The vector will be represent (not accurately) like the diagram below:
Now, from the expression
\(\theta=\tan ^{-1}(\frac{v_x}{v_y})\)we get the pink angle, but we need the green angle. To get the correct one we calculate the pink one and then we find its supplementary angle; let's do that:
\(\begin{gathered} \theta=\tan ^{-1}(\frac{11.1}{43}) \\ \theta=14.47 \end{gathered}\)Now, the green angle will be:
\(180-14.47=165.53\)Therefore the direction of the vector is 165.53°
a wave where particles move parallel to its energy is
Any wave in which the motion of the medium's particles is parallel to the wave's direction is referred to as a longitudinal wave.
Imagine that a slinky is stretched out horizontally across the classroom, and that the left end of the slinky receives a pulse from the left and right vibrations of the first coil. From left to right, energy will start to move through the slinky. The individual coils of the medium will be shifted left and right as the energy moves from left to right. The medium's particles in this instance travel in a direction parallel to the pulse's. A longitudinal wave is this kind of wave. Particle motion is consistently parallel to wave motion in longitudinal waves.
A well-known example of a longitudinal wave is a sound wave moving through air.
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A building with a wall 50m long by 4m high with sixty percent (60%) of the wall area occupied by 10 mm thick plate glass and the remainder is of 20 cm thick concrete blocks with solid concrete cores is being designed. If expected condition for site of the building has average dally air temperatures of 35°C and the interior temperature of the building will be kept at 25 °C by designed air conditioning syster, calculate the rate of heat transfer from outside to inside (heat load) due to this wall.
Answer: If you have "A, B, C" as answers chose the answer: "A".
Explanation:
Trust me.
A spatially challenged goldfish swims along the x-axis only. Its initial position is 7.8 m. After swimming back and forth a while, it finds itself at the position 4.4 m. Calculate the fish’s displacement (including its sign).
Answer:
The fish displacement was -3.4 m
Explanation:
Distance and Displacement
A moving object constantly travels some distance at defined periods of time. The total moved distance is the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is obtained independently of the direction the object moves.
The displacement only takes into consideration the initial and final points of the path defined by the object in its moving. The displacement, unlike distance, is a vectorial magnitude and can be even zero if the object starts and ends the movement at the same point.
The displacement, when the object moves in one axis only is given by:
d = final position - initial position
We know the fist started at 7.8 m from a given reference along the x-axis.
After some undisclosed movements, it ends up at the position 4.4 m. Thus, the displacement is:
d = 4.4 m - 7.8 m = -3.4 m
This means the fish ended up to the left of the position it started from.
The fish displacement was -3.4 m
The heat vaporization for methyl alcohol is 1100 kj/kg. It is 2257 KJ/Kg for water. Thus means that______________.
A) these are the amounts of energy to change temperature 1 degree C. required for these substances
B) Methyl alcohol requires less than half as much energy per kg to evaporate than water doe
C) water will get twice as ot as methyl alcohol during vaporization.
d) when alcohol and water evaporate they release 2,2 kj and 2257 kj of energy for every kg respectivly
Please hurry! I'm being timed!
Answer: B) Methyl alcohol requires less than half as much energy per kg to evaporate than water does
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 kilo gram of liquid into its vapor state without change in its temperature.
Heat of vaporization is more for water than for methyl alcohol which means more heat is required to convert from liquid to vapour form.
As the Heat of vaporization for methyl alcohol (1100) is almost half as that of Heat of vaporization for water (2257) , it means Methyl alcohol requires less than half as much energy per kg to evaporate than water does.
Name the type of component through which current only flows in one direction.
A 25kg box is slid across the floor using 1500J of work, how fast is the box moving?
What does your personal background mean to you?
(In the world/in your life/in your career) What ways do you see diversity celebrated around you and in what ways can we all do a better job of celebrating diversity?
If you could have dinner with any historical figure, who would you choose and why?
Can you share a fun fact about yourself?
What ways do you see diversity celebrated around you and in what ways can we all do a better job of celebrating diversity?
Ans- Visit an exhibition or a museum dedicated to other cultures.
Learn about another religion.
Plan an international movie night.
Listen to music from a different culture.
Play a game or take up a sport from a different culture (karate, cricket,
Invite a friend and cook traditional food.
If you could have dinner with any historical figure, who would you choose and why?
Ans- My younger self. Think about it. If you could have dinner with your younger self, you could easily become the smartest person in history.
Can you share a fun fact about yourself?
Ans- Yes, from 1 breadth I cam swim from 1 end to another
What makes astronomers think that impact rates for the Moon must have been higher earlier than 3.8 billion years ago?
