Which of the following descriptions best describe a liquid
A
takes the shape and volume of its container
B
matter is made of atoms so tightly packed together that they cannot move around
C
has a definite volume, but takes the shape of its container

Answer:

roughly 8-10 hours for the average human being

Explanation:

Given

Egg sinks in freshwater but floats in saturated solution of salt and water​

To find

Give reason

Explanation

We know the density of egg is more than the density of fresh water while it is less than the density of saturated solution

Thus the upward force ( upthrust) from the freshwater couldnot balance the downward for the edd and it sinks.

In case of saturated solution, the egg's downward force is less than the upward force of the saturated solution and thus it floats

Answer:

The mass of the ice added = 16.71 g

Explanation:

The heat gained by the ice is equal to the heat lost by the calorimeter cup and the water in the cup.

But for this question, the cup is said to be perfectly insulated, hence, there is no loss of heat from the calorimeter cup.

Heat gained by the ice = Heat lost by the 326 g of water.

Let the mass of ice be m

The heat gained by the ice = (Heat gained by ice in temperature from -5.5°C to 0°C) + (Heat used by the ice to melt at 0°C) + (Heat required for the melted ice to rise in temperature from 0°C to 15°C)

Heat gained by ice in temperature from -5.5°C to 0°C = mCΔT

m = unknown mass of ice

C = Specific Heat capacity of ice = 2.108 J/g°C

ΔT = change in temperature = 0 - (-5.5) = 5.5°C

Heat gained by ice in temperature from -5.5°C to 0°C = m×2.108×5.5 = (11.594m) J

Heat used by the ice to melt at 0°C = mL

m = unknown mass of ice

L = Latent Heat of fusion of ice to water = 334 J/g

Heat used by the ice to melt at 0°C = m×334 = (334m) J

Heat required for the melted ice or water now, to rise in temperature from 0°C to 15°C = mCΔT

m = unknown mass of water (which was ice)

C = Specific Heat capacity of water = 4.186 J/g°C

ΔT = change in temperature = 15 - 0 = 15°C

Heat required for the melted ice or water now, to rise in temperature from 0°C to 15°C = m×4.186×15 = (62.79m) J

Total heat gained by the ice = 11.594m + 334m + 62.79m = (408.384m) J

Heat lost by the water in the calorimeter cup = MCΔT

M = mass of water in the calorimeter cup = 326 g

C = specific heat capacity of water = 4.186 J/g°C

ΔT = change in temperature = 20 - 15 = 5°C

Heat lost by the water in the calorimeter cup = 326×4.186×5 = 6,823.18 J

Heat gained by the ice = Heat lost by the 326 g of water.

408.384m = 6,823.18

m = (6,823.18/408.384)

m = 16.71 g

Hope this Helps!!!

If you have no weight, then the acceleration due to gravity is zero.

We know that the acceleration due to gravity of the object would have to be the acceleration that would be granted to a body because it is within the sphere of the gravitational pull of the earth.

We must know that the weight of the object is the product of the mass and the acceleration due to gravity. If the object is weightless, the implication of that is that the acceleration due to gravity is zero at that point.

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Answer:

The answer is D.

Explanation:

A Hypothesis is what they think is gonna happen or n educated guess. An opinion is someone's point of view on something. A theory is an idea intended to explain something. Evidence is an object you collect to find out something and it helps support your research. Evidence matches your question best.

Mass remains mass no matter what you do to it.

Answer:

I don't know but you got this!!

Answer:

The correct answer is "121.36 meters and 2.40 MHz".

Explanation:

Given:

Red shift,

\(\frac{v}{c}=\frac{\lambda - \lambda_0}{\lambda_0} = 0.03\)

Wavelength,

\(\lambda = 125 \ meters\)

The observed frequency will be:

⇒ \(f = \frac{c}{\lambda}\)

      \(=\frac{3\times 10^8}{125}\)

      \(=24\times 10^5\)

      \(= 2.40\times 10^6\)

      \(=2.40 \ MHz\)

hence,

The Emitted wavelength will be:

⇒ \(\frac{125-\lambda_0}{\lambda_0} =0.03\)

   \(\frac{125}{\lambda_0}-1 =0.03\)

         \(125=1.03 \ \lambda_0\)

           \(\lambda_0=\frac{125}{1.03}\)

                \(=121.36 \ m\)

Answer:

No because sugar is more sweet and it would not have the benefits of salt. Think of it like how people used to put salt on meat to preserve it. Would they put sugar on? No they would not because salt is a combination of things that sugar does not have.

Explanation

The volume of the solid immersed in the liquid is  5 x 10⁻⁵ m³.

