A spring is stretched 0. 50 m and the force was 30000 N. What is the spring constant?

When the energy in a system is transformed, the total amount of energy in the system is always conserved.

The changing of one form of energy into another, or the movement of energy from one place to another. An energy transformation is a change of power from one form to another. Fire (Chemical energy Heat and Light) Electric lamp (Electrical energy Heat and Light), Microphone (Sound Electrical energy), Wave power (Mechanical energy Electrical energy). Energy transformation is also known as energy regeneration which is a process of changing energy from one form to another. Energy transformations are procedures that convert energy from one type, for example, kinetic, gravitational potential, and chemical energy.

So we can conclude that an energy transformation is the change of energy from one form to another.

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The correct answer is option D.2 years

According to Kepler's Third Law of Planetary Motion, T² is proportional to r³, where T is the period of revolution of the planet and r is the distance between the planet and the star.

In order to solve for T,  

AU = 1

Astronomical Unit = the average distance between the Earth and the Sun = 149.6 million kilometres

Therefore, the planet is orbiting at a distance of 149.6 million kilometres from the star.

Substituting the values of r and solving for

T².T² ∝ r³T² ∝ (149.6)³T²

= (149.6)³T²

= 3.522 x 10¹²T

= √3.522 x 10^¹²T

= 1.87 x 10⁶ seconds

T = 31,100 minutes

T = 518 hours

T = 21.6 days

T = 2 years

Therefore, the orbital period of the planet with twice the mass of Earth orbiting at a distance of 1 AU from a star with the same mass as the Sun is 2 years.

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Answer: To solve the problem, several physics concepts are needed. Here are the terms and their definitions:

Resistance (R): Resistance is a measure of how much a material or component opposes the flow of electric current. It is measured in ohms (Ω) and determines the amount of voltage drop across a component for a given current.

Equivalent Resistance: Equivalent resistance refers to the combined or total resistance of multiple resistors connected in a circuit. It is determined using specific formulas or techniques, such as series or parallel resistor combinations.

Current (I): Current is the flow of electric charge in a circuit. It is measured in amperes (A) and represents the rate of flow of charge through a conductor. Current is the same at all points in a series circuit and splits at junctions in a parallel circuit.

Series Circuit: A series circuit is a circuit configuration where components (such as resistors) are connected one after the other, creating a single pathway for current to flow. In a series circuit, the total resistance is the sum of individual resistances, and the current remains the same throughout the circuit.

Parallel Circuit: A parallel circuit is a circuit configuration where components are connected side by side, providing multiple pathways for current to flow. In a parallel circuit, the voltage across each component is the same, and the reciprocal of the total resistance is the sum of the reciprocals of individual resistances.

Voltage (V): Voltage, also known as electric potential difference, is the driving force that pushes electric charges through a circuit. It is measured in volts (V) and determines the flow of current in a circuit. Voltage can be calculated using Ohm's Law, which states that V = I × R, where V is voltage, I is current, and R is resistance.

Ohm's Law: Ohm's Law relates voltage (V), current (I), and resistance (R) in a circuit. It states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to the resistance of the conductor. Mathematically, Ohm's Law is expressed as V = I × R or I = V / R or R = V / I.

To solve the given problem, you would need to apply these concepts to determine the equivalent resistance (R) of the circuit and calculate the total current (I) flowing through it. The problem does not provide a specific circuit diagram, so the circuit's arrangement and connections would need to be inferred or further specified to solve it accurately.

To determine the time elapsed for a sample to reduce from 200g to 3g, we would need to know the specific half-life of the isotope in question.


The half-life of an isotope refers to the time it takes for half of a sample to decay into another element. Assuming we have the half-life information, we can use the following formula to calculate the time elapsed:
n = (log(initial mass/final mass)) / log(2)
Where n is the number of half-lives elapsed, and the initial mass and final mass are 200g and 3g, respectively.
After finding the value of n, we can then multiply it by the half-life of the isotope to find the approximate time elapsed. For example, if the half-life of the isotope was 1,000 years, and we find that 5.6 half-lives have elapsed:
5.6 x 1,000 years = 5,600 years
Approximately 5,600 years would elapse before the sample reduces from 200g to 3g. Keep in mind that this answer is dependent on the half-life of the specific isotope in question, which must be provided to accurately calculate the time elapsed.  Isotopes are atoms of an element with varying atomic masses but the same atomic number, meaning they have different numbers of neutrons but the same number of protons and, consequently, the same chemical characteristics. Radioisotopes, as well as stable and unstable isotopes, can exist.

