how could you confirm the missing mass dissolved in the aqueous layer?

Answer:

c. Y

Explanation:

Newton's third law of motion states that action and reaction are equal and opposite. Hence for every action, there is an equal and opposite reaction.

Considering the system of forces shown in the image, W and Y are  opposite forces. When the driver slams on the brakes, he will be pushed forward towards the windscreen. The force Y exerted by the seat belt keeps him on the drivers seat by moving him backwards towards the seat.

Answer:

2m/s²

Explanation:

F = 12 N

m = 3kg

a = ?

F = ma

a = F/m = 12/3 = 4 m/s²

when m = 6kg

a = F/m = 12/6

a = 2 m/s²

Answer:

waning crescent

Explanation:

Waxing Crescent - Rises before noon, transits meridian before sunset, sets before midnight

Answer:

new moon

Explanation:

yea im sure

can i get the brainliest? or not ok T-T im always alone i know and nobody doesnt like me so yes u are right im always alone for forever

and nobody doesnt wanna chat with me ok i got it bcoz thats all my bad im a bad person :(

Answer: 0.85 N

Explanation: We can solve this problem using the principles of buoyancy and Newton's laws.

First, we need to find the buoyant force acting on the metallic alloy block. The buoyant force is equal to the weight of the water displaced by the block, which can be calculated using the block's volume and the density of water:

V = m_block / ρ_block = 3.4 kg / 3700 kg/m³ = 0.0009189 m³

F_buoyant = ρ_water x g x V = 1000 kg/m³ x 9.8 m/s² x 0.0009189 m³ = 8.96 N

So the buoyant force acting on the metallic alloy block is 8.96 N.

Next, we can calculate the tension force in the spring scale attached to the block. Since the block is in static equilibrium, the tension force must be equal in magnitude and opposite in direction to the weight of the block plus the buoyant force:

Tension force = weight of block + buoyant force

Tension force = m_block x g + F_buoyant

Tension force = 3.4 kg x 9.8 m/s² + 8.96 N = 42.04 N

So the hanging scale reads 42.04 N.

Finally, we can find the reading of the lower scale. The lower scale measures the weight of the beaker and the water in it, minus the buoyant force acting on the beaker. The weight of the beaker and the water is:

weight of beaker + weight of water = m_beaker x g + m_water x g

weight of beaker + weight of water = 1.3 kg x 9.8 m/s² + 2.5 kg x 9.8 m/s² = 35.35 N

The buoyant force acting on the beaker can be calculated using the volume of water displaced by the beaker:

V = m_water / ρ_water = 2.5 kg / 1000 kg/m³ = 0.0025 m³

F_buoyant = ρ_water x g x V = 1000 kg/m³ x 9.8 m/s² x 0.0025 m³ = 24.5 N

So the reading of the lower scale is:

Reading of lower scale = weight of beaker + weight of water - buoyant force

Reading of lower scale = 35.35 N - 24.5 N = 10.85 N

Therefore, the lower scale reads 10.85 N.

Answer:

2

Explanation:

50 times 2

Answer:

89 i would say

Explanation:

Answer:

the answer is b

Explanation:

Answer:

b

Explanation:

I just did it on a p e x

The following statement best describes how gravity helps protoplanets create layers in that gravity pulls materials and generates compaction, which produces heat and causes materials to melt, sink, and rise. Option A is correct.

Gravitation is a natural law by which all things with all matter are attracted towards one another. gravity causes weight to all matter and the gravity of the moon causes the ocean tides.

The force that draws massed bodies toward one another is known as gravity. Gravitatithus

According to the alternatives, gravity pulls things together and causes compaction, which generates heat and causes things to melt,

Thus, we may draw the conclusion that gravity draws materials and creates compaction, which generates heat and causes materials to melt, sink, and rise.

Hence option A is correct,

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Answer:

its A

Explanation:

The projectile must be launched at an angle of 14 degrees to reach a maximum height of 4.630 m with a launch speed of 20 m/s on a planet with a free fall acceleration of 10.8 m/s².

To solve this problem, we can use the maximum height formula for a projectile,

h = (v^2 * sin^2(a)) / (2 * g)

where h is the maximum height, v is the launch speed, a is the launch angle, and g is the acceleration due to gravity.

