A spring with spring constant 12.8 n/m hangs from the ceiling. a ball is suspended from the spring and allowed to come to rest. it is then pulled down 4.50 cm and released. the ball makes 40.0 oscillations in 22.0 seconds.
What is its the mass of the ball?
Express your answer using two significant figures.
m = _____ g
What is its maximum speed?
Express your answer using two significant figures.
Answers
We can start by finding the period of oscillation using the given information:Number of oscillations: 40
Time: 22.0 s
The period T is given by:
T = t/N = 22.0 s/40 = 0.55 s
The angular frequency ω is:
ω = 2π/T = 2π/0.55 s = 11.4 rad/s
The amplitude A is half of the displacement, so:
A = 4.50 cm/2 = 0.0225 m
The maximum speed vmax is given by:
vmax = ωA
Substituting the values, we get:
vmax = (11.4 rad/s)(0.0225 m) = 0.257 m/s
Now, we can use the maximum speed and the spring constant k to find the mass m of the ball:
vmax = √(k/m)A
Rearranging and squaring both sides, we get:
m = kA^2/vmax^2
Substituting the values, we get:
m = (12.8 N/m)(0.0225 m)^2/(0.257 m/s)^2 = 0.053 kg
Converting to grams, we get:
m = 53 g
Therefore, the mass of the ball is 53 g and its maximum speed is 0.26 m/s.
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Related Questions
what is universe made off
Answers
Answer:
I mean, correct me if I'm wrong for some reason, but I think its Matter?
Answer:
The Universe is thought to consist of three types of substance: normal matter, 'dark matter' and 'dark energy'. Normal matter consists of the atoms that make up stars, planets, human beings and every other visible object in the Universe.
Explanation:
The hydrogen and oxygen atoms in a water molecule form a _____ bond, however, bonds between water molecules are called “hydrogen bonds”.
Answers
Explanation:
covalent.
in fact, the precise name is
polar covalent bond
because the shared electrons have even a preference and stay in their trip around the atoms in the molecule a little bit longer near the oxygen nucleus than the hydrogen ones.
making the oxygen "side" a little bit negatively charged, and the hydrogen "side" a little bit positively charged.
(a) A dc power line for a light-rail system carries \(1000 \mathrm{~A}\) at an angle of \(30.0^{\circ}\) to Earth's \(5.0 \times 10^{-5} \mathrm{~T}\) field. What is the force on a \(100-m\) section of this line? (b) Discuss practical concerns this presents, if any.
Answers
The magnetic force on the wire, is 2.5 N.
The practical concern of this is that the magnetic force on the wire can cause motor effect.
What is the magnetic force on the wire?
The magnetic force at the given section of the wire, is calculated by applying the following equation.
F = BIL sinθ
where;
I is the current in the wireL is the length of the wireθ is the orientation of the wireF = (5 x 10⁻⁵ x 1000 x 100) x sin(30)
F = 2.5 N
The practical concern of this is that the magnetic force on the wire can cause motor effect because it can interact with other magnetic field.
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This equation shows how the number of biscuits Olivia can bake is related to the amount of flour she has.
c = 15f
The variable f represents the number of scoops of flour Olivia has, and the variable c represents the number of biscuits she can bake. With 1 scoop of flour, how many biscuits can Olivia bake?
Answers
With 1 scoop of flour, Olivia can bake 15 biscuits if the the equation that shows the relation between number of biscuits and amount of flour is c = 15f.
c = 15 f
c = Number of biscuits
f = Number of scoops of flour
f = 1
c = 15 * 1
c = 15
This equation shows that number of biscuits that can be made is 15 times the number of scoops of flour. So if the number of scoops of flour is 1, the number of biscuits that can be made is 15.
Therefore, with 1 scoop of flour, Olivia can bake 15 biscuits
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Dos resistencias de 30 y 20 Ω se conectan en seria a un generador que tiene una diferencia de potencial de 20 V entre sus bornes. a. Determina la resistencia equivalente de la asociación b. Dibuja el circuito y coloca un amperímetro que indique el valor de la intensidad de la corriente y unos voltímetros que muestren la diferencia de potencial entre los extremos de las resistencias ¿Qué valores muestran estos aparatos?