Answer: See explanation
Explanation:
The reason why astronomers think that the rates of impact for the Moon must have been higher earlier than 3.8 billion years ago is because on the older highlands, there are ten times more craters than on the younger maria.
It is believed that the impact rate was higher earlier and thus can be seen when the numbers of the craters that can be seen on the lunar highlands is being compared to that on the maria. It should be noted that there are about 10 times more craters that can be found on the highlands than those on the maria.
If there was a constant rate of impact throughout the history of the Moon, then the highlands be about 10 times older and therefore will have been formed about 38 billion years ago.
soulve the plane polare eqestion in circular
Answer:
Explanation:
u
A 3.59 kg block is released from rest 53.0 m above the ground. When it has fallen 21.3 m, what is its kinetic energy
\(\implies\)1115.2 Joules
Given :-\(\red{\leadsto}\:\)\(\textsf{Height\: at \:rest\:} \)\(\sf,h_2= 53.0m \)
\(\green{\leadsto}\:\)\(\textsf{Height\: to\:which\;block\:}\)\(\sf,h_1= 21.3 \)
Solution :-\(\maltese\)As the block falls , the change in potential energy will be converted into kinetic energy
\(\leadsto\)Potential Energy at rest at height,\(h_2\) = \(\sf mgh_2\)
\(\leadsto\)Potential Energy when fell at height,\(h_1\) = \(\sf mgh_1\)
\(\\\)
\(\leadsto\)Kinetic energy= Change in Potential energy = = \(\sf mgh_2-mgh_1\)
\(\begin{gathered}\implies\quad \sf mg(h_2-h_1) \\\end{gathered} \)
\(\begin{gathered}\implies\quad \sf mg(53.0-21.3) \\\end{gathered} \)
\(\begin{gathered}\implies\quad \sf 3.59 \times 9.8\times (53.0-21.3) \\\end{gathered} \)
\(\begin{gathered}\implies\quad \sf 3.59 \times 9.8\times 31.7\\\end{gathered} \)
\(\begin{gathered}\implies\quad \boxed{\sf{1115.2\: Joules}}\\\end{gathered} \)
Someone help me I will mark brainless it’s 2 questions .
Answer:
1.C,2.A
Explanation:
A crate hangs from a rope that is attached to a metal ring. The metal ring is suspended by a second rope that is attached overhead at two points, as shown. What is the angle if the tension in rope 1 is 1.52 times the tension in rope 2?
Explanation:
vertical tensions in each side of rope 2
2 x mg cos Φ and this equals 1.52 tension in rope 1
2 x mg cos Φ = 1.52 mg 'divide out ' mg
2 cosΦ = 1.52
cosΦ = 1.52/2
arccos ( 1.52/2) = Φ = 40.5 degrees
why is electromagnet are called temporary magnet
pls its urgent
Answer: because when you remove the battery, the the magnet no longer has electricity flowing through it, therefore the magnetic field disappears. Thats why its called a temporary magnet
Explanation:
Two polaroids are placed at 90° to each other. What happens, when (n-1) more polaroids are inserted between them? Their axis are equally spaced. How does the transmitted intensity behave for large n?
When (n-1) polaroids are placed between, two polaroids. Total number of polaroids becomes (n-1+1+1) = (n+1). The axis of all the polaroids are equally spaced. If x is angle between the axis of the two consecutive polaroids then:
\({:\implies \quad \sf x+x+x+\cdots \cdots n\:\:times=\dfrac{\pi}{2}}\)
\({:\implies \quad \sf nx=\dfrac{\pi}{2}}\)
\({:\implies \quad \sf x=\dfrac{\pi}{2n}}\)
Now, by Malus law, we know that the intensity of light on passing through a pair of Polaroid is proportional to cos²(x). Before the light passes out of the last polaroid, this change in intensity will be repeated n times. If \({I_0}\) is intensity of the incident light and \({I}\), is the intensity of light after passing through all the polaroids, then mathematically from Malus law:
\({:\implies \quad I=I_{0}\sf \cos^{2n}(x)}\)
\({:\implies \quad I=I_{0}\sf \cos^{2n}\bigg(\dfrac{\pi}{2n}\bigg)}\)
When, n will be very large, the angle x → 0, so that the whole cosine expression → 1. So, when n will be very much large, \({I}\) will approach \({I_0}\)
Explanation:
hope it helps you
thank you
7. State condition of equilibrium when a borly is acted upon by a number of parallel forces. A uniform metal tube of length 5cm and mass 9 kg is suspended horizontally by two vertical wire attaches at 50cm and 150cm respectively from the ends of the tuber Find the tension in each wire. in tril Solution -
According to the question the tension in each wire is 1.96 N.