The volume of the solid is calculated as follows;

V = (Ws - Wa) / (ρg)

where;

Ws = 0.2 kg x 9.8 m/s²

Ws = 1.96 N

Wa = 0.16 kg x 9.8 m/s²

Wa = 1.568 N

ρ = 0.8 x 1000 g/km³ = 800 kg/m³

The volume is calculated as;

V = (1.96 - 1.568 )/(800 x 9.8)

V = 5 x 10⁻⁵ m³

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Answer:

A) v = √[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))]

B)√[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))] ≤ v ≤ v = √[(rg(tan θ + µ_s))/(1 - (µ_s•tan θ))]

C) µ_s = tan θ

D) µ_s = 0.4663

Explanation:

A) The forces acting on the car will be;

Force due to friction; F_f

Force due to Gravity; F_g

Normal Force; F_n

Now, let us take the vertical direction to be j^ and the direction approaching the centre to be i^ downwards and parallel to the road surface by k^.

Also, we will assume that initially, F_n is in the negative k^ direction and that it will have a maximum possible value of; F_f = µ_s × F_n

Thus, sum of forces about the vertical j^ direction gives;

ΣF_j^ = F_n•cos θ − mg + F_f•sin θ = 0

Since F_f = µ_s × F_n ;

F_n•cos θ − mg + (µ_s × F_n × sin θ) =0

F_n = mg/[cos θ + (µ_s•sin θ)]

Also, sum of forces about the centre i^ direction gives;

ΣF_i^ = F_n(sin θ + (µ_s•cos θ)) = mv²/r

Plugging in formula for F_n gives;

ΣF_i^ = [mg/[cos θ + (µ_s•sin θ)]] × (sin θ + (µ_s•cos θ)) = mv²/r

Making v the subject gives;

v = √[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))]

B) What we got in a above is the minimum speed the car can have while going round the turn.

The maximum speed will be gotten by making the frictional force(F_f) to point in the positive k^ direction. This means that F_f will be negative.

Now, if we change the sign in front of F_f in the equation in part a that led to the minimum velocity, we will have the maximum as;

v = √[(rg(tan θ + µ_s))/(1 - (µ_s•tan θ))]

Thus the range is;

√[(rg(tan θ - µ_s))/(1 + (µ_s•tan θ))] ≤ v ≤ v = √[(rg(tan θ + µ_s))/(1 - (µ_s•tan θ))]

C) For the minimum speed to be 0, it implies that F_f will be in the negative k^ direction. Thus, Sum of the forces in the k^ direction gives;

ΣF_k^ = mg(sin θ - µ_s•cos θ) = 0

Thus;

mg(sin θ - µ_s•cos θ) = 0

Making µ_s the subject gives;

µ_s = sin θ/cos θ

µ_s = tan θ

D) If θ = 25.0°;

Thus;

µ_s = tan 25

µ_s = 0.4663

The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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Complete question:

Check file uploaded for diagram of the apparatus

Answer:

The pressure of the gas inside the apparatus is 1000 mmHg

Explanation:

Given;

outside pressure, Patm = 750 mmHg

change in height of the two columns, Δh = 25 cm = 250 mm

The pressure of the gas inside the apparatus is given by;

P(gas) = P(atm) + P(Hg)

where;

P(atm) is the outside pressure

P(Hg) is the gauge pressure = height difference of the two columns.

P(gas) = 750 mmHg + 250 mmHg

P(gas) = 1000 mmHg

Therefore, the pressure of the gas inside the apparatus is 1000 mmHg

The pressure of the gas inside the apparatus is 1000 mmHg.

Since

outside pressure, Patm = 750 mmHg

change in height of the two columns, Δh = 25 cm = 250 mm

so we know that

The pressure of the gas inside the apparatus is

P(gas) = P(atm) + P(Hg)

here;

P(atm) is the outside pressure

P(Hg) is the gauge pressure = height difference of the two columns.

So,

P(gas) = 750 mmHg + 250 mmHg

P(gas) = 1000 mmHg

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Answer:

A:  magnitude and direction

B: Force that the field exerts on a test charge

C: its magnitude and direction is the same.

D: electrostatic machine

two rollers that are driven by a motor that generates a rotation

Explanation:

Answer:

Highest order: m = 1

Explanation:

Formula for solving this is;

dsin θ_m = mλ

We want to find m, thus;

m = (dsin θ_m)/λ

We are told that White light spans from 380nm - 750 nm. Thus, at maximum, λ = 750 nm.

θ_m = 90°

d = (900 lines/mm) = 9000 × 10^(-7) lines/nm

Since we want to find m, the units nm has to cancel out in the equation.

Thus, we will write d in nm/lines as (10^(7))/9000 nm/lines

Thus;

m = ((10^(7))/9000 × sin 90)/750

m = 1.48

Approximately 1

The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.

Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:

Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:

Solving for T2, we get:

Thus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

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Explanation:

1 mile = 1609m

Distance=260 miles= 418340 m

Speed= 40 m/s

Time = distance/speed

= 418340/40

=10458.5 seconds

= 2.9 hours

Answer: 3.52m/s

Explanation:

Kinetic energy is calculated as:

= 1/2mv²

where,

m = mass

v = velocity

Therefore,

775 = 1/2 × 125 × v²

775 = 62.5v²

v² = 775/62.5

v² = 12.4

v = ✓12.4

v = 3.52m/s

Answer:

Explanation:

Energy can can be transferred from one form to another in many ways,

Forms of energy that exist are Chemical Energy, Nuclear Energy

Electrical Energy Heat Energy and others.

one example is conversation of chemical energy by stove to heat energy.

Chemical energy which a form of energy that allow substance to experience chemical reaction, when a gasoline which posses chemical energy is put into stove then it convert this chemical energy to heat energy through burning which helps our food to cook as a result of heat energy gotten

According to the given statement M = 18.67 x 10⁶ Solar masses of the object that the star is orbiting.

The rate at which the position of an object shifts in any direction. Speed is defined as the ratio of the distance traveled to the time required to cover that distance. Speed is a numerical number since it just has a path and no magnitude.

Briefing:

M = Mass of Object = ?

v = orbital speed of star = 1100 km/s = 1100000 m/s

G= 6.67 x 1011 N.m2/kg is the universal gravitational constant,

r = distance between star and object = (22 light-days)(2.59 x 10¹³ m/1 light-day) = 5.698 x 10¹⁴ m

Therefore,

\(M=\frac{(1100000 \mathrm{~m} / \mathrm{s})^2\left(5.698 \times 10^{14} \mathrm{~m}\right)}{6.67 \times 10^{-11} N . \mathrm{m}^2 / \mathrm{kg}^2}\)

M = (9.39 x 10³⁷  kg)(1 solar mass/ 1.989 x 10³⁰ kg)

M = 18.67 x 10⁶ Solar masses

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The height that will illustrate the distance will be d = 6.36m

Based on the information given, the length of the vine will be:

L = ✓(16² + 27.7)²

L = 32m

The velocity of Jane when she reaches position B will be:

V = ✓2gh

V = ✓(2 × 9.8 × 4.3)

V = 9.18m/s

We will apply the conversation of momentum. This will be:

50 × 9.18 = (50 + 80)V1

V1 = 3.53m/s

Therefore, the height that will illustrate the distance will be:

31.36² + d² = 32²

d² = 32² - 31.36²

d = 6.36m

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Answer:

10 mls2

Explanation:

speed =distance /time

Answer:

hello your question is incomplete attached below is the complete question

answer : The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor  i.e. J > Jm

Explanation:

Gear ratio G > 1

a) Determine the moment of inertia felt by the motor

moment of inertia felt by Motor = moment of Inertia at the armature

b) Determine the moment of inertial felt by someone who is rotating the mass by hand

moment of inertia felt by someone is = J

The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor

attached below is a detailed solution

Answer:

true it all changes

Explanation:

________________________

Answer:

C. its thermal energy increases

Answer:

Explanation:

C

The speed of the second marble must be 14.8 m/s so that the two marbles reach the ground at the same time.

The time taken by the first stone to reach the ground is calculated using the formula below:

h = ut + ¹/₂gt²

where:

From the data provided;

h = 30, u = 10m/s, g = 9.8 m/s

30 = 10t  + 0.5 * 9.8t²

30 = 10t + 4.9t²

4.9t² + 10t - 30 = 0

t = 1.65 s

For the second marble, time taken = 1.65 - 0.50

t = 1.15 s

Initial velocity, u will be:

30 = u(1.15)  + 0.5 * 9.8 * 1.15²

1.15u = 30 - 12.96

u = 14.8 m/s

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Answer:

answer is FALSE

Explanation:

AMPLITUDE IS THE MAXIMUM AMOUNT OF DISPLACEMENT OF A PARTICLE ON THE MEDIUM FROM ITS REST POSITION

AND WAVELENGTH can be measured as crest to crest

Amplitude of a wave is the strength of the wave. It is measured from the central line of the wave to the top of the crest or bottom of the trough. Therefore, the statement is false.

Amplitude is a parameter measuring the strength of a wave. It is the maximum displacement moved by the wave from its equilibrium position. The vibrational path will be twice that of the amplitude of the wave.

As the amplitude of the wave increases its intensity increases. Both are in direct proportion with the frequency and energy of a wave. For instance the amplification of sound waves increases the intensity of waves that we hear.

The distance between two consecutive crests or troughs is the wavelength of the wave not amplitude. Amplitude is measured from the axis line to the top of the crest thus, from exact middle of the wave crest to the top or to the bottom of trough. Thus, the statement is false.

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