Answers
Answer:
V = 12V, V = 8V
Explanation:
a) In this series circuit the equivalent resistance is
Req - R1 + R2
Req = 30 + 20
Eeq = 50 Ω
b) see attached
c) the circuit current is
i = V / Req
i = 20/50
i = 0.4 A
voltages are>
V = 0.4 30
V = 12V
V = 0.4 20
V = 8V
A train accelerates from 23m/s to 190m/s in 54 seconds. What was its acceleration?
Answers
Answer:
Use the method on the image and solve it.
The train is accelerating with an initial velocity of 23 m/s, a final velocity of 190 m/s in the time period of 54 seconds, then the acceleration will be 3.09 m/s².
What is velocity?Velocity is the measurement of a particle's or object's displacement with relation to time. The recognized unit of magnitude for velocity is the meter per second (m/s) (also known as speed).
There are several ways to show a velocity vector's direction, depending on how many dimensions are provided.
The given values in the question are,
Initial velocity, u = 23 m/s
Final velocity, v = 190 m/s and,
Time, t =54 seconds.
By putting the formula of the equation of motion :
v = u + at
190 = 23 + (a)(54)
a = 167/54
a = 3.09 m/s².
Hence, the acceleration of the train is equal to 3.09 m/s².
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The table describes the properties of four compounds.
Which compounds are most likely ionic?
compounds A and B
compounds B and C
compounds C and D
compounds D and A
Answers
Answer:
Last option
Explanation:
please help will make brainlist.
Answers
Answer:
the box should be 1 N
Explanation:
forces are equal left and right, and up and down. hope that helped, sorry if its wrong...
An unknown sample has a mass of 38.00 g and a volume of 56.39 ml. Calculate the density in g/ml. Provide your answer with 2 decimals. Show your work
Answers
The density of the unknown sample is 0.67 g/ml.
To calculate the density, we use the formula:
Density = Mass / Volume
Mass = 38.00 g
Volume = 56.39 ml
Substituting the values into the formula:
Density = 38.00 g / 56.39 ml
Dividing the mass by the volume, we find:
Density = 0.674 g/ml
Rounding to two decimal places, the density of the unknown sample is 0.67 g/ml.
Density is a measure of how much mass is contained within a given volume. In this case, we are given the mass of the unknown sample as 38.00 g and its volume as 56.39 ml. To find the density, we divide the mass by the volume. By performing the calculation, we obtain a density of 0.674 g/ml.
When rounding the value to two decimal places, the density of the unknown sample is 0.67 g/ml. This means that for every milliliter of the sample, there is 0.67 grams of mass. Density is an important property in chemistry and materials science as it can help identify substances and determine their behavior in various applications.
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3. A man hits a 0.2 kg golf ball with a force of 4
N. at what rate will the golf ball
accelerate?
Answers
Answer:
Force(f)= mass x acceleration
Acceleration (a) is the rate of change in velocity.
F=4N
M=0.2kg
a=F/M
a=4/0.2
a=20m/s^2
Explanation:
Answer:
the answer would be 20 m/s^2
Explanation:
An aeroplane accelerates uniformly from an initial velocity of 100 m.s-1 to a velocity of 200 m.s-1 in 10 seconds. It then accelerates uniformly to a final velocity of 240 m.s-1 in 20 seconds. Let the direction of motion of the aeroplane be the positive direction.
(a) Calculate the acceleration of the aeroplane during the first 10 seconds of the motion
(b) Calculate the distance the plane travels in the first 10 seconds
(c) Calculate the acceleration of the aeroplane during the next 20 seconds of its motion.
(d) Calculate the distance the plane travels in 20 seconds
Answers
Aikakajaj
The size of a balloon increases when the pressure inside it increases. The balloon gets bigger when it is left in the heat from the Sun. Why does this happen?
Answers
Explanation:
This happens because the gas inside tend to expand because its temperature gets higher.
This is why the balloon that is put in a freezer for too long tend to gets smaller, because the gas temperature that is inside the balloon decreases.
(you can try it at home)
It is related to the temperature of the gas.
a student uses 0.0821 l• atm/mol • k as the value of the gas constant. what is most likely true about the variables in the ideal gas law? p has the units of liters • atmospheres, and t has the units of kelvin. p has the units of liters • atmospheres, and t has the units of degrees celsius. v has the units of liters, and t has the units of kelvin. v has the units of liters, and t has the units of degrees celsius.