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Unrequited love is most likely to be experienced by people with the anxious/ambivalent attachment style according to attachment theory.

Attachment theory is a psychological model that explains the dynamics of long-term relationships between humans. It is an important concept in the field of social psychology, personality psychology, and developmental psychology.The attachment style describes the relationship style and pattern between an individual and their romantic partner. There are mainly three attachment styles: avoidant, secure, and anxious/ambivalent. People with anxious/ambivalent attachment style have a high degree of emotional dependence, possessiveness, and a strong desire for closeness to their partner.

However, their insecurity and fear of rejection or abandonment often lead them to act in ways that push their partner away. This may result in unrequited love or a one-sided relationship. People with this attachment style often experience more negative emotions such as anxiety, jealousy, and depression due to their sensitivity to rejection. Hence, unrequited love is most likely to be experienced by people with the anxious/ambivalent attachment style.

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The radius of the event horizon for a black hole is measured by the Schwarzschild Radius.

Hence, the correct option is B.

The Schwarzschild Radius is a characteristic length scale associated with a non-rotating, spherically symmetric black hole.

It represents the radius of the event horizon, which is the boundary beyond which nothing, including light, can escape the gravitational pull of the black hole.

It is denoted by the symbol "rs" and is calculated based on the mass of the black hole. The Schwarzschild Radius determines the size of the event horizon and plays a crucial role in defining the properties of a black hole.

Therefore, The radius of the event horizon for a black hole is measured by the Schwarzschild Radius

Hence, the correct option is B.

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To explain the tangent plane to the surface, `z = 53 − x² − 2y²` at the point `(3, 2, 6)`, let us first determine the partial derivatives of `z` with respect to `x` and `y`.

Partial derivative of `z` with respect to `x`, `∂z/∂x = -2x`Partial derivative of `z` with respect to `y`, `∂z/∂y = -4y`Now, let's find the gradient vector `grad z` at `(3, 2, 6)` and the value of `z` at `(3, 2)`.gradient vector `grad z = (-2x, -4y, 1)`gradient vector `grad z = (-6, -8, 1)` at `(3, 2, 6)`.Value of `z` at `(3, 2)` is given by `z = 53 - 3² - 2(2)² = 39`.

Therefore, the equation of the tangent plane to the surface `

z = 53 − x² − 2y²` at `(3, 2, 6)` is:

`z - 6 = -6(x - 3) - 8(y - 2)`

which can be written as:`6x + 8y + z = 50`Thus, the equation of the tangent plane to the surface `z = 53 − x² − 2y²` at the point `(3, 2, 6)` is `6x + 8y + z = 50`.

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Her distances and displacement are;

\(\begin{array}{|l|c|c|}\mathbf{Location}&\mathbf{Displacement}&\mathbf{Distance}\\&&\\a. \ Quarter \ way \ around&\dfrac{750 \cdot \sqrt{2} }{\pi} m &375 \ m\\&&\\b. \ Half \ way \ around&\dfrac{1500}{\pi} m&750 \ m\\&& \\C. \ Three \ quarter\ way \ around&\dfrac{750 \cdot \sqrt{2} }{\pi} m&1,125 \ m\\&&\\d. \ Entire \ lap&0&1,500 \ m\\\end{array}\right]\)

The reason the above values are correct are as follows:

The known details are:

The length of the circular track, C = 1,500 m

The required details;

Her distance and displacement at four locations starting at the top of the circle, as follows;

At the top, the starting point, the displacement = The distance = 0

a. A quarter way round the track;

The radius of the circular track, r = C/(2·π)