What is tension?Tension is a term that describes the psychological and physical state of a person or system in which there is a high degree of stress, uncertainty, and anxiety. It is often associated with conflict and is often experienced when individuals or groups feel threatened or constrained in some way. Tension can be experienced in a variety of different contexts, from interpersonal relationships to the workplace. It can result from a variety of different factors, including a lack of communication, conflicting goals or expectations, and unmet needs.
The body is in equilibrium when the sum of all forces acting on it is equal to zero. In this case, the forces acting on the metal tube are the two wires and the weight of the tube due to gravity.
The tension in each wire is equal to the weight of the tube divided by the length of the tube. This is because the tube is suspended horizontally, so the forces in each wire must be equal in order to keep the tube in equilibrium.
Therefore, the tension in each wire is:
T = (9 kg × 9.8 m/s2) / (5 cm × 0.01 m)
= 1.96 N
Therefore, the tension in each wire is 1.96 N.
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An absorption spectrum is:
a) various wavelengths emitted by an excited substance
b) a spectrum containing all wavelengths
c) the range of wavelengths emitted or absorbed by an object
d) the wavelengths that are removed from a continuous spectrum when it passes through a substance
e) a spectrum that contains only a few discrete wavelengths
What determines whether a real or a virtual image is formed from a concave mirror?
Answer:
The distance of the object from the concave mirror determines if it is a virtual or real image
Explanation:
Concave mirrors form both real and virtual images. When the concave mirror is placed very close to the object, a virtual and magnified image is obtained and if we increase the distance between the object and the mirror, the size of the image reduces and real images are formed.
A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What is the 3250 kg car’s initial velocity calculated to the nearest tenth? Record your answer in the boxes below. Be sure to use the correct place value.
Answer:
2.1 m/s
Explanation:
According to law of conservation of momentum;
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and u2 are the initial velocities
v is the common velocity
Given
m1 = 2150kg
m2 = 3250kg
u1 = 10.0m/s
u2 = ?
v = 5.22m/s
Substitute and get u2
2150(10) + 3250u2 = (2150+3250)5.22
21,500 + 3250u2 = 5400(5.22)
3250u2 = 28,188 - 21500
3250u2 = 6688
u2 = 6688/3250
u2 = 2.1 m/s
Hence the 3250 kg car’s initial velocity has an initial velocity of 2.1 m/s
1.What is the Kinetic energy of a 3 kg object moving at 4 m/s?
Plz help I’ll give points
Answer:
24 J
Explanation:
\(K = \frac{1}{2} mv^{2} = \frac{1}{2} (3kg)(4m/s)^{2} = 24 J\)
A proton enters a magnetic field (B = 5.00 x 10^-2 T INTO THE PAGE) with
a velocity of 5.60 x 10^6 m/s West. Calculate the RADIUS (in m) of the
circular path the particle will follow when it is travelling within the
magnetic field. Will it move CLOCKWISE or COUNTERCLOCKWISE? Which
HAND RULE did you use?*
Answer:
r = 1.16 m
Explanation:
It is given that,
Magnetic field, \(B=5.6\times 10^6\ m/s\)
Velocity of proton, \(v=5.6\times 10^6\ m/s\)
We need to find the radius (in m) of the circular path the particle will follow when it is travelling within the magnetic field. The radius followed by the proton is given by :
\(r=\dfrac{mv}{qB}\)
m is mass of proton, \(m=1.67\times 10^{-27}\ kg\)
So,
\(r=\dfrac{1.67\times 10^{-27}\times 5.6\times 10^6}{1.6\times 10^{-19}\times 5\times 10^{-2}}\\\\r=1.16\ m\)
So, the radius of circular path is 1.16 m.
Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next
Answer: Hope this helps ;) don't forget to rate this answer !
Explanation:
There are two correct answers:
A) A corporation leader makes direct payment to the candidate.
D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.
Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.
Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.
I hope this helps! Let me know if you have any other questions.
Which of these properties of sound is directly related to frequency?
tone
loudness
pitch
Answer:
Loudness
Explanation:
The Pitch and Tone are related to frequency because they affect how short or long the wavelength is.
A stone is dropped in a mine shaft 15 m deep. The speed of sound is 343 m/s. How long does it take to hear the echo?
It takes 0.1311 seconds to hear the echo of the stone.
