Use the circle graph to answer the question. A library classifies its DVDs into one of the categories shown. The library
owns 1830 DVDs.
Determine the number of comedy DVDs.
The number of comedy DVDs will be equal to 604.
What is the percentage?The percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.
Given that the total number of DVDs are 1830 and the percentage of comedy DVDs is 33%.
The number of comedy DVDs will be calculated as,
N = ( 1830 x 33%)
N = (1830 x 33 ) / 100
N = 604
Therefore, the number of comedy DVDs will be equal to 604.
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estimate each product 8 × 56.7
Answer:
465??
Step-by-step explanation:
Can like someone do this on paper???
It would be helpful is someone awake to do this if so brainlist for that person
Step-by-step explanation:
Im gonna do that now, I'm not very sure how to do it, but I'll try my best
what is the domain and range of the graph?
Answer:
Domain- {-2,0,2}
Range- {0,6,12}
Step-by-step explanation:
Answer:
Domain- {-2,0,2}
Range- {0,6,12}
Step-by-step explanation:
domain is x and range is y
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.
What is the height of BA?
Answer:
10 cm
Step-by-step explanation:
2/10=x/50
cross multiply
2*50=x*10
100÷10=x
x=10
The revenue, in thousands of dollars, of a new flavor of liquor is given below as function of the number of gallons (in hundreds), x, sold:
\(r(x) = 50x - {x}^{2} \)
What is the maximum revenue? Use units
Answer:
$625,000
Step-by-step explanation:
The maximum revenue will be found where the derivative of the revenue function is zero.
r'(x) = 50 -2x = 0
50 = 2x
x = 25
When 2500 gallons are sold, the revenue is ...
r(25) = 50(25) -25(25) = (50 -25)(25) = 25(25) = 625 . . . thousands
The maximum revenue is $625,000.
PLEASE HELP FAST!!!! IT IS URGENT!!!!!
In early 2019, the us rate of recycling plastic water bottles was only 23%. a government agency designs an expensive program to increase the recycling rate. the program will be tested in texas and, if successful, it will be used nationally. a hypothesis test is conducted with h0: the proportion of water bottles that are recycled is still 23% after the program, and ha: the proportion of water bottles that are recycled is more than 23% after the program. what is a type ii error and its consequence in this context?
A. the agency concludes that the program increases the recycling rate, when in fact it does not. the program will be implemented at great cost to the agency.
B. the agency concludes that the program does not increase the recycling rate, when in fact it does increase the rate.
C.the agency will not implement a program that could have increased the water bottle recycling rate.
D.the agency concludes that the program increases the recycling rate, when in fact it does not. the agency will not implement a program that could have increased the water bottle recycling rate.
Answer:
B. The type II error in this context is when the agency concludes that the program does not increase the recycling rate, when in fact it does increase the rate. This consequence of this error is that the agency will not implement a program that could have increased the water bottle recycling rate.
We have two geometric sequences of positive real numbers:
6,a,b and 1/b,a,54
Solve for a
The value of a is 3√2 when the two geometric sequences of positive real numbers of 6, a,b and 1/b, a,54.
A sequence of the numbers in which all the numbers are arranged in such a manner so that the ratio of two successive numbers is always constant,
The geometric progression and the constant ratio are known as the common ratio (r).
A general G.P. can be represented as:
a,ar,ar²,ar³,...............,arⁿ⁻¹,........
Where a=First term, r is the Common ratio and the n=Number of terms.
The nth term of a G.P.:
an=arⁿ⁻¹
Some of the infinite terms of a G.P.:
S∞=a/1−r
Here r<1
Let:
\(a_n=a_1q^n^-^1\\a_n_-_1=a_1q^n^-^2\\a_n_+_1=a_1q^n\)
Now multiply the last two equations:
\(a_n_-_1 a_n_+_1=a_1q^n^-^2a_1q^n\\\\a_n_-_1 a_n_+_1=a_1^2+q^n^-^2q^n\\\\a_n_-_1 a_n_+_1=a_1^2+q^n^+^n^-^2\\\\a_n_-_1 a_n_+_1=a_1^2+q^2^n^-^2\\\\a_n_-_1 a_n_+_1=a_1^2+q^2^(^n^-^1^)\\\\a_n_-_1 a_n_+_1=a_1^2+q^(^n^-^1^)^2\\\\\sqrt{a_n_-_1 a_n_+_1} =a_1^2+q^(^n^-^1^)\\\\\sqrt{a_n_-_1 a_n_+_1}=a_n\)
Formula:
\(a_n=\sqrt{a_n_-_1a_n_+_1}\)
a=√6b-----(1)
a=√1/b*54----(2)
By Equalating both equations:
6b=√1/b*54
b²=54/6
b²=9
b=3
substitute the b value in equation(1)
a=√6b
a=√6*3
a=√18
a=3√2
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A company uses a periodic inventory system. On August 1, the company had 6 items of beginning inventory with a cost of $7 per unit. On August 3, the company purchased 16 units at $14 per unit. then, on August 5, the company sold 12 units. Using FIFO, the cost of 12 units sold is ___?