Answers
The most likely true statement about the variables in the ideal gas law is that volume (V) has the units of liters (L), and temperature (T) has the units of Kelvin (K).
In the ideal gas law, which is expressed as PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature, the units of each variable must be consistent. In this case, the gas constant value given is 0.0821 L•atm/mol•K. The units of atm and mol match with the respective variables in the ideal gas law (pressure and the number of moles), and the unit of K matches with temperature. Therefore, it is most likely that volume has the units of litres and temperature has the units of Kelvin.
It is important to note that in the given scenario, the units of pressure and temperature are not consistent with any of the options provided. Pressure is typically measured in atmospheres (atm), not litres • atmospheres, and temperature is typically measured in Kelvin (K), not degrees Celsius (°C).
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The most likely true statement about the variables in the ideal gas law is that volume (V) has the units of liters (L), and temperature (T) has the units of Kelvin (K).
In the ideal gas law, which is expressed as PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature, the units of each variable must be consistent. In this case, the gas constant value given is 0.0821 L•atm/mol•K. The units of atm and mol match with the respective variables in the ideal gas law (pressure and the number of moles), and the unit of K matches with temperature. Therefore, it is most likely that volume has the units of litres and temperature has the units of Kelvin.
It is important to note that in the given scenario, the units of pressure and temperature are not consistent with any of the options provided. Pressure is typically measured in atmospheres (atm), not litres • atmospheres, and temperature is typically measured in Kelvin (K), not degrees Celsius (°C).
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the filament of a 75-w light bulb is at a temperature of 2,600 k. assuming the filament has an emissivity e = 0.5, find its surface area.
Answers
The surface area of the filament is not directly calculable with the given information. More data, such as the dimensions or shape of the filament, is required to determine its surface area.
The temperature and emissivity only provide information about the thermal radiation emitted by the filament, not its physical characteristics. To calculate the surface area of the filament, you would need to know its shape, dimensions, and/or surface characteristics. Without these details, it is not possible to determine the surface area using just the temperature and emissivity. To find the surface area of the filament, we need to consider the Stefan-Boltzmann law, which relates the power radiated by an object to its temperature and emissivity. The equation is P = σ * A * e * T^4, where P is the power (75 W in this case), σ is the Stefan-Boltzmann constant, A is the surface area, e is the emissivity (0.5), and T is the temperature in Kelvin (2,600 K). Rearranging the equation to solve for A, we have A = P / (σ * e * T^4). Plugging in the given values, we can calculate the surface area of the filament.
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A toy car is about to roll down a track, as the car will reach its greatest speed?
Answers
Answer:
Huh????????
Explanation:
An object on a number line moved from x = 15 cm to x = 165 cm and
then moved back to x = 25 cm, all in a time of 100 seconds.
What was the average speed of the object?
Answers
Answer:
v_avg = 2.9 cm/s
Explanation:
The average velocity of the object is the sum of the distance of all its trajectories divided the time:
x_all is the total distance traveled by the object. In this case you have that the object traveled in the first trajectory 165cm-15cm = 150cm, and in the second one, 165cm - 25cm = 140cm
Then, x_all = 150cm + 140cm = 290cm
The average velocity is, for t = 100s
hence, the average velocity of the object in the total trajectory traveled is 2.9 cm/s
What is the pH of 0.25Liters of chicken soup? How about 0.5L? Is it acidic or basic?
Answers
Acidic hehe hope this helps
A stream moving with 2 m/s reaches a point where the cross-section area of the stream decreases to one-fourth of the original area. What is the water speed in this narrowed portion of the stream?
Answers
Given,
Initial speed is v=2 m/s
The cross sectional area reduces to 1/4 of the original area
To find
The speed of water at the narrowed portion.
Explanation
Let the original area be A
Let the speed at the narrowed portion be u
By conservation lawwe have,
\(\begin{gathered} v\times A=u\times\frac{1}{4}A \\ \Rightarrow2\times4=u \\ \Rightarrow u=8\text{ m/s} \end{gathered}\)Conclusion
The speed at the narrowed portion is 8 m/s
Un atleta tiene en un instante dado una velocidad de 4 m/s. Si a partir de ese instante y durante 2 s adquiere un MRUA con una aceleración de 3 m/s2. Calcula la velocidad que alcanza al cabo de esos 2 s.