Plugging in the given values,

4.630 = (20^2 * sin^2(a)) / (2 * 10.8)

Simplifying and solving for sin^2(a),

sin^2(a) = (4.630 * 2 * 10.8) / 400

sin^2(a) = 0.05649

Taking the square root of both sides,

sin(a) = 0.2376

To find the launch angle, we need to take the inverse sine of this value,

a = sin^-1(0.2376)

a = 13.661°

Rounding this to the nearest integer,

a = 14

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Answer:

to find the weight, use the following formula

F= m x g

in Earth---> 45 x 9.8= 441 N

in Moon---> 45 x 1.6= 72 N

Explanation:

I HOPE THIS HELPS!!! :)

The change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on Earth and Moon are 7.056kJ and 1.152kJ respectively.

Gravitational potential energy is defined as the energy possessed by or acquired by an object due to a change in its position when it is present in a gravitational field. This can be said that gravitational potential energy is the energy which is related to the gravitational force or gravitation.

Gravitational potential energy is expressed as

U=m g h

Where, U = gravitational potential energy

m = mass

g = gravitational field

h = height

For above given example,

The change in gravitational potential energy for Earth

mass= 45kg

Difference in height \((H_2-H_1)\)= 18-2= 16m

g= \(9.8m/s^2\)

U= 45*16*9.8 = 7056J or 7.056kJ

The change in gravitational potential energy for Moon

mass= 45kg

Difference in height \((H_2-H_1)\)= 18-2= 16m

g= \(1.6m/s^2\)

U= 45*16* 1.6= 1152J or 1.152kJ

Thus, the change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on Earth and Moon are 7.056kJ and 1.152kJ respectively.

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Where the mantle bursts through the crust, a plate is formed in the midst of it.

A famous example of a sizable seamount and island chain produced by hot-spot volcanism is the Hawaiian Emperor seamount chain. With a northwesterly direction, the chain's islands or submerged seamounts get older and older.

The Pacific plate, which is migrating north-west, is where the Hawaiian Islands are located. Volcanoes formed there.

The fragile and brittle asthenosphere is covered by lithosphere plates. This also applies to the Pacific plate. If access is provided via faulting or other geological conduits, the weak asthenosphere may erupt on the surface. Hotpots form on the crust as a result of these mantle magmas rising to the surface.

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The estimated average daily energy use per person for one round-trip from Phoenix to London to Phoenix is approximately 3.044 x 10¹⁰ Joules/person/day.

Assuming the round-trip from Phoenix to London to Phoenix takes 1 week and the flight time is approximately 10 hours each way, we can estimate the total energy consumption as follows:

1. According to the International Energy Agency, the average energy consumption of a long-haul flight is approximately 0.18 kWh per passenger kilometer.

2. The distance between Phoenix and London is approximately 8570 km, so the round-trip distance is approximately 17,140 km.

3. Therefore, the total energy consumption per person for the round-trip is approximately 0.18 kWh/passenger-km x 17,140 km = 3,085.2 kWh/person.

4. To convert this to Joules, we multiply by 3.6 x 10^6 (the number of Joules in 1 kWh):

3,085.2 kWh/person x 3.6 x 10⁶ J/kWh

= 1.1107 x 10¹³ Joules/person.

5. Dividing by 365 (the number of days in a year), we get an average daily energy use of approximately 3.044 x 10¹⁰ Joules/person/day.

Therefore, the estimated average daily energy use per person for one round-trip from Phoenix to London to Phoenix is approximately 3.044 x 10¹⁰ Joules/person/day.

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In the context of statistical significance, confidence intervals are used to estimate population parameters. To calculate the number of wind data she must sample to obtain a 99% confidence interval with + 1.0 kph, we can use the following formula.

N = (Zσ/E)²Where:N = The sample sizeZ = The z-score that corresponds to the desired level of confidenceσ = The standard deviationE = The margin of errorThe z-score that corresponds to the 99% confidence level is 2.576 (using a standard normal distribution table or calculator).Therefore, using the formula, the sample size that needs to be taken is:N = (Zσ/E)²N = (2.576 × 5.0 / 1.0)²N = 663.49The answer to the question, rounded to the nearest whole number, is 663. Therefore, she must sample 663 wind data to obtain a 99% confidence interval with + 1.0 kph.

