtle moves with a velocity of 0.1 m/s. What is the kinetic energy of the turtle?

A. 20 J

B. 0.2 J

C. 0.1 J

Answers

Answer:
C
Explanation:
KE=1/2mv^2
KE=1/2(20)(0.1)^2
0.1^2= 0.01
KE= 1/2(20)(0.01)
KE= 0.1 J

lol
idk what this is​

Answers

Answer:

I know

Explanation:

Physics= hard

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A train travels 8.81 m/s in a -51.0° direction.
The train accelerates for 2.23 s, changing its
velocity to 9.66 m/s in a 37.0° direction.
What is [delta]x?

A train travels 8.81 m/s in a -51.0 direction.The train accelerates for 2.23 s, changing itsvelocity

Answers

The displacement of the train after 2.23 seconds is 25.4 m.

Resultant velocity of the train

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

θ is the angle between the velocity = (90 - 51) + 37 = 76⁰

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

Displacement of the train

The displacement is calculated as follows;

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

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Which of the following is most likely the caption for the illustration that was scratched out of the textbook?

A. An electrically-charged object can attract an uncharged object with magnetic properties.

B. An electrically-charged object is stronger than a magnet.

C. A dry cell battery has magnetic properties.

D. An electric circuit can only have one dry cell battery.

IMAGE DOWN BELOW OR UP

Which of the following is most likely the caption for the illustration that was scratched out of the

Answers

The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.

A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.

The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.

So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.

Therefore, The correct answer is option C.

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why pet cats are not called Panthera Cantus.

Answers

Panthera is a genus within the family Felidae that was named and described by Lorenz Oken in 1816 who placed all the spotted cats in this group.

A car slows from 22m/s to 3m/s with a constant acceleration of -2.1m/s². How long does it take?

Answers

Answer:

The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.

Explanation:

Answer:

The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time

Explanation:

Nonreflective coatings on camera lenses reduce the loss of light at the surfaces of multilens systems and prevent internal reflections that might mar the image. Find the minimum thickness of a layer of magnesium fluoride (n = 1.38) on flint glass (n = 1.66) that will cause destructive interference of reflected light of wavelength 480 nm near the middle of the visible spectrum.

Answers

The minimum thickness of the magnesium fluoride layer that will cause destructive interference of reflected light with a wavelength of 480 nm is 86.9 nm

How do we sole for the minimum thickness that will cause destructive interference ?

To find minimum thickness of a non-reflective coating that causes destructive interference we use the formula t = (mλ) / (4n)

The wavelength (λ) of the light is 480 nm

the refractive index (n) of magnesium fluoride is 1.38,

we can calculate the minimum thickness (t) by saying

t = 0 × 480 / 4 × 1.38

t = 0 nm

t = 1 × 480 nm / 4 × 1.38

t = 480 nm / 5.52

t = 86.96 nm

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. An object 8.5 cm high is placed 28 cm from a converging lens. The focal length of the lens is 12 cm. Calculate the image distance, di. Calculate the image height, hi.

Answers

The converging lens is also called a concave lens. The height of the image formed by the lens is 2.55 cm.

Using the lens formula;

1/f = 1/u + 1/v

f = focal length of the lens

u = object distance

v = image distance

Note that the focal length of a converging lens is positive

Substituting values;

1/12 = 1/28 + 1/v

1/v = 1/12 -  1/28

v = 8.4 cm

Magnification= image height/object height = image distance/object distance

image height = ?

object height = 8.5 cm

image distance = 8.4 cm

object distance =  28 cm

So

image height/8.5 = 8.4/28

image height = 8.5 × 8.4/28

image height = 2.55 cm

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A ball connected to a 1.1 m string and is swing in circular fashion. It’s tangential velocity is 15 m/s. What is its centripetal acceleration?