Answers
Answer:
Velocidad final, V = 8 m/s
Explanation:
Dados los siguientes datos;
Velocidad inicial, u = 4 m/s
Aceleración, a = 2 m/s²
Tiempo, t = 2 segundos
Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;
V = u + at
Sustituyendo en la fórmula, tenemos;
V = 4 + 2*2
V = 4 + 4
Velocidad final, V = 8 m/s
what is the magnitude of the force provided by the third rope, in terms of θ ? A. FABCos(θ) B. 2FABCos(θ) C. 2FABSin(θ) D.FABSin(θ)
Answers
the magnitude of the force provided by the third rope, in terms of θ is 2FABCos(θ) (Option B)
What is geometry problem?Geometry problems refer to mathematical problems that involve the study of spatial relationships, shapes, sizes, and positions of objects in two or three-dimensional space. The goal of solving geometry problems is to find unknown information about a given geometric figure or to prove a theorem based on given information.
The reason behind magnitude of the force provided by the third rope is that the boat is pulled to the left in a horizontal direction by the forces' cosine component. To balance the other two ropes, a third rope can be attached from A to F.
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Complete question:
A boat owner pulls her boat into the dock shown, where there are six bollards to which to tie the boat. She has three ropes. She can tie the boat from the boat's center (A) to any of the bollards (B through G) along the dotted arrows shown.
Suppose the owner has tied three ropes: one rope runs to A from B, another to A from D, and a final rope from A to F. The ropes are tied such that FAB=FAD
What is the magnitude of the force provided by the third rope, in terms of θ?
A pile of boxes exerts a force of 500 newtons downward on the floor. The boxes are not in motion. What is the normal force on these boxes?
Answers
Answer:
Weight of the pile of boxes as I think
pls pls help me out AHH, what is not true about MEIOSIS?
A. The chromosomes in the daughter cells half the number from the parent cell.
B. The chromosomes in the daughter cells are the same number as the parents cell.
C. The only cells that will undergo meiosis will become sperm or egg cells used for reproduction.
D. The shuffling of genes happens in meiosis.
Answers
Answer:
B.
Explanation:
This is not true as the number of chromosomes in the daughter cells are half the number in the parent's cells
thorium isotope (Th^232) has a half-life of 1.4*10¹⁰ years.
a)write the radioactive decay equation.
b) find the radioactive radiation activity of 10 g of thorium
c)and the activity after 10 years
Answers
Th-232 --> He-4 + Ra-228
b) The radioactive decay constant (λ) for Thorium-232 can be calculated using the half-life formula:
t1/2 = (ln 2) / λ
Rearranging the formula, we get:
λ = (ln 2) / t1/2
λ = (ln 2) / 1.4*10^10 years = 4.95*10^-11 per year
The radioactive radiation activity (A) of 10 g of Thorium-232 can be calculated using the following formula:
A = λ * N
Where N is the number of atoms of Thorium-232 in 10 g of Thorium. The number of atoms can be calculated using Avogadro's number (6.02*10^23 atoms per mole) and the molar mass of Thorium-232 (232 g per mole):
N = (10 g / 232 g per mole) * (6.02*10^23 atoms per mole) = 2.60*10^22 atoms
Therefore, the radioactive radiation activity is:
A = 4.95*10^-11 per year * 2.60*10^22 atoms = 1.29*10^12 decays per second
c) After 10 years, the activity of Thorium-232 will decrease due to radioactive decay. The remaining activity can be calculated using the following formula:
A = A0 * e^(-λt)
Where A0 is the initial activity, λ is the decay constant, t is the time elapsed, and e is the base of the natural logarithm (2.718).
The initial activity (A0) is the activity calculated in part b:
A0 = 1.29*10^12 decays per second
The time elapsed (t) is 10 years.
Therefore, the remaining activity is:
A = A0 * e^(-λt) = 1.29*10^12 decays per second * e^(-4.95*10^-11 per year * 10 years) = 1.09*10^12 decays per second
Therefore, the activity after 10 years is 1.09*10^12 decays per second.