The cost of 12 units sold is $126 .
What is FIFO ?FIFO is the short form for the accounting method First in First Out , The inventory that has entered first will be exited first .
It is given that
On August 1, the company had 6 items of beginning inventory with a cost of $7 per unit.
On August 3, the company purchased 16 units at $14 per unit.
on August 5, the company sold 12 units
The units that will be sold first will be the those that have taken in first
$7 * 6 + $14* 6
42 + 84
$126
Therefore the cost of 12 units sold is $126 .
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please help this is Due!!
Answer:
c=6d
Step-by-step explanation:
Use the definition of continuity and the properties of limits to show that the function is continuous at the given number (a).
f(x) = (x+3x^5)^4 , a= (-1)
 lim f(x) as x approaches -1 (x+3x^5)^4
= (lim x +3 times lim x^5)^4
= (-1 +3 (???)^5)^4 ------got stuck here
= ???
f(-1) = ??
The function\(f(x)\) is continuous at \(x = -1.\)
We must demonstrate the following to establish that the function \(f(x) = (x+3x5)4\) is continuous at \(a=-1\)
if\(x -1\), then\(f(x) = f (-1)\)
\(f(-1) = (-1 + 3(-1)^5)^4 = (-1 - 3)^4 = 16\)
The phrase \(lim x -1\)f can then be made simpler using the properties of limits (x). The formula for binomial expansion allows us to express \(f(x)\) as follows:
\(f(x)=x4 + 12 + 9 + 54 + 13 + 108 + 81\)
Next, we have
\(lim x → f(x) = -1 lim x (x4 + 12x9 + 54x13 + 108x17 + 81x21) - 1 = lim x -1 x^4 + lim x → -1 12x^9 + lim x → -1 54x^13 + lim x → -1 108x^17 + lim x → -1 81x^21 \s= (-1) (-1) ^4 + 12(-1)^9 + 54(-1)^13 + 108(-1)^17 + 81(-1)^21 \s= 1 - 12 + 54 - 108 + 81 \s= 16\)
Therefore, since \(lim x → -1 f(x) = f(-1)\), the function \(f(x)\) is continuous at\(x = -1.\)
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A veterinarian prescribes Benadryl for a dog with allergies. The recommended dosage is 3 mg per kg per day to be given in two doses. If your golden retriever weighs 67 lbs., how much Benadryl should he get in each dose? Round to nearest milligram.
Answer:
Each dose should be of 5.05 milligrams.
Step-by-step explanation:
To solve the present problem, it is necessary to first establish the equivalence between pounds and kilograms. Thus, 1 pound is equal to 0.453 kilograms. Therefore, the dog weighs about 30.35 kilograms (67 x 0.453), with which, since 3 milligrams must be applied for each kilogram of the animal's weight, 10.1 milligrams of Benadryl (30.35 / 3) should be applied.
Now, since Benadryl is applied in two doses, each of these doses should be 5.05 milligrams (10.1 / 2).
Please help I did help
The scientific notation of the expression is as follows:
(7 × 10⁻⁶) (7 × 10⁻⁶) = 4.9 × 10⁻¹¹(3.76 × 10⁵) + (7.44 × 10⁵) = 1.12 × 10⁶How to solve expression in scientific notation?The proper format for scientific notation is a x 10ᵇ where a is a number or decimal number such that the absolute value of a is greater than or equal to one and less than ten or, 1 ≤ |a| < 10.
Scientific notation is a special way of writing numbers.
The expression can be express in scientific notation as follows:
Therefore,
(7 × 10⁻⁶) (7 × 10⁻⁶)
Hence, we have to multiply the integers and add the exponents as follows:
(7 × 7) × (10⁻⁶. 10⁻⁶)
49 × 10⁻⁶⁻⁶
49 × 10⁻¹²
4.9 × 10⁻¹¹
Hence, the second can be express in scientific notation as follows:
(3.76 × 10⁵) + (7.44 × 10⁵)
(3.76 + 7.44) × 10⁵
11.2 × 10⁵
1.12 × 10⁵⁺¹
1.12 × 10⁶
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We can use the formula r = ⎷S/12.6 to relate a ball's surface area S (in square inches) to its radius r (in inches). Suppose a ball has a surface area of 403.2 square inches. What is its radius?
Round your answer to the nearest tenth.
