During a tensile test of a steel specimen, the strain at a stress of 35 mpa was calculated to be 0. 000 170 (point a). the strain at a stress of 134 mpa was calculated to be 0. 000 630 (point b). determine the modulus of elasticity for this material using the slope between these two points. calculate the expected stress that would correspond to a strain of 0. 000 250. the proportional limit is 200 mpa

The statement, "Some commercial trash compactor services provide the customer with a weight measurement of the compacted solid waste for every load of solid waste removed from the site.

This information enables the site environmental manager to establish waste reduction goals and track progress towards meeting the goals" is true. What is a commercial trash compactor? A commercial trash compactor is a dumpster with a large, powerful hydraulic press that compacts trash. The pressing force of the trash compactor reduces the volume of the waste, allowing it to be stored and transported more efficiently.

Commercial trash compactors are suitable for a variety of businesses, including apartment buildings, hotels, and retail establishments. Why is it important to measure waste? It's critical to keep track of the quantity of waste you produce if you want to lower waste. Measuring your waste provides information on how much you're producing, where it's coming from, and when it's being produced.

This information enables the site environmental manager to establish waste reduction goals and track progress towards meeting the goals. Conclusively, the statement is correct; some commercial trash compactor services provide the customer with a weight measurement of the compacted solid waste for every load of solid waste removed from the site.

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The option that best explains what will need to be minimized in the following scenario is energy loss. Thus, the correct option for this question is B.

A fluid power system may be characterized as a type of system that significantly has a pump driven by a prime mover (such as an electric motor or internal combustion engine) that converts mechanical energy into fluid energy.

According to the context of this question, if Walt is designing a fluid power system that will need to produce the least amount of waste possible. It would be required by the systm to reduce or eliminate the chances of energy loss in order to produce least amount of waste product.

Therefore, the option that best explains what will need to be minimized in the following scenario is energy loss. Thus, the correct option for this question is B.

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Answer:

The correct answer is energy loss

Explanation:

Answer:

genorator- electrical to mechanical

motor- mechanical to electrical

If an oil leak is discovered through soil testing, the first priority should be to locate the source of the leak and stop it immediately.

This may involve shutting down equipment or pipelines, or repairing damaged equipment or pipes.

Once the source is contained, the next step should be to pump out any remaining oil and clean up the affected area.

Applying an oil condenser or hardener may help with the cleanup process, but it should not be the first priority.

A nwtph-dx test can be performed to obtain more accurate results and determine the extent of the contamination, but it should be done after the source is contained and the cleanup process is underway.

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Answer:

true

Explanation:

true

Answer:

I believe this is true

Explanation:

If your looking at something and you look at something else everything is still in perfect view and clear, in focus.

hope this helps :)

Answer:

Deactivated Anti-Lock Braking System

Explanation:

Well this actually depends on the vehicles braking function

I'd say in this case not sure if ABS coz it prevents the vehicle from slipping while braking...

On the otherside ESP is inportant for it stability

To display the user agent in a `

` tag in the webpage, the `writeln()` method of the document object can be used. The `navigator.userAgent` property of the `window.navigator` object contains the user agent. The code below demonstrates how to do this.

To display the user agent in a `

` tag in the webpage, the following steps are required:1. Create a `

` element and assign it an id to make it easier to reference. For example, `

`2. Use the `writeln()` method of the document object to display the user agent in the `

` element. The `navigator.userAgent` property of the `window.navigator` object can be used to get the user agent. The code below demonstrates how to do this.document.writeln(`

${window.navigator.userAgent}

`);Note that the backticks (`) and ${} notation are used to interpolate the value of `window.navigator.userAgent` into the `

` element.

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Two different kinds of losses can happen in a three-phase induction motor. These losses are variable losses that are constant or fixed losses. Fixed or Constant Losses Consta.

Stator losses, including as stator iron loss and stator copper loss, are financed in part by this power input. Rotor input is provided with the leftover power, or (input electrical power - stator losses). Thus, rotor input P2 equals Pin minus stator losses (stator copper loss and stator iron loss).

Fixed losses, Copper losses, and stray losses are a few types of losses that can occur in three-phase induction motors. Core losses, bearing friction losses, brush friction losses (in wound rotor motors), and windage losses make up the majority of these losses.

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We can decompose the supplied pseudoinstruction into smaller parts and implement it with a minimal set of MIPS instructions.

Here is one conceivable application:

Use the XORI (exclusive OR immediate) instruction and the immediate value -1 to perform bit-wise inversion (not operation) on register $t2:

XORI $t2, $t2, -1

The NOR instruction can be used to carry out the following operation between registers $11 and $12 and save the outcome in $t2:

NOR $t2, $11, $12

With the assumption that $t1 holds the memory address, we can use the SW (store word) instruction to store the output of NOR into memory at address $t1:

SW $t2, 0($t1)

The NORI (NOR instant) instruction can be used to execute a NOR operation between the value in $t1 and the immediate value -12 and store the outcome in $12:

NORI $12, $t1, -12

The NOR instruction can be used to execute a NOR operation between the values in $t1 and $t2 and then store the outcome back in $t1:

NOR $t1, $t1, $t2

Thus, the bare minimum set of MIPS instructions required to execute the provided pseudoinstruction is shown here.