In the united states a standard letter sized piece of paper is 8.5 inches wide by 11 inches long. The international standard for a letter sized piece of paper is different. The international standard based on SI units:21.0cm wide by 29.7 cm long
Answers
This question is incomplete
Complete Question
In the United States, a standard letter-sized piece of paper is 8.5 inches wide by 11 inches long. The international standard for a letter-sized piece of paper is different. The international standard is based on SI units: 21.0 cm wide by 29.7 cm long.
a. Convert 21.0 cm to inches. Show your dimensional analysis setup.
b. Convert 29.7 cm to inches. Show your dimensional analysis setup.
c. State the dimensions, in inches, of the international standard for a letter-sized piece of paper.
d. Which piece of paper is longer: a U.S. letter-sized piece of paper, or an international letter-sized piece of paper?
Answer:
a) 8.267721 inches ≈ 8.3 inches
b) 11.6929197 inches ≈ 11.7 inches
c) It's dimensions in inches for the international standard for letter - sized for paper = 8.3 wide inches by 11.7 inches long
d) The International standard letter - sized paper is longer.
Explanation:
a. Convert 21.0 cm to inches. Show your dimensional analysis setup.
1 cm = 0.393701inch
21 cm =
Cross Multiply
21 cm × 0.393701inch/ 1 cm
= 8.267721 inches
Approximately 8.3 inches
b. Convert 29.7 cm to inches. Show your dimensional analysis setup.
1 cm = 0.393701inch
29.7 cm =
Cross Multiply
29.7 × 0.393701 inch/ 1 cm
= 11.6929197 inches
Approximately 11.7 inches
c. State the dimensions, in inches, of the international standard for a letter-sized piece of paper.
The international standard for a letter-sized has dimensions 21.0 cm wide by 29.7 cm long.
Where
21.0cm = 8.267721 inches
≈ 8.3 inches
29.7cm = 11.6929197 inches
≈ 11.7 inches
Hence, it's dimensions in inches = 8.3 inches by 11.7 inches.
d. Which piece of paper is longer: a U.S. letter-sized piece of paper, or an international letter-sized piece of paper?
U.S letter - sized paper = 8.5 inches wide by 11 inches long
International standard letter- sized paper = 8.3 wide inches by 11.7 inches long.
Hence, the International standard letter - sized paper is longer.
Question 4 of 32
Which vector goes from (5, 5) to (4,0)?
OA. a
B. d
C. c
D. b
Answers
The vector a, the correct answer is point D.
What is a vector?In physics, a vector is a quantity that has both magnitude and direction. It is typically represented by an arrow with the same direction as the quantity and a length proportional to the magnitude of the quantity.
We need to make the subtraction from the x, and y points. It will be the points of the head minus the points of the tail.
x=(5, 5) and y = (4,0)
Vector = ( 5 - 4, 5 - 0 )
Vector = ( 1, 0 )
Vector = R = î + 5ĵ
The vector will go to the point ( 1 , 0 ). The correct answer is point D on vector a.
The missing image is attached with the answer below.
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All the atoms/elements came from where including yourself
Answers
God created all things in the beginning of time
Explanation:
He said the things he wanted to make an they came into existence.
Im christian so if u dont like the answer or get mad i'm sorry i couldnt help you
Water flows at a speed v of 2.00 m/s through a hose of radius 3 cm and into a large empty rectangular pool. The pool has a level bottom and measures 10.0 m long by 8.00 m wide. The density of water is 1 000 kg/m 3 and atmospheric pressure is 1.01x10 5 Pa. Express all numerical answers to the following part to at least three significant figures. (a) Calculate the total pressure exerted downward on the bottom of the pool after the water has been running for 3 hours. (b) A small ball is floating in the water as the pool fills. Indicate whether the buoyant force on the floating ball increases, decreases, or stays the same as the amount of water in the pool increases. Briefly explain your reasoning.
Answers
The total pressure exerted on the bottom of the pool after the water has been running for 3 hours is 4.84 x 105 Pa. Here are the steps to solve the problem:Step 1: Calculate the volume of water that flows through the hose per second. v = 2.00 m/sr = 3 cm = 0.03 m
∴ Area of cross-section (A) = πr2= π(0.03)2= 0.00282743 m2∴ Volume of water flowing per second = V1 = A × v = 0.00282743 m2 × 2.00 m/s = 0.00565486 m3/sStep 2: Find the total volume of water that flows in 3 hours. ∴ Total volume of water in 3 hours = V2 = V1 × t = 0.00565486 m3/s × 10800 s = 61.10 m3Step 3: Calculate the mass of water that flows into the pool. Mass = Density × Volume= 1000 kg/m3 × 61.10 m3= 6.11 × 104 kgStep 4: Calculate the pressure exerted on the bottom of the pool.Pressure = Force / AreaThe weight of water is equal to the force exerted on the bottom of the pool.
