Define place value and explain how you could use place value to solve the equation 19 + 50 =

The simplified expression for the volume is 8x³ - 2x² - 3x. The answer is option C.

The length of the rectangular prism be x units. The width of the rectangular prism is given by the expression 2x + 1 units. The height of the rectangular prism is given by the expression 4x - 3 units. The volume of a rectangular prism is given by the formula V = lwh. Therefore the volume of the rectangular prism can be expressed as;V = x(2x + 1)(4x - 3)We can simplify this expression by using algebraic factorization. Hence;V = x(2x + 1)(4x - 3)V = x(8x² - 6x + 4x - 3)V = x(8x² - 2x - 3)V = 8x³ - 2x² - 3xHence, the simplified expression for the volume is 8x³ - 2x² - 3x. The answer is option C.

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The simplified expression is D) 8x3 + 14x2 + 3x.

Edge 2023

The simplify value of numeric expression, 3 + 2, after adding 3456 then subtracting 45 and then dividing by 20 is equals the 17.8.

We have an expression of numbers, 3 + 2 we have to apply some arithematic operations on it and determine the final simplfy value. Let the expression be x = 3 + 2, add 3456 in it

=> x = 3 + 2 + 3456

Substracts 45 from above expression

=> x = 3 + 2 + 3456 - 45

Dividing the above expression of x by 20

=>

\(\frac{ x } {20} = \frac{ 3 + 2 + 3456 - 45}{20}\)

\(= \frac{3416}{20}\)

= 17.8

Hence, required simplify value is 17.8.

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enjoy it

it best answer for you

Answer:

90

Step-by-step explanation:

Answer:

the missing angle or the missing exterior angle is 90

Step-by-step explanation:

180-90=90

Answer:

Step-by-step explanation:

Answer:

443.28

Step-by-step explanation:

Subtract 42.24 from 570.3 three times.

The absolute value of any number is always non-negative, meaning it is equal to or greater than zero. Therefore, the equation |4x - 3| = -1 has no solutions.

The equation |4x - 3| = -1 implies that the absolute value of (4x - 3) is equal to -1. However, since absolute values are always non-negative, there is no way for the absolute value of an expression to equal -1. Thus, the equation has no solutions.

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The absolute maximum value of f(x) on the interval [1, 4] is 1.5, which occurs at x = 1, and the absolute minimum value is 0.176, which occurs at x = 4.

To find the absolute maximum and minimum values of the function f(x) = 3/(x^2 + 1) on the interval [1, 4], we need to first find the critical points and then evaluate the function at the endpoints of the interval.

Critical points occur where the derivative of the function is equal to 0 or is undefined.

First, find the derivative of f(x):
f'(x) = -6x / (x^2 + 1)^2

To find the absolute maximum and minimum values of the function f(x) = 3/(x^2 + 1) on the interval [1, 4], we need to first find the critical points and the endpoints of the interval.
f'(x) = -6x/(x^2 + 1)^2 = 0

Next, we evaluate the function at the endpoints of the interval:
f(1) = 3/(1^2 + 1) = 1.5
f(4) = 3/(4^2 + 1) = 0.176
Set f'(x) to 0 and solve for x:
-6x / (x^2 + 1)^2 = 0

Since the denominator can never be 0, the only way this equation can be true is if the numerator is 0:
-6x = 0
x = 0

However, x = 0 is not in the interval [1, 4], so there are no critical points in the interval.

Now, evaluate the function at the endpoints of the interval:
f(1) = 3/(1^2 + 1) = 3/2 = 1.5
f(4) = 3/(4^2 + 1) = 3/17 ≈ 0.2

Since there are no critical points in the interval, the absolute maximum and minimum values occur at the endpoints. Thus, the absolute maximum value is 1.5 at x = 1, and the absolute minimum value is approximately 0.2 at x = 4.

Answer: Absolute maximum = 1.5 at x = 1
Absolute minimum ≈ 0.2 at x = 4

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Answer:

44

Step-by-step explanation:

Just divide 660 by 15 to get 44.

Answer:

yes because if you factor you get (x-1)^2(x+1), and then if you solve that for the roots you get 1, 1, and -1

Answer: Is true

Step-by-step explanation:

A part of a line that has 1 endpoint and extends indefinitely in only one direction is called a ray.

A ray is named using its endpoint first, and then any other point on the ray

Properties of ray:

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The co-domain of T is R2. So the correct option is: R2.

In linear algebra, a linear transformation is a function that maps vectors from one vector space to another while preserving certain properties.

In this case, the given linear transformation T takes a vector in \($\mathbb{R}^3$\) as input and outputs a vector in \($\mathbb{R}^2$\).

The notation T: \($\mathbb{R}^3$\) \($\to$\) \($\mathbb{R}^2$\) indicates that the domain of T is \($\mathbb{R}^3$\) and the co-domain (or range) is \($\mathbb{R}^2$\).