∴ r₁ = 1,500 m/(2·π) = (750 m)/π

The displacement a quarter way round the track, s₁² = r² + r²

∴ s₁² = ((750 m)/π)² + ((750 m)/π)²

s₁ = ((750 m)/π)·√2

The displacement a quarter way round the track, s₁ = ((750·√2)/π) m

The distance a quarter way round the track, d₁ = C/4

∴ d₁ = 1,500 m/4 = 375 m

The distance a quarter way round the track, d₁ = 375 m

b. The displacement half way around the track, s₂ = r + r

∴ s₂ = r + r = (750 m)/π + (750 m)/π = (1,500 m)/π

The distance moved half way round the circular track, d₂ = C/2

∴ d₂ = 1,500 m/2 = 750 m

The distance moved half way round the circular track, d₂ = 750 m

C. The displacement 3/4 way round the track, s₃ = s₁ = (750 m)/π)·√2

The distance moved 3/4 way round the circular track, d₃ = (3/4) × 1,500 m = 1,125 m

D. The displacement for an entire lap, which is back to starting point at the TOP, s₄ = 0

The distance traveled in one lap = The circumference of the track, C = 1,500 m

Therefore, we have the following displacement and distances at the four different locations;

\(\begin{array}{|l|c|c|}\mathbf{Location}&\mathbf{Displacement}&\mathbf{Distance}\\&&\\a. \ Quarter \ way \ around&\dfrac{750 \cdot \sqrt{2} }{\pi} m &375 \ m\\&&\\b. \ Half \ way \ around&\dfrac{1500}{\pi} m&750 \ m\\&& \\C. \ Three \ quarter\ way \ around&\dfrac{750 \cdot \sqrt{2} }{\pi} m&1,125 \ m\\&&\\d. \ Entire \ lap&0&1,500 \ m\\\end{array}\right]\)

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Astronomers explain the energetic jets that come out of quasars and active galactic nuclei(AGN) in opposite directions in a way that the supermassive black holes' chaotic accretion discs "spit out" jets in directions perpendicular to the disc.

Quasar : A supermassive black hole with a mass between millions and tens of billions of solar masses that is fueled by an extraordinarily bright active galactic nucleus (AGN) and encircled by a gaseous accretion disc is known as a quasar.

An active galactic nucleus (AGN) is a compact area at the Centre of a galaxy that exhibits features that indicate the luminosity is not coming from stars and is substantially brighter than usual over at least some of the electromagnetic spectrum.

Hence, astronomers propose that the chaotic accretion discs of supermassive black holes "spit out" jets in directions perpendicular to the disc, explaining the intense jets that emerge from quasars and active galactic nuclei in different directions.

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The force of gravity upon the object located a distance of 2R above the Earth's surface is 15 Newtons.

The correct answer is option D.

To determine the force of gravity upon an object located a distance of 2R above the Earth's surface (a distance of 3R from its center), we can use the inverse square law of gravity. The force of gravity between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Let's assume that the mass of the object remains the same regardless of its position. The weight of an object is the force of gravity acting on it, so if the object weighs 30 Newton on the surface of the Earth (at a distance of R from its center), we can use this information to calculate the force of gravity at the new distance.

According to the inverse square law of gravity, the force of gravity (F) at a distance of 2R from the Earth's surface is given by:

F = (30 N) *\((R/R^2)^2\)

Simplifying this equation:

F = (30 N) * (1/R)

Now, substituting the value of 2R for R:

F = (30 N) * (1/(2R))

F = 15 N/R

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Answer:

The size (diameter) of the basketball's shadow on the wall is approximately 53.38 cm

Explanation:

The given parameters of the basketball are;

The diameter of the basketball = 23 cm (9 inches)

The distance of the light bulb from the closest side of the basketball = 3 m

The distance from the ball to the wall = 4 m

The distance from the light source to the center of the ball, d = 3 m + 0.23/2 m = 3.115 m

The angle the light ray makes with the edge of the ball, θ = arctan(0.115/3.115)

Therefore, the ratio of the shadow width divided by 2 to the distance from the light from the wall = 0.115/3.115

The distance from the light from the wall = 3 m + 4 m + 0.23 m = 7.23 m

Therefore;