∴ Weight of water = mg = Density × Volume × g= 1000 kg/m3 × 61.10 m3 × 9.81 m/s2= 6.04 × 105 NThe pressure exerted on the bottom of the pool = 6.04 × 105 N / (10.0 m × 8.00 m) = 7.55 × 103 PaNow, the atmospheric pressure is 1.01 × 105 Pa.Thus, the total pressure exerted downward on the bottom of the pool after the water has been running for 3 hours = atmospheric pressure + pressure exerted on the bottom of the pool= 1.01 × 105 Pa + 7.55 × 103 Pa = 4.84 × 105 Pa ≈ 4.84 × 105 Pa(b) The main answer is: The buoyant force on the floating ball stays the same as the amount of water in the pool increases. Explanation:As the amount of water in the pool increases, the buoyant force on the ball stays the same. This is because the buoyant force is equal to the weight of the fluid displaced by the object (Archimedes' Principle), and this weight is determined by the volume of the object. The ball's volume does not change as more water is added to the pool, so the buoyant force stays the same.
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a shopper standing 3 m from a convex security mirror sees his image with a magnification of 0.26. what is the radius of curvature (in meters) of this mirror? your answer should be a number with two decimal places, do not include unit.
Answers
The radius of curvature (R) of the convex security mirror can be calculated by using the mirror formula is found to be 2.40 m.
We can use the mirror formula, which relates the object distance (p), image distance (q), and focal length (f) of a spherical mirror as follows:
1/f = 1/p + 1/q
For a convex mirror, the focal length is negative, so we can write:
1/f = -1/p + 1/q
We also know that the magnification (M) of an image formed by a spherical mirror is given by:
M = -q/p
where a negative sign indicates that the image is inverted.
Using the given information, we can write:
M = -q/p = 0.26 and p = 3 m
Substituting these values in the magnification equation, we get:
q = M × p = 0.26 × 3 m = 0.78 m
Now, using the mirror formula, we can solve for the focal length as follows:
1/f = -1/p + 1/q = -1/3 m + 1/0.78 m
Simplifying this expression, we get:
1/f = -0.447 + 1.282
1/f = 0.835
Therefore, the focal length of the convex mirror is:
f = 1/0.835 m ≈ 1.20 m
The radius of curvature (R) of the mirror is twice the focal length, so we have:
R = 2f ≈ 2 × 1.20 m ≈ 2.40 m
Therefore, the radius of curvature of the convex security mirror is approximately 2.40 meters.
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what is the wavelength of a 1.0 mhzmhz ultrasound wave traveling through aluminum? express your answer to two significant figures and include the appropriate units.
Answers
The wavelength of a 1.0 MHz ultrasound wave traveling through aluminum is approximately 1.5 mm. To express the answer with two significant figures, we round the value to 1.5 mm
To calculate the wavelength, we can use the formula:
wavelength = speed / frequency
In this case, the frequency is given as 1.0 MHz, which is equivalent to 1.0 × 10^6 Hz. The speed of sound in aluminum is approximately 6,320 m/s.
Converting the frequency to Hz and substituting the values into the formula:
wavelength = 6,320 m/s / 1.0 × 10^6 Hz
Simplifying the equation:
wavelength = 6.32 × 10^(-3) m
To express the answer with two significant figures, we round the value to 1.5 mm (since 6.32 has two significant figures).
The wavelength of a 1.0 MHz ultrasound wave traveling through aluminum is approximately 1.5 mm.
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Velocity of an object of mass 5 kg increases from 3 m/s to 7 m/s on applying a force continuously for 2 s. Find out the force applied. If the duration for which force acts is extended to 5 s, what will be the velocity of the object then?
Answers
Answer:
Force=10N
Velocity=13m/s
Explanation:
Given,
Mass = 5kg
initial velocity=3m/s
Final velocity=7m/s
Time=2s
Now acceleration= v-u/t
=7-3/2
=4/2
=2m/s²
So, acceleration=2m/s²
Now,
F=ma
=5*2
=10N