The radius of the ball will be;
⇒ r = 5.66 inch
What is square root of a number?
A square root of a number is a value that multiplied by itself gives the same number.
Given that;
The formula is,
⇒ r = √ S / 12.6
Where, 'r' is radius and 'S' is surface area.
Now,
A ball has a surface area of 403.2 square inches.
Hence, The radius of ball is,
⇒ r = √ S / 12.6
⇒ r = √ 403.2 / 12.6
⇒ r = √32
⇒ r = 5.66 inch
Thus, The radius of the ball will be;
⇒ r = 5.66 inch
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A triangle abc has angle measurement of 45, 45 and 90 and two congruent sides is
Answer:
Step-by-step explanation:
The two congruent sides make the triangle isosceles.
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Answer:
8 cm
Step-by-step explanation:
Using the Pythagorean theorem, we can confirm that this is a right-angled triangle:
6² + 8² = 36 + 64 = 100
10² = 100
Since 6 cm and 8 cm are the lengths of the other two sides, we can use the Pythagorean theorem again to find the length of the altitude drawn from the right angle to the hypotenuse. Let h be the length of the altitude:
h² + 6² = 10²
h² = 10² - 6²
h² = 100 - 36
h² = 64
h = 8
Therefore, the length of the altitude drawn from the right angle to the hypotenuse is 8 cm.
Answer:
120 ft²
Step-by-step explanation:
first of all we need to fine the area of the triangular sides
base = 6ft
height = 4ft
formula for area of the triangle is:
½×base×height
= ½ × 6 × 4
= 3×4 = 12ft²
therefore, the area of both the triangles is (12×2) = 24ft²
area of the base of the prisim is:
length × breadth
= 6 × 6 = 36ft²
area of the other two sides
length × breadth
= 5 × 6 = 30ft²
therefore, the area of both the sides is (30×2) = 60ft²
adding up all the values we get:
24 + 36 + 60 = 120ft²
What is an example of "an enumeration of its range {aξ : ξ < α}"?
An example of "an enumeration of its range {aξ : ξ < α}" in this case would be the list of natural numbers {0, 1, 2, 3, ...}, which represents the ordinal numbers less than ω^2.
How to determine an example of "an enumeration of its range {aξ : ξ < α}"An example of "an enumeration of its range {aξ : ξ < α}" can be found in the context of ordinal numbers.
Let's consider the ordinal number α = ω^2, where ω represents the first infinite ordinal (the set of all natural numbers). In this case, the range {aξ : ξ < α} refers to the collection of all ordinal numbers that are less than α.
The ordinal numbers less than ω^2 can be enumerated as follows:
a0 = 0
a1 = 1
a2 = 2
...
an = n
...
Each natural number n corresponds to an ordinal number less than ω^2. The enumeration continues indefinitely, as there are infinitely many ordinal numbers less than ω^2.
So, an example of "an enumeration of its range {aξ : ξ < α}" in this case would be the list of natural numbers {0, 1, 2, 3, ...}, which represents the ordinal numbers less than ω^2.
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In an election, 313 votes are cast. How many votes are needed to have a majority of
the votes in this election?
Answer with a whole number of votes.
How do I answer this?
Answer:
Step-by-step explanation:
area of trapezium ABCD
=(16.5+12)/2 \times 15
=(28.5)/2 \times 15
=213.75 cm^2
\(\frac{PQ}{DC} =\frac{8}{12} =\frac{2}{3}\)
Area of PQRS
=213.75 \times (\frac{2}{3} )^2\\=213.75 \times\frac{4}{9} \\=95 ~cm^2
area of green portion=213.75-95=118.75 cm²
What is the area of the
composite figure below?
A. 29cm squared
B. 163cmc squared
C.388cm squared
D. 720cm squared
Answer:
D. 720cm squared is the answer
1. Add the following three vectors to find the resultant vector, XR:
X1 (-2,0)m, X2= (0,-5,)m, x3 = (3,0)m
We must add the relevant components of each of the three vectors, X1, X2, and X3, in order to resultant vector the final vector XR, which has the components (1, -5)m.
How can a resultant vector be located?R = A + B. Equation 2 To create the resultant vector, opposing vectors are subtracted from one another. R is the resulting vector in this case, and the column B is directed in the opposite direction to a vector A.
We must add the relevant components of each of the three vectors, X1, X2, and X3, in order to resultant vector the final vector XR, which has the components (1, -5)m.
To find the resultant vector, we need to add the corresponding components of the three given vectors. So, we have:
XR = X1 + X2 + X3
XR = (-2,0) m + (0,-5) m + (3,0) m
XR = (-2+0+3, 0+(-5)+0) m
XR = (1, -5) m
Therefore, the resultant vector XR is (1, -5) meters.