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Answer:

The lateral stress ratio of the soil at point A is 0.3

Explanation:

given that; Unit weight = 20 kNm⁻³ at point A 5m below the ground surface,

vertical stress (\(V_{stress}\)) = 20 kNm⁻³ × 5m ⇒ 100 kNm⁻²

vertical stress (\(V_{stress}\)) = 100kPa

note that; Horizontal Stress (\(H_{stress}\)) is given by k(\(V_{stress}\))

where "k" is the lateral stress ratio

\(H_{stress}\) = k(\(V_{stress}\))

k = \(H_{stress}\) ÷ \(V_{stress}\)

k = 30 kPa ÷ 100 kPa

k = 0.3

To determine the various characteristics of the frequency modulated (FM) signal, we can use the following formulas:

1. The average transmitted power of the FM modulated signal can be calculated using the formula:

  Average Power = (Amplitude of the modulating signal)^2 / 2

  In this case, the modulating signal is the carrier signal c(t) = 20 cos(2πfet), and the amplitude is 20. Therefore, the average transmitted power would be:

  Average Power = (20^2) / 2 = 200 mW

2. The peak-phase deviation represents the maximum change in phase from the carrier signal due to modulation. In this case, the phase function is o(t) = 10 cos(6000nt). The peak-phase deviation can be calculated by taking the maximum absolute value of the phase function, which is 10.

  Therefore, the peak-phase deviation is 10 radians.

3. The peak-frequency deviation represents the maximum change in frequency from the carrier signal due to modulation. For FM modulation, the peak-frequency deviation is related to the peak-phase deviation and the modulating frequency by the formula:

 Peak Frequency Deviation = (Peak Phase Deviation) / (2π × Modulating Frequency)

  In this case, the peak-phase deviation is 10 radians, and the modulating frequency is 6000 Hz.

  Peak Frequency Deviation = 10 / (2π × 6000) ≈ 0.0266 Hz

  Therefore, the peak-frequency deviation is approximately 0.0266 Hz.

4. The bandwidth of the FM modulated signal can be approximated using Carson's rule:

  Bandwidth ≈ 2 × (Peak Frequency Deviation + Modulating Frequency)

  In this case, the peak-frequency deviation is 0.0266 Hz, and the modulating frequency is 6000 Hz.

  Bandwidth ≈ 2 × (0.0266 + 6000) ≈ 12000.0532 Hz

  Therefore, the bandwidth of the FM modulated signal is approximately 12 kHz.

Please note that these calculations are approximations and based on simplifications. Actual FM signals may have additional factors and considerations that can affect the precise values.

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❎❎❎❎❎❎❎ sorry but that didn't help me that much

The correct answer is A text link without the <a> tag will not display correctly in the browser.

The <a> tag is an HTML element that creates a hyperlink to another web page or resource. Without this tag, the browser will not recognize the text as a link and will display it as plain text. The <a> tag requires a href attribute that specifies the destination URL of the link. It can also include additional attributes such as target to control how the link opens, and title to provide additional information about the link.tag will not display correctly in the browser.

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Modern lightweight construction presents the greatest collapse hazard among the options provided.

This type of construction is characterized by the use of lightweight and combustible materials such as wood, engineered lumber, and synthetic plastics, which can ignite and burn rapidly, leading to the loss of structural integrity and collapse. Moreover, modern lightweight buildings often have open floor plans, large void spaces, and limited fire protection measures, which increase the risk of fire spread and smoke inhalation.

Balloon construction is an obsolete method that was used in the 1800s and early 1900s, where long continuous studs were used to create the height of the building. Steel structural elements are generally considered strong and durable, but they can also fail due to various factors such as corrosion, overloading, or design errors. However, with proper maintenance and inspection, steel structures can last for a very long time without significant hazards.

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The appropriate calculation and diagram is attached.

Field notes are a type of shorthand or abbreviated notes taken by researchers, scientists, and other professionals who work in the field. Field notes can include observations, conversations, measurements, and other data that are recorded quickly and efficiently in real-time.

Field notes are typically taken using pen and paper, although they can also be recorded digitally using smartphones or other electronic devices. They are often used in qualitative research, such as ethnography, where the researcher is studying a culture or community in its natural setting.

Field notes may include descriptive details about the setting, the people being observed, their behaviors, and any other relevant information that the researcher feels is important. They may also include personal reflections and insights that the researcher has while conducting the research.