Answers

Answer:

ac = 204 [m/s²]

Explanation:

To solve this problem we must use the following equation that relates the tangential velocity to the radius of rotation.

ac = v²/r

where:

v = tangential velocity = 15 [m/s]

r = radius = 1.1 [m]

Now replacing we have:

ac = (15)²/1.1

ac = 204 [m/s²]

A mass on a
string is swung in a circle of radius 1.0m
at a speed of 5.0mls. What is the period of
revolution?​

Answers

Answer:

S = 2 * pi * 1 m = 6.28 m = distance traveled

V = S / T   or   T = S / V = 6.28 m / 5 m/s = 1.26 sec

This will be the time for 1 revolution or the period of the motion.    

Help! I've tried solving it a few times!


An electron travels 2.68 m in 6.11 × 10^-8 s. How fast does it travel in cm/s? Answer in units of cm/s.

Answers

If an electron travels 2.68 m in 6.11 × 10^-8 s, it will travel at a speed of 43.86 * \(10^{8}\) cm / s

v = d / t

v = Velocity

d = Distance

t = Time

d = 2.68 m

t = 6.11 * \(10^{-8}\)

v = 2.68 / 6.11 * \(10^{-8}\)

v = 0.4386 * \(10^{8}\) m / s

v = 0.4386 * \(10^{8}\) * 10² cm / s

v = 43.86 * \(10^{8}\) cm / s

One meter is equal to 100 centimeters. So in order to convert a meter value into centimeter, multiply the meter value by 100 or 10².

Therefore, the electron travels at 43.86 * \(10^{8}\) cm / s

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A 25kg box in released on a 27° incline and accelerates down the incline at 0.3 m/s2. Find the friction force impending its motion? What is the coefficient of kinetic friction?
A block is given an initial speed of 3m/s up a 25° incline. Coefficient of friction

Answers

Answer:

a)  μ = 0.475 , b)   μ = 0.433

Explanation:

a) For this exercise of Newton's second law, we create a reference system with the x-axis parallel to the plane and the y-axis perpendicular to it

X axis

     Wₓ - fr = m a

the friction force has the expression

     fr = μ N

y Axis

     N - \(W_{y}\) = 0

let's use trigonometry for the components the weight

     sin 27 = Wₓ / W

     Wₓ = W sin 27

     cos 27 = W_{y} / W

     W_{y} = W cos 27

     N = W cos 27

     W sin 27 - μ W cos 27 = m a

     mg sin 27 - μ mg cos 27 = m a

      μ = (g sin 27 - a) / (g cos 27)

      very = tan 27 - a / g sec 27

      μ = 0.510 - 0.0344

      μ = 0.475

b) now the block starts with an initial speed of 3m / s. In Newton's second law velocity does not appear, so this term does not affect the result, the change in slope does affect the result

         μ = tan 25 - 0.3 / 9.8 sec 25

         μ = 0.466 -0.03378

         μ = 0.433

In a baseball game a foul ball was hit straight up with a speed if 30 m/s. Ignore air resistance.
a. How high did the ball go up?
b. How long was the ball in the air?
c. What happened to the answers in part “a” and “b” if the initial velocity was only 15 m/s?

initial position = ?
finial position = ?
initial velocity = ?
final velocity = ?
acceleration = ?
time = ?

Answers

Answer:

h=4+85*time - 1/2 32*time^2

16time^2-85*time-106=0

use the quadratic formula to solve for time (notice two solutions, one going up, one going back down).

time=(85+-sqrt(85^2+4*16*106) )/32

Explanation:

Recheck my work just in case I'm not good at this type of class but I wanted to help.

a. At maximum height h, the baseball has zero vertical velocity, so that with initial velocity v we have

\(0^2-v^2 = -2gh \implies h = \dfrac{v^2}{2g}\)

Given that \(v = 30 \frac{\rm m}{\rm s}\), the ball reaches a height of

\(h = \dfrac{\left(30\frac{\rm m}{\rm s}\right)^2}{2g} \approx \boxed{46\,\mathrm m}\)

b. At max height, the baseball's vertical velocity is such that

\(0=v-gt\)

For \(v = 30 \frac{\rm m}{\rm s}\), we find

\(gt=30\dfrac{\rm m}{\rm s} \implies t = \dfrac{30\frac{\rm m}{\rm s}}g \implies t \approx 3.1 s\)

which is half the time it spends in the air, making the total time about 6.1 s.

c. We saw in part (a) that

\(h = \dfrac{v^2}{2g}\)

If we halve the initial speed and replace \(v\) with \(\frac v2\), we get

\(h = \dfrac{\left(\frac v2\right)^2}{2g} = \dfrac14 \cdot \dfrac{v^2}{2g}\)

which means the max height is reduced by a factor of 1/4.