((The width of the shadow)/2)/(The distance from the light from the wall) = 0.115/3.115

∴ ((The width of the shadow)/2)/(7.23 m) = 0.115/3.115

((The width of the shadow)/2) = 7.23 m × 0.115/3.115 = 16629/62300 m ≈ 0.2669 m = 26.69 cm

The width (diameter) of the shadow on the wall = 2 × 16629/62300 m ≈ 0.5338 m = 53.38 cm

The size (diameter) of the basketball's shadow on the wall ≈ 53.38 cm

Answer: Fn

Explanation: Because Fn is applying force upward

Answer:

it increases drag

Explanation:

Answer:C

Explanation:

Answer:

c is the correct one......

Answer:

w=f×s

w = 16000 J, hope this helps

To find the density of the silver, we'll first need to determine its volume. We can do this by using the apparent weight of the silver in water and the buoyant force formula.

The buoyant force equals the weight of the water displaced by the object, which is also equal to the difference between the object's actual weight and its apparent weight.
We know the apparent weight is 61.0 N and the mass of the silver is 6.88 kg. To find the actual weight, multiply the mass by the acceleration due to gravity (approximately 9.81 m/s^2):
Actual weight = 6.88 kg * 9.81 m/s^2 ≈ 67.5 N
Now, find the buoyant force:
Buoyant force = Actual weight - Apparent weight = 67.5 N - 61.0 N = 6.5 N
Next, we can find the volume of water displaced by dividing the buoyant force by the density of water (1.00 g/cm^3) and gravity (9.81 m/s^2):
Volume = (6.5 N) / (1.00 g/cm^3 * 9.81 m/s^2) ≈ 0.663 L
Since the volume of the water displaced is equal to the volume of the silver, we can now find the density of the silver by dividing its mass (6.88 kg) by its volume (0.663 L). First, convert the mass to grams:
6.88 kg * 1000 g/kg = 6880 g
Now, divide the mass by the volume:
Density = 6880 g / 0.663 L ≈ 10.38 g/cm^3
The closest answer to this value is option B, 10.5 g/cm^3.

A force that is generated upward by the water that an object displaces is known as buoyancy. It is directly proportional to the volume (weight) of water that is being displaced by an object, in accordance with Archimede's principle. Therefore, the force of buoyancy pushing an object up increases as an object displaces more water.

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From low to high frequency, a wave's wavelength increases while its frequency decreases: 0.8 km, 5 m, 7 cm, 3 m, 460 nm, and 0.02 nm. The characteristic of a wave is known as its wavelength.

A wave's wavelength is the characteristic that determines how far identical locations between two succeeding waves are separated. The Greek letter lambda () is used to represent it. Thus, the wavelength is defined as the separation between one wave's crest or trough and the following wave.

The frequency of an event is its repetitions per unit of time. As a contrast to spatial frequency, it is also sometimes referred to as temporal frequency, and as a contrast to angular frequency, it is sometimes referred to as ordinary frequency.

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Answer:

La magnitud de la masa del peso es 78.447 libras-masa.

Explanation:

La tensión es una fuerza de reacción de la cuerda causada por la acción de una fuerza externa. En este caso, esa fuerza externa es el peso que cuelga en el centro de la cuerda. Abajo hemos adjuntado una representación simplificada del enunciado.

Por las leyes de Newton, tenemos la siguiente ecuación de equilibrio conformada por tres fuerzas:

\(\vec T_{1} + \vec T_{2} + \vec W = (0, 0)\, [N]\) (1)

Donde:

\(\vec T_{1}\), \(\vec T_{2}\) - Tensiones a cada lado de la cuerda, en newtons.

\(\vec W\)- Peso, en newtons.

Si sabemos que \(\vec T_{1} = T\cdot (\cos \alpha, \sin \alpha)\), \(\vec T_{2} = T\cdot (-\cos \alpha, \sin \alpha)\) y \(\vec W = W\cdot (0, -1)\), entonces tenemos la siguiente ecuación vectorial:

\(T\cdot (\cos \alpha, \sin \alpha) + T\cdot (-\cos\alpha, \sin \alpha) + W\cdot (0, -1) = (0,0)\)

\(T\cdot (0, 2\cdot \sin \alpha) = W\cdot (0, 1)\)

Esto permite reducir la anterior expresión a una fórmula escalar:

\(2\cdot T\cdot \sin \alpha = W\)

Donde \(\alpha\) es el ángulo de inclinación de la cuerda, medido en grados sexagesimales.