The co-domain is the set of all possible output values that can be obtained from the linear transformation.

The co-domain of a linear transformation is the set of all possible outputs that can be obtained by applying the transformation to any input.

In this case, the linear transformation T maps a vector in R3 to a vector in R2.

Therefore, the co-domain of the given linear transformation T is \($\mathbb{R}^2$\), which means that the output of T is a two-dimensional vector.

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Answer:

12 = x^2 + y^2

PLEASE BRAINLIEST?!

The equation of the circle centered at the origin has a radius of 12 is x² + y² - 144 = 0.

The circle has a diameter, the whole circumference of the circle, so the radius is the half of the diameter.

The radius of the circle given 12.

All the points on the circle you're looking for have a distance from the origin of 12/ A point's distance from the center is

The equation will be

\(\rm d = \sqrt{x^2 + y^2} \\\\ 12 = \sqrt{x^2 + y^2}\\\\12^2 = x^2 + y^2\\\\x^2 + y^2 - 144 = 0\)

Thus, the equation will be \(\rm x^2 + y^2 - 144 = 0\)

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Answer:

To find the answers, all I have to do is apply the operations (plus, minus, times, and divide) that they tell me to, in the order that they tell me to.

(f + g)(x) = f (x) + g(x)

= [3x + 2] + [4 – 5x]

= 3x + 2 + 4 – 5x

= 3x – 5x + 2 + 4

= –2x + 6

(f – g)(x) = f (x) – g(x)

= [3x + 2] – [4 – 5x]

= 3x + 2 – 4 + 5x

= 3x + 5x + 2 – 4

= 8x – 2

(f  × g)(x) = [f (x)][g(x)]

= (3x + 2)(4 – 5x)

= 12x + 8 – 15x2 – 10x

= –15x2 + 2x + 8

\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(  

g

f

​  

)(x)=  

g(x)

f(x)

​  

= \small{\dfrac{3x+2}{4-5x}}=  

4−5x

3x+2

​  

My answer is the neat listing of each of my results, clearly labelled as to which is which.

( f + g ) (x) = –2x + 6

( f – g ) (x) = 8x – 2

( f  × g ) (x) = –15x2 + 2x + 8

\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}(  

g

f

​  

)(x)=  

4−5x

3x+2

​

Step-by-step explanation:

1. nβ₀ + β₁Σxi = Σyi

β₀Σxi + β₁Σxi² = Σxiyi

These are simultaneous linear equations in β₀ and β₁. Solving these equations will give us the critical values of β₀ and β₁ that minimize the RSS. The exact solution depends on the specific values of Σxi, Σyi, Σxi², and Σxiyi.

2.  The solution depends on the specific values of Σxi, Σyi, Σ(xi - X), and Σ(xi - X)(yi - α₀ - α₁(xi - X)).

1. To derive the critical values of β₀ and β₁ that minimize the residual sum of squares (RSS) for the sample regression model Yi = β₀ + β₁X₁ + ei, we need to find the partial derivatives of the RSS with respect to β₀ and β₁ and set them equal to zero.

The RSS is defined as the sum of the squared residuals:

RSS = Σ(yi - β₀ - β₁xi)²

To find the critical values, we differentiate the RSS with respect to β₀ and β₁ separately and set the derivatives equal to zero:

∂RSS/∂β₀ = -2Σ(yi - β₀ - β₁xi) = 0

∂RSS/∂β₁ = -2Σ(xi)(yi - β₀ - β₁xi) = 0

Simplifying the above equations, we get:

Σyi - nβ₀ - β₁Σxi = 0

Σxi(yi - β₀ - β₁xi) = 0

Rearranging the equations, we have:

nβ₀ + β₁Σxi = Σyi

β₀Σxi + β₁Σxi² = Σxiyi

These are simultaneous linear equations in β₀ and β₁. Solving these equations will give us the critical values of β₀ and β₁ that minimize the RSS. The exact solution depends on the specific values of Σxi, Σyi, Σxi², and Σxiyi.

2. To derive the critical values of α₀ and α₁ that minimize the RSS for the sample regression model Yi = α₀ + α₁(Xi - X) + ei, we follow a similar approach as in the previous question.

The RSS is still defined as the sum of the squared residuals:

RSS = Σ(yi - α₀ - α₁(xi - X))²

We differentiate the RSS with respect to α₀ and α₁ separately and set the derivatives equal to zero:

∂RSS/∂α₀ = -2Σ(yi - α₀ - α₁(xi - X)) = 0

∂RSS/∂α₁ = -2Σ(xi - X)(yi - α₀ - α₁(xi - X)) = 0

Simplifying the equations, we get:

Σyi - nα₀ + α₁(Σxi - nX) = 0

Σ(xi - X)(yi - α₀ - α₁(xi - X)) = 0

Again, these are simultaneous linear equations in α₀ and α₁. Solving these equations will give us the critical values of α₀ and α₁ that minimize the RSS. The solution depends on the specific values of Σxi, Σyi, Σ(xi - X), and Σ(xi - X)(yi - α₀ - α₁(xi - X)).