How to calculate the time it takes to hear the echo of the stone.First we need to determine the time it takes for the sound wave to travel from the stone to the bottom of the mine shaft and back up to our ears.
Let's start by finding the time it takes for the sound wave to reach the bottom of the mine shaft. We can use the formula:
time = distance / speed
The distance is the depth of the mine shaft, which is 15 meters. The speed of sound is 343 m/s, as given in the problem. Therefore, the time it takes for the sound wave to reach the bottom of the mine shaft is:
time = 15 m / 343 m/s
time = 0.0437 s
Now, we need to find the time it takes for the sound wave to travel back up to our ears. Since the sound wave travels at the same speed, 343 m/s, the distance it needs to cover is twice the depth of the mine shaft, or 30 meters. Therefore, the time it takes for the sound wave to travel back up to our ears is:
time = 30 m / 343 m/s
time = 0.0874 s
Finally, to find the total time it takes to hear the echo, we add the time it takes for the sound wave to reach the bottom of the mine shaft to the time it takes to travel back up to our ears:
total time = 0.0437 s + 0.0874 s
total time = 0.1311 s
Therefore, it takes 0.1311 seconds to hear the echo of the stone.
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question is shown is in the pictures.
please solve for 100pt
The type of dispersion in the Debye model is linear.
When it is at the longer wavelength limit, the density of states is referred to as quadratic.
D(ω) = [3ω²/2π²c³] s rad⁻¹m⁻³
This has a maximum frequency ωD, known as the Debye frequency. In the three dimensions, there are 3 degrees of freedom per atom.
So, the number of phonon modes present here is 3n.
3n = (0→ωD)∫D(ω)dω
Where n is known as the atomic density of the phonon.
We know that, for a frequency that is above the Debye frequency there will be no phonon modes present.
The Debye frequency,
ω³D = 6π²nc³
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A tape diagram. 0 dollars is 0 percent. Question mark dollars is 23 percent. 52 dollars is 100 percent. Jared has earned 23% of the $52 he needs to buy a new jacket. Find 23% of $52. Which expression can you use to find 23% of 52? 23% of $52 is $ . An easy way to check your answer is to use the friendly and divide 52 by to get .
Answer:
Jared has earned 23% of the $52 he needs to buy a new jacket. Find 23% of $52.
Which expression can you use to find 23% of 52?
✔ 0.23 × 52
23% of $52 is $
✔ 11.96
.
An easy way to check your answer is to use the friendly
✔ 25%
and divide 52 by
✔ 4
to get
✔ 13
.
Explanation:
A 15 kg box is pushed with a force of 35 N in the +x direction, and the box accelerates to the right. It does not accelerate up or down
The box accelerates to the right due to the applied force of 35 N in the +x direction.
Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:
acceleration = net force / mass
acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)
Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.
Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.
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Mr. Daumer wants to create a magnet. He attaches a battery to a metal wire and
wants to wrap the wire around an object. Which object should he wrap the wire around?
a) A battery
b) A pencil
c) A ruler
d) A piece of steel metal.
what is prefixe name of 1.5×10⁴
Answer:
10000
Explanation:
10 to the 5th power
APEX: the use of seatbelts in a car has significantly reduced to the number of crash fatalities. which statement best explains how government regulations guided the development of seat-belt technology
Answer:
As the public need for preventing injuries and deaths from car crashes became known, laws were enacted to mandate the inclusion of seat belts in almost all passenger vehicles
Explanation:
Correct on Ap3x
Answer:
D
Explanation:
If the fundamental frequency of this harmonic is 7 Hz, at which frequency is this created? (Just type the number, not the units)
If the fundamental frequency of the harmonic is 7 Hz, the frequency at which it is created depends on the harmonic being referred to.
Frequency of harmonicsIf the fundamental frequency of a harmonic is 7 Hz, then the frequency at which the harmonic is created depends on the harmonic series being used.
For a harmonic series, the frequency of the nth harmonic is given by n times the fundamental frequency. Therefore, for a harmonic series starting with the fundamental frequency of 7 Hz, the first five harmonics would be:
First harmonic (fundamental): 7 HzSecond harmonic: 2 x 7 Hz = 14 HzThird harmonic: 3 x 7 Hz = 21 HzFourth harmonic: 4 x 7 Hz = 28 HzFifth harmonic: 5 x 7 Hz = 35 HzSo, the frequency at which the harmonic with a fundamental frequency of 7 Hz is created depends on which harmonic is being referred to. For example, if we're talking about the third harmonic, the frequency would be 21 Hz. If we're talking about the fifth harmonic, the frequency would be 35 Hz.
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