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The coefficient of kinetic friction is approximately 0.102.

The  coefficient of kinetic friction is calculated by using the following formula;

frictional force = coefficient of kinetic friction x normal force

Since the object is not accelerating, we know that the force of gravity pulling down on the object is equal and opposite to the normal force pushing up on the object. Therefore, we can use the formula:

normal force = weight of the object = mass x gravity

where;

So, the normal force on the object is:

normal force = 95 kg x 9.8 m/s^2 = 931 N

Now we can substitute the values we have into the formula for coefficient of kinetic friction:

95 N = coefficient of kinetic friction x 931 N

Solving for the coefficient of kinetic friction, we get:

coefficient of kinetic friction = 95 N / 931 N ≈ 0.102

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The complete question is below:

The mass of the object is 95kg. What is the coefficient of kinetic frictions, if the frictional force is 95N.

Answer: See answers below.

Explanation: In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.

We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.

where:

W = weight [N] (units of Newtons)

m = mass = 15 [kg]

g = gravity acceleration [m/s²]

Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.

Mercury

Venus

Moon

Mars

Jupiter

Saturn

Uranus

Neptune

Pluto

In this problem, we must be clear about the concept of weight. Weight is defined as the product of mass by gravitational acceleration.

We must be clear that the mass is always preserved, that is, the mass of 15 [kg] will always be the same regardless of the planet where they are.

where:

W = weight [N] (units of Newtons)

m = mass = 15 [kg]

g = gravity acceleration [m/s²]

Since we have 9 places with different gravitational acceleration, then we calculate the weight in each of these nine places.

Mercury

Venus

Moon

Mars

Jupiter

Saturn

Uranus

Neptune

Pluto

The observed value of the total radiant energy flux density at the earth from the sun, integrated over all emission wavelengths and referred to the mean earth-sun distance, is approximately 1,366 watts per square meter.

This value is known as the solar constant and is an important factor in understanding the earth's climate and energy balance. It represents the amount of solar energy that is received per unit area at the top of the earth's atmosphere and is a key input for models of global climate change.

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Answer:

\(Q=-38.15kJ\)

Explanation:

From the question we are told that

Piston-cylinder initial Volume of air \(v_1=0.1 m^3\)

Piston-cylinder initial temperature \(T_1=400k\)

Piston-cylinder initial pressure \(P_1= 100kpa\)

Supply line temperature\(T_s=400k\)

Supply line pressure \(P_s= 500kpa\)

Valve  final pressure \(P_v=500kpa\)

Piston movement pressure \(P_m=200kpa\)

Piston-cylinder final Volume of air\(v_2=0.2 m^3\)

Piston-cylinder final temperature \(T_2=440k\)

Piston-cylinder final pressure \(P_2= 500kpa\)

Generally the  equation for conservation of mass is mathematically given by

\(Q=m_2 \mu_2-m_1 \mu_1 +W-(m_2-m_1)h\)

where

Initial moment

\(m_1=\frac{p_1 V_1}{RT_1}\)

\(m_1=\frac{100*0.1}{0.287*400}\)

\(m_1=8.7*10^-^2kg\)

Final moment

\(m_2=\frac{p_2 V_2}{RT_2}\)

\(m_1=\frac{500*0.3}{0.287*440}\)

\(m_1=79*10^{-2}kg\)

Work done by Piston movement pressure

\(W=Pd\)

\(W=P(v_2-v_1)\)

\(W=200(0.2-0.1))\)

\(W=20000J\)

Heat function

\(h=cT_1\)

\(h=1.005(400)\)

\(h=402\)

Therefore

\(Q=(0.792*0.718(440)-0.0871*0.718(400)+20-(0.792-0.087)*402))\)

\(Q=-38.15kJ\)

It is given mathematically that the system lost  or dissipated Heat of

\(Q=-38.15kJ\)

The velocity at the bottom of the swing is \(\mathbf{v= \sqrt{2gh -2gd}}\). The time it took the child to reach the river is 0.62 seconds.