In both cases, finding the exact critical values of the parameters involves solving the equations using linear algebra techniques such as matrix algebra or least squares estimation.

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Answer:

10

Step-by-step explanation:

We can use the distance formula to find the distance between the two points:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates of A and B, we get:

Distance = √((-2 - 6)^2 + (-1 - 5)^2)

Distance = √((-8)^2 + (-6)^2)

Distance = √(64 + 36)

Distance = √100

Distance = 10

Therefore, the distance between A(6, 5) and B(−2, −1) is 10 units.

Answer:

129

Step-by-step explanation:

Answer:

4 oz

Step-by-step explanation:

1:4 is the ratio for this. in total, this makes 5 oz of paint. multipy 5 by 4 to get 20 oz. multiply the 1 oz of green paint by 4 as well.

Answer:

\(\frac{27y^6}{8x^{12}}\)

Step-by-step explanation:

1) Use Product Rule: \(x^ax^b=x^{a+b}\).

\((\frac{3x^{-5+2}{y^3}}{2z^0yx}) ^3\)

2) Use Negative Power Rule: \(x^{-a}=\frac{1}{x^a}\).

\((\frac{3\times\frac{1}{x^3} y^3}{2x^0yx} )^3\)

3) Use Rule of Zero: \(x^0=1\).

\((\frac{\frac{3y^3}{x^3} }{2\times1\times yx} )^3\)

4) use Product Rule: \(x^ax^b=x^{a+b}\).

\((\frac{3y^3}{2x^{3+1}y} )^3\)

5) Use Quotient Rule: \(\frac{x^a}{x^b} =x^{a-b}\).

\((\frac{3y^{3-1}x^{-4}}{2} )^3\)

6) Use Negative Power Rule: \(x^{-a}=\frac{1}{x^a}\).

\((\frac{3y^2\times\frac{1}{x^4} }{2} )^3\)

7) Use Division Distributive Property: \((\frac{x}{y} )^a=\frac{x^a}{y^a}\).

\(\frac{(3y^2)^3}{2x^4}\)

8) Use Multiplication Distributive Property:  \((xy)^a=x^ay^a\).

\(\frac{(3^3(y^2)^3}{(2x^4)^3}\)

9) Use Power Rule: \((x^a)^b=x^{ab}\).

\(\frac{27y^6}{(2x^4)^3}\)

10)  Use Multiplication Distributive Property:  \((xy)^a=x^ay^a\).

\(\frac{26y^6}{(2^3)(x^4)^3}\)

11) Use Power Rule: \((x^a)^b=x^{ab}\).

\(\frac{27y^6}{8x^12}\)

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Answer:

\(\displaystyle \frac{27y^{6}}{8x^{12}}\)

Step-by-step explanation:

\(\displaystyle \biggr(\frac{3x^{-5}y^3x^2}{2z^0yx}\biggr)^3\\\\=\biggr(\frac{3x^{-5}y^2x}{2}\biggr)^3\\\\=\frac{(3x^{-5}y^2x)^3}{2^3}\\\\=\frac{3^3x^{-5*3}y^{2*3}x^3}{8}\\\\=\frac{27x^{-15}y^{6}x^3}{8}\\\\=\frac{27y^{6}x^3}{8x^{15}}\\\\=\frac{27y^{6}}{8x^{12}}\)

Notes:

1) Make sure when raising a variable with an exponent to an exponent that the exponents get multiplied

2) Variables with negative exponents in the numerator become positive and go in the denominator (like with \(x^{-15}\))

3) When raising a fraction to an exponent, it applies to BOTH the numerator and denominator

Hope this helped!

The specific solution depends on the given matrix A.

To find a basis for each of the subspaces r(AT), N(A), r(A), and N(AT), we first need to understand what each of these terms represents:

1. r(AT) - the row space of the transpose of matrix A
2. N(A) - the null space of matrix A
3. r(A) - the row space of matrix A
4. N(AT) - the null space of the transpose of matrix A

To find a basis for each of these subspaces, follow these general steps:

1. For r(A) and r(AT), row reduce the matrix A and its transpose AT to their row echelon forms. The non-zero rows in the reduced matrices will form a basis for the row spaces.

2. For N(A) and N(AT), set up the homogenous system of linear equations (Ax = 0 and ATx = 0), where x is the vector of variables. Then, solve the systems using Gaussian elimination, and find the general solutions. The general solutions will provide the basis vectors for the null spaces.