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Answer & Explanation:

i) If a student foolishly decides to binge drink 21 beers on their 21st birthday, they would consume a total of 21 x 170 = <<21*170=3570>>3570 calories of digestible energy. Since one calorie is equivalent to raising the temperature of one gram of water by one degree Celsius, and one gallon of water is equivalent to 3,785 grams, the student would have consumed enough energy to raise the temperature of 3,785 grams x 3570 calories = 13,678,950 calories of water from 24 °C to 100 °C. This means that the student could have heated 13,678,950 / 100 = <<136789500/100=136789.5>>136789.5 grams of water from room temperature to boiling, which is equivalent to 136789.5 / 3,785 = <<136789.5/3785=36.19>>36.19 gallons of water.

ii) The energy equivalent of the beer consumed by the student is 3570 calories x 4.184 joules/calorie = 14,889.48 joules. Since one BTU is equivalent to 1,055 joules, this energy is equivalent to 14,889.48 joules / 1,055 joules/BTU = <<14889.48/1055=14.15>>14.15 BTU.

iii) If the student had purchased an equivalent amount of electrical energy from the utility company, they would have to pay 14.15 kW-hr x $0.10/kW-hr = $<<14.15*0.1=1.42>>1.42. This is cheaper than buying beer, as a can of beer typically costs more than $1.42.

When the source-to-film distance was increased from 60 in. to 120 in., the geometric unsharpness was improved. This means that the image on the radiograph will be sharper and clearer, making it easier to identify any defects or issues with the weld.

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The correct answer to the question is that output directly onto a web page from JavaScript is done using the built-in function document.write().

To use the document.write() function, you simply need to pass in the content that you want to display as a string. This can be anything from simple text to HTML tags and even JavaScript code.

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Answer:

Tech A

Explanation:

Answer:

$Monitor

Explanation:

The command that would be used when running a test bench to monitor variables or signals ( i.e. changes in the values of specific variables and signa)

is the $Monitor command

This command is also used to monitor the varying values of signals during simulation.

A "calorie" is a unit of energy that is defined as the usually inform you of the number of calories of digestible energy present in one serving of food. 21 beers times 17 calories per beer equals 357 calories.

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When an engine has been diagnosed with blowby, technician B is only correct who states that the compression rings could be worn.

Engine blowby happens when a mixture of combustion gases or air-fuel leaks between the pistons and cylinder wall into the crankcase of the engine because of the lose pistons's rings. Engine blowby can occur within both gas and diesel engines. Minor levels of engine blowby are normal but excessive levels of engine blowby are an indicator of larger issues. So technician B says correctly.

While technician A is not right to say that a cracked flywheel could be a reason for the blowby engine.

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Answer:

E = 132.69 sin(ωt -11.56)

i(t) = 6.64 sin (ωt +48.44) A

Explanation:

given data

e1 = 80 sin ωt volts                       80 < 0

e2 = 60 sin (ωt + π/2) volts          60 < 90

e3 = 100 sin (ωt – π/3) volts        100 < -60

solution

resultant will be  = e2 + e2 + e3

E =  80 < 0 + 60 < 90 + 100 < -60

\(\bar E\) = 80 + j60 + 50 - j50\(\sqrt{3}\)

\(\bar E\) = 130 + (-j26.60)

\(\bar E\) = 132.69  that is less than -11.56

so

E = 132.69 sin(ωt -11.56)

and

as we have given the impedance

z = (10-j17.3)Ω

z = 19.982 < -60

and

i(t) = \(\frac{132.69}{19.982}\) sin(ωt -11.56 + 60)  

i(t) = 6.64 sin (ωt +48.44) A

Answer:

True

Explanation:

Atmospheric science is studying of the Earth's atmosphere. Meteorology includes atmospheric chemistry and atmospheric physics with a major focus on weather forecasting.

Answer:

The other person is Correct the answer is true

Explanation:

Answer:

........

....... False

The steel pipe with an inner diameter of 2.75 inches and an outer diameter of 3 inches is fixed at point C and subjected to a horizontal 60-lb force applied at the end of a pipe wrench handle. The state of stresses at point A, located on the outer surface of the pipe, needs to be determined, including the principal stresses.

Since the pipe is fixed at point C, the force applied at the end of the pipe wrench handle will induce stresses in the pipe. Considering the symmetry of the pipe, the stresses can be assumed to be uniform around its circumference.

To determine the state of stresses at point A, we can analyze the situation using basic principles of mechanics. The force applied by the pipe wrench handle will induce a tensile stress on the outer surface of the pipe and a compressive stress on the inner surface. Due to the applied force, there will also be a shearing stress acting tangentially to the pipe's circumference.

To calculate the stresses more precisely, we can utilize the concept of stress concentration factor. The change in pipe diameter from 2.75 inches to 3 inches will result in stress concentration at point A. By using appropriate formulas and equations, the actual magnitudes of tensile and compressive stresses at point A can be determined.

To find the principal stresses at point A, we need to determine the maximum and minimum stresses acting on the pipe. The principal stresses occur when the shearing stress is zero. By applying stress transformation equations and solving for the principal stresses, we can determine the values and their orientation relative to the applied force.

In conclusion, by analyzing the given parameters and employing principles of mechanics, the state of stresses in the steel pipe at point A, including the principal stresses, can be determined.

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