The objective of this question is to determine:

At the bottom of the swing, there is an equal change in both the Kinetic energy as well as the potential energy and the expression can be computed as:

\(\mathbf{\dfrac{1}{2}mv^2 = mg (h -d)}\)

\(\mathbf{\dfrac{v^2}{2}= g (h -d)}\)

\(\mathbf{v^2= 2gh -2gd}\)

\(\mathbf{v= \sqrt{2gh -2gd}}\)

According to the second equation of motion;

\(\mathbf{S = ut +\dfrac{1}{2}at^2}\)

where;

∴

\(\mathbf{1.9 = 0(t) +\dfrac{1}{2}(9.8) t^2}\)

\(\mathbf{1.9 = \dfrac{1}{2}(9.8) t^2}\)

\(\mathbf{t^2 =\dfrac{1.9\times 2}{9.8} }}\)

\(\mathbf{t = \sqrt{\dfrac{1.9\times2}{9.8}}}\)

\(\mathbf{t =0.62 \ s}\)

Therefore, we can conclude that the velocity at the bottom of the swing is \(\mathbf{v= \sqrt{2gh -2gd}}\). The time it took the child to reach the river is 0.62 seconds.

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Whenever an object's motion varies, the pressures are out of equilibrium. Forces are balanced when they are conducted in the opposite direction and are of equal size.

Physics defines force as: The pushing and pulling that alters the velocity of a massed object. A agent with both the capacity to alter a bodies natural resting and moving condition is called as an external force. It has both a magnitude and a direction.

Force symmetry Balanced forces are those that have opposing directions and equal sizes. One definition of equilibrium is a state of balance forces. When the forces are in balance, there is really no need to alter your strategy.

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Answer: The connection between the two is that potential energy transforms into kinetic energy.

Explanation:

Answer:

R = -2500N

Explanation:

Use formula ΣF = Ma. We can split the Net Force into two parts: Fe - Ff  =  Ma.

Fe is the force developed by the engine: 4000N

Ff (R) is the air resistance projected on the vehicle. This is the value we're looking for.

Mass: 1000kg

Acceleration: 1.5m/s^2

Next, just plug in the values and solve.

▪4000N - Ff  =  (1000kg)(1.5m/s^2)

▪Ff = 1500N - 4000N

▪Ff = -2500N

R = -2500N.

The air resistance acting on the car is R = -2500N.

Part (a) The rocket's acceleration during the period from its launch until it runs out of fuel is approximately 35.15 m/s^2.

Part (b) After the rocket's engine turns off at a height of 1.35 km, the rocket's acceleration during the period from engine shutoff until it returns to the ground is approximately -9.8 m/s^2 (negative due to the downward direction).

Part (c) The maximum height that the rocket reaches is approximately 2.78 km above ground level.

Part (a):

We can use the kinematic equation to calculate the rocket's acceleration during the period from its launch until it runs out of fuel. The equation relates the final velocity (vf), initial velocity (vi), acceleration (a), and displacement (d):

vf^2 = vi^2 + 2ad

At launch, the rocket starts from rest (vi = 0), and the displacement (d) is the height reached (h = 1.35 km = 1350 m). Substituting these values and the final velocity (vf = 288 m/s) into the equation, we can solve for acceleration (a):

288^2 = 0^2 + 2a(1350)
a ≈ 35.15 m/s^2

Therefore, the rocket's acceleration during the period from its launch until it runs out of fuel is approximately 35.15 m/s^2.

Part (b):

After the rocket's engine turns off, the only force acting on it is gravity, which accelerates it downward. The acceleration due to gravity is approximately -9.8 m/s^2.

Since the rocket is moving upward, the acceleration due to gravity will act in the opposite direction. Therefore, the rocket's acceleration during the period from engine shutoff until it returns to the ground is approximately -9.8 m/s^2.

Part (c):

To calculate the maximum height reached by the rocket, we can use the kinematic equation that relates initial velocity (vi), final velocity (vf), acceleration (a), and displacement (d):

vf^2 = vi^2 + 2ad

At the maximum height, the final velocity is zero (vf = 0), and the initial velocity is the velocity reached when the engine turns off (vi = 288 m/s). The acceleration is the acceleration due to gravity (-9.8 m/s^2). Solving for displacement (d), which represents the maximum height, we have:

0^2 = (288)^2 + 2(-9.8)d
d ≈ 2778.6 m

Therefore, the maximum height reached by the rocket is approximately 2.78 km above ground level.