In part (b), we found the time to max height is

\(t = \dfrac{v}{g}\)

and halving the initial speed gives

\(t = \dfrac{\frac v2}g = \dfrac12 \cdot \dfrac{v}{g}\)

That is, the time to max height is reduced by a factor of 2 when the speed is halved, and so the overall time in the air is reduced by a factor of 2.

1. A 20 Ohm resistor and a 5 Ohm lamp are connected in a single path, with a 50 amps.
What type of circuit is this:
What is the total resistance of the circuit?
What is the total voltage in this circuit?
What is the current?

Answers

The circuit given is a series resistance circuit.

1) The given circuit is a series resistance circuit.

2) Resistance, R₁ = 20 Ω

Resistance, R₂ = 5 Ω

The effective resistance of the circuit is given by,

Reff = R₁ + R₂

Reff = 20 + 5

Reff = 25 Ω

3) Total resistance of the circuit, R = 25 Ω

Current flowing through the circuit, I = 50 A

Therefore, the voltage across the circuit is,

V = IR

V = 50 x 25

V = 1250 V

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The energy that a substance contains is

a. equilibrium
b. heat
c. thermal energy
d. entropy​

Answers

The energy that substance contain is. B.heat

The energy that a substance contains is known as heat. Thus, the correct option for this question is B.

What is Entropy?

Entropy may be characterized as the measurement of the degree of randomness or in other words, it is the increase in the disorganization within a system. It is the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.

Equilibrium is a state of balance between opposing forces or actions that is either static or dynamic. It symbolizes the circumstance of being balanced in nature.

Thermal energy is a type of energy that is significantly contained within a system that is responsible for its temperature. Heat is the flow of thermal energy.

Therefore, the energy that a substance contains is known as heat. Thus, the correct option for this question is B.

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suppose a car of 1200kg is moving with a velocity of 40km/hr therefore its kinetic energy is not zero. 1. explain briefly what happens to its kinetic energy when the driver applies the breaks and the car stops​

Answers

Answer:

Explanation:

For starters begin with a warning not to touch the brake drums. All of the KE is transferred to the brake drums. The result is a large rise in temperature. Heat. If you press hard on the brakes, rubber is left on the road and there is heat involved in that too.

Answer:

KInetic energy reduces.

Explanation:

Application of breaks reduces velocity. Reduction of velocity constitutes velocity reduction.

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A 5 kg ball is moving at a velocity of +2 m/s when it
speeds up to +5 m/s in 7 seconds.
Calculate the acceleration.

Answers

Heya!!

For calculate aceleration, lets applicate formula:

                                                   \(\boxed{a=\frac{V-V_o}{t} }\)

                                                   Δ   Being   Δ

                                          V = Final Velocity = 5 m/s

                                         Vo = Initial Velocity = 2 m/s

                                          a = Aceleration = ? m/s²

                                                   t = Time = 7 s

⇒ Let's replace according the formula:

\(\boxed{a=\frac{5\ m/s - 2 \ m/s}{7\ s} }\)

⇒ Resolving

\(\boxed{ a=0,428\ m/s^{2}}\)

Result:

The aceleration of the object is 0,428 m/s²

Good Luck!!

Answer:

Ksasdasd

Explanation:

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Can yall help me please

Answers

Answer:

physical

Explanation:

it is a real life model that was built

In the study of personality, what model includes different traits that underlie one’s basic tendencies

Answers

In the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

What is the Five-factor model?

The Five-factor model is a scientific theory that states traits of the personality of an individual are due to its biology and therefore they respond to adaptations, which are central in the biology field.

In conclusion, in the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

Learn more about the Five-factor model here:

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