Note that specific solutions depend on the given matrix A. The process outlined above will help you find the basis for each of the subspaces r(AT), N(A), r(A), and N(AT) once you have the matrix A.

The correct question should be :

What is the matrix A for which you would like to find the basis for each of the subspaces r(AT), N(A), r(A), and N(AT)?

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Answer:

Option 4

Step-by-step explanation:

So we know that the area of a square is found by s^2. This means that we can just look for (6r)^2, since 6r is our side length! Let's see...We know that (6r)^2 is equal to 6^2 times r^2 because of the distributive property of exponents. Therefore, option 4 is our right answer. 36 is 6^2 and r^2 is r^2.

can u send me the question once more correctly so that I can help u

My username is Ayaan707.

^_^

Answer:

Total length of wire bought = 2 1/4 + 3 1/3

=9/4 + 10/3

=9*3/4*3 + 10*4/3*4 (LCM)

= 27/12 + 40/12

=67/12= 5 7/12metre is the answer

Ayaan707 avatar

difference btw copper and iron wire = 40/12 - 27/12

=13/12= 1 1/12 metre of copper wire

Step-by-step explanation:

HOPE IT HELPS , JENNY

The probability that the amount dispensed per box will have to be increased is 0.

To answer this question, we need to know the target amount that should be distributed per carton.

Assuming that the target amount is also 1 pound, we can use the concept of the normal distribution to estimate the likelihood that we will have to increase the amount distributed per case.

hence the probability of having to increase the amount is 0.

z = (target volume - mean) / standard deviation

z = (1 - 1) / 0.2

z = 0

A Z-score of 0 indicates that the target volume is equal to the mean. A standard normal distribution table or calculator can be used to find the probability that the amount should be increased.

However, the target amount is equal to the mean value,

In summary, without knowing the target amount to be dispensed in each case, it is not possible to determine the potential for volume increases.

If the target amount is to be £1 and the mean and standard deviation is also £1 and 0.2 respectively, then the probability of having to increase the amount is 0.

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(i)The impulse response h(t) is a quadratic function that opens downward and has roots at t = -1. (ii)Therefore, by evaluating the convolution integral with the given input signal x(t) and impulse response h(t), we can determine the output signal y(t) and sketch its graph based on the obtained expression.

i. To sketch the signals x(t) and h(t), we can analyze their mathematical expressions. The input signal x(t) is a linear function with negative slope from t = 0 to t = 4, and it is zero for t > 4. The impulse response h(t) is a quadratic function that opens downward and has roots at t = -1. We can plot the graphs of x(t) and h(t) based on these characteristics.

ii. To determine the output signal y(t), we can use the convolution integral, which is given by the expression:

y(t) = ∫[x(τ)h(t-τ)] dτ

In this case, we substitute the expressions for x(t) and h(t) into the convolution integral. By performing the convolution integral calculation, we obtain the expression for y(t) as a function of t.

To sketch the output signal y(t), we can plot the graph of y(t) based on the obtained expression. The shape of the output signal will depend on the specific values of t and the coefficients in the expressions for x(t) and h(t).

Therefore, by evaluating the convolution integral with the given input signal x(t) and impulse response h(t), we can determine the output signal y(t) and sketch its graph based on the obtained expression.

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Answer: The given vector can be expressed as a linear combination of u, v, and w as (14, 9, 14) = u - v + 3w.

Question: Express the following as a linear combination of u =(3, 1,6), v = (1.-1.4) and w=(8,3,8). (14, 9, 14) = ____ u- _____ v+ _____

Current Progress: To express the given vector as a linear combination of u, v, and w, we need to find scalars a, b, and c such that (14, 9, 14) = a*u + b*v + c*w.

Step 1: Write the equation in component form:
(14, 9, 14) = (3a + b + 8c, a - b + 3c, 6a + 4b + 8c)

Step 2: Equate the corresponding components and solve for a, b, and c:
3a + b + 8c = 14
a - b + 3c = 9
6a + 4b + 8c = 14

Step 3: Solve the system of equations using any method (substitution, elimination, etc.). One possible solution is a = 1, b = -1, and c = 3.

Step 4: Plug the values of a, b, and c back into the linear combination equation:
(14, 9, 14) = 1*u + (-1)*v + 3*w

Step 5: Simplify the equation:
(14, 9, 14) = u - v + 3w

Answer: The given vector can be expressed as a linear combination of u, v, and w as (14, 9, 14) = u - v + 3w.

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Answer:

x=20.5

Step-by-step explanation:

Perimeter of rectangle = 2(L+B)

L- Length and B - Breadth

150 = 2( 2x+4 +30)

150÷2 = 2x + 34

75 = 2x + 34

2x = 75 -34

2x = 41

x = 20.5

Answer:

a. y=x^2

Step-by-step explanation:

desmos graphing calculator