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Answer:

In a wheelbarrow, the load is in the middle. The fulcrum is at the end where the wheels touch the ground. The effort is applied at the other end where we hold the wheelbarrow. So, it is classified as a class 2 lever.

Explanation:

Btw, you spelled liver, not lever. Anyway, hope this helped you! The answer is underlined.

The speed of the rock halfway down 17.3 m/s  (b) 19.4 m/s

To solve this problem, we can use the principles of conservation of energy to find the speed of the rock at different points during its fall.

First, we can calculate the potential energy of the rock when it is at the top of its fall:

PE = mgh = 1.50 kg ˣ 9.81 \(m/s^2\) ˣ 30 m = 441.45 J

Since there is no air resistance, this potential energy will be converted entirely into kinetic energy as the rock falls.

PE = KE

mgh = (1/2)\(mv^2\)

v = sqrt(2gh) = sqrt(2 ˣ 9.81 \(m/s^2\) ˣ 15 m) = 17.15 m/s

Therefore, the speed of the rock halfway down is 17.15 m/s.

so we can again set these two values equal to each other and solve for the speed:

PE = KE

mgh = (1/2)\(mv^2\)

v = sqrt(2gh) = sqrt(2 ˣ 9.81 \(m/s^2\) ˣ 30 m) = 19.42 m/s

Therefore, the speed of the rock when it reaches the ground is 19.42 m/s.

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(a) The budget constraint can be written as: C = wL + V, where C is consumption, w is the real wage, L is leisure, and V is non-labor market income.

(b) With ẞ = 1/2, V = 100, and w = 200, John's optimal supply of labor cannot be determined without information about his preferences for leisure and consumption. The utility function only represents his preferences, but we need additional information to determine the specific amount of labor he would choose to supply.

(c) John's total income is the sum of his labor income and non-labor market income: Total income = Labor income + Non-labor income = wL + V. Without knowing the specific value of L, we cannot calculate the total income.

(d) Similarly, without knowing John's preferences for leisure and consumption, we cannot determine the specific level of consumption he would choose.

(e) In the case where John is subject to a 10% income tax on labor income only, his new optimal supply of labor would depend on the tax rate's impact on his preferences and the trade-off between leisure and consumption. Without further information on his preferences and the specific tax structure, we cannot determine the new optimal supply of labor.

Additional information about John's preferences for leisure and consumption, as well as the specific tax structure, is necessary to calculate his optimal labor supply, total income, consumption, and the impact of the income tax on his labor supply.

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The branch of physics and technology concerned with the design of circuits using transistors and microchips, and with the behavior and movement of electrons in a semiconductor, conductor, vacuum, or gas is known as electronics.

In electronics, the essential elements of the circuit include transistors, diodes, capacitors, and resistors. Furthermore, microchips are made of semiconducting materials, including silicon, germanium, and gallium arsenide, that are designed with the ability to control the flow of electrons. Circuits have a wide range of applications, including telecommunications, information processing, and control systems. Electronics has made our lives easier and more comfortable by providing us with a wide range of devices such as smartphones, computers, televisions, and other digital products.

Electrons in these devices are manipulated by microchips and transistors to perform specific functions, including communication, calculation, and display.The development of electronics has revolutionized the way we live, work, and interact with the world around us. The miniaturization of circuits has led to the creation of smaller and more portable devices, making electronics more accessible and affordable for people around the world. Overall, electronics has transformed our world and will continue to shape our future.

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Answer:

Answer:- Volume of the balloon is 5.78 L.

Solution:- There are 0.24 moles of hydrogen gas in a balloon at 35 degree C and 1.05 atm pressure. It asks to calculate the volume of the balloon.

This problem is based on ideal gas law equation:

P = 1.05 atm, n = 0.24 mole, T = 35 + 273 = 308 K

R =

V = ?

The equation could be rearranged for the volume as:

Let's plug in the values and do the calculations to get the volume of the balloon:

V = 5.78 L

So, the volume of the gas balloon is 5.78 L.