El ángulo de inclinación de la cuerda se determina mediante la siguiente fórmula trigonométrica inversa es:

\(\alpha = \tan^{-1} \left(\frac{2\,ft}{10\,ft}\right)\)

\(\alpha \approx 11.310^{\circ}\)

Si conocemos que \(\alpha \approx 11.310^{\circ}\) y \(T = 200\,lbf\), entonces la magnitud del peso es:

\(W = 2\cdot (200\,lb)\cdot \sin 11.310^{\circ}\)

\(W \approx 78.447\,lbf\)

En el Sistema Imperial, las fuerzas son medidas en forma gravitacional, entonces la magnitud de la fuerza gravitacional del peso equivale a la magnitud de su masa. En síntesis, la magnitud de la masa es \(78.447\,lbm\).

La magnitud de la masa del peso es 78.447 libras-masa.

When you eat mushrooms, such as those on a pizza, most of the mass of the mushroom material that you are eating consists of water. In fact, mushrooms are approximately 90% water by weight.

This means that the nutritional content of mushrooms is relatively low, but they are still a valuable source of vitamins and minerals such as vitamin D, potassium, and selenium. Despite their high water content, mushrooms are a popular food due to their unique texture and flavor. They can be used in a variety of dishes, from salads to soups to stir-fries, and are often a vegetarian or vegan alternative to meat. It is worth noting that while mushrooms are generally safe to eat, some varieties can be toxic if consumed in large quantities. Always be sure to purchase mushrooms from a reputable source and avoid eating any that appear to be spoiled or have a strange odor or appearance.
Overall, mushrooms may not be the most nutrient-dense food, but they are still a healthy and delicious addition to any diet.

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Physical properties are used to identify and describe matter. They include

To determine the mass of granite, we must first understand the definition of density. Density is defined as the amount of matter present in a substance per unit volume.

We use the formula: density = mass/volume to calculate the mass of a substance given its density and volume. To calculate the mass of 54.3 m³ of granite, we use the following steps:

Given Density of granite = 2700 kg/m³Given volume of granite = 54.3 m³Let us substitute the values in the formula of density:density = mass/volume Solving for mass, we get:mass = density × volume Substitute the given values of density and volume into the formula:mass = 2700 kg/m³ × 54.3 m³

The m³ unit in the volume cancels out, leaving us with kg as the unit for mass.

We then solve the equation to get the mass:mass = 146,610 kg

Therefore, the mass of 54.3 m³ of granite is 146,610 kg.

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Answer: the coefficient of friction

Explanation:

The magnitude of frictional force is \(\mu\)N and the magnitude of the force is N. So if we take the ratio of it we will get  \(\mu\) In result.

The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing motion between them. Typically, the Greek letter is used to symbolize it, i.e., \(\mu\). In mathematical terms, is equal to F/N, where F represents frictional force and N represents normal force. Since both F and N are measured in units of force, the coefficient of friction is a dimensional less quantity (such as newtons or pounds).

For both static and kinetic friction, the coefficient of friction has a range of values. When an object experiences static friction, the frictional force resists any applied force, causing the object to stay at rest until the static frictional force is removed. In kinetic friction, the frictional force resists the motion of the object.

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Answer: Sexual reproduction in fungi

Explanation:

Genetic recombination is the transfer of hereditary matter between various organisms that leads to the generation of children with orders of characteristics that vary from those located in either one of the parents.

F = 20 N

m = 250 g = 0.25 Kg

a = ?

Using Newton's 2nd Law

a = F/m

a = 20/0.25

a = 80 m/s²

The acceleration of an object with a mass of 250 grams or 0.250 kg and force applied of 20N is 80m/s².