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Complete question -
Add the following three vectors to find the resultant vector, XR:
X1 = (-2,0)m, X2= (0,-5,)m, x3 = (3,0)m
Which equation is y=-6x^2+3x+2
Answer: y = 39x +2
Step-by-step explanation: -6x^2 is equal to -6x-6 which is 36x + 3x is 39x, add the 2 and you get 39x +2.
What is twenty% of 1000
Answer:
200
Step-by-step explanation:
Answer:
200
Step-by-step explanation:
Google told me that 20% of 1000 is 200
find by a digit to make the number divisible by 3 1234?
A digit to make the number divisible by 3 is by adding the digit 2 to the number 1234.
To make the number 1234 divisible by 3, we can find the sum of its digits and determine if it is divisible by 3. If the sum of the digits is divisible by 3, then the original number is also divisible by 3.
Let's calculate the sum of the digits in 1234:
1 + 2 + 3 + 4 = 10
The sum of the digits is 10. Since 10 is not divisible by 3, we need to add or subtract a digit to make the sum divisible by 3.
To find the digit we need to add or subtract, we can use the fact that the difference between the original sum and the next multiple of 3 is the required digit.
The next multiple of 3 greater than 10 is 12 (12 - 10 = 2). Therefore, we need to add 2 to the number 1234 to make it divisible by 3.
1234 + 2 = 1236
we obtain the number 1236, which is divisible by 3.
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The general form of the equation of a circle is a X squared plus BY squared plus 3X plus 3Y plus Z equals zero wear a equals B does not equal zero is the circle has a radius of three units in the center lies on the Y axis, which set of values of a B C,D and E my correspond to the circle
The set of values that corresponds to the circle with a radius of three units and the center lying on the Y axis is:
A = 1, B = 1, C = 0, D = 3, E = 0.
The general equation of a circle is given by:
x^2 + y^2 + 2gx + 2fy + c = 0
In this case, since the circle has a radius of three units and the center lies on the Y axis, we can deduce the following information:
The center of the circle lies on the Y axis, which means the x-coordinate of the center is zero.
The radius of the circle is three units, which means the distance from the center to any point on the circle is three units.
Using the information above, we can substitute the values into the general equation to solve for the corresponding values:
Substituting the x-coordinate of the center (zero) into the equation, we have:
0^2 + y^2 + 2g(0) + 2fy + c = 0
y^2 + 2fy + c = 0
Since the center lies on the Y axis, the x-coordinate is zero, so the term with x (2gx) becomes zero.
Substituting the radius of the circle (three) into the equation, we have:
(3)^2 = 9
Therefore, the equation becomes:
y^2 + 2fy + c = 9
Comparing this equation with the general form of the circle equation, we can deduce the values of A, B, C, D, and E as follows:
A = 1 (coefficient of x^2)
B = 1 (coefficient of y^2)
C = 0 (constant term)
D = 3 (coefficient of x)
E = 0 (coefficient of y)
Hence, the set of values that corresponds to the circle is A = 1, B = 1, C = 0, D = 3, and E = 0.
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please help me solve this correct answer I will give Brainlist to
13 is what percent of 24?
Answer: 3.12
Step-by-step explanation:
I need help with this
CONNECT ITUse the problem from the previous page to help you understand how to findactual lengths from a scale drawing.1 How far, in feet, are the library, town hall, and train station from the school?2 Look at the first Model It. How does the double number line show the scalefactor you can use to find an actual distance, given the distance on the map?Look at the sacond
Answer
The actual distance of the street is
Library= 875 feet
Train station = 1000 feet
Townhall = 1,125 feet
Step-by-step explanation:
The initial distance of the streets from the school is given as
Library = 3.5cm
Train station = 4cm
Townhall = 4.5cm
The scale drawing of the map is given as 2cm: 500ft
For library
The initial distance = 3.5cm
The scale drawing on the map is 2cm : 500ft
The real distance can be calculated as follows
Let the distance be l
2 = 500
3.5 = l
Cross multiply
2*l = 500 * 3.5
2l = 1750
Divide through by 2
2l/2 = 1750/2
l = 875 ft
The library is 875 feet far from school to the library
For Train station
Let the distance in feet be t
The initial distance is 4cm
2 : 500
4 : t
Cross multiply
2*t = 500 * 4
2t = 2000
Divide through by 2
2t/2 = 2000/2
t = 1000
The train station is 1000 ft far from the school
For townhall
Let h represents the distance of the town hall
The initial length is 4.5 cm
2 =500
4 = h
Cross multiply
2 * h = 4.5* 500
2h = 2250
Divide through by =
2h/2 = 2250 /2
h = 1, 125 feet