Acceleration is the rate of change of velocity of an object. Acceleration means the speed of the object is changing, but not always. When an object moves in a circular path at a constant speed rather than variable, it is still accelerating, because the direction of its velocity is changing. It is a vector quantity as it has both the magnitude and direction. The SI unit of acceleration is meter per second (m/s²).

According to the formula,

f = m × a

f = force,

m = mass of the body,

a = acceleration of the body

f = 20N

m = 250 grams = 0.250kg (1kg = 1000grams)

f = m × a

a = f/ m

a = 20N/ 0.250kg

a = 80m/s²

The acceleration of the body is 80m/s².

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Answer:

Explanation:

A simple pendulum consists of a mass (usually represented as a small object or bob) attached to a string or rod of negligible mass. The mass is free to swing back and forth under the influence of gravity.

In the figure, the point of suspension is denoted by "O," and the mass (bob) is represented by the small circle. The string or rod is represented by the vertical line connecting the point of suspension to the bob.

Amplitude:

The amplitude of a pendulum refers to the maximum displacement or swing of the bob from its equilibrium position. In the figure, the amplitude can be represented by the angle formed between the vertical position and the position of the bob when it swings to its maximum distance on one side. It is usually denoted by the symbol "A."

Effective Length:

The effective length of a pendulum refers to the distance from the point of suspension to the center of mass of the bob. It represents the distance over which the mass swings back and forth. In the figure, the effective length can be measured as the length of the string or rod from the point of suspension to the center of the bob. It is usually denoted by the symbol "L."

It is important to note that the amplitude and effective length of a simple pendulum affect its period of oscillation (the time taken for one complete swing). The relationship between these parameters and the period can be described by mathematical formulas.

Overall, the simple pendulum is a fundamental concept in physics and provides a simplified model for understanding oscillatory motion and the principles of periodic motion.

The water leaves the hose with a velocity of approximately 1.061 m/s.

To solve this problem, we can use the equation for the volume flow rate of a fluid through a pipe:

Q = A * v

where Q is the volume flow rate, A is the cross-sectional area of the pipe, and v is the velocity of the fluid.

Given that the diameter of the water hose is 2 cm, we can calculate the radius (r) and the cross-sectional area (A) of the hose:

r = diameter / 2 = 2 cm / 2 = 1 cm = 0.01 m

A = π * r^2

Using the given values, we can calculate A:

A = π * (0.01 m)^2 ≈ 0.000314 m^2

Next, we are given that it takes 1 minute to fill a 20-liter bucket. We need to convert the volume of the bucket to cubic meters:

20 liters = 20 * 10^(-3) m^3

Now, we can calculate the velocity (v) of the fluid using the formula:

v = Q / A

Since we are given the time (1 minute) and the volume (20 liters), we can calculate the volumeflow rate (Q) as follows:

Q = Volume / Time

Substituting the values, we have:

Q = (20 * 10^(-3) m^3) / (1 minute) ≈ 0.3333 * 10^(-3) m^3/s

Finally, we can calculate the velocity (v):

v = (0.3333 * 10^(-3) m^3/s) / (0.000314 m^2) ≈ 1.061 m/s

Therefore, the water leaves the hose with a velocity of approximately 1.061 m/s.

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The velocity of the two-block system at the top of the ramp is half the initial velocity of the second block. However, the force due to gravity exerted on both blocks as they travel up the ramp is not relevant to the conservation of momentum because it is a conservative force that does not affect the total momentum of the system.

The total momentum of the system before the collision is equal to the momentum of the second block, which is given by:

p = mv0

where m is the mass of each block, and v0 is the initial velocity of the second block.

After the collision, the two blocks move together with an unknown velocity vr. The total momentum of the system after the collision is:

p' = (2m)vr

where 2m is the total mass of the two blocks, and vr is the final velocity of the system.

The conservation of momentum states that the total momentum of an isolated system remains constant, provided no external forces act on it. Therefore, the total momentum of the system before the collision is equal to the total momentum of the system after the collision:

p = p'

Substituting the expressions for p and p' gives:

mv0 = (2m)vr

Simplifying gives:

vr = v0/2

The velocity of the system can be measured to confirm that the conservation of momentum